Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!

Answer: two congruent segments.

Step-by-step explanation:

idlk im not smart

OPTION D

m<6 and m<3 are congruent because they are alternate interior angles.

Answer:

if it's parallel isn't the slope the same?

Answer: The violet line in the graph attached is your answer.

Step-by-step explanation:

Hey buddy I am here to help!

yellow marbles = 4

blue marbles = 2

red marbles = 3

total marbles = 9

1 random marbles taken off probability left = 8/9

1 random marble taken off probability = 1/9

marble if replaced = + 1

if one marble if replaced then = 8/9 + 1/9 = 9/9 that means total marbles r 9

yellow marbles drawn off = 2

so... 4 - 2 = 2 marbles left

red marbles taken off = 1

so... 3 -1 = 2 marbles left

probability/answer  = 3/9 = 1/3

Hope it helps!

Plz mark my answer brainliest

Answer:

hsvxnosh jwydtko isgrekon dtdorny

Answer:

35/37

Step-by-step explanation:

In this question, we are to calculate the ratio that represents the cosine of angle O

Firstly, please check attachment for diagram of the triangle.

Mathematically, the trigonometric term Cos means the ratio of the length of the adjacent to that of the hypotenuse

The hypotenuse is the longest length which is 37 which represents the length ON

The side adjacent to angle O is the side OP which is 35

Thus, the ratio representing the cosine of angle O is 35/37

Answer:

8/15

Step-by-step explanation:

this is another answer, if you get these numbers

Therefore, the correct inequality to find the domain is simply x - 3 < 0, which simplifies to x < 3.

To find the domain of a function, we need to determine all the values of the independent variable (usually represented by x) that the function is defined for. In this case, the function is defined as f(x) = x - 3, which means we can plug in any value of x into the expression x - 3 to get a corresponding value of f(x).

However, there are some values of x that would cause the expression x - 3 to be undefined. For example, if we were trying to find f(x) when x = 2, we would get f(2) = 2 - 3 = -1, which is a valid output. But if we were trying to find f(x) when x = 3, we would get f(3) = 3 - 3 = 0/0, which is undefined.

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Answer:

11

Step-by-step explanation:

5 x 2 = 10

10 + 6 = 16

16 - 5 = 11

there u go!

Answer:

is there are abcd?

Step-by-step explanation:

The tasks offered to require you to determine the series solution to a differential equation. For each issue, we must establish if the differential equation has a regular singular point for a given value of x, as well as the indicial equation, recurrence relation, and indicial equation roots. Consequently, if the bigger and smaller roots exist, we can obtain the series solution to the differential equation.

1. a) Regular singular point at x0=0

b) Indicial equation: r(r-1)+r=0, which simplifies to r^2=0. The roots are r1=r2=0.

c) y(x) = c0 + c1*x, where c0 and c1 are constants of integration.

d) N/A as the roots are equal.

2. a) Regular singular point at x0=0

b) Indicial equation: r(r-1)+r/9=0, which simplifies to r(r-1+1/9)=0. The roots are r1=0 and r2=1-1/3=2/3.

Recurrence relation: an=-(2n-1)/n(3n+1)an-1

c) y(x) = c0 + c1x^(2/3) - 1/21x^(8/3) + 2/495x^(14/3) - 26/25515x^(20/3) + ...

d) y(x) = c2x^0 + c3x^(-1/3) - 5/63x^(5/3) + 11/2079x^(11/3) - 301/54235*x^(17/3) + ...

3. a) Regular singular point at x0=0

b) Indicial equation: r(r-1)=0. The roots are r1=0 and r2=1.

Recurrence relation: an=-(1/2)an-1

c) y(x) = c0 + c1*x

d) y(x) = c2 + c3/x

4. a) Regular singular point at x0=0

b) Indicial equation: r(r-1)-1=0, which simplifies to r^2-r-1=0. The roots are r1=(1+sqrt(5))/2 and r2=(1-sqrt(5))/2.

Recurrence relation: an=-[2(n-1)+1-1]/(n(n+1)-1)(r1(n-1)+r2n)an-1

c) y(x) = c0 + c1exp(r1x) + c2exp(r2x)

d) y(x) = c3exp(r2x)

5. a) Regular singular point at x0=0

b) Indicial equation: r(r-1)+r+2=0, which simplifies to r^2=1. The roots are r1=1 and r2=-1.

Recurrence relation: for r1: an=-1/[(n+2)(n+1)]an-1, for r2: an=1/(n(n-1)+2n-6)an-1

c) y(x) = c0 + c1x - x^2/3 + 4/45x^4 - 2/945*x^6 + ...

d) y(x) = c2 + c3/x^2

6. a) Regular singular point at x0=0

b) Indicial equation: r(r-1)+(1-x)r=0, which simplifies to r^2-xr=0. The roots are r1=0 and r2=x.

