On a coordinate plane, line P Q goes through (negative 6, 4) and (4, negative 4). Point R is at (4, 2).
Which point is on the line that passes through point R and is perpendicular to line PQ?

(–6, 10)
(–4, –8)
(0, –1)
(2, 4)

Answer:

For 2 its 5, and for 6 its 5

Step-by-step explanation:

6x5=30 there are six sides so divide by 6, and there you get 5.

2=5

6=5

Answer:

Two 1/6 pieces

Step-by-step explanation:

Two 1/6 pieces equals 1/3 of the apple

Answer:

x = 5*|y|

Step-by-step explanation:

We know that the function is something of the form:

x = |a*y|

We know this because the vertex of the function is in the point where the value of the absolute part is zero, this is when y = 0

and:

x = |a*0| = 0

(0, 0)

Now let's look another point where the graph passes through to find the value of a.

We can see that the graph also passes through the point (5, 1) and (5, -1)

Then, when y = 1, we must have x = 5

Replacing these in our equation we get:

x = |a*y|

5 = |a*1|

5 = |a|

then we can have

Then we can rewrite:

x = |a*y| = |a|*|y| = 5*|y|

x = 5*|y|

The correct option is the last option.

The value of  in the given image of the right triangle is 18.87.

Th given shape is a right triangle. A right triangle is a triangle that has an angle that measures 90 degrees. The sum of angles in a right triangle is 180 degrees.

In order to determine the value of x, trigonometry would be used.

We have to determine the value of the opposite side given the value of the adjacent side. This means that tan would be used to determine the value of x.

Tan 48 = opposite / adjacent

Tan 48 = x / 17

1.11061251 = x / 17

x = 1.1106125 x 17

= 18.87

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The graph of g(x) is (a) an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 2) and goes through (1, 5).

The function f(x) is given as:

\(f(x) = 2(0.4)^x\)

\((x,y) \to (-x,y)\)

This means that:

\(g(x) =f(-x)\)

\(f(-x) = 2(0.4)^{-x}\)

\(g(x) = 2(0.4)^{-x}\)

Hence, the graph of g(x) is graph (a)

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The number of real solutions of a quadratic equation depends on the sign of the discriminant.We can find discriminant by using discriminant formula.

A real solution in algebra is simply a solution to an equation that is a real number. there can be 0, 1, or 2 solutions to a quadratic equation depending on whether the expression inside the square root sign (b2 - 4ac), is positive, negative, or zero.

When the discriminant value is positive we get two real solutions. When the discriminant value is zero we get one real solution. When the discriminant value is negative we get a pair of complex solutions.

So that we can find real solution of quadratic equation by finding discriminant of given equation.

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Answer:

5/2

Step-by-step explanation:

23x-19x+5=2x

23x-19x-2x=5

2x/2=5/2

x=5/2

Answer: The correct answer is 27

Step-by-step explanation: EDGE 2022

Answer:

7.14

Step-by-step explanation:

Answer:

x > 3

Step-by-step explanation:

The expression that equals 2B+C in standard form is 4x² + 6

From the question, we have the following parameters that can be used in our computation:

B = x² + 2

C = 2 + 2x²

The expression to calculate is given as

2B + C

Substitute the known values in the above equation, so, we have the following representation

2B + C = 2x² + 4 + 2 + 2x²

Evaluate the like terms

2B + C = 4x² + 6

Hence, the expression is 4x² + 6

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The measure of reliability of a statistical inference is the significance level. The significance level, also known as alpha, is the probability of rejecting the null hypothesis when it is actually true. It determines the threshold for accepting or rejecting a hypothesis.

A lower significance level indicates a higher level of confidence in the results. A descriptive statistic provides information about the data, but it does not directly measure the reliability of a statistical inference. It simply summarizes and describes the characteristics of the data.

A sample statistic is a numerical value calculated from a sample, such as the mean or standard deviation. While it can be used to make inferences about the population, it does not measure the reliability of those inferences.
A population parameter is a numerical value that describes a population, such as the population mean or proportion.

While it provides information about the population, it does not measure the reliability of inferences made from a sample. In conclusion, the significance level is the measure of reliability in a statistical inference as it determines the probability of making a Type I error, which is rejecting the null hypothesis when it is actually true.

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EXPLANATION:

We are given the following;

A farmer wants to make a 70% protein ration

The mix would have;

75% protein supplement

25% protein ration

1800 pounds mix of 70% protein ration

From these details we can make out the following;

Take note that the mixture would be made up of protein supplements and protein rations. Hence, the total mix of 1800 pounds would be'

Supplements + Ration = Mixture

Where Supplements is x pounds, then Ration would be 1800 minus x to derive the total weight of Ration.

We can now simplify the equations we came up with and we'll have;

Divide both sides by 50;

Therefore, for the protein supplement we would have;

Also, for the protein ration;

ANSWER:

Protein Supplement = 1215 pounds

Protein Ration = 585 pounds

A mathematical operation which is the same as dividing a number by 1,000 include the following: C. move the decimal 3 places to the left.

In Mathematics, a quotient can be defined as a mathematical expression that is typically used for the representation of the division of a number by another number.

This ultimately implies that, a quotient in terms of numerical data simply refers to a division of a number (numerator) by another number (denominator).

In terms of determining the decimal place after a division of a number by 1000, we have the following:

Number = 1/1000

Number = 0.001 (3 places to the left.)

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The possible dimensions (length and width) of the field are:(10 m × 13 m) or (13 m × 10 m) and (11 m × 12 m) or (12 m × 11 m).

Given that Aaron has 47m of fencing to build a three-sided fence around a rectangular plot of land that sits on a riverbank. The fourth side of the enclosure would be the river.

The area of the land is 266 square meters.To find the possible dimensions (length and width) of the field, we can use the given information.The length of fencing required = 47 m.

Since the fence needs to be built on three sides of the rectangular plot, the total length of the sides would be 2l + w = 47.1. When l = 10 and w = 13, we have:

Length of the field, l = 10 m Width of the field, w = 13 mArea of the field = l × w = 10 × 13 = 130 sq. m2. When l = 11 and w = 12,

we have:Length of the field, l = 11 m

Width of the field, w = 12 m

Area of the field = l × w = 11 × 12 = 132 sq. m

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a.) The probability that Ben is ruined is 0.07776, or approximately 7.78%

b.) The probability that Jerry is ruined is 0.064, or approximately 6.4%

a. To find the probability that Ben is ruined, we need to calculate the probability of Jerry winning all the remaining games.
Ben starts with $9 and Jerry starts with $6. In order for Jerry to wipe out Ben, he needs to win at least $9 from Ben.
Let's consider the scenario where Ben loses all his remaining money, one game at a time.
For Ben to lose $9, Jerry needs to win at least 5 games in a row.
The probability of Jerry winning a game is 0.6. So, the probability of Jerry winning 5 games in a row is 0.6^5 = 0.07776.
Therefore, the probability that Ben is ruined is 0.07776, or approximately 7.78%.

b. To find the probability that Jerry is ruined, we need to calculate the probability of Ben winning all the remaining games.
For Jerry to be ruined, Ben needs to win at least $6 from Jerry.
Let's consider the scenario where Jerry loses all his remaining money, one game at a time.
For Jerry to lose $6, Ben needs to win at least 3 games in a row.
The probability of Ben winning a game is 0.4 (since Jerry wins with a probability of 0.6). So, the probability of Ben winning 3 games in a row is 0.4^3 = 0.064.
Therefore, the probability that Jerry is ruined is 0.064, or approximately 6.4%.

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Answer:

Step-by-step explanation:

Objective function:

Maximize 60y₁ + 280y₂ + 248y₃

Constraints:

7y₁ + 10y₂ + 4y₃ ≤ 14

9y₁ + 3y₂ + 2y₃ ≤ 27

4y₁ + 6y₂ + y₃ ≤ 9

To convert the given standard minimum problem into its dual standard maximum problem, we need to reverse the objective function and constraints. The new objective function will be to maximize the sum of the coefficients multiplied by the dual variables, while the constraints will represent the coefficients of the primal variables in the original problem.

The original standard minimum problem is:

Minimize 14x₁ + 27x₂ + 9x₁

subject to:

7x₁ + 9x₂ + 4x₂ ≥ 60

10x₂ + 3x₂ + 6x₂ ≥ 280

4x₁ + 2x₂ + x₂ ≥ 248

x₁ ≥ 20, x₂ ≥ 20, x₂ ≥ 20.

To convert this into its dual standard maximum problem, we reverse the objective function and constraints. The new objective function will be to maximize the sum of the coefficients multiplied by the dual variables:

Maximize 60y₁ + 280y₂ + 248y₃ + 20y₄ + 20y₅ + 20y₆

subject to:

7y₁ + 10y₂ + 4y₃ + y₄ ≥ 14

9y₁ + 3y₂ + 2y₃ + y₅ ≥ 27

4y₁ + 6y₂ + y₃ + y₆ ≥ 9

y₁, y₂, y₃, y₄, y₅, y₆ ≥ 0.

In the new problem, the dual variables y₁, y₂, y₃, y₄, y₅, and y₆ represent the constraints in the original problem. The objective is to maximize the sum of the coefficients of the dual variables, subject to the new constraints. Solving this dual problem will provide the maximum value for the original minimum problem.

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The value of x from the similar triangles is x = 4

If two triangles' corresponding angles are congruent and their corresponding sides are proportional, they are said to be similar triangles. In other words, similar triangles have the same shape but may or may not be the same size. The triangles are congruent if their corresponding sides are also of identical length.

Corresponding sides of similar triangles are in the same ratio. The ratio of area of similar triangles is the same as the ratio of the square of any pair of their corresponding sides

Given data ,

Let the first triangle be ΔQRS

Let the second triangle be ΔLMN

Now , the measure of ∠QRS = measure of ∠NLM

And , the triangles are similar

Now , the corresponding sides of similar triangles are in the same ratio

On simplifying , we get

LM / RQ = LN / QS

( 2x + 4 ) / 8 = 9 / 6

Multiply by 8 on both sides , we get

2x + 4 = ( 3/2 ) 8

2x + 4 = 12

Subtracting 4 on both sides , we get

2x = 8

Divide by 2 on both sides , we get

x = 4

Therefore , the value of x is 4

Hence , the similar triangles are solved

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Step-by-step explanation:

Examples of like terms in math are x, 4x, -2x, and 7x. These are like terms because they all contain the same variable, x. The terms 8y2, y2, and -2y2 are like terms as well. These all contain the same variable, y, raised to the second power.

Answer:

it's -4

Step-by-step explanation:

hope it helped!!!!!!

Answer:

-4

Step-by-step explanation:

The answer will be the same as a positive square root, just add a negative.

Answer:

6 3/100

Step-by-step explanation:

brainliest pls

Answer:

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Find the distance between the given point (-3, 2) and the center of circle (4, 0) using distance formula:

As we see the distance is greater than radius, hence it is outside circle.

The following were the observed points of the triangles as shown in the image provided:

The transformation of triangle ABC to A'B'C' is of the rule (x, y) to (-x, -y). This rule represents a 180-degree counterclockwise rotation

The transformation of triangle A'B'C' to A"B"C" is of the rule (x, y) to (x, y-3). This rule represents a translation down by 3 units

Hence, ABC is rotated 180 degrees counterclockwise about the origin to become A'B'C'. Then A'B'C' is translated 3 units down to become A"B"C" the transformation are both rigid, the pre-image and image are congruent

The probabilities are given as follows:

The mass probability formula, giving the probability of x successes, is of:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

The parameters are given by:

The parameter values for this problem are given as follows:

Hence the probability of one senior having the birthday on the same day as the graduation is of:

P(X = 1) = 68 x 1/365 x (364/365)^67 = 0.1550.

The probability of more than one is given as follows:

P(X > 1) = 1 - P(X <= 1).

In which:

P(X <= 1) = P(X = 0) + P(X = 1)

Hence:

Finally:

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Answer:

0.50 goes right in the middle between 0 and 1 and 0.85 goes 1/5 away from 1

Step-by-step explanation:

Answer:

1. Income highlight: $4123 of take home pay. That's it.

Total monthly income: $4123

------------------------------------

2. Expense highlight:

$1200 child support

$475 every 2 weeks

$145 car payment

$113 car insurance

$47.36 house insurance

$55 loan payment

Total monthly expense:  $2510.36

(1200 + 2(475) + 145 + 113 + 47.36 + 55 = $2510.36

---------------------------------------------

3. $4123 - 2510.36 = 1612.64 surplus

--------------------------------------------

The only question remaining is what if they want him paying more on his credit line...it's kind of a variable expense at this point.

John also has an outstanding credit line of $8500. The only amount due on this account is the interest of about $55 monthly. However John is trying to pay off the credit line within the next 2 years, so he pays off as much of this loan as he can afford each month.

It is used to simplify and combine fractions with different denominators by finding a common denominator.(\(m^{2}\) + 2mn) / (mn+\(n^{2}\)) Thus option D is correct.

To perform the operation:

m/mn + n/m+n

We need to find the LCD (Least Common Denominator) of the fractions, which is mn+n.

Then, we can rewrite each fraction with the LCD and simplify:

m/mn + n/m+n = m(m+n)/(mn+\(n^{2}\)) + n(mn)/(mn+\(n^{2}\))

= m(m+n)/(mn+\(n^{2}\)) + mn/(mn+\(n^{2}\))

= m(m+n) + mn / (mn+\(n^{2}\))

= (\(m^{2}\) + mn + mn) / (mn+\(n^{2}\))

= ( + 2mn) / (m\(m^{2}\)n+\(n^{2}\))

Therefore,  (\(m^{2}\) + 2mn) / (mn+\(n^{2}\)), which is option 4.

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Answer:

3. 1 is ur answer

Step-by-step explanation: Just did the lesson and got it right

In comparing line segment lengths in geometry, measure the length of the reference line (in this case, line BG) and then measure the lengths of the other line segments. Those of identical length to line BG are the ones you're looking for.

Given that line BG is the reference, we need to examine the other line segments to determine which are the same length. This is a process of comparison in geometry. Given that no image was provided, I can't specify the segments equal to line BG. However, the process involves measuring the length of line BG and then measuring the lengths of the other line segments one by one. The line segments that are the same length as line BG are the ones we're looking for.

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