PLS HURRY THIS IS DUE IN 5 mins
(a) Waves P and Q have the same
but wave P has twice the
of wave Q.
(b) Waves Q and R have the same
but wave R has twice the
of wave Q.
(c) Wave
shows a steady frequency but changing amplitude.
(d) Wave
shows steady amplitude but a changing frequency
Tel Waves
and
have a lowamplitude and a steadvafrecuency

PLS HURRY THIS IS DUE IN 5 Mins (a) Waves P And Q Have The Samebut Wave P Has Twice Theof Wave Q.(b)

Answers

Answer 1

Answer:

(a) Waves P and Q have the same  wavelength but wave P has twice the  amplitude of wave Q.

(b) Waves Q and R have the same amplitude  but wave R has twice the wavelength  of wave Q.

(c) Wave  T shows a steady frequency but changing amplitude.

(d) Wave  S shows steady amplitude but a changing frequency.

e) Waves  Q and R have a low amplitude and a steady  frequency.


Related Questions

of the battery and the resistances of resistors 1 and 2 are known, but the resistance of the variable resistor is unknown. the students want to determine the resistance of the variable resistor, but they only have an ammeter. one student proposes measuring the current through the battery, and the other proposes measuring the current through resistor 1. which of the measurements will allow the students to determine the resistance of the variable resistor?

Answers

Student 1 is right. If we measure current through the battery, We can determine the resistance of the variable resistor.

How can we determine unknown resistance in this case?

Let, current through the battery is I

Now, equivalent resistance of the circuit is given by,

\(R= \frac{R_1*(R_2+R_{unknown})}{ R_1+R_2+R_{unknown}}Current through the battery is given by, I=\frac{E}{R}= \frac{E*(R_1+R_2+R_{unknown})}{R_1*(R_2+R_{unknown})}By, solving the above relation we can get, the value of the unknown resistance.\)

In series circuit, the resistance of all the components adds up. If the resistance of individual component is R₁, R₂, R₃,...

Equivalent resistance for a series circuit is

R = R₁ + R₂+ R₃ +...

From Ohm's Law,

The current in series circuit is I = V R where R is equivalent resistance, V is the net voltage.

Voltage drop across each component is V₁, V₂,V₃,..

V₁ = I R₁

V₂ = I R₂

V₃ = I R₃

I R = I R₁ + I R₂+ I R₃ +...

⇒ R = R₁ + R₂+ R₃ +...

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Two cars have reached their destinations. One traveled 32 km north, and the other traveled 25 km
east. What is the distance between them?​

Answers

Answer:

NE = 40.61km

Explanation:

Given the following data;

North, N = 32

East, E = 25

To resultant distance, NE

We would use Pythagoras theorem;

NE² = N² + E²

NE² = 32² + 25²

NE² = 1024 + 625

NE² = 1649

Taking the square root of both sides

NE = 40.61km

Drag the tiles to the correct boxes to complete the pairs.
Recall how Newton’s investigation of light followed one form of the scientific method. Match the statements about Newton’s experiment with the steps in the scientific method.
Tiles
White light becomes a spectrum of seven
colored lights after passing through a prism.
What happens to a single color of light
when it passes through a prism?
A single color of light will not change
when it passes through a prism.
White light passes through a prism. A slit
is used to direct only the red light through
a second prism.
When the red light goes through a second
prism, its color does not change.
The hypothesis proposed for this experiment
is true.
The colors in a spectrum are part of white
light, and the prism separates them.
Pairs
Make an observation.
arrowBoth
Ask a question.
arrowBoth
Construct a hypothesis.
arrowBoth
Test the hypothesis with an investigation.
arrowBoth
Analyze the data.
arrowBoth
Confirm whether the hypothesis is true.
arrowBoth
Explain the results.
arrowBoth

Answers

Newton's optics experiment observation and intervention. In order to make his observations, Newton used the theory of light passing through prisms and the rays that were sent by them. It was revealed that light has a variety of properties and features.

Prisms, lenses, and optical rays were the basis of Newton's inquiry into light.According to him, different coloured lights had varying degrees of re-frangibility.Newton adopted the "Proof by Experiments" method to back up his theories. Each technique was chosen to highlight a particular quality of light.Newton found a phenomenon called the Newton rings.After pressing two prisms together, Newton saw that there was a translucent area.

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I added an image of the answers/ Hope this helps! good luck on it.

Drag the tiles to the correct boxes to complete the pairs.Recall how Newtons investigation of light followed

the joints that connect the four fingers with the mother carpal bones are

Answers

The joints that connect the four fingers (excluding the thumb) with the carpal bones are called metacarpophalangeal joints (MCP joints).

The metacarpophalangeal joints are located at the base of each finger, where the metacarpal bones of the hand articulate with the proximal phalanges of the fingers. These joints allow for flexion (bending) and extension (straightening) of the fingers and also provide some degree of rotational movement.

There are five metacarpophalangeal joints in total, one for each finger. They are commonly referred to as the knuckles.

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A 38-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface?

Answers

The horizontal force applied to the box to cause it to start sliding along the surface  is 111.72 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the horizontal force that must be applied. we use the formula below.

Formula:

F = mgμ............. Equation 1

Where:

F = Force applied to the boxm = Mass of the boxg = Acceleration due to gravityμ = Coefficient of static friction

From the question,

Given:

m = 38 kgg = 9.8 m/s²μ = 0.3

Substitute these values into equation 1

F = 38×9.8×0.3F = 111.72 N

Hence, the horizontal force applied to the box is 111.72 N.

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PLEASE HELP!!!
When your muscle gets tired, it builds up the _______ and makes it more powerful.


momentum


blood


cells


--------------------------------------------------------------------------------------------------------------------------------

.

When it comes to fitness, at the end of the day the most important thing is ____________.


motivation


acceptance


sleep

--------------------------------------------------------------------------------------------------------------------------------

You can best measure your own resting heart rate when you first wake up in the morning.


True

False

____________________________________________________________________

Your normal heartbeat before exercise is called your ____________________.


heart rate


muscle




tissue

Answers

Answer:

asd

Explanation:

a race car is traveling at a speed of 80.0m/s on a circular race track of radius 450m what is the centripetal acceleration

Answers

Answer:

The answer of this question is =1.258*10-4

It takes 6s for a stone to fall from the top of a building to the ground calculate i.the height of the building ii.the speed of the stone just before it strikes the ground (g=10ms^-2

Answers

Answer:

fffffff

Explanation:

A decrease in the price level results in a(n) ________ in the quantity of real GDP demanded because a lower price level ________ consumption, investment, and net exports.

Answers

A decrease in the price level results in an increase in the quantity of real GDP demanded because a lower price level stimulates consumption, investment, and net exports.

When the price level decreases, it means that the general level of prices for goods and services in the economy has fallen. This can have several effects:

Consumption: With lower prices, consumers can purchase more goods and services for the same amount of money. This increase in purchasing power encourages higher levels of consumption, leading to an increase in the quantity of real GDP demanded.

Investment: Lower prices can also reduce the cost of production for businesses. This can incentivize firms to invest in new projects or expand their existing operations, as they can produce goods and services at a lower cost. Increased investment boosts economic activity and contributes to higher real GDP demand.

Net Exports: A decrease in the price level can make domestic goods and services relatively cheaper compared to foreign goods and services. This can lead to an increase in exports as foreign consumers find the goods more affordable. At the same time, it can discourage imports as domestic consumers may choose cheaper domestic alternatives. This increase in net exports contributes to an overall increase in the quantity of real GDP demanded.

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A stray dog was taken to a veterinarian. What cell organelle would help the veterinarian determine the breed of the dog?
nucleus

vacuole

cytoplasm

chloroplast

Answers

Answer:

chloroplast will help determine the breed of dog

The nucleus can help determine what breed the dog is.

A wooden block of 16N is placed on a rough surface. If the coefficient of friction between both surface is 0.25,the least horizontal force required to move the block is?

Answers

The least horizontal force required to move the block is 4.0 N.

What is static  friction?

A force that holds an object at rest is called static friction.

The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.

Weight of the block = 16 N

The coefficient of friction between both surface is 0.25,

Hence, the least horizontal force required to move the block is = frictional resistance force

= 0.25 × 16 N

= 4 N.

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while standing at a crosswalk, you hear a frequency of 560 hz from an approaching police car. after the police car passes, its frequency is 480 hz. what is the speed of the police car? (speed of sound

Answers

We can presume that an ambulance with its siren activated is rushing to get somewhere and, depending on the driving circumstances, is likely travelling between 30 and 150 km/h. The vehicle's speed can be determined using the Doppler effect equation. Let va represent the ambulance's maximum speed. The frequency, f'=(vvv a)f=560Hz, is audible as it gets closer.

Because the source is travelling in the direction of the observer, a negative sign appears. The ambulance is described as moving away by the opposite sign with source velocity magnitude. The Doppler shifted frequency as it recedes is f')=(vv+v0)f=480Hz.

The speed of the source can be calculated as va=v(f'f')f'+f'=(343ms)(560Hz480Hz)560Hz+480Hz=26.4ms by solving the second of these equations for f and substituting into the other.

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d. A 15 cm long cube made of oak floats in water with 10.5 cm of its depth below the surface and with its sides vertical. What is the density of the cube? (density of water = 1000 kg m-³). [Ans: 750 kg/m³] ​

Answers

Answer:

700 kg /m3

Explanation:

formula

h in water x d of water = h total x d cube

10.5 x 1 = 15 x y

y = 10.5/15 g/cm3

ANS == 700kg/m3

what sample period if required if we wish to sampe the function g(t) = sinc(2t) at 2 times the rate required to avoid aliasing

Answers

The minimum sample period required is:

T = 1 / (2 x 1) = 1/2 ( we need to sample g(t) every 0.5 units of time or twice per unit of time)

When we sample a continuous-time signal, we need to ensure that we do not encounter aliasing, which occurs when the sampling rate is not sufficient to accurately represent the original signal.

To avoid aliasing in the function g(t) = sinc(2t), we need to sample it at a rate that is twice the maximum frequency present in the signal.

In this case, the maximum frequency is 1 Hz (half the bandwidth of the sinc function), so we need to sample it at 2 Hz.

Therefore, the sample period required to avoid aliasing is 1/2 = 0.5 seconds.

This means that we need to take a sample of the function every 0.5 seconds to ensure that we obtain an accurate representation of the original signal without aliasing.

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A(n)______circuit is a set of microscopic electronic components etched onto a thin slice of semiconducting material.

Answers

An integrated circuit is a set of microscopic electronic components etched onto a thin slice of semiconducting material.

The integrated circuit is a low coast circuit which consist of active and passive components that are joined together on a single crystal chip of silicon .It is also called microelectronic circuit or a microchip. Its short form is Ics and Ics can be designed as a digital device such as microprocessor, or logic gates , or analog devices such as audio & instrumental amplifiers.

The semiconductor materials are silicon , germanium and gallium arsenide.

And gallium arsenide is the second most common semiconductor after silicon. It is used in laser diodes, solar cells .

The microprocessor is can be described as that it is a computer processor logic and a small number of integrated circuit. It contains the arithmetic logics and perform the functions of a computer's central processing unit.

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We want to look at a number of thermodynamic transitions and see how much heat and work they produce. In all cases, the system considered is n
moles of an ideal gas with a specific heat of c~. All transitions are reversible. (a) The system starts at a temperature T and entropy Si, and goes isothermally to the state with temperature T and entropy S2. What is the work done and the heat produced? Express your answer in terms of T, S1, S, & and n (you
may or may not need all of these quantities). (b) The system starts at a temperature T1 and entropy S, and goes at constant entropy to the state with temperature T2 and entropy S. What is the work done and the the heat produced? Express your answer in terms of Th, T2, S, co
and n (you may or may not need all of these quantities).

Answers

:(a) The work done during the isothermal transition is zero, and the heat produced is Q = T(S2 - S1). (b) The work done during the constant-entropy transition is W = n(coT2 - ThT1), and the heat produced is Q = nTh(T2 - T1).

What are the work done and heat produced during the given thermodynamic transitions?

(a) During an isothermal transition of an ideal gas from temperature T and entropy S1 to temperature T and entropy S2, the work done is zero. This is because the volume change during the transition occurs at a constant temperature, resulting in no net work.

The heat produced during this transition can be calculated using the formula Q = T(S2 - S1), where T is the temperature and S2 and S1 are the entropies at the respective states.

(b) In a constant-entropy transition of an ideal gas from temperature T1 and entropy S to temperature T2 and entropy S, the work done can be determined using the formula W = n(coT2 - ThT1), where n is the number of moles of the gas, co is the specific heat, and Th is the absolute temperature. The heat produced during this transition can be calculated using the formula Q = nTh(T2 - T1).

the calculations involved in determining the work done and heat produced during different thermodynamic transitions of an ideal gas.

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an object that is 1.0 cm tall is placed on a principal axis of a concave mirror whose focal length is 15.0 cm. the base of the object is 10.0 cm from the vertex of the mirror. make a ray diagram with 2 or 3 rays that locate the image. using the mirror equation, and the magnification equation, and the proper sign convention, calculate the image distance and the magnification. is the image real or virtual? is the image inverted or upright compared to the object? is the image taller or shorter than the object?

