Answer:
slope=3
y intercept=4
Step-by-step explanation:
i did this using the equation y=mx+b m being slope and b being y intercept
During a back-to-school shopping trip, a group of friends spent 245.86 on 14 shirts and pants. Each shirt cost11.99. Each pair of pants cost24.99. How many shirts and pairs of pants did the group buy?
c. How could you simplify the numbers used in this system to simplify the system?
Does this new system change your answers to part (b)? Explain
To simplify the numbers used in the system, we can multiply all the prices and total cost by 100 to work with whole numbers. This doesn't change the answers from part (b) because the ratios between the quantities remain the same after scaling the numbers.
To solve the problem, let's define:
x = number of shirts
y = number of pairs of pants
According to the given information:
Each shirt costs $11.99.
Each pair of pants costs $24.99.
We can set up a system of equations based on the given information:
x + y = 14 (equation for the number of items)
11.99x + 24.99y = 245.86 (equation for the total cost)
To simplify the numbers used in this system, we can multiply both sides of equation 2 by 100 to eliminate the decimal places:
1199x + 2499y = 24586
Now let's solve the system of equations:
Using the method of substitution or elimination, we can solve the system of equations:
From equation 1, we have x = 14 - y.
Substituting this value into equation 2:
1199(14 - y) + 2499y = 24586
16786 - 1199y + 2499y = 24586
1300y = 7800
Dividing both sides by 1300:
y = 6
Substituting the value of y = 6 back into equation 1:
x + 6 = 14
x = 8
Therefore, the group bought 8 shirts and 6 pairs of pants.
Regarding part (c), simplifying the numbers used in the system does not change the answers from part (b). The calculations remain the same, but working with whole numbers instead of decimals might make the computations easier.
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30 points !! Which measurements could not represent the side lengths of a right triangle?
A. 6 cm, 8cm , 10cm
B. 12 cm, 35cm, 37cm
C. 4cm, 6cm, 10cm
D, 10cm, 24 , 26cm
Step-by-step explanation:
it C but if it not please don't blame me
Divide 2x2 + 7x – 3 by 2x + 5. Which expression represents the quotient and remainder? = X + Y + What are the values of X and Y?
Answer:
D, if there are choices
Step-by-step explanation:
;)
Find the product 0.025 x 7
A. 0.0175
B: 0.175
C. 1.75
D. 17.5
Answer:
b
Step-by-step explanation:
used a calucator
Tim drove at distance of 511 km in 7 h. What was his average driving speed in km/h?
Tim drove at a distance of 511 km in 7 h. His average driving speed in km/h is 73.
By computing Tim's average driving speed, we have to divide the total distance that he traveled by the time it takes him to complete the whole journey. In this respect, Tim drove a total distance of 511 km in 7 hours.
Average driving speed = Total distance/Total time taken
By putting the values in the equation we get :
Average driving speed =\(\frac{ 511 km}{7 h}\)
Now by computing the average driving speed:
Average driving speed = 73 km
So, Tim's average driving speed was 73 km/h.
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how many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 if each digit can be used only once? how many of these are odd numbers? how many are greater than 330?
By using the concept of combinations, we have determined that there are 210 three-digit numbers that can be formed using the digits 0-6 without repeating any of them. Among them, there are 90 odd numbers and 120 numbers greater than 330.
Combinations are a fundamental concept in mathematics, particularly in the field of combinatorics, which deals with counting and arranging objects.
To solve this problem, we can use the concept of combinations, which is a way of counting the number of ways we can choose k items from a set of n items. In this case, we want to find the number of three-digit numbers we can form from the set {0, 1, 2, 3, 4, 5, 6}, without repeating any of the digits.
First, we can determine the number of ways we can choose the first digit. Since there are seven digits to choose from, we have 7 options for the first digit.
Next, we can determine the number of ways we can choose the second digit. Since we have already used one of the digits, we only have 6 options left for the second digit.
Finally, we can determine the number of ways we can choose the third digit. Since we have used two of the digits, we only have 5 options left for the third digit.
Therefore, the total number of three-digit numbers we can form is given by the product of the number of choices for each digit:
7 x 6 x 5 = 210
So there are 210 different three-digit numbers that can be formed using the digits 0, 1, 2, 3, 4, 5, and 6, without repeating any of the digits.
To find the number of odd numbers, we need to consider that the last digit must be either 1, 3, or 5, since these are the only odd digits in the set. We can choose the first two digits in the same way as before, and then choose one of the three odd digits for the last digit. Therefore, the number of odd three-digit numbers is:
6 x 5 x 3 = 90
To find the number of three-digit numbers greater than 330, we need to consider that the first digit must be either 3, 4, 5, or 6. We can choose the first digit in 4 ways, and then choose the remaining two digits as before. Therefore, the number of three-digit numbers greater than 330 is:
4 x 6 x 5 = 120
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16 The cost for parking at a city airport is shown in the table.
Price for first day
$16.60
For every
2
day afterwards
$9
Yuri pays $124.60 to park his car.
How many days does he park his car for?
Show your working.
Answer:
He paid $9 twelve times
12× 2= 24 days
Step-by-step explanation:
1st day = $16.60
3rd day=$ 9 (i.e for every 2days afterwards)
5th day=$ 9
Yuri pays : 124.60
124.60-16.60
= $108.00
After paying the first day he paid 108.00
108.00÷ 9 = 12
He paid $9 twelve times
12× 2= 24 days
task;2round off the following numbers to the highest place value.
Answer:
1.) 434 ____________
2.)5658 ____________
3.) 8374 ____________
4.) 361 ____________
5.) 7454 ____________
ito po ba ang i raround off
Step-by-step explanation:
answer:
1. 400
2.5000
3.8000
4.400
5.7000
kung ito po
#HOPE ITS HELP
Please answer correctly! I will mark you as Brainliest
Answer:
424.3m³
Step-by-step explanation:
I'm sorry, I don't have any proof because I used the go.ogle calculator, you're just gonna have to trust me on this one
The length of a rope is 0.05hm.Convert the length to cm
Answer: 500 cm
Step-by-step explanation:
multiply by 0.5 by 10000
pythagorean theorem calc: find b, a=7, c=25
Answer:
The value of side b is 24.
Step-by-step explanation:
To obtain the value of side b using the Pythagorean theorem, we have the following information:a = 7 (length of side a)
c = 25 (length of the hypotenuse, side c)
The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b). Mathematically, it can be written as:
a² + b² = c²
Substituting the given values:
7² + b²= 25^249 + b² = 625
To isolate b², we can subtract 49 from both sides:
b² = 625 - 49b² = 576
Taking the square root of both sides to solve for b:
b = √576
b = 24
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Evelyn and her friends bought 35 grams of cinnamon. They used 3.1 grams of it to make some snickerdoodle cookies. How much cinnamon do they have left?
Answer:
31.9 grams
Step-by-step explanation:
35 - 3.1 = 31.9 grams
Hope this helped you!
A compressive load of 80,000 lb is applied to a bar with
circular section0.75indiameter and a length of 10 in. if the
modulus of elasticity of the bar material is10,000 ksi and the
Poisson’s ratio i
The decrease in diameter of the bar due to the applied load is -0.005434905d and the final diameter of the bar is 1.005434905d.
A compressive load of 80,000 lb is applied to a bar with a circular section of 0.75 in diameter and a length of 10 in.
if the modulus of elasticity of the bar material is 10,000 ksi and the Poisson's ratio is 0.3.
We have to determine the decrease in diameter of the bar due to the applied load.
Let d be the initial diameter of the bar and ∆d be the decrease in diameter of the bar due to the applied load, then the final diameter of the bar is d - ∆d.
Length of the bar, L = 10 in
Cross-sectional area of the bar, A = πd²/4 = π(0.75)²/4 = 0.4418 in²
Stress produced by the applied load,σ = P/A
= 80,000/0.4418
= 181163.5 psi
Young's modulus of elasticity, E = 10,000 ksi
Poisson's ratio, ν = 0.3
The longitudinal strain produced in the bar, ɛ = σ/E
= 181163.5/10,000,000
= 0.01811635
The lateral strain produced in the bar, υ = νɛ
= 0.3 × 0.01811635
= 0.005434905'
The decrease in diameter of the bar due to the applied load, ∆d/d = -υ
= -0.005434905∆d
= -0.005434905d
The final diameter of the bar,
d - ∆d = d + 0.005434905d
= 1.005434905d
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A model rocket is fired vertically upward from rest. Its acceleration for the first 3 seconds is a(t) = 60t at which time the fuel is exhausted and it becomes a freely "falling" body. 14 seconds later, the rocket's parachute opens, and the (down)?
velocity slows linearly to -18 ft/s in 5 s. The rocket then "floats" to the ground at that rate.
(b) At what time does the rocket reach its maximum height? (Give your answer correct to one decimal place.)
What is that height? (Give your answer correct to the nearest whole number.)
(c) At what time does the rocket land? (Give your answer correct to one decimal place.)
To solve this problem, we will use the equations of motion for constant acceleration. We will break the problem into three parts:
The rocket's motion while the engine is firing (up to 3 seconds)
The rocket's motion as a freely falling body (from 3 seconds to 14 seconds)
The rocket's motion with the parachute deployed (from 14 seconds until it lands)
We will use the convention that up is positive, and down is negative.
(a) First, let's find the maximum height reached by the rocket. We can do this by finding the time when the rocket's velocity becomes zero (the peak of its trajectory).
For the first 3 seconds, the rocket's acceleration is given by a(t) = 60t. Integrating this with respect to time gives us the velocity as a function of time:
v(t) = ∫a(t) dt = 30t^2 + C1
At t = 0, the rocket is at rest, so C1 = 0.
For the first 3 seconds, the rocket's position is given by the double integral:
y(t) = ∫∫a(t) dt^2 = 10t^3 + C2t + C3
At t = 0, the rocket is at height y = 0, so C3 = 0. At t = 3 seconds, the rocket's velocity is v(3) = 270 ft/s. So we have:
270 = 30(3)^2 + C1
C1 = 180
Therefore, the velocity of the rocket at any time t during the first 3 seconds is:
v(t) = 30t^2 + 180 ft/s
From 3 seconds to 14 seconds, the rocket is in freefall. During this time, its acceleration is constant at -32.2 ft/s^2 (due to gravity). The velocity of the rocket at any time t during this period is given by:
v(t) = v(3) - 32.2(t - 3) = 270 - 32.2t
The position of the rocket at any time t during this period is given by:
y(t) = y(3) + v(3)(t - 3) - 16.1(t - 3)^2 = 540 - 16.1t^2
At t = 14 seconds, the rocket's velocity is -18 ft/s. So we have:
-18 = 270 - 32.2(14)
t = 17.4 seconds
Therefore, the rocket lands 17.4 seconds after it was launched.
(b) To find the maximum height reached by the rocket, we need to find the time t when its velocity is zero. This occurs when:
30t^2 + 180 - 32.2t = 0
t ≈ 3.53 seconds
Therefore, the rocket reaches its maximum height 3.53 seconds after it was launched. To find this height, we plug this time into the equation for y(t) during the first 3 seconds:
y(3.53) = 10(3.53)^3 = 436 ft
Therefore, the rocket reaches a maximum height of approximately 436 feet.
(c) We already found that the rocket lands 17.4 seconds after it was launched, so it lands at a time of 20.4 seconds (17.4 seconds after the engine shuts off).
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Simplify the expression. (2x5)4
2x20
16x20
16x9
2x625
Answer:
16 x^20
Step-by-step explanation:
(2x^5) ^4
We can separate this into
2^4 * x^5^4
We know that a^b^c = a^(b*c)
16 x^(5*4)
16 x^20
Answer:
The answer is b
Step-by-step explanation:
answer my question help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
375
425
.......................
Answer:
The correct answer is 375 and 425.
Step-by-step explanation:
Hope this helps:) Goodluck!
solve for x:
-6 + 4x = 13
Answer:
x = 19/4
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesStep-by-step explanation:
Step 1: Define equation
-6 + 4x = 13
Step 2: Solve for x
Add 6 to both sides: 4x = 19Divide both sides by 4: x = 19/4Step 3: Check
Plug in x to verify it's a solution.
Substitute: -6 + 4(19/4) = 13Multiply: -6 + 19 = 13Add: 13 = 13Here, we see that 13 does indeed equal 13.
∴ x = 19/4 is a solution of the equation.
what expression should replace A,B,C
Answer:
A = 5x + 3y
B = 8x + 5y
C = 15x + 11y
Step-by-step explanation:
B = 6x + 2y + 2x + 3y
= 6x + 2x + 2y + 3y
= 8x + 5y
C = 8x + 5y + 7x + 6y
= 8x + 7x + 5y + 6y
= 15x + 11y
A = 7x + 6y - 2x - 3y
= 7x - 2x + 6y - 3y
= 5x + 3y
A student is studying the ways different elements are similar to one another. Diagrams of atoms from four different elements are shown below.
Which two atoms are of elements in the same group in the periodic table?
Answer:
Step-by-step explanation:
the way to determine if two atoms are of elements in the same group in the periodic table is to look at the number of valence electrons in the outermost energy level of the atom. Elements in the same group have the same number of valence electrons. For example, elements in Group 1 have 1 valence electron, elements in Group 2 have 2 valence electrons, and so on.
It's worth mentioning that the group in the periodic table is also known as family or column.
5/10 divided by 7/9 I NEED THIS NOW!
Answer:
0.64285714285
Step-by-step explanation:
Answer: 9/14
In decimal form it’s 0.6428571 I don’t know how to explain this hopefully it works
A boy cycles 5km from his home to school and 8km from his home to the market. The chief's camp is closer to the boys home than the market but further than the school. Write a compound inequality to show the distance from the boys home to the chief's camp.
A compound inequality to show the distance from the boys home to the chief's camp is 5 < d < 8
How to explain the inequalityThe distance from the boy's home to the school is 5km.
The distance from the boy's home to the market is 8km.
The chief's camp is closer to the boy's home than the market, but further than the school
The chief's camp is closer to the boy's home than the market, so the distance from the boy's home to the chief's camp is less than 8km.
Putting these together, we can write a compound inequality to show the possible distances d from the boy's home to the chief's camp:
distance from home to school < distance < home to maket
5 < d < 8
The inequality is 5 < d < 8.
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Towns K and L are shown on a map.
a) Work out the actual distance between towns K and L.
b) A third town, M, is 150 km due
South of town K.
Mark Mon the map with X.
c) Measure the bearing of town L from town K.
a) The actual distance between towns K and L is: 100 km
b) As shown in the attached file
c) The bearing of town L from town K is 117 degrees.
How to Interpret the map?The scale of the map is given as:
1 cm to represent 50 km
Now, when we measure the distance between K and L on the map, we see that it gives us a distance of 2 cm.
Using the scale of 1 cm: 50 km, we can say that:
Actual distance between towns K and L = (2 * 50)/1 = 100 km
b) Using a compass and it’s 3cm aiming down {South} as seen in the attached photo. Then a line was drawn aiming {South} with a ruler. On the end of the line the (x) point was put there to get the mark.
c) Measuring the angle gives the bearing of town L from town K which is 117 degrees.
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Pierre de fermat a 17th century french lawyer stated that any whole number can be written as the sum of four or less square numbers for example 15 equals three squared +2 squared plus one squared plus one squared express 61 as such a sum
61 is the sum of two consecutive integers (-6,-5 ) and (5,6).
According to Pierr De Fermat any whole number writteen as the sum of four or less square numbers.
So 61 is the whole number so we can write in the sum of squares,
Now we know even+odd=odd so that let a and a+1 integer , according to Pierr De Fermat we can write,
a²+(a+1)²=61;
⇒a²+a²+2a+1=61
⇒2a²+2a-60=0
⇒a²+a-30=0 (∵divided by 2)
⇒a²+6a-5a-30=0
⇒a(a+6)-5(a+6)=0
⇒(a+6)(a-5)=0
⇒a+6=0 or a-5=0 ⇒a=-6 or a=5
If a=-6 then a+1=-6+1=-5.
if a=5 then a+1=5+1= 6.
so 61= (-6)²+(-5)² and 61= 6²+5².
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b2 - 12a when a = 1/4 and b = 8
Answer:
13
Step-by-step explanation:
b2-12a
2(8)-12(1/4)
16-12/4
16-3
13
Using Laplace Transforms, find the solution of the initial value problem: d²y +9y =9. sin(t). U(t - 3), = y(0) = y'(0) = 0 dx²
The solution to the given initial value problem, obtained using Laplace transforms, is y(x) = 0. This means that the function y(x) is identically zero for all values of x.
To find the solution of the initial value problem using Laplace transforms for the equation d²y/dx² + 9y = 9sin(t)u(t - 3), where y(0) = y'(0) = 0, we can follow these steps:
Take the Laplace transform of the given differential equation.
Applying the Laplace transform to the equation d²y/dx² + 9y = 9sin(t)u(t - 3), we get:
s²Y(s) - sy(0) - y'(0) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))
Since y(0) = 0 and y'(0) = 0, the Laplace transform simplifies to:
s²Y(s) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))
Solve for Y(s).
Combining like terms, we have:
Y(s) * (s² + 9) = 9 * (1/s² + 1/(s² + 1))
Multiply through by (s² + 1)(s² + 9) to get rid of the denominators:
Y(s) * (s⁴ + 10s² + 9) = 9 * (s² + 1)
Simplifying further, we have:
Y(s) * (s⁴ + 10s² + 9) = 9s² + 9
Divide both sides by (s⁴ + 10s² + 9) to solve for Y(s):
Y(s) = (9s² + 9)/(s⁴ + 10s² + 9)
Partial fraction decomposition.
To proceed, we need to decompose the right side of the equation using partial fraction decomposition:
Y(s) = (9s² + 9)/(s⁴ + 10s² + 9) = A/(s² + 1) + B/(s² + 9)
Multiplying through by (s⁴ + 10s² + 9), we have:
9s² + 9 = A(s² + 9) + B(s² + 1)
Equating the coefficients of like powers of s, we get:
9 = 9A + B
0 = A + B
Solving these equations, we find:
A = 0
B = 0
Therefore, the decomposition becomes:
Y(s) = 0/(s² + 1) + 0/(s² + 9)
Inverse Laplace transform.
Taking the inverse Laplace transform of the decomposed terms, we find:
L^(-1){Y(s)} = L^(-1){0/(s² + 1)} + L^(-1){0/(s² + 9)}
The inverse Laplace transform of 0/(s² + 1) is 0.
The inverse Laplace transform of 0/(s² + 9) is 0.
Combining these terms, we have:
Y(x) = 0 + 0
Therefore, the solution to the initial value problem is:
y(x) = 0
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CAN SOMEONE HELP ME PLEASE ASAP!?
Answer: 20 ft.
Step-by-step explanation:
Simply multiply 5 x 4.
Answer:
20 ft`
Step by step explanation:
N/A
PLEASE HELPPPPP
Franklin is an ecologist monitoring the catfish population in Athena Lake each year. When he first started monitoring the population one year ago, he estimated that there were 800 catfish in the lake. Today, Franklin estimates the population has decreased to 760 and it will continue decreasing each year.
1.Write an exponential equation in the form y=a(b)x that can model the estimated catfish population, y, x years after Franklin started monitoring it.
2.how many years after Franklin's first estimate will the catfish population be estimated as less than 600??
The exponential function is given by y = 800 (b)ˣ.
x = ln(0.75) / ln(b) is the first estimate will the catfish population be estimated as less than 600.
What is exponential function?An exponential function is a mathematical function of the form f(x) = aˣ, where a is a positive constant and x is the independent variable. The value of the function increases or decreases rapidly as x increases or decreases, depending on whether a is greater than 1 or less than 1, respectively. Exponential functions are commonly used to model growth or decay in various fields such as finance, biology, and physics.
The exponential equation in the form y = a(b)ˣ that can model the estimated catfish population, y, x years after Franklin started monitoring it, can be written as:
y = 800 * (b)^x
where:
y = estimated catfish population x years after Franklin started monitoring
a = initial population estimate, which is 800 in this case
b = growth/decay factor, which represents the rate at which the population changes each year
x = number of years after Franklin started monitoring
To find out how many years after Franklin's first estimate the catfish population will be estimated as less than 600, we can substitute y = 600 into the exponential equation and solve for x:
600 = 800 × (b)ˣ
Divide both sides by 800:
0.75 = (b)ˣ
Take the natural logarithm of both sides:
ln(0.75) = ln((b)ˣ)
x ln(b) = ln(0.75)
Divide both sides by ln(b):
x = ln(0.75) / ln(b)
Since the population is decreasing, the growth/decay factor, b, will be between 0 and 1. Without knowing the specific value of b, we cannot determine the exact number of years it will take for the catfish population to be estimated as less than 600. We would need to know the value of b in order to calculate x.
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Are my answers correct? Will give points if not correct can you solve please
The area of the smaller sector or minor sector is 125.66 yd².
The area of the larger sector or major sector is 326.73 yd².
What are the areas of the sector?The areas of the minor and major sectors is calculated by applying the following formulas follow;
Area of sector is given as;
A = (θ/360) x πr²
where;
r is the radius of the sectorθ is the angle of the sectorThe area of the smaller sector or minor sector is calculated as follows;
A = ( 100 / 360 ) x π ( 12 yd)²
A = 125.66 yd²
The area of the larger sector or major sector is calculated as follows;
θ = 360 - 100
θ = 260⁰
A = ( 260 / 360 ) x π ( 12 yd)²
A = 326.73 yd²
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Determine whether the relation is a function. (-11, 2), (-9,2), (-7, 3). (-5; 3). (-3.3)
A. yes
B. no
please help, brainliest if right
Answer:
yes it is
Step-by-step explanation:
each input only has one output (there arent any repeating numbers for x)
A. The scale along the vertical axis is not appropriate for the data.
B. The intervals along the vertical axis are not equal.
C. The average temperatures of some of the days are not correctly plotted.
D. On January 4 the temperature was higher than any other day.
Answer:
A
Step-by-step explanation:
beacuse it is more reasonable hope this helps