Please help with hw

Factory A sent 14 loads of rice to Store 1

Factory A sent no loads of rice to Store 2

Factory B sent 6 loads of rice to Store 1

Factory B sent 16 loads of rice to Store 2

Let

    A1 = Loads sent from Factory A to Store 1

    A2 = Loads sent from Factory A to Store 2

    B1 = Loads sent from Factory B to Store 1

    B2 = Loads sent from Factory B to Store 2

Then, the equations describing the scenario are;

    \(A1+A2=14\)

    \(B1+B2=22\)

    \(A1+B1=20\)

    \(A2+B2=16\)

    \(200A1+350A2+300B1+250B2=8600\)

The simultaneous equations can be expressed in matrix form thus:

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&1&0&0&14\\0&0&1&1&22\\1&0&1&0&20\\0&1&0&1&16\\200&350&300&250&8600\end{array}\right]\)

Reducing the matrix:

Step 1:

\(R_3 \leftarrow R_3 - R_1\\R_5 \leftarrow R_5 - 200R_1\)

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&1&0&0&14\\0&0&1&1&22\\0&-1&1&0&6\\0&1&0&1&16\\0&150&300&250&5800\end{array}\right]\)

Step 2:

Switch \(R_4\) and \(R_2\)

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&1&0&0&14\\0&1&0&1&16\\0&-1&1&0&6\\0&0&1&1&22\\0&150&300&250&5800\end{array}\right]\)

Step 3:

\(R_3\leftarrow R_3+R_2\\R_5 \leftarrow R_5-150R_2\)

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&1&0&0&14\\0&1&0&1&16\\0&0&1&1&22\\0&0&1&1&22\\0&0&300&100&3400\end{array}\right]\)

Step 4:

\(R_4\leftarrow R_4+R_3\\R_5 \leftarrow R_5-300R_3\)

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&1&0&0&14\\0&1&0&1&16\\0&0&1&1&22\\0&0&0&0&0\\0&0&0&-200&-3200\end{array}\right]\)

Step 5:

Switch \(R_4\) and \(R_5\)

\(R_4\leftarrow R_4 \times \frac{1}{-200}\\R_1 \leftarrow R_1-R_2\)

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&0&0&-1&-2\\0&1&0&1&16\\0&0&1&1&22\\0&0&0&1&16\\0&0&0&0&0\end{array}\right]\)

Step 6:

\(R_1 \leftarrow R_1 + R_4\\R_2\leftarrow R_2 - R_4\\R_3 \leftarrow R_3-R_4\)

\(\left[\begin{array}{ccccc}{A1}&{A2}&{B1}&{B2}&{}\\1&0&0&0&14\\0&1&0&0&0\\0&0&1&0&6\\0&0&0&1&16\\0&0&0&0&0\end{array}\right]\)

So,

\(A1=14\\A2=0\\B1=6\\B2=16\)

From the above calculations, we see that

Factory A sent 14 loads of rice to Store 1

Factory A sent no loads of rice to Store 2

Factory B sent 6 loads of rice to Store 1

Factory B sent 16 loads of rice to Store 2

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The volume of the shaded portion of the cone is V = 621.667 inches³

Given data ,

Let the volume of the shaded region be V

Now , the volume of the larger cone be A

Let the volume of the smaller cone be B

Volume of Cone = ( 1/3 ) πr²h

V = A - B

And , A = ( 1/3 ) ( 9 )² ( 25 )

On simplifying , we get

A = ( 1/3 ) ( 81 ) ( 25 )

A = 675 inches³

And , B = ( 1/3 ) ( 4 )² ( 10 )

B = ( 160/3 ) inches³

So , Volume of shaded region V = A - B

V = 675 inches³ - ( 160/3 ) inches³

V = ( 1,865/3 ) inches³

V = 621.667 inches³

Hence , the volume of cone is 621.667 inches³

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The value of dy/dx is -cotθ, d^2y/dx^2 is -6cosec³θ, slope is -cotθ, concavity is -6cosec³θ.

Parametric Equations Point x = 6cosθ, y = 6sinθ and θ = π/4

We have to determine the value of dy/dx.

We can define dy/dx as;

dy/dx = (dy/dθ)/(dx/dθ)

We first define dy/dθ and dx/dθ.

x = 6cosθ                             y = 6sinθ

dx/dθ = -6sinθ                     dy/dθ = 6cosθ

Now put the value

dy/dx = 6cosθ/(-6sinθ)

dy/dx = -cotθ

Now we have to determine the value of d²y/dx².

d²y/dx² = d/dx(dy/dx)

We can write it as

d²y/dx² = \(\frac{\frac{d}{d\theta}(\frac{dy}{dx})}{dx/d\theta}\)

We first determine the value of d/dθ(dy/dx)

d/dθ(dy/dx) = d/dθ(-cotθ)

d/dθ(dy/dx) = cosec²θ

Now put the value

d²y/dx² = cosec²θ/(-6sinθ)

d²y/dx² = -6cosec³θ

Now we have to determine the slope.

Slope = dy/dx

Slope = -cotθ

Now we have to determine the concavity.

Concavity = d²y/dx²

Concavity = -6cosec³θ

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Answer:

D. Confidence interval decreases.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \(\mu = p\) and standard deviation \(s = \sqrt{\frac{p(1-p)}{n}}\)

When sample size increases:

The standard deviation of the sample mean is:

\(s = \frac{\sigma}{\sqrt{n}}\)

That is, it is inversely proportional to the sample size, so if the sample size incerases, the standard deviation decreases, and so does the confidence interval.

This means that the correct answer is given by option D.

a.) The value of pulses exported by US in billion would be=30 billion.

b.) The ratio of wheat export of UK to maize export of IND would be= 6:5

For question a.)

To calculate the pulses, the following steps should be taken as follows:

From the bar chart, the value of pulses in billions = 30 billions.

For question b.)

The ratio of wheat export at UK and maize export at IND would be calculated as follows:

The quantity of wheat export at UK = 24

The quantity of maize export at IND = 20

Therefore, the ratio of wheat to maize = 24:20= 6:5

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Answer:

Fourth choice: - Domain: All real numbers ; Range {y | y > 0}

Explanation:

The domain of the function is the set of x values for which y is defined.

The range of the function is the set of y value that y can take.

Now for our function

x can take any real value; it is defined for both positive

Answer:

$159.24 is the balance after 9 months is the answer that you seek

Step-by-step explanation:

Answer:

the savings plan balance after 9 months with an APR of 8% and monthly payments of $250 is approximately $2,366.98.

Step-by-step explanation:

To find the savings plan balance after 9 months with an APR of 8% and monthly payments of $250, we can use the formula for the future value of an annuity:

FV = Pmt x ((1 + r/n)^(n x t) - 1) / (r/n)

where:

FV = future value

Pmt = monthly payment

r = annual interest rate

n = number of compounding periods per year

t = time in years

In this case, we have:

Pmt = $250

r = 8%

n = 12 (since payments are made monthly)

t = 9/12 = 0.75 (since 9 months is three-quarters of a year)

Substituting these values into the formula, we get:

FV = $250 x ((1 + 0.08/12)^(12 x 0.75) - 1) / (0.08/12)

FV ≈ $2,366.98

Therefore, the savings plan balance after 9 months with an APR of 8% and monthly payments of $250 is approximately $2,366.98.

Answer:

Step-by-step explanation:

This is a doozy. You have to know A LOT about parabolas to get to this answer. First and foremost, we will have to complete the square on the x terms and get everything else on the other side of the equals sign with the intention of putting this into standard form which looks like this:

\(-4p(y-k)=(x-h)^2\)

The negative is because the parabola is upside down. We begin breaking it down by multiplying everything by -4 to get:

\(-4y=x^2+8x+8\) and subtract that 8 from both sides to get:

\(-4y-8=x^2+8x\). Now we'll complete the square on the x terms by taking half the linear term, squaring it, and then adding it to both sides. Our linear term (the number with the x stuck to it) is 8. Half of 8 is 4 ad 4 squared is 16. So we add 16 to both sides to get:

\(-4y-8+16=(x^2+8x+16)\)

The right side will simplify into a perfect square binomial and the left side we will just combine like terms to get:

\(-4y+8=(x+4)^2\)

We're getting close. Now we need to just factor out the -4 on the left to get:

\(-4(y-2)=(x+4)^2\)

If the standard form is -4p blah blah blah, then p has to be 1. That means that the focus is 1 unit below the vertex. The vertex is (-4, 2). p is the distance between the vertex and the focus. The focus is always on the axis of symmetry. We know that the parabola opens upside down because of the negative sign, and the parabola always wraps itself around the focus. That's why the focus is p units below the vertex. That means that the focus is located at (-4, 1).

Told you it was difficult. I noticed no one helped you with this one and it's been up here for 5 days...

Answer:

16.46 I don't know

Step-by-step explanation:

you didn't include the picture, so I cant see what the question is, sorry.

or if you mean any lines they just have to not intersect or combined at any point like the image I attached, that is parallel lines when they never touch.

Answer:

the square

Step-by-step explanation:

perpendicular = 90 degrees

Square (Option 1) has at least one pair of perpendicular sides

"Perpendicular means two lines, or sides, that meet at a right angle. A right angle is the measurement of 90 degrees."

"Perpendicular sides are at a 90-degree angle. Since they are so common, there is a special symbol to signify the sides are perpendicular without measuring."

Option 1

Squares are made up of two sets of parallel line segments, and their four 90° angles mean that those segments also happen to be perpendicular to one another.

Option 2

A parallelogram is a special kind of quadrilateral that is formed by parallel lines. The angle between the adjacent sides of a parallelogram may vary but the opposite sides need to be parallel for it to be a parallelogram.

Option 3

There are three angles in a triangle. These angles are formed by two sides of the triangle, which meets at a common point, known as the vertex. The sum of all three interior angles is equal to 180 degrees.

Option 4

A trapezoid is a quadrilateral with exactly one pair of parallel sides. Isosceles trapezoids have two sides which are equal sized and have the same angles between themselves and the bases.

Hence, Square (Option 1) has at least one pair of perpendicular sides

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Answer:

\(P(-2.05<X<-1.49)=P(\frac{-2.05-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{-1.49-\mu}{\sigma})=P(\frac{-2.05-0}{1}<Z<\frac{-1.49-0}{1})=P(-2.05<z<-1.49)\)

And we can find this probability with this difference

\(P(-2.05<z<-1.49)=P(z<-1.49)-P(z<-2.05)=0.068- 0.0202= 0.0478\)

And we can see the figure in the plot attached.

Step-by-step explanation:

Let X the random variable that represent the redings on thermometers of a population, and for this case we know the distribution for X is given by:

\(X \sim N(0,1)\)  

Where \(\mu=0\) and \(\sigma=1\)

We are interested on this probability

\(P(-2.05<X<-1.49)\)

We can use the z score formula given by:

\(z=\frac{x-\mu}{\sigma}\)

Using this formula we got:

\(P(-2.05<X<-1.49)=P(\frac{-2.05-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{-1.49-\mu}{\sigma})=P(\frac{-2.05-0}{1}<Z<\frac{-1.49-0}{1})=P(-2.05<z<-1.49)\)

And we can find this probability with this difference

\(P(-2.05<z<-1.49)=P(z<-1.49)-P(z<-2.05)=0.068- 0.0202= 0.0478\)

And we can see the figure in the plot attached.

