Question 6 of 25Simplify the radical expression below.이히O A.A.v28O B.9O c.NIC3

sinusoidal curve equation 29 sin (\(\pi\)/9 x)-49

Given the graph of a sinusoidal function, we can write its equation in the form y = A·sin(B(x - C)) + D using the following steps. D: To find D, take the average of a local maximum and minimum of the sinusoid. y=D is the "midline," or the line around which the sinusoid is centered.

In the state of Michigan, the lowest average temperature of the year is in January and is about 20 °F.

The highest monthly average temperature occurs in July at 78 °F

Assume the period is 12 months and January is at the origin of the graph of this function.

sinusoidal curve equation that models the data y

Then, Graph the curve using x = 0 for January, and x = 11 for December, so that x = 12 will be the start of the next year, or end of the period.

So, using the property of sinusoidal curve equation we have

=29 sin (\(\pi\)/9 x)-49

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Step-by-step explanation:

It is important to know that the diagonals of a rhombus are PERPINDICUALR bisectors of each other .   Opposite angles are equal and adjacen angles sum to 180 degrees .

Then remember alternate angles are equal  and there are 180 degrees inside of a triangle .....then you should be able to solve these...here is the first one

Answer:

14=-2x-4

18=-2x

x=-9

Hope This Helps!!!

M<2 + M<3 = 180 degrees, as this is the sum of all angles in a triangle.

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Answer:

1) 7/8     8/7

2) 4.4

3) 3.7

4) 2.8

Step-by-step explanation:

Length of bottom side of Figure A: 8 cm

Length of bottom side of Figure B: 7 cm

From Figure A to Figure B, the scale factor is 7/8.

7/8

8/7

5 × 7/8 = 35/8 = 4.375

4.4

3.2 × 8/7 = 3.657...

3.7

3.2 × 7/8 = 2.8

2.8

Answer:

-2,2

Step-by-step explanation:

Let

\(y_1=4x^2-c^2\)

\(y_2=c^2-4x^2\)

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

\(y_1=y_2\)

\(4x^2-c^2=c^2-4x^2\)

\(4x^2+4x^2=c^2+c^2\)

\(8x^2=2c^2\)

\(x^2=c^2/4\)

\(x=\pm \frac{c}{2}\)

Now, the area bounded by two curves

\(A=\int_{a}^{b}(y_2-y_1)dx\)

\(A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx\)

\(\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx\)

\(\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx\)

\(\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}\)

\(\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))\)

\(\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))\)

\(\frac{32}{3}=2(c^3-\frac{c^3}{3})\)

\(\frac{32}{3}=2(\frac{2}{3}c^3)\)

\(c^3=\frac{32\times 3}{4\times 3}\)

\(c^3=8\)

\(c=\sqrt[3]{8}=2\)

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

i might have read this problem wrong since i didnt get a clear understanding because of the wording of this problem but i will do the best i can!

step-by-step explanation:

first step is to make a table! and ill just make one on here so you can get a better understanding on this problem :)

----------------------------------

| boxes sold (b) | money collected (m) |

----------------------------------

|    1    |          1.50           |

----------------------------------

|    2    |          3           |

----------------------------------

|    3    |          4.50            |

----------------------------------

|    4    |          6           |

----------------------------------

|   5    |          7.50           |

----------------------------------

|   6    |          9           |

----------------------------------

|   7    |          10.50           |

----------------------------------

|   8    |          12           |

----------------------------------

(b * 1.50) = m

the independent variable = boxes sold (b)

the dependent variable = money collected (m)

hope this helps you and please tell me if i did something wrong or if you need extra help understanding this problem! :)

Answer:

The null hypothesis is \(H_0: p_1 - p_2 = 0\)

The alternate hypothesis is \(H_a: p_1 - p_2 \neq 0\)

The pvalue of the test is 0.03 < 0.05, which means that we have enough evidence to accept the alternative hypothesis that he proportion of people who wear life vests while riding a jet ski is not the same as the proportion of people who wear life vests while riding in a boat.

Step-by-step explanation:

Before testing the null hypothesis, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \(\mu = p\) and standard deviation \(s = \sqrt{\frac{p(1-p)}{n}}\)

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Out of 500 randomly selected people who rode a jet ski, 85% wore life vests.

This means that \(p_1 = 0.85, s_1 = \sqrt{\frac{0.85*0.15}{500}} = 0.016\)

Out of 250 randomly selected boaters, 90.4% wore life vests.

This means that \(p_2 = 0.904, s_2 = \sqrt{\frac{{0.904*0.096}{250}} = 0.019\)

Test the claim that the proportion of people who wear life vests while riding a jet ski is not the same as the proportion of people who wear life vests while riding in a boat.

At the null hypothesis, we test that the proportions are the same, that is, the subtraction between them is zero. So

\(H_0: p_1 - p_2 = 0\)

At the alternate hypothesis, we test that the proportions are different, that is, the subtraction between them is different of zero. So

\(H_a: p_1 - p_2 \neq 0\)

The test statistic is:

\(z = \frac{X - \mu}{s}\)

In which X is the sample mean, \(\mu\) is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \(\mu = 0\)

From the two samples, we have that:

\(X = p_1 - p_2 = 0.85 - 0.904 = -0.054\)

\(s = \sqrt{s_1^2+s_2^2} = \sqrt{0.016^2 + 0.019^2} = 0.0248\)

Test statistic:

\(z = \frac{X - \mu}{s}\)

\(z = \frac{-0.054 - 0}{0.0248}\)

\(z = -2.17\)

Pvalue of the test and decision:

The pvalue of the test is the probability that the difference differs from 0 by at least 0.054, which is P(|Z| > 2.17), which is 2 multiplied by the pvalue of z = -2.17

Looking at the z-table, z = -2.17 has a pvalue of 0.015

2*0.015 = 0.03

The pvalue of the test is 0.03 < 0.05, which means that we have enough evidence to accept the alternative hypothesis that he proportion of people who wear life vests while riding a jet ski is not the same as the proportion of people who wear life vests while riding in a boat.

Answer:

x = 22.2

Step-by-step explanation:

Let's set up this problem using cosine law:

x^2 = a^2 + b^2 -2abcos110

where a = 12, b = 15

x^2 = (12)^2 + (15)^2 - 2(12)(15)cos110

= 144 + 225 - 360(-0.342)

= 492

x = 22.2

The domain and the range of the piecewise function in this problem are given as follows:

The function in this problem is defined for all values of x between -6 and 2, except x = 0, and assumes all values of y between 0 and 6, except y = 1, hence the domain and range are given as follows:

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(c) The argument is valid, and we can conclude that Penelope missed class because she got a detention.

(e) The argument is valid, and we can conclude that Penelope did not miss class because she got an A and did not get a detention.

(c) To prove this argument's validity, we need to define the predicates and express the hypotheses and conclusion using them:

Let "M(x)" be the predicate "x missed class", and "D(x)" be the predicate "x got a detention".

Hypotheses: M(Penelope), D(Penelope)

Conclusion: M(Penelope)

Using modus ponens, which states that if P implies Q and P is true, then Q must be true, we can conclude that M(Penelope) is true:

From M(Penelope) and "Every student who missed class got a detention", we have D(Penelope)

From D(Penelope), we have M(Penelope)

So, the argument is valid, and we can conclude that Penelope missed class because she got a detention.

(e) To prove this argument's validity, we need to define the predicates and express the hypotheses and conclusion using them:

Let "M(x)" be the predicate "x missed class", "D(x)" be the predicate "x got a detention", and "A(x)" be the predicate "x got an A".

Hypotheses: A(Penelope), ~D(Penelope)

Conclusion: ~M(Penelope)

Using modus tollens, which states that if P implies Q and Q is false, then P must be false,

we can conclude that M(Penelope) is false:

From A(Penelope) and "Every student who missed class or got a detention did not get an A",

we have ~M(Penelope) & ~D(Penelope)

From ~D(Penelope), we have ~M(Penelope)

So, the argument is valid, and we can conclude that Penelope did not miss class because she got an A and did not get a detention.

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The reason that justifies the second statement "Angle L is congruent to angle T" is:

In a parallelogram, opposite angles are congruent.

Option C is the correct answer.

A parallelogram is a quadrilateral that has two pairs of parallel sides.

In a parallelogram, opposite sides and angles are equal.

The adjacent angles add up to 180 degrees.

We have,

Parallelogram LENS and parallelogram NGTH

Now,

Parallelogram LENS:

∠L = ∠N _____(1)

Opposite angles are equal.

Parallelogram NGTH:

∠N = ∠T ______(2)

Opposite angles are equal.

Now,

∠ENS = ∠GNH

Vertical angles are equal.

So,

From (1) and (2).

∠L = ∠T

Angle L is congruent to angle T

Thus,

Angle L is congruent to angle T

[ In a parallelogram, opposite angles are congruent ].

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Divide total distance by total time:

-90 /9 = -10

Answer: -10 feet per second

Answer:

The change in the Parachutists elevation each second is 10ft

Step-by-step explanation:

If you divide the elevation -90ft by 9 seconds you will get the feet per second. (-90/9) Hope this helps :D

Answer:

60

Step-by-step explanation:

if she learns 5 new facts each chapter and has 12 chapters to read you should multiply 12 and 5

The equation given in slope-intercept form does not represent the graph because the y-intercept of the graph is equal to 4 while the y-intercept of the equation is equal to 5.

In Mathematics, the slope-intercept form of a line can be calculated by using this linear equation:

y = mx + c

Where:

In Mathematics, the y-intercept of any graph such as a linear function, generally occur at the point where the value of "x" is equal to zero (x = 0).

Based on the information provided regarding the equations and graphs, the y-intercept are as follows:

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answer: 85+85+85+25



Answer:

A. Using the lens equation, 1/p + 1/q = 1/f, and substituting f = 5 cm and q = 7 cm, we can solve for p:

1/p + 1/7 = 1/5

Multiplying both sides by 35p, we get:

35 + 5p = 7p

Simplifying and rearranging, we get:

2p = 35

Therefore, the distance from the lens to the object, p, is:

p = 35/2 cm

B. Solving the lens equation, 1/p + 1/q = 1/f, for q, we get:

1/q = 1/f - 1/p

Substituting f = 5 cm, we get:

1/q = 1/5 - 1/p

Multiplying both sides by 5qp, we get:

5p = qp - 5q

Simplifying and rearranging, we get:

q = 5p / (p - 5)

Therefore, the expression that gives q as a function of p is:

q = 5p / (p - 5)

C. Here is a sketch of the graph of q(p):

The graph is a hyperbola with vertical asymptote at p = 5 and horizontal asymptote at q = 5. The image distance q is positive for object distances p greater than 5, which corresponds to a real image. The image distance q is negative for object distances p less than 5, which corresponds to a virtual image.

D. Taking the limit of q as p approaches infinity, we get:

lim q(p) = 5

This represents the horizontal asymptote of the graph. As the object distance becomes very large, the image distance approaches the focal length of the lens, which is 5 cm.

Taking the limit of q as p approaches 5 from the positive side, we get:

lim q(p) = -infinity

This represents the vertical asymptote of the graph. As the object distance approaches the focal length of the lens, the image distance becomes infinitely large, indicating that the lens is no longer able to form a real image.

In order for the lens to form a real image, the object distance p must be greater than the focal length f. When the object distance is less than the focal length, the lens forms a virtual image.

Answer:

I think is it 27 divided by 3 or 3/27

Step-by-step explanation:

Answer:

I think it's the first

Step-by-step explanation:

When h = 4, j = 5, and k = -1, the expression jkh + hj - jk equals 5.

To solve the expression we have to substitute the value of each variable in the expression. Then simplify the expression according to mathematic rule. After solving we get the solution of the expression.

An expression is a combination of numbers, variables, and/or operations that can be evaluated or simplified to obtain a numerical or algebraic result.

The given expression is:

jkh + hj - jk

Substituting the given values of h, j, and k, we get:

jkh + hj - jk = (5 x (-1) x 4) + (5 x 4) - (5 x (-1))

Now simplify the expression

jkh + hj - jk = (-20) + 20 + 5

jkh + hj - jk = 5

Therefore, the value of  jkh + hj - jk equals 5.

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Answer:

\(y =\frac{x}{4}\)

Step-by-step explanation:

We are given several functions, and we want to figure out which one is linear.

A linear function has both of its variables (x and y) with a power of 1. Variables with other powers do not mean that the function is linear.

Let's go through the list.

Starting with \(y=\frac{3}{x} -7\), we can see that x is in the denominator. If this is the case, it means that the power of x is -1.

Even though y has a power of 1, this is NOT linear, because x has a power of -1.

Now, with y=√x-2, this is also not linear. This is because √x = \(x^\frac{1}{2}\), even though y has a power of 1.

For x² - 1 = y, we can clearly see that x has a power of 2, while y has a power of 1. This means that the function is not linear.

This leaves us with \(y = \frac{x}{4}\). x is in a fraction, however it is not in the denominator. This means that the power of x in this function is 1. We can also see that the power of y in this function is 1.

This means that \(y=\frac{x}{4}\) is linear.

An explicit description of Nul A is given by the set of vectors {[0, 0, 1, 0], [0, 0, 0, 1]}.

What is the explicit description of a null space matrix?

To find an explicit description of the null space of matrix A, we can find a spanning set of vectors that span the null space.

The null space of matrix A, denoted Nul A, is the set of all vectors x that satisfy the equation Ax = 0. In other words, the null space consists of all vectors that are mapped to the zero vector by the matrix A.

To find a spanning set for Nul A, we can use the following steps:

Row reduces the matrix A to a reduced row-echelon form using elementary row operations.

Identify the free variables in the row-reduced matrix.

For each free variable, create a vector with a 1 in the position corresponding to the free variable and 0's in all other positions.

The set of vectors created in step 3 form a spanning set for Nul A.

For example, consider the matrix A = [1, 2, 3, 0; 0, 0, 1, 0]. To find a spanning set for Nul A, we can row reduce the matrix to reduced row-echelon form:

[1, 2, 3, 0] -> [1, 2, 3, 0]

[0, 0, 1, 0] -> [0, 0, 1, 0]

The matrix is already in reduced row-echelon form, so there are no more elementary row operations to perform. The free variables in this matrix are the third and fourth columns, which correspond to the variables x3 and x4, respectively. Therefore, we can create the following vectors:

x3 = [0, 0, 1, 0]

x4 = [0, 0, 0, 1]

These vectors form a spanning set for Nul A, as they are linearly independent and span the null space.

Hence, an explicit description of Nul A is given by the set of vectors {[0, 0, 1, 0], [0, 0, 0, 1]}.

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Answer:

------------------------

Find the slope of AB:

Use point-slope form and point A(2, 4) to determine the line:

Multiply both sides by 9 to clear fraction:

Open parenthesis and convert the equation into ax + by + c = 0:

Hence the output variable (total weekly earnings) is a function of the input variable (number of hours worked as a payroll clerk) and may be expressed by the equation y = 16x + 120.

A variable is anything that may be altered in the context of a mathematical notion or experiment. Variables are frequently denoted by a single symbol. .

a. Input variables: hours worked as a cashier, payroll clerk, and assistant.

The total amount earned each week is the output variable.

b. To determine the weekly total, multiply the number of hours worked at each job by the hourly rate and put them together. As a result, the equation would be:

Total weekly wage = (hours worked as a cashier x cashier hourly rate) + (hours worked as a payroll clerk x payroll clerk hourly rate) + (hours worked as an aide x rate per hour as an aide)

c. The amount of hours worked as an assistant is always 10 hours fewer than that of a payroll clerk. Therefore, if x denotes the number of hours worked as a payroll clerk, then the number of hours worked as an assistant may be denoted as (x - 10).

d. The equation describing the total money earned each week is as follows:

(20 x 9.5) + (x x 9) + ((x - 10) x 7) = y

This expression is simplified as follows:

y = 190 + 9x - 70 + 7x

y = 16x + 120

Hence the output variable (total weekly earnings) is a function of the input variable (number of hours worked as a payroll clerk) and may be expressed by the equation y = 16x + 120.

f. The realistic replacement values for x would be determined by the maximum number of hours you may work at each job as well as the amount of time available to work. Working 8 hours as a payroll clerk may be a reasonable substitute value if you have restricted availability, but 50 hours is unlikely.

g. If you do not work as an aide, you may calculate your total weekly income by setting the number of hours worked as an aide to zero in the calculation for the total amount earned each week. This results in:

y = 16x + 120 + 0

y = 16x + 120

As a result, the total weekly wage would be determined only by the number of hours performed as a cashier and payroll clerk.

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The overhead cost would be assigned to Product J00A using the company's activity-based costing system is $4313.87.

The overhead cost that would be assigned to Product J00A using the company's activity-based costing system will be:

= ($86.50 × 34) + ($4.63 × 105) + ($52.16 × 17)

= $2941 + $486.15 + $886.72

= $4313.87

The overhead cost would be assigned to Product S06U using the company's activity-based costing system will be:

= ($86.50 × 43) + ($4.63 × 812) + ($52.16 × 32)

= $3719.50 + $3759.56 + $1669.12

= $9148.18

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The function g (x) is called an inner function and the function f (x) is called an outer function. Hence, we can also read f [g (x)] as “the function g is the inner function of the outer function f”.

Given that,

f(x) = 2x²+2  and

g(x)=x2-1

So find the (f- g)(x).

(f- g)(x) means,

Multiply x into f and g functions

Then, (f- g)(x) = f(x)-g(x)

Replace with f(x) and g(x) values in this equation

So,

(f- g)(x)= f(x)-g(x)

          = (2x²+2) - (x2-1)

Distribute the subtraction to all three of the last terms.          

          = 2x²+2-2x+1

          = 2x²-2x+2+1

Combine like terms

  (f- g)(x) = 2x²-2x+3

Therefore,

f(x) = 2x²+2 and

g(x)=x2-1,    

So,

       (f- g)(x) = 2x²-2x+3.

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Answer:

  y = {-1/2x +7 for x < 6; 1/2x +1 for x ≥ 6}

Step-by-step explanation:

You want y = 1/2|x -6| +4 written as a piecewise function.

The absolute value function changes its definition when its argument is negative:

  y = |x|   ⇒   y = -x for x < 0, and y = x for x ≥ 0

This means our piecewise function will have one definition for (x-6) < 0 and another for (x -6) ≥ 0.

The argument is negated in this domain, so we have ...

  y = -1/2(x -6) +4

  y = -1/2x +3 +4

  y = -1/2x +7

The absolute value function is an identity function in this domain:

  y = 1/2(x -6) +4

  y = 1/2x -3 +4

  y = 1/2x +1

Combining these descriptions into one, we have ...

  \(\boxed{y=\begin{cases}-\dfrac{1}{2}x+7&\text{for }x < 6\\\\\dfrac{1}{2}x+1&\text{for }x\ge6\end{cases}}\)

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Answer:

80 tickets

Step-by-step explanation:

Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of  tickets, x, that need to be sold for the drama club to break  even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;

y = x^2 – 40x – 3,200,

0 = x^2 – 40x – 3,200,

x^2 – 40x – 3,200 = 0

x^2 – 80x  + 40x – 3,200 = 0

x(x-80)+40(x-80) = 0

(x+40)(x-80) = 0

x = -40 and x = 80

x cannot be negative

Hence the total number of  tickets, x, that need to be sold for the drama club to break  even is 80 tickets

The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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