Omg- I need mega help- Ok- WHATS 1+1?! fr- this is such a hard question

Answer:

214.50

Step-by-step explanation:

A = lw

13 x 11 = 143 (13 is a guess)

143 x 1.50 = 214.50

im not 100 % but give it a try

hope this helps

pls mark brainliest

Answer:

The most sense-making answer in my calculation is A.

Step-by-step explanation:

Pls consider marking my answer as Brainliest! It would mean a lot!

Step-by-step explanation:

step 1 :first solve one linear equation for y in terms of x

step 2: then substitute that expression for y in the other linear equation

step 3 :solve this and you have the x-coordinate of the intersection

step 4: then plug in a to either equation to find the corresponding y -coordinate

Answer:

4\(m^{3}\) +13m² + 4m - 12

Step-by-step explanation:

Use FOIL type method:

(4m^2 +5m - 6)(m+2)

= (4m^2)(m) + (5m)(m) - (6)(m) + (4m^2)(2) + (5m)(2) - (6)(2)

= 4m^3 +5m^2 +8m^2 -6m +10m -12

combine like terms:

= 4m^3 +13m^2 + 4m -12

- BRAINLIEST answerer

The to find the volume of the parallelepiped is V = |A · B × C| where A, B, and C are vectors representing three adjacent sides of the parallelepiped and | | denotes the magnitude of the cross product of two vectors.

The cross product of two vectors is a vector that is perpendicular to both the vectors, and its magnitude is equal to the product of the magnitudes of the two vectors multiplied by the sine of the angle between the two vectors he three adjacent sides of the parallelepiped can be represented by the vectors v1, v2, and v3, and these vectors can be found by subtracting the coordinates of the vertices

:v1 = (-2, 5, -8) - (-2, -2, -5)

= (0, 7, -3)v2 = (-2, -8, -7) - (-2, -2, -5)

= (0, -6, -2)v3 = (-7, -9, -1) - (-2, -2, -5)

= (-5, -7, 4)

Using the formula V = |A · B × C|, we can find the volume of the parallelepiped as follows:

V = |v1 · (v2 × v3)|

where v2 × v3 is the cross product of vectors v2 and v3, and v1 · (v2 × v3) is the dot product of vector v1 and the cross product v2 × v3.Using the determinant formula for the cross-product, we can find that:

v2 × v3

= (-6)(4)i + (-2)(5)j + (-6)(-7)k

= -48i - 10j + 42k

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Answer:

Step-by-step explanation:

25

Answer:

Step-by-step explanation:

not clear

The probability that the die landed with a 2 or 3, given that a red marble was drawn, is approximately X.

To calculate the probability, we can use Bayes' theorem. Let's define the events as follows:

- A: Die landed with a 2 or 3.

- R: Red marble was drawn.

We are interested in finding P(A|R), which is the probability that the die landed with a 2 or 3 given that a red marble was drawn.

Using Bayes' theorem, we have:

P(A|R) = (P(R|A) * P(A)) / P(R)

P(R|A) is the probability of drawing a red marble given that the die landed with a 2 or 3. In box B1, there are 10 red marbles out of 15 total marbles. Therefore, P(R|A) = 10/15.

P(A) is the probability that the die landed with a 2 or 3. There are 2 favorable outcomes (2 or 3) out of 6 possible outcomes when rolling a fair die. Hence, P(A) = 2/6.

P(R) is the probability of drawing a red marble, which can be calculated using the law of total probability. We consider two cases: selecting box B1 and selecting box B2.

- P(R and B1) is the probability of drawing a red marble from box B1. There are 10 red marbles out of 15 total marbles in box B1, and the probability of selecting box B1 is 1/3. Therefore, P(R and B1) = (10/15) * (1/3).

- P(R and B2) is the probability of drawing a red marble from box B2. There are 8 red marbles out of 11 total marbles in box B2, and the probability of selecting box B2 is 2/3. Therefore, P(R and B2) = (8/11) * (2/3).

Thus, we can calculate P(R) as the sum of these probabilities: P(R) = P(R and B1) + P(R and B2).

Finally, we substitute these values into Bayes' theorem to calculate P(A|R), which gives us the probability that the die landed with a 2 or 3, given that a red marble was drawn.

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The formula for calculating confidence interval is: $\overline{X} \pm Z_{\alpha/2}\frac{σ}{\sqrt{n}}$,

where $\overline{X}$ is the sample mean,

$σ$ is the population standard deviation,

$n$ is the sample size, and $Z_{\alpha/2}$ is the critical value of the standard normal distribution at $\alpha/2$ and $(1-\alpha/2)$ levels of significance respectively. To construct the 90% confidence interval for the given data: n = 240p-hat = 0.55The sample mean is equal to p-hat which is 0.55. Therefore, the margin of error is given by;

ME = Z_{α/2} × √{p-hat(1 - p-hat) / n}α = 0.10, thus α/2 = 0.05, so the area to the right of the critical value is equal to 0.05.

Using the standard normal distribution table, the critical value for α/2 = 0.05 is: Z_{α/2} = 1.64

Therefore, the confidence interval is given by; CI = p-hat ± Z_{α/2} × √{p-hat(1 - p-hat) / n}CI = 0.55 ± 1.64 × √{0.55(1 - 0.55) / 240}CI = 0.55 ± 0.077

Therefore, the confidence interval is (0.473, 0.627) (rounded to three decimal places).

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The approximate value of 6.032 + 5.982 + 6.992 using the linear approximation is 121.22.

To find the linear approximation of the function f(x, y, z) = x² + y² + z² at (6, 6, 7), we need to calculate the partial derivatives of f with respect to x, y, and z at the given point. Then we can use these derivatives to form the equation of the tangent plane, which will serve as the linear approximation.

Let's start by calculating the partial derivatives:

∂f/∂x = 2x

∂f/∂y = 2y

∂f/∂z = 2z

Now, we can evaluate the partial derivatives at (6, 6, 7):

∂f/∂x = 2(6) = 12

∂f/∂y = 2(6) = 12

∂f/∂z = 2(7) = 14

The equation of the tangent plane can be written as:

f(x, y, z) ≈ f(a, b, c) + ∂f/∂x(a, b, c)(x - a) + ∂f/∂y(a, b, c)(y - b) + ∂f/∂z(a, b, c)(z - c)

Plugging in the values from the given point (6, 6, 7) and the partial derivatives we calculated:

f(x, y, z) ≈ f(6, 6, 7) + 12(x - 6) + 12(y - 6) + 14(z - 7)

≈ 6² + 6² + 7² + 12(x - 6) + 12(y - 6) + 14(z - 7)

≈ 36 + 36 + 49 + 12(x - 6) + 12(y - 6) + 14(z - 7)

≈ 121 + 12(x - 6) + 12(y - 6) + 14(z - 7)

Now, let's use this linear approximation to approximate the value of f(6.03, 5.98, 6.99):

f(6.03, 5.98, 6.99) ≈ 121 + 12(6.03 - 6) + 12(5.98 - 6) + 14(6.99 - 7)

≈ 121 + 12(0.03) + 12(-0.02) + 14(-0.01)

≈ 121 + 0.36 - 0.24 - 0.14

≈ 121 + 0.22

≈ 121.22

Therefore, the approximate value of 6.032 + 5.982 + 6.992 using the linear approximation is 121.22.

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Answer:

225 x a^4

Step-by-step explanation:

Answer:

a)

\(8(x + 5)\)

b)

\(13y + 10\)

Step-by-step explanation:

Answer:

(a) 1st, 2nd

(b) 4th

Step-by-step explanation:

(a) Option 1: Expanding with the distributive property, we have

\(8(x+5)=8x+8\cdot 5\\~~~~~~~~~~~~=8x+40,\)

which is equivalent.

Option 2: Multiplying the terms gives

\(8\cdot x+8\cdot 5= 8x+40\),

which is equivalent.

Option 3: We don't