Recurrence relation: an=-an-1/(n(1-x+n))

c) y(x) = c

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Answer:

12 y − 3

Step-by-step explanation:

4(3y+2)-11

Expand 4(3y+2): 12y+8

12y+8-11

=12y-3

Ploidy level shifts between a pair of species (one diploid, one tetraploid) fit the "allopolyploid hybridization model" very well because it explains the origin of the diploid and tetraploid forms.

The allopolyploid hybridization model proposes that the tetraploid species originated from the hybridization between two different diploid species.

Specifically, the hybridization event resulted in a doubling of the chromosome number, creating a tetraploid individual with four copies of each chromosome.

This event is known as allopolyploidization.

The diploid species that served as the parents of the tetraploid species are not identical to either of the two tetraploid species.

Rather, they are thought to be extinct or still-existing diploid species that hybridized to produce the tetraploid offspring.

The allopolyploid hybridization model explains why the diploid and tetraploid species often have similar morphology and DNA sequences. The diploid parent of the tetraploid species contributes half of the genome, while the other half comes from the other diploid parent.

This hybridization event leads to a mix of the two parent genomes, resulting in a unique genome that can contribute to the formation of a new species.

Overall, the allopolyploid hybridization model provides a plausible explanation for the origin of tetraploid species, and it is supported by extensive genetic and morphological evidence.

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Answer:

140 oranges

Step-by-step explanation:

From the Question, we know that the pyramid has 7 layers

The number of oranges in the first layer is = 1

Hence, the number of oranges in a pile is calculated as:

1² + 2² + 3² + 4² + 5² + 6² + 7²

= 1 + 4 + 9 + 16 + 25 + 36 + 49

= 140 oranges

Answer:

140

Step-by-step explanation::)

The difference of the given expressions is 5.

The given expressions are -6x+3 and -6x+8.

To subtract an algebraic expression from another, we should change the signs (from '+' to '-' or from '-' to '+') of all the terms of the expression which is to be subtracted and then the two expressions are added.

Now, subtract -6x+3 from -6x+8

-6x+8 - (-6x+3)

= -6x+8+6x-3

= 5

Therefore, the difference of the given expressions is 5.

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Answer:

6 boys

Step-by-step explanation:

12% of 50 is 6

Answer:

6 boys

Step-by-step explanation:

Given:

50 Student

12% are boys

Question:

How many are boys?

Solve:

Note that: 12% = .12

Thus, 50 x .12=6

50 -6 = 44

Hence, 44 are girls and 6 are boys

Answer = 6 boys

[RevyBreeze]

The amount of milk that Michael has left is: 49/40 liters or 1⁹/₄₀ liters

Amount of milk bought by Michael = 2 liters

If he drank 2/5 liters of it and gave 3/8 liters to his brother, it mean the total amount of milk from the original quantity taken is:

2/5 + 3/8 = 31/40

Thus, the amount of milk he will have left after all is:

2 - 31/40

= 49/40 = 1⁹/₄₀ liters

Therefore the left milk is 49/40 liters.

So, Michael is left with 49/40 liters of milk.

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Complete question is:

Michael bought 2 liters of milk. He drank 2/5 liters of it and gave 3/8 liters to his brother. How much milk did Michael have left?

Answer:

1=v

Step-by-step explanation:

40-48v=-7-v

+48v     +48v

_____________

40=-7+47v

+7  +7

_____________

47=47v

÷47     ÷47

____________

1=v

Hope this helps :3

Answer:

1 resdantial area 2  12 to 15

Step-by-step explanation:

(a) The domain closed and bounded.

(b) The domain bounded.

(c) The domain closed.

(d) The domain bounded.

(e) The domain closed and bounded.

(f) The domain closed and bounded.

In this question, we have been given some domains.

We need to check which domains are closed and which are bounded.

A domain of function is said to be closed if the region R contains all boundary points.

A bounded domain is nothing but a domain which is a bounded set.

(a) {(x,y)∈R2:x^2+y^2≤1}

The domain of x^2+y^2≤1 contains set of all points (x, y) ∈R2

so, the domain closed and bounded.

(b) {(x,y)∈R2:x2+y2<1}

The domain of x^2+y^2 < 1 contains set of all points (x, y) ∈R2

so, the domain is bounded.

(c) {(x,y)∈R2: x ≥ 0}

The domain of x ≥ 0 is R2 - {x < 0}

So, the domain is closed.

(d) {(x, y) ∈ R2 : x > 0,y > 0}

The domain is R2 - {(x, y) ≥ 0}

So, the domain is bounded.

(e) {(x, y) ∈ R2 : 1 ≤ x ≤ 4, 5 ≤ y ≤ 10}

The domain is closed and bounded.

(f) {(x,y)∈R2:x>0,x^2+y^2≤10}

The domain is closed and bounded.

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Answer:

Well, if we consider \(r\) as y and \(q\) as x.

Step-by-step explanation:

So, typically, a linear function is either represented using function notation

\(f(x)=mx+b\)

Or in slope-intercept form

\(y=mx+b\)

This question is oddly using the variables r and q in place of y and x. If we replace them to be y and x, it will be a linear equation (because the slope is constantly changing).

But, if you aren't allowed to replace r and q to be y and x, then it isn't a linear function.

Differentiate both sides of

\(y = \dfrac{x\sqrt{a^2-x^2}}2 + \dfrac{a^2}2\sin^{-1}\left(\dfrac xa\right)\)

with respect to y ; by the product rule,

\(1 = \dfrac12\sqrt{a^2-x^2}\dfrac{\mathrm dx}{\mathrm dy} + \dfrac x2 \dfrac{\mathrm d}{\mathrm dy}\left[\sqrt{a^2-x^2}\right] + \dfrac{a^2}2\dfrac{\mathrm d}{\mathrm dy}\left[\sin^{-1}\left(\dfrac xa\right)\right]\)

Use the chain rule for the remaining derivatives.

\(\dfrac{\mathrm d}{\mathrm dy}\left[\sqrt{a^2-x^2}\right] = \dfrac1{2\sqrt{a^2-x^2}}\dfrac{\mathrm d}{\mathrm dy}\left[a^2-x^2\right] \\\\ = \dfrac{-2x}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = -\dfrac x{\sqrt{a^2-x^2}} \dfrac{\mathrm dx}{\mathrm dy}\)

Recall that

\(\dfrac{\mathrm d}{\mathrm dx}\left[\sin^{-1}(x)\right] = \dfrac1{\sqrt{1-x^2}}\)

Then

\(\dfrac{\mathrm d}{\mathrm dy}\left[\sin^{-1}\left(\dfrac xa\right)\right] = \dfrac1{\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm d}{\mathrm dy}\left[\dfrac xa\right] \\\\ = \dfrac1{a\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = \dfrac1{\sqrt{a^2}\sqrt{1-\left(\frac xa\right)^2}}\dfrac{\mathrm dx}{\mathrm dy} \\\\ = \dfrac1{\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

Putting everything together, we have

\(1 = \dfrac{\sqrt{a^2-x^2}}2\dfrac{\mathrm dx}{\mathrm dy} - \dfrac{x^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy} + \dfrac{a^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \left(\dfrac{\sqrt{a^2-x^2}}2+\dfrac{a^2-x^2}{2\sqrt{a^2-x^2}}\right)\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \dfrac1{2\sqrt{a^2-x^2}}\bigg((a^2-x^2) + (a^2-x^2)\bigg)\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \dfrac{2a^2-2x^2}{2\sqrt{a^2-x^2}}\dfrac{\mathrm dx}{\mathrm dy}\)

\(1 = \sqrt{a^2-x^2}\dfrac{\mathrm dx}{\mathrm dy}\)

\(\boxed{\dfrac{\mathrm dx}{\mathrm dy} = \dfrac1{\sqrt{a^2-x^2}}}\)

The correct formula that defines an arithmetic sequence is option d) tn = 5n + 14.

An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms remains constant. In other words, each term can be obtained by adding a fixed value (the common difference) to the previous term.

In option a) tn = 5 + 14, the term does not depend on the value of n and does not exhibit a constant difference between terms. Therefore, it does not represent an arithmetic sequence.

Option b) tn = 5n² + 14 represents a quadratic sequence, where the difference between consecutive terms increases with each term. It does not represent an arithmetic sequence.

Option c) tn = 5n(n+14) represents a sequence with a varying difference, as it depends on the value of n. It does not represent an arithmetic sequence.

Option d) tn = 5n + 14 represents an arithmetic sequence, where each term is obtained by adding a constant value of 5 to the previous term. The common difference between consecutive terms is 5, making it the correct formula for an arithmetic sequence.

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- Span{v1, v2, v3, 0} is equal to the span of {v1, v2, v3}.
- Span{v1, v1-v2, v3} is equal to the span of {v1, v2, v3}.
- Span{v1, v2} is NOT equal to the span of {v1, v2, v3}.

Let's analyze each of the sets of vectors to determine if they are equal to the span of {v1, v2, v3}:
1. Span{v1, v2, v3, 0}:
This set is equal to the span of {v1, v2, v3} because adding the zero vector (0) does not affect the linear independence or the span of the other vectors.

A span is the set of all possible linear combinations of the vectors, and since the zero vector does not change the linear combinations, the span remains the same.
2. Span{v1, v1-v2, v3}:
This set is also equal to the span of {v1, v2, v3}.

The reason is that the vector (v1-v2) can be written as a linear combination of v1 and v2: (v1-v2) = 1*v1 + (-1)*v2.

Since all vectors in this set can be expressed as linear combinations of {v1, v2, v3}, the span remains the same.
3. Span{v1, v2}:
This set is NOT equal to the span of {v1, v2, v3} because it is missing the vector v3.

Since v1, v2, and v3 are linearly independent, removing one of them (v3 in this case) means that the set cannot span the same space as {v1, v2, v3}.

It has a lower dimension, and therefore, the span is different.

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The probability of the weather forecast being correct on the randomly chosen day is 0.6, and the probability of it not being correct is 0.4.

To find the probability of the weather forecast being correct or not correct on a randomly chosen day, we need to use the information given:
Total number of days: 300
Number of days the weather forecast was correct: 180
First, let's find the probability that the weather forecast was correct on the randomly chosen day:
Probability of correct forecast = (Number of correct forecasts) / (Total number of days)
Probability of correct forecast = 180 / 300
Probability of correct forecast = 0.6
Now, let's find the probability that the weather forecast was not correct on the randomly chosen day:
Probability of incorrect forecast = 1 - Probability of correct forecast
Probability of incorrect forecast = 1 - 0.6
Probability of incorrect forecast = 0.4

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Answer:

111 / 190

Step-by-step explanation:

Let us first compute the probability of picking 2 of each sweet. Take liquorice as the first example. There are 12 / 20 liquorice now, but after picking 1 there will be 11 / 19 left. Thus the probability of getting two liquorice is demonstrated below;

\(12 / 20 * 11 / 19 = \frac{33}{95},\\Probability of Drawing 2 Liquorice = \frac{33}{95}\)

Apply this same concept to each of the other sweets;

\(5 / 20 * 4 / 19 = \frac{1}{19},\\Probability of Drawing 2 Mint Sweets = 1 / 19\\\\3 / 20 * 2 / 19 = \frac{3}{190},\\Probability of Drawing 2 Humbugs = 3 / 190\)

Now add these probabilities together to work out the probability of drawing 2 of the same sweets, and subtract this from 1 to get the probability of not drawing 2 of the same sweets;

\(33 / 95 + 1 / 19 + 3 / 190 = \frac{79}{190},\\1 - \frac{79}{190} = \frac{111}{190}\\\\\)

The probability that the two sweets will not be the same type of sweet =

111 / 190

The union of two sets is to avoid counting the same elements twice.

The mathematical logic subfield of set theory investigates sets, which can be loosely defined as collections of objects. Although any object can be combined into a set, set theory, as a mathematical discipline, focuses primarily on those that are relevant to mathematics as a whole.

Given union of set

(A ∪ B),

The set of all objects that are members of either A or B, or both, is the union of the sets A ∪ B.

let us take example,

A = { 1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

(A ∪ B) = { 1, 2, 3, 4} ∪  {3, 4, 5, 6, 7}

we can simply write all of A and B's elements in a single set to avoid duplicates to find A U B.

(A ∪ B) = {1, 2, 3, 4, 5, 6, 7}

Hence the  union of two sets is a set that contains all the elements of both set and avoid duplicates.

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Using the graph, we can find the following:

a) The gymnast stays 4 seconds in the air.

b) The maximum height that the gymnast reaches is 10 ft.

c) After 2 seconds the gymnast starts to descend.

d) The quadratic function that models this situation is:

y = mx + c

Quantitative data can be represented and analysed graphically. In a graph, variables representing data are drawn over a coordinate plane. Analysing the magnitude of one variable's change in light of other variables' changes became simple.

Here in the question,

a. We can see from the graph that the curve above x-axis starts from the origin (0,0) and ends at (4,0) on the x-axis.

So, the gymnast stays 4 seconds in the air.

b. As we can see from the graph that it rises and then at point (2,10) it starts to descend.

So, the maximum height that the gymnast reaches is 10 ft.

c. As we can see from the graph that it rises and then at point (2,10) it starts to descend.

So, after 2 seconds the gymnast starts to descend.

d. The quadratic function that models this situation is:

y = mx + c

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Answer:

the answer is 167/3

Step-by-step explanation: