Answer:
You can name an angle by a vertex name, by a number or by the three letters of the two segments forming the angle.
The names of the given angle:
∠Z∠1∠WZX∠XZWStep-by-step explanation:
\(\sf \angle \: Z\)
\(\sf \angle \: XZW\)
\(\sf \angle \: WZX\)
\(\sf \angle \: 1\)
Solve the system by substitution.
a + b - 2c = 14
4b + c = -1
C = -5
Answer:
a = 3 ; b = 1 ; c = -5
Step-by-step explanation:
Solving system of equations by substitution method:a +b - 2c = 14 -----------------------------(I)
4b + c = -1 -----------------------------(II)
c = -5 ------------------(III)
Substitute c = -5 in equation (II) and find the value of 'b',
4b + (-5) = -1
4b = -1 + 5
4b = 4
b = 4 ÷ 4
\(\sf \boxed{b = 1}\)
Substitute c = -5 and b = 1 in equation (I)
a + 1 - 2*(-5) = 14
a + 1 + 10 = 14
a +11 = 14
a = 14 - 11
\(\sf \boxed{a = 3 }\)
Verification:a + b - 2c = 14
LHS = a + b - 2c
= 3 + 1 - 2*(-5)
= 3 + 1 + 10
= 14 = RHS
Hence verified.
Answer:
(3, 1, - 5 )
Step-by-step explanation:
a + b - 2c = 14 → (1)
4b + c = - 1 → (2)
c = - 5 → (3)
substitute c = - 5 into (2)
4b - 5 = - 1 ( add 5 to both sides )
4b = 4 ( divide both sides by 4 )
b = 1
substitute b = 1 and c = - 5 into (1)
a + 1 - 2(- 5) = 14
a + 1 + 10 = 14
a + 11 = 14 ( subtract 11 from both sides )
a = 3
solution is (3, 1, - 5 )
as a check substitute values into (1) and (2)
a + b + c = 3 + 1 - 2(- 5) = 4 + 10 = 14 ← correct
4b + c = 4(1) - 5 = 4 - 5 = - 1 ← correct
what is the answer to 'Which problem would be solved using multiplication, and what is the solution to the problem?'
Answer:
Jim is 12 years old. Anna is 3 times older than Jim. Calculate Anna’s age using multiplication.
Step-by-step explanation:
The problem above is solved by using multiplication and the solution to the problem is 36.
you multiply 12 * 3 and you get 36.
hope that helps!
which expressions are equivalent to 2 to the power of 6? Choose ALL that apply
6x6x6x6x6x6
2x2x2x2x2x2
2x6
4x16
12x12
8x8
Answer:
2x2x2x2x2x2, 4x16, and 8x8
Step-by-step explanation:
the activity of a radioactive isotope is found to decrease by 40% in one week. what are the values of its: a) decay constant, b) half-life, c) mean lifetime?
Answer: A) The decay constant (λ) is a measure of the rate at which a radioactive isotope decays. It is defined as the probability per unit time that an atom of the isotope will decay. The decay constant can be calculated using the formula:
λ = -ln(1 - x) / t
Where x is the fraction of the original activity that has decayed (in this case, 0.40), and t is the time over which the decay occurred (in this case, one week).
B) The half-life (T1/2) is the amount of time it takes for half of the original activity of a radioactive isotope to decay. It can be calculated using the formula:
T1/2 = ln(2) / λ
C) The mean lifetime (τ) is the average amount of time an atom of a radioactive isotope will survive before it decays. It can be calculated using the formula:
τ = 1 / λ
It's important to note that the above formulas are based on the exponential decay model, which assumes that the decay process is random and that the decay constant is constant over time. If the isotope does not decay in this way, these formulas may not give accurate results.
Step-by-step explanation:
Lisa bought a treadmill for $925. She made a 20% down payment and financed the rest over 18 months. Find the monthly payment if the interest rate was 11%.
The monthly payment if the interest rate was 11% will be $45.63.
The remaining amount is calculated as,
P = (1 - 0.20) x $925
P = 0.80 x $925
P = $740
The monthly payment is calculated as,
MP = [$740 + ($740 x 0.11)] / 18
MP = $821.4 / 18
MP = $45.63
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The monthly payment is $49.69.
We have,
The amount of the down payment is:
0.20 x $925 = $185
So the amount financed is:
$925 - $185 = $740
Using the formula for the monthly payment on a loan:
= (Pr(1+r)^n) / ((1+r)^n - 1)
where:
P = principal or amount financed = $740
r = monthly interest rate = 11%/12 = 0.0091667
n = total number of payments = 18
Plugging in the values, we get:
Monthly payment
= ($7400.0091667 x (1+0.0091667)^18) / ((1 + 0.0091667)^18 - 1)
= $49.69 (rounded to the nearest cent)
Therefore,
The monthly payment is $49.69.
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The product of 6 and a number is the same as 40 less than twice that same number. Find the number.
Answer:
-10
Step-by-step explanation:
let the number=x
6x=2x-40
6x-2x=-40
4x=-40
x=-40/4=-10
9.03 which number is in the tenths place
Answer:
0
Step-by-step explanation:
think of the decimal as one
Answer:
Step-by-step explanation:
Zero (0) is in the tenths place here.
Refer to Exercise 17. a. Predict the total numbers of people who reported an earthquake 9 minutes and 15 minutes after it ended. b. The table shows the actual data. Describe the accuracy of your extrapolations in part (a). Minutes,x=9,15 People,y=2750,3200
The Correlation coefficient of the given data is 0.9889 and the linear regression equation is ŷ = 381.07143X - 565.71429.
What is the correlation coefficient?A correlation coefficient is a statistical indicator of how well changes in one variable's value predict changes in another. When two variables are positively linked, the value either rises or falls together.
Given a Table of data where x is minutes after the earthquake and y is people noticed that
x y
1 10
2 100
3 400
4 900
5 1400
6 1800
7 2100
M: 4 M: 958.5714
Sum of X = 28
Sum of Y = 6710
Mean X = 4
Mean Y = 958.5714
Sum of squares (SSX) = 28
Sum of products (SP) = 10670
Regression Equation = ŷ = bX + a
b = SP/SSX = 10670/28 = 381.07143
a = MY - bMX = 958.57 - (381.07*4) = -565.71429
Thus, the linear equation is ŷ = 381.07143X - 565.71429
For correlation coefficient
X Values
∑ = 28
Mean = 4
∑(X - Mx)2 = SSx = 28
Y Values
∑ = 6710
Mean = 958.571
∑(Y - My)2 = SSy = 4158085.714
X and Y Combined
N = 7
∑(X - Mx)(Y - My) = 10670
R Calculation
r = ∑((X - My)(Y - Mx)) / √((SSₓ)(SS))
r = 10670 / √((28)(4158085.714)) = 0.9889
Meta Numerics (cross-check)
r = 0.9889
Thus the correlation coefficient for the given data is 0.9889.
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What is the area of this figure?
Answer:
your mom
Step-by-step explanation:
y
This is a test question for underdstanding this feature
Answer:
i didn't understand what your question is
Which statement best describes how to slice a cone so that the resulting cross section is an ellipse
Cutting at less than a right angle to the axis but more than the angle made by the side of the cone produces an ellipse.
Therefore, with this above statement, the statement which best describes how to slice a cone so that the resulting cross-section is an ellipse is
A plane slicing the cone diagonally without intersecting the base
The correct option, therefore, is OPTION B
algebra work needed please help
If (-3,5) and (3,-5) are two points that lie on function f, then is f even, odd, or neither?
f(-3) ≠ f(3) and f(-3) ≠ -f(3), which means that the function f does not satisfy the properties required for it to be even or odd.
To determine whether the function f is even, odd, or neither, we need to evaluate the symmetry of the function with respect to the y-axis and the origin.
For a function to be even, it must satisfy the property f(x) = f(-x) for all values of x in the function's domain. This means that if we substitute -x for x in the function, we should obtain the same output as when we evaluate the function at x.
For a function to be odd, it must satisfy the property f(x) = -f(-x) for all values of x in the function's domain. This means that if we substitute -x for x in the function, we should obtain the negative of the output we obtain when we evaluate the function at x.
Let's evaluate the function f using the given points (-3,5) and (3,-5):
For the point (-3,5):
f(-3) = 5
For the point (3,-5):
f(3) = -5
We can see that f(-3) ≠ f(3) and f(-3) ≠ -f(3), which means that the function f does not satisfy the properties required for it to be even or odd.
We can conclude that the function f is neither even nor odd.
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Use the Table of Integrals to evaluate the integral. (Remember to use absolute values where appropriate.) / e4x dx 19 e8x e4x C 8 19 e4x 19 4x 19 + C 19 19 19 C 19 + C 19 19 + C 8 19 4x 19 0/1 points | Previous Answers SCalcET8 7.6.023. Use the Table of Integrals to evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) 33 sec5(x) dx X Use the Table of Integrals to evaluate the integral. 6х4е-x dx
The integration is as follow
\(\int\limits {e^{4x} / 19 - e^{8x}} \, dx\) = 1/8√19 log|(\(e^{4x}\) + √19)/ (\(e^{4x}\) - √19)| + C\(\int\limits {33 sec^5 (x)} \, dx\) = 33/4 tan x sec³x + 99/8 tan x sec x +99/8 log (sec x+ tan x) + CWhat is Integration?Finding an antiderivative of a function is the process of integration. If a function can be integrated and its integral across the domain is finite with the given bounds, then the integration is definite.
Given:
first, \(\int\limits {e^{4x} / 19 - e^{8x}} \, dx\)
= \(\int\limits {e^{4x} / 19 - e^{(4x)}^2} \, dx\)
let \(e^{4x}\) = z
4\(e^{4x}\) dx = dz
= 1/4 \(\int\limits {dz / \sqrt{19} ^2 -z^2} \,\)
= 1/4 x 1/2√19 log|(z+ √19)/(z-√19)| + C
= 1/8√19 log|(\(e^{4x}\) + √19)/ (\(e^{4x}\) - √19)| + C
Second,
\(\int\limits {33 sec^5 (x)} \, dx\)
= 33 [ 1/4 tan x sec³x + 3/4 ∫sec³x dx]
= 33/4 tan x sec³x + 99/4[ 1/2 tan x sec x +1/2 ∫sec x dx]
= 33/4 tan x sec³x + 99/8 tan x sec x +99/8 log (sec x+ tan x) + C
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When the Ford recall department performed their own crash test of the Pinto after field reports had come in, they discovered that the average speed at which the Pinto's fuel tank was likely to rupture in a rear-end collision was _____ miles per hour.
At the point when the Portage review division played out its own Crash Test of the Pinto, it found that the normal speed at which the Pinto's gas tank will crack was 25 miles each hour.
At the point when the Passage review division played out their own accident trial of the Pinto after field reports had come in, they found that the normal speed at which the Pinto's gas tank was probably going to burst in a backside impact was 25 miles each hour.
A crash test is a kind of destructive testing that is usually done to make sure that various modes of transportation or related systems and components meet safe design standards in terms of crashworthiness and compatibility.
The moving barrier, which resembles the front of a 1970s car, strikes the side of the test vehicle at a speed of 39 mph and an angle of 27 degrees during the NHTSA crash test.
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Please answer
Determine the common difference of the arithemetic sequence in which a1=3 and a4=15
Check the picture below.
The common difference of the arithmetic sequence in which a1=3 and a4=15 is d = 4
What is an arithmetic sequence?An arithmetic sequence is a sequence of integers with its adjacent terms differing with one common difference.
If the initial term of a sequence is 'a' and the common difference is of 'd', then we have the arithmetic sequence as:
a, a + d, a + 2d, ... , a + (n+1)d, ...
