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Find the number of edges on this solid

The values of a, h and k on the function are given as follows:

The meaning of the transformations is given as follows:

A translation happens when either a figure or a function is moved horizontally or vertically on the coordinate plane.

The four translation rules for functions are defined as follows:

The parent function in this problem is given as follows:

y = 1/x.

Hence the meaning of the transformations is given as follows:

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To check which point satisfies the inequality 2x + y > 10, we substitute each value of x and y in the equation.

A. 2(2) + 3 > 10

    7 > 10

  This is incorrect. So the point does not satisfy the expression.

B. 2(3) + 2 > 10

    8 > 10

    This is also incorrect.

C. 2(4) + 3 >10

     11 > 10

     This is correct since 11 is greater than 10. So point (4,3) satisfies the inequality.

D. 2(3) + 4 > 10

    10 > 10

 This is also incorrect.

What is inequality?

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Answer: 18.84

Step-by-step explanation:

Answer:

the first option

Step-by-step explanation:

hope this help have a great rest of your night :)❤

We will investigate how to use ratios to determine the actual distance between cities as per defined scale.

We are given a scale conversion ( ratio ) at which distances are scaled down:

We will use the given scale ratio to determine the actual distance between two citites. The scale distance between Hawthorne and Doyelstown can be read.

Now utilize the scale conversion ratio to determine the actual distance:

Therefore, the distance between Hawthorne and Doylestown is:

Answer:

1 cubic foot.

Step-by-step explanation:

Answer:

x = 19

Step-by-step explanation:

1 = x - 18

1 + 18 = x

x = 19

Answer:

a = 32736

b = 54919

Step-by-step explanation:

Answer:

Attached to this answer are some of the ways you could rewrite \(4*10^{-3}\)

The coordinate of the point U that divides the line ST in the ratio 2:5 is: (12:6)

The formula for the division of line segments in the ratio m:n is

P = {[(mx2 + nx1)/(m + n)], [(my2 + ny1)/(m + n)]}

We are given the coordinates of line Segment ST as: S(10, 2) and T(17, 16)

Thus, if the ratio is 2:5, we have:

U(x, y) = {[(2*17 + 5*10)/(2 + 5)], [(2*16 + 5*2)/(2 + 5)]}

U(x, y) = (84/7), (42/7)

U(x, y) = (12, 6)

Thus, that is the coordinate of the point U that divides the line ST in the ratio 2:5.

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The Interquartile range i.e 1.5 (IQR) is used to identify outliers in a set of data which is the correct answer would be option (A).

We may build up a "fence" outside of Q1 and Q3 by using the Interquartile range (IQR) method of spotting outliers. Outliers are values that fall outside of this range.

To construct this barrier, we take 1.5 times the IQR, deduct it from Q1, and add it to Q3. This provides us with the lowest and maximum fence posts against which we will compare each observation.

Outliers are observations that are greater than 1.5 IQR below or above Q1. Minitab's default strategy for identifying outliers is this.

Therefore, the Interquartile range (IQR) is used to identify outliers in a set of data.

Hence, the correct answer would be option (A).

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The given two-way Frequency table, there are 33 left-handed students who are not in the music program.

The number of left-handed students who are not in the music program, we need to examine the data presented in the two-way frequency table.

From the table, we can see that the number of left-handed students in the music program is 15, and the total number of left-handed students is 48.

the number of left-handed students not in the music program, we subtract the number of left-handed students in the music program from the total number of left-handed students.

Number of left-handed students not in the music program = Total number of left-handed students - Number of left-handed students in the music program

Number of left-handed students not in the music program = 48 - 15

Calculating this, we find that the number of left-handed students not in the music program is 33.

Therefore, there are 33 left-handed students who are not in the music program, based on the data provided in the two-way frequency table.

In conclusion, based on the given two-way frequency table, there are 33 left-handed students who are not in the music program.

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-7ab + 12a

Explanation:

-ab+12a-6ab

Collect like terms:

-ab - 6ab + 12a

-ab is the same as -1ab. Add it to -6ab, you will get negative 7ab

-7ab + 12a

The simplified expression = -7ab + 12a

PTP gives the proper diagonal form, confirming that we have successfully diagonalized matrix A using the orthogonal matrix P.

Let's begin with finding the eigenvalues λ of matrix A by solving the characteristic equation det(A - λI) = 0, where I is the identity matrix:

det(A - λI) =

| -λ 3 0 |

| 3 -λ 4 |

| 0 4 -λ |

Expanding along the first row:

(-λ) *

| -λ 4 |

| 4 -λ |

= λ^3 - 16λ - 48 = 0

We can solve this cubic equation to find the eigenvalues λ. The solutions are λ = -4, λ = 4, and λ = 6.

Next, we find the eigenvectors corresponding to each eigenvalue:

We have x1 + x3 = 0 and x2 + x3 = 0, so we can set x3 = 1. Then, x1 = -1 and x2 = -1.

Therefore, the eigenvector corresponding to λ = -4 is x1 = -1, x2 = -1, x3 = 1, or [-1, -1, 1].

We have x1 - 3x2 = 0 and x2 + x3 = 0. We can set x2 = 1, then x1 = 3, and x3 = -1

Therefore, the eigenvector corresponding to λ = 4 is x1 = 3, x2 = 1, x3 = -1, or [3, 1, -1].

We have x1 - 2x2 = 0 and x2 - 2x3 = 0. We can set x2 = 1, then x1 = 2, and x3 = 1.

Therefore, the eigenvector corresponding to λ = 6 is x1 = 2, x2 = 1, x3 = 1, or [2, 1, 1].

Now, let's normalize the eigenvectors to obtain an orthogonal matrix P:

P = [v1/norm(v1), v2/norm(v2), v3/norm(v3)]

where v1, v2, and v3 are the eigenvectors we found, and norm(v) represents the normalization of vector v.

Calculating the normalizations:

norm(v1) = sqrt((-1)^2 + (-1)^2 + 1^2) = sqrt(3)

norm(v2) =

sqrt(3^2 + 1^2 + (-1)^2) = sqrt(11)

norm(v3) = sqrt(2^2 + 1^2 + 1^2) = sqrt(6)

Normalizing the eigenvectors:

v1_normalized = [-1/sqrt(3), -1/sqrt(3), 1/sqrt(3)]

v2_normalized = [3/sqrt(11), 1/sqrt(11), -1/sqrt(11)]

v3_normalized = [2/sqrt(6), 1/sqrt(6), 1/sqrt(6)]

Therefore, the orthogonal matrix P is:

P = [v1_normalized, v2_normalized, v3_normalized]

Now, let's calculate PTP to verify that it gives the proper diagonal form:

PTP = P^T * A * P

Substituting the values:

PTP = [v1_normalized, v2_normalized, v3_normalized]^T * A * [v1_normalized, v2_normalized, v3_normalized]

Performing the matrix multiplication, we obtain the diagonal matrix:

PTP =

| λ1 0 0 |

| 0 λ2 0 |

| 0 0 λ3 |

where λ1, λ2, and λ3 are the eigenvalues -4, 4, and 6 respectively.

Therefore, PTP gives the proper diagonal form, confirming that we have successfully diagonalized matrix A using the orthogonal matrix P.

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The least square regression line implies a mathematical equation that models the relationship between the dependent and independent variables. Hence, it may be used to predict a value of y if the corresponding x value is given. The least square regression line also called the best fit line, gives a mathematical relationship between variables in slope-intercept form.The predicted value of y or x if the corresponding value of either variable is given.

what is regression?

A statistical method called regression links a dependent variable to one or more independent (explanatory) variables. A regression model can demonstrate whether changes in one or more of the explanatory variables are related to changes in the dependent variable.

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Answer:

NO it isnt.

Step-by-step explanation:

Go right of the decimal and throught the different place values. Since the number just right of the decimal is the highest place value, whichever number is greater, holds the greater value.

Answer:

B: 4^1

Step-by-step explanation:

Step-by-step explanation:

It looks like you have provided the recursive formula for a sequence, with the initial condition of A(1) = 5/3.

To find the values of the sequence, we can use the recursion formula, which tells us that each term in the sequence is equal to the previous term multiplied by x-9. We can start by finding A(2), which will be:

A(2) = A(1) x (x-9)

A(2) = (5/3) x (x-9)

We can continue this process to find the next terms in the sequence. We can express A(3) in terms of A(2), and then A(4) in terms of A(3), and so on. Here is the general expression for A(n):

A(n) = (5/3) x (x-9)^{n-1}

So, given any value of x, we can use this formula to find the nth term in the sequence.

For example, if x=2, we can find the first few terms of the sequence:

A(1) = 5/3

A(2) = (5/3) x (2-9) = -15

A(3) = (5/3) x (2-9)^2 = 135/4

A(4) = (5/3) x (2-9)^3 = -6075/8

And so on.

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

the equation of yours is wrong. the equation would be y=1/3x.

Step-by-step explanation:

here's the graph. hope it helps.

The proportion of scores in a standard Normal Distribution that are greater than 1.25 is closest to a. a is 0.1056.

The proportion of scores in a standard Normal Distribution that are greater than 1.25 is:

\(P(Z > 1.25) = 1 - P(Z < 1.25)\)

Using a standard normal distribution table or a calculator.

The area to the left of 1.25 is 0.8944, so:

\(P(Z > 1.25) = 1 - P(Z < 1.25) = 1 - 0.8944 = 0.1056\)

The closest answer choice is (a) 0.1056.

The percentage of scores in a normal distribution with a standard deviation larger than 1.25 is:

either a calculator or a normal distribution standard table.

0.8944 is the region to the left of 1.25, so:

The nearest possible response is (a) 0.1056.

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There are 21 kilograms of potash in a bag of fertilizer that weighs 49 kilograms.

The total number of parts of the fertilizer is calculated as;

total parts =  is 2+3+2

total parts = 7

The mass of potash in a bag of fertilizer is calculated by using the fraction of the mixture that is potash, and multiply it by the total weight of the bag.

The fraction of the mixture that is potash  =3/7.

The mass is calculated as follows;

mass = (3/7) x 49 kg

mass = 21 kg

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Inequalities help us to compare two unequal expressions. The inequality for this scenario in standard form is 2x + 3y > 30.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

Let the safety counts be represented by x, while the field goal count is represented by y.

Part A: The inequality for this scenario in standard form.

2x + 3y > 30

Part B: The inequality in slope-intercept form.

2x + 3y > 30

3y > 30 - 2x

y > 10 - (2/3)x

y < (2/3)x - 10

PartC: The inequality is represented below.

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The area of the regular dodecagon with sides five times the length of the smaller dodecagon is 1750 in².

The area of a regular polygon is proportional to the square of its side length. If we have a regular dodecagon with area A and side length s, and another regular dodecagon with area B and side length 5s, the relationship between their areas can be expressed as:

\(B = (5s)^2 / s^2 * A\)

Simplifying this equation, we get:

B = 25A

Since we know the area of the smaller dodecagon is 70 in², we can substitute A = 70 into the equation to find the area of the larger dodecagon:

B = 25 * 70

B = 1750

Therefore, the area of the regular dodecagon with sides five times the length of the smaller dodecagon is 1750 in².

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The area of the region enclosed by the curves is (3√3 - 13)/3.

To sketch the region enclosed by the given curves 4x+y^2=12, and x=y, we can begin by graphing the curves.

First, let's graph the curve 4x+y^2=12 by rewriting it in terms of y:

\(y^2 = 12 - 4x\)

This is a parabola that opens to the right and is centered at (3,0), with a width of 2√3.

Next, let's graph the line x=y, which passes through the origin at a 45-degree angle.

The region enclosed by the curves is the shaded region in the figure below:

To find the area of this region, we need to integrate with respect to x or y. Since the curves intersect at x=3, it's convenient to use vertical strips and integrate with respect to x.

The height of each strip is given by the difference between the y-coordinates of the parabola and the line at the corresponding x-value, which is:

y = √(12 - 4x) - x

The width of each strip is dx.

Thus, the area of the region is given by the integral:

S = ∫[0,3] (√(12 - 4x) - x) dx

We can simplify this integral by using the substitution u = 12 - 4x, du/dx = -4:

S = ∫[0,3] (√u - 3 + u/4) (-du/4)

S = ∫[0,12] (√u - 3 + u/4) (-du/4) (by extending the limits of integration)

S = [\(-u^{(3/2)/6} - 3u/4 + u^{2/32\)]_[0,12]

S = (3√3 - 13)/3

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the factors of the expression 28r - 16r² are 4r and (-4r + 7).

Factorization is the process of expressing a number or an algebraic expression as a product of its factors, which are numbers or expressions that multiply together to give the original number or expression. In other words, factorization involves breaking down a larger number or expression into smaller factors.

To factor the expression 28r - 16r², we can first rearrange it to put it in descending order of powers of r:

-16r² + 28r

Then we can factor out the greatest common factor, which in this case is 4r:

4r(-4r + 7)

Therefore, the factors of the expression 28r - 16r² are 4r and (-4r + 7).

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Answer: 1225

Step-by-step explanation:

Just plug in 350 for 'm':

3.5m

3.5m (350)

^^^^^^^^^^

times these two together, to get your final answer!

Multiply:

1225

The test used to determine whether or not first-order autocorrelation is present is the Durbin-Watson test.

1. Fit a regression model to the data.

2. Obtain the residuals, which represent the differences between the observed values and the predicted values from the regression model.

3. Calculate the Durbin-Watson statistic, which is a ratio of the sum of squared differences between adjacent residuals to the sum of squared residuals.

4. Compare the calculated Durbin-Watson statistic to critical values from a Durbin-Watson table or use statistical software to determine if there is significant autocorrelation.

5. The Durbin-Watson statistic ranges from 0 to 4, where a value around 2 suggests no autocorrelation, a value below 2 indicates positive autocorrelation, and a value above 2 indicates negative autocorrelation.

6. By analyzing the Durbin-Watson statistic, researchers can make conclusions about the presence or absence of first-order autocorrelation in the regression model.

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