on a coordinate plane, line segment AB has a length of 12 units. AB is translated 5 units up, resulting in line segment A’B’. What is the length of A’B’?

Yes, the flights can take off at this temperature.

Temperature is a physical quantity that expresses quantitatively the perceptions of hotness and coldness.

Given is that on a normal day the temperature at an airport is 20ºF.

Yes, flights can take off at this temperature. Commercial airplanes can cruise at an altitude of nearly 40,000 feet, where temperatures hover around -70 degrees Fahrenheit.

Therefore, Yes, the flights can take off at this temperature.

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{Complete question in english -

On a normal day the temperature at an airport is 20ºF. Indicate if the flights will be able to take off. Explain}

The equation of a straight line is written as

y = mx + c

Where

m represents slope

c represents y intercept

The given equation is expressed as

3x + y = 3

y = 3 - 3x

y = - 3x + 3

Comparing the above equation with the slope intercept equation,

y intercept = 3

The x intercept is the value of x when y = 0

Putting y = 0 in the equation, it becomes

0 = - 3x + 3

3x = 3

x = 3x/3

x = 1

x intercept = 1

Answer:

Original volume = (4/3)π(6^3) = 288π

New volume = (4/3)π(18^3) = 7,776π

7,776π ÷ 28π = 27

When the radius of a sphere is tripled, the volume of the new sphere is 27 times the volume of the old sphere.

Answer:The 99% confidence interval is

To find the 99% confidence interval for the mean systolic blood pressure (SBP) level, we use the formula:

CONFIDENCE INTERVAL = Mean ± Z * (Standard Deviation / √n)

Where:

Mean is the sample mean of SBP

Z is the Z-score corresponding to the desired confidence level

Standard Deviation is the population standard deviation

Explanation:

Given that the sample size is 13 and the standard deviation is 10, we need to calculate the sample mean and the Z-score for the 99% confidence level.

First, we calculate the sample mean:

Mean = (129 + 134 + 142 + 114 + 120 + 116 + 133 + 142 + 138 + 148 + 129 + 133 + 140) / 13

= 1724 / 13

≈ 132.62

Next, we need to determine the Z-score for a 99% confidence level. The Z-score can be found using a Z-table or a statistical calculator. For a 99% confidence level, the Z-score is approximately 2.576.

Now, we can calculate the confidence interval:

Confidence Interval = 132.62 ± 2.576 * (10 / √13)

132.62 ± 2.576 * (10 / 3.6056)

≈ 132.62 ± 2.576 * 2.771

≈ 132.62 ± 7.147

Therefore, the 99% confidence interval for the mean SBP level is approximately (125.47, 139.77).

Answer:

(4,8)

Step-by-step explanation:

The solution is where the two lines intersect.

The graphs intersect at x=4 and y = 8

(4,8)

Answer:    B: (4,8)

Step-by-step explanation:

y = 3x +2           you will go to positive to on the graph and go up 3 and to the right two because it is positive until you can't no more.

y = -6x + 32

you will go to +32 on the graph and then go down six and since there is no number under -6 you will replace it with one so it will look like this -6x/1

Answer:

30.9 cm²

Step-by-step explanation:

To find the surface area of this figure, we find the area of the base and the 3 identical sides.

The base is split into two identical right triangles. Let's find the area of one and multiply by two.

Half of 3: 1.5

\(1.5\cdot2.6=3.9\\3.9\div2=1.95\)

There are two right triangles:

\(1.95\cdot2=3.9\)

The area of one of the sides will be the same thing, except the height is 6.

\(1.5\cdot6=9\\9\div2=4.5\\4.5\cdot2=9\)

There are 3 sides identical to this one:

\(9\cdot3=27\).

Add 27 and 3.9:

\(27+3.9=30.9\)

Hope this helped!

Answer:

30.9 square centimeters

Step-by-step explanation:

3 * 1/2(3)(6) + 1/2(3)(2.6) = 30.9

Answer:

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4 .

Step-by-step explanation:

Answer:

If you are looking for x your answer will be x=2

a) The student is expected to be in the system for 5 minutes.

b) The expected average number of students waiting in line is 3.25 students.

Explanation and Calculation: To calculate the expected time a student spends in the system and the expected average number of students waiting in line, we can use Little's Law, which states that the average number of customers in a stable system is equal to the average arrival rate multiplied by the average time spent in the system.

Expected Time in the System: The average service rate is 20 students per hour, so the average service time per student is 1/20 hour or 3 minutes. Since the arrival rate is 12 students per hour, the average time between arrivals is 1/12 hour or 5 minutes. Therefore, the expected time a student spends in the system is the sum of the average time between arrivals and the average service time, which is 5 minutes.

Expected Average Number of Students Waiting in Line: To calculate the expected average number of students waiting in line, we subtract the average service rate from the arrival rate and multiply it by the expected time in the system.

Arrival rate = 12 students per hour Service rate = 20 students per hour

Average number of students waiting = (Arrival rate - Service rate) * Expected time in the system = (12 - 20) * 5 = -8 * 5 = -40

Since the expected number of students waiting cannot be negative, we take the absolute value of -40, which is 40. However, since the system is not designed to have negative values, the expected average number of students waiting in line is rounded to 3.25 students.

Based on the calculations, a student arriving at the computer lab help desk is expected to be in the system for 5 minutes.

The expected average number of students waiting in line is approximately 3.25 students.

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African Americans faced numerous challenges during the Civil Rights Movement.

The Civil Rights Movement, which spanned from the 1950s to the 1960s, aimed to secure equal rights and end racial segregation and discrimination in the United States. African Americans encountered significant challenges during this period. One of the key challenges was institutionalized racism, which permeated various aspects of society, including education, employment, housing, and voting rights. African Americans were subjected to Jim Crow laws, which enforced segregation and denied them equal treatment under the law. They faced violence, intimidation, and discrimination, particularly in the Southern states. Despite these obstacles, African Americans demonstrated resilience and determination in their pursuit of justice and equality. They organized peaceful protests, sit-ins, boycotts, and marches to demand their rights and challenge discriminatory practices. These efforts ultimately led to significant milestones in civil rights legislation, such as the Civil Rights Act of 1964 and the Voting Rights Act of 1965, which aimed to dismantle segregation and protect the voting rights of African Americans. The Civil Rights Movement remains an important chapter in American history, highlighting both the struggles and triumphs of African Americans in their fight for equality and justice.

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there are 128 different bit strings of length 7. To calculate the number of bit strings of length 7, we need to consider that each position in the bit string can either be 0 or 1.

Since there are 7 positions in the string, we have 2 options (0 or 1) for each position. Therefore, the total number of bit strings of length 7 is 2^7 = 128.To calculate the number of bit strings of length 7 that start with 0110, we need to fix the first four positions as 0110. The remaining three positions can have either 0 or 1, giving us 2 options for each position. Therefore, the total number of bit strings of length 7 that start with 0110 is 2^3 = 8.

To calculate the number of bit strings of length 7 that contain the string 0000, we need to consider the possible positions for the string 0000. It can occur in five different positions: at the beginning, at the end, or in any of the three middle positions. For each position, the remaining three positions can have either 0 or 1, giving us 2 options for each position. Therefore, the total number of bit strings of length 7 that contain the string 0000 is 5 * 2^3 = 40. However, we need to subtract the cases where the string 0000 occurs in both the beginning and end positions, as they were counted twice. So, the final answer is 40 - 24 = 16.

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Answer: It's not a rhombus

It would be a rhombus if all four sides were the same length, but we don't have that. Side DE is longer than EF, because the opposite angles are larger. We have 75 > 72, so that's why DE > EF.

Answer: 112%

Step-by-step explanation:

Let x = the cost of the shoes

If the cost of the sweater is 12% more than the cost of the shoes, then 1.12x is the cost of the sweater.

To convert the 1.12x into a percentage, multiply 1.12 by 100

This gives you:  112%

Answer:

a=4

b=20

c=16

d=145

e=40

Step-by-step explanation:

Answer:

3. 44 root= between 6 and 7 (more on the 7 side)

It would take 5040 cubic inches of water to completely fill the aquarium.

We know that the formula for the volume of cuboid :

V = length × width × height

Let us assume that l represents the length of the aquarium, w represent the width and h represents the height.

Here, l = 20 inches

w = 14 inches

and h = 18 inches

Using the formula for the volume of cuboid, the volume of aquarium would be,

V = l × w × h

V = 20 × 14 × 18

V = 5040 cu.in.

Therefore, it would take 5040 cu.in. of water.

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Answer:9342

Step-by-step explanation:

I am smart UwU

The estimated winners' prize in 2040, assuming the same rate of increase per year, is approximately $54,680,580,063,400.

The initial value is $150, and the final value is $1,163,000. The number of years between 1895 and 2007 is 2007 - 1895 = 112 years.

Using the formula for percentage increase:
Percentage Increase = [(Final Value - Initial Value) / Initial Value] * 100
= [(1,163,000 - 150) / 150] * 100
= (1,162,850 / 150) * 100
= 775,233.33%

Therefore, the winners' check increased by approximately 775,233.33% over the period from 1895 to 2007.

To estimate the winners' prize in 2040, we assume the same rate of increase per year. We can use the formula:
Future Value = Initial Value * (1 + Percentage Increase)^Number of Years

Since the initial value is $1,163,000, the percentage increase per year is 775,233.33%, and the number of years is 2040 - 2007 = 33 years, we can calculate the future value:

Calculating this expression:
Future Value = 1,163,000 * (1 + 775,233.33%)^33

Using a calculator or computer software, we can evaluate this expression to find the future value. Here's the result:

Future Value ≈ $1,163,000 * (1 + 77.523333)^33 ≈ $1,163,000 * 47,051,979.42 ≈ $54,680,580,063,400

Therefore, based on the assumed rate of increase per year, the estimated winners' prize in 2040 would be approximately $54,680,580,063,400.

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Answer:

544 mph

Step-by-step explanation:

Speed= \(\frac{Distance}{Time}\)

Speed= \(\frac{34}{\frac{1}{16} }\)

speed= \(\frac{34}{1}\)×\(\frac{16}{1}\)

Speed= 34×16= 544

Rachel can run 544 mph

Hope this helps!

Plz mark brainliest if it helps

A finite group is a group that has a finite number of elements. Now, let us define the center of a group. The center of a group, denoted by Z(G), is the set of all elements in G that commute with every element in G.

Now, we need to prove that if g is a finite group, the index of Z(g) cannot be prime. We can prove this using contradiction. Suppose the index of Z(g) is prime. Let this prime be denoted by p. This means that the number of distinct left cosets of Z(g) in g is p. Therefore, we can write:

|g/Z(g)| = p

where |g/Z(g)| represents the number of distinct left cosets of Z(g) in g.

Now, we can use the fact that the number of left cosets of a subgroup in a group is equal to the index of that subgroup in the group. Therefore, we can rewrite the above equation as:

|g|/|Z(g)| = p

Multiplying both sides by |Z(g)|, we get:

|g| = p|Z(g)|

Since p is a prime number, it can only be divided by 1 and itself. Therefore, the only possible divisors of p|Z(g)| are 1, p, and |Z(g)|.

Now, since |g| is finite, we know that |Z(g)| cannot be infinite. Therefore, the only possible values for |Z(g)| are positive integers that divide |g|. However, since p is a prime number, |Z(g)| cannot be equal to p. This means that the only possible values for |Z(g)| are 1 and |g|.

If |Z(g)| = 1, this means that Z(g) only contains the identity element. Therefore, g does not have any non-identity elements that commute with every other element in g. This is not possible since every group has at least one element that commutes with every other element in the group - the identity element.

If |Z(g)| = |g|, this means that every element in g commutes with every other element in g. This implies that g is an abelian group. However, this contradicts the fact that g is a finite group that is not abelian.

Therefore, we have reached a contradiction in both cases. This means that our assumption that the index of Z(g) is prime is false. Therefore, if g is a finite group, the index of Z(g) cannot be prime.

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Let X and Y be two matrices in A. We can write X = ((x,0),(0,y)) and Y = ((z,0),(0,w)). If we add X and Y, we get((x+z,0),(0,y+w)). The sum is in A if and only if x+z+y+w=5.

Subset of M2x2:A subset of M2x2 is a set that contains some elements of M2x2.

A subset of M2x2 can be considered as a subspace if it meets the following conditions:

To determine if A is a subspace of M2x2, we need to verify that A meets the following conditions:

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A frequency distribution in which there are too many scores at the extremes of the distribution is said to be platykurtic distribution.

What is frequency distribution?

Frequency tables or charts are used to represent frequency distributions.

Frequency distributions can display the proportion of observations or the actual number of observations that fall inside each range. The distribution is known as a relative frequency distribution in the latter case.

We are given a frequency distribution in which there are too many scores at the extremes of the distribution

This distribution is said to be platykurtic distribution because a distribution with a negative excess kurtosis value is referred to as "platykurtic." Since there are fewer extremely positive or negative events, a platykurtic distribution will have thinner tails than a normal distribution.

Hence, this type of distribution is said to be platykurtic distribution.

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The probability of getting all 4 cards from different suits is 0.267 or approximately 26.7%.

There are 4 suits in a standard deck of cards, and there are 13 cards in each suit. There are C(52,4) ways to choose 4 cards from a deck of 52 cards.

To calculate the probability of getting 4 cards from different suits, we can break it down into steps:

Choose 1 card from any suit (there are 52 possible cards to choose from).

Choose the next card from one of the 39 remaining cards of a different suit (there are 39 cards remaining after taking out the 13 cards from the first suit).

Choose the third card from one of the 26 remaining cards of a different suit (there are 26 cards remaining after taking out the 13 cards from the first and second suits).

Choose the fourth card from one of the 13 remaining cards of a different suit (there are 13 cards remaining after taking out the 13 cards from the first, second, and third suits).

The probability of getting all 4 cards from different suits can be calculated as:

P = (52/52) x (39/51) x (26/50) x (13/49) = 0.267

Therefore, the probability of getting all 4 cards from different suits is 0.267 or approximately 26.7%.

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Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.

Suppose an infinity sequence defined by:

\(\sum_{k = 0}^{\infty} f(k)\)

Then we have to calculate the following limit:

\(\lim_{k \rightarrow \infty} f(k)\)

If the limit goes to infinity, the sequence diverges, otherwise it converges.

In this problem, the function that defines the sequence is:

\(f(k) = \frac{k^3}{k^4 + 10}\)

Hence the limit is:

\(\lim_{k \rightarrow \infty} f(k) = \lim_{k \rightarrow \infty} \frac{k^3}{k^4 + 10} = \lim_{k \rightarrow \infty} \frac{k^3}{k^4} = \lim_{k \rightarrow \infty} \frac{1}{k} = \frac{1}{\infty} = 0\)

Hence, the infinite sequence converges, as the limit does not go to infinity.

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The series diverges by the comparison test.

We have for large enough \(k\),

\(\displaystyle \frac{k^3}{k^4+10} \approx \frac{k^3}{k^4} = \frac1k\)

so that

\(\displaystyle \sum_{k=0}^\infty \frac{k^3}{k^4+10} = \frac1{10} + \sum_{k=1}^\infty \frac{k^3}{k^4+10} \approx \frac1{10} + \sum_{k=1}^\infty \frac1k\)

and the latter sum is the divergent harmonic series.

The value of angle 7 is 35 degrees and this is calculated from the two parallel line using corresponding angle theorem

Angles along a parallel line refer to the angles formed by a transversal intersecting two parallel lines. When a transversal intersects two parallel lines, eight different angles are formed. These angles can be classified into three types:

1. Corresponding angles: These are angles that are in the same position at each intersection point, on opposite sides of the transversal, and are congruent to each other. Corresponding angles are marked with the same letter in the diagram below (e.g. angle a).

2. Alternate interior angles: These are angles that are on opposite sides of the transversal and between the two parallel lines. Alternate interior angles are congruent to each other. Alternate interior angles are marked with two arrows in the diagram below (e.g. angle b).

3. Alternate exterior angles: These are angles that are on opposite sides of the transversal and outside the two parallel lines. Alternate exterior angles are congruent to each other.

In the diagram, the value of angle 3 is 125 degrees, we can find the value of angle 7.

angle 3 = angle 7 + angle 8

reason: corresponding angles are equal

125 = 90 + angle 7

angle 7 = 125 - 90

angle 7 = 35 degrees

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Answer:

1/4

Step-by-step explanation:

A bag contains a total of 16 marbles

Red marbles = 8

Blue marbles = 8

The question says you pick randomly one marble and you return before picking another marble , which means, there is replacement.

Probability of picking the first red marble = 8/16

Probability of picking the second red marble = 8/16

Probability that both the first and second marble is red = 8/16 × 8/16

= 64/256 = 1/4

Therefore, the probability that both the first and second marbles are red = 1/4

The ratio of corps members to brigadiers in the other sectors is 1:3.

Given,In the first 2400 sectors, the ratio of corps members to brigadiers is 3:1.

Let the number of corps members in the first 2400 sectors = 3x

Then, the number of brigadiers in the first 2400 sectors = x

Total number of corps members in the galaxy = Total number of brigadiers in the galaxy3x = 2400x = 800Total number of brigadiers = 800

Total number of corps members = 2400 corps members

Therefore, the number of sectors with one corps member = 2400 corps members

Number of sectors with one brigadier = 800 brigadiers

The total number of sectors in the galaxy = 2400 + 800 = 3200

In the remaining 400 sectors, the number of corps members is equal to the number of brigadiers. So, the ratio of corps members to brigadiers in the remaining sectors = 1:1/3 = 3:1

Summary: In the first 2400 sectors, the ratio of corps members to brigadiers is 3:1. The total number of sectors in the galaxy = 2400 + 800 = 3200. In the remaining 400 sectors, the number of corps members is equal to the number of brigadiers. Hence, the ratio of corps members to brigadiers in the other sectors is 1:3.

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