Please help immediately

Based on the Alternate Interior Angles Theorem, the measure of angle 3 in the image attached below is: 100°

If we have a situation where two parallel lines are intersected by a transversal, according to the Alternate Interior Angles Theorem, the pairs of alternate interior angles formed are congruent.

Angles 7 and 3 lie in the interior sides of the parallel lines but on opposite sides of the transversal, which makes them alternate interior angles. Therefore, based on the Alternate Interior Angles Theorem, we have:

m<3 = m<7

Substitute:

m<3 = 100°

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Answer:

74

Step-by-step explanation:

42+64=106

180-106=74

Answer:

c. is the correct answer

mark me as brainlist

Answer:

1080cm²

Step-by-step explanation:

Area of a quadrilateral = 1/2 x length of diagonal (length of perpendicular)

\( \frac{1}{2} \times 10(18 \times 12) \\ \frac{1}{2} \times 10(216) \\ \frac{1}{2} \times 2160 \\ {1080cm}^{2} \)

The most commonly cited disadvantage of using laboratory experiments to learn about human behavior is the lack of ecological validity.

Laboratory experiments involve studying human behavior in a controlled and artificial environment, often with specific tasks and conditions designed by researchers. While laboratory experiments offer advantages such as control over variables and the ability to establish cause-and-effect relationships, they also have limitations. One of the main disadvantages frequently mentioned is the lack of ecological validity. Ecological validity refers to the extent to which the findings from a study can be generalized to real-world settings and situations. Laboratory experiments often create an artificial setting that may not fully represent the complexities and nuances of everyday life.

Participants' behavior in a laboratory setting may differ from their behavior in natural settings due to factors such as the presence of observers, demand characteristics, and the controlled nature of the environment. As a result, the findings may not accurately reflect how individuals would behave in their natural environment, limiting the external validity and generalizability of the research findings. Researchers need to consider the trade-off between experimental control and ecological validity when designing studies and interpreting the results obtained from laboratory experiments.

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Answer:

41

Step-by-step explanation:

Answer:

\(41\)

Step-by-step explanation:

Use PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

\(160 \div (1+3^2)+5^3 - 10^2\)

\(160 \div (1+9)+5^3 - 10^2\)

\(160 \div (10)+5^3 - 10^2\)

\(160 \div (10)+125 -100\)

\(\dfrac{160}{10}+125-100\)

\(16+125-100\)

\(141-100=41\)

The inequalities equation which will shade all the points except target point are, y >= 2, y >= -3.5x + 4.5 and y <= 1.25x - 1.5.

The line passing through P(-1,2) and P(-4,2) has a slope of 0 and a y-intercept of 2, so its equation is y = 2. The line passing through P(-1,2) and P(-2,0.5) has a slope of -3.5 and a y-intercept of 4.5, so its equation is y = -3.5x + 4.5. The line passing through P(-2,0.5) and P(-4,2) has a slope of 1.25 and a y-intercept of -1.5, so its equation is y = 1.25x - 1.5.

Now we can create a system of inequalities that will shade all of the points except for T(-2,2). We can do this by making sure that the inequality for each line is greater than or equal to the target point on one side of the line, and less than or equal to the target point on the other side of the line.

For the line y = 2, we can write the inequality y >= 2 on the side of the line that contains the target point T(-2,2). For the line y = -3.5x + 4.5, we can write the inequality y >= -3.5x + 4.5 on the side of the line that contains the point T(-2,2). For the line y = 1.25x - 1.5, we can write the inequality y <= 1.25x - 1.5 on the side of the line that contains the point T(-2,2).

Putting all of these inequalities together, we get:

y >= 2 (for the line passing through P(-1,2) and P(-4,2))

y >= -3.5x + 4.5 (for the line passing through P(-1,2) and P(-2,0.5))

y <= 1.25x - 1.5 (for the line passing through P(-2,0.5) and P(-4,2))

These inequalities should shade all of the points except for the target point T(-2,2), and they should do so with the fewest number of inequalities possible.

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--The complete question is, With the fewest inequalities, shade all the points but leave the targets exposed. Write the inequality equations to do this.

Points are P(-1,2), P(-4,2) and P(-2, 0.5)

T(-2,2)
Graph is show in the image.--

Answer:

42,195

Step-by-step explanation:

Answer:

Your expression would be 150(11)=x

The answer to this expression would be 1,650. Producing the equation 150(11)= 1,650

Step-by-step explanation:

Your equation is 150(11)=x because; the hot air balloon owner charges $150 per ride. And there are 11 rides. So our equation is solely saying $150 charged per ride for 11 rides.

Let's solve this equation

150(11)= 1,650

So, we would multiply 150 by 11 to get 1,650.

And if your professor asks a statement for your equation you would say; The total income for the balloon owner that weekend is $1,650. $900 made on Saturday plus $750 made on Sunday.

, Hope this helps :)

Have a great day!!

Answer: $3.75

Step-by-step explanation:

Divide 15 by 4

Henry could only see one line since both lines had the same slope, which means that the graphs of both equations will be identical and hence overlap.

Linear equations in a system 3x + 2y = 4, and 9x + 6y = 12

We must demonstrate why Henry could only make out one line when he plotted the equations 3x-2y=4 and 9x-6y=12 on a graph.

Take the provided linear equation system into consideration.

3x - 2y = 4 ................(1)

9x - 6y = 12 ..................(2)

Due to the fact that equation (2) is a multiple of equation (1), 3 (3x - 2y = 4) = 9x - 6y = 12

The slopes of the provided equations are also same.

Difference with regard to x for equation (1) yields,

additional to equation (2),

With regard to x, we can differentiate to get,

The graphs of both equations will overlap since both lines have the same slope and hence have the same appearance on the graph.

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The equivalent fractions for 2/3 is (3×2)/(3×3) = 6/9 and for  5/12 is (4×5)/(4×12) = 20/48.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

The equivalent fraction for 2/3 is (3×2)/(3×3) = 6/9.

The equivalent fraction for 5/12 is (4×5)/(4×12) = 20/48.

We have to multiply the same number to both the numerator and denominator to get equivalent fractions.

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Answer:

I would say the answer is C

Step-by-step explanation:

Answer:

d + (4)

Step-by-step explanation:

The value of the double integral using the easier order, ydA bounded by y = x − 6; x = y² is 125/12.

The double integral, indicated by ', is mostly used to calculate the surface area of a two-dimensional figure. By using double integration, we may quickly determine the area of a rectangular region. If we understand simple integration, we can easily tackle double integration difficulties. Hence, first and foremost, we will go over some fundamental integration guidelines.

Given, the double integral ∫∫yA and the region y = x-6 and x = y²

y = x-6

x = y²

y² = y +6

y² - y - 6 = 0

y² - 3y +2y - 6 = 0

(y-3) (y+2) = 0

y = 3 and y = -2

\(\int\int\limits_\triangle {y} \, dA\\ \\\)

= \(\int\limits^3_2 {y(y+6-y^2)} \, dx \\\\\int\limits^3_2 {(y^2+6y-y^3)} \, dx \\\\(\frac{y^3}{3} + 3y^2-\frac{y^4}{4} )_-_2^3\\\\\frac{63}{4} -\frac{16}{3} \\\\\frac{125}{12}\)

The value for the double integral is 125/12.

Integration is an important aspect of calculus, and there are many different forms of integrations, such as basic integration, double integration, and triple integration. We often utilise integral calculus to determine the area and volume on a very big scale that simple formulae or calculations cannot.

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Given:

A diagram of Aram's observations.

To find:

The measure of the missing angle.

Solution:

From the given figure it is clear that the three angles \(52^\circ,x^\circ,68^\circ\) lie on a single point and right side of a straight line.

So, the sum of angle \(52^\circ,x^\circ,68^\circ\) must be \(180^\circ\).

\(52^\circ+x^\circ+68^\circ=180^\circ\)

\(x^\circ+120^\circ=180^\circ\)

\(x^\circ=180^\circ-120^\circ\)

\(x^\circ=60^\circ\)

Therefore, the measure of the missing angle is \(x^\circ=60^\circ\).

The correct statement regarding the null hypothesis is: the null hypothesis claims the opposite of what the researcher believes.

The null hypothesis is the claim that no relationship exists between two sets of data or variables being analyzed. The

null hypothesis is that any experimentally observed difference is due to chance alone, and an underlying causative

relationship does not exist, hence the term "null".

In research, the null hypothesis is a statement of no effect or no relationship between variables, while the alternative

hypothesis represents the effect or relationship the researcher is interested in demonstrating.

The purpose of statistical testing is to determine whether there is enough evidence to reject the null hypothesis in

favor of the alternative hypothesis.

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Answer:

if you can tell me what this ^means i can help you

The perimeter when 96 triangles are put together in the pattern shown below will be 98cm

Find the required triangle attached

In the diagram shown, we can see that we have 5 triangles.

The first thing we need to do is add one more triangle to have, six triangles,

Perimeter of the resulting 6 triangles = 6 + 2 = 8cm

For 8 triangles;

Perimter = 8 + 2 = 10cm

For "n" triangles;

Perimeter of n triangles = n + 2

Hence if 96 triangles are put together in the pattern shown below, hence

n = 96

Perimeter of the 96 triangles = 96 + 2

Perimeter of the 96 triangles = 98 cm

Hence the perimeter when 96 triangles are put together in the pattern shown below will be 98cm

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Answer:

X=6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

15=7x+3−5x

15=7x+3+−5x

15=(7x+−5x)+(3)(Combine Like Terms)

15=2x+3

15=2x+3

Step 2: Flip the equation.

2x+3=15

Step 3: Subtract 3 from both sides.

2x+3−3=15−3

2x=12

Step 4: Divide both sides by 2.

2x2=122

x=6

Answer:

x=6

Answer:

1/100

Step-by-step explanation:

the problem description is not copied fully.

but I think I understand it.

since the ratio of the perimeter is 1/10, so is then also the ratio for each side.

that means the longest side of ABC is 4 units (40/10), right ?

anyway, when the ratio of lengths and distance is 1/10, then the ratio for the area is 1/10×1/10 = 1/100.

because for the area (baseline × height / 2) two lengths have to be multiplied. and that multiplies the scaling factor twice into the calculation effectively squaring it as the area scaling factor.

and 1/10×1/10 = (1/10)² = 1/100

The approximate distance in km between her house and her job is 9 km.

The map is a scale drawing of the places mentioned. A scale drawing is a smaller image of a larger place or diagram.

The scale of the map = 8cm : 12km

Distance between the house and the job = (12 x 6) / 8 = 9m

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Answer:

5x/3

Step-by-step explanation:

Therefore, Wn = (R1 + R2 +...+Rn) / (X1 + X1 +...+Xn), Wn -> E[R]/E[X] as n -> [infinity] by using the law of large numbers.

The formula Wn = (R1 + R2 +...+Rn) / (X1 + X1 +...+Xn) represents the average reward earned during the first n cycles in a renewal reward process. To show that Wn -> E[R]/E[X] as n -> [infinity], we need to use the law of large numbers. This law states that as the number of observations increases, the sample average will converge to the expected value of the variable being observed. In this case, as n -> [infinity], the sample average Wn will converge to the expected value of the ratio E[R]/E[X], which is the desired result.

Therefore, Wn = (R1 + R2 +...+Rn) / (X1 + X1 +...+Xn), Wn -> E[R]/E[X] as n -> [infinity] by using the law of large numbers.

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Main Answer: As n approaches infinity, Wn converges to E[R]/E[X].

Supporting Question and Answer:

How can we show that a sequence of random variables converges to a certain value?

To show that a sequence of random variables converges to a certain value, we can use mathematical techniques such as the law of large numbers or limit theorems.

Body of the Solution:To show that Wn converges to E[R]/E[X] as n approaches infinity, we need to demonstrate that the limit of Wn as n approaches infinity is equal to E[R]/E[X].

Let's break down the problem step by step:

First, let's define the random variables involved:

R1, R2, ... Rn:

Rewards obtained during each cycle (assumed to be independent and identically distributed random variables).

X1, X2, ... Xn:

Lengths of each cycle (also assumed to be independent and identically distributed random variables).

We are given that y1 and y2 are linearly independent solutions to the homogeneous differential equation, which means they are distinct solutions and not proportional to each other.

The average reward earned during the first n cycles, Wn, is defined as the sum of rewards R1, R2, ..., Rn divided by the sum of cycle lengths X1, X2, ..., Xn.

To show that Wn converges to E[R]/E[X] as n approaches infinity, we need to show that the limit of Wn as n approaches infinity is equal to E[R]/E[X].

We can start by expressing Wn in terms of the expected values of R and X:

Wn = (R1 + R2 + ... + Rn) / (X1 + X2 + ... + Xn) = (1/n) * (R1 + R2 + ... + Rn) / (1/n) * (X1 + X2 + ... + Xn)

Now, let's consider the numerator (R1 + R2 + ... + Rn) and denominator (X1 + X2 + ... + Xn) separately:

The numerator (R1 + R2 + ... + Rn) is the sum of n independent and identically distributed random variables with mean E[R].

The denominator (X1 + X2 + ... + Xn) is the sum of n independent and identically distributed random variables with mean E[X].

As n approaches infinity, by the law of large numbers, the sum of these random variables will converge to n times their respective means. Therefore, we can rewrite the numerator and denominator as:

(R1 + R2 + ... + Rn) approaches n * E[R]

(X1 + X2 + ... + Xn) approaches n * E[X]

Substituting these limits into our expression for Wn:

Wn = (1/n) * (R1 + R2 + ... + Rn) / (1/n) * (X1 + X2 + ... + Xn) = (1/n) * (n * E[R]) / (n * E[X]) = E[R] / E[X]

Thus, we have shown that as n approaches infinity, Wn converges to E[R]/E[X].

This demonstrates that the average reward earned during the first n cycles, Wn, approaches the ratio of the expected reward E[R] to the expected cycle length E[X] as the number of cycles increases.

Final Answer: Therefore,we prove that Wn -> E[R]/E[X] as n -> [infinity].

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No of extra miles:-

\(\\ \tt\hookrightarrow 16.54/0.25=66.16mi\)

Now

Total average miles

\(\\ \tt\hookrightarrow 159+66.16=216.16mi/day\)

The number of miles that you can drive per day, on average, and not exceed your daily budget of $60.00 will be 216.16 miles.

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

A Ford Taurus at Enterprise Rent-a-Car rents for $43.46 per day. You receive 150 free miles per day but are charged $0.25 per mile for any additional miles.

Let x be the number of miles that you drive and y be the total rent. Then the equation will be

y = 0.25(x - 150) + 43.46

Then the number of miles that you can drive per day, on average, and not exceed your daily budget of $60.00 will be

60 = 0.25(x - 150) + 43.46

60 = 0.25(x - 150) + 43.46

16.54 = 0.25(x - 150)

66.15 = x - 150

x = 150 + 66.15

x = 216.16 miles

Thus, the number of miles that you can drive per day, on average, and not exceed your daily budget of $60.00 will be 216.16 miles.

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Assuming the rectangular piece of land is what is given in the image attached below, and each units = 1,000 ft, therefore:

Length = 8,000 ft

Width = 2,000 ft

Therefore, assuming the rectangular piece of land is what is given in the image attached below, and each units = 1,000 ft, therefore:

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Answer:

\(60\pi\:\mathrm{cm^2}\)

Step-by-step explanation:

The total surface area of a cone with radius \(r\) and slant height \(\ell\) is equal to \(SA=\pi r\ell+r^2\pi\).

What we're given:

Substituting given values, we get:

\(SA=3\cdot 17\cdot \pi+3^2\pi,\\SA=51\pi+9\pi,\\SA=\boxed{60\pi\:\mathrm{cm^2}}\)

Answer:

B) 6<x<90

Step-by-step explanation:

48+42=90

48-42=6

There will be a number greater than and a number less than x.

90>6

6<x<90

Hope this helps :)

Answer:

perpendicular

Step-by-step explanation: