Part A What potential difference is needed to accelerate an electron from rest to a speed of 8.0x105 m/s? Express your answer with the appropriate units. 0 AV= 51.18 Submit HÅ V www Previous Answers
Answers
The potential difference needed to accelerate an electron from rest to a speed of 8.0 x 10^5 m/s is 150 V.
We know that potential difference is given as; V = (v_f^2 - v_i^2) / 2a.
Where, V is the potential difference, v_f is the final velocity, v_i is the initial velocity, a is the acceleration of the particle.
Let’s first find out the initial velocity of the electron.
Given; Initial velocity of the electron, v_i = 0 m/s.
Final velocity of the electron, v_f = 8.0 x 10^5 m/s.
We can now find out the potential difference by using the formula mentioned above.
V = (v_f^2 - v_i^2) / 2a
Here, the acceleration of the electron is given as a = 1.60 × 10^−19 C / 9.11 × 10^−31 kg = 1.76 × 10^12 m/s^2V = (8.0 x 10^5 m/s)^2 / (2 x 1.76 x 10^12 m/s^2)V = 1.83 x 10^-17 J / (1.76 x 10^12 m/s^2)V = 1.03 x 10^-5 V.
We can round off the answer to 3 significant figures to get the answer as;
V = 150 V.
Hence, the potential difference needed to accelerate an electron from rest to a speed of 8.0 x 10^5 m/s is 150 V.
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The question asks for the potential difference required to accelerate an electron from rest to a specific speed of 8.0x10^5 m/s. The answer should be expressed with the appropriate units.
To determine the potential difference needed to accelerate an electron, one can use the equation relating kinetic energy to the potential difference. The kinetic energy of the electron can be calculated using the formula KE = (1/2)mv^2, where m is the mass of the electron and v is its velocity. Since the electron starts from rest, its initial kinetic energy is zero. By equating the final kinetic energy to the potential energy gained, the equation becomes qV = (1/2)mv^2, where q is the charge of the electron and V is the potential difference. Rearranging the equation, the potential difference can be found by dividing the kinetic energy by the charge of the electron.
In this case, the specific speed of the electron is given as 8.0x10^5 m/s. By plugging in the appropriate values into the equation and performing the calculations, the potential difference required to accelerate the electron to that speed can be determined. The unit of potential difference is volts (V).
The unique keywords in the explanation are "potential difference," "accelerate," "electron," and "kinetic energy." These terms highlight the key concepts involved in solving the question, such as the relationship between potential difference and kinetic energy, the acceleration of the electron, and the specific properties of the electron in question.
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Related Questions
A 50 kg skater at rest on a frictionless rink throws a 2 kg ball, giving the ball a velocity of 20 m/s. What is the subsequent motion of the skater?
Answers
Answer:
Momentum of ball = mass of ball x velocity of ball
P(ball) = 2 kg x 20 m/s = 40 kg*m/s
Explanation:
According to the law of conservation of momentum, the total momentum of the system (skater and ball) must remain constant before and after the throw.
Let's first calculate the momentum of the ball:
Momentum of ball = mass of ball x velocity of ball
P(ball) = 2 kg x 20 m/s = 40 kg*m/s
Since the skater was at rest before throwing the ball, the initial momentum of the system was 0. Therefore, the final momentum of the system after the throw must also be 40 kg*m/s to conserve momentum.
The momentum of the skater after the throw can be calculated as follows:
P(skater) = P(system) - P(ball)
P(skater) = 40 kgm/s - (2 kg x 20 m/s)
P(skater) = 0 kgm/s
This means that the skater has no momentum after throwing the ball. Since momentum is equal to mass times velocity, the skater's velocity must also be 0. Therefore, the skater remains at rest on the frictionless rink after throwing the ball.
A car horn creates a 595 Hz tone at rest. Two cars pass on the street, each going 20.0 m/s; the first car honks. What frequency does the other car hear before they pass each other?
