Select the best order of reagents to complete each of the following multi-step syntheses with the highest yield of the desired product. Assume all subsequent reactions will proceed regardless of the presence of deactivating groups

Answer:

1. Diamonds

2. Graphite

3. Textiles

4. Life Itself

5. Coal

6. Graphene

7. Carbon Dioxide

8. Coca-Cola

9. Paintball Guns

10. White dwarf stars

11. Oil

12. Gasoline

13. Curede oil

14. Wood (almost all fibers used for clothes contain carbon, as they are either proteins from animals/plants, or they are plastics.)

15. Acetic acid.

16. Acetylene.

17. Benzeze.

18. Carbon dioxide.

19. Carbon disulfide.

20. Carbon monoxide.

Avogadro's Number:

Avogadro's number, which is equal to 6.02214076 x \(10^{23}\) , is the quantity of units in one mole of any material. Hence, 1 mole of calcium phosphate,\(Ca_{3} (PO_{4}) _{2}\)   will contain 6.02214076 x \(10^{23}\)   atoms.

The molar mass of calcium phosphate is 310.18 g/mol,

Then, number of moles in 24.83g of calcium phosphate = \(\frac{mass}{molar mass}\)

                                                                                              = \(\frac{24.83}{310.18}\)

                                                                                               = 0.08 mole

Then, 0.08 mole of \(Ca_{3} (PO_{4}) _{2}\)   will contain,

= 0.08 moles x 6.02214076 x \(10^{23}\)   atoms

=  0.4818 x \(10^{23}\)   atoms = 4.818 x  \(10^{22}\) atoms.

Hence, 0.08 mole of calcium phosphate will contain 4.818 x  \(10^{22}\) atoms.

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Answer

Iron powder

Explanation

The one with the highest surface area will react with oxygen the fastest.

This is because if the surface area of a reactant is increased; more particles are exposed to the other reactant, and there is a greater chance of particles colliding, which leads to more successful collisions per second. Hence the rate of reaction increases.

The one with the highest surface area is iron powder.

A. False (The pH of an alkaline solution is greater than 7.)

B. True

C. True

D. False (Alkalis are usually soapy to touch and have a bitter or metallic taste.)

Corrected versions:

A. The pH of an alkaline solution is greater than 7.

D. Alkalis are usually soapy to touch and have a bitter or metallic taste.

Calculation:

To calculate the density of the essential oil, you would use the following equation:

density = mass/volume

Plugging in the given values, you would get:

density = 40 g/50 ml = 0.8 g/ml

Answer:

Below

Explanation:

Balanced form;

\(2C_6H_6 +15O_2 -> 12CO_2+6H_2O\\\\ Ca_3(PO_4)_2 +8C -> Ca_3P_2 +8CO\\\\2HNO_2+O_2 -> 2HNO_3\\\\Ca(OH)_2 + CO_2 -> CaC0_3+H_2O\\\\2K +Br_2 ->2KBr\\\\2NaOH+FeSO_4 -. Na_2SO_4 +Fe(OH)_2\)

1.Benzene + Dioxygen = Carbon Dioxide + Water

2.Tricalcium phosphate +Carbon = Calcium phosphide + carbon monoxide

3.Nitrous acid react with oxygen to produce nitric acid.

4.This means that the carbon dioxide and limewater react to produce calcium carbonate and water.

5.Potassium react with bromine to produce potassium bromide

6. An aqueous solution of ferrous sulphate reacts with aqueous solution of sodium hydroxide to form a precipitate of ferrous hydroxide and sodium sulphate remains in the solution.

Answer:

(a) pH=4.0

(b) pH=8.3

Explanation:

Hello there!

In this case, since the pH is understood as the potential of the hydrogen in an aqueous solution, and we can calculate it is as follows:

\(pH=-log([H^+])\)

We simply need to plug in the concentrations on each question as shown below:

(a)

\(pH=-log(1x10^{-4})\\\\pH=4\)

(b)

\(pH=-log(5x10^{-9})\\\\pH=8.3\)

Regards!

The ionic compound's metal will be replaced with AI. True for Fe2O3

Atomic bonds can be covalent or ionic in nature. The structures and characteristics of these bonds vary. Pairs of electrons are included in covalent bonds through the binding of two atoms in a specific orientation. Ionic bonds, on the other hand, are bonds that connect two ions.

Ionic bonding will typically be present in compounds where a metal is bound to either a quasi or a semi-metal. Molecular compounds are those that contain only non-metals or quasi combined with non-metals and exhibit covalent bonding.

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Answer:

B.) 0.316

Explanation:

To find the moles, you need to multiply the given value by the molar mass. The molar mass is made up of each element's atomic mass times their quantities. It is important to arrange the conversion in a way that allows for the cancellation of units.

Atomic Mass (S): 32.065 g/mol

Atomic Mass (O): 15.998 g/mol

Molar Mass (SO₃): 32.065 g/mol + 3(15.998 g/mol)

Molar Mass (SO₃): 80.059 g/mol

25.3 grams SO₃                1 mole
-------------------------  x  -------------------------  =  0.316 moles SO₃
                                    80.059 grams

We need to add 50 mL of lotion base to the 30 mL of oxiconazole nitrate lotion to reduce its concentration to 6 mg/mL.

To solve this problem, we need to find the volume of lotion base that needs to be added to achieve a concentration of 6 mg/mL.

First, we need to convert the concentration of the oxiconazole nitrate lotion from 1% w/v to mg/mL.

1% w/v means that 1 gram of oxiconazole nitrate is present in 100 mL of solution. Therefore, the concentration is 1 gram/100 mL = 10 mg/mL.

We want to reduce the concentration to 6 mg/mL. This means that for every 1 mL of solution, we need 6 mg of oxiconazole nitrate.

Now, let's calculate the volume of lotion base needed. Since we have 30 mL of the original lotion with a concentration of 10 mg/mL, the total amount of oxiconazole nitrate in this lotion is 30 mL * 10 mg/mL = 300 mg.

To achieve a concentration of 6 mg/mL, we divide the total amount of oxiconazole nitrate (300 mg) by the desired concentration (6 mg/mL):

300 mg / 6 mg/mL = 50 mL.

Therefore, to achieve a concentration of 6 mg/mL, 50 mL of lotion base should be added to the existing 30 mL of oxiconazole nitrate lotion.

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Answer:

C.Universal indicator turns orange in

weak acid.

Explanation:

option A and B are incorrect coz universal indicator turns red in strong acid and in strong alkali (base) it turns blue

1st part is ure answer --> 2M

Given mass -> 58 grams

mass of NaCl -> 58.44 approx -> 58 any

moles given-> 1 moles

\(Molarity = \frac{moles}{vol \: in \: lts} \)

\(Molarity = \frac{1}{0.5} = \frac{10}{5} \\Molarity = 2M\)

Answer:the answer is a

Explanation:

The density of a gas at standard temperature and pressure conditions is 1.40 grams per liter.

Standard temperature and pressure are defined as a standard set of conditions required for experimental measurements which are established to allow comparison between different sets of data.

Standards which are commonly used are those International Union of pure and applied chemistry and national institute of standards and technology.These are not universally accepted standards but are the ones which are commonly used.

Standard conditions of pressure and temperature are necessary to define standard reference conditions used to express volumes of liquids and gases.These values are important to physicists, chemists ,engineers ,pilots and navigators.

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Answer:

See below

Explanation:

13.  The molar mass of Cl2 is 70.9 grams/mole.  Mass of 0.560 moles:

(0.560 moles)*(70.9 grams/mole) = 39.7 grams Cl2

14.  2 moles of M93N2 has 2*2 = 4 moles of N atoms

15.   2.00 moles Mg3N2 has 2*2 = 4 moles N atoms

16.  9.0 grams of Ag.  The molar mass of silver is 107.9 g/mole.  9.0 grams means that there is (9.0g/(107.9 g/mole) = 0.0834 moles Ag.  

   (0.0834 moles Ag)*(6.022x10^23 Ag atoms/mole) = 5.02x10^22 atoms of silver

The mass of 0.560 moles of chlorine gas is 39.7 g. There are 6.00 moles of Mg atoms and 4.00 moles of N atoms respectively in 2.00 moles of Mg3N2 compound. The number of atoms in 9.0 g of silver can be calculated by converting the grams to moles then multiplying by Avogadro's number.

The mass of chlorine gas can be calculated by multiplying the given moles with the molar mass of chlorine. The molar mass of chlorine (Cl2) is approximately 70.9 g/mol. Therefore, the mass of 0.560 moles of chlorine gas would be 0.560 * 70.9 = 39.7 g.

For Mg3N2, there are 3 moles of Mg per mole of Mg3N2, so there are 2.00 * 3= 6.00 moles of Mg atoms in 2.00 moles of Mg3N2. Similarly, there are 2 moles of N per mole of Mg3N2 so, there are 2*2.00 = 4.00 moles of N atoms in 2.00 moles of Mg3N2.

The number of atoms in silver can be calculated using Avogadro's number, which is 6.02 x 10^23 atoms per mole. First convert the mass to moles (silver has a molar mass of approximately 107.87 g/mol) and then multiply by Avogadro's number.

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Answer:

there will be less and less space

Explanation:

The amount of a sample of 100 grams of a radioactive isotope that would remain after 732 days would be 14.0625 grams.

Given, the Half-life of the radioactive isotope = 273 days.Time elapsed = 732 days.Initial quantity or sample = 100 grams. Let's determine how many half-lives have passed since 732 days: Number of half-lives = (time elapsed) / (half-life)= 732 / 273 ≈ 2.683

Half-life #1: After the first half-life of 273 days, the sample will be halved. Therefore, after 273 days, the quantity remaining will be 1/2 * 100g = 50g

Half-life #2: After the second half-life of 273 days, the sample will be halved again. Therefore, after 546 days, the quantity remaining will be 1/2 * 50g = 25gHalf-life #3: After the third half-life of 273 days, the sample will be halved again.

Therefore, after 819 days, the quantity remaining will be 1/2 * 25g = 12.5gHowever, the time elapsed from 819 days to 732 days is 87 days. This time interval is less than the half-life. As a result, it is critical to calculate the amount that would be left over after 732 days using a different method. Let us consider the remaining amount from 819 days (12.5g) as the new initial quantity for the remaining 87 days. The half-life of the radioactive isotope is 273 days.

Therefore, the rate of decay for each day will be: Rate of decay per day = (1/2)^(1/273)≈ 0.002540401Therefore, the amount of the sample remaining after 87 days (or 0.3195 half-lives) can be calculated using the following formula: Q = Q0(0.5)^(t/h)where Q0 is the original quantity, Q is the remaining quantity after time t, and h is the half-life of the isotope. Q = 12.5g × (0.5)^(0.3195)Q ≈ 6.5625g

Therefore, the total amount of the sample remaining after 732 days can be found by adding up the amounts of the sample remaining from each half-life: Total remaining = 50g + 25g + 6.5625gTotal remaining ≈ 81.5625 the amount of a sample of 100 grams of a radioactive isotope that would remain after 732 days would be 14.0625 grams.

After 732 days, the sample would have decayed by three half-lives (819 days) and an additional 87 days. As a result, 81.5625g of the sample will remain after 732 days. Therefore, 100g - 81.5625g = 18.4375g of the sample would have decayed in 732 days.

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Answer:

B.

Explanation:

Atoms make up molecules and ionic bonds cannot make up a molecule because they do not share electrons like in a covalent bond.

For the 4 g of hydrogen, only 32 g of Oxygen is required to react completely.

Hydrogen is described as the chemical element with the symbol H and atomic number 1. Hydrogen is known as the lightest element. At standard conditions hydrogen is also known to be a gas of diatomic molecules having the formula H₂.

Hydrogen has some properties which includes : It is colorless, odorless, tasteless, non-toxic, and highly combustible.

From the equation, Molecular mass of H2 = 2g/mol

Molecular mass of O2 = 32g/mol

From  the balanced chemical equation,

2H +O 2 →2H 2O

2×2=4 g of hydrogen requires 32 g of Oxygen to react completely.

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Answer:

Biology

Explanation:

Biology is the study of all living beings. From the smallest algae or micro organism to the biggest living being is all covered under biology. How micro organisms live, how do they function and how they affect other living beings is studied in biology.

Answer:

Micro bioligist

Explanation: hope this helps

The appropriate definition that applies to the compound in red (F-(aq)) is Bronsted-Lowry base.

Based on the given chemical equation F-(aq) + HSO4-(aq) → HF(aq) + SO42-(aq), the compound in red is F-(aq) (fluoride ion).

In this context, F-(aq) acts as a base by accepting a proton (H+) from the HSO4-(aq) ion, forming HF(aq) and SO42-(aq).

Therefore, the appropriate definition that applies to the compound in red (F-(aq)) is Bronsted-Lowry base.

In the given chemical equation F-(aq) + HSO4-(aq) → HF(aq) + SO42-(aq), the compound highlighted in red is F-(aq), which represents the fluoride ion.

In this specific context, F-(aq) demonstrates its characteristics as a base by accepting a proton (H+) from the HSO4-(aq) ion. This proton transfer reaction results in the formation of HF(aq) and SO42-(aq).

Therefore, based on its behavior in the equation, the appropriate definition for the compound in question, F-(aq), is that of a Bronsted-Lowry base.

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Explanation:

Hi there!

Chloroethane requires atleast one chlorine in ethane. It's general formula is CnH2n+1Cl. It mean it must have 2 carbons, 5 hydrogens and atleast one chlorine.

In addition, carbon-carbon bond must be single and chlorine is attached to either carbons. The carbon of this compound is SP³ hybridized and has bond angle of 120°.

Hope it helps!

Nucleophilic addition and proton transfer are the two stages involved in the conjugate 1,4-addition of cyanide to a -unsaturated carbonyl.

A carbonyl group (C=O) connected to a carbon-carbon double bond (C=C) in an organic molecule is known as an unsaturated carbonyl in chemistry. The atoms are arranged in a planar form with a distinctive resonance, which gives the molecule its distinct reactivity and physical characteristics.

These functional groups are crucial intermediates in several chemical processes because the double bond in an unsaturated carbonyl is sensitive to nucleophilic addition reactions including Michael addition and conjugate addition. Moreover, the parent molecule gains various chemical features from the presence of an unsaturated carbonyl, including higher acidity, greater reactivity with electrophiles, and changed physical qualities such boiling.

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Answer:

Calcium

Explanation:

It has the largest atom

Answer:

False

Explanation:

When you continuously feed waves into space, there are going to be some cold spots, or "dead spots."

Answer:

different sizes of the parachute

Explanation:

this is what is being changed throughout the experiment

Answer:

Explanation:

True

Answer:

the law of definite proportion states that in a compound the ratio of atom is fixed

for example, hydrogen and oxygen in pure water is always 1:8 by weight