Answers

To make a ray diagram for this problem, we can draw two rays from the top and bottom of the object, parallel to the principal axis and then reflecting off the mirror and converging at a point.

Another ray can be drawn from the top of the object through the focal point and then reflecting off the mirror parallel to the principal axis. This ray will also converge at the same point as the first two rays.

Using the mirror equation, we can find the image distance (di) as:

1/f = 1/do + 1/di

where f is the focal length of the concave mirror and do is the distance of the object from the mirror. Substituting the given values, we get:

1/15 = 1/10 + 1/di

Solving for di, we get:

di = -30 cm

The negative sign indicates that the image is virtual and upright.

Using the magnification equation:

m = -di/do

where m is the magnification. Substituting the given values, we get:

m = -(-30 cm) / 10 cm

m = 3

The positive magnification indicates that the image is upright compared to the object.

Finally, we can determine if the image is taller or shorter than the object by comparing their heights. Since the magnification is greater than 1, the image will be taller than the object. Therefore, the image is upright, virtual, and taller than the object.
In order to locate the image using a ray diagram and calculate the image distance, magnification, and determine the image properties, we will apply the mirror equation, magnification equation, and proper sign convention.

Mirror equation:
1/f = 1/u + 1/v
where f is the focal length, u is the object distance, and v is the image distance.

Given:
f = -15 cm (concave mirror has a negative focal length),
u = -10 cm (object distance is negative as per sign convention).

1/(-15) = 1/(-10) + 1/v
Solving for v, we get:
v ≈ -30 cm (image distance is negative, indicating a real image)

Magnification equation:
M = -v/u
M = -(-30)/(-10)
M = 3

The magnification is 3, indicating the image is taller than the object.

The image formed by the concave mirror in this case is real, inverted (since the magnification is negative), and 3 times taller than the object.

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The image formed by the concave mirror is real, inverted, and shorter than the object. The image distance is 6.0 cm, and the magnification is 0.6.

Determine how to find the image distance and magnification?

The image formed by the concave mirror is real, inverted compared to the object, and shorter than the object.

To locate the image, we can use the ray diagram method. Drawing two rays will be sufficient:

1. Ray 1: Draw a ray parallel to the principal axis that passes through the focal point on the opposite side of the mirror. After reflection, this ray will appear to pass through the focal point on the same side of the mirror.

2. Ray 2: Draw a ray that passes through the center of curvature of the mirror. This ray will be reflected back along the same path.

The point where these two rays intersect after reflection gives the location of the image.

Using the mirror equation:

1/f = 1/v - 1/u

Where:

f = focal length of the mirror (15.0 cm)

v = image distance from the mirror

u = object distance from the mirror (-10.0 cm, considering the object is placed on the same side as the incident light)

Substituting the values:

1/15.0 = 1/v - 1/(-10.0)

Simplifying the equation:

1/v = 1/15.0 + 1/10.0

Calculating:

1/v = 2/30 + 3/30 = 5/30

Taking the reciprocal:

v = 30/5 = 6.0 cm

Using the magnification equation:

magnification (m) = -v/u

Substituting the values:

m = -(6.0 cm)/(-10.0 cm) = 0.6

Therefore, the image distance is 6.0 cm and the magnification is 0.6.

The image formed by the concave mirror is real because the image distance is positive (6.0 cm). It is inverted compared to the object because the magnification is negative (-0.6).

The image is shorter than the object because the magnification (0.6) is less than 1.

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an object that is 1.0 cm tall is placed on a principal axis of a concave mirror whose focal length is

A 4.6pf capacitor initially uncharged is connected in series with 7.50kohm resistor and an emf source with e=125v[negligible internal resistance]. what is the voltage drop across the capacitor after the circuit is completed?

Answers

Without the value of time, we cannot calculate the voltage drop across the capacitor.

The given parameters are:

Capacitance, C = 4.6pF

Resistor, R = 7.50 kΩ

EMF, E = 125 V

The formula to calculate the voltage drop across the capacitor in the circuit is

 Vc = E (1 – e-t/RC) Where,

Vc = voltage across the capacitor E = EMF value R = resistance C = capacitance t = time

To obtain the voltage drop across the capacitor, the value of time is required. However, the time is not given in the question, which means we cannot calculate the voltage across the capacitor with the formula mentioned above.

Thus, it is not possible to calculate the voltage drop across the capacitor as the value of time is not given in the question.

A series circuit of an uncharged capacitor of capacitance 4.6 pF and a resistor of 7.50 kΩ is connected with an EMF source of 125V. The voltage drop across the capacitor is to be calculated using the formula

Vc = E (1 – e-t/RC)

Where Vc = voltage across the capacitor E = EMF value R = resistance

C = capacitance t = time

The time is not given in the question, and thus it is not possible to calculate the voltage drop across the capacitor.

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1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)

Answers

1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.

1b) The height of the tank is 2 m.

2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.

3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.

3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.

3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

1a) To calculate the amount of energy stored in the three weights, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

For the 4.5 kg weight:

E = 4.5 x 10 x 0.7 = 31.5 J

For each of the 3.5 kg weight:

E = 3.5 x 10 x 0.7 = 24.5 J

Thus, the total energy stored when all three weights are raised by 70 cm is:

31.5 J + 24.5 J + 24.5 J = 80.5 J

1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:

E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)

To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:

Mass = 200 kg

The height of the tank is 2 m.

Therefore, the gravitational potential energy stored in the water in the tank is:

E = mgh = 200 x 10 x 2 = 4000 J

Assumptions made in the answer:

We have assumed that the tank is full.

2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:

PE = KEPE = mghKE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:

PE = mgh = 200 x 10 x 2 = 4000 J

The potential energy is converted into kinetic energy when the water flows out of the taps.

Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)

3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:

Mass = Volume x Density

Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg

3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:

E = mgh

Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J

3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:

PE = KEP

E = mgh

KE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,

PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:

Power = Energy / Time

Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)

The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

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the main bonding jumper is located at the . a. last outlet in the branch circuit b. service disconnect c. ground rod or other grounding system d. meter enclosure

Answers

Bonding jumper is located at the service disconnect. This is the point in the electrical system where the main breaker or fuses are located, and where the power from the utility company enters the building.

The main bonding jumper is an important component that connects the grounded conductor (neutral) and the equipment grounding conductor to ensure a low-impedance path for fault currents. This helps to prevent electrical shock and fire hazards.

the main bonding jumper plays a crucial role in ensuring the safety and proper functioning of the electrical system, and it is located at the service disconnect.


To ensure safety and proper functioning of an electrical system, it is important to know the location of the main bonding jumper, which is at the service disconnect.

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Final answer:

The main bonding jumper is situated at the b) service disconnect. It plays a key role in ensuring safety by causing the circuit breaker to trip in case of a fault condition, which then forces the repair of the appliance. Besides, circuit breakers and GFCIs are also vital protective devices for preventing electrical accidents.

Explanation:

The main bonding jumper is typically located at the service disconnect (b), which is designed to interrupt the electric service for maintenance or emergency.

When the insulation of a live or hot wire is worn and it comes into direct contact with the metal casing of an appliance, it can cause a severe shock. However, if there's a proper earth or ground, the circuit breaker will trip and force the repair of the appliance.

Circuit breakers are important protective devices that prevent over-current situations by interrupting the electrical flow upon the detection of a fault condition. They are rated for a maximum current and can be reset after tripping. Another prominent protective device found particularly in kitchens and bathrooms is a Ground Fault Circuit Interrupter (GFCI), which responds quickly to changes in current and open if a change in the magnetic field produced by current-carrying conductors is detected.

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Which of the following is most likely to happen when energy is transferred to
an object?
A. The object will stay exactly the same.
B. The force on the object will decrease.
o
C. The object will begin to move.
D. The mass of the object will increase.
AUTEM

Answers

Answer:The object will begin to move

Explanation:

jimmy is a astronaut, when he was in space he drifted close to the sun. he said that he felt the hottest he had ever felt. what kind of heat transfer caused this?

Answers

The intense heat Jimmy felt when drifting close to the sun was primarily due to radiant heat transfer, as the sun's radiant energy reached him directly in the vacuum of space.

Radiant heat transfer occurs through electromagnetic waves, such as infrared radiation, which can travel through the vacuum of space. The sun emits an enormous amount of radiant energy, including visible light and a significant portion of infrared radiation. As Jimmy drifted closer to the sun, his proximity exposed him to a much higher intensity of radiant heat.

Unlike conduction or convection, which require a medium to transfer heat, radiant heat can travel through space without the need for a material medium. Consequently, even in the vacuum of space, the radiant energy emitted by the sun can reach Jimmy and warm his body directly.

This intense radiant heat transfer from the sun to Jimmy's body caused him to feel an unprecedented level of heat. The absence of a protective atmosphere or insulating medium amplified the effect of the sun's radiation, resulting in a scorching experience for the astronaut.

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dew forms when humid air cools overnight. if the temperature falls below freezing, blank will form instead

Answers

frost

i think this is right bc frozen water is just ice abs dew is water and frozen dew is frost

9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent
resistance for the bulbs in series? In parallel?

10. What would be the current through each light of problem 9?
For parallel circuit?
For series circuit?

-no bs answers

Answers

20 ohms 5 ohms
12volts

A boat heads north in still water at 4. 5 m/s directly across a river that is running east at 3. 0 m/s. What is the velocity of the boat with respect to earth?.

Answers

Answer:

5.

i am not sur

bcoz i am giving thos answer only for points

NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)
Group of answer choices

It does not explain why objects exert gravitational force.

It does not describe the relationship between objects and forces.

It can be changed by new experimentation and investigation.

It can be used to prove that theories on gravity are non-observable.

Answers

_______________________a

PLS HELP!!!! the image shows a chart to help!!
-The question is, "The following equations represents Chemical reactions. Which equation shows at the total mass during a chemical reaction stays the same?"
answer choice are:
A. equation 2
B. equation 1
C. equation 3
D. equation 4

PLS HELP!!!! the image shows a chart to help!! -The question is, "The following equations represents

Answers

I dont even know dude just send it 32-90

Two students sit on either side of a teeter-totter that is 2.8 m in length.
The teeter-totter balances when the student on the left side is 1.1 m
from the center and the student on the right is 1.4 m from the center.
The total mass of the two students is 78 kg . Assume that the teeter-
totter itself pivots at the center and produces zero torque.

What is the mass of the student on the left side of the teeter totter

Answers

The mass of the student on the left side of the teeter totter is 43.68 kg

Law of moments

Since the teeter totter is in equilibrium, the sum of moments about its center of mass is zero. That is, the clockwise moment, M = anticlockwise moments, M'

Taking moments of the students weight about the center, we have

m₁gx₁ = m₂gx₂ where

m₁ = mass of student on left, x₁ = distance of student on left from center = 1.1 m, m₂ = mass of student on right, x₂ = distance of student on right from center = 1.4 m and g = acceleration due to gravity.

m₁x₁ = m₂x₂

Given that their total mass is 78 kg, we have that m₁ + m₂ = 78.

So, m₂ = 78 - m₁

Substituting m₂ into the equation, we have

m₁x₁ = m₂x₂

m₁x₁ = (78 - m₁)x₂

Making m₁ subject of the formula, we have

m₁x₁ = 78x₂ - m₁x₂

m₁x₁ + m₁x₂ = 78x₂

m₁(x₁ + x₂) = 78x₂

m₁ = 78x₂/(x₁ + x₂)

Mass of student of left side of teeter totter

Substituting the values of the variables into the equation, we have

m₁ = 78x₂/(x₁ + x₂)

m₁ = 78 × 1.4 m/(1.1 m + 1.4 m)

m₁ = 109.2 kgm/2.5 m

m₁ = 43.68 kg

So, the mass of the student on the left side of the teeter totter is 43.68 kg

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why was the triple beam balance invented​

Answers

Answer:

The triple beam balance is an instrument used to measure mass very precisely. Such devices typically have a reading error of ±0.05 grams. ... The triple beam balance can be used to measure mass directly from the objects, find mass by difference for liquid, and measure out substances.

A car has an initial velocity of 24 km/h, the car then accelerates at 2 m/s² for 6 seconds. Calculate the final velocity in km/h.​

Answers

Answer:

final velocity in km/h= 67.2km/h

Explanation:

Data

initial velocity (u)= 24km/h

from 36km/h = 10m/s

then 24km/h= u

hence,

\(u= \frac{24}{36} \times 10\)

u= 20/3 m/s

Time= 6s

Acceleration= 2m/s²

\(v = u + at\)

\(v = \frac{20}{3} + 2(6)\)

\(v = \frac{20}{3} + 12\)

\(v = \frac{56}{3} \)

final velocity = 56/3 m/s

From 10m/s=36km/h

56/3 m/s = V

V(km/h)=

\( \frac{56}{3} \times \frac{36}{10} \)

V(km/h)=67.2km/h

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