When Photons of wavelength 0.024 a are incident on free electrons, the wavelength of a photon which is scattered 30° is 0.0576 x \(10^{-11}\) and for the one scattering at 120° is 0.38 x \(10^{-11}\) A.
How can the Compton effect be used to determine the energy of scattered photons?The incident photon’s energy is equal to the scattered photon’s energy minus the total of the recoil electron’s kinetic energy and binding energy.
Compton scattering causes the loss of an electron and ionization of the absorbing atom, just like photoelectric absorption does.
What is the scattered photon’s wavelength?After the scattering event and before, the photon’s wavelength varies by ∆λ = (h/mc) (1-cosφ). Here, c is the speed of light, m is the rest mass of the electron, and is the angle at which the photon is scattered. H is the Planck constant.
Given photon wavelength λ = 0.024A
φ = 30°
From the Compton effect we know that
∆λ = λ1 - λ = h/mc (1-cosφ)
λ1 = \(\frac{6.62*10^{-34}}{9.1}\) x \(10^{-3}\) x 3 x \(10^{8}\) (1- cos30°) + 0.024A
= 0.0576 x \(10^{-11}\) A
And then calculating the same for
φ = 120°
we get,
λ1 = 0.38 x \(10^{-11}\)A
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Complete Question
Photons of wavelength 0.024A are incident on free electrons.
(a) Find the wavelength of a photon which is scattered 30° from the incident direction and the kinetic energy imparted to the recoil electron
(b) Do the same if the scattering angle is 120°.
A body of mass 3.0Kg is acted upon by a force of 24N, if the frictional force on the body is 13N.Calculate the acceleration of the body
Answer:
Fnet=ma
24-13=3a
11/3=a
a=3.6m/s2
The acceleration of the body of mass 3 kg is 3.67 meters per second squared.
The force can be computed from Newton's second law. The acceleration is computed from velocity and time. The acceleration is a vector quantity that describes both magnitude and direction. The standard unit is a meter per second square.
From Newton's second law:
Net force = Mass × Acceleration
Net force = Applied force - Frictional force
Net force = 24 N - 13 N
Net force = 11 N
The acceleration is:
Acceleration = Net force / Mass
Acceleration = 11 N / 3.0 kg
Acceleration = 3.67 m/s²
Hence, the acceleration of the body of mass 3 kg is 3.67 meters per second squared.
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Can someone please help
99.16 Newtons is the new force of attraction between the particles.
What causes an atoms to attract one another?The forces that hold atoms together to create molecules and solids are referred to as chemical bonds. The attraction between the electrons of one atom and the nuclei of another atom as a result of this electric force is what is known as a chemical bond.
\(F = (kq1q2)/r^2\)
\(9,916 = (kq1q2)/r^2\)
\(F = (k*(q1/5)*(q2/5))/(2r)^2\)
\(F = (1/100)((kq1*q2)/(r^2))\)
So, the new force of attraction is:
\(F = (1/100)*9,916 = 99.16\)Newtons (rounded to 4 decimal places)
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state the term used to describe the turning force exerted by the man pushing down on a lever to lift one end of a heavy log
The term used to describe the turning force exerted when pushing an object is effort.
What is effort?The is the input force or force applied at one point of a lever in order to overcome a load.
The relationship between effort, load and mechanical advantage of a lever is given as;
M.A = L/E
where;
M.A is mechanical advantageL is the loadE is the applied force or effortThus, the term used to describe the turning force exerted when pushing an object is effort.
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Where is the south pole of the bar magnet, based on the magnetic field lines
shown?
A. On the right end
B. On the bottom edge
C. On the left end
D. On the top edge
SUBMIT
it would be on the right end I believe. Forgive me if I am incorrect.
|5x-8|+5=32 how would i set this problem up to solve
You have the following expression:
\(\lvert5x-8\rvert+5=32\)subtract 5 both sides of the equation:
\(\begin{gathered} \lvert5x-8\rvert=32-5 \\ \lvert5x-8\rvert=27 \end{gathered}\)Take into account that the absolute value of any number is equal to the same number but positive.
Then, you have:
\(5x-8=-27\)and
\(5x-8=27\)Then, solve the previous equations:
5x - 8 = -27 add 8 both sides
5x = -27 + 8
5x = -19 divide by 5
x = -19/5
5x - 8 = 27 add 8 both sides
5x = 27 + 8
5x = 32 divide by 5
x = 32/5
Then, the solutions of the given equations are:
x = -19/5
x = 32/5
The speed an
object travels in a
specific
DIRECTION
Is this speed velocity or acceleration
Which best represents the appearance of the moon on July 25, 2011
Answer:
Its the third quarter or waning quarter
Hope this helps :3
why do chemical bonds form
Answer:
A chemical bond is a force of attraction between atoms or ions. Bonds form when atoms share or transfer valence electrons. Atoms form chemical bonds to achieve a full outer energy level, which is the most stable arrangement of electrons
Explanation:
Answer:
A chemical bond is a force of attraction between atoms or ions. Bonds form when atoms share or transfer valence electrons. Atoms form chemical bonds to achieve a full outer energy level, which is the most stable arrangement of electrons.
Question 14 (3 points)
What part of volcano carries magma from the magma chamber to the vent? (3 points)
Vent
Magma Chamber
Lava Flow
Conduit
d
you may check it online
what is the velocity of the 0.220-kg ball after the collision, in m/s? use a positive number for east and a negative number for west.
To answer this question, we need more information about the collision. In particular, we need to know what the ball collided with and what the initial velocity of the ball was. Without this information, it is impossible to calculate the velocity of the ball after the collision.
Assuming we have all the necessary information, we can use the principles of conservation of momentum to calculate the velocity of the ball after the collision. According to this principle, the total momentum of the system (ball + object it collided with) before the collision is equal to the total momentum of the system after the collision.
If we assume that the collision is perfectly elastic, meaning that no energy is lost in the collision, we can also use the principle of conservation of kinetic energy. This principle states that the total kinetic energy of the system before the collision is equal to the total kinetic energy of the system after the collision.
Using these principles, we can set up equations to solve for the final velocity of the ball after the collision. However, the specific equations will depend on the details of the collision.
In summary, we cannot answer the question without more information about the collision. However, if we have all the necessary information, we can use the principles of conservation of momentum and kinetic energy to calculate the final velocity of the ball after the collision.
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what is the defining property of the trojan asteroids?
The defining property of Trojan asteroids, therefore, is their orbital relationship with a planet and their confinement to stable Lagrange points, distinguishing them from other asteroids that follow independent orbits in the Solar System.
The defining property of Trojan asteroids is their unique orbital relationship with a larger celestial body, typically a planet. Trojan asteroids are a group of small celestial bodies that share the same orbit as a planet, either preceding it or following it in its path around the Sun. These asteroids are situated in stable regions known as Lagrange points, specifically the L4 and L5 Lagrange points.
The L4 and L5 Lagrange points are positions in a planet's orbit where the gravitational forces of the planet and the Sun balance out, creating stable regions where objects can remain relatively stationary. Trojan asteroids are trapped in these Lagrange points, forming clusters or swarms around these stable regions.
The most well-known example of Trojan asteroids is found in the orbit of Jupiter, where thousands of Trojan asteroids have been discovered. Similarly, Trojan asteroids have also been identified in the orbits of other planets, including Mars, Neptune, and Earth.
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I’m on earth.I have an object with a mass of 15 kg. When I put it on a scale, what will the scale read?
The scale will read 147N
Explanation:The mass of the object, m = 15 kg
Since I am on the earth, the acceleration due to gravity on the earth is:
g = 9.8 m/s²
The scale will read the weight of the object, and is calculated below
The weight, W = mg
W = 15(9.8)
W = 147 N
Therefore, the scale will read 147N
What is the speed of the fast train if an observer standing near the tracks between the trains hears a beat frequency of 4.2 Hz? Express your answer using two significant figures. u= m/s Submit Request Answer
the speed of the fast train is: u = 1.4 x 10^2 m/s
The beat frequency is the difference between the frequencies of the two sound waves coming from the trains. We can use this information to calculate the speed of the fast train.
First, we need to know the frequency of the sound wave emitted by each train. Let's call the frequency of the sound wave from the fast train f1 and the frequency of the sound wave from the slow train f2.
We can use the formula for beat frequency:
beat frequency = |f1 - f2|
Plugging in the given beat frequency of 4.2 Hz, we get:
4.2 Hz = |f1 - f2|
Next, we can use the Doppler effect formula for sound:
f = (v +/- u) / (v +/- vs) * f0
where:
f = observed frequency
v = speed of sound (343 m/s)
u = speed of the observer (unknown)
vs = speed of the source (unknown)
f0 = frequency of the sound wave emitted by the source
For the observer standing near the tracks, we can assume that vs = 0.
So for the sound wave from the fast train, we have:
f1 = (v + u) / v * f0
And for the sound wave from the slow train, we have:
f2 = (v - u) / v * f0
Substituting these into the beat frequency equation and simplifying, we get:
4.2 Hz = u / v * f0
Solving for u, we get:
u = 4.2 Hz * v / f0
Plugging in the given frequency of the sound wave from the fast train (which is the same as f0), we get:
u = 4.2 Hz * 343 m/s / f1
Rounding to two significant figures, the speed of the fast train is:
u = 1.4 x 10^2 m/s
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Which point on the standing wave will not move?
Answer:
B
Explanation:
A P E X
Can someone help me solve number 3 for chemical equations?
Answer:
I'm pretty sure it should be 4KClO3-->3KClO4+1KCl
Explanation:
Which substance in the air of U.S. cities has decreased least since the Clean Air Act began?
A. carbon monoxide
B. ground-level ozone
C. particulate matter
D. sulfur dioxide
Answer: the answer is carbon monoxide
Explanation:
hope this helps :)
Identify the following physical quantities as scalars or vectors.speeddistancevelocitypositiondisplacementaverage velocityacceleration
Speed, distance, and position are scalar quantities, while velocity, displacement, average velocity, and acceleration are vector quantities.
Speed refers to how fast an object is moving and is a scalar quantity, with only magnitude, without direction. Distance is a scalar quantity that refers to the amount of space between two points, also having only magnitude.
Position is a scalar quantity that refers to the location of an object in space and also has only magnitude.
Velocity, on the other hand, is a vector quantity, as it has both magnitude and direction. It is the rate of change of an object's position over time.
Displacement is another vector quantity, and it refers to the change in position of an object from its starting point.
Average velocity is a vector quantity that is the average of all velocity changes during a certain time interval.
Acceleration is also a vector quantity and refers to the rate of change of velocity. It measures how quickly the velocity of an object changes, and like velocity, it has both magnitude and direction.
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which of the following is an example of an exerting force?
a child running through a field
a train speeding down a track
a carpenter hammering a nail
an airplane speeding down the track
A stockroom worker pushes a box with a mass of 11.2 kg on a horizontal surface with a constant speed of 3.5 m/s. The coefficient of kinetic friction between the box and the surface is 0.20. a) What horizontal force must be applied by the worker to maintain the motion? b) If the force calculated in part (a) is removed, how far does the box slide before coming to rest?
The distance travelled by the box can be calculated using the equation of motion: s = ut + 1/2 at², where s is the distance travelled, u is the initial velocity, a is the acceleration, and t is the time taken. Substituting the values, we get s = 3.5 m/s × 1.79 s + 1/2 × 1.96 m/s² × (1.79 s)² = 6.27 m. So, the box slides a distance of 6.27 m before coming to rest.
In the problem, we are given that a stockroom worker pushes a box with a mass of 11.2 kg on a horizontal surface with a constant speed of 3.5 m/s and the coefficient of kinetic friction between the box and the surface is 0.20.(a) To maintain the motion of the box with a constant speed of 3.5 m/s, the net force acting on the box must be zero. Since the force of friction is opposing the motion, the force applied by the worker must balance the force of friction, so the worker applies a force equal and opposite to the force of friction.
We know that frictional force can be calculated by the equation: f = μNwhere f is the frictional force, μ is the coefficient of friction, and N is the normal force acting on the object. The normal force acting on the box is equal and opposite to the weight of the box, so N = mg.
The force of friction acting on the box is given by f = 0.20 × 11.2 kg × 9.8 m/s² = 21.952 N. So, the force applied by the worker to maintain the motion is F = f = 21.952 N.(b) If the force calculated in part (a) is removed, then the net force acting on the box is equal to the force of friction, which causes the box to decelerate. The acceleration of the box is given by a = F/m, where m is the mass of the box.
So, a = 21.952 N / 11.2 kg = 1.96 m/s². The time taken by the box to come to rest can be calculated using the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. Since the final velocity is zero, the equation becomes 0 = 3.5 m/s - 1.96 m/s² t. Solving for t, we get t = 1.79 s.
The distance travelled by the box can be calculated using the equation of motion: s = ut + 1/2 at², where s is the distance travelled, u is the initial velocity, a is the acceleration, and t is the time taken. Substituting the values, we get s = 3.5 m/s × 1.79 s + 1/2 × 1.96 m/s² × (1.79 s)² = 6.27 m. So, the box slides a distance of 6.27 m before coming to rest.
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What do you think will happen to current if we increase or decrease the resistance of the connecting wire?
Answer:
If resistance is increased, the current decreases and if the resistance is decreased, the current flowing through the wire increases.
Explanation:
V = IR is ohm's law which implies I = V/R, where I is the current and V is the voltage and R is the resistance. Hence, I is inversely proportional to R.
1. A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N
opposing the motion. Calculate the acceleration of the object.
The acceleration of the block is 6.4 m/s².
To calculate the acceleration of the block, we need to consider the forces acting on it.
The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.
The frictional force opposing the motion is 8 N.
The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).
The net force is the difference between the applied force and the frictional force:
40 N - 8 N = 32 N.
Now, we can plug the values into Newton's second law:
32 N = 5 kg × a.
Solving for the acceleration (a), we get
a = 32 N / 5 kg
a = 6.4 m/s².
Therefore, the acceleration of the block is 6.4 m/s².
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If the mass of the products measured 120 g, what would be the mass of the reactants? 30 g 60 g 120 g 240 g
Answer:
The correct answer option is C
Explanation:
In a balanced chemical reaction mass of the reactant are always equal to mass of the products. Also known as Law of Conservation of Mass which states that " mass can nor be created nor be destroyed in a chemical reaction."
So, the mass of the reactant will be equal to the mass of products.That is 120 grams.
Hence, the correct answer option(C).
If the mass of the products measured 120 grams, then the mass of the reactants would be the same as 120 grams, as per the law of conservation of mass which state that "mass is neither created nor destroyed in a chemical reaction".
Therefore the correct answer is option C,120 grams.
What is a chemical reaction?A chemical reaction is a process in which one or more substances, also known as reactants are converted to one or more different substances, known as products.
According to the law of conservation of mass, which states that "mass is neither generated nor destroyed in a chemical reaction,"
If the mass of the products was 120 grams, then the mass of the reactants would also be 120 grams.
Thus, the correct answer is option C.
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A vertical spring has a spring constant k=32 N/m with a 2 kg mass connected to it. The spring is initially at rest and hanging at its equilibrium position. At t=0, a force is applied to the spring given by: F=128sin(4t). Neglecting air resistance or other damping forces, find the position of the mass as a function of time.
The position of the mass as a function of time is x(t) = 5 * sin(4t).
To find the position of the mass as a function of time, we can use Newton's second law of motion, which states that the sum of the forces acting on an object is equal to the mass of the object multiplied by its acceleration.
The equation of motion for a mass-spring system is given by:
m * d^2x/dt^2 + k * x = F(t)
Where:
m is the mass connected to the spring,
x is the position of the mass,
t is time,
k is the spring constant,
F(t) is the applied force as a function of time.
In this case, the mass m is 2 kg, the spring constant k is 32 N/m, and the applied force is given by F(t) = 128sin(4t).
Plugging these values into the equation of motion, we get:
2 * d^2x/dt^2 + 32 * x = 128sin(4t)
Rearranging the equation, we have:
d^2x/dt^2 + 16 * x = 64sin(4t)
This is a second-order linear ordinary differential equation with constant coefficients. To solve this equation, we can assume a solution of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase angle.
Differentiating x(t) twice with respect to time, we have:
dx/dt = A * ω * cos(ωt + φ)
d^2x/dt^2 = -A * ω^2 * sin(ωt + φ)
Substituting these derivatives into the equation of motion, we get:
-A * ω^2 * sin(ωt + φ) + 16 * A * sin(ωt + φ) = 64sin(4t)
Equating the terms with sin(ωt + φ) on both sides, we have:
-A * ω^2 + 16 * A = 64
Simplifying the equation, we get:
16A - Aω^2 = 64
We know that the angular frequency ω is related to the spring constant k and the mass m as ω = √(k/m). Substituting the given values, we have:
ω = √(32 N/m / 2 kg) = √(16) = 4
Plugging ω = 4 into the equation, we get:
16A - 16 = 64
Solving for A, we have:
16A = 80
A = 5
Therefore, the amplitude A is 5.
Now, we can write the position function as:
x(t) = 5 * sin(4t + φ)
To find the phase angle φ, we can use the initial conditions. At t = 0, the spring is initially at rest and hanging at its equilibrium position, which means x(0) = 0.
Plugging this into the position function, we have:
0 = 5 * sin(0 + φ)
Since sin(0) = 0, we get:
0 = 0 + φ
φ = 0
Therefore, the phase angle φ is 0.
Finally, the position of the mass as a function of time is:
x(t) = 5 * sin(4t)
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determine the direction of the force on the charge due to the magnetic field. (figure 1)
The direction of the force on the charge due to the magnetic field is 0(if angle is 180°) and qVB (angle is 90°)
Magnitude force on moving charge particles is F = qvBsinθ
Direction of particle is given by right hand thumb rule,
Right hand point in direction of v, the finger in direction of B.
Force is directly perpendicular to the right hand palm.
Angle. between. V and B. is 180. degrees
F = qVB sin 180° = 0
Angle between V and B is 90 degrees
F = qVB sin90° = qVB
A magnetic field is a vector field that explains the magnetic influence on electrically charged objects in motion, electric currents, magnetic materials,[1]: [2]. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field. [1]: ch13 [3]: 278 The magnetic field of a permanent magnet attracts or repels other magnets and pulls on ferromagnetic materials like iron. In addition, three more magnetic effects—paramagnetism, diamagnetism, and antiferromagnetism—exert minute forces on "nonmagnetic" materials in a nonuniform magnetic field, however these forces are often so minute that can only be measured by laboratory apparatus
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True or false? When a change of state starts to occur, the energy supplied changes the temperature but not the internal energy.
Answer:
True
Explanation:
This heat energy allows the change of state to happen, and the temperature remains constant during the process. The amount of energy required to change the state of a substance depends upon the mass and characteristics of that substance. The energy required to change the state of a material is known as the latent heat. During a change of phase the temperature does not change, but the internal energy does. The internal energy is the sum of the kinetic energy of the molecules and the chemical potential energy of the molecules.
How do you reduce a camping tent' heat in DIY Method Pl do not cam me with dum replie!
Camping - Even on sweltering summer days, camping is a delightful outdoor activity.
However, if it's hot outside, your tent may become very uncomfortable. Thankfully, there are ways to keep your tent cool. By making the most of your supplies, setting up your tent in the ideal location, and using a tarp or umbrella to block off the sun, you may avoid the heat.
Three methods to keep the tent cool:
1. Bring your cooler of ice into the tent.
2. Use a battery-operated fan to circulate the air.
3. Open your tent’s door and vents if it has any.
4. Sleep on top of your sleeping bag to stay cool.
5. Remove the rain fly if the weather forecast doesn’t predict rain.
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Justin, with a mass of 55 kg, is going down an 8.0-m-high water slide. He starts at rest, and his speed at the bottom is 12 m/s.How much thermal energy is created by friction during his descent?
The converted energy of is the thermal energy created by the friction during his descent. The thermal energy is created by friction during his descent is 404 J .
Given information:
Mass of Justin = 55 kg
Height of water slide = 8 m
Speed at the bottom = 12m/s
Mechanical energy (kinetic or potential energy) is the energy of an object in motion or the energy stored by an object in its position. Mechanical energy is also the engine of renewable energies.
Now,
the total mechanical energy is:
E(i) = U = mgh
⇒ E(i) = 55×9.81×8
⇒ 4004 J
Kinetic energy is the energy that an object possesses due to its motion. If we want to accelerate an object, we must apply a force. The application of force forces us to work. After the work has been done, the energy has been transferred to the object and the object will move at a new constant speed.
And, the kinetic energy :
E(f) = K = (1/2) mv²
⇒ E(f) = 0.50 × 50 × 12
⇒ E(f) = 3600 J
So, the energy lost by the Justin:
ΔE = E(i) -E(j)
⇒ ΔE = 4004 J - 3600 J
⇒ ΔE = 404 J
Hence, this converted energy of is the thermal energy created by the friction during his descent.
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What are some practical applications for determining the motion of an object?
Answer:
Some practical applications for determining the motion of an object are measuring kinetic energy, acceleration, etc.
Explanation:
Can you guys please like my spotify playlist
Answer:
sure
Explanation:
Answer:
uhm ok
Explanation:
coherent light that contains two wavelengths, 660 nm and 470 nm, passes through two narrow slits with a separation of 0.270 mm and an interference pattern is observed on a 2 screen which is a distance 5.10 m from the slits. (a) what is the width of the first-order bright fringe for 660nm light? (b) what is the width of the first-order bright fringe for 470nm light? (c) what is the distance on the screen between the first-order bright fringe for each wavelength?
a) The width of the first-order bright fringe for 660nm light is 12.3 mm
b) The width of the first-order bright fringe for 470nm light is 8.85 mm.
c) The distance between the first-order bright fringe for each wavelength is 3.45 mm.
(a) To find the width of the first-order bright fringe for 660nm light, we can use the formula:
w = λL/d
where w is the width of the fringe, λ is the wavelength of the light, L is the distance between the slits and the screen, and d is the distance between the slits.
Substituting the values, we get:
w = (660 x 10^-9 m) x (5.10 m) / 0.270 x 10^-3 m
w = 1.23 x 10^-2 m or 12.3 mm
Therefore, the width of the first-order bright fringe for 660nm light is 12.3 mm.
(b) Similarly, to find the width of the first-order bright fringe for 470nm light, we can use the same formula:
w = λL/d
Substituting the values, we get:
w = (470 x 10^-9 m) x (5.10 m) / 0.270 x 10^-3 m
w = 8.85 x 10^-3 m or 8.85 mm
Therefore, 8.85 mm is the width of the first-order bright fringe for 470nm light.
(c) The distance between the first-order bright fringe for each wavelength can be found by subtracting the position of the 470nm fringe from the position of the 660nm fringe:
Δx = w660 - w470
Δx = (1.23 x 10^-2 m) - (8.85 x 10^-3 m)
Δx = 3.45 x 10^-3 m or 3.45 mm
Therefore, the distance between the first-order bright fringe for each wavelength is 3.45 mm.
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