please answer step by step.
A spaceship moves past Earth with a speed of . As it is passing, a person on Earth measures the spaceship's length to be 667 m. HINT (a) Determine the spaceship's proper length (nm). (b) Determine the

Answer: Two objects collide and stop. Their kinetic energy becomes sound energy when it is completely converted into another form of energy.

Sound energy is a form of energy that is generated due to the vibration of the particles. The sound energy is transferred through the air, liquids, and solids in the form of waves.

When two objects collide, their kinetic energy converts into sound energy. This sound energy is due to the collision of the objects. The kinetic energy is converted into sound energy because of the vibrations that occur during the collision.

When the sound energy is produced, it starts to propagate through the surrounding medium until it is absorbed by another medium. The energy stops being sound energy when it is completely converted into another form of energy. It can be absorbed by the medium in which it is traveling or can be transformed into other forms of energy such as heat or electrical energy.

Thus, the sound energy produced by the collision of two objects stops being sound energy when it is completely converted into another form of energy.

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Answer:

Dark colors absorb more radiated heat from the sunlight while lighter colors reflect it. That's why wearing a black shirt on a sunny day makes you feel so much hotter than when you're wearing a white shirt!

Answer:

black

Explanation:

Light energy can be converted into heat energy. A black object absorbs all wavelengths of light and converts them into heat, so the object gets warm

Answer:

fundamental units are those units that are independent to other units where as derived units are derived from fundamental units . there are altogether 7 fundamental units where as there are more than seven derived units..

Answer:

\( \boxed{ \sf{see \: below}}\)

Explanation:

\(\underline{ \sf{fundamental \: unit}}\)

\( \star\) This is the unit of a fundamental quantity.

\( \star\) This unit is independent of other units.

\( \star\) There are only seven fundamental units. They are metre , kilogram , second , Kelvin , ampere , candela and mole.

\( \underline{ \sf{derived \: unit}}\)

\( \star\) This is the unit of a derived Quantity.

\( \star\) This unit is obtained from fundamental units.

\( \star\) It is formed in many types using seven fundamental units. They are Newton , Pascal , Joule , Watt , Hertz , Ohm etc.

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Answer:

30 ms⁻¹

Explanation:

Given:

108kmh⁻¹

Find:

Change into ms⁻¹

Computation:

⇒ 1 km = 1,000 m

⇒ 1 hour = 60 x 60 = 3,600 sec

So,

⇒ 108[1,000/3,600]

30 ms⁻¹

The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.

To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:

Friction force = coefficient of static friction * Normal force

The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).

Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:

Friction force = Component of weight parallel to incline

By substituting the given values and solving for the angle, we find:

coefficient of static friction = tan(angle)

angle = arctan(coefficient of static friction)

angle = arctan(0.55) ≈ 33.4°

Therefore, the correct answer is Option A, 33.4°.

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Answer:

Gravity

Explanation:

The optimum ue for this mission is u_e_opt = u_e ln(m0/mu)/(1 - αP/m0).

The rocket equation in the case where the mass delivered by a rocket, mf​, is separated into useful payload mu​ and the power-producing system mass mp​ = αP, takes the form

m0mu​ = e−Δvue−2ηΔtαue2​(1−e−Δvue​),

Where Δt is the thrusting time, and η is the conversion efficiency.

This information is given in the question.

The optimum ue for this mission is the one that maximizes the payload mass mu for a given launch mass m0.

The rocket equation gives the relation between the initial mass of the rocket m0 and the final mass mf and the velocity change Δv it produces.

The rocket equation can be written as follows:

m0mf​ = e−Δvue​,

Where Δv = ue ln(m0/mf)

The mass of the rocket that is consumed in a given time interval Δt is given by mp = αP Δt

The mass of the useful payload is given by

mu = mf - mp

Substituting for mf and mp, we get

mu = (1 - αP/m0)mf

Substituting the above equation in the rocket equation, we get

m0(1 - αP/m0)mf = e^(-Δv/ue)

mf = m0 e^(-Δv/ue)/(1 - αP/m0)

Substituting for mf, we get

mu = (1 - αP/m0) m0 e^(-Δv/ue)/(1 - αP/m0)

mu = m0 e^(-Δv/ue)

Multiplying both sides of the equation by m0/mu, we get

m0/mu = m0 e^(Δv/ue)

Taking the natural logarithm of both sides of the equation, we get ln(m0/mu) = Δv/ue

ue = Δv/ln(m0/mu)

Substituting the value of Δv from the rocket equation, we get

ue = u_e_opt

    = u_e ln(m0/mu)/(1 - αP/m0)

Therefore, the optimum ue for this mission is u_e_opt = u_e ln(m0/mu)/(1 - αP/m0).

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Answer:

D) None of the Above

I hope this is correct; Let me know if it is in the comments.

The wavelength of an ultrasonic wave with a frequency of 1.0×10^5 Hz, given the speed of sound in air as 340 m/s, is approximately 3.4 mm.

The wavelength of a wave can be calculated using the formula λ = v/f, where λ represents the wavelength, v is the velocity or speed of the wave, and f is the frequency of the wave.

In this case, the frequency is given as 1.0×10^5 Hz, and the speed of sound in air is 340 m/s. By substituting these values into the formula, we can determine the wavelength.

λ = 340 m/s / (1.0×10^5 Hz) = 3.4×10^-3 m = 3.4 mm

Therefore, the wavelength of the ultrasonic wave emitted by bats, with a frequency of 1.0×10^5 Hz, is approximately 3.4 mm.

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(a) The magnitude of the average force acting on the car to bring it to rest is 120,000 N.

(b) The horizontal (vx) and vertical (vy) components of this velocity is 9.66 m/s and 2.59 m/s respectively.

The magnitude of the force acting on the car is calculated as follows;

F = mv / t

where;

F = ( 1200 kg x 10 m/s ) / ( 0.1 s )

F = 120,000 N

The horizontal and vertical component of the velocity of the car is calculated as follows;

Vx = V cosθ

Vy = V sinθ

where;

Vx = 10 m/s  x  cos (15) = 9.66 m/s

Vy = 10 m/s x sin (15) = 2.59 m/s

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The name given to it is "terminal velocity".

In reality, it isn't a velocity, and it doesn't happen in free-fall.

Go figure.

No, it is not possible to determine whether the objects are positively or negatively charged based on the observation that they electrostatically repel each other.

This is because the electrostatic force between two charged objects depends not only on their charges but also on the distance between them.

The force of electrostatic repulsion between two like charges (positive-positive or negative-negative) is always repulsive, while the force of electrostatic attraction between two opposite charges (positive-negative) is always attractive.

However, the magnitude and direction of the force depend on the magnitudes and signs of the charges as well as the distance between them.

Therefore, it is possible for two objects with either positive or negative charges to exhibit electrostatic repulsion, depending on the relative magnitudes and signs of their charges and the distance between them.

Additional information, such as the exact distance between the objects or their charges, is needed to determine their charge signs.

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The decay process λ⁰ → p + π⁰ violates the conservation laws of baryon number and strangeness.
Here's a step-by-step explanation:
Baryon number conservation: In this decay process, a lambda particle (λ⁰) decays into a proton (p) and a neutral pion (π⁰). The lambda particle is a baryon, which means it has a baryon number of +1. The proton is also a baryon with a baryon number of +1. The neutral pion, on the other hand, is a meson and has a baryon number of 0. Therefore, the sum of the baryon numbers before and after the decay is not conserved.
Strangeness conservation: The lambda particle has a strangeness of -1, while the proton has a strangeness of 0. The neutral pion also has a strangeness of 0. Since the strangeness is not conserved, this decay violates the conservation law of strangeness.
The decay process λ⁰ → p + π⁰ violates the conservation laws of baryon number and strangeness.
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Answer:

the answer is C

Explanation:

I know because mercury is the first planet closest to the sun

Answer:

f=1.92 cm

If ans is correct reply for explanation.

The typical focal length formula looks as follows: 1/Focal length = 1/Image distance + 1/Object distance , where: Image distance and Object distance are given in mm.

1/f = 1/u + 1/v

1/f = 1/133 + 1/22.5

    = 0.007 + 0.044

    = 0.0514 mm

"The focal length of an optical system is a measure of how strongly the system converges or diverges light; it is the inverse of the system's optical power. A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light."

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the second and third one

If the electronic configuration of an atom is 1s2 2s2 2p2 then it has 6 electrons.

This electronic configuration corresponds to carbon, whose atomic number is 6.

The electronic configuration is a form of organization by layers that the electrons have.

Its importance is based on the ability to determine through it the total properties of chemical combination of atoms, which is equivalent to their location on the periodic table of elements.

Furthermore, the electronic configuration of an element defines its binding energy and thus its state at room temperature.

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Answer:

true

Explanation:

half life is the time an isotope takes to decay

The tension forces in cables AB and AC for lifting a 500 kg container are found as functions of θ, and the shortest lengths of cables satisfying a maximum tension of 5 kN are 4408.5 m and 1886.5 m.

Assuming the container is being lifted vertically, we can draw a free-body diagram of the container and apply Newton's second law to find the tension forces in cables AB and AC.

Let T_AB and T_AC be the tensions in cables AB and AC respectively, and let W be the weight of the container. Then we have

T_AC * cos(θ) = T_AB * cos(θ) = W

T_AC * sin(θ) = T_AB * sin(θ)

Dividing the first equation by the second, we get

tan(θ) = T_AC / T_AB

Solving for T_AC and T_AB in terms of θ, we get

T_AC = W / cos(θ)

T_AB = W / (cos(θ) * tan(θ))

Substituting W = 500 kg * 9.81 m/s² = 4905 N, we get:

T_AC = 4905 / cos(θ)

T_AB = 4905 / (cos(θ) * tan(θ))

To find the shortest lengths of cables AB and AC that can be used for the lift, we need to make sure that the tension in each cable does not exceed 5 kN. Since the tensions are functions of θ, we can find the maximum value of θ that satisfies this condition.

For cable AB

T_AB = 4905 / (cos(θ) * tan(θ)) <= 5 kN

cos(θ) * tan(θ) >= 4905 / (5 kN) = 0.981

Using a calculator or a table of trigonometric functions, we can find that the minimum value of cos(θ) * tan(θ) that satisfies this inequality is approximately 0.739. Therefore, we have

cos(θ) * tan(θ) >= 0.739

Solving for θ, we get

θ <= atan(0.739 / cos(θ)) = 51.4°

Similarly, for cable AC

T_AC = 4905 / cos(θ) <= 5 kN

cos(θ) >= 4905 / (5 kN) = 0.981

Solving for θ, we get

θ >= acos(0.981) = 11.2°

Therefore, the shortest lengths of cables AB and AC that can be used for the lift are given by

L_AB = 500 / sin(θ) <= 4408.5 m

L_AC = 500 / sin(θ) >= 1886.5 m

where we have used the maximum and minimum values of θ obtained above. These lengths assume that the cables are perfectly vertical, and in practice there may be some additional length required to account for the angle at which the cables are attached to the container.

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Answer:

convection thermal energy causes ocean currents?

When a person with normal vision looks at an object 10m away, the image is formed clearly on the retina. The reason is that the eye has an optical power of 60 diopters. Therefore, a person with normal vision can see an object 10 meters away clearly.

Optical power refers to the ability of a lens to bend light. It is measured in diopters (D). The greater the diopter, the greater the lens's ability to bend light. The human eye's lens and cornea both contribute to its optical power.The cornea contributes around 43 diopters, while the lens contributes the remaining 17 diopters. The human eye's total optical power is usually about 60 diopters.A person with normal vision has an optical power of 60 diopters. When they look at an object 10m away, the image is formed clearly on the retina. The reason is that the eye has an optical power of 60 diopters.

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The temperature of the atmosphere can be determined using the root mean square (rms) speed of oxygen molecules and the molar mass of oxygen. The formula to calculate temperature from rms speed is:

T = (m * v^2) / (3 * R)

Where T is the temperature in Kelvin, m is the molar mass of the gas (in this case, oxygen), v is the rms speed, and R is the ideal gas constant.

First, we need to convert the rms speed from m/s to cm/s. There are 100 cm in 1 meter, so the rms speed of oxygen molecules is 535 * 100 = 53,500 cm/s.

The molar mass of oxygen (O₂) is 32 g/mol.

The ideal gas constant (R) is 8.314 J/(mol·K).

Substituting the values into the formula, we get:

T = (32 * 53500^2) / (3 * 8.314)

Calculating this expression, we find that the temperature of the atmosphere at the given location is approximately 6661.64 K.

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The temperature of the atmosphere at this location is approximately 291 Kelvin.

Explanation :

The temperature of the Earth's atmosphere at a certain location can be determined using the root mean square (rms) speed of the oxygen molecules and the ideal gas law.

First, we need to convert the rms speed of oxygen molecules from m/s to m^2/s^2 by squaring it: (535 m/s)^2 = 286,225 m^2/s^2.

Next, we can use the formula for rms speed: rms speed = √(3RT/M), where R is the ideal gas constant, T is the temperature in Kelvin, and M is the molar mass of oxygen.

Since oxygen makes up 21% of the atmosphere, we can assume that the molar mass of oxygen (M) is 0.21 times the molar mass of air, which is approximately 29 g/mol.

We can rearrange the formula to solve for temperature (T): T = (rms speed)^2 * M / (3R).

Plugging in the values, we have T = (286,225 m^2/s^2) * (0.21 * 29 g/mol) / (3 * 8.314 J/(mol*K)).

Converting the molar mass of oxygen to kg/mol and simplifying the equation, we find T ≈ 291 K.

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(1) Mean of X is 15 minutes and Variance of X is 75 minutes^2.

(2) The probability distribution function of X is f(x) = (0.008 * x^2 * e^(-0.2x)) / 2

(1) To find the mean and variance of X, we first need to determine the distribution of the waiting time until the third arrival. Since arrival times follow a Poisson process with mean rate λ = 0.2 arrivals per minute, the waiting times follow an exponential distribution. The waiting time until the k-th arrival (in this case, k = 3) follows a Gamma distribution with parameters k and λ.

Mean of X: E(X) = k / λ = 3 / 0.2 = 15 minutes
Variance of X: Var(X) = k / λ^2 = 3 / (0.2^2) = 75 minutes^2

(2) To find the probability distribution function (PDF) of X, we'll use the formula for the Gamma distribution:

f(x) = (λ^k * x^(k-1) * e^(-λx)) / Γ(k)

For our case, k = 3 and λ = 0.2:

f(x) = (0.2^3 * x^(3-1) * e^(-0.2x)) / Γ(3)

f(x) = (0.008 * x^2 * e^(-0.2x)) / 2

This is the probability distribution function of X, the waiting time until the third arrival.

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Answer:

A. When one bulb burns out, all the other lights stay lit.

Answer: C.. all bulbs go out.

Explanation:

Answer:Im doing that same quiz rn and i just put A

Explanation:

this is because EM energy is produced when electrically charged participles vibrate generating an electric filed and a magnetic field which sends out an EM wave.

i hope this helped

At the point of incidence, the incident and reflected rays form the following two angles:

The law of reflection states that the angle of incidence and angle of reflection are identical. The normal is in the same plane as both the angle of incidence and the angle of reflection, which are always equal.

Light is renowned for its highly predictable behavior. The behavior of a beam of light as it reflects would follow a determinable law known as the law of reflection if it could be seen approaching and reflecting off of a flat mirror. The law of reflection is shown in the diagram below.

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