PLEASE HELP !!! ILL GIVE BRAINLIEST!! *DONT SKIP* ILL GIVE 40 POINTS.

t = 0.06p

================================================

Explanation:

If we plugged in p = 2, then,

t = 0.06*p = 0.06*2 = 0.12

Showing that the point (2, 0.12) is on the diagonal line of the equation t = 0.06p

This matches with what the graph shows.

The y axis is incrementing by $0.025, aka 2.5 cents, each tickmark upward. Counting up 5 tickmarks will get you to $0.125 or 12.5 cents which is fairly close to 12 cents.

When you divided the x and y values to find the constant of variation, you divided in the wrong order. You should do y/x instead of x/y.

Answer:

One third or 1/3

Step-by-step explanation:

We can see here that matching the steps for constructing a congruent line segment to their pictures, we have:

Step 1 - Picture a

Step 2 - Picture b

Step 3 - Picture c

Step 4 - Picture c.

Any portion of a line with two ends and a set length is referred to as a line segment. It differs from a line that has neither a beginning nor an end and can be stretched in both directions.

The endpoints of a line segment can be used to define it. The portion of the line that begins at point A and finishes at point B, for instance, is known as the line segment AB.

A ruler or measuring tape can be used to determine the length of a line segment. The distance between two line segments' endpoints is the segment's length.

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Answer:

Step-by-step explanation:

The Value of the expression with p = 1/2 and s = 3 1/2 is 87/6.

To evaluate the expression with p = 1/2 and s = 3 1/2, we substitute these values into the given expression:

3p + 2s + 6 1/3

Substituting p = 1/2 and s = 3 1/2:

3(1/2) + 2(3 1/2) + 6 1/3

We first simplify the expression within parentheses:

3/2 + 2(7/2) + 6 1/3

Next, we perform the multiplication:

3/2 + 14/2 + 6 1/3

The denominators are already the same, so we can add the fractions:

3/2 + 14/2 + 6 1/3 = (3 + 14)/2 + 6 1/3

Now, we need to find a common denominator for the fraction and the whole number:

(3 + 14)/2 + 6 1/3 = 17/2 + 6 1/3

To add the fractions, we need a common denominator of 6:

17/2 + 6 1/3 = 17/2 + 18/3

Now, we can find a common denominator for the fractions:

17/2 + 18/3 = 51/6 + 36/6

Adding the fractions:

51/6 + 36/6 = 87/6

Therefore, the value of the expression with p = 1/2 and s = 3 1/2 is 87/6.

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Answer:   She practices 5 hours a day

Step-by-step explanation:  6 days a week x 4 weeks = 24 days

120 hours of practice / 24 days = 5 hours of practice a day

Answer:

5hrs

Step-by-step explanation:

120 ÷ 4 = 30. 30 ÷ 6 = 5. She practices for 5hrs a week.

The 46th term of the sequence is 324.

We have,

To find the 46th term of the sequence, we need to determine the pattern or rule that generates the terms.

Since the difference between consecutive terms is a constant value of 7, we know that this is an arithmetic sequence with a common difference

of 7.

To find the 46th term, we can use the formula for the nth term of an arithmetic sequence:

a(n) = a(1) + (n - 1) d

where a(1) is the first term, d is the common difference, and n is the term number we want to find.

Using the given information, we have:

a(1) = 9

d = 7

n = 46

Plugging these values into the formula, we get:

a (46) = 9 + (46 - 1)7

a (46) = 9 + 45 (7)

a(46) = 9 + 315

a(46) = 324

Therefore,

The 46th term of the sequence is 324.

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When you toss 7 fair coins, the number of ways that it is possible to obtain at least two heads is 120 ways.

First, find the number of outcomes when tossing 7 fair coins:
= 2 x 2 x 2 x 2 x2 x 2 x 2

= 128 outcomes

The total number of ways you can attain at least two heads is:
= Total outcomes - Outcomes where only 1 head is obtained - Outcomes where no heads are obtained

= 128 - 7 - 1

= 120 outcomes

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∠A = 41.81°

To get measure of angle A, we would apply trigonometry ratio SOHCAHTOA:

opposite = side opposite the angle = 4

hypotenuse = 6

adjacent = base = AC = ?

Since we have been given the opposite and the hypotenuse, we would use the sine ratio:

Sin A = opposite/hypotenuse

Sin A = 4/6

sin A = 0.6667

A = 41.8129 degrees

To the nearest hundredth, ∠A = 41.81°

Answer:  9

Step-by-step explanation:

Y=x2=9

Answer:

176.842105263

Step-by-step explanation:

multiply 210 by 3/19 to get the miles downhill and subtract that from 210 to get the uphill

On a bicycle trip of 210 miles in the mountains and 3/19 of the trip is Downhill, Number of  miles of the trip are not downhill is, 33 miles.

A ratio in mathematics is a comparison of two or more numbers that shows how big one is in comparison to the other. The dividend or number being divided is referred to as the antecedent, while the divisor or number that is dividing is referred to as the consequent.

Given that,

Total bicycle trip of 210 miles in the mountains

3/19 of the trip is Downhill

Downhill = 3/19(210)

Downhill = 33 miles

Miles of the trip are not downhill  = 210-33

                                                        = 177

Hence, the not downhill distance is 177 miles

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Answer:

\(\textsf{(a)} \quad \textsf{Increasing}: \quad \left(-\infty, \dfrac{-1-\sqrt{13}}{2}\right) \cup \left(\dfrac{-1+\sqrt{13}}{2}, \infty\right)\)

        \(\textsf{Decreasing}: \quad \left(\dfrac{-1-\sqrt{13}}{2} < x < \dfrac{-1+\sqrt{13}}{2}\right)\)

\(\textsf{(b)} \quad \textsf{Minimum}: \quad \left(\dfrac{-1-\sqrt{13}}{2},\dfrac{19+13\sqrt{13}}{2}\right)\)

        \(\textsf{Maximum}: \quad \left(\dfrac{-1+\sqrt{13}}{2},\dfrac{19-13\sqrt{13}}{2}\right)\)

\(\textsf{(c)} \quad \textsf{Point of inflection}: \quad \left(-\dfrac{1}{2}, \dfrac{19}{2}\right)\)

        \(\textsf{Concave up}: \quad \left(-\dfrac{1}{2}, \infty\right)\)

        \(\textsf{Concave down}: \quad \left(- \infty,-\dfrac{1}{2}\right)\)

Step-by-step explanation:

Given function:

\(f(x) = 2x^3 + 3x^2-18x\)

\(\textsf{A function is \textbf{increasing} when the \underline{gradient is positive}}\implies f'(x) > 0\)

\(\textsf{A function is \textbf{decreasing} when the \underline{gradient is negative}} \implies f'(x) < 0\)

Differentiate the given function:

\(\implies f'(x)=3 \cdot 2x^{3-1}+2 \cdot 3x^{2-1}-18x^{1-1}\)

\(\implies f'(x)=6x^2+6x-18\)

Complete the square:

\(\implies f'(x)=6(x^2+x-3)\)

\(\implies f'(x)=6\left(x^2+x+\dfrac{1}{4}-3-\dfrac{1}{4}\right)\)

\(\implies f'(x)=6\left(x^2+x+\dfrac{1}{4}\right)-\dfrac{39}{2}\)

\(\implies f'(x)=6\left(x+\dfrac{1}{2}\right)^2-\dfrac{39}{2}\)

Increasing

To find the interval where f(x) is increasing, set the differentiated function to more than zero:

\(\implies f'(x) > 0\)

\(\implies 6\left(x+\dfrac{1}{2}\right)^2-\dfrac{39}{2} > 0\)

\(\implies 6\left(x+\dfrac{1}{2}\right)^2 > \dfrac{39}{2}\)

\(\implies \left(x+\dfrac{1}{2}\right)^2 > \dfrac{39}{12}\)

\(\implies \left(x+\dfrac{1}{2}\right)^2 > \dfrac{13}{4}\)

\(\textsf{For\;\;$u^n > a$,\;\;if\;$n$\;is\;even\;then\;\;$u < -\sqrt[n]{a}$\;\;or\;\;$u > \sqrt[n]{a}$}.\)

Therefore:

\(x+\dfrac{1}{2} < -\sqrt{\dfrac{13}{4}}\implies x < \dfrac{-1-\sqrt{13}}{2}\)

\(x+\dfrac{1}{2} > \sqrt{\dfrac{13}{4}}\implies x < \dfrac{-1+\sqrt{13}}{2}\)

So the interval on which function f(x) is increasing is:

\(\left(-\infty, \dfrac{-1-\sqrt{13}}{2}\right) \cup \left(\dfrac{-1+\sqrt{13}}{2}, \infty\right)\)

Decreasing

To find the interval where f(x) is decreasing, set the differentiated function to less than zero:

\(\implies f'(x) < 0\)

\(\implies 6\left(x+\dfrac{1}{2}\right)^2-\dfrac{39}{2} < 0\)

\(\implies \left(x+\dfrac{1}{2}\right)^2 < \dfrac{13}{4}\)

\(\textsf{For\;\;$u^n < a$,\;\;if\;$n$\;is\;even\;then\;\;$-\sqrt[n]{a} < u < \sqrt[n]{a}$}.\)

Therefore:

\(x+\dfrac{1}{2} > -\sqrt{\dfrac{13}{4}}\implies x > \dfrac{-1-\sqrt{13}}{2}\)

\(x+\dfrac{1}{2} < \sqrt{\dfrac{13}{4}}\implies x < \dfrac{-1+\sqrt{13}}{2}\)

So the interval on which function f(x) is decreasing is:

\(\left(\dfrac{-1-\sqrt{13}}{2} < x < \dfrac{-1+\sqrt{13}}{2}\right)\)

To find x-coordinates of the local minimum and maximum set the differentiated function to zero and solve for x:

\(\implies f'(x)=0\)

\(\implies 6\left(x+\dfrac{1}{2}\right)^2-\dfrac{39}{2} =0\)

\(\implies \left(x+\dfrac{1}{2}\right)^2 =\dfrac{13}{4}\)

\(\implies x=\dfrac{-1-\sqrt{13}}{2},\;\;\dfrac{-1+\sqrt{13}}{2}\)

To find the y-coordinates of the turning points, substitute the found values of x into the function and solve for y:

\(\implies f\left(\dfrac{-1-\sqrt{13}}{2}\right)=\dfrac{19+13\sqrt{13}}{2}\)

\(\implies f\left(\dfrac{-1+\sqrt{13}}{2}\right)=\dfrac{19-13\sqrt{13}}{2}\)

Therefore:

\(\textsf{Minimum}: \quad \left(\dfrac{-1-\sqrt{13}}{2},\dfrac{19+13\sqrt{13}}{2}\right) \approx (-2.30, 32.94)\)

\(\textsf{Maximum}: \quad \left(\dfrac{-1+\sqrt{13}}{2},\dfrac{19-13\sqrt{13}}{2}\right) \approx (1.30, -13.94)\)

At a point of inflection, f''(x) = 0.

To find the point of inflection, differentiate the function again:

\(\implies f''(x)=12x+6\)

Set the second derivative to zero and solve for x:

\(\implies f''(x)=0\)

\(\implies 12x+6=0\)

\(\implies x=-\dfrac{1}{2}\)

Substitute the found value of x into the original function to the find the y-coordinate of the point of inflection:

\(\implies f\left(-\dfrac{1}{2}\right)=\dfrac{19}{2}\)

Therefore, the inflection point is:

\(\left(-\dfrac{1}{2}, \dfrac{19}{2}\right)\)

A curve y = f(x) is concave up if f''(x) > 0 for all values of x.

A curve y = f(x) is concave down if f''(x) < 0 for all values of x.

Concave up

\(\implies f''(x) > 0\)

\(\implies 12x+6 > 0\)

\(\implies x > -\dfrac{1}{2}\)

\(\implies \left(-\dfrac{1}{2}, \infty\right)\)

Concave down

\(\implies f''(x) < 0\)

\(\implies 12x+6 > 0\)

\(\implies x < -\dfrac{1}{2}\)

\(\implies \left(- \infty,-\dfrac{1}{2}\right)\)

Answer:

Option 1

Step-by-step explanation:

\(\frac{2x^2 - 7x-4}{x^2 - 5x+4}=\frac{(x-4)(2x+1)}{(x-4)(x-1)}=\frac{2x+1}{x-1}\)

The intersection (2,2) (2,4) (8,4) (8,2) is  (5,3).

On the coordinate plane, the four points that are given together form a rectangle. We must first locate the midway of both diagonals in order to determine where the diagonals will connect.

The midpoint of the diagonal that passes through the points (2,2) and (8,4) is ((2+8)/2, (2+4)/2). (5,3).

The midpoint of the diagonal that passes through the points (2,4) and (8,2) is ((2+8)/2, (4+2)/2). (5,3).

Consequently, the diagonals' point of intersection is (5,3).

Due to the fact that a rectangle's two diagonals meet here in the middle, this location also serves as the rectangle's centre.

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Answer:

4

Step-by-step explanation:

If 1/20 of the metal is lost during casting. Calculate the number of complete slabs casted. (4mks)

The value of m + n is given as follows:

A. 18.

The exponential expression for this problem is defined as follows:

\((x^5y^6)^{\frac{1}{5}}(x^3y^4}^{\frac{1}{4}}\)

Applying the power of power rule, we have that the exponents are given as follows:

Then the values of m and n are given as follows:

m = 7, n = 11.

Thus the sum is given as follows:

m + n = 7 + 11 = 18.

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\(\begin{array}{llll} f(x)~from\\\\ x_1 ~~ to ~~ x_2 \end{array}~\hfill slope = m \implies \cfrac{ \stackrel{rise}{f(x_2) - f(x_1)}}{ \underset{run}{x_2 - x_1}}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array} \\\\[-0.35em] ~\dotfill\\\\ f(x)= 2x^2 + x -3 \qquad \begin{cases} x_1=0\\ x_2=2 \end{cases}\implies \cfrac{f(2)-f(0)}{2 - 0} \\\\\\ \cfrac{[2(2)^2 + (2) -3]~~ - ~~[2(0)^2 +(0) -3]}{2}\implies \cfrac{7-(-3)}{2}\implies \cfrac{7+3}{2}\implies \text{\LARGE 5}\)

The rate of change for the interval between 0 and 2 for the quadratic equation will be 5. Then the correct option is C.

It is the average amount by which the function varied per unit throughout that time period. It is calculated using the gradient of the line linking the interval's ends on the graph depicting the function.

Average rate = [f(x₂) - f(x₁)] / [x₂ - x₁]

The function is given below.

f(x) = 2x² + x - 3

The rate of change of the function for the interval between 0 to 2 is calculated as,

Average rate = [f(2) - f(0)] / [2 - 0]

Average rate = [(2(2)² + 2 - 3) - (2(0)² + 0 - 3)] / 2

Average rate = 10 / 2

Average rate = 5

The rate of change for the interval between 0 and 2 for the quadratic equation will be 5. Then the correct option is C.

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Answer:2

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

Change 3 into a fraction.

Which gives you 3/1

multiply 3/1 by the inverse of 1/6

3/1x1/6

Then you get 1 :)

Answer:

Yes

Step-by-step explanation:

60 × 13 = 780 milliliters

due to 971 > 780

therefore there is enough buffer solution in the bottle for all 13 experiments

Answer:

2.98

Step-by-step explanation:

First find 3% of 16.05 which is 0.48.

Then add 0.48 to 16.05 which is 16.53.

Then multiply .18 by 16.53 which gets you 2.98

Hope it helps

Answer:

To find the amount of the sales tax, we need to multiply the bill amount by the tax rate of 3% or 0.03:

Sales tax = 0.03 x $16.05 = $0.48

To find the total amount of the bill after the sales tax was added, we need to add the bill amount to the sales tax:

Total bill = $16.05 + $0.48 = $16.53

To find the amount of the tip, we need to calculate 18% of the total bill after the sales tax was added:

Tip = 0.18 x $16.53 = $2.98

Rounding to the nearest cent, Penelope left a tip of $2.98.

Step-by-step explanation:

Complete question

The complete question is shown on the first uploaded image

Answer:

Wind direction [Mode] is South west

The [Mean] temperature is  \(T  =  91\)

The  [Bimodal] pavement is  Dry Wet

Step-by-step explanation:

From the question the first question is to determine the wind direction

Generally from the wind direction would be the data with the highest frequency on the wind column i.e the mode of the data, this because this variable(wind direction ) is a nominal level type of level of measurement where the value assigned to the variable are for classification of the data (i.e telling what the data is all about )

So

The mode is South west

This means that the wind direction is South west

From the question the second question is to determine the temperature

Generally given that their are are no outlier that will skew the data we can obtain the temperature by calculating the mean for the temperature column

This is mathematically represented as

\(T = \frac{89 + 86 + \cdots + 93 + 93}{8}\)

          \(T  =  91\)

From the question the first question is to determine the  pavement

Generally from the pavement would be the data with the highest frequency on the pavement i.e the mode of the data, this because this variable(pavement ) is a nominal level type of level of measurement where the value assigned to the variable are for classification of the data (i.e telling what the data is all about )

From the table we see that the pavement that the pavement column is bimodal

So the mode is Dry  Wet

This mean that the pavement is Dry Wet

m=number of miles

A=$110+$0.50m

B=$80+$0.80m

$110+$0.50m=$80+$0.80m Subtract ($80+$0.50m)

$30=$0.30m Divide each side by $0.30

100=m ANSWER: More than 100 miles must be driven per day to make Company A a better deal.

Answer:

33 \(\frac{99}{100}\)

Step-by-step explanation:

hope this helps :)

Answer:99/100

Step-by-step explanation:

(a) | BD | bisects | AC | (reason : Given)

(b) |AD| ≅ |CD| (reason: |BD| is the perpendicular bisector of segment AC).

(c) ∠ABD ≅ ∠CBD (reason: | BD |  bisects angle ABC)

(d) ∠A ≅ ∠ C (reason: complementary angles of a right triangle)

Congruent angles are the angles that have equal measure. So all the angles that have equal measure will be called congruent angles.

From the first statement, we will complete the flow chart as follows;

line BD bisects line AC (reason : Given)

line AD is congruent to line CD (reason: line BD is the perpendicular bisector of segment AC)

Angle ABD is congruent to angle CBD (reason: line BD bisects angle ABC)

Angle A is congruent to angle C (reason: angle ABD = angle CBD, and both triangles ABD and CBD are right triangles).

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Answer:

a. Mb = 188.6

b. Ma = 184.8

c. The upper-bound 95% confidence interval for the mean is (-∞, -1.3).

As the upper bound of the confidence interval is negative, we are 95% confident that the true mean difference is negative and the treatment is effective.

Step-by-step explanation:

The matched-pair sample data we have is:

Before After Difference

247.7 232.9 -14.8

177.8 169.7 -8.1

152.7 151.6 -1.1

115.9 119.1          3.2

242.5 241         -1.5

121.7 126.2 4.5

241.3 234.5 -6.8

212.8 217.7 4.9

182.5 176.7 -5.8

231.3 222.8 -8.5

225.9 217.2 -8.7

155.3 154.4 -0.9

187.9 177.5 -10.4

149.4 139.3 -10.1

187.7 194.1 6.4

176.4 174.3 -2.1

197.7 191.8 -5.9

We can calculate the mean and standard deviation of the before weight as:

\(M_b=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_b=\dfrac{1}{17}(247.7+177.8+152.7+. . .+197.7)\\\\\\M_b=\dfrac{3206.5}{17}\\\\\\M_b=188.6\\\\\\s_b=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_b)^2}\\\\\\s_b=\sqrt{\dfrac{1}{16}((247.7-188.6)^2+(177.8-188.6)^2+(152.7-188.6)^2+. . . +(197.7-188.6)^2)}\\\\\\s_b=\sqrt{\dfrac{27057.6}{16}}\\\\\\s_b=\sqrt{1691.1}=41.1\\\\\\\)

We can calculate the mean and standard deviation of the after weight as:

\(M_a=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_a=\dfrac{1}{17}(232.9+169.7+151.6+. . .+191.8)\\\\\\M_a=\dfrac{3140.8}{17}\\\\\\M_a=184.8\\\\\\s_a=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_a)^2}\\\\\\s_a=\sqrt{\dfrac{1}{16}((232.9-184.8)^2+(169.7-184.8)^2+(151.6-184.8)^2+. . . +(191.8-184.8)^2)}\\\\\\s_a=\sqrt{\dfrac{23958}{16}}\\\\\\s_a=\sqrt{1497.4}=38.7\\\\\\\)

As this is a matched-paired data, we can test the effectiveness of the program using the sample data for the difference of each pair.

First, we calculate the mean and standard deviation of the pair differences:

\(M_d=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_d=\dfrac{1}{17}((-14.8)+(-8.1)+(-1.1)+. . .+(-5.9))\\\\\\M_d=\dfrac{-65.7}{17}\\\\\\M_d=-3.9\\\\\\s_d=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_d)^2}\\\\\\s_d=\sqrt{\dfrac{1}{16}((-14.8-(-3.9))^2+(-8.1-(-3.9))^2+(-1.1-(-3.9))^2+. . . +(-5.9-(-3.9))^2)}\\\\\\s_d=\sqrt{\dfrac{607.7}{16}}\\\\\\s_d=\sqrt{38}=6.2\\\\\\\)

We have to calculate a 95% confidence interval for the paired difference.  We are only interested in the upper bound, so the lower bound is not calculated.

If the upper bound is negative, that means that we are 95% confident that the mean difference is negative or significantly smaller than 0, which means that the treatment is effective.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=-3.9.

The sample size is N=17.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

\(s_M=\dfrac{s}{\sqrt{N}}=\dfrac{6.2}{\sqrt{17}}=\dfrac{6.2}{4.123}=1.504\)

The degrees of freedom for this sample size are:

\(df=n-1=17-1=16\)

The t-value for an upper-bound 95% confidence interval and 16 degrees of freedom is t=1.746.

The margin of error (MOE) can be calculated as:

\(MOE=t\cdot s_M=1.746 \cdot 1.504=2.63\)

Then, the lower and upper bounds of the confidence interval are:

\(UL=M+t \cdot s_M = -3.9+2.63=-1.3\)

The upper-bound 95% confidence interval for the mean is (-∞, -1.3).

As the upper bound of the confidence interval is negative, we are 95% confident that the true mean difference is negative and the treatment is effective.

Answer:

50.75

Step-by-step explanation:

We have:

\(E[g(x)] = \int\limits^{\infty}_{-\infty} {g(x)f(x)} \, dx \\\\= \int\limits^{1}_{-\infty} {g(x)(0)} \, dx+\int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx+\int\limits^{\infty}_{6} {g(x)(0)} \, dx\\\\= \int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x+3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x)\frac{2}{x} } \, dx + \int\limits^{6}_{1} {(3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {8} \, dx + \int\limits^{6}_{1} {\frac{6}{x} } \, dx\\\\\)

\(=8\int\limits^{6}_{1} \, dx + 6\int\limits^{6}_{1} {\frac{1}{x} } \, dx\\\\= 8[x]^{^6}_{_1} + 6 [ln(x)]^{^6}_{_1}\\\\= 8[6-1] + 6[ln(6) - ln(1)]\\\\= 8(5) + 6(ln(6))\\\\= 40 + 10.75\\\\= 50.74\)

The graph could be the graph of exponential function of option b)

\(F(x) = 2 • (0.5)^{x} \)

The general form of an exponential function is

\(f(x) = {ab}^{x} \)

Here, a is the function's starting value and b is its growth factor.

F(x) is an increasing function if b > 1, and if b<1, then f(x) is a decreasing function

The function's initial value is 2 as can be seen from the provided graph. Therefore, a has a value of 2.

Given that the graph indicates that the function is decreasing, b must be less than 1.

It indicates that the necessary function is in the form of

\(f(x) = 2(b)^{x} \)

Where it is b<1

By checking option B, b=0.5<1. Hence, option B is the correct answer

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Note that the full question is:

(check the attached image)

Answer:

13 weeks because he loses 3 pounds per week

Step-by-step explanation:

269-251=39

39 divided by 3 = 13

13 weeks is your answer!

please mark brainliest please!!!

Answer:

A.  True

Step-by-step explanation:

Answer:

can we get a picture

Step-by-step explanation: