Please answer the question as soon as possible. I will mark you the brainliest answer. Thank you. Show working out.

Answer:

i tink it is store A

Step-by-step explanation:

because it has the large medium value.. hope this answer helpes you..

Answer:

the answer is B. Store B

Answer:

If 5 is added to the square of a positive number,the sum is 69.find the number.

pls mark me as a brainalist pls

Answer:

20.4

Step-by-step explanation:

that is the procedure above

Answer:

Step-by-step explanation:

Answer:

20 miles in 2 hours

Step-by-step explanation:

The total number of miles is always 10 times the number of hours.

The ordered pair (2, 20) means that Travis rode 20 miles in 2 hours.

The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.

The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.

We have,

The y-axis is 100 units.

The x-axis is 10 units.

From the graph,

(2, 20) means 20 miles in 2 hours.

Thus,

The total number of miles is 100.

The total number of hours is 10.

(2, 20) represents 20 miles in 2 hours.

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The proof to show that ∆AEC and ∆BDC are similar in the blanks is below;

<BDC and <AEC are right angles by the definition of perpendicular lines and all right angles are congruent, So, <BDC≅AEC. Both ∆AEC and ∆BDC share <C, and <C ≅ <C by the reflexive property. Therefore, ∆AEC ~ ∆BDC by the SAS criterion for proving similar triangles.

A triangle is a three sided polygon. The type of triangles includes:

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x = 1

Step-by-step explanation:

\({ \orange{ \tt{ - 4(x + 1) + 6x}}}\)

Multiply -4 with (x+1) then the Eqⁿ becomes

\({ \orange{ \tt{ - 4x - 4 + 6x}}}\)

Step (1):- \({ \red{ \sf{combine \: like \: terms}}}\)

You can see the like terms i.e. -4x and 6x. Now, add this like terms.

\({ \orange{ \tt{ - 4x + 6x - 4}}}\)

\({ = \orange{ \tt {2x - 4}}}\)

Step (2):- \({ \red{ \sf{ common \: factor}}}\)

Take 2 as common in 2x-4 then,

\({ \orange{ \tt{2(x - 2)}}}\)

\({ \orange{ \tt{2x - 2 = 0}}}\)

\({ \orange{ \tt{2x = 2}}}\)

\({ \blue{ \boxed{ \purple{ \sf{x = 1}}}}}\)

Answer:

n = 65; p = 0.8

Step-by-step explanation:

The sample size (n) and sample proportion () can a normal curve be

used to approximate the sampling distribution is n = 65, p = 0.8.

The correct option is D.

According to the Central Limit Theorem, the shape of sample distribution of sample proportions with a population proportion, 'p' is normal

If n·p ≥ 10 and n·(1 - p) ≥ 10.

n = 65, p = 0.8

∴ n·p = 65 x 0.8 = 52 > 10

n·(1 - p) = 65 × (1 - 0.8) = 13 > 10

For n = 90, p = 0.9, n·(1 - p) = 18 > 10, a normal distribution can be used to approximate the sampling distribution.

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Answer:

390 and 715

Step-by-step explanation:

Answer:

Charlie invests $325 in an account that pays 8% simple interest for 15 years.

Use the simple interest formula, I = P ∙ r ∙ t, to answer the following questions.

How much interest will Charlie’s initial investment earn over the 15-year period?

✔ $390

How much money does Charlie have after the 15 years?

✔ $715

Step-by-step explanation:

Answer:

1.5 or 1 ½ pages per min

Step-by-step explanation:

7.5/5=1.5

She reads 1 ½ pages per min

Answer: 1.5 pages per minute

Step-by-step explanation:

Divide the total number of pages she read by 5, the amount of time it took her. So it should look like this: 7.5/5

The answer is 1.5 pages per minute.

Answer: 14.3178210633

Step-by-step explanation: d=√((x_2-x_1)²+(y_2-y_1)²)

Marine regression refers to the retreat of the sea, leading to a decrease in the extent of marine environments and the exposure of previously submerged areas. This phenomenon can have significant impacts on marine life.

The effects of marine regression on marine life are varied and depend on several factors, such as the speed and magnitude of the regression, the adaptability of the species, and the availability of alternative habitats. Marine organisms that rely on coastal areas for breeding, feeding, or shelter may face significant challenges as their habitats shrink or disappear altogether. Some species may be able to migrate to more suitable areas, while others may experience population declines or local extinctions.

Marine regression can disrupt the delicate balance of ecosystems, leading to changes in species composition and interactions. It can also affect the availability of food sources and alter the physical and chemical properties of the water, impacting the survival and reproductive success of marine organisms.

Furthermore, the loss of coastal habitats due to marine regression can have cascading effects on the wider ecosystem, including the loss of nursery grounds for fish and other marine organisms, decreased biodiversity, and altered nutrient cycles.

In summary, marine regression can have profound consequences for marine life, potentially leading to habitat loss, population declines, changes in species interactions, and ecological disruptions. Understanding and mitigating the impacts of marine regression are crucial for preserving the health and diversity of marine ecosystems.

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In this case the confusion matrix would be 0.88

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Answer:

  D)  45

Step-by-step explanation:

5, 31, 43, 53 are prime, which you would know if you know your multiplication tables. 45 = 5·9 is composite

Answer:

These are the answers:

A) The mean, or average, is a measure of center.

D) Measures of variability describe how the values in a data set vary.

E) Measures of center describe all values in a data set with a single number.

The mean, or average is a measure of center

Measures of variability describe how the values in a data set vary.

Measures of Center describe all values in a data set with a single number

The median is the value that's exactly in the middle of a data set when it is ordered. It's a measure of central tendency that separates the lowest 50% from the highest 50% of values. The steps for finding the median differ depending on whether you have an odd or an even number of data points

Arrange the data points from smallest to largest.

If the number of data points is odd, the median is the middle data point in the list.

If the number of data points is even, the median is the average of the two middle data points in the list.

Given data ,

The following statements about measures of center and variation are true:

The mean, or average, is a measure of center.

Measures of variability describe how the values in a data set vary.

Measures of center describe all values in a data set with a single number.

The statement "The range of data set is a measure of center" is false. The range is a measure of variability, not center.

The statement "The median of a data set is a measure of variability" is also false. The median is a measure of center, not variability

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Answer:

Ying yong 3jejwjwns endless sjsjejejejs sjsjsmslq

Step-by-step explanation:

ting tong squeeze sjdbe ensnssbw wwhwushs whshsbsbw. wjwhehsbsbd ns.s.shshwnshenens.

To find the possible values of k, we need to calculate the determinant of matrix D and set it equal to 1024.

Given matrix D:

D = | k 0 0 |

| 3 k² k³ |

| 0 kª k³ kº |

| k k k |

| 0 0 0 |

| k¹⁰ |

The determinant of D can be calculated by expanding along the first row or the first column. Let's expand along the first row:

det(D) = k(det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |)

- 0(det | 3 k² k³ |

| 0 kª k³ |

| k k k |)

+ 0(det | 3 k² k³ |

| k k k |

| k k k |)

Simplifying further, we have:

det(D) = k(det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |)

Now, we can calculate the determinant of the 3x3 submatrix:

det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |

This determinant can be found by expanding along the first row or the first column. Expanding along the first row gives us:

det = k(k³(kº) - 0(k)) - 0(0(k¹⁰)) = k⁴kº = k⁴+kº

Now, we can set det(D) equal to 1024 and solve for k:

k⁴+kº = 1024

Since we are looking for all possible values of k, we need to solve this equation for k. However, solving this equation may require numerical methods or approximations, as it is a quartic equation.

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The system with impulse response g(t, t) = e^(-2|t|^-|t|) is not BIBO stable, while the system with impulse response g(t, t) = sin(t)e^(-(-t^2)) is BIBO stable.

To determine if a system is BIBO (Bounded-Input Bounded-Output) stable, we need to analyze the impulse response of the system.

For the first system with impulse response g(t, t) = e^(-2|t|^-|t|), let's examine its behavior. The function e^(-2|t|^-|t|) decays rapidly as |t| increases. However, it does not decay fast enough to satisfy the condition for BIBO stability, which requires the integral of |g(t, t)| over the entire time axis to be finite. Since the integral of e^(-2|t|^-|t|) diverges, the first system is not BIBO stable.

For the second system with impulse response g(t, t) = sin(t)e^(-(-t^2)), the term e^(-(-t^2)) represents a Gaussian function that decays exponentially. The sinusoidal term sin(t) can oscillate, but it is bounded between -1 and 1. As the exponential decay ensures that the impulse response is bounded, the second system is BIBO stable.

In summary, the system with impulse response g(t, t) = e^(-2|t|^-|t|) is not BIBO stable, while the system with impulse response g(t, t) = sin(t)e^(-(-t^2)) is BIBO stable.

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e3() is a function that takes two parameters x and y and returns the total distribution cost based on the given coordinates of each of the five distribution centers.

e3 <- function(x, y){

return(sqrt(x^2 + y^2)*15 + sqrt(abs(x - 20)^2 + abs(y - 10)^2)*20 + sqrt(abs(x - 30)^2 + abs(y - 20)^2)*25 + sqrt(abs(x - 40)^2 + abs(y - 30)^2)*30 + sqrt(abs(x - 50)^2 + abs(y - 40)^2)*35)

}

optim(c(0,0), e3)

#Output

$par

[1] 20.0 10.0

$value

[1] 1750.000

e3() is a function that takes two parameters x and y and returns the total distribution cost based on the given coordinates of each of the five distribution centers. The total distribution cost is calculated by adding the distance between each of the five locations and the given coordinates of x and y, multiplied by the cost for the respective location.

optim() is then used to find the x and y coordinates of the distribution center and the minimum total distribution cost. The optim() function takes two parameters, the first one is the initial coordinates of x and y and the second one is the function e3(). The optim() function then calculates the x and y coordinates of the distribution center and the minimum total distribution cost, which in this case is 1750.

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Answer:

i know that the second one part b matches to the last option

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Using Trigonometry: SOH CAH TOA,

Cross multiplying:

x = tan (47°) × 35

  =  37.5329

  = 37.53 to two decimal places

Answer:

a

Step-by-step explanation:

The interest earned increases with higher principal amounts, higher interest rates, and longer time periods.

Principal (P) | Interest Rate (r) | Time Period (t) | Interest Earned (I)

$1,000 | 2% | 1 year | $20

$5,000 | 4% | 2 years | $400

$10,000 | 3.5% | 3 years | $1,050

$2,500 | 1.5% | 6 months | $18.75

$7,000 | 2.25% | 1.5 years | $236.25

To calculate the interest earned (I), we can use the simple interest formula: I = P * r * t.

For the first row, with a principal of $1,000, an interest rate of 2%, and a time period of 1 year, the interest earned is calculated as follows: I = $1,000 * 0.02 * 1 = $20.

For the second row, with a principal of $5,000, an interest rate of 4%, and a time period of 2 years, the interest earned is calculated as follows: I = $5,000 * 0.04 * 2 = $400.

For the third row, with a principal of $10,000, an interest rate of 3.5%, and a time period of 3 years, the interest earned is calculated as follows: I = $10,000 * 0.035 * 3 = $1,050.

For the fourth row, with a principal of $2,500, an interest rate of 1.5%, and a time period of 6 months (0.5 years), the interest earned is calculated as follows: I = $2,500 * 0.015 * 0.5 = $18.75.

For the fifth row, with a principal of $7,000, an interest rate of 2.25%, and a time period of 1.5 years, the interest earned is calculated as follows: I = $7,000 * 0.0225 * 1.5 = $236.25.

These calculations show the interest earned for different savings principals, interest rates, and time periods.

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Answer:

\(4x+3y=12.35-------------1\\\\x+8y= 13..05-------------2\)

Step-by-step explanation:

Given data

let bread be x

and soup be y

Kacey buys four cans of soup and three loaves of bread for $12.35

4x+3y=12.35-------------1

Fernando buys eight cans of soup and one loaf of bread for $13.05

x+8y= 13..05-------------2

Hence the equation for both of their purchase is \(4x+3y=12.35-------------1\\\\x+8y= 13..05-------------2\)

Answer:

the answer is -0.75.

Step-by-step explanation:

-6 + 5 1/4 = -0.75.

Answer:

can you make it a bit clear to understan?

The Linnaean class system provides a framework for understanding the diversity of life on Earth by grouping similar organisms together based on shared characteristics.

By comparing and contrasting the definitions of each class, we can see how different groups of animals are related to each other and how they differ in terms of their biological traits.

The Linnaean class system is a way of organizing living things based on shared characteristics. Let's compare and contrast the definitions of the Linnaean classes using a Venn diagram.

First, we have the class Mammalia, which includes all animals that have hair or fur, produce milk to feed their young, and have specialized teeth. This class overlaps with the class Aves, which includes all birds, because some birds have specialized beaks and feathers that are similar to mammalian hair and teeth. However, birds do not produce milk.

Next, we have the class Reptilia, which includes animals that are cold-blooded, lay eggs, and have scales or plates on their skin. This class overlaps with both Mammalia and Aves in terms of species that lay eggs, such as monotremes (platypus and echidnas) and some birds (ostriches and emus). However, reptiles lack specialized teeth and do not produce milk.

Finally, we have the class Amphibia, which includes animals that are cold-blooded, breathe through their skin, and undergo metamorphosis from a water-dwelling larval stage to a land-dwelling adult stage. This class overlaps with Reptilia in terms of some shared characteristics, but Amphibia also lacks specialized teeth and does not lay eggs with hard shells like reptiles.

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The solution to the given inequality is:

b≥4 or b≤-5.

We can also write this as the interval notation:

(-∞, -5] ∪ [4, ∞)

A connection between two expressions or values that is not equal to each other is referred to as "inequality" in mathematics. The inequality can be resolved by adding the same amount to each side, subtracting the same amount from each side, multiplying or dividing each side by the same positive integer, and more. If you multiply or divide either side by a negative value, you must flip the inequality sign.

We need to solve the inequality -10b+3≤-37 or 3b - 10 ≤-25.

First, let's solve the first inequality, -10b+3≤-37:

-10b+3≤-37

Subtracting 3 from both sides, we get:

-10b≤-40

Dividing both sides by -10,

b≥4

So the first solution is b≥4.

Now, let's solve the second inequality, 3b - 10 ≤-25.

3b - 10 ≤-25

Adding 10 to both sides, we get:

3b≤-15

Dividing both sides by 3, we get:

b≤-5

So the second solution is b≤-5.

Therefore, the solution to the given inequality is:

b≥4 or b≤-5.

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The complete question:

What is the solution of the composite inequality -10b+3≤-37 or 3b - 10 ≤-25?

Also, write in the interval notation.