Please help with Question(ii). I don't understand the shown step of calculating the momentum of ball B. Especially after the third line 12+Pb=15.

Answer:

The paper focuses on the biology of stress and resilience and their biomarkers in humans from the system science perspective. A stressor pushes the physiological system away from its baseline state toward a lower utility state. The physiological system may return toward the original state in one attractor basin but may be shifted to a state in another, lower utility attractor basin. While some physiological changes induced by stressors may benefit health, there is often a chronic wear and tear cost due to implementing changes to enable the return of the system to its baseline state and maintain itself in the high utility baseline attractor basin following repeated perturbations. This cost, also called allostatic load, is the utility reduction associated with both a change in state and with alterations in the attractor basin that affect system responses following future perturbations. This added cost can increase the time course of the return to baseline or the likelihood of moving into a different attractor basin following a perturbation. Opposite to this is the system's resilience which influences its ability to return to the high utility attractor basin following a perturbation by increasing the likelihood and/or speed of returning to the baseline state following a stressor. This review paper is a qualitative systematic review; it covers areas most relevant for moving the stress and resilience field forward from a more quantitative and neuroscientific perspective.

Explanation:

During a normal reaction to a stressful event, muscles are moved to their maximum capacity, and sensitivity is increased.

This is defined as the ability of an organism to respond to stimuli such as touch, sensation etc.

During exercise, sensitivity to substances such as insulin when glucose transport wears off helps to balance energy supply.

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Your question has been heard loud and clear.

Averge velocity formula=  Total distance travelled / total time taken.

Total distance=7meters

Total time taken=9 seconds.

Average velocity = 7/9= 0.77 metres/second

Average velocity= 0.77m/s

Thank you.

Answer:

angle of reflection and angle of incident is always equal

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

             b)  8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = \(\frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }\)  --  ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft  

a) determine the increase in speed

V = v - \(\sqrt{\frac{gR^2}{R + h} }\)  

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = \(\frac{3t}{2}\)

 = \(\frac{3*5670.76}{2}\)  =  8506.1 secs

attached below is the remaining part of the detailed solution

The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns

This is defined as the change in momentum of an object.

Impulse = change in momentum

Impulse = final moment – Initial momentum

Impulse = force × time

h = ½gt²

6.02 = ½ × 9.8 × t²

6.02 = 4.9 × t²

Divide both side by 4.9

t² = 6.02 / 4.9

Take the square root of both side

t = √(6.02 / 4.9)

t = 1.1 s

Impulse = Force × time

Impulse = 66.052 × 1.1

Impulse = 72.66 Ns

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What will happen to the magnitude of the field energy between them is that

Whenever there is a stored energy in an object at rest, the object will move in the direction that causes the energy stored to decrease, which will be replaced by movement energy.

Therefore, if two magnets with like poles are pointing together, then the energy stored will decrease as they move apart. Hence, as the distance between poles decreases, field energy increases.

Magnetic pole are region at each end of a magnet where the external magnetic field is strongest.

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If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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The minimum depth of harbor of the oil tank is 2.22 m

The given parameters:

mass of the oil tanker, m = 40,000 tonnes

length of the tanker, l = 500 m

width of the tanker, w = 40 m

To find:

minimum depth of harbor

Note: The specific gravity of oil is approximately 0.9

          The density of water (\(\rho_w\)) = 1000 kg/m³

Covert the given mass to kilogram

1 tonne = 1000 kg

40,000 tonnes = 40,000,000 kg

The density of the oil tanker is calculated as:

\(S.G = \frac{\rho_o}{\rho_w} \\\\\rho_o = S.G \times \rho_w\\\\\rho_o = 0.9 \times 1000\\\\\rho_o = 900 \ kg/m^3\)

The volume of the oil tanker is calculated as:

\(Volume = \frac{mass}{density} \\\\Volume = \frac{40,000,000}{900} \\\\Volume = 44,444.44 \ m^3\)

The minimum depth of harbor is calculated as:

\(height = \frac{volume}{Length \times width} \\\\height = \frac{44,444.44}{500\times 40} \\\\height = 2.22 \ m\)

The minimum depth of harbor of the oil tank is 2.22 m

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Answer:

94.4

Explanation:

it is

Answer:

94.4 i took the test and got it right :)

hope that helps

Explanation:

N2 + H2 --> NH3

balance them:

N2 + 3 H2 --> 2 NH3

so if 6 moles of N2 react, 12 moles of NH3 will form.

(you have to look at the big number in front, in this case its N2 and 2 NH3, therefore the amount of N2 will produce double the amount of NH3 )

The electrostatic force exerts on each other is 1.134 N

The electrostatic force between the two charges is given by Coulomb's Law:

F = k * |q1| * |q2| / r^2

where k is the Coulomb constant (9.0 x 10^9 N*m^2/C^2), |q1| and |q2| are the magnitudes of the two charges, and r is the distance between them.

Substituting the given values, we have:

F = (9.0 x 10^9 N*m^2/C^2) * (3.5 x 10^-6 C) * (1.8 x 10^-6 C) / (0.15 m)^2

F = 1.134 N

The electrostatic force exerted on each charge is equal in magnitude but opposite in direction, according to Newton's Third Law. Therefore, the magnitude of the force on each charge is 1.134 N, but they point in opposite directions. The force on q1 is attractive (toward q2), while the force on q2 is repulsive (away from q1).

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Based on the calculations, approximately 3,697,808 BTUs must be added to 34 lbs. of ice at -32°F to change it to steam at 416°F.

To solve this problem, we need to consider the three stages of the process:

Heating the ice from -32°F to 0°F

Melting the ice at 0°F

Heating the water from 0°F to 416°F

First, we need to calculate the amount of heat required to raise the temperature of 34 lb of ice from -32°F to 0°F. We can use the specific heat of ice, which is 0.5 Btu/lb°F:

Q1 = m * c * ΔT

Q1 = 34 lb * 0.5 Btu/lb°F * (0°F - (-32°F))

Q1 = 544 Btu

Next, we need to calculate the amount of heat required to melt the ice at 0°F. We can use the heat of fusion of ice, which is 144 Btu/lb:

Q2 = m * ΔHf

Q2 = 34 lb * 144 Btu/lb

Q2 = 4896 Btu

Finally, we need to calculate the amount of heat required to raise the temperature of the water from 0°F to 416°F. We can use the specific heat of water, which is 1.0 Btu/lb°F:

Q3 = m * c * ΔT

Q3 = 34 lb * 1.0 Btu/lb°F * (416°F - 0°F)

Q3 = 14,144 Btu

The total amount of heat required is the sum of Q1, Q2, and Q3:

Q total = Q1 + Q2 + Q3

Q total = 544 Btu + 4896 Btu + 14,144 Btu

Q total = 19,584 Btu

Therefore, 19,584 Btus must be added to 34 lb of ice at -32°F to change it to steam at 416°F.

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Answer:

As = 6[km/hr]

Explanation:

First we must convert the units from minutes to hours.

\(30[min]*[\frac{1hr}{60min} ]=0.5[hr]\)

Now the average velocity is defined as the relationship between space and time.

\(As=3/0.5\\As=6[km/hr]\)

A plant sits on a bookshelf. The diagram of the forces acting on the plant is the normal force in the upward vertical direction and the gravitational force in the downward direction.

A force is regarded as a push or pull. In the equilibrium of forces, the sum total of forces acting on a given object with constant mass is equal to the product of the mass of the object and its acceleration.

The sum of the forces can also be measured and resolve into vertical components and horizontal components.

Some of the factors that can affect forces depend on the following;

From the free-body attached diagram below, we can conclude that the plant sitting on the bookshelf is the normal force in the upward vertical direction and the gravitational force in the downward direction.

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Answer:

I don't get the question

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.

Explanation:

Good Question

The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.

To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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The energy of an absorbed photon is \(2.998 * 10^8\) and  the resulting unit for energy is Joules (J).

To determine the energy of an absorbed photon in electronvolts (eV), we can use the equation E = hv, where E represents energy, h is Planck's constant, and v is the frequency of the photon. By substituting the values and units correctly, we can calculate the energy in electronvolts.

To determine the energy of an absorbed photon, one can use the following formula:

energy of absorbed photon = Planck's constant x frequency of radiation

Where Planck's constant is equal to \(6.626 * 10^{-34\) Joule seconds and frequency of radiation is measured in Hertz (Hz).

The energy of an absorbed photon can also be expressed using the wavelength of the radiation instead of its frequency.

The formula for this is:energy of absorbed photon = Planck's constant x speed of light / wavelength of radiation

Where the speed of light is equal to \(2.998 * 10^8\) m/s.In both cases,

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a) 12.1 Average.

B) It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.

A) Determine the average length and express the answer using the correct number of significant figures:

12.2+12.1+12=36.3/3 = 12.1 Average.

B)  Based on your average length calculation in part a, discuss the importance of recording measurements to the appropriate number of significant figures:

It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.

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Answer:

See the answers below.

Explanation:

Momentum is defined as the product of mass by velocity, in this way we have the following equation.

\(P=m*v\)

where:

P = momemtum [kg*m/s]

m = mass = 1500 [kg]

v = velocity = 6 [m/s]

\(P = 1500*6\\P=9000 [kg*m/s]\)

Now we have to calculate the momentum of the plane when it travels at 30 [m/s].

\(P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s]\)

Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.

\(P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s]\)

Answer:

1.  9000 kg-m/s

2.  27.2 m/s

Answer: λₑ = 123pm; λₚ = 286pm

Explanation:

λ= h/√2mE where E = Kinetic Energy.

λₑ = h/√2mₑE = 6.626 X 10^-33/√2 X 9.1 X 10⁻31 X 100 X 1.6 X 10^-19 = 123pm

λₚ = h/√2mₚE = 6.626 X 10^-33/√2 X 1.6 X 10⁻27 X 100 X 1.6 X 10^-19 = 286pm

Hope this helps!!!

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Answer:

A

Explanation:

KE = 1/2 m v^2

     the greatest is  A

Answer:

Initial velocity = 6.5 m/s

Final velocity = 21.5 m/s

Explanation:

Acceleration = a = 3m/s²

Distance = s = 70m

Time = t = 5s

Initial velocity = u

Final velocity = v

s=ut+(1/2)at²

70=u(5)+(1/2)(3)(5²)

70=5u+37.5

5u=70-37.5

5u=32.5

u=6.5m/s

v=u+at

v=6.5+(3)(5)

v=6.5+15

v=21.5m/s

The primary locations for the birth of new stars are in galaxies' spiral arms. The proportion of the galaxy that can participate in star formation increases as more gas and dust become available.

We refer to some spiral galaxies as "barred spirals" because the centre bulge seems extended, like a bar. The spiral arms of the galaxy seem to emerge from the ends of the bar in barred spirals. Elliptical galaxies are round or oval in shape, as their name implies, and have a rather uniform distribution of stars.

The Norma and Cygnus arm, Sagittarius, Scutum-Crux, and Perseus arms are the four principal spiral arms of the Milky Way.

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Answer:

A) 60 Hz

B) 0.04 T

Explanation:

Given that.

Number of turns, N = 200

Length of the side, l = 20 cm = 0.2 m

Speed if rotation, w = 3600 rpm

Voltage, V = 120 V

First, we try to convert the speed from rpm to rad/s

3600 * (2π/60)

3600 * 0.10473

3600 rpm = 377 rad/s

Now, we use that as our w, speed of rotation

Frequency of output, f =

w/2π

f = 377 / 6.284

f = 59.99 Hz or approximately, 60 Hz.

B

Strength of the magnetic field in which the coil is turning

E• = NABw

Where, A = l² = 0.2² = 0.04, on substituting the values to the equation, we have

120 = 200 * 0.04 * 377 * B

120

Making B subject of formula,

B = 120/ 3016

B = 0.04 T..

The frequency of the output voltage is 60 Hz and the strength of the magnetic field is 0.04 T

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av the dimension of which of the following is time.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.

A = x/v

since x is displacement and v is velocity

x/v = m/(m/s) = s

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