Answer:

25 remainder of 4

Step-by-step explanation:

Answer:

here hope this will be you ^^"

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Answer: The inequality is: n ≥ 36/37

Step-by-step explanation:

Let's solve your inequality step-by-step.

n − 5n + 6 ≥ −7(5n−6)−6

----------------------------------------------------------------------------------------------------------------

Step 1: Simplify both sides of the inequality.

−4n + 6 ≥ −41n + 42

----------------------------------------------------------------------------------------------------------------

Step 2: Add 41n to both sides.

−4n + 6 + 41n ≥ − 41n+ 42 + 41n

37n + 6 ≥ 42

----------------------------------------------------------------------------------------------------------------

Step 3: Subtract 6 from both sides.

37n + 6 − 6 ≥ 42 − 6

37n ≥ 36

----------------------------------------------------------------------------------------------------------------

Step 4: Divide both sides by 37.

37n/37 ≥ 36/37

n ≥ 36/37

----------------------------------------------------------------------------------------------------------------

Answer:

n ≥ 36/37

Source: https://www.mathpapa.com/calc.html?q=x+y%3D7%2C%20x+2y%3D11

,  Hope this helps :)

Have a great day!!

The revised Doubtful Debts Provision should be, $4,555.

Now, Using a net debtors value of $91,100 and a provision rate of 5%, use the calculation to get the adjusted Provision for Doubtful Debts (PDD):

Net Debts x Provision Rate equals Adjusted PDD.

The computation would then be:

= $91,100 x 0.05

= $4,555 is the adjusted PDD.

Because of the additional $550 in bad debt and the revised net debtors value of $91,100, the Provision for Doubtful Debts must be raised by ,

= $4,555 - $3,500

= $1,055

Hence, The revised Doubtful Debts Provision should be $4,555.

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Answer:

correct

Step-by-step explanation:

Answer:

40     Right Angle Triangle

Step-by-step explanation:

180-50-90=x

x=40

Right angle triangle

Answer:

40

Step-by-step explanation:

90 + 50 = 140

A triange = 180

A right angle(aka the square) = 90

180 - 140 = 40

x = 40

Answer:

\(E \approx \exp(0.31)\)

Step-by-step explanation:

From the question we are told that

Occurrence of volcanoes\(x=37 times\)

The number year

\(N= 1832-1950\\N=118 years\)

Generally the number  of volcanoes occurring is mathematically modeled as

\(X \approx Poisson(0.31)\)

Generally the waiting time of the earthquakes will also be modeled with exponential distribution with the same parameters

\(E \approx \exp(0.31)\)

The slope of the line tangent to the graph of h(x) = 1/x + 3 at the point when x is -6 is -1/36.

To determine the slope of the line tangent to the graph of the given function when x = -6;

Using alternative form of the definition of derivative.

f'(a) = lim (h->0) [f(a+h) - f(a)] / h

Using this formula for the given function;

h'(a) = lim (h->0) [h(a+h) - h(a)] / h

Now, substitute a = -6 into the formula:

h'(-6) = lim (h->0) [h(-6+h) - h(-6)] / h

Next, simplify the expression by plugging in the values:

h'(-6) = lim (h->0) [1/(-6+h) + 3 - (1/-6 + 3)] / h

Simplifying further:

h'(-6) = lim (h->0) [1/(-6+h) - 1/-6] / h

Now, let's combine the fractions with a common denominator:

h'(-6) = lim (h->0) [(-6 - (-6+h))/((-6+h)(-6))] / h

Simplifying the numerator:

h'(-6) = lim (h->0) [-h / ((-6+h)(-6))] / h

Canceling out the h's:

h'(-6) = lim (h->0) [-1 / ((-6+h)(-6))]

Taking the limit as h approaches 0:

h'(-6) = -1 / ((-6)(-6))

Simplifying further:

h'(-6) = -1 / 36

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Answer:

FAIL TO REJECT

NOT ENOUGH

Step-by-step explanation:

Given a Pvalue of 0.32

Decision region :

When Pvalue < α ; Reject the Null and conclude that there is significant or enough evidence to accept the alternative hypothesis.

Otherwise, fail to reject reject the null and conclude that, there is not enough evidence to accept the alternative hypothesis

Therefore, for the scenario above, where Pvalue = 0.32

Possible α values are ; 0.1, 0.05, 0.01

For all α - values listed, the Pvalue is greater than α

Pvalue > α ; Hence, FAIL TO REJECT the Null.

Conclusion :

There is NOT ENOUGH evidence to support the alternative that the proportion of students who have ear infection at one school and the other is different.

Answer:

y = -4.2

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

Answer:6. Calculate the appropriate measure of Skewness for the data below. Class 0-10 10-20 20-30 30-40 40-50 50-60 12 25 35 40 50 No. of workers 10 Ans: -0.49

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

trust me

In algebra, "seven times a number" is written as 7x, which is the multiplication of seven instances of the symbol x.

An equation that includes constants, variables, and a few algebraic operations is said to be algebraic. A good example of an algebraic expression is 3x2 2xy + d. So, three different types of fundamental building blocks make up an algebraic expression: Coefficient (i.e. numbers) (i.e. numbers)

A seven-times-a-number is represented by multiplying it by seven or adding it to another integer (since this is an abbreviated successive addition ).

If x is any number, then it may be written as follows seven times: Algebraic expressions (numbers or letters) are linked by fundamental operations including addition, subtraction, multiplication, and division in mathematical language.

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Complete question -

Seven times a number in algebraic expression

Answer:

Set your calculator to degree mode.

cos(37°) = 52/x

x cos(37°) = 52

x = 52/cos(37°) = 65.1

To solve the problem, we need to find Julian's average speed, given that he started biking from a position behind the simulated biker at a speed of 20 km/h, and after 15 minutes, his position was reported as -214 km.

We can use the formula for average speed:

Average speed = total distance / total time

To find the total distance, we need to calculate the displacement of Julian from the initial position of -d (where d is the distance between Julian and the simulated biker when he started biking) to the position of -214 km after 15 minutes.

Displacement = final position - initial position

Displacement = (-214 km) - (-d) = d - 214 km

The total distance covered by Julian is equal to the absolute value of the displacement, since the direction of the motion does not matter when computing distance.

Total distance = |d - 214 km|

To find the total time, we need to convert 15 minutes to hours:

Total time = 15 minutes / 60 minutes/hour = 0.25 hours

Now we can substitute the values into the formula for average speed:

Average speed = total distance / total time

Average speed = |d - 214 km| / 0.25 hours

Since Julian was traveling at a constant speed of 20 km/h, we can also express the distance in terms of time:

Average speed = (20 km/h) x t / 0.25 hours

where t is the time Julian biked in hours.

Setting the two expressions for average speed equal to each other, we can solve for t:

|d - 214 km| / 0.25 hours = (20 km/h) x t / 0.25 hours

|d - 214 km| = 20 km/h x t

Solving for t:

t = |d - 214 km| / 20 km/h

Now we can substitute this expression for t into either expression for average speed:

Average speed = (20 km/h) x t / 0.25 hours

Average speed = |d - 214 km| / 0.25 hours

Substituting the expression for t:

Average speed = |d - 214 km| x 4 / |d - 214 km|

Simplifying:

Average speed = 80 km/h

Therefore, Julian's average speed so far has been 80 km/h.

Answer:

0.9955

Step-by-step explanation:

Given :

Mean weight increase , μ = 14

Sample mean weight increase , xbar = 16.3

Standard deviation, s = 5.9

Sample size, n = 45

Hypothesis :

H0 : μ = 14

H1 : μ > 14

The test statistic : (xbar - μ) ÷ (s/sqrt(n))

Test statistic = (16.3 - 14) ÷ (5.9/sqrt(45))

Test statistic = 2.3 / 0.8795200

Test statistic = 2.615

The Pvalue :

P(Z < 2.615) = 0.99554

Hence, pvalue = 0.9955 (4 decimal places).