In a beer brewery, the levels of maintenance refer to the different stages or categories of maintenance activities that are performed to ensure the smooth operation and reliability of the brewing equipment and facilities. These levels can vary depending on the complexity of the maintenance tasks and the skills required to perform them. Here are the explanations for two levels of maintenance commonly seen in beer breweries:
1. Level 1 - Organizational Maintenance:
At this level, the maintenance activities primarily focus on the day-to-day operations and basic upkeep of the brewing equipment. These tasks are often carried out by the operational staff at the brewery site who have basic maintenance skills. The activities involved at this level may include routine inspections, cleaning, lubrication, and minor repairs or adjustments. The goal is to maintain the equipment in good working condition, prevent breakdowns, and ensure the production process runs smoothly.
2. Level 2 - Intermediate Maintenance:
The intermediate maintenance level involves more specialized tasks that may require the involvement of dedicated maintenance personnel or specialized technicians. This level includes maintenance activities performed on mobile or fixed units within the brewery, such as specific brewing vessels, fermentation tanks, or packaging equipment. These tasks often require a higher level of technical expertise and knowledge of the brewing process. Examples of activities at this level can include equipment calibration, troubleshooting and diagnostics, preventive maintenance, component replacement, and equipment optimization.
It's important to note that the levels of maintenance may vary depending on the size of the brewery, the complexity of the brewing process, and the level of automation in place. Larger breweries with more advanced equipment and automation systems may have additional levels of maintenance, such as advanced diagnostics and predictive maintenance, to ensure maximum efficiency and minimize downtime.
In summary, the levels of maintenance in a beer brewery range from basic organizational maintenance performed by operational staff to intermediate maintenance carried out by dedicated maintenance personnel or specialized technicians. These levels reflect the varying complexity and skill requirements of the maintenance tasks involved in ensuring the smooth operation of the brewery's equipment and facilities.
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In California, the Pacific plate slides past the North American plate. If the Pacific plate is moving at a speed of 5 centimeters per year, how long will it take for the plate to travel 100 meters?
Answer:
500
Explanation:
sddds2
Question: convert 32 °C to F
Answer:
89.6
Explanation:
(Cx9/5)+32=F
F=89.6
Answer:
the answer is 89.6 Fahrenheit
a balloon flies off when the opening is released a. Newton’s First Law b. Newton’s Second Law c. Newton’s Third Law
B. Newtons second law! Have a great day!
which of these interactions that hold hair strands together is/are ph sensitive? i. a salt bridge ii. a hydrogen bond iii. a disulfide linkage group of answer choices i, ii, and iii i and iii i and ii iii only i only
The interactions that hold hair strands together and are pH-sensitive are (iii) a disulfide linkage. The correct answer is "iii only".
Disulfide linkages are formed between sulfur atoms in the amino acid cysteine, which is present in the protein structure of hair. These linkages are responsible for the structural stability and strength of hair. When the pH of the hair is altered, such as through the use of chemical treatments or hair products, the disulfide linkages can be disrupted. This can lead to changes in the shape and texture of the hair. Therefore, the presence and integrity of disulfide linkages in hair are pH-sensitive. On the other hand, salt bridges and hydrogen bonds, mentioned in options (i) and (ii) respectively, are not directly pH-sensitive. Salt bridges are ionic interactions that can be influenced by pH indirectly through changes in ionization states of charged amino acids. Hydrogen bonds, while important for the structure of hair, are not directly affected by pH changes.
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Which factor causes a decrease in the rate of dissolution?
There are several factors that can cause a decrease in the rate of dissolution:
Decrease in temperature: As the temperature decreases, the kinetic energy of the particles decreases, and the rate of dissolution also decreases.
Increase in solute concentration: If the solution is already saturated with solute, then adding more solute will cause it to become supersaturated, which can cause a decrease in the rate of dissolution.
Increase in pressure: Increasing the pressure can force more solute into the solution, but it can also cause an increase in the solubility of the solute, which can cause a decrease in the rate of dissolution.
Decrease in surface area: If the solute is in the form of large particles, then breaking it down into smaller particles will increase the surface area available for dissolution and increase the rate of dissolution. Conversely, decreasing the surface area will decrease the rate of dissolution.
Formation of a precipitate: If the solute is capable of forming a precipitate in the solution, then the rate of dissolution may decrease as the solute is removed from the solution and deposited as a solid.
~~~Harsha~~~
The following compound is used as an adhesive in the oil and gas industry.
Classify the molecular geometry of the following compound
Answer:
See Explanation
Explanation:
The compound involved here is BF3(boron triflouride). The central atom is boron and it is surrounded by three fluorine atoms as shown in the image.
When a molecule has three electron domains in its structure, the molecule is trigonal planar. Hence, the molecular geometry of the compound is trigonal planar.
(subject is astronomy)
Part C
As you conduct your research, be sure to take notes from the sources you’ve identified. You might need a day or two to do your research. Consider using these reading strategies when analyzing texts and websites.
In the space provided here, describe one piece of data that you found about Proxima Centauri, and explain the technology humans used to collect this data.
One piece of data found about Proxima Centauri is that it has a small rocky planet orbiting around it, known as Proxima Centauri b, which is located within its habitable zone.
This data was collected using the radial velocity method, a technique used to detect exoplanets by measuring the periodic variations in the star's spectral lines as it wobbles around its center of mass due to the gravitational pull of orbiting planets.
The technique involves analyzing the Doppler shift of the star's light as it moves towards or away from Earth, indicating changes in the star's radial velocity caused by the presence of a planet. The radial velocity method has been used to detect thousands of exoplanets, including Proxima Centauri b, and provides valuable information about their mass and orbit.
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Calculate the enthalpy change for the reaction: 4Al(s) + 3MnO2(s) --> 2Al2O3 (s) + 3Mn(s)2Al(s) + 3/2 O2 (g) --> Al2O3(s). ∆ H=-1676.0 kJMn(s) + O2 (g) --> MnO2(s). ∆ H = -521.0 kJ
Explanation:
To solve this question, we need to use the Hess's Law.
Hess's Law states that: in a chemical reaction, the heat released or absorbed is constant and independent of the number of steps the reaction goes through. That is, the law states that the enthalpy change of a chemical reaction depends only on its initial state and its final state.
Hess's Law is also known as the law of the sum of heats of reaction, because the enthalpy change is equal to the sum of the changes in the steps through which the chemical reaction passes (intermediate reactions). The calculation is performed as follows:
- If the chemical reaction is inverted, the sign of the enthalpy change must also be inverted;
- If the equation is multiplied, the enthalpy change must also be multiplied;
- If dividing the equation, the enthalpy change must also be divided.
So we're going to invert, divide, or multiply each given equation in order to get the equation that the question gives us.
The equation the question gives us is:
4Al(s) + 3MnO2(s) --> 2Al2O3 (s) + 3Mn(s)
Let's multiply the first equation by 2:
4 Al + 3 O2 --> 2 Al2O3
ΔH = -1676 * 2 = -3,352 kJ
Let's invert and multiply by 3 the second equation:
3 MnO2 -> 3 Mn + 3O2
ΔH = -521 * 3 * (-1)
ΔH = 1,563 kJ
Answer: -1,789 kJ
Which phrase is an accurate description of the process of erosion
The correct option is C. Erosion is the process by which the earth surface get worn down. It involves the removal of soil, rocks or dissolved material from one location and its transportation to another location.
2) Provide a systematic name for each of the following compounds below:
CCCCC(CC)C(C)C(C)C
CCCCC(CC)C(C)C
CC(C)C(C(C)C)C(C)C
Systematic name for each of the following compounds are C49H74O4, C49H74O4, C49H74O4 respectively.
What is natural compound?
Pure compounds are created while factors integrate permanently, forming one substance. For example, while the factors mercury and oxygen integrate, and a chemical response takes place, mercury (II) oxide is created.
A chemical compound is a chemical substance composed of many equal molecules containing atoms from multiple chemical detail held collectively with the aid of using chemical bonds. A molecule which includes atoms of most effective one detail is consequently now no longer a compound
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Carbon cycle – What are the main reservoirs
of the carbon cycle? Where do the inorganic and organic carbon
cycles interact? What are the major differences and similarities
between the inorganic and organic carbon?
The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.
The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.
Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.
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id like to know is it bakudeku or bakukiri?
Answer:
bakukiri
Explanation:
hmmmm...
Answer:
BakuKiri I think is canon
Explanation:
Cause th crator made it like that :v
In which Group do most of the elements have 8 valence electrons?
A. Transition metals
B. Alkaline earth metals
C. Halogens
D. Noble gases
a. calculate the molarity and normality of a 140.0 mg/l solution of h2so4; find the concentration of the same solution in units of ""mg/l as caco3"".
1 L of the acid solution contains 142.85 mg of CaCO3.
Given, mass of H2SO4 = 140 mg / L
The molecular weight of H2SO4 = 98g / mol
Molarity = mass of H2SO4 / molecular weight of H2SO4 = 140/98 = 1.4285
Normality = Molarity x n factor n factor for H2SO4 = 2Molarity = 1.4285
Normality = 2 x 1.4285 = 2.857 mg / mL1 mol of H2SO4 = 98 g
Hence, 1 ml of H2SO4 = 98/1000 = 0.098gCaCO3 has a molecular weight of 100 g. Therefore, 1 mole of CaCO3 has a mass of 100 g. According to this, 1 mole of CaCO3 reacts with 2 moles of H2SO4.
The normality of the acid is 2.857.
Hence, 1 L of the acid will have 2.857 moles of H2SO4.To calculate the concentration in mg/L of the acid in terms of CaCO3, we need to first find the number of moles of CaCO3 that can be reacted with 2.857 moles of H2SO4.2 moles of H2SO4 react with 1 mole of CaCO3.Therefore, 2.857 moles of H2SO4 will react with:
1 mole of CaCO3/2 moles of H2SO4 = 1.4285 moles of CaCO3In 1 L of the acid, there are 1.4285 moles of CaCO3.The mass of 1.4285 moles of CaCO3 = 1.4285 x 100 = 142.85 g / L
Therefore, 1 L of the acid solution contains 142.85 mg of CaCO3.
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Which of the following is a source of carbon dioxide in atmosphere?
Answer:
Natural sources like decomposition, ocean release, and respiration.
Human activities like cement production, deforestation, and the burning of fossil fuels like coal, oil and natural gas.
An ion has an atomic number of 13, a mass number of 27, and 10 electrons. How many neutrons does the nucleus of the ion have?
14
13
3
27
Answer:
\(\huge\boxed{\sf 14}\)
Explanation:
Atomic number = 13
Mass number = 27
No. of neutrons:= Mass number - Atomic number
= 27 - 13
= 14\(\rule[225]{225}{2}\)
HELP
Balance the following skeleton equation and determine how many grams of water can be produced when 50.0 grams of Al(OH)3 react with 60.0 grams of H2SO4 .
Al(OH)3 + H2SO4 --> Al2(SO4)3 + H2O
Explanation:
2Al(OH)3 + 3H2SO4 --> Al2 (SO4)3 + 6H2O
Create a chart that compares physical and chemical properties. Give two examples for each type of property
Answer:
look the image
Explanation:
Compare the value you obtain using average bond energies to the actual standard enthalpy of formation of gaseous benzene, 82.9 kJ/mol . What does the difference between these two values tell you about the stability of benzene
This difference in the actual and estimated standard enthalpy of formation of gaseous benzene tells us that benzene is much more stable than we would expect based on the average bond energies.
How to calculate the standard enthalpy of formation of gaseous benzene?To calculate the standard enthalpy of formation of gaseous benzene using average bond energies, we need to break all the bonds in the reactants and form all the bonds in the products, and then calculate the energy change involved in the process.
Using average bond energies, we can estimate the enthalpy change for the reaction:
\(C_{6}H_{6}\)(g) → 6 C(g) + 3 \(H_{2}\)(g)
The bond energies we need to use are:
C-C: 347 kJ/mol
C=C: 611 kJ/mol
C-H: 413 kJ/mol
Breaking the bonds in benzene requires:
6 C-C bonds × 347 kJ/mol = 2082 kJ/mol
3 C=C bonds × 611 kJ/mol = 1833 kJ/mol
12 C-H bonds × 413 kJ/mol = 4956 kJ/mol
Total energy required to break the bonds in benzene = 8871 kJ/mol
Forming the bonds in the products requires:
6 C atoms × 0 kJ/mol = 0 kJ/mol
3 H-H bonds × 436 kJ/mol = 1308 kJ/mol
Total energy released when forming the bonds in the products = 1308 kJ/mol
Thus, the estimated enthalpy change for the reaction is:
ΔH = (energy required to break bonds) - (energy released when forming bonds) = 8871 kJ/mol - 1308 kJ/mol = 7563 kJ/mol
However, the actual standard enthalpy of formation of gaseous benzene is 82.9 kJ/mol. Therefore, the difference between the estimated value and the actual value is significant.
This is because the structure of benzene is highly delocalized, with the π-electrons distributed evenly over all six carbon atoms in the ring. This delocalization stabilizes the molecule and reduces its energy, making it more stable than we would expect based on the energy required to break its individual bonds.
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. Sketch the nucleotide being described: it uses a monosaccharide present in RNA, and a nitrogenous base found only in RNA. Point an arrow to the glycosidic bond.
Answer:
See below
Explanation:
The glycosidic bond forms between the carbon atom on the glucose molecule and the nitrogen atom present on the nitrogenous base. A diagram has been attached to show this particular bond. There is also a phosphate molecule bonded on the sugar molecule at the other end.
When 127.68 g of brass at 163 °C are added to 150.00 g H₂O at 22.4 °C, the final
temperature
for brass.
of the brass and water is 32.6 °C. Calculate the value of the specific heat, c,
For water: q = cmΔT = 4.18 ∙ 150 (32.6 – 22.4) = 6395.4J
For brass: c = q / mΔT = 6395 / 127.68 (163 – 32.6) = 0.384 J / gC
What is water?
The global economy depends heavily on water. Agriculture uses over 70% of the freshwater that people use. 6.5% of the world's protein comes from fishing in salt and fresh water bodies, which has been and still is an important source of food for many regions of the world. Commodities (including oil, natural gas, and manufactured goods) are frequently transported across vast distances by boats over the oceans, rivers, lakes, and canals. In both industry and residences, huge amounts of water, ice, and steam are utilised for cooling and heating. Water is utilised extensively in industrial processes, as well as in cooking and washing, as it is a great solvent for a wide range of compounds, both mineral and organic.To know more about water, click the link given below:
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a solution is made by mixing 9.76 ml of 4.00 m acetone, 4.11 ml of 1.00 m hcl, 10.00 ml of 0.0500 m i2 and 20.00 ml of water. what is the concentration of the acetone immediately after mixing (in m). give your answer to 3 sig figs)
concentration of the acetone immediately after mixing
We are given:
- Molarity of Acetone\($=4.0 \mathrm{M}$,\)
- Volume of Acetone\($=11 \mathrm{~mL}=0.011 \mathrm{~L}$,\)
- Volume of\($B r_2=16 \mathrm{~mL}$,\)
- Volume of \($\mathrm{HCl}=11 \mathrm{~mL}$\), and
- Volume of Water\($=16 \mathrm{~mL}$.\)
therefore Total Volume of Solution\($=(11+16+11+16) m L=54 m L=0.054 L$\)and
Total No. of moles \(\mathrm{M} \times 0.011 \mathrm{~L}$$=0.044 \mathrm{~mol}$\)of Acetone = Molarity of Acetone \($\times$\) Volume of Acetone i =4.0
\($\therefore$ Molarity of Acetone $=\frac{\text { No. of moles of Acetone }}{\text { Volume of solution in liter }}$\)
\($=\frac{0.044 \mathrm{~mol}}{0.054 \mathrm{~L}}$$=0.815 M$Hence, Concentration of Acetone (in Molarity) is $0.815 \mathrm{M}$.\)
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FOR BRAINLY
21-24
PLEASE DONT GUESS
Answer:
2 in front of the H and O for number 21
2 in vfront of the Ag as the left aside of the equation
1 in front of everything for 23
1 in front of everything for 24
Explanation:
The Ka value for acetic acid, CH3COOH(aq), is 1.8x10^-5. Calculate the ph of a 2.80 M acetic acid solution.
PH=
Calculate the ph of the resulting solution when 3.00 mL of the 2.80 M acetic acid is diluted to make a 250.0 mL solution.
PH=
Answers are not 4.6 or 3.8
The pH of the solution containing 2.80 M acetic acid is 2.34.
Given, The Ka value for acetic acid, CH3COOH(aq), is 1.8x10^-5.Molar concentration of acetic acid, CH3COOH(aq), is 2.80 M.
Step 1 The equation for the ionization of acetic acid is as follows.CH3COOH(aq) + H2O(l) ⇆ H3O+(aq) + CH3COO-(aq)
Step 2Expression for Ka isKa = [H3O+][CH3COO-]/[CH3COOH(aq)]1.8 x 10-5 = [H3O+][CH3COO-]/2.80[H3O+] = √(Ka [CH3COOH(aq)]) = √(1.8 x 10-5 x 2.80) = 0.00462 M
Step 3pH = -log[H3O+] = -log(0.00462) = 2.34
So, the pH of the solution containing 2.80 M acetic acid is 2.34.
Acetic acid (CH3COOH) is a weak acid with a Ka value of 1.8x10⁻.
By utilizing this Ka value and the molar concentration of acetic acid, the pH of a 2.80 M acetic acid solution can be calculated.
Using the equation Ka = [H3O+][CH3COO-]/[CH3COOH(aq)], and after simplifying,
it can be determined that [H3O+] = √(Ka [CH3COOH(aq)]).
After substituting the values for Ka and [CH3COOH(aq)], [H3O+] is found to be 0.00462 M.
Finally, pH can be calculated by the expression pH = -log[H3O+], and we obtain the answer of pH=2.34.
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what is the volume of 0.284g of carbon dioxide at STP ??
Answer:
Explanatio
NCO2= 0, 248 /44= 0 ,005636
VCO2= 0,005636* 22,4= 0 ,126254545
When writing the chemical formulas for a molecular compound, what method do you use?
Answer:
A molecular compound is usually composed of two or more nonmetal elements. Molecular compounds are named with the first element first and then the second element by using the stem of the element name plus the suffix -ide.
1.5g of magnesium ribbon is burnt in oxygen to produce 2.5g of magnesium oxide. How much oxygen is required in grams?
Answer:
2.5 grams
Explanation:
law of conservation of mass applies. the magnesium completely burns
A compound of bromine and fluorine is used to make uf6, which is an important chemical in processing and reprocessing of nuclear fuel. The compound contains 58. 37 mass percent bromine. Determine its empirical formula.
The empirical formula for the given compound is BrF₃.
It is given that,
% of Br = 58.37
then % of F = 100 - 58.37 = 41.63%
Let the mass of the compound be 100 g. So, the percentages given are taken as mass.
Mass of Br = 58.37 g
Mass of F = 41.63 g
To formulate the empirical formula,
No. of moles of Br = 58.37/79.90 = 0.73 moles
No. of moles of F = 41.63/19 = 2.19 moles.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.73 moles.
For Bromine = 0.73/0.73 = 1
For Fluorine = 2.19/0.73 = 3
Now, taking the mole ratio as their subscripts.
The ratio of Br : F = 1 : 3
Hence, the empirical formula for the given compound is BrF₃.
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How many moles of iron is needed to react completely with 5.00 moles of sulfur to form iron
Fe + S -->
no
Answer:
5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur
Explanation:
The balanced equation in this question is
Iron + Sulfur = Iron(II) Sulfide
Fe (II) + S --> Fe(II)S
Thus one mole of sulfur reacts with one mole of Fe(II)
Hence, 5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur
Ethanol is used as a fuel.
c2h5oh + 3o2 3h2o + 2co2
the complete combustion of one mole of ethanol releases 1350kj of energy.
a sample of ethanol reacts with excess oxygen to make 0.240dm3 of carbon dioxide,
measured at room temperature and pressure.
calculate the energy released, in kj, in this reaction
The energy released in this reaction can be calculated by using the stoichiometry of the balanced equation.
Since the balanced equation shows that 2 moles of ethanol produce 2 moles of CO2, we can assume that the reaction of 1 mole of ethanol will produce 1 mole of CO2. Therefore, we can use the given volume of 0.240 dm3 of CO2 to calculate the moles of CO2 produced.
From the balanced equation, we know that 1 mole of ethanol produces 2 moles of CO2. Since the volume of CO2 is given, we can use the ideal gas law to convert the volume to moles. Assuming room temperature and pressure (RT = 22.4 L/mol), we can calculate the moles of CO2 produced.
Once we have the moles of CO2, we can use the given energy value of 1350 kJ/mol to calculate the energy released in this reaction. Since 1 mole of ethanol produces 1350 kJ of energy, and we have determined the moles of CO2 produced, we can multiply the moles of CO2 by the energy value to obtain the energy released in kJ.
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