Answers
Answer:
-4 5/12
Step-by-step explanation:
-23/3 + (-11/2) + 35/4
Find a common denominator (12).
-92/12 + (-66/12) + 105/12
Reform the equation to have this as a single fraction.
(-92 + (-66) + 105)/12
Subtract 66 from -92 to get -158.
(-158 + 105)/12
Add 105 to -158 to get -53.
-53/12
Convert into a mixed number by dividing by 12.
-4 5/12 (Choice A) is your answer.
Related Questions
Hove
Find the average rate of change indicated below.
y = 4x+1
[-1, 1)
A.15
B.3.75
C.1.875
D.7.5
Answers
The average rate of change of the function over the interval is 4
Finding the average rate of changeFrom the question, we have the following parameters that can be used in our computation:
y = 4x + 1
The interval is given as
[-1, 1)
The function is a linear function
This means that it has a constant average rate of change
From y = 4x + 1, we have
Rate = 4
Hence, the rate is 4
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Need ASAP if you don’t know the answer don’t answer
Answers
Answer:
11.5
Step-by-step explanation:
Step by step explanation:
36 divided by m over x times 9
Answers
Answer:
Step-by-step explanation:
4/mx
.
On a number line, point L is at-2.5, and point M is at 6.5. If the ratio LK to KM is 6:3, where is point K on the number line?
Answers
Answer:
3.5
Step-by step
-2.5+6(6.5-(-2.5)/9
-2.5+6
3.5
the first 5 muliples of 14 after 0 are
Answers
Answer:
28,42,56,70,84
Step-by-step explanation:
Answer:
14,28,42,56,70
Step-by-step explanation:
hope it helps
Solve x^2 + 5x – 3 = 0 using the quadratic formula.
Answers
The quadratic formula is:
\(x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}\)For a quadratic equation in standard form:
\(ax^2+bx+c=0\)In this case, we have:
\(\begin{gathered} a=1 \\ b=5 \\ c=-3 \end{gathered}\)\(\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-5\pm\sqrt[]{(5)^2-4(1)(-3)}}{2(1)} \\ x=\frac{-5\pm\sqrt[]{25+12}}{2} \\ x=\frac{-5\pm\sqrt[]{37}}{2} \end{gathered}\)The given quadratic equation has two solutions:
• First one
\(\begin{gathered} x_1=\frac{-5+\sqrt[]{37}}{2} \\ x_1=-\frac{5}{2}+\frac{\sqrt[]{37}}{2} \end{gathered}\)• Second one
\(\begin{gathered} x_2=\frac{-5-\sqrt[]{37}}{2} \\ x_2=-\frac{5}{2}-\frac{\sqrt[]{37}}{2} \end{gathered}\)Therefore, the solutions of the given quadratic equation are:
\($$\boldsymbol{x=-\frac{5}{2}+\frac{\sqrt[]{37}}{2}}$$,$$\boldsymbol{x=-\frac{5}{2}-\frac{\sqrt[]{37}}{2}}$$\)solve this equation by using the look inside method to rewrite the problem
-81 = 3(5 - 4r)
Answers
27＝－(5－4r)
27＝－5＋4r
－4r＝－5－27
－4r＝－32
r＝8
Hope my answer helped u :)
Work out the volume of the prism height of 12 4 and five
Answers
The calculated volume of the prism is 702 cubic cm
Finding the volume of the prismFrom the question, we have the following parameters that can be used in our computation
The trapezoidal prism (see attachment)
The formula of the volume of a trapezoidal prism is
Volume = Base area * Height
Where we have
Base area = 1/2 * (8 + 10) * 6
Evaluate the sum of 8 and 10
Base area = 1/2 * 18 * 6
Evaluate the products of 1/2, 18 and 6
Base area = 54
Also, we have
Height = 13
So, the volume is calculated as
volume = 13 * 54
Evaluate
volume = 702
Hence, the volume of the prism is 702 cubic cm
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Select the correct answer from each drop-down menu. Each graph shows the results of a transformation applied to function f where f(x) = (1/2)^x.
Complete the statement given that g(x) =f(kx). The graph of function g is graph Because the graph a function g is the result of a  applied to the graph of function F .
Answers
Given that g(x) =f(kx). The graph of function g is graph Z Because the graph a function g is the result of a horizontal compression applied to the graph of function F.
What is a graph?A graph can be described as a pictorial representation or a diagram that represents data or values in an organized manner.
The graph of the function g(x) = f(kx) is obtained from the graph of f(x) by a horizontal compression or stretching, depending on the value of k.
In conclusion, If k is greater than 1, then the graph of g(x) is obtained from the graph of f(x) by a horizontal compression.
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S 2. Let f(x) = x - k√x
a. Find a value of k such that the function has a critical point at x = 25.
b. Is the above critical point a local maximum, local minimum or neither? Show calculus to support your answer.
Answers
a. A critical point at x = 25 would mean f'(25) = 0 or doesn't exist. We have derivative
\(f(x) = x - k \sqrt x \implies f'(x) = 1 - \dfrac k{2\sqrt x}\)
so that
\(f'(25) = 1 - \dfrac k{2\sqrt{25}} = 1 - \dfrac k{10} = 0 \implies \boxed{k=10}\)
b. Taking the second derivative, we get
\(f''(x) = \dfrac k{4 x^{3/2}} = \dfrac5{2 x^{3/2}}\)
At x = 25, the second derivative has a positive sign,
\(f''(25) = \dfrac 5{2 \times 25^{3/2}} = \dfrac 5{2\times5^3} = \dfrac1{50} > 0\)
which means f(x) is concave upward around x = 25, so this critical point is a local minimum.
Here is a picture of some sea animals. The number line on the left shows the vertical position of each animal above or below sea level, in meters.
1. How far above or below sea level is each animal? Measure to their eye level.
2. A mobula ray is 3 meters above the surface of the ocean. How does its vertical position compare to the
height or depth of:
The jumping dolphin?
The flying seagull?
The octopus?
3. An albatross is 5 meters above the surface of the ocean. How does its vertical position compare to the
height or depth of:
The jumping dolphin?
The flying seagull?
The octopus?
4. A clownfish is 2 meters below the surface of the ocean. How does its vertical position compare to the
height or depth of:
The jumping dolphin?
The flying seagull?
The octopus?
5. The vertical distance of a new dolphin from the dolphin in the picture is 3 meters. What is its distance from the surface of the ocean?
Answers
Answer:
How far above or below sea level is each animal? Measure to their eye level.The jumping dolphin is approx. 6 meters under sea level
The flying seagull is approx. 8 meters under sea level
The mobula ray is approx. 2 meters under sea level
The clownfish is approx.t 4 meters under sea level
The octopus is approx. 8 meters under sea level
A mobula ray is 3 meters above the surface of the ocean. How does its vertical position compare to the height or depth of:The jumping dolphin: The mobula ray is 9 meters lower than the jumping dolphin.
The flying seagull: The mobula ray is 11 meters lower than the flying seagull.
The octopus: The mobula ray is 11 meters higher than the octopus.
An albatross is 5 meters above the surface of the ocean. How does its vertical position compare to the height or depth of:The jumping dolphin: The albatross is 1 meter lower than the jumping dolphin.
The flying seagull: The albatross is 3 meters lower than the flying seagull.
The octopus: The albatross is 13 meters higher than the octopus.
A clownfish is 2 meters below the surface of the ocean. How does its vertical position compare to the height or depth of:The jumping dolphin: The clownfish is 8 meters lower than the jumping dolphin.
The flying seagull: The clownfish is 10 meters lower than the flying seagull.
The octopus: The clownfish is 6 meters higher than the octopus.
The vertical distance of a new dolphin from the dolphin in the picture is 3 meters. What is its distance from the surface of the ocean?If the new dolphin is above the dolphin in the picture, then its distance from the surface of the ocean is 6 - 3 = 3 meters.
If the new dolphin is below the dolphin in the picture, then its distance from the surface of the ocean is 6 + 3 = 9 meters.
✧☆*: .｡. Hope this helps, happy learning! (✧×✧) .｡.:*☆✧
what is the solution to the equation:
5(n - 1/10) = 1/2
a. n= 13/5
b. n= 3/25
c. n= 0
d. n= 1/5
Answers
\( \sf \longrightarrow \: 5 \bigg( \: n - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)
\( \sf \longrightarrow \: 5 \bigg( \: \frac{n}{1} - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)
\( \sf \longrightarrow \: 5 \bigg( \: \frac{10 \times n - 1 \times 1}{1 \times 10} \bigg) = \frac{1}{2} \\ \)
\( \sf \longrightarrow \: 5 \bigg( \: \frac{10n - 1}{ 10} \bigg) = \frac{1}{2} \\ \)
\( \sf \longrightarrow \: \: \frac{50n - 5}{ 10} = \frac{1}{2} \\ \)
\( \sf \longrightarrow \: \: 2(50n - 5) =1(10) \\ \)
\( \sf \longrightarrow \: \: 2(50n - 5) =10 \\ \)
\( \sf \longrightarrow \: \: 100n - 10=10 \\ \)
\( \sf \longrightarrow \: \: 100n =10 + 10\\ \)
\( \sf \longrightarrow \: \: 100n =20\\ \)
\( \sf \longrightarrow \: \:n = \frac{2 \cancel{0}}{10 \cancel{0}} \\ \)
\( \sf \longrightarrow \: \:n = \frac{1}{5} \\ \)
Answer:-
Answer:- D) n = ⅕ ✅To solve the equation \(\sf 5(n - \frac{1}{10}) = \frac{1}{2} \\\) for \(\sf n \\\), we can follow these steps:
Step 1: Distribute the 5 on the left side:
\(\sf 5n - \frac{1}{2} = \frac{1}{2} \\\)
Step 2: Add \(\sf \frac{1}{2} \\\) to both sides of the equation:
\(\sf 5n = \frac{1}{2} + \frac{1}{2} \\\)
\(\sf 5n = 1 \\\)
Step 3: Divide both sides of the equation by 5 to isolate \(\sf n \\\):
\(\sf \frac{5n}{5} = \frac{1}{5} \\\)
\(\sf n = \frac{1}{5} \\\)
Therefore, the solution to the equation \(\sf 5(n - \frac{1}{10})\ = \frac{1}{2} \\\) is \(\sf n = \frac{1}{5} \\\), which corresponds to option (d).
\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)
♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
Three-fourths of the 64 counties voted snickers as the best candy bar. How many counties voted snickers the best candy bar?
Answers
Multiply total votes by the fraction:
64 x 3/4 = (64 x 3) / 4 = 192/4 = 48
Answer: 48
Answer:
48
Step-by-step explanation:
64×3/4 three fourths
=48
Can someone please help fast!!
can you simplify this: 1/3(5x-8)+2/3x
Answers
Answer:(7/3)x - 8/3.
Step-by-step explanation:
To simplify this expression, you need to distribute the 1/3 to the expression inside the parenthesis. This gives:
1/3(5x-8) = (1/3)*5x - (1/3)*8 = (5/3)x - (8/3)
Now, you can distribute the 2/3 to the x-term:
2/3x = (2/3)x
Putting the two terms together, you get:
(5/3)x - (8/3) + (2/3)x = (5/3 + 2/3)x - 8/3 = (7/3)x - 8/3
So, the simplified expression is (7/3)x - 8/3.
Answer:
Step-by-step explanation:
1/3(5x-8)+2/3x
multiply everything by the LCM of the denomenators
LCM of the denomenators=3
1/3 x 3=0
(5x-8)x3=15x-24
2/3x x3=2x
15x+2x-24
=17x-24
Maximizing Profit: Tutorial
? Question
Buzz and Hover Electronics is a company that sells a variety of flying drones. For one model of drone, the cost and revenue
can be described by the given functions and graphs, where x is the number of drones.
R(x) = 180x
C(x) = 65x+13,800
Total (dollars)
+40,000
+35,000
+30,000
+25,000
+20,000
+15.000
D
+10,000
Answers
The company cannot maximize profit because the cost of producing outweighs the revenue or profit made
How should they maximize profit?
The profit function is given by P(x) = R(x) - C(x), where R(x) is the revenue function and C(x) is the cost function:
P(x) = R(x) - C(x) = 180x - (65x + 13,800) = 115x - 13,800
To maximize the profit, we need to find the value of x that maximizes P(x). We can do this by finding the vertex of the parabola that represents the profit function. Since the coefficient of the x² term is negative (-115), the parabola opens downward and the vertex represents the maximum value of the function.
The x-coordinate of the vertex is given by x = -b/2a, where a and b are the coefficients of the x² and x terms, respectively. In this case, a = -115 and b = 0, so x = 0.
Therefore, the maximum profit occurs when x = 0, which means that the company should not produce any drones. This is because the cost of producing each drone (65x + 13,800) is greater than the revenue generated by selling each drone (180x) for all values of x.
In other words, the company will lose money for each drone produced, so it should not produce any at all.
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Write the coordinates for
each given point on the
coordinate plane below.
1. Point A
2. Point B
3. Point C
4. Point D
Answers
Answer:
Point A (-3,3)
Point B about (3,-2.75)
Point C (-4,-4)
Point D (1,0)
Step-by-step explanation:
what is the property of 3x(5x7)=(3x5)7
Answers
The property you are referring to is called the associative property of multiplication. According to this property, when multiplying three numbers, the grouping of the numbers does not affect the result. In other words, you can change the grouping of the factors without changing the product.
In the equation you provided: 3x(5x7) = (3x5)7
The associative property allows us to group the factors in different ways without changing the result. So, whether we multiply 5 and 7 first, or multiply 3 and 5 first, the final product will be the same.
Which of the following values could the number 500,000 be composed of?
5,000 tens
50,000 tens
5,000 hundreds
50,000 hundreds
5,000 thousand
Answers
50000 tens
5000hundreds
How?
1ten=1050000 tens:-
\(\\ \sf\longmapsto 50000(10)=500000\)
1hundred=1005000hundreds
\(\\ \sf\longmapsto 5000(100)=500000\)
The number 500,000 can be composed of in 50,000 tens and 5,000 hundred option (B) 50,000 tens and option (C) 5,000 hundreds are correct.
What is the number?A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.
It is given that a number that is:
= 500, 000
In the above number there is five zeroes
As we know,
Tens = 10 (one zero)
Hundreds = 100 (two zero)
We can write the above number as follows:
500,000 = 50,000x10 = 5,000 tens
500,000 = 5,000x100 = 5,000 tens
The number 500,000 can be composed of:
50,000 tens5,000 hundredsWhere tens mean 10 and hundreds mean 100.
Thus, the number 500,000 can be composed of in 50,000 tens and 5,000 hundred option (B) 50,000 tens and option (C) 5,000 hundreds are correct.
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The art club had an election to select a president. 40 members voted in the election and 10 did not vote. What percentage of the members voted?
Answers
Answer:
Step-by-step explanation:
30% of 60 member voted
so you have to find
30% 0f 60
(30/100 ) * 60 =18
18 members voted for election
Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of μ = 1.1 kg and a standard deviation of o= 4.6 kg.
Complete parts (a) through (c) below.
b. If 25 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg.
The probability is
(Round to four decimal places as needed.)
Answers
The probability that their mean weight gain during freshman year is between 0 kg and 3 kg is 70%
What is Probability?It is a branch of mathematics that deals with the occurrence of a random event.
Given,
Amounts of weight that male college students gain during their freshman year are normally distributed
mean of μ = 1.1 kg and
Standard deviation of o= 4.6 kg.
Z score=x-μ/o
=25-1.1/4.6
=23.9/4.6
=5.196
Z score=x-μ/o
=25-1.1/0
=0
Z score=25-1.1/3
=23.9/3
=7.966
By observing the z table the probability that their mean weight gain during freshman year is between 0 kg and 3 kg is 70%
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A rain gutter is made from sheets of
aluminum that are 24 inches wide by
turning up the edges to form right
angles. Determine the depth of the
gutter that will maximize its cross-
sectional area and allow the greatest
amount of water to flow. What is the
maximum cross-sectional area?
Flat sheet 24 inches wide
1 Write a quadratic function for the Area in terms of x: A(x) =
2 The cross-sectional area is maximized when the depth of the gutter is
3 The maximum cross-sectional area is square inches.
Answers
1. The quadratic function for the Area in terms of x: A(x) = 24x.
2. The cross-sectional area is maximized when the depth of the gutter is 0.
3. The maximum cross-sectional area is square inches 0.
To determine the depth of the gutter that maximizes its cross-sectional area and allows the greatest amount of water to flow, we need to follow a step-by-step process.
1. Write a quadratic function for the area in terms of x:
The cross-sectional area of the gutter can be represented as a rectangle with a width of 24 inches and a depth of x. Therefore, the area, A(x), is given by A(x) = 24x.
2. The cross-sectional area is maximized when the depth of the gutter is:
To find the value of x that maximizes the area, we need to find the vertex of the quadratic function. The vertex of a quadratic function in form f(x) = ax² + bx + c is given by x = -b/(2a). In our case, a = 0 (since there is no x² term), b = 24, and c = 0. Thus, the depth of the gutter that maximizes the area is x = -24/(2 * 0) = 0.
3. The maximum cross-sectional area is square inches:
Substituting the value of x = 0 into the quadratic function A(x) = 24x, we get A(0) = 24 * 0 = 0. Therefore, the maximum cross-sectional area is 0 square inches.
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The denominator of a fraction is three more than twice the numerator. if both numerator and denominator are degreased by seven, the simplified result is 4/13
orgnal fraction. (Don't simplify.)
Answers
Answer:
2/7
Step-by-step explanation:
d=2n+3
\(\frac{d-7}{2n-4} = \frac{4}{13}\)
13(2n+3) -91 =8n - 16
26n+39 -91 = 8n-16
18n=36
n=2
d=7
Given the function f(x) = 3x ^ 2 - x + 6 , what is f(- 2) ?
Answers
Answer:
f(x) = 3x2 + 5 and y = 3x2 + 5
Step-by-step explanation:
10) Lisa recorded the shoe sizes of some of her teammates on
the basketball team. The results are given below. Which shoe sizes will only have one dot if the data is recorded on a line plot?
Answers
The shoe sizes that will only have one dot are 5 1/2, 7, 8 and 10 1/2
Identiying the shoe sizes that will only have one dotFrom the question, we have the following parameters that can be used in our computation:
The record of shoe sizes
From the data values, we have the following shoe sizes that appear once
5 1/2, 7, 8 and 10 1/2
These are the data values that will have only one dot if the data is recorded on a line plot
Hence, the shoe sizes that will only have one dot are 5 1/2, 7, 8 and 10 1/2
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The data set below shows the number of homework assignments required in math classes for a month. Write both at TRUE and a FALSE statement about this dataset. 22 23 23 21 18 4 17 15 23 20 24 15 25 16
Answers
The statement that is true based on the data set is B. There is one outlier that indicates an unusually small number of assignments required in that class.
How to solve this?The given data set is
22, 23, 23, 21, 18, 4, 17, 15, 23, 20, 24, 15, 25, 16
Arrange the data is ascending order.
4, 15, 15, 16, 17, 18, 20, 21, 22, 23, 23, 23, 24, 25
Divide the data in 4 equal parts.
(4, 15, 15), 16, (17, 18, 20), (21, 22, 23), 23, (23, 24, 25)
Now, we can say that
Q1= 16
Q3= 23
The interquartile range of the data set is 23- 16 = 7
If the data lie in the interval [Q1-1.5(IQR), Q3 + 1.5 (IQR)], then the data set has no outliers.
All the data lie in the interval [5.5,33.5] except 4. So, 4 is an outlier of the given data.
There is one outlier that indicates an unusually small number of assignments required in that class. Therefore the correct option is option B
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Which of the following statements is true based on the data set?
There is one outlier that indicates an unusually large number of assignments required in that class.
There is one outlier that indicates an unusually small number of assignments required in that class.
There are two outliers that indicate an unusually large number of assignments required in those two classes.
There are two outliers that indicate an unusually small number of assignments required in those two classes.
Jack collected 18 ten dollar bills while selling tickets for a show. He gave 1 over 6 of the bills to the theater and kept the rest. How much money did he keep?
Answers
Answer:
150
Step-by-step explanation:
Collected bills: 18 * 10= 180
1/6 of 180 = 30
180-30=150
Answer:
15 ten dollar bills, 150 dollars
Step-by-step explanation:
1/6 of 18 is 3, so he gave 3 bills to the theater and kept the other 15 for himself
2
1
-1
-2
Determine the period.
2 4
6 8 10 12 14
Acellus
Answers
According to the information we can infer that the period of the graph is 8.
How to determine the period of the graph?To determine the period of the graph we have to consider that the period of a grah is the distance between rigdes. So, in this case we have to count what is the difference between each rigde.
In this case, the distance between rigdes is 8 units because the first is located in the line 1 an the second is located in the line 9. So we can conclude that the period of the graph is 8.
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An experiment was used to test a new migraine medicine. Each participant took either the new medicine or a placebo
then waited for one hour to see if the headache went away or remained. The results are compiled in the contingency
table below. Use the table to answer the questions.
Went Away| Medicine| Placebo
Remained|. 120. |. 68
18. | 44
Your answers should be exact numerical values.
There were
participants whose headache remained.
The probability of randomly selecting an individual whose headache remained is
There were
participants whose headache remained and took a placebo.
The probability of randomly selecting an individual whose headache remained and took a placebo is
Answers
1) Number of participants whose headache remained is: 62
2) The probability of randomly selecting an individual whose headache remained is: 0.4133
3) The probability of randomly selecting an individual whose headache remained and took a placebo is: 0.2933
How to find the probability of random selection?From the table, we have the parameters as:
Number of participants that took medicine and headache went away = 120
Number of participants that took placebo and headache went away = 68
Number of participants that took and headache remained = 18
Number of participants that took placebo and headache remained = 44
1) Number of participants whose headache remained = 18 + 44 = 62
2) The probability of randomly selecting an individual whose headache remained is:
62/(62 + 120 + 68)
= 62/150
= 0.4133
3) The probability of randomly selecting an individual whose headache remained and took a placebo is:
44/150 = 0.2933
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I need help please. I will give u brainlist if correct answer.
Answers
Answer:
A. u just asked if he or she tracks profile daily. 220 lines up with daily
Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0
Answers
The equations to solve the length of the room is
a) y² - 5y = 750
b) 750 - y ( y - 5 ) = 0
c) ( y + 25 ) ( y - 30 ) = 0
Given data ,
Let the area of a rectangular room is 750 square feet.
Let the width of the room is 5 feet less than the length of the room
So , on simplifying , we get
w = l - 5
Area of rectangle = length x width
And , A = l x w
A = l ( l - 5 )
750 = y ( y - 5 )
Therefore , the equation is
a) y² - 5y = 750
b) 750 - y ( y - 5 ) = 0
On simplifying the quadratic equation , we get
c) ( y + 25 ) ( y - 30 ) = 0
Hence , the length of the rectangular room is solved
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The complete question is attached below :
Which equations can be used to solve for y, the length of the room? Select three options.
a) y(y + 5) = 750
b) y² – 5y = 750
c) 750 – y(y – 5) = 0
d) y(y – 5) + 750 = 0
e) (y + 25)(y – 30) = 0
