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The amount of power generated for a 162 J work done in 18 seconds is 9.0 Watts.

Power is the quantity of energy transferred per unit time. It can be expressed as;

P = E/t

Where P is power, E is energy and t is time.

Given the data in the question;

To determine the amount of power created, plug the given values into the formula above and solve for P.

P = E/t

P = 162kgm²/s² / 18.0s

P = 9 kgm²/s³

P = 9.0 W

Therefore, the power generated is 9.0 Watts.

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a compound machine is made of several simple machines

the difference is like a tree and a jungle

Answer:

neutron.

Explanation:

subatomic particles include,

neutron.

proton.

electron.

hope it helps. :)

To draw the circuit diagram with four 15 ohm resistors connected in a series to a 45-v battery, along with an ammeter and voltmeter, follow the steps below:Step 1: Place the batteryTo begin with, draw the 45 V battery at the top of the page, as shown in the figure below.  Step 2: Add resistorsNext, add the four 15 ohm resistors in a series circuit after the battery, as shown in the figure below.  

Step 3: Add the ammeterIn the circuit, an ammeter is placed in series with the resistors to calculate the total current in the circuit. Connect the ammeter between the last resistor and the negative terminal of the battery, as shown in the figure below.Step 4: Add the voltmeter. Finally, a voltmeter is placed in parallel with the resistors to determine the voltage across them.

Connect the voltmeter in parallel with each resistor, as shown in the figure below. [Figure]Hence, this is how the circuit diagram with four 15 ohm resistors connected in a series to a 45-v battery looks like, along with an ammeter and voltmeter.

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Answer:

Sound

Explanation:

Answer:

When an object vibrates, it creates kinetic energy that is transmitted by molecules in the medium. As the vibrating sound wave comes in contact with air particles passes its kinetic energy to nearby molecules. As these energized molecules begin to move, they energize other molecules that repeat the process.

Explanation:

So sound waves

The first-order decomposition of phosphine is a chemical reaction in which phosphine decomposes into its constituent elements over time. The rate of this reaction is proportional to the concentration of phosphine. In this problem, we are given that the time required to go from 1.00 m to 0.250 m is 120 seconds.

To determine the time it will take for the concentration to go from 0.400 m to 0.100 m, we can use the following formula:

ln([A]t/[A]0) = -kt

where [A]t is the concentration of phosphine at time t, [A]0 is the initial concentration of phosphine, k is the rate constant of the reaction, and t is the time.

We can rearrange this formula to solve for t:

t = ln([A]t/[A]0) / -k

We know that the initial concentration is [A]0 = 0.400 m and the final concentration is [A]t = 0.100 m. We can also use the rate constant k, which can be determined from the half-life of the reaction:

t1/2 = ln(2) / k

We are given that the time required to go from 1.00 m to 0.250 m is 120 seconds, so we can use this information to find the half-life:

t1/2 = ln(2) / k = ln(2) / (120 seconds) = 0.0058 seconds^-1

Now we can use this value of k and the concentrations to find the time required to go from 0.400 m to 0.100 m:

t = ln([A]t/[A]0) / -k = ln(0.100/0.400) / (-0.0058 seconds^-1) = 358 seconds

Therefore, it will take approximately 358 seconds for the concentration of phosphine to go from 0.400 m to 0.100 m.

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Answer:

obviously sasuke

Explanation:

everyone is always over estimating borutos powers like lets be real here sasuke is almost as strong as naruto and when they were younger he had better hand to hand combat and in jutsu's he was a prodigy and he is able to calculate precise movements to try and defeat his oponent lets not forget that he has the sharingon over whatever jutsus boruto has (i dont know because ive never seen the anime and i dont plan on doing so) (i hate boruto its trash) which means he could read borutos chakra and he would be more powerful because his sharingan awoken when he was a mear child he would be much more powerful beause hes mastered his sharingan. oh yeah and his fire ball and chidori (which could k!11 boruto if sasuke inflicts enough chakra into his jutsu) (if u want to say otherwise my pronouns are she/her so use them if u want to say something involving pronouns thanks)

I think its "a dropped penny sinks at the bottom of a pond". Because, non-contact force is a force that you don't touch, like gravity or weight, that falls but you didn't drop it on purpose nature did or gravity itself did.

The periodic table has the provided elements in the same column because they have the same amount of valence electrons.Why do elements belonging to the same group exhibit the same chemical behaviour.

Because they all have the same amount of valence electrons in their valence shells, the elements Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs), and Francium (Fr) are arranged in the same column in the periodic table.

The number of electrons in an element's outermost shell determines its chemical characteristics. If two elements have the same number of valence electrons, they belong to the same group. As a result, every element in the same group on the current periodic table has the same chemical characteristics.

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By finding the specific heat, we can expect that the material of the block is copper or silver (or a mix).

We know that we give 13,500 joules of energy to the metal block (which we assume has a mass of 1kg) and the temperature increases from 15°C to 60°C.

Then the increase is:

60°C - 15°C = 45°C

Then this metal has a specific heat of:

H = 13,500j/(45°C*1 kg) = 300 J/°C*kg

So it could be copper, which has a specific heat of 380J/°C*kg or Silver, which has a specific heat of 240 J/°C*kg (or a mix of these two).

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Answer:

Which one are we supposed to do

Explanation:

Answer: \(4 m/s^{2}\)

Explanation:

First you take your end velocity and subtract the initial velocity (\(40-20=20\))

Then you divide the difference by the time (\(20/5=4\))

Giving you the result of \(4 m/s^{2}\)

This all uses the equation \(V_{f}-V_{i}=ta\)

bicycle wheels

roller skates

doorknob

A wheel that has a rope wrapped around it

An ideal bandpass filter with unit gain and a bandwidth of 200 Hz is applied to the input signal g(t) = 8 cos(400πt) cos(200,000πt) + 18 cos(200,000nt). The center frequency of the filter is 100,200 Hz. We can sketch the amplitude spectrum of the signal at the output of the filter using the following steps:

Step 1: Determine the Fourier transform of the input signal g(t)The Fourier transform of g(t) is given by: G(ω) = π[δ(ω + 2π × 200,000) + δ(ω - 2π × 200,000)] + π/2[δ(ω + 2π × 200) + δ(ω - 2π × 200)]

Step 2: Determine the transfer function of the bandpass filter

The transfer function of the ideal bandpass filter with unit gain and a bandwidth of 200 Hz centered at 100,200 Hz is given by: H(ω) = {1 for |ω - 2π × 100,200| < π × 100, and 0 otherwise}

Step 3: Multiply the Fourier transform of the input signal by the transfer function of the filter

The output of the filter is given by:

Y(ω) = G(ω)H(ω)The product of the Fourier transform of the input signal and the transfer function of the filter is shown in the figure below.

The given signal is a combination of two cosines, where the first cosine has a frequency of 400π radians/second and the second cosine has a frequency of 200,000π radians/second.

The output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude spectrum of the output signal is zero outside the bandpass region and is equal to the product of the amplitude spectrum of the input signal and the frequency response of the filter within the passband region.

The amplitude spectrum of the output signal is shown in the figure below:

Therefore, the amplitude spectrum of the signal at the output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude of the signal within the passband region is given by the product of the amplitude of the input signal and the frequency response of the filter within the passband region.

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Taking into account the definition of velocity, Clara's average velocity is 0.5 m/s.

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction. So it is considered a vector magnitude.

In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction, and can be calculated using the expression:

velocity= distance traveled÷ time

Clara rushes 30 m to a truck then turns and walks back. Total travel is 120s. Then, you know:

Replacing in the definition of velocity:

velocity= 60 m÷ 120 s

Solving:

velocity= 0.5 m/s

Finally, Clara's average velocity is 0.5 m/s.

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As shown in the figure below, Clara rushes 30 m towards her truck 30 m toward her truck. She notices she forgot her donut and returns back to the house. Her total travel time is 120 s.

Answer:

What is Clara’s average velocity over the 120 period?

Answer: 0  m/s

What is Clara’s average speed over the  120 s period?

Answer: 0.50  m/s

Answer:

The value of g on the moon is 1.625 m/s2 and the value of the g on the jupiter is 2.528g.

Jupiter's surface gravity is 24.79/s or 2.528 g .

The acceleration due to gravity on the surface of the moon is approximately 1.625m/s .

hope this helps you

mrk me braniliest plzz

When considering the amount of time it took for the glove to stop the ball, we can determine the magnitude of the net force on the ball while it is in the glove by using the equation

Fnet = mΔv/Δt, where Fnet is the net force, m is the mass of the ball, Δv is the change in velocity of the ball, and Δt is the time it took for the ball to come to a stop.

Let's assume that the ball has a mass of 0.2 kg and was moving at a velocity of 5 m/s before it was caught by the glove. If it took 0.1 seconds for the ball to come to a complete stop within the glove, we can find the magnitude of the net force on the ball while it is in the glove as follows:

Fnet = mΔv/Δt

Fnet = 0.2 kg x (-5 m/s)/0.1 s

Fnet = -10 N

The negative sign indicates that the direction of the net force is opposite to the direction of the ball's motion.

Therefore, the magnitude of the net force on the ball while it is in the glove is 10 N.

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This equation demonstrates the relationship between your variables and allows you to make predictions or draw conclusions based on the linearized data.

To answer your question, I would need more specific details about your experiment or the data you are working with. However, I can provide a general explanation using the terms you've provided.

To linearize data, you might have used a specific function such as the logarithmic, exponential, or power function, depending on the context of the data. The choice of function depends on the pattern observed in the data and the best fit for linearization.

The mathematical relationship you found would be represented as an equation, typically in the form of y = mx + b for a linearized function. Here, 'm' represents the slope of the linearized data, and 'b' is the y-intercept. This equation demonstrates the relationship between your variables and allows you to make predictions or draw conclusions based on the linearized data.

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The position of the point charge q can be placed such that the net electrostatic force is -1.857 m.

To find the position where the net electrostatic force on the charge q is zero, we need to apply Coulomb's Law. Coulomb's law states that the electrostatic force between two charges is proportional to the product of the charges and inversely proportional to the square of the charges. distance between them.

In this case, we have two charges Q1 and Q2 at known positions and we need to find the position of the third charge q such that the net force is zero.

By equating the force due to Q1 with the force due to Q2, we can solve for the position of q. Changing the sign of Q2 changes the direction of the force on q and changes the position of q.

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The question is -

An electric point charge of Q1 = 7.43 nC is placed at the origin of the real axis. Another point charge of Q2 = 1.21 nC is placed at a position of p = 3.95 m on the real axis. At which position can a third point charge of q = -1.99 nC be placed so that the net electrostatic force on it is zero? Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?

Answer:

300 Watt

Explanation:

power=(450/3)*2

The isotope gamma decayed, turning some of its mass into the energy of the gamma rays.

During the experiment, the physicist observed that the sample of the newly discovered radioactive isotope lost mass. This loss of mass indicates that the isotope underwent gamma decay, a type of radioactive decay process.

Gamma decay involves the emission of gamma rays, which are high-energy photons. The fact that the sample emitted gamma rays suggests that the isotope released some of its energy during the decay process.

According to Einstein's mass-energy equivalence principle (E=mc²), energy and mass are interchangeable. In this case, as the isotope underwent gamma decay, some of its mass was converted into the energy of the emitted gamma rays.

This conversion is possible because the energy of gamma rays is directly proportional to their frequency and inversely proportional to their wavelength.

Therefore, the correct explanation for what happened in the experiment is that the isotope gamma decayed, turning some of its mass into the energy of the gamma rays. This process highlights the fundamental relationship between mass and energy in the realm of nuclear physics.

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The speed of the air on the wide side of the divider should be greater than the speed of the air on the narrow side.

Speed is the rate at which an object covers a certain distance in a given period of time. It is measured in units of distance, such as kilometers per hour (km/h), miles per hour (mph), or feet per second (fps). Speed is a scalar quantity, which means it has magnitude but no direction. Speed is usually calculated by dividing the distance an object has traveled by the time it took to travel that distance. It is important to note that speed does not necessarily equal velocity, as velocity has both magnitude and direction.

This is because the amount of space on the wide side is greater than on the narrow side, allowing more air to be pushed through the tube. Therefore, the air on the wide side will move faster due to the increased pressure.

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The body's response to a cold involves various immune cells and processes. Here is a simplified flow chart depicting the step-by-step response:

This flow chart demonstrates the coordinated response of B cells, helper T cells, macrophages, mucus production, lymph, cytokines, receptor proteins, antibodies, memory cells, and plasma cells in combating a cold virus and eventually eliminating it from the body.

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Answer:

balanced forces external forces

Explanation:

A body that is under a network of balanced external forces will experience no resultant force at all, since all the forces cancel themselves out. A body that is moving with this type of force will  experience no acceleration, since there is no force acting on them. This lack of acceleration means that the body maintains a constant velocity if it is already in motion, or zero when the body is at rest.

Answer: 41.9 below the negative x-axis.

Explanation: To find the direction of the resultant vector, we need to use some trigonometry and vector addition. Here are the steps:

Draw a diagram of the particle’s motion and label the vectors. The particle starts at the origin and moves 7.22 cm in the negative y-direction, which we can call vector A. Then it moves 8.05 cm in the positive x-direction, which we can call vector B. The resultant vector R is the vector that goes from the origin to the final position of the particle.

Find the components of vector A and vector B. Vector A has a magnitude of 7.22cm and a direction of 270 degrees (or -90 degrees) from the positive x-axis. Vector B has a magnitude of 8.05 cm and a direction of 0 degrees (or 360 degrees) from the positive x-axis. Using trigonometry, we can find the x and y components of each vector as follows:

A_x = A cos(270) = 7.22 cos(270) = 0

A_y = A sin(270) = 7.22 sin(270) = -7.22

B_x = B cos(0) = 8.05 cos(0) = 8.05

B_y = B sin(0) = 8.05 sin(0) = 0

Add the components of vector A and vector B to get the components of vector R. Using vector addition, we can find the x and y components of the resultant vector as follows:

R_x = A_x + B_x = 0 + 8.05 = 8.05

R_y = A_y + B_y = -7.22 + 0 = -7.22

Find the magnitude and direction of vector R using Pythagoras’ theorem and inverse tangent function. The magnitude of vector R is given by the square root of the sum of the squares of its components, and the direction of vector R is given by the inverse tangent of its y component divided by its x component, as follows:

R = sqrt(R_x^2 + R_y^2) = sqrt(8.05^2 + (-7.22)^2) = sqrt(114.81) = 10.71 cm

theta = tan^-1(R_y / R_x) = tan^-1(-7.22 / 8.05) = -41.9 degrees

Adjust the direction of vector R according to its quadrant. Since vector R is in the fourth quadrant, where both x and y are positive, we need to add 360 degrees to its direction to get a positive angle measured counterclockwise from the positive x-axis, as follows:

theta = -41.9 + 360 = 318.1 degrees

Alternatively, we can express the direction of vector R as an angle measured clockwise from the negative x-axis, which is equivalent to subtracting its direction from 360 degrees, as follows:

theta = 360 - (-41.9) = 401.9 degrees

However, since angles are periodic with a period of 360 degrees, we can subtract multiples of 360 degrees from this angle to get an equivalent angle between 0 and 360 degrees, as follows:

theta = 401.9 - 360 = 41.9 degrees

Therefore, the direction of vector R is either 318.1 degrees counterclockwise from the positive x-axis or 41.9 degrees clockwise from the negative x-axis.

Hope this helps, and have a great day! =)

The mean lifetime of A is given by τ(A) = 26 × 10⁻¹⁰ s. The A decays into p + e⁻ + ve with a branching fraction of BR(A → p + e⁻ + ve) = 83 × 10⁻⁴.The mean lifetime of A⁺ (udc) is given by τ(A⁺) = 2-1 × 10⁻¹³ s.

The branching fraction of A into A⁺ + e⁺ + ve is given as follows: First, we can calculate the decay constant for A.λ = (1/τ) = (1/26 × 10⁻¹⁰) s⁻¹.The half-life of A is given by t₁/₂ = ln(2) / λ = (ln2 × τ) = 2.667 × 10⁻¹⁰ s. The branching fraction of A → A⁺ + e⁺ + ve is given as follows: BR(A → A⁺ + e⁺ + ve) = 1 - BR(A → p + e⁻ + ve) = 1 - (83 × 10⁻⁴) = 0.99917.

The measured value of the branching fraction of A → A⁺ + e⁺ + ve is BR(e+ve) = 2106 %.This is greater than 100%. Therefore, the value must be a typographical error. The correct percentage is probably 21.06%.The estimated branching fraction of A → A⁺ + e⁺ + ve is 99.917%, which is very close to 100%. This implies that the A mainly decays into A⁺ + e⁺ + ve.

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A 45°-angled, half-transparent mirror is a feature of the interferometer. The light beam is divided into two equal portions using this mirror. The number of fringes that would be counted for 600 nm light is 200.

Fringes are areas of contrastive brightness or darkness that are produced by the diffraction or interference of radiation with a definable wavelength. Interference fringes can be either dazzling or black depending on whether two light beams are in phase or out of phase.

The expression used to calculate the number of fringes is:

D = mλ / 2

m = number of fringes

D = Distance

λ = wavelength

600 nm = 6 × 10⁻⁷ m

120 micron = 1.2 × 10⁻⁴ m

m = 2D / λ

m = 2 × 1.2 × 10⁻⁴ / 6 × 10⁻⁷

m = 200

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Create the Android App, set up the project, design the user interface, handle user input, perform calculations, and display the results.

Creating an Android App that calculates force and density can be done by following these steps:

Set up the project in Android Studio.

Design the layout of the user interface using XML, including TextViews, EditTexts, and a Button.

Define the necessary variables and views in the Java code.

Set an onClickListener for the button to perform the calculations.

Retrieve the user input from the EditText fields and convert them to appropriate data types.

Calculate the force using the formula F = ma and the entered mass and acceleration.

Display the calculated force in the result TextView.

Repeat steps 5-7 for calculating density if desired.

Run the app on an Android emulator or device to test its functionality.

The Simplifying User Input App developed in class can serve as a guide for implementing the user interface and handling user input.

You would need to modify the code to incorporate the force and density calculations based on the provided equations.

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