Answer:
1st answer choice
P4O6 + 2 O2 -> P4O10
Explanation:
You need to cancel out reactants and products that are the same.
P4 cancels out because it appears in both reactants and products
We get 2 O2 in the reactants because 5-3= 2
Thus, answer choice 1 is correct.
Section 1: Parts of Chemical Reaction and Conservation of mass
1) Identify the reactants cand products of the following
Chemical equation:
(The equation in image)
Answer:
The reactants are on the left of the arrow, the products are on the right.
Explanation:
Reactants are the substances that exist before the chemical reaction takes place. When writing a chemical reaction or equation, they are found on the left of the arrow. They react to form new substances, which are known as the products. The products are found to the right of the arrow in the reaction.
Ethanol is one of many toxic substances found in tobacco smoke.
a. True
b. False
The statement is False.
Ethanol is one of many toxic substances found in tobacco smoke.
Ethanol is used in the manufacture of drugs, plastics, lacquers, polishes, plasticizers, and cosmetics. Ethanol is utilized in remedy as a topical antiinfective, and as an antidote for ethylene glycol or methanol overdose.
Ethanol is a natural chemical compound. it's far simple alcohol with the chemical formula C₂H₆O. Its system can be additionally written as CH ₃−CH ₂−OH or C ₂H ₅OH and is frequently abbreviated as EtOH. Ethanol is a risky, flammable, colorless liquid with a characteristic wine-like smell and pungent taste.
Within the worst instances, there can also be respiratory problems, low blood strain, incontinence coronary heart troubles, blood troubles, liver damage, and loss of life. Ethanol can also dry out and worsen the skin; there may be aches, redness, and swelling. Eye publicity to ethanol also can purpose tearing, burning, and stinging.
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Silver bromide is the photosensitive material in 35 mm photographic film. When monochromatic light falls on film, the photons are recorded if
they contain sufficient energy to react with silver bromide in the film. The minimum energy needed to do this is approximately 57.9 kJ/mol. What
is the wavelength of this energy in nm?
The minimum energy needed by the photons to react with silver bromide in the film is approximately 57.9 kJ/mol. Then, the wavelength is 206 nm.
What is wavelength?Wavelength of a wave is the distance between two consecutive crests or troughs of the wave.
To find the wavelength of the energy in nm, we can use the equation:
E = hc/λ
where E is the energy in joules, h is Planck's constant (6.626 x 10⁻³⁴ J s), c is the speed of light (2.998 x 10⁸ m/s), and λ is the wavelength in meters.
First, we need to convert the energy from kJ/mol to J/photon:
57.9 kJ/mol = 57.9 x 1000 J/mol / 6.02 x 10²³ mol^-1
= 9.626 x 10²⁰ J/photon
Now we can use the equation above to find the wavelength:
9.626 x 10²⁰ J/photon = (6.626 x 10⁻³⁴ J s)(2.998 x 10⁸ m/s) / λ
Solving for λ, we get:
λ = hc/E = (6.626 x 10⁻³⁴ J s)(2.998 x 10^8 m/s) / 9.626 x 10⁻²⁰J/photon
= 2.06 x 10⁻⁷ m
Finally, we convert the wavelength from meters to nanometers:
λ = 2.06 x 10⁻⁷ m x (10⁻⁹ nm/m)
= 206 nm
Therefore, the wavelength of the energy needed to react with silver bromide in 35 mm photographic film is approximately 206 nm.
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Identify the reasons that cities boomed during the Middle Ages.
Answer:
Explanation:
The reasons that cities boomed during the Middle Ages are more employment opportunities, increased trade, and growing interest in culture and art.
Answer:
Explanation:
By the High Middle Ages, towns were growing again. One reason for their growth was improvements in agriculture. Farmers were clearing forests and adopting better farming methods. As a result, they had a surplus of crops to sell in town markets.
Also, as the amount of trade increased between Europe and other continents. Trade began to grow in Europe after the Crusades. Most of this trade was controlled by merchants from Italy and Northern Europe.
Which of the following is an
example of cohesion?
Answer:
Explanation:
Predict whether methanol or hexanol would be more soluble in acetone. Explain your answer.
a) Hexanol. Both methanol and hexanol are polar and can interact with acetone via dipole-dipole interactions as acetone is also polar. Methanol has a much shorter hydrocarbon chain than hexanol, and its molecules have a greater dipole moment, which might cause methanol to interact more strongly with itself than with acetone and hence cause it to be less soluble in acetone. b) Methanol. Both methanol and hexanol have an -- OH group that can hydrogen bond with the oxygen on acetone. Hexanol has a much longer hydrocarbon chain than methanol, and its molecules would interact via dispersion forces, which might cause hexanol to interact more strongly with itself than with acetone, and hence cause it to be less soluble in acetone. c) Methanol. Both methanol and hexanel are polar and can interact with acetone via dipole-dipole interactions as acetone is also polar Hexanol has a much longer hydrocarbon chain than methanol, and its molecules are more polarizable and have a greater dipole moment. which might cause hexanol to interact more strongly with itself than with acetone and hence cause it to be less soluble in acetone. d) Hexanol. Both methanol and hexanol have an -OH group that can hydrogen bond with the oxygen on acetone. Hexanol has a much longer hydrocarbon chain than methanol, and its molecules would interact via relatively strong dispersion forces, which might cause hexanol to interact more strongly with acetone than with itself, thus increasing solubility.
The correct answer is option c) Methanol. Both methanol and hexanol are polar substances, and they can interact with acetone through dipole-dipole interactions since acetone is also polar. However, methanol is more soluble in acetone compared to hexanol. Here's the explanation:
Methanol has a shorter hydrocarbon chain compared to hexanol. Due to its shorter chain, the molecules of methanol have a smaller size and a greater dipole moment. This makes methanol more capable of forming stronger dipole-dipole interactions with acetone molecules.
On the other hand, hexanol has a longer hydrocarbon chain. The longer chain makes hexanol molecules larger and less polarizable compared to methanol. While hexanol can still interact with acetone through dipole-dipole interactions, the relatively weaker interactions and the tendency of hexanol molecules to interact more strongly with themselves through dispersion forces limit its solubility in acetone.
In summary, methanol, with its smaller size and stronger dipole moment, is more likely to form favorable interactions with acetone molecules and dissolve more readily in acetone compared to hexanol.
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plzz!!! I need help now
this is science
A toy car that is 0.12 m long is used to model the actions of an actual size car that is 6 m long which ratio shows the relationship between the sizes of the model and the actual car ?
Answer:
The correct answer is - 1:50.
Explanation:
Given:
Model toy car = 0.12 m
Actual size of car = 6 m
The ratio of model and actual car size = ?
Solution:
We know that 1 m = 100 cm
then, Model toy car - 0.12*100 = 12 cm
and size of the actual car - 6*100 - 600 cm
Then the ratio of model and actual car size = model car size/ actual car size
= 12/600
= 1/50
Thus, the correct answer is - 1:50.
what is the chemistry of acid and base
Answer:
Of what?
Explanation:
But uhh: An acid is a substance that donates protons or accepts a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.
select true or false: an electron loses energy in the transition from a 4f subshell to a 6s subshell. group startstrue or falsetrueunselected button,correctunavailablefalseselected button,incorrectunavailablegroup ends
True, an electron loses energy in the transition from a 4f subshell to a 6s subshell
Orbitals of lower energies fill up first. The pattern of filling is 1s, 2s, 2p, 3s, 3p, 4s, 3d, etc. An full subshell of a specific orbital type must be filled before going on to the next subshell with a higher energy level since all of the orbitals inside a subshell are degenerate (of equal energy).
The orbitals are filled in accordance with the (n+1) rule, which states that even if an orbit's n value is greater, the orbits with a higher (n+1) value will be filled first.
Here, the (n+1) of the 6s orbital is 6, whereas the (n+1) of the 4f orbital is 7, filling the 4f orbital before the 6s orbital.
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Cansjhdhsbdhajajajhsbsbshs hahahah she jansbsbsns haha be safe
Answer:
wait what?
Explanation:
brainliest pls
A sample of 0.53 of carbon dioxide was obtained by heating 1.31 grams of calcium carbonate. What is the percent yield for this reaction?
Step 1
The reaction:
CaCO3 + heat => CaO + CO2 (completed and balanced)
-----------------------
Step 2
Information provided:
Actual yield = 0.53
how many atoms are in 1.2x10^5 moles of neon?
Answer:
7.224 × 10^28 atoms
Explanation:
The number of moles contained in a substance (n) can be calculated from this expression:
nA = n × 6.02 × 10^23 atoms
Where;
nA = number of atoms of substance
n = number of moles of substance
Avagadro's number or constant = 6.02 × 10^23 atoms
Using nA = n × 6.02 × 10^23 atoms
In this question, there are 1.2 x 10^5 moles of neon (N). The number of atoms (nA) is as follows:
nA of neon = 1.2 x 10^5 × 6.02 × 10^23
nA = 7.224 × 10^ (5 + 23)
nA = 7.224 × 10^28 atoms
The number of neon atoms in 1.2 x 10^5 is 7.224 × 10^28 atoms.
Part A Consider the following reaction at 298 K: 2H2S(g)+SO2(g)→3S(s, rhombic)+2H2O(g),ΔG∘rxn=−102 kJ Calculate ΔGrxn under these conditions: PH2SPSO2PH2O===2.00 atm1.50 atm0.0100 atm Express the free energy change in kilojoules to three significant figures.
ΔGrxn = ?
Part B Consider the following reaction at 298 K: 2H2S(g)+SO2(g)→3S(s, rhombic)+2H2O(g),ΔG∘rxn=−102 kJ
Is the reaction more or less spontaneous under these conditions than under standard conditions?
a. ΔGrxn under the given conditions is -109 kJ. b. The reaction is more spontaneous under the given conditions than under standard conditions.
a. To calculate ΔGrxn under the given conditions, we can use the equation ΔGrxn = ΔGrxn° + RT ln(Q), where ΔGrxn° is the standard free energy change, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.
Given:
ΔGrxn° = -102 kJ (standard free energy change)
P(H2S) = 2.00 atm
P(SO2) = 1.50 atm
P(H2O) = 0.0100 atm
Using the ideal gas law, we can calculate the reaction quotient:
Q = \((PH2O)^2 / (PH2S)^2 (PSO2)\)
= \((0.0100)^2 / (2.00)^2 (1.50)\)
= 0.000000333
Plugging the values into the equation ΔGrxn = ΔGrxn° + RT ln(Q), we get:
ΔGrxn = -102 kJ + (8.314 J/mol·K)(298 K) ln(0.000000333)
= -109 kJ
Therefore, ΔGrxn under the given conditions is -109 kJ.
b. To determine whether the reaction is more or less spontaneous under the given conditions than under standard conditions, we compare the sign of ΔGrxn. Since ΔGrxn is negative (-109 kJ), the reaction is more spontaneous under the given conditions than under standard conditions, where ΔGrxn° is -102 kJ. A more negative value of ΔGrxn indicates a more spontaneous reaction, meaning that the reaction is more likely to occur under the given conditions than under standard conditions.
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An investigation into an unknown object in space resulted in the following observations:
It is made of rock.
It has a round shape.
What additional piece of information is required to confirm that the object is an asteroid?
It gives off light.
It has a tail of dust and gas.
It orbits the sun.
It rotates on its axis.
An investigation into an unknown object in space resulted in the following observations: It was discovered to be an asteroid, It revolves around the sun, which is in the third position.
What is an asteroid?It is a small, rocky substance that rotates around the sun and is found in the asteroid belt, which is located between the orbits of Mars and Jupiter, and its size varies, with some still in fragments and others having a large structure.
Hence, an investigation into an unknown object in space resulted in the following observations: It was discovered to be an asteroid, It revolves around the sun, which is in the third position.
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4. Manik saw his father watering his garden plants in hot weather. He noticed that
water doesn’t stick to the plant leaves and leaves become dry but looked fresh. He asked
following questions to his teacher
a. Which tissue forms the outer covering of a plant and does it have a protective role
to play?How ?
b. Why does water not stick to the leaves?
Water does not stick to the leaves of the plant owing to the fact that the leaves has a waterproof cuticle.
What tissues protects the leaves?We know that the leaves are the parts of the plant that are involved in photosynthesis. Photosynthesis is the process by which green plants produce their own food in the presence of sunlight and chlorophyll. We know that the leave has an outer protective covering.
The tissue that plays this outer covering of a plant for is the epidermis and its waxy cuticle. It prevents damage to the plant.
Water does not stick to the leaves of the plant owing to the fact that the leaves has a waterproof cuticle.
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Within the textbook, the idea that goods would be equally distributed if the distributor was not allowed to know of his/her status or position is referred to as _____________.
Within the textbook, the idea that goods would be equally distributed if the distributor was not allowed to know of his/her status or position is referred to as the veil of ignorance.
This concept, introduced by philosopher John Rawls, suggests that in a just society, individuals should make decisions about the distribution of resources and opportunities without any knowledge of their own advantages or disadvantages in that society.
The veil of ignorance serves as a thought experiment to encourage impartiality and fairness, as decision-makers would be motivated to create a system that benefits everyone, regardless of their personal circumstances, ensuring a more equitable distribution of goods.
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consider the two‑step synthesis of cyclopentanecarboxylic acid from cyclopentanol. identify the missing reagents and draw the intermediate formed.
The two-step synthesis of cyclopentane-carboxylic acid from cyclopentanone involves the conversion of cyclopentanone into cyclopentyl sulfate using sulfuric acid as the reagent in the first step. In the second step, the leaving group is substituted by a carboxyl group using sodium or potassium cyanide as the reagent.
To synthesize cyclopentane carboxylic acid from cyclopentanone, a two-step process is typically employed. In the first step, the hydroxyl group of cyclopentanone is converted into a leaving group, which is then substituted by a carboxyl group in the second step. Here are the missing reagents and the intermediate formed for each step:
Step 1: Conversion of Cyclopentanol into a Leaving Group Intermediate
To convert cyclopentanone into a suitable leaving group, an acid is commonly used. The acid protonates the hydroxyl group, making it a better-leaving group. In this case, sulfuric acid (H2SO4) can be used as the reagent. The resulting intermediate formed is cyclopentyl sulfate.
Step 2: Substitution of the Leaving Group with a Carboxyl Group
In the second step, the leaving group (cyclopentyl sulfate) is replaced by a carboxyl group (-COOH). To achieve this, a nucleophile that can attack the sulfur atom in the intermediate is required. Sodium or potassium cyanide (NaCN or KCN) can be used as the reagent. This leads to the formation of cyclopentane-carboxylic acid, with the sulfate group replaced by the carboxyl group.
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For the following equation insert the correct coefficients that would balance the equation. If no coefficient is need please insert the NUMBER 1.
5. K3PO4 + HCl --> KCl + H3PO4
The balanced equation is K3PO4 + 3HCl --> 3KCl + H3PO4.
In order to balance the equation, coefficients must be added to each element or molecule in the equation so that the same number of atoms of each element is present on both sides.
Starting with the potassium ions (K), there are 3 on the left side and only 1 on the right side.
Therefore, a coefficient of 3 must be added to KCl to balance the K atoms. Next, the phosphorous ion (PO4) is already balanced with 1 on each side.
Finally, looking at the hydrogen ions (H), there are 3 on the left and 1 on the right, so a coefficient of 3 must be added to HCl to balance the H atoms. This results in the balanced equation: K3PO4 + 3HCl --> 3KCl + H3PO4.
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Look at your gumdrop model of a water molecule. If you had several of those water molecules, and you pulled the gumdrops apart, what other molecules could you make? Explain your answer.
PLEASE HELP ME FAST!! How many moles are contained in 500 mL of a 3.5M NaOH solution?
Answer:
1.75moles
Explanation:
Molarity = number of moles (n) ÷ volume (V)
According to the information given in this question,
V = 500mL = 500/1000 = 0.500L
n = ?
Molarity = 3.5M
Using Molarity = n/V
number of moles (n) = V × molarity
n = 0.5 × 3.5
n = 1.75moles.
Easy question please help. DUE IN 15 MINUTES. Calculate the frequency of light that has a wavelength of 9.75 x 10^-7 m.
Answer:
3.077 × 10¹⁴ Hz
Explanation:
f = ?
wavelength = 9.75 × 10-⁷m
using the formula,
c = wavelength × frequency
f = c/wavelength
but c(speed of light) = 3×10⁸m/s
f = 3 × 10⁸/9.75 × 10-⁷
f = 3.077 × 10¹⁴ s-¹
Laboratory Math 1. You learned that 10% of renal blood flow becomes filtrate. How much filtrate is formed in 1 minute? 10% of 1 L/min=100ml/min 2. How much filtrate is formed in 1 hour? 3. How much filtrate is formed in 1 day? 4. How much filtrate is reabsorbed per day? Consider that roughly 2 L of urine are formed per day. 5. Speculate about the purpose of so much filtrate being formed. This seems crazy! What advantage might this give? 6. Consider that plasma Na+ is 140mM. If the GFR is 125ml/min, how much Na+ is filtered per day?
To determine the amount of filtrate formed in 1 minute, we use the given information that 10% of renal blood flow becomes filtrate. If the renal blood flow is 1 L/min, then 10% of that is 100 ml/min.
2. To find the amount of filtrate formed in 1 hour, we multiply the filtrate formed per minute (100 ml/min) by the number of minutes in an hour (60). This gives us 6,000 ml or 6 L of filtrate formed in 1 hour.3. For the amount of filtrate formed in 1 day, we multiply the filtrate formed per minute (100 ml/min) by the number of minutes in a day (1,440). This gives us 144,000 ml or 144 L of filtrate formed in 1 day.
4. To calculate the amount of filtrate reabsorbed per day, we subtract the amount of urine formed per day from the amount of filtrate formed per day. Given that roughly 2 L of urine are formed per day, the amount of filtrate reabsorbed would be 144 L - 2 L = 142 L. 5. The purpose of forming such a large amount of filtrate can be understood in terms of kidney function. The kidneys play a vital role in maintaining homeostasis by regulating the balance of various substances in the body. The filtration process allows for the removal of waste products, excess ions, and toxins from the blood. Additionally, it allows for the selective reabsorption of essential substances back into the bloodstream, ensuring their retention and proper functioning in the body. The large amount of filtrate formed provides the kidneys with a higher chance of effectively filtering waste and maintaining appropriate levels of essential substances.
6. To calculate the amount of filtered sodium (Na+) per day, we need to consider the glomerular filtration rate (GFR) and the concentration of plasma Na+. Given that the GFR is 125 ml/min and the plasma Na+ concentration is 140 mM (millimolar), we can multiply these values to find the amount of Na+ filtered per minute. This gives us 125 ml/min * 140 mM = 17,500 millimoles of Na+ filtered per minute. To convert this to per day, we multiply by the number of minutes in a day (1,440).
Thus, the amount of Na+ filtered per day would be 17,500 millimoles/min * 1,440 min/day = 25,200,000 millimoles or 25,200 moles of Na+ per day.
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what is M2 ?how does FOMCs could affect M2 and why ?
M2 refers to the money supply measure known as M2 money stock.
The FOMC's decisions and actions can impact M2 through its control over interest rates, open market operations, and the influence on economic conditions and confidence. Changes in monetary policy by the FOMC aim to manage the money supply and promote price stability, economic growth, and employment.
M2 is a broad measure of the money supply that includes cash, checking and savings deposits, money market funds, and other time deposits.
The Federal Open Market Committee (FOMC) is a committee within the U.S. Federal Reserve System that is responsible for making decisions regarding monetary policy, including setting interest rates and implementing measures to manage the money supply.
The actions taken by the FOMC can have an impact on M2 and the broader money supply in the economy. Here's how:
1. Open Market Operations: The FOMC conducts open market operations by buying or selling government securities in the open market. When the FOMC buys government securities, it injects money into the banking system, increasing bank reserves and potentially leading to an expansion of M2.
2. Interest Rate Policy: The FOMC sets the target federal funds rate, which is the interest rate at which depository institutions lend and borrow funds from each other overnight. By adjusting the federal funds rate, the FOMC influences borrowing costs for banks and, in turn, affects their lending practices. Changes in interest rates can impact the demand for loans and affect the growth of M2.
3. Impact on Confidence and Spending: The FOMC's actions and communications can influence consumer and business confidence. When the FOMC signals a more accommodative monetary policy stance, it can encourage borrowing and spending, potentially leading to an increase in the growth of M2.
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provide the structure of the 1,4-addition product for the reaction of 1,3- hexadiene with br2/ccl4
The 1,4-addition reaction between 1,3-hexadiene and Br2/CCl4 produces 1,4-dibromo-2-hexene where Br atoms add to the carbon atoms at positions 1 and 4 of the diene while the double bonds at positions 2 and 3 remain unaltered.
How to provide the structure of the 1,4-addition product?The reaction of 1,3-hexadiene with Br2/CCl4 undergoes 1,4-addition, also known as conjugate addition, where the electrophilic Br2 adds to the conjugate diene system. The resulting product is 1,4-dibromo-2-hexene.
The addition of Br2 to the conjugated diene takes place in such a way that the electrophilic bromine atoms add to the carbon atoms at positions 1 and 4 of the diene, which are conjugated with each other. The double bonds at positions 2 and 3 remain unchanged.
The structure of the 1,4-addition product, 1,4-dibromo-2-hexene, is:
Br Br
| |
H2C=CH-CH=CH-CH2-CH3
| |
Br H
where the Br atoms are attached to carbons 1 and 4 of the diene, and the double bonds at positions 2 and 3 remain intact.
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. Arrange the following in order of increasing radius:
a) Mg2+, Na+, Al3+
b) Na+, Al3+ , Mg2+
c) Mg2+ , Al3+ , Na+
d) Al3+ , Mg2+, Na+
Answer:
d
Explanation:
because nuclear charge ( no. of protons) increases
Using the rules for significant figures, what do you get when you multiply 67.6 by 1.2?
Answer:
The answer should have as many significant figures as the lowest number used in the multiplication, which is 1.2 .
Calculate the binding energy of 11C. The atomic mass of 11C is 1.82850 ×× 10–26 kg.
The binding energy of an atom is the amount of energy required to completely separate all its individual protons and neutrons from each other. This energy is released when an atom is formed from its individual particles and is equivalent to the mass defect of the atom. The binding energy of 11C is approximately 1.86 × 10^-11 J.
To calculate the binding energy of 11C, we need to follow these steps:
Step 1: Convert the atomic mass of 11C to energy using the mass-energy equivalence formula:
E = mc², where m is the mass, c is the speed of light (3 × 10^8 m/s), and E is the energy.
E = (1.82850 × 10^-26 kg) × (3 × 10^8 m/s)^2
E ≈ 1.64665 × 10^-11 J
Step 2: Calculate the mass defect by subtracting the sum of the masses of individual protons and neutrons from the atomic mass of 11C. There are 6 protons and 5 neutrons in 11C.
Mass defect = (11C atomic mass) - [(mass of proton × 6) + (mass of neutron × 5)]
Mass defect ≈ 1.82850 × 10^-26 kg - [(1.67262 × 10^-27 kg × 6) + (1.67493 × 10^-27 kg × 5)]
Mass defect ≈ 1.16548 × 10^-28 kg
Step 3: Convert the mass defect to energy using the mass-energy equivalence formula:
Binding energy = (1.16548 × 10^-28 kg) × (3 × 10^8 m/s)^2
Binding energy ≈ 1.86 × 10^-11 J
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Alkaline water is the best-selling type of bottled water in the country. This is an example of:
A. Popular Opinion
B. Line of Evidence
C. Anecdote
Answer:
mu answer is A
Explanation:
i think it is a popular opinion because its the opinion of a country
Now assemble a model of methylcyclohexane by replacing a hydrogen atom with a methyl group. Rotate the C-C ring bonds so that you adopt a chair conformation. There are two chair conformations possible. To interconvert between chair conformations, you need to change the relative positions of the carbon atoms above and below the ring. If carbon atom 1 is above the plane formed by carbon atoms 2, 3, 5, 6, then rotate it so that it points below the plane. Alternatively, carbon 4 should move from below the plane to above the plane to perform a ring-flip. If you view your molecule from the side, the methyl group can be oriented either straight up/down relative to the ring (called an axial orientation) or the methyl group can be oriented pointed outward from the ring slightly angled up/down (called an equatorial orientation). Draw the ring-flip equilibrium for methylcyclohexane, being careful to accurately depict the axial/equatorial methyl group.
To assemble a model of methylcyclohexane in a chair conformation, you need to replace a hydrogen atom with a methyl group and then rotate the C-C ring bonds. There are two chair conformations possible for methylcyclohexane.
1. Start by drawing a cyclohexane ring, which consists of six carbon atoms in a ring shape.
2. Choose one carbon atom on the ring to replace with a methyl group (CH3).
3. Rotate the C-C ring bonds so that you adopt a chair conformation. In a chair conformation, the ring is shaped like a chair with alternating carbon atoms above and below the plane of the ring.
4. To interconvert between chair conformations, you need to change the relative positions of the carbon atoms above and below the ring.
5. If carbon atom 1 is initially above the plane formed by carbon atoms 2, 3, 5, 6, rotate it so that it points below the plane.
6. Similarly, carbon atom 4 should move from below the plane to above the plane to perform a ring-flip.
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