Answer:
We conclude that
\(3^{-3}\times \:8^{-6}=\frac{1}{8^6\times \:\:3^3}\)
Step-by-step explanation:
Given the expression
\(3^{-3}\times \:8^{-6}\)
\(\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\)
\(3^{-3}\times\:8^{-6}=8^{-6}\times \:\frac{1}{3^3}\)
\(\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\)
\(=\frac{1}{3^3}\times \frac{1}{8^6}\)
\(\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}\)
\(=\frac{1\times \:1}{3^3\times \:8^6}\)
\(=\frac{1}{8^6\times \:3^3}\)
Therefore, we conclude that
\(3^{-3}\times \:8^{-6}=\frac{1}{8^6\times \:\:3^3}\)
Please help me!!!!!!!!!
Stella buys a one-pint bottle of juice for $2.72. What is the unit rate of the
cost of the juice per fluid ounce?
Answer: 0.17
Step-by-step explanation:
If she bought one pint of juice and there are 16 fluid ounces in one pint then you would take 2.72 the cost of it and divide ut by 16. So, 2.72/16 which is 0.17.
In fitting a least squares line to n = 15 data points, the following quantities were computed:
SSxx = 40, SSyy =200, SSxy = -82, mean of x = 2.4 and mean of y = 44.
3.1a Find the least squares line. What is the value of β1?
3.1b Find the least squares line. What is the value of β0?
3.2 Calculate SSE.
3.3 Calculate s.
3.4a Find the 90% confidence interval for the mean value of y when x = 15. What is the lower bound?
3.4b Find the 90% confidence interval for the mean value of y when x = 15. What is the upper bound?
3.5a Find a 90% prediction interval for y when x = 15. What is the lower bound?
3.5b Find a 90% prediction interval for y when x = 15. What is the upper bound?
3.1a The value of β1, which is the slope of the least squares line, is -2.05. 3.1b The value of β0, which is the y-intercept of the least squares line, is 48.92. 3.2 The Sum of Squares Error (SSE) is calculated to be 31.9. 3.3 The standard error of the estimate (s) is approximately 1.785. 3.4a The lower bound of the 90% confidence interval for the mean value of y when x = 15 is obtained using the formula and the given values. 3.4b The upper bound of the 90% confidence interval for the mean value of y when x = 15 is obtained using the formula and the given values. 3.5a The lower bound of the 90% prediction interval for y when x = 15 is obtained using the formula and the given values. 3.5b The upper bound of the 90% prediction interval for y when x = 15 is obtained using the formula and the given values.
3.1a To find the least squares line, we need to calculate the value of β1. β1 is given by the formula:
β1 = SSxy / SSxx
Using the values given, we have:
β1 = -82 / 40
β1 = -2.05
Therefore, the value of β1 is -2.05.
3.1b To find the least squares line, we also need to calculate the value of β0. β0 is given by the formula:
β0 = mean of y - β1 * (mean of x)
Using the values given, we have:
β0 = 44 - (-2.05 * 2.4)
β0 = 44 + 4.92
β0 = 48.92
Therefore, the value of β0 is 48.92.
3.2 SSE (Sum of Squares Error) can be calculated using the formula:
SSE = SSyy - β1 * SSxy
Using the values given, we have:
SSE = 200 - (-2.05 * -82)
SSE = 200 - 168.1
SSE = 31.9
Therefore, SSE is equal to 31.9.
3.3 To calculate s (the standard error of the estimate), we can use the formula:
s = sqrt(SSE / (n - 2))
Using the values given, we have:
s = sqrt(31.9 / (15 - 2))
s = sqrt(31.9 / 13)
s ≈ 1.785
Therefore, s is approximately equal to 1.785.
3.4a To find the 90% confidence interval for the mean value of y when x = 15, we use the formula:
Lower bound = β0 + β1 * x - t(α/2, n-2) * s * sqrt(1/n + (x - mean of x)^2 / SSxx)
Substituting the values, we have:
Lower bound = 48.92 + (-2.05 * 15) - t(0.05/2, 15-2) * 1.785 * sqrt(1/15 + (15 - 2.4)^2 / 40)
3.4b To find the upper bound of the confidence interval, we use the same formula as in 3.4a but with a positive value for t(α/2, n-2).
3.5a To find the 90% prediction interval for y when x = 15, we use the formula:
Lower bound = β0 + β1 * x - t(α/2, n-2) * s * sqrt(1 + 1/n + (x - mean of x)^2 / SSxx)
3.5b To find the upper bound of the prediction interval, we use the same formula as in 3.5a but with a positive value for t(α/2, n-2).
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he gypsy moth is a serious threat to oak and aspen trees. A state agriculture department places traps throughout the state to detect the moths. When traps are checked periodically, the mean number of moths trapped is only 0.5, but some traps have several moths. The distribution of moth counts is discrete and strongly skewed, with standard deviation 0.7. (a) What are the mean and standard deviation of the average number of moths ž in 60 traps? (b) Use the central limit theorem to find the probability that the average number of moths in 60 traps is greater than 0.4.
The probability that the average number of moths in 60 traps is greater than 0.4 is approximately 0.9738 or 97.38%.
(a) To find the mean and standard deviation of the average number of moths in 60 traps, we can use the properties of the normal distribution and the central limit theorem.
The mean of the average number of moths in 60 traps is equal to the mean of the individual moth counts, which is 0.5.
The standard deviation of the average number of moths in 60 traps is equal to the standard deviation of the individual moth counts, divided by the square root of the sample size.
standard deviation = 0.7 / sqrt(60) = 0.0905
the mean and standard deviation of the average number of moths in 60 traps are 0.5 and 0.0905, respectively.
(b) To use the central limit theorem to find the probability that the average number of moths in 60 traps is greater than 0.4, we need to standardize the distribution of sample means using the Z-score formula:
Z = (sample mean - population mean) / (standard deviation / sqrt(sample size))
Substituting the given values, we have:
Z = (0.4 - 0.5) / (0.7 / sqrt(60)) = -1.94
Using a standard normal table or a calculator with a normal distribution function, we can find that the probability of getting a Z-score greater than -1.94 is approximately 0.9738.
The probability that the average number of moths in 60 traps is greater than 0.4 is approximately 0.9738 or 97.38%.
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determine whether the sequence converges or diverges. if it converges, find the limit. (if an answer does not exist, enter dne.) an = (−1)n 5 n lim n→[infinity] an =
The sequence an = (-1)ⁿ * 5ⁿ alternates between positive and negative terms and grows without bound as n increases, so it does not converge and the limit does not exist (DNE).
The sequence is defined as an = (-1)ⁿ * 5ⁿ.
When n is odd, (-1)ⁿ is equal to -1, so an = -5ⁿ.
When n is even, (-1)ⁿ is equal to 1, so an = 5ⁿ.
Therefore, the sequence alternates between positive and negative terms, and the absolute value of the terms grows without bound as n increases.
This means that the sequence does not converge.
Hence, the limit of the sequence as n approaches infinity does not exist (DNE).
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what is the definition for relation in math?
A relation in math is a set of ordered pairs containing two elements, one from each set. The first element is from the domain and the second from the range.
Relations can be expressed as a set of ordered pairs, as a graph, or as a mapping diagram. A function is a special type of relation in which, for every element in the domain, there is one and only one element in the range. This is expressed mathematically by stating that for every x in the domain, there is one and only one y in the range such that y = f(x). To calculate a relation, the domain and range values are paired with each other, and the ordered pairs are written down. For example, if the domain is {2,3,4,5} and the range is {7,8,9,10}, then the relation would be {(2,7),(3,8),(4,9),(5,10)}.
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Which theorem or postulate proves that △ABC and △DEF are similar?
Select from the drop-down menu to correctly complete the statement.
The two triangles are similar by the ________.
A. AA Similarity Postulate
B. SSS Similarity Theorem
C. SAS Similarity Theorem
Option A. AA Similarity Postulate. The AA Similarity Postulate is a geometric principle that states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.
This means that their corresponding sides are in proportion, and the triangles have the same shape, but not necessarily the same size. This postulate is one of the ways to prove the similarity of two triangles. In the case of the given question, if we know that two angles of one triangle are congruent to the two angles of another triangle, then we can use the AA Similarity Postulate to prove that the triangles are similar. This principle is widely used in geometry and helps to establish relationships between different shapes and figures.