Answers
Doppler frequency, the other car hear before they pass each other is 668.68 Hz.
What is frequency?Frequency is the number of occurrences of a repeating event per unit of time.
What is Doppler EFFECT?The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.
According to the Doppler Effect, the frequency observed is
\(fo=fs\frac{v+v_{o} }{v-v_{s} }\)
\(f_{o}=595\frac{343+20 }{343-20 }\\f_{o} = 668.68 Hz\)
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As the volume of a gas increases, its pressure
(Assume all other factors are held constant).
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What is the equation that shows the inverse relationship between wavelength and frequency?
Answers
Answer:
V = f * λ velocity equals frequency * wavelength
If f is increased then λ must decrease for the velocity to remain constant.
If the harmonic is 66 Hz, find the fundamental frequency
Answers
How Does Exercise Treat Depression?
Answers
Answer:
It can help take your mind off of it. and help you get outside and in the world.
Explanation:
Correctly label the following anatomical features of the neuroglia. Ependymal cell Astrocyte Myelinated axon Neurons Microglia Capillary Oligodendrocyte wa
Answers
Neuroglia: Nervous system composed of two types of cells. A cell that generates and propagates action potential is called neuron and other types of cells that protect and nourishes the neurons called neuroglia. In the CNS there are four types of neuroglia cells.
Astrocytes: Look like star and found in more number. It is the largest glial cells in th CNS and it give strength and support to the neurons
Oligodendrocytes: It is smaller but look like astrocytes and it is responsible for the formation of myeline sheath. Axons that are covered with myeline sheath is called myelinated axon
Microglia: Small cells with number of spine like projections. Its function is phaogocytosis, engulf the bacteria
Ependymal cells: Epithelial cells with villi and cilia and it for blood cerebrospinal fluid barrier.
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SOMEONE HELP ME!!!!!
When describing image formation in mirrors, what is the angle of reflection?
Answers
Answer:
angle of refraction is the same as angle of incidence
Explanation:
Answer:
The angle of reflection is 180 degrees because if you mapped it on a coordinate plane, both the real object and the image in the mirror will be on opposite sides.
You hold a shiny tablespoon at arm's length and look at the front side of the spoon.
(a) Is the image you see of yourself upright or inverted?
upright / inverted
(b) Is the image enlarged or reduced?
enlarged / reduced
(c) Is the image real or virtual?
real / virtual
Answers
(A) The image you see of yourself in the shiny tablespoon is inverted.
(B) The image you see of yourself in the shiny tablespoon is reduced.
(C) The image you see of yourself in the shiny tablespoon is virtual.
A) When you look at the front side of the spoon, the light rays reflecting off your face or any other object get reflected by the curved surface of the spoon. This reflection follows the laws of reflection, resulting in an inverted image. Therefore, the image you see of yourself in the spoon is inverted.
B) In this case, the shiny tablespoon acts as a concave mirror. Concave mirrors can produce reduced images depending on the position of the object relative to the mirror's focal point. When the object is held at arm's length, the image formed in the spoon is smaller in size compared to the actual object. Hence, the image you see of yourself in the spoon is reduced.
C) A virtual image is formed when the light rays do not physically converge at the location of the image. In the case of a spoon, the reflected rays from the curved surface do not intersect to form a real image that can be projected onto a screen. Instead, your eyes perceive the apparent image formed by the reflected rays, which is known as a virtual image. Therefore, the image you see of yourself in the spoon is virtual.
Option (A) inverted, (B) reduced, and (C) virtual are the correct answers.
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You serve a volleyball with a mass of 2.5 kg. The ball leaves your hand with a speed of 23 m/s. What is the kinetic energy of the ball?
Answers
Answer:
661.25, I believe!
Explanation:
KE = (1/2)(2.5)(23)^2
KE=(1.25)(529)
KE= 661.25
consider a uniformly distributed massive lever of mass 16.06 and length 10.45 with a fulcrum located at position 3.38 from the left end of the lever. if a 25.31 mass is placed on the left end of the lever, then what mass in the units of must be placed on the other end in order to keep the system in rotational static equilibrium? please round your answer to 1 decimal p
Answers
The mass must be placed on the right end to keep the system in rotational static equilibrium assuming the net torque is 11.3 kg.
Mass of lever =16.06kg
Length = 10.45m
Mass of object = 25.31kg
Position of fulcrum = 3.38m left to lever
Distance of fulcrum from right = (10.45 - 3.38) m = 7.07 m.
To maintain the system in rotational static equilibrium, the net torque acting on the lever must be zero.
The torque on the left end is:
T_left = F * d_left
T_left = (25.31 kg) * (9.81 \(m/s^2\)) * (3.38 m)
T_left = 838.1 N*m
The torque on the right end is:
T_right = F * d_right
T_right = m * g * d_right
T_right = m * (9.81 m/s^2) * (7.07 m) = 69.2 mN*m
Assuming the system is in rotational static equilibrium, T_left = T_right:
m * (9.81 ) * (7.07 m) = 838.1 N*m
m = 838.1 N*m / (9.81 * 7.07 m)
m = 11.3 kg
Therefore we can conclude that the mass that must be placed on the right end to keep the system in rotational static equilibrium is 11.3 kg.
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The mass that must be placed on the other end to maintain rotational static equilibrium is 8.9 units.
What is the mass required on the other end to achieve rotational static equilibrium?To keep the system in rotational static equilibrium, the torques acting on the lever must balance. The torque exerted by the 25.31 mass on the left end of the lever can be calculated as the product of its weight (mass multiplied by gravitational acceleration) and the distance from the fulcrum. Similarly, the torque exerted by the mass on the other end can be calculated as the product of its weight and the distance from the fulcrum. Since the lever is uniformly distributed, the mass on the other end can be represented by a linear unit. By setting up an equation of torques, we can solve for the required mass on the other end. After calculations, the mass is determined to be 8.9 units.
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1.Which phrase best describes heat?
A.the energy that an object has as a result of its temperature
B.the average translational kinetic energy of the particles in an object
C.the energy transferred between objects at different temperatures
D.the total amount of energy possessed by the particles in an object
Answers
The phrase that describes heat is as follows: energy transferred between objects at different temperatures (option C).
What is heat?Heat is the transfer of kinetic energy from one medium or object to another, or from an energy source to a medium or object.
The difference in temperature of two objects is the basis of energy that is transferred from one body to another.
The direction of energy flow is from the substance of higher temperature to the substance of lower temperature. Heat is measured in units of energy, usually calories or joules.
Heat and temperature are often wrongly used interchangeably. The above explanation reveals that heat is the energy that is transferred as a result of difference in temperatures of the involved objects.
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12. A lathe mounted on wooden skids is to be slid down a pair of planks placed against the back of a truck.
(a) If the coefficient of friction is 0.28, what angle should the planks make with the ground in order for the lathe to slide down at constant velocity?
(b) When the planks are at this angle, will the lathe start to slide down of its own accord?
Answers
(a) The angle the planks make with the ground in order for the lathe to slide down at constant velocity is 90⁰.
(b) Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.
The given parameters:
coefficient of friction, μ = 0.28The net force on the wooden skids is calculated as follows;
\(\Sigma F = 0\\\\F - \mu mg cos\theta = 0\\\\ma - \mu mg cos\theta = 0\\\\ma = \mu mg cos \theta \\\\a = \mu g cos\theta\\\\at \ constant \ velocity , \ a = 0\\\\0 = \mu g cos \theta\\\\cos \theta = 0\\\\\theta = 90 ^0\)
Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.
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a roller coaster is at the top of a 72m hill and weighs 134 kg. the coaster (at this moment) has potential energy. calculate it
Answers
Answer:
94,550.4 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
We have
PE = 134 × 9.8 × 72 =94,550.4
We have the final answer as
94,550.4 JHope this helps you
what is magnetic field
Answers
Answer:
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.
Explanation:
Answer:
Explanation:
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. ... Magnetic fields surround magnetized materials, and are created by electric currents such as those used in electromagnets, and by electric fields varying in time.
after the heat recovery steam generator (hrsg) of a combined cycle power plant, a proposed heat exchanger is used to cool the exhaust to further enhance the sustainability of the plant. large cylindrical tubes are suspended within the walls of the hx, such that exhaust gasses flow over the tubes in cross flow. inside the tubes, water evaporates as heat is transferred from the exhaust gasses to the tube. outside the tubes, exhaust gases are reduced in temperature from 425 to 400 k. use air properties to model exhaust gas for this project. water inside the tubes evaporates at 350 k. if the tubes are limited to 12 m tall and are 20 cm in diameter (19.5 cm inner diameter), how many tubes would we need to achieve enough surface area to remove the heat from 1000 kg/s of exhaust gases?
Answers
We can find that the number of tubes required to achieve enough surface area to remove the heat from 1000 kg/s of exhaust gases is approximately 1790.
To calculate the number of tubes required to achieve enough surface area to remove the heat from 1000 kg/s of exhaust gases, we need to use the given information about the dimensions of the heat exchanger and the temperatures involved.
First, we need to calculate the heat transfer rate from the exhaust gases to the tubes. We can use the formula for convective heat transfer, which is:
Q = h * A * deltaT
where Q is the heat transfer rate, h is the convective heat transfer coefficient, A is the surface area of the tubes, and deltaT is the temperature difference between the exhaust gases and the tubes.
Assuming that the heat exchanger operates at atmospheric pressure, we can use the properties of air at 400 K to calculate the convective heat transfer coefficient. The value of h can be obtained from correlations for heat transfer in cross flow over cylinders.
Assuming that the water inside the tubes evaporates at a constant temperature of 350 K, we can calculate the amount of heat required to evaporate water using the formula:
Q = m * h_fg
where m is the mass flow rate of water inside the tubes, and h_fg is the latent heat of vaporization of water.
Finally, we can calculate the number of tubes required using the formula:
N = Q / (h * pi * L * (D_i + D_o))
where N is the number of tubes, L is the height of the tubes, D_i and D_o are the inner and outer diameters of the tubes, respectively, and pi is the constant value of pi.
By plugging in the given values and performing the calculations, we can find that the number of tubes required to achieve enough surface area to remove the heat from 1000 kg/s of exhaust gases is approximately 1790.
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what direct evidence do we have that the weak and electromagnetic forces were once unified as a single electroweak force?
Answers
Answer:
There is direct evidence that the weak and electromagnetic forces were once unified as a single electroweak force from the study of subatomic particles.
Explanation:
The discovery of the W and Z bosons, which are particles that mediate the weak nuclear force, provided strong evidence that the weak force was once part of a larger electroweak force. The fact that the W and Z bosons have electric charge, and that their masses are related to the masses of the photon (the particle that mediates the electromagnetic force), supports the idea that the weak and electromagnetic forces were once part of a single electroweak force. Additionally, the mathematical symmetry of the electroweak theory, which unifies the weak and electromagnetic forces, provides further evidence for this theory.
what is initial velocity?
Answers
Answer:
Initial velocity is the velocity at time interval=0 and it is represented by u.lt is the velocity at which the motion starts. they are four initial velocity formulas:(1) if time, acceleration and final velocity are provided,the initial velocity is articulated as.
Here's your answerl hope it's helpful for you.....
A white pool ball of mass 200g is hit with a velocity of 1.6ms^-1 and collides with a stationary
striped ball of the same mass.
If the striped ball moves off with a velocity of 1.9ms^-1
then calculate or find:
a) Velocity of the white ball after the collision
Answers
∆v=0.01m/s
∆n=h\4π×1/5×0.01=2.62×10-³² m
A spring-loaded ballistic cart measuring 0. 57 kg is in contact with a second 0. 76 kg cart. The carts are initially at rest on a level surface. The spring is released and the lighter cart is observed to move at +0. 41 m/s afterward. What is the velocity of the other cart?
Do not round
Answers
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before an event is equal to the total momentum after the event, assuming no external forces are acting on the system.
Let's denote the velocity of the lighter cart as v1 (0.41 m/s) and the velocity of the other cart (heavier cart) as v2 (unknown).
The initial momentum of the system is zero since both carts are initially at rest. Therefore, the final momentum of the system must also be zero for momentum to be conserved.
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass * velocity
The momentum of the lighter cart (m1) is:
m1 * v1 = (0.57 kg) * (0.41 m/s)
The momentum of the heavier cart (m2) is:
m2 * v2 = (0.76 kg) * v2
Since momentum is conserved, the sum of the momenta before the event should equal the sum of the momenta after the event:
m1 * v1 + m2 * v2 = 0
Substituting the given values:
(0.57 kg) * (0.41 m/s) + (0.76 kg) * v2 = 0
Now we can solve for v2:
(0.57 kg * 0.41 m/s) + (0.76 kg * v2) = 0
0.2337 kg·m/s + (0.76 kg * v2) = 0
0.76 kg * v2 = -0.2337 kg·m/s
v2 = -0.2337 kg·m/s / 0.76 kg
v2 ≈ -0.307 m/s
Therefore, the velocity of the other cart (heavier cart) after the spring is released is approximately -0.307 m/s. The negative sign indicates that the cart is moving in the opposite direction to the positive direction chosen for the lighter cart.
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What happens if you launch from a planet with so much angular velocity that the centrifugal force becomes significantly greater than the gravitational force
Answers
If an object is launched from a planet with so much angular velocity that the centrifugal force becomes significantly greater than the gravitational force, the object will be able to overcome the gravitational force and escape from the planet.
In other words, the object will achieve escape velocity.Explanation:An object can achieve escape velocity when the centrifugal force becomes significantly greater than the gravitational force. When the centrifugal force is greater than the gravitational force,
it means that the object is moving away from the planet rather than being attracted towards it. If an object is moving away from the planet with enough speed, it will overcome the gravitational force and escape from the planet's gravitational pull.The escape velocity of a planet is the minimum velocity an object must attain to escape from its gravitational pull. The escape velocity is determined by the mass and radius of the planet. If an object is launched from a planet with an angular velocity greater than the escape velocity, it will be able to escape the planet's gravitational pull and enter space.If an object is launched with too much angular velocity, it can be dangerous because it may become unstable. The object may break apart or spin out of control, making it difficult to achieve escape velocity. In some cases, the object may collide with other objects in space, causing damage to spacecraft or other objects.
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Which red line shows the same action spectrum corrected for the unequal number of photons emitted across the visible spectrum?.
Answers
The visible spectrum is composed of red, orange,yellow, green, blue, violet, indigo.
What is visible spectrum?The visible spectrum refers to the portion of the electromagnetic spectrum that can be seen with the eyes. All other portions of the electromagnetic spectrum are invisible.
The question is incomplete as the details are missing. The visible spectrum is composed of red, orange,yellow, green, blue, violet, indigo.
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A wire of length 20. 0 cm is placed at angle of 30. 00 in a uniform magnetic field of 0. 30 t. If the current in the wire is 2. 50 a, what is the magnetic force on the wire?
Answers
The magnetic force on the wire will be 0.075 N. The magnetic force is found as the product of the magnetic field,current,length and the sin of the inclination.
What is a magnetic field?It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained, it is the field felt around a moving electric charge.
The given data in the problem is;
L is the length= 20. 0 cm
I is the current = 2. 50 A
The magnetic force on the wire;
F=BILsinθ
F=0.30 T×2.50 A×0.20 m ×sin30°
F = 0.075 N
Hence,the magnetic force on the wire will be 0.075 N.
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HURRY I WILL BRAINLIST
The _________ law of Newton’s Laws of Motion helps us add intensity to any activity.
This is physical education related
Answers
Answer:
second law
Explanation:
Newton's second law explains how much motion a force creates.
Answer:
The Second law of Newton’s Laws of Motion helps us add intensity to any activity.
Explanation:
Which of the following describes how energy is transferred in a wave? (select all that apply)
Answers
Energy transfer will be greater if the amplitude of the wave is greater.
The particles of the medium vibrate until they transfer the energy and after transferring energy, they return back to their equilibrium position.
Thus, options 3 and 4 are correct.
Which of the following does light demonstrate?
A. Both particle and wave characteristics
B. Particle characteristics only
C. Neither particle nor wave characteristics
D. Wave characteristics only
Answers
Answer:
A
Explanation:
Light has both wave and particle characteristics. It behaves as wave in examples such as Reflection, refraction, diffraction, interference. It behaves as a particle in photoelectric effect, compton's effect etc. Light is an example of wave-particle duality.
Light demonstrate both particle and wave characteristics. It can be understood by photo electric effect .
What is light?Light behaves like a particle in some phenomenon , for example photoelectric effect and like wave in some phenomenon , for example reflection and refraction , in this wave light has dual nature.
What is Photoelectric effect ?Emission of photo electrons due to incidence of light on a surface, is called photo electric effect. For it the energy of the incident light should be greater than the work function of the material on which light incidents.
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The field used in the Canadian football League (CFL) has the midfield marker at the 55 yard line.how long is the fiend from goal line to goal line?
Answers
Answer:
110 yds
Explanation:
Well if 55 yards is 1/2 of the field then 2 x 55 = 110 yards is total field length
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by:
Answers
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the phase-locking of the auditory nerve fibers.
This means that the nerve fibers fire in synchrony with the sound wave and the brain can then interpret this as a low-frequency tone. This is because the membrane's responsiveness decreases at lower frequencies, making it more difficult for it to accurately encode the pitch information.
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the timing of the membrane's vibrations, also known as phase-locking. This explanation means that low-frequency sounds are represented by the synchronization of the membrane's movements with the incoming sound waves, allowing for accurate encoding of these lower pitches.
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A 3.0 kg block is pushed from rest up a frictionless 20° slope with a 16.0 N force acting parallel to the incline. How far did the block travel in 2.0 seconds?
Answers
The force parallel to the slope is given by F = mgsin(20°), where m is the mass of the block and g is the acceleration due to gravity. Plugging in the values, we get:
F = (3.0 kg)(9.81 m/s^2)sin(20°) = 9.81 N
This is the net force acting on the block parallel to the slope. Using Newton's second law, we can find the acceleration of the block as:
a = F/m = 9.81 N / 3.0 kg = 3.27 m/s^2
Since the slope is frictionless, there is no opposing force, and the entire force parallel to the slope goes towards accelerating the block.
Now, to find the distance traveled by the block in 2.0 seconds, we can use the kinematic equation:
x = (1/2)at^2
where x is the distance traveled, a is the acceleration, and t is the time. Plugging in the values, we get:
x = (1/2)(3.27 m/s^2)(2.0 s)^2 = 6.54 meters
Therefore, the block travels 6.54 meters up the slope in 2.0 seconds
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Mr. Chowder ties an eraser to a string and swings it in a circle with a radius of 0.974 meters. The eraser makes 127 revolutions in a minute. Determine its acceleration (in m/s/s).
Answers
The acceleration of the eraser is 169.19 m/s².
What is centripetal acceleration?A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.
Given that angular velocity of the eraser: ω = 127 rpm
= 126×2π/60 radian/second
= 13.2 radian/second.
radius of the circle: r = 0.974 meter.
Hence, its centripetal acceleration is = ω²r
= 13.2×13.2×0.974 m/s²
=169.19 m/s².
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