Points In LED dimmer circuit, if the PWM value send/write to the LED is 125, what is the value of the analog reading in the potentiometer? Note: Answer must be round off to whole number.

Answer:

See below

Explanation:

Check One-Sample T-Interval Conditions

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

One-Sample T-Interval Information

Problem 1

The critical t-value, as mentioned previously, would be \(t^*=2.0096\), making the 95% confidence interval equal to \(CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}\)

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

Answer:

point B where \(Q_B = 101.25 \ in^3\)  has the largest Q value at section a–a

Explanation:

The missing diagram that is suppose to be attached to this question can be found in the attached file below.

So from the given information ;we are to determine the  point that  has the largest Q value at section a–a

In order to do that; we will work hand in hand with the image attached below.

From the image attached ; we will realize that there are 8 blocks aligned on top on another in the R.H.S of the image with the total of 12 in; meaning that each block contains 1.5 in each.

We also have block partitioned into different point segments . i,e A,B,C, D

For point A ;

Let Q be the moment of the Area A;

SO ; \(Q_A = Area \times y_1\)

where ;

\(y_1 = (6 - \dfrac{1.5}{2})\)

\(y_1 = (6- 0.75)\)

\(y_1 = 5.25 \ in\)

\(Q_A =(L \times B) \times y_1\)

\(Q_A =(6 \times 1.5) \times 5.25\)

\(Q_A =47.25 \ in^3\)

For point B ;

Let Q be the moment of the Area B;

SO ; \(Q_B = Area \times y_2\)

where ;

\(y_2 = (6 - \dfrac{1.5 \times 3}{2})\)

\(y_2= (6 - \dfrac{4.5}{2}})\)

\(y_2 = (6 -2.25})\)

\(y_2 = 3.75 \ in\)

\(Q_B =(L \times B) \times y_1\)

\(Q_B=(6 \times 4.5) \times 3.75\)

\(Q_B = 101.25 \ in^3\)

For point C ;

Let Q be the moment of the Area C;

SO ; \(Q_C = Area \times y_3\)

where ;

\(y_3 = (6 - \dfrac{1.5 \times 2}{2})\)

\(y_3 = (6 - 1.5})\)

\(y_3= 4.5 \ in\)

\(Q_C =(L \times B) \times y_1\)

\(Q_C =(6 \times 3) \times 4.5\)

\(Q_C=81 \ in^3\)

For point D ;

Let Q be the moment of the Area D;

SO ; \(Q_D = Area \times y_4\)

since there is no area about point D

Area = 0

\(Q_D =0 \times y_4\)

\(Q_D = 0\)

Thus; from the foregoing ; point B where \(Q_B = 101.25 \ in^3\)  has the largest Q value at section a–a

Inadequate nutrition, pollution-associated health disorders and communicable illnesses, poor sanitation and housing conditions, and linked health conditions are some of the primary health concerns caused by urbanization. Hence, a properly planned topography will prevent these negative concerns.

The drafting of plans for, as well as the control and management of, towns, cities, and metropolitan regions falls within the purview of urban planning. It tries to arrange sociospatial linkages at many levels of government and governance.

Urban planning can help to create more livable and desirable communities by designing for walkability, accessibility, and green spaces.

It can help to create more efficient and sustainable communities by promoting the use of public transportation, promoting mixed-use development, and designing for energy efficiency. This can help to reduce greenhouse gas emissions, reduce traffic congestion, and save energy.

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The highest possible average flow velocity in the duct is the same at both the inlet and the outlet and can be determined by calculating the velocity using the cross-sectional area of the duct, which is π(0.15 m)².

To determine the highest possible average flow velocity in the duct, we can use Bernoulli's equation, which relates the pressure, velocity, and elevation of a fluid in a streamline.

Bernoulli's equation states:

P₁ + ½ρV₁² + ρgh₁ = P₂ + ½ρV₂² + ρgh₂

Where:

P₁ and P₂ are the pressures at points 1 and 2, respectively,

ρ is the density of the fluid,

V₁ and V₂ are the velocities at points 1 and 2, respectively,

g is the acceleration due to gravity,

h₁ and h₂ are the elevations at points 1 and 2, respectively.

Since the fan is raising the pressure of air by 50 Pa, we can consider P₂ as P₁ + 50 Pa.

To find the highest possible average flow velocity, we need to determine the pressure drop across the fan.

Since the fan is in a horizontal flow section, the elevations at points 1 and 2 are the same, and we can neglect the term ρgh₁ and ρgh₂.

The equation then simplifies to:

P₁ + ½ρV₁² = P₁ + 50 Pa + ½ρV₂²

Simplifying further:

½ρV₁² = 50 Pa + ½ρV₂²

We know that the fan needs to raise the pressure of air by 50 Pa to maintain the flow. Therefore, we can rewrite the equation as:

½ρV₁² = ½ρV₂²

Since the density ρ is the same on both sides, it cancels out, and we are left with:

V₁² = V₂²

Taking the square root of both sides, we get:

V₁ = V₂

This means that the highest possible average flow velocity in the duct occurs when the velocity at the inlet (V₁) is equal to the velocity at the outlet (V₂).

Therefore, the highest possible average flow velocity in the duct is the same at both the inlet and the outlet, and it can be determined by calculating the velocity of the airflow at either location.

To calculate the velocity, we can use the equation for the flow rate (Q) through a duct:

Q = A₁V₁ = A₂V₂

Where:

A₁ and A₂ are the cross-sectional areas of the duct at points 1 and 2, respectively.

The diameter of the duct is given as 30 cm, so the radius (r) is 15 cm or 0.15 m. The cross-sectional areas can be calculated as follows:

A₁ = πr₁² = π(0.15 m)²

A₂ = πr₂² = π(0.15 m)²

Since A₁ = A₂, the velocities V₁ and V₂ will also be equal.

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Answer:

5 rad/sec

0.796 Hz

1.256 seconds

Explanation:

Y(t) = 23sin5t ----1

Y(t) = aSin(w)t----2

w = 5 rad/sec

Then we get the Oscillation frequency from the formula below

w = 2πf

We make f to be the subject of this formula

f = w/2π

f = 5/2*3.24

f = 5/6.28

f = 0.796Hz

From the calculated frequency, we get the period = 1/f

= 1/0.796

= 1.256 seconds

Answer:

Parallel Axes / Spur Gear, Helical Gear, Gear Rack, Internal Gear.Intersecting Axes / Miter Gear, Straight Bevel Gear, Spiral Bevel Gear.Nonparallel, Nonintersecting Axes / Screw Gear, Worm, Worm Gear (Worm Wheel)

Answer:

Sarah is a professional interior designer.

Therefore, Sarah carries the title of a _registered___ interior designer.

Explanation:

Some states require only the licensed designers to carry out interior designs, while some others allow both the licensed and unlicensed interior designers to carry on the work of interior designers.  In the states where only the licensed designers are allowed to use the title of interior designer, they are registered after passing the state-prescribed examinations and meeting some professional experience requirements. The most common exam is the National Council for Interior Design Qualification (NCIDQ) examination, which only bachelor degree holders in interior design are allowed to sit for.

Answer:

Screw Gauge belong to brass group.

Explanation:

Screw gauge is used to measure the circumference of smaller objects.  Different  instruments belong to different groups. Screw gauge belong to brass category. There are 5 main categories of instruments which are, brass, wood, keyboard, strings and percussion.

Alloys were stronger and more durable

a. Deflecting Torque:

Deflecting torque refers to the torque exerted on a moving system, such as a galvanometer or a motor, due to an external force or a magnetic field. It is responsible for deflecting the system from its equilibrium position.

In the case of a galvanometer, the deflecting torque is given by the equation:

T_deflect = k * I * B * sin(θ),

where T_deflect is the deflecting torque, k is a constant specific to the galvanometer, I is the current passing through the coil, B is the magnetic field strength, and θ is the angle between the coil and the magnetic field.

b. Controlling Torque:

Controlling torque is the torque applied to a system to bring it back to its equilibrium position and counteract the deflecting torque. It helps in maintaining stability and accuracy in the system's operation.

The controlling torque can be calculated using the equation:

T_control = -k * θ,

where T_control is the controlling torque, k is the torsional constant of the system, and θ is the angular displacement from the equilibrium position.

c. Damping Torque:

Damping torque is a torque that opposes the motion of a system and reduces oscillations or overshooting. It is responsible for controlling the speed of the system and bringing it to a stop.

The damping torque is given by the equation:

T_damping = -b * ω,

where T_damping is the damping torque, b is the damping constant of the system, and ω is the angular velocity.

Deflecting torque, controlling torque, and damping torque play crucial roles in various systems. The deflecting torque deflects the system from its equilibrium position, while the controlling torque brings it back to equilibrium. The damping torque helps in reducing oscillations and controlling the speed of the system. Understanding and managing these torques are essential for the proper functioning and stability of mechanical and electrical systems.

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The type of architecture that deploys VPN so that traffic to and from the VPN is not firewalled is known as a split-tunnel VPN architecture.

In a split-tunnel VPN, only traffic destined for the organization's internal network goes through the VPN tunnel, while all other traffic goes directly to the internet. This means that traffic to and from external websites, applications, and services does not pass through the organization's firewall, reducing the load on the firewall and improving performance for users. Split-tunnel VPN architecture is typically used in large organizations with remote employees who need access to internal resources while still being able to access the internet for their personal needs. It is important to note that split-tunnel VPNs can increase security risks, as the internet traffic is not filtered by the organization's firewall, and remote users must ensure that their devices are secured with up-to-date antivirus and firewall software.

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Answer:

The plan is to make your design on AutoCAD and then make technical drawings. Print those technical drawings out with a scale of 1:1 and use those to trace over wood or metal.

Explanation:

Answer:

Make your design, make technical drawings, 3D print or trace

Explanation:

Option A holds the correct answer. Because the statement given in option A truly reflects the radial load and axial load.

When the load pressure is perpendicular to the axis of the shaft, a radial load is applied and when the load pressure is parallel to the axis of the shaft, an axial load is applied. In other words, the radial load is applied when the pressure from the load is 'perpendicular to the axis of the shaft'. In contrast, the axial load is applied when the pressure from the load is 'parallel to the axis of the shaft'.

However, the rest of the statements are not correct in the context of radial loads and axial loads.

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The spreadsheet can be set up to allow for additional density and percent crystallinity values to be inputted, and the formulas will update automatically. With this spreadsheet, the user can easily determine the density and percent crystallinity of the polymer for various values.

To develop a spreadsheet for the given polymer, we can use the following formulas:

(a) Density of totally crystalline polymer = Highest density value given
(b) Density of totally amorphous polymer = Lowest density value given
(c) Percent crystallinity of a specified density = (Density of the specified value - Density of totally amorphous polymer) / (Density of totally crystalline polymer - Density of totally amorphous polymer) x 100
(d) Density for a specified percent crystallinity = Density of totally amorphous polymer + (Specified percent crystallinity / 100) x (Density of totally crystalline polymer - Density of totally amorphous polymer)

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Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

The data string for a standard transaction can be compared to a sequence of information or instructions that are processed in a specific order to complete a transaction.

Just like a data string, a standard transaction consists of various elements or fields that convey specific information related to the transaction. These fields could include details such as transaction ID, date and time, customer information, product or service information, payment details, and any other relevant data required to complete the transaction.

The comparison highlights the structured nature of both the data string and the standard transaction, where each element plays a crucial role in ensuring the accuracy and completeness of the transaction process.

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Answer:

Resistance = 360,000 Ω = 360 kΩ

Tolerance = +/- 5%

Explanation:

You can follow a four-band resistor chart to determine resistance and tolerance based off each column.

1st Band = Orange = 3

2nd Band = Blue = 6

3rd Band = Yellow = 10,000 Ω (this is the multiplier)

Resistance = 36 * 10,000 Ω = 360,000 Ω = 360 kΩ

4th Band = Gold = +/- 5% Tolerance

The change in momentum of the object is equal to the impulse it experiences. F • t = m • v is an equation. When two objects collide, they both experience an impulse, which both causes and is equal to the change in momentum.

The impulse-momentum theorem predicts that an object's applied impulse will be equal to its changed momentum. As of late, we can clearly discern the impulse-momentum theorem.

In a collision, an object is subjected to a force for a predetermined period of time, changing the velocity of its mass. The impulse-momentum change theorem is what is used to prove this.

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I'd say number 4, number 3 looks like an exhaust valve

A suitable analysis for one discrete independent variable with four levels and one continuous dependent variable would be a one-way analysis of variance (ANOVA) .It allows for the comparison of means across the different levels and provides statistical evidence of any significant differences observed.

ANOVA is used to determine whether there are any significant differences between the means of two or more groups. In this case, the four levels of the discrete independent variable represent the different groups or categories being compared, while the continuous dependent variable represents the measurement or outcome being assessed.

By conducting a one-way ANOVA, we can assess whether there are any significant differences in the mean values of the continuous dependent variable across the four levels of the independent variable. The ANOVA analysis will provide an F-statistic, p-value, and potentially other relevant statistics that help determine the significance of the observed differences.

If the p-value is below a predetermined significance level (usually 0.05), it suggests that there are significant differences between at least two of the groups. In such cases, additional post-hoc tests, such as Tukey's Honestly Significant Difference (HSD) test, can be conducted to identify which specific groups differ significantly from each other.

Overall, a one-way ANOVA is an appropriate analysis to examine the relationship between a discrete independent variable with four levels and a continuous dependent variable. It allows for the comparison of means across the different levels and provides statistical evidence of any significant differences observed.

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Without specific details or the provided figure, it is not possible to determine the dollar value of the deadweight loss.

The given information refers to a figure related to foreign trade. However, since the figure is not provided, it is not possible to determine the specific details of the market and the deadweight loss.

Deadweight loss is a concept in economics that represents the loss of economic efficiency caused by market distortions, such as trade restrictions. It is typically measured as the area between the demand and supply curves under the restricted trade scenario.

Without the figure or any specific information about the market, it is not possible to determine the dollar value of the deadweight loss.

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Answer:

yes it is certainly good ice cream

Answer:

It is economical

Explanation:

Given data for determining

cost of product = £5 per kg

cost of solvent = £20 per /kg

additional solvent makeup = 10 kg/d

current loss of product = 0.7 kg/h

anticipated recovery of product = 80%

additional service ( utility cost ) = negligible

Determine if it is economical to install the recovery system

cost of product = £5 per kg

cost of solvent = £20 per /kg

additional solvent required = 10 kg / d

cost of additional solvent in a day  = £200 / day  ( £20 per kg * 10 kg / d )

product lost = 0.7 kg/h

product recovered = 0.7 * 80% = 0.56 kg/h

therefore product recovered in a day = 0.56 * 24 = 13.44 kg / day

Next :

calculate income generated from product recovery

13.44 kg/day *  £20 /kg =  £268.88 / day

Determine if it is economical

Income - cost

= £268.88 - £200

=  £68.88  ( hence it is economical )

The probability mass function of the random variable Y = 2X-1.5 points is \(f_Y(5) = f_X(3) = 1/6\)

a. To find E(X), multiply each value of x by its probability and add them.

\(E(X) = \sum [x * f(x)] = (1 * 3/6) + (2 * 2/6) + (3 * 1/6) = 1.5\)

b. To find σ of X, compute Var(X):

\(Var(X) = E(X^2) - (E(X))^2\\E(X^2) = \sum [x^2 * f(x)] = (1 * 3/6) + (4 * 2/6) + (9 * 1/6) = 3\\Var(X) = 3 - 1.5^2 = 0.75\)

σ = √Var(X) = √0.75 ≈ 0.87

c. Find P(Y).

\(f_Y(y) = f_X((y + 1) / 2) for y = 1, 3, 5\)

\(f_Y(1) = f_X(1) = 3/6\)

\(f_Y(3) = f_X(2) = 2/6\)

\(f_Y(5) = f_X(3) = 1/6\)

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The minimum number of 4 x 1 multiplexers required to design a 256 x 1 multiplexer is 2^252.

To design a 256 x 1 multiplexers, we can use the concept of hierarchical design by cascading multiple smaller multiplexers. In this case, we can use 8 x 1 multiplexers as building blocks.

The formula to calculate the number of smaller multiplexers required is:

Number of smaller multiplexers = (2^n) / (2^m)

Where:

n = Number of inputs of the larger multiplexer

m = Number of inputs of the smaller multiplexer

In our case, we have a 256 x 1 multiplexer, which means it has 256 inputs. The 4 x 1 multiplexer has 4 inputs. Substituting these values into the formula, we get:

Number of smaller multiplexers = (2^256) / (2^4)

Simplifying further, we have:

Number of smaller multiplexers = 2^252

Therefore, the minimum number of 4 x 1 multiplexers required to design a 256 x 1 multiplexer is 2^252.

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The minimum trade size RMC permitted to be installed, is 4 inches. If the RMC is being used to enclose the conductors and provide physical protection, the minimum trade size required is based on the number and size of the conductors contained within it.

The minimum trade size of rigid metal conduit (RMC) that is permitted to be installed between two panelboards that are 5 feet apart depends on the type of RMC being used and the number and size of the conductors contained within it.

In this case, there are four 4/0 AWG THHN/THWN conductors and one 4 AWG THHN/THWN ground conductor, which requires a minimum trade size of 4 inches according to Table 1 of the NEC.

Therefore, the minimum trade size of RMC that is permitted to be installed between two panelboards that are 5 feet apart, and containing four 4/0 AWG THHN/THWN conductors and one 4 AWG THHN/THWN ground conductor, is 4 inches.

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The research findings of Clark and Clark's (1939) doll study played a crucial role in Brown v. Board of Education

Brown vs Board of Education case, the Supreme Court ruled that segregation in public schools was unconstitutional, meaning it was against the law and not allowed.

This decision led to the integration of schools, allowing students of all races to attend the same schools. The Supreme Court decided that it was against the law to separate students in public schools because of their skin color in the Board of Education case. The Clark doll study showed how segregation affected African American kids, and it was done by two important psychologists named Kenneth and Mamie Clark.

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