The angle that completes the law of cosines is 62°.
Option D is the correct answer.
What are trigonometric identities?There are three commonly used trigonometric identities.
Sin x = 1/ cosec x
Cos x = 1/ sec x
Tan x = 1/ cot x or sin x / cos x
Cot x = cos x / sin x
We have,
The law of cosines in a triangle states that,
c² = a² + b² - 2ab cos C
Where c is the side opposite to ∠C.
Similarly,
a² = b² + c² - 2bc cos A
b² = a² + c² - 2ac cos B
Now,
289 + 64 - 272 cos __ = 15²
17² + 8² - 2 x 17 x 8 cos 62 = 15²
289 + 64 - 272 cos 62 = 15²
Thus,
The angle that completes the law of cosines is 62°.
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The complete question.
289 + 64 - 272 cos __ = 15²
Does anybody know this? I know what the radius is but when I calculated my answer doesn't match the options. Find the surface area of a sphere is the area of the great circle is 81pi in^2
\(\stackrel{\textit{area of the great circle}}{A=\pi r^2}\hspace{5em}81\pi =\pi r^2\implies \cfrac{81\pi }{\pi }=r^2\implies 81=r^2 \\\\\\ \sqrt{81}=r\implies 9=r \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{surface area of the sphere}}{SA=4\pi r^2}\hspace{5em}SA=4\pi (9)^2\implies SA=324\pi ~in^2\)
Suppose that V₁, V2, , Um are linear dependent in a vector space V. For every & EV, show that 7₁, V2, , Um, 7 are also linearly dependent. 9
By supposing that V₁, V2, and Um are linearly dependent in a vector space V. For every & EV. V₁, V₂, ..., Uₘ are linearly dependent in a vector space V. As 7₁V₁ = 7(c₂V₂ + c₃V₃ + ... + cₘUₘ)
To show that 7₁V₁, 7₂V₂, ..., 7ₘUₘ, 7 is also linearly dependent for every 'c' in V, we can use the following approach: If V₁, V₂, ..., Uₘ are linearly dependent, then we can write at least one vector as a linear combination of the other vectors.
Let's assume V₁ can be written as a linear combination of the other vectors as follows:
V₁ = a₂V₂ + a₃V₃ + ... + aₘUₘ
where a₂, a₃, ..., aₘ are constants. Now, we can express the vector 7₁V₁ as:
7₁V₁ = 7₁a₂V₂ + 7₁a₃V₃ + ... + 7₁aₘUₘ
Since 7 is a constant, we can take it outside the bracket as:
7₁V₁ = 7(a₂7₁V₂ + a₃7₁V₃ + ... + aₘ7₁Uₘ)
Let's assume the sum inside the bracket is equal to 'b'. Then,
7₁V₁ = 7b
Since we know that V₁, V₂, ..., Uₘ are linearly dependent, we can write b as a linear combination of the other vectors as follows:
b = c₂V₂ + c₃V₃ + ... + cₘUₘ
where c₂, c₃, ..., cₘ are constants. Now, substituting the value of b in the equation for 7₁V₁, we get:
7₁V₁ = 7(c₂V₂ + c₃V₃ + ... + cₘUₘ)
This shows that 7₁V₁, 7₂V₂, ..., 7ₘUₘ, 7 are also linearly dependent. Therefore, we have proved that for every 'c' in V, 7₁V₁, 7₂V₂, ..., 7ₘUₘ, 7 are also linearly dependent.
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Please Help With Geometry! Will Mark Brainliest!
The measure οf ∠LBH is 12.5°, the measure οf ∠DWL is 155° and the measure οf arc BW is 25°.
What is circle?In geοmetry, a circle is a twο-dimensiοnal curved shape that cοnsists οf all pοints that are a fixed distance frοm a given pοint called the center.
First, nοte that since triangle LWN is isοsceles, we have ∠WLN = ∠LWN = 25°.
Tο find ∠LBH, we can use the fοllοwing steps:
Since ∠LH is an inscribed angle that intercepts arc LN, its measure is half the measure οf arc LN, i.e., ∠LH = 1/2 * arc LN = 1/2 * (360 - 2*25) = 155°.
Since triangle LBH is isοsceles (LB = BH), we have ∠LHB = ∠HLB.
The sum οf angles in triangle LHB is 180°, sο we have 2*∠LHB + ∠LH = 180°.
Substituting ∠LH = 155° and sοlving fοr ∠LHB, we get ∠LHB = (180 - 155)/2 = 12.5°.
Therefοre, ∠LBH = ∠LHB = 12.5°.
Tο find ∠DWL, nοte that ∠DWL and ∠WLN fοrm a linear pair (i.e., they are adjacent angles that add up tο 180 degrees).
Therefοre, we have ∠DWL = 180 - ∠WLN = 180 - 25 = 155°.
Tο find the measure οf arc BW, nοte that this arc is subtended by ∠LHB. Since ∠LHB = 12.5°, we have arc BW = 2*∠LHB = 25°.
Therefοre, the measure οf ∠DWL is 155° and the measure οf arc BW is 25°.
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what is 0,0.5,1,1.5,2,3,3.5,4,4.5,5,6,6.5,7 in order from least to greatest?
Answer:
0, 0.5, 1, 1.5, 2, 3, 3.5, 4, 4.5, 5, 6, 6.5, 7
Step-by-step explanation:
(Q2) Order the sides of ΔDEF from shortest to longest.
The order would be DE < FD < EF. To order the sides of triangle ΔDEF from shortest to longest, you need to compare the lengths of the sides.
1. Determine the lengths of sides DE, EF, and FD.
2. Compare the lengths to find the shortest side.
3. Identify the next shortest side.
4. The remaining side will be the longest.
Once you have the side lengths, simply arrange them in ascending order (from shortest to longest) to answer your question. For example, if DE is 3 units, EF is 5 units, and FD is 4 units, the order would be DE < FD < EF.
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Farrah borrowed $155 from her brother. She has already paid back $15. She plans to pay back $35 each month until the debt is paid off.
Answer:
Just subtract 155 from 15 and divide that number what you got from 155 - 15 and divide it to 35.
Step-by-step explanation:
I dont know how much months are there so how much months you divide it from 35.
Answer:
A,b and d
Step-by-step explanation:
passing through point (0,5) and perpendicular to the x-axis
Need help ASAP!! Due in 10 minutes. Please help
Answer:
Its J
Step-by-step explanation:
to flip over the X-axis you multiply all the y values by -1 then subtract 2 from the Y values to translate it down
If K is the midpoint of JL, JK = 8x + 11 and KL = 14x – 1, find JL.
Answer:
\(JL=54\)
Step-by-step explanation:
We are given that K is the midpoint of JL. Using this information, we want to find JL.
By the definition of midpoint, this means that:
\(JK=KL\)
Substitute them for their equations:
\(8x+11=14x-1\)
Solve for x. Subtract 8x from both sides:
\(11=6x-1\)
Add 1 to both sides:
\(6x=12\)
And divide both sides by 6. Hence:
\(x=2\)
JL is the sum of JK and KL. Hence:
\(JK+KL=JL\)
Since JK = KL, substitute either one for the other:
\(JK+(JK)=2JK=JL\)
Substitute JK for its equation:
\(2(8x+11)=JL\)
Since we know that x = 2:
\(2(8(2)+11)=2(16+11)=2(27)=54=JL\)
Thus:
\(JL=54\)
HELPPPPPP pls give explaiantikn or work pls pls pls pls brainliest
Answer:
Elizabeth had 30 stamps originally.
Step-by-step explanation:
Let,
x be the number of stamps Elizabeth have.
Number of stamps given to John = 1/6 of x = \(\frac{1}{6}x\)
Remaining stamps = \(x-\frac{1}{6}x = \frac{6x-1x}{6} = \frac{5}{6}x\)
Stamps given to Peter = 1/5 of remainder = \(\frac{1}{5}*\frac{5}{6}x = \frac{1}{6}x\)
Number of stamps left = 20
Now,
\(\frac{1}{6}x + \frac{1}{6}x + 20 = x\\\\\frac{1x+1x+120}{6} = x\\\\\frac{2x+120}{6} = x\\\\2x + 120 = 6x \\\\120 = 6x - 2x \\\\120 = 4x \\4x = 120\)
Dividing both sides by 4
\(\frac{4x}{4}=\frac{120}{4}\\x=30\)
Hence,
Elizabeth had 30 stamps originally.
Find the cost for renting a car for six days at $24.75 per day and 13¢ per mile, if the car is driven 1,083 miles.
A. $148.50
B. $289.29
C. $140.79
D. $278.29
Answer:
Step-by-step explanation:
13per mile×1080 mile =140.79
Answer:
B
Step-by-step explanation:
if you at $24.74 * 6 = 148.5
then you take 1083 * .13 = 140.79
then add the two number to get 289.29
In a region where there is a uniform electric field, the potential, v1, is 1. 3 v at position y1=26 cm. At position y2=28 cm , the potential, v2, is 3. 9 v. What is the change in electric potential energy of an alpha particle (charge = +2e) if it is moved from y1 to y3?.
The change in electric potential energy of an alpha particle is:
1.3V/cm
"Information available from the question"
In a region where there is a uniform electric field, the potential, v1, is 1. 3 v at position y1=26 cm.
At position y2=28 cm , the potential, v2, is 3. 9 v.
Now, According to the question:
Calculation of magnitude:
Since V1 is 1.3 V at position y1=26 cm. At position y2=28 cm, the potential, V2, is 3.9 V
So, We know that
\(E =\frac{V_2-V_1}{Y_2-Y_1}\)
\(E=\frac{3.9-1.3}{28-26}\)
\(E=\frac{2.6}{2}\)
E = 1.3V/cm
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Use the graph to complete the statement.
The triangle at the top of the graph is a reflection of the
triangle at the bottom.
Over what line is the triangle reflected?
The triangle is reflected over line _________
Answer:
C
Step-by-step explanation:
I know my reflections =D
Mark as brainliest ;D
Answer:
c
Step-by-step explanation:
rationalize the denominator 4√2/4√5
Answer:
answer given in the phot
A 120 m square shaped floor is to be covered with square tiles of side 4 m. One 1 tile cost $4.25 at Drakes Traders Ltd. How many tiles are needed to cover the floor?
Answer:
$46.75
Step-by-step explanation:
1 tile covers: 4*4= 16 m²
Tiles required: 120/16= 11
Cost: 11*$4.25= $46.75
Four-fifths of a liter of lemonade was poured into 5 cups so that each cup had the same amount. The lemonade from 4 of those cups was then poured into one large glass. What fraction of a liter of lemonade is now in the large glass?
If four-fifths of a liter of lemonade was poured into 5 cups so that each cup had the same amount, each cup would contain 1/5 of four-fifths of a liter.
1/5 of four-fifths can be calculated as follows:
(1/5) * (4/5) = 4/25
So, each cup contains 4/25 of a liter of lemonade.
If the lemonade from 4 of those cups was poured into one large glass, the large glass would contain the combined amount from those 4 cups. Therefore, the large glass would contain:
4 * (4/25) = 16/25
Thus, the fraction of a liter of lemonade in the large glass is 16/25.
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Helpppppp MEEEEE PLSSSS
Emma earns an annual salary of $84,400 and is paid biweekly. Her W-4 shows "married filing jointly and uses the standard withholding" What is her FIT withholding?
To determine Emma's federal income tax (FIT) withholding, we need to consider her annual salary, pay frequency, filing status, and the standard withholding allowances.
Given that Emma earns an annual salary of $84,400 and is paid biweekly, we can calculate her gross biweekly salary by dividing the annual salary by the number of pay periods in a year. Assuming there are 26 pay periods in a year for biweekly payments:
Gross biweekly salary = Annual salary / Number of pay periods
= $84,400 / 26
= $3,246.15 (rounded to two decimal places)
Next, we need to determine Emma's withholding allowances based on her filing status. Since she selected "married filing jointly" and is using the standard withholding, the default number of allowances for this status is usually higher compared to single or married filing separately. However, the specific number of allowances can vary based on personal circumstances.
As of my knowledge cutoff in September 2021, the standard withholding allowances for married filing jointly were as follows:
First allowance: $4,300
Additional allowances: $4,400
Please note that tax laws can change, and it's advisable to consult the latest IRS guidelines or use an online tax calculator to get accurate withholding information.
To calculate Emma's FIT withholding, we'll subtract her allowances from her gross biweekly salary and apply the appropriate tax rates. For simplicity, let's assume Emma has one withholding allowance:
Total allowances = First allowance + Additional allowances
= $4,300 + $4,400
= $8,700
Taxable income = Gross biweekly salary - Total allowances
= $3,246.15 - $8,700
= -$5,453.85 (negative because allowances exceed the salary)
Since the taxable income is negative, Emma's FIT withholding should be $0. In this case, no federal income tax will be withheld from her biweekly paychecks. However, please note that Emma may still owe taxes when filing her annual tax return if her other sources of income or deductions are not accounted for in her withholding calculations.
Does someone mind helping me with this. Thank you!
Answer:13
Step-by-step explanation:
y=kx
Substitute values
104=8k
Divide both sides by 8 to solve for k
k=13
Can you help me please?
An object is thrown upward from the top of a 200 foot cliff with a velocity of 12 feet per second. The height h in feet of the object after t second is h= -16t + 12t + 200.
How long after the object is thrown will it strike the ground?
The time It takes the object to strike the ground after it is thrown is 3.93 s
How to find how long after the object is thrown will it strike the ground?Since an object is thrown upward from the top of a 200 foot cliff with a velocity of 12 feet per second. The height h in feet of the object after t second is h= -16t² + 12t + 200.
Since the object is a parabola, the time it takes to strike the ground is when it strikes the ground at h = 0.
So, h = 0
⇒ -16t² + 12t + 200 = 0
Dividing through by -4, we have that
-16t²/-4 + 12t/-4 + 200/-4 = 0/-4
4t² - 3t - 50 = 0
Using the quadratic formula, we find t
\(t = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}\)where
a = 4, b = -3 and c = -50
So, substituting the values of the variables into the equation, we have that
\(t = \frac{-(-3) +/- \sqrt{(-3)^{2} - 4\times4\times(-50)} }{2\times4}\\= \frac{3 +/- \sqrt{9 + 800} }{8}\\= \frac{3 +/- \sqrt{809} }{8}\\= \frac{3 +/- 28.443}{8}\\= \frac{3 + 28.443}{8} or t = \frac{3 - 28.443}{8}\\= \frac{31.443}{8} or t = \frac{- 25.443}{8}\\t = 3.93 s or t = -3.18 s\)
Since t cannot be negative, t = 3.93 s
So, it takes 3.93 s to strike the ground
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1 point
52. A primary school with six
grade levels would like to do a
survey with 50 students about
their favourite lunch menu. The
school would like the sample to
be fair. Which set of students
should they collect the 50
samples from?
*
O All the students from the 4-H clubs.
O
Grade 6 students only.
Randomly selected students from
grades 4-6 only
Randomly selected students from
across all 6 grade levels.
Randomly selected students from across all 6 grade levels.
Answer:
survey across all grade levels i think
Step-by-step explanation:
good luck
Find the perimeter of the shaded region. Round your answer to the nearest hundredth
Answer:
38 units
Step-by-step explanation:
13+13=26
6+6=12
26+12=38
E
F G
H
+_+
7
TI
の
3
4
5
What letter is located at approximately V22
Answer:
I'm not completely sure but I think it's A E
he school store is running a promotion on school supplies. Different supplies are placed on two shelves.
You can purchase 3 items from shelf A and 2 from shelf B for $26, or
You can purchase 2 items from shelf A and 5 from shelf B for $32.
Let x represent the cost of an item from shelf A and let y represent the cost of an item from shelf B. Write and solve a system of equations to find the cost of items from shelf A and shelf B. Show your work and thinking!
Answer:
Shelf A = $6 ;Shelf y = $4
Step-by-step explanation:
Let :
x = cost of items from shelf A
y = cost of items from shelf B
3x + 2y = 26 - - - - (1)
2x + 5y = 32 - - - - (11)
Using elimination method :
Multiply (1) by 2 and (11) by 3
6x + 4y = 52 - - - (111)
6x + 15y = 96 - - - (1V)
Subtract (1V) from (111)
-11y = - 44
y = 44/ 11 ; y = 4
Put y = 4 in (1)
3x + 2(4) = 26
3x + 8 = 26
3x = 26 - 8
3x = 18
x = 18 / 3
x = 6
You can use those variables specified to make symbolic relation between the cost and number of items. Then you can use any of the methods to solve the obtained system of equations.
The cost of items from shelf A is x = $6
The cost of items from shelf B is y = $4
Given that:
You can purchase 3 items from shelf A and 2 from shelf B for $26, orYou can purchase 2 items from shelf A and 5 from shelf B for $32.x represents the cost of an item from shelf A
y represents the cost of an item from shelf B
How to form the symbolic relation or equation between the cost and the number of items picked from each shelf?From given data, we have:
\(3 \times x + 2 \times y = \$26\\ 2 \times x + 5 \times y = \$32\)
Or, we get the system of equations as:
\(3x + 2y =26\\ 2x + 5y = 32\)
Using the method of substitution to deduce the solution:\(3x + 2y = 26\\ 2y = 26 - 3x\\ y = \dfrac{26-3x}{2} = 13 - 1.5x\)
Substituting this value of y in second equation, we get:
\(2x + 5y = 32\\ 2x + 5(13-1.5x) = 32\\ 2x - 7.5x + 65 = 32\\ -5.5x = -65 + 32\\ 5.5x = 33\\\\ x = \dfrac{33}{5.5}\\\\ x = 6\)
Using this value of x, we get:
\(y = 13 - 1.5x\\ y =13 - 1.5 \times 6\\ y = 13 - 9 = 4\)
Thus, we have:
The cost of items from shelf A is x = $6
The cost of items from shelf B is y = $4
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A project has five activities with the durations (days) listed
below:
Activity
Precedes
Expected
Duration
Variance
Start
A, B
-
-
A
C
40
0.31
B
E
32
0.25
C
D
21
0.35
The critical path is the path with the longest duration, which in this case is A -> B -> D -> E with a duration of 11 days.
To determine the critical path of the project, we need to find the longest path of activities that must be completed in order to finish the project on time. This is done by calculating the earliest start time (ES) and earliest finish time (EF) for each activity.
Starting with activity A, ES = 0 and EF = 4. Activity B can start immediately after A is complete, so ES = 4 and EF = 7. Activity C can start after A is complete, so ES = 4 and EF = 6. Activity D can start after B is complete, so ES = 7 and EF = 9. Finally, activity E can start after C and D are complete, so ES = 9 and EF = 11.
The variance for each activity is also given, which allows us to calculate the standard deviation and determine the probability of completing the project on time. The critical path is the path with the longest duration, which in this case is A -> B -> D -> E with a duration of 11 days.
Using the expected durations and variances, we can calculate the standard deviation of the critical path. This information can be used to determine the probability of completing the project on time.
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Can someone please help me
f(x) = -3x + 20; f(8)
Answer:
-4
Step-by-step explanation:
the function simplified is -4 i have no way to explain just trust
write (14+x)+(12x-8) in standard form
Answer:
13x+6
Step-by-step explanation:
A fossil contains 18% of the carbon-14 that the organism contained when it was alive. Graphically estimate its age. Use 5700 years for the half-life of the carbon-14.
Graphically estimating the age of the fossil with 18% of the original carbon-14 content involves determining the number of half-lives that have passed. Therefore, the fossil is estimated to be between 11400 and 17100 years old.
Since the half-life of carbon-14 is 5700 years, we can divide the remaining carbon-14 content (18%) by the initial amount (100%) to obtain 0.18. Taking the logarithm base 2 of 0.18 gives us approximately -2.5146.
In the graph, we can plot the ratio of remaining carbon-14 to the initial amount on the y-axis, and the number of half-lives on the x-axis. The value of -2.5146 lies between -2 and -3 on the x-axis, indicating that the fossil is between 2 and 3 half-lives old.
Since each half-life is 5700 years, multiplying the number of half-lives by the half-life period gives us the age estimate.
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A gumball machine contains 7 red, 8 orange, 9 purple, 7 white, and 5 yellow gumballs. If the machine dispenses 3 gumballs at random all at once, find the probabilities for the different combinations below: a.) Find the probability of getting 1 purple, 1 white, and 1 red gumballs: b.) Find the probability of getting 1 orange and 2 yellow gumballs:
The given number of different colored gumballs in the gumball machine are as follows:7 red, 8 orange, 9 purple, 7 white, and 5 yellow gumballs.
Therefore, the total number of gumballs = 7 + 8 + 9 + 7 + 5 = 36.Using the formula for combinations, the total number of ways to get 3 gumballs at once is given by:36C3 = (36 × 35 × 34)/(3 × 2 × 1) = 7140a) Find the probability of getting 1 purple, 1 white, and 1 red gumballs There are 9 purple, 7 white, and 7 red gumballs in the machine. The number of ways to choose one purple, one white, and one red gumball is:9C1 × 7C1 × 7C1 = 9 × 7 × 7 = 441.
The probability of choosing one purple, one white, and one red gumball is:441/7140 = 0.0618 (approx)Therefore, the probability of getting 1 purple, 1 white, and 1 red gumballs is 0.0618.b) Find the probability of getting 1 orange and 2 yellow gumballsThere are 8 orange and 5 yellow gumballs in the machine. The number of ways to choose one orange and two yellow gumballs is:8C1 × 5C2 = 8 × (5 × 4)/(2 × 1) = 80The probability of choosing one orange and two yellow gumballs is:80/7140 = 0.0112 (approx)Therefore, the probability of getting 1 orange and 2 yellow gumballs is 0.0112.
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