Its nth term is \(T_n = a + (n-1)d\)
(for all positive integer values of n)
And thus, the common difference is \(T_{n+1} - T_n\)
for all positive integer values of n
Given that a1=3 and a4=15
nth term of G.P is ;
Calculation:
\(T_n = a + (n-1)d\)
a1 = 3
a2 = 3+ d
a3 = 3+ d
a4=15
3 + 3d = 15
d =4
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Solve 2(1 - x) > 2x.
a.) O x < 0.5
b.) Ox> 2
c.) Ox<2
d.) O x > 0.5
Answer:
a) Ox<0.5 wjsjdhdjdjdj
Answer:
a.)x < 0.5
Step-by-step explanation:
2(1 - x) > 2x
2 - 2x > 2x
+2x +2x
2 > 4x
/4 /4
0.5 > x
Triangle ABC is a right triangle.What is the relationship between angles A and B?
Answer:
Step-by-step explanation:
They're congruent.
In general, higher confidence levels provide: a)narrower confidence intervals b)a smaller standard error c)wider confidence intervals d)unbiased estimates
In general, higher confidence levels provide wider confidence intervals.
What is the concept of confidence level and confidence interval?
Confidence level:
The confidence level refers to the long term success rate of the method , that is , how often this type of interval will capture the parameter of interest.
Confidence interval:
A specific confidence interval gives a range of plausible values for the parameter of interest.
As the confidence level increases, the width of confidence interval also increases.
A larger confidence level increases the chance that the correct value will be found in the confidence interval. This means the interval is larger.
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(i) Let V=2xy^2z ^3+3ln(x ^2+2y ^2+3z^2)N in free space. Guduate each of the following amounts in P(3,2,−1) (a) V (b) ∣V∣ (c) E (d) ∣E∣
The electric potential, V, is 73.63 N and the magnitude of the electric field is 12.00 V/m.
The given electric potential is,V=2xy²z³+3ln(x²+2y²+3z²) N
The components of the electric field can be found as follows,
E=-∇V=- (∂V/∂x) i - (∂V/∂y) j - (∂V/∂z) k
(a) To determine the potential at P(3, 2, -1), substitute x=3, y=2, and z=-1 in the given potential,
V=2(3)(2²)(-1)³ + 3 ln [(3)²+2(2)²+3(-1)²]= 72.32 N
(b) The magnitude of the potential is given by,
|V|= √ (Vx²+Vy²+Vz²)
The electric potential, V, is a scalar quantity. Its magnitude is always positive. Therefore,
|V|= √ [(2xy²z³)² + (3ln(x²+2y²+3z²))²]= √ [(-72)² + (16.32)²]= 73.63 N
(c) To determine the electric field E at P(3,2,-1), find the partial derivatives of V with respect to x, y, and z, and then substitute x=3, y=2, and z=-1 to obtain Ex, Ey, and Ez.
Ex = -(∂V/∂x)= -2y²z³/(x²+2y²+3z²) = -4.8 V/m
Ey = -(∂V/∂y)= -4xyz³/(x²+2y²+3z²) = -10.67 V/m
Ez = -(∂V/∂z)= -6xyz²/(x²+2y²+3z²) = 5.33 V/m
Therefore, the electric field E at P(3,2,-1) is, E=Exi+Eyj+Ezk=-4.8 i - 10.67 j + 5.33 k
(d) The magnitude of the electric field is given by,
|E|= √ (Ex²+Ey²+Ez²)= √ [(4.8)²+(10.67)²+(5.33)²]= 12.00 V/m
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Find the length of x. Round to nearest hundredth.
PLS I NEED HELP ANSWER WILL GIVE BRAINLIEST ANSWER BOTH QUESTIONS ONE AND TWO
Help pls, I’ve been struggling with this specific geometry field and my teacher kinda sucks at explaining things
Can y'all help me with my math problem please
Answer:
A
Step-by-step explanation:
Hello, option B is correct
On a map, an art gallery is located at (13,-3). A car wash is located at(13,-5) . If each unit on the map is a city block, how many city blocks is the art gallery from the museum?
Answer:
The art gallery is 2 city blocks from the car wash
Step-by-step explanation:
If the x-coordinates of two points on a line equal, then the line is a vertical lineThe length of a vertical segment whose endpoints are (x, y1) and (x, y2) is Iy2 - y1ILet us solve the question
∵ The art gallery is located at the point (13, -3)
∴ x1 = 13 and y1 = -3
∵ A car wash is located at (13, -5)
∴ x2 = 13 and y2 = -5
∵ x1 = x2 = 13
→ That means the gallery and the car wash located vertically over each other
∴ The distance between them = Iy2 - y1I
∵ y1 = -3 and y2 = -5
∴ The distance between them = I-5 - (-3)I
∴ The distance between them = I-5 + 3I
∴ The distance between them = I-2I
→ Remember the absolute value cancel the negative sign
∴ The distance between them = 2 units
∵ Each unit on the map is a city block
∵ The distance between them is 2 units
→ That means the vertical distance between them is 2 city blocks
∴ The art gallery is 2 city blocks from the car wash
How do you find the point slope form for the points (2,7) and (-1,9)?
Answer:
y = -2/3 x + 25/3
Step-by-step explanation:
The slope = (y_2 - y_1) / (x_2 - x_1) = (9 - 7) / (-1 - 2) = -2/3.
Our equation needs to be in y = mx + b form.
We can plug in (2, 7) as our (x, y) and find b:
7 = -2/3 (2) + b
b = 7 + 4/3 = 25 / 3.
Therefore, our equation is y = -2/3 x + 25/3
Use the Equation(in the picture) and plug in your variables to find m(slope)
\(\frac{9-7}{-1-2} = \frac{-2}{3} = -0.67\)
a • 9 for a = 2 I do not understand how to do it
Answer:
Answer is 18
Step-by-step explanation:
Substitute the variable.
2 x 9 =
Then solve
2 x 9 = 18
Prove that if f is differentiable at a, then |f| is also differentiable at a, provided that f(a)≠0
If a function f is differentiable at a point a and f(a) is not equal to zero, then the absolute value function |f| is also differentiable at that point.
The proof involves considering two cases based on the sign of f(a) and showing that the limit of the difference quotient exists for |f| at point a in both cases. However, it is important to note that |f| is not differentiable at the point where f(a) equals zero.
To prove that if f is differentiable at a, then |f| is also differentiable at a, provided that f(a) ≠ 0, we need to show that the limit of the difference quotient exists for |f| at point a.
Let's consider the function g(x) = |x|. The absolute value function is defined as follows:
g(x) = {
x if x ≥ 0,
-x if x < 0.
Since f(a) ≠ 0, we can conclude that f(a) is either positive or negative. Let's consider two cases:
Case 1: f(a) > 0
In this case, we have g(f(a)) = f(a). Since f is differentiable at a, the limit of the difference quotient exists for f at point a:
lim (x→a) [(f(x) - f(a)) / (x - a)] = f'(a).
Taking the absolute value of both sides, we have:
lim (x→a) |(f(x) - f(a)) / (x - a)| = |f'(a)|.
Since |g(f(x)) - g(f(a))| / |x - a| = |(f(x) - f(a)) / (x - a)| for f(a) > 0, the limit on the left-hand side is equal to the limit on the right-hand side, which means |f| is differentiable at a when f(a) > 0.
Case 2: f(a) < 0
In this case, we have g(f(a)) = -f(a). Similarly, we can use the same reasoning as in Case 1 and conclude that |f| is differentiable at a when f(a) < 0.
Since we have covered both cases, we can conclude that if f is differentiable at a and f(a) ≠ 0, then |f| is also differentiable at a.
Note: It's worth mentioning that at the point where f(a) = 0, |f| is not differentiable. The proof above is valid when f(a) ≠ 0.
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The area of a swimming pool is 119 square meters. The width of the pool is 7 meters. What is the length of the pool in centimeters?
Answer:
17 meters
Step-by-step explanation:
Area = Length x Width
Width = 7
Area = 119
Solving for: Length
Equation:
119 = 7 * x
Solving for Length (x) :
119 = 7 * x
x = 119/7
x = 17
Units = meters
Answer: 17 meters
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what is the value of p
Answer:
p = 61 degrees
Step-by-step explanation:
The sum of all angles that make up a striaght line is 180 degrees. To find p you just subtract the other angles from 180: 180 - 87 - 32 = 61.