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TOSSING A NUMBER cube numbered from 1 to 6 and getting and even number that is greater that or equal to 2
Answer:
the probability is 3/5
Step-by-step explanation:
you have the numbers 2, 4, 6
and the numbers 3, 5
the 1 doesn't count, the question says numbers greater than or equal to 2
so, the remaining numbers add up to 3/5
answers are : • center D and scale factor ½• center D and scale factor 1 • center E and scale factor 3• center E and scale factor ½
The center of the dilation is a fixed point in the plane about which all the points are expanded or contracted, the center of the dilation is the only point that does not change. Hence in this case the center of the dilation is the point D.
Now, we notice that the dilation contracted in half the original figure.
Therefore, the dilation is: center D and scale factor 1/2
Decide whether each equation is true or false.
1. 9 ⋅ 9 ⋅ 3 = 3 5
2. 7 + 7 + 7 = 3 + 3 + 3 + 3 + 3 + 3 + 3
3. 1 7 ⋅ 1 7 ⋅ 1 7 = 3 7
4. 4 1 = 4 ⋅ 1
5. 6 + 6 + 6 = 6 3
Answer:
Step-by-step explanation:
Number 1 FALSE
9 * 9 * 3 = 81 * 3 = 243
Number 2 TRUE
7 + 7 + 7 = 3 + 3 + 3 + 3 + 3 + 3 + 3
7 * 3 = 3 * 7
21 = 21
Number 3 FALSE
17 * 17 * 17 = 4913
Number 4 FALSE
4 * 1 = 4
Number 5 FALSE
6 + 6 + 6 = 18
another chool is also cosidering changing thier pizza vendor. the school selects seperate random samples of 50 freshman, 50 sophiomres, 50 jjuniors, and 50 seniors. each student tries
If another school is considering changing their pizza vendor, they may also select separate random samples of 50 freshmen, 50 sophomores, 50 juniors, and 50 seniors to gather feedback from the students. By doing so, they can obtain a representative sample of the entire student population and ensure that each grade level is equally represented.
This will provide valuable insight into the preferences and opinions of the students, allowing the school to make an informed decision on which pizza vendor to choose. It is important to consider the feedback of all students in the decision-making process to ensure that the majority of the student body is satisfied with the food options provided by the school.
Step 1: Select random samples of students from each grade level.
Step 2: Provide the new pizza to each student in the samples.
Step 3: Ask the students to evaluate the pizza based on taste and quality.
Step 4: Collect the feedback from all 200 students.
Step 5: Analyze the data to determine if the majority of students prefer the new pizza vendor.
Based on the analysis, the school can make an informed decision about whether to change their pizza vendor or not.
another school is also cosidering changing thier pizza vendor. the school selects seperate random samples of 50 freshman, 50 sophiomres, 50 jjuniors, and 50 seniors. each student tries
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what is this answer guys
Answer:
The answer is A. 0.284
Step-by-step explanation:
Numbers that have a line above them represent that they never end. Since an irrational number is a number that never ends, option A is our answer.
[ 7 11] [12 4 5 ]
Find C =AB, if A = [2 9] B = [3 6 1]
[ 10 6]
The exercise involves finding the product C = AB, where matrix A is given by [2 9] and matrix B is given by [3 6 1]. We need to perform the matrix multiplication to obtain the resulting matrix C.
Let's calculate the matrix product C = AB step by step:
Matrix A has dimensions 2x1, and matrix B has dimensions 1x3. To perform the multiplication, the number of columns in A must match the number of rows in B.
In this case, both matrices satisfy this condition, so the product C = AB is defined.
Calculating AB:
AB = [23 + 912 26 + 94 21 + 95]
[103 + 612 106 + 64 101 + 65]
Simplifying the calculations:
AB = [6 + 108 12 + 36 2 + 45]
[30 + 72 60 + 24 10 + 30]
AB = [114 48 47]
[102 84 40]
Therefore, the product C = AB is:
C = [114 48 47]
[102 84 40]
In summary, the matrix product C = AB, where A = [2 9] and B = [3 6 1], is given by:
C = [114 48 47]
[102 84 40]
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calculate the range and standard deviation for 40, 65, 33, 46, 55, 50, 61
Answer:Therefore, the range is 32 and the standard deviation is approximately 10.523 for the given data set.
Step-by-step explanation:To calculate the range and standard deviation for the given data set {40, 65, 33, 46, 55, 50, 61}, we can follow these steps:
Step 1: Find the range.
The range is calculated by subtracting the minimum value from the maximum value in the data set.
Range = Maximum value - Minimum value
Range = 65 - 33
Range = 32
Step 2: Calculate the mean.
The mean is calculated by summing up all the values in the data set and dividing by the total number of values.
Mean = (40 + 65 + 33 + 46 + 55 + 50 + 61) / 7
Mean = 350 / 7
Mean = 50
Step 3: Calculate the deviation for each value.
Deviation is calculated by subtracting the mean from each value in the data set.
Deviation for 40 = 40 - 50 = -10
Deviation for 65 = 65 - 50 = 15
Deviation for 33 = 33 - 50 = -17
Deviation for 46 = 46 - 50 = -4
Deviation for 55 = 55 - 50 = 5
Deviation for 50 = 50 - 50 = 0
Deviation for 61 = 61 - 50 = 11
Step 4: Square each deviation.
Squared deviation for -10 = (-10)^2 = 100
Squared deviation for 15 = 15^2 = 225
Squared deviation for -17 = (-17)^2 = 289
Squared deviation for -4 = (-4)^2 = 16
Squared deviation for 5 = 5^2 = 25
Squared deviation for 0 = 0^2 = 0
Squared deviation for 11 = 11^2 = 121
Step 5: Calculate the variance.
Variance is calculated by summing up all the squared deviations and dividing by the total number of values.
Variance = (100 + 225 + 289 + 16 + 25 + 0 + 121) / 7
Variance = 776 / 7
Variance ≈ 110.857
Step 6: Calculate the standard deviation.
The standard deviation is the square root of the variance.
Standard Deviation ≈ √110.857
Standard Deviation ≈ 10.523
Write 480 ml as a fraction of 3 litres
Give your answer in its simplest form
Answer:
Step-by-step explanation:480/3000
Which of the following is the value of discriminant for √ 2x² − 5x+ √ 2 = 0?
17 is the value of discriminant for quadratic equation.
What in mathematics is a quadratic equation?
A quadratic equation is a second-order polynomial equation in one variable using the formula x = ax2 + bx + c = 0 and a 0.
The fundamental theorem of algebra ensures that it has at least one solution because it is a second-order polynomial problem. Real or complex solutions are also possible.
General form of a quadratic equation is
ax² + bx + c = 0
The Discriminant of the quadratic equation is denoted by D and defined as
D = b² - 4ac
The given Quadratic equation is
√2x² - 5x + √2 = 0
Comparing with the general equation of quadratic equation ax² + bx + c = 0 we get
a = √2 , b = - 5 , c = √2
Value of Discriminant
= b² - 4ac
= (-5)² - 4 * √2 * √2
= 25 - 8
= 17
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is 0 a whole number?
Answer: Yes.
Step-by-step explanation:
Yes, zero is a whole number. Zero isn't a fraction or decimal and it isn't negative. This means that zero is a whole number because it aligns with the rules of a whole number.
When 3(2x + 5) is added to 2(2x − 4) the resulting expression is?
Answer:
10x + 7
Step-by-step explanation:
3(2x + 5) added to 2(2x - 4) is the same as 3(2x +5) + 2(2x - 4)
Remember PEMDAS
P – Parentheses (distribution)
E – Exponents
M – Multiplication
/D – Division (whichever comes first from left to right)
A – Addition
/S – Subtraction (whichever comes first from left to right)
First, we will distribute the left side.
3(2x + 5)
3 * 2x = 6x
3 * 5 = 15
Add them together to get:
6x + 15
6x + 15 + 2(2x - 4)
We must now distribute the right side.
2 * 2x = 4x
2 * -4 = -8
Add them together to get:
4x -8
We now have:
6x + 15 + 4x - 8
Let's combine like terms.
6x and 4x are like terms.
Combine: 6x + 4x = 10x
15 and -8 are like terms.
15 - 8 = 7
Now we have 10x + 7
Since 10 and 7 don't have any GCF, we have our answer.
10x + 7
~ \(InLoveWithPugs\)
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Math Enthusiast
Will make brainiest if 2 people answer :3
Answer:
1.6
Step-by-step explanation:
12.8/8 = 1.6
15.2/9.5 = 1.6
Scale factor = 1.6
The sum of a number and twice that number is equal to ss . In terms of ss , which of the following represents the smaller of the two numbers?
A) 3s
B) 2s
C) s
D) s/3
Answer:
2s
Step-by-step explanation:
timbers and the horses
In terms of ss , the one that represents the smaller of the two numbers is "s".
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
We are given that sum of a number and twice that number is equal to ss.
Let consider the two numbers are x and y. then
The sum of a number and twice that number is 2x
x + y = ss
x + 2x = ss
3x = ss
If we replace x by s then we the equation get;
3s = ss
Hence, In terms of ss , the one that represents the smaller of the two numbers is "s".
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Find the volume (in units3) generated when the region between the curves is rotated around the given axis. y = x3, y = 0, and y = 27 rotated around the y-axis
The Volume generated when the region between the curves is rotated around the y - axis is 1216500335.46
Volume of the curves:
The volume of the solid formed by revolving the region bounded by the curve x = f(y) and the y-axis between y = c and y = d about the y-axis is given by
V = π ∫dc [f(y)]2dy.
The cross-section perpendicular to the axis of revolution has the form of a disk of radius R = f(y).
Given,
y = x³
Here we have to find the volume along to the y axis.
With limit as y = 0 and y = 27.
When we apply the values it can be written as,
=>\(V=\pi \int\limits^0_{27} {(x^3)^2} \, dx\)
\(\implies V=\pi \int\limits^0_{27} {(x^6)} \, dx\)
Apply the limits then we get,
\(\implies V = \pi [0^6 - (27)^6]\)
=> V = π [0 - 387420489]
=> V = π x 387420489
=> V = 1216500335.46
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Help me to do this question plz plz plz plz
Answer:
2) 90-62=28°
3) 180-108=72°
4) 180-89=91°
please mark as brainliest
Help aspp please thank you
The equation of the line would be y = (-3/4)x + 5.
What is the slope-point form of the line?
For the line having slope "m" and the point (x1, y1) the equation of the line passing through the point (x1, y1) having slope 'm' would be
y - y1 = m(x - x1)
The given equation is \(y=-\frac{3}{4}x-17\)
The required line is parallel to the given line.
and we know that the slopes of the parallel lines are equal so the slope of the required line would be m = -3/4
And the required line passes through (8, -1)
so by using slope - point form of the line,
y - (-1) = (-3/4)(x - 8)
y + 1 = (-3/4)x - (-3/4)8
y + 1 = (-3/4)x + 24/4
y = (-3/4)x + (12/2 - 1)
y = (-3/4)x + 5
Hence, the equation of the line would be y = (-3/4)x + 5.
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Find the Tangent vector, the Normal vector, and the Binormal vector (→T, →N and →B) for the curve →r(t)=〈4cos(2t),4sin(2t),5t〉 at the point t=0. Round answers to 3 decimal places.
T(0) =0=[sqrt(89)= sqrt(89)]
N(0) =[ ]
B(0) =[ ]
The tangent vector → \(r(t)=〈4cos(2t),4sin(2t),5t〉\), normal vector at t=0 is given by →N(0) = 〈-1,0,0〉, and binormal vector at t=0 is given by →\(B(0) = 〈0, -0.441, -0.898〉\)
The tangent vector, normal vector, and binormal vector of the given curve are as follows:
Given curve:
→ \(r(t)=〈4cos(2t),4sin(2t),5t〉\) at the point t=0
To find: Tangent vector, the Normal vector, and the Binormal vector (→T, →N and →B) at the point t=0
Tangent vector: To find the tangent vector of the given curve
→\(r(t)=〈4cos(2t),4sin(2t),5t〉\) at the point t=0,
we need to differentiate the equation of the curve with respect to t.t = 0, we have:
→\(r(t) = 〈4cos(2t),4sin(2t),5t〉→r(0) = 〈4cos(0),4sin(0),5(0)〉= 〈4,0,0〉\)
Differentiating w.r.t t:→\(r(t) = 〈4cos(2t),4sin(2t),5t〉 → r'(t) = 〈-8sin(2t),8cos(2t),5〉t = 0\),
we have:
→\(r'(0) = 〈-8sin(0),8cos(0),5〉= 〈0,8,5〉\)
Therefore, the tangent vector at t = 0 is given by
→\(T(0) = r'(0) / |r'(0)|= 〈0,8,5〉 / sqrt(89)≈〈0.000,0.898,0.441〉\)
Normal vector:To find the normal vector of the given curve
→\(r(t)=〈4cos(2t),4sin(2t),5t〉\)
at the point t=0, we need to differentiate the equation of the tangent vector with respect to t.t = 0, we have:
→\(T(0) = 〈0.000,0.898,0.441〉\)
Differentiating w.r.t t:
→\(T'(t) = 〈-16cos(2t),-16sin(2t),0〉t = 0\),
we have:
→\(T'(0) = 〈-16cos(0),-16sin(0),0〉= 〈-16,0,0〉\)
Therefore, the normal vector at t = 0 is given by
→\(N(0) = T'(0) / |T'(0)|= 〈-16,0,0〉 / 16= 〈-1,0,0〉\)
Binormal vector: To find the binormal vector of the given curve
→\(r(t)=〈4cos(2t),4sin(2t),5t〉\)
at the point t=0, we need to cross-product the equation of the tangent vector and normal vector of the curve.t = 0, we have:
→\(T(0) = 〈0.000,0.898,0.441〉→N(0) = 〈-1,0,0〉\)
The cross product of two vectors:
→\(B(0) = →T(0) × →N(0)= 〈0.000,0.898,0.441〉 × 〈-1,0,0〉= 〈0, -0.441, -0.898〉\)
Therefore, the binormal vector at t = 0 is given by→B(0) = 〈0, -0.441, -0.898〉
Hence, the tangent vector, normal vector, and binormal vector of the given curve at t=0 are as follows:
→\(T(0) = 〈0.000,0.898,0.441〉→N(0) = 〈-1,0,0〉→B(0) = 〈0, -0.441, -0.898〉\)
The given curve is
→\(r(t)=〈4cos(2t),4sin(2t),5t〉 at the point t=0.\)
We are asked to find the tangent vector, the normal vector, and the binormal vector of the given curve at t=0.
the tangent vector at t=0. To find the tangent vector, we need to differentiate the equation of the curve with respect to t. Then, we can substitute t=0 to find the tangent vector at that point. the equation of the curve Is:
→\(r(t) = 〈4cos(2t),4sin(2t),5t〉\)
At t = 0, we have:
→\(r(0) = 〈4cos(0),4sin(0),5(0)〉= 〈4,0,0〉\)
We can differentiate this equation with respect to t to get the tangent vector as:
→\(r'(t) = 〈-8sin(2t),8cos(2t),5〉\)
At t=0, the tangent vector is:
→\(T(0) = r'(0) / |r'(0)|= 〈0,8,5〉 / sqrt(89)≈〈0.000,0.898,0.441〉\)
Next, we find the normal vector. To find the normal vector, we need to differentiate the equation of the tangent vector with respect to t. Then, we can substitute t=0 to find the normal vector at that point.
At t=0, the tangent vector is:
→\(T(0) = 〈0.000,0.898,0.441〉\)
Differentiating this equation with respect to t, we get the normal vector as:
→\(T'(t) = 〈-16cos(2t),-16sin(2t),0〉\)
At t=0, the normal vector is:
→\(N(0) = T'(0) / |T'(0)|= 〈-16,0,0〉 / 16= 〈-1,0,0〉\)
Finally, we find the binormal vector. To find the binormal vector, we need to cross-product the equation of the tangent vector and the normal vector of the curve.
At t=0, we can cross product →T(0) and →N(0) to find the binormal vector.
At t=0, the tangent vector is:
→\(T(0) = 〈0.000,0.898,0.441〉\)
The normal vector is:
→N(0) = 〈-1,0,0〉Cross product of two vectors →T(0) and →N(0) is given as:
→\(B(0) = →T(0) × →N(0)= 〈0.000,0.898,0.441〉 × 〈-1,0,0〉= 〈0, -0.441, -0.898〉\)
Therefore, the tangent vector, normal vector, and binormal vector of the given curve at t=0 are:
→\(T(0) = 〈0.000,0.898,0.441〉→N(0) = 〈-1,0,0〉→B(0) = 〈0, -0.441, -0.898〉\)
The tangent vector of the given curve
→\(r(t)=〈4cos(2t),4sin(2t),5t〉\)
at the point t=0 is given by →\(T(0) = 〈0.000,0.898,0.441〉.\)
The normal vector at t=0 is given by →N(0) = 〈-1,0,0〉.
The binormal vector at t=0 is given by →B(0) = 〈0, -0.441, -0.898〉.
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how many samples of size n=2 can be drawn from this population
The samples of size n = 2 that can be drawn from this population is 28
How many samples of size n=2 can be drawn from this populationFrom the question, we have the following parameters that can be used in our computation:
Population, N = 8
Sample, n = 2
The samples of size n = 2 that can be drawn from this population is calculated as
Sample = N!/(n! * (N - n)!)
substitute the known values in the above equation, so, we have the following representation
Sample = 8!/(2! * 6!)
Evaluate
Sample = 28
Hence, the number of samples is 28
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Complete question
A finite population consists of 8 elements.
10,10,10,10,10,12,18,40
How many samples of size n = 2 can be drawn this population?
I need help with this it's for my E2020 class
Answer:
\(f = \frac{ - 6g}{5} \)
Step-by-step explanation:
6f + 9g = 3g + f
6f - f = 3g - 9g
5f = - 6g
\(f = \frac{ - 6g}{5} \)
Answer:
B
Step-by-step explanation:
10. What is the solution of the initial value problem x' = [1 −5] -3 x, x(0) = ? H cost 2 sin t (a) e-t sin t -t (b) cost + 4 sin t sin t (c) cost + 2 sint sin t cost + 2 sint (d) sin t cost + 4 sin t (e) sin t e -2t e e-2t
The solution of the given initial value problem is e-2t[cos t + 2 sin t].
Given that the initial value problem isx' = [1 -5] -3 xand x(0) = ?We know that if A is a matrix and X is the solution of x' = Ax, thenX = eAtX(0)
Where eAt is the matrix exponential given bye
Summary: The initial value problem is x' = [1 -5] -3 x, x(0) = ?. The matrix can be written as [1 -5] = PDP-1, where P is the matrix of eigenvectors and D is the matrix of eigenvalues. Then, eAt = PeDtP-1= 1 / 3 [2 1; -1 1][e-2t 0; 0 e-2t][1 1; 1 -2]. Finally, the solution of the initial value problem is e-2t[cos t + 2 sin
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1) There are 8 college basketball teams in a certain
Sub-Division
How many ways are there to choose 6 teams for the playoffs?
There are 28 ways to choose 6 teams for the playoffs if there are 8 college basketball teams in a certain sub-division.
To determine the number of ways to choose 6 teams for the playoffs out of the 8 college basketball teams in a certain Sub-Division, we can use the combination formula. The formula for combinations is given by
nCr = n! / (r! * (n-r)!),
where n represents the total number of teams and r represents the number of teams to be chosen.
In this case, n = 8 and r = 6.
Plugging in these values, we have
8C6 = 8! / (6! * (8-6)!) = 8! / (6! * 2!) = (8 * 7) / (2 * 1) = 28.
Therefore, there are total 28 ways to choose 6 teams.
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0.93=
please explain how you got the answer.
determine whether the domain is continuous or discreet:
-input years: 1, 2, 3
-output height of tree(feet): 6, 9, 12
Answer:
34
Step-by-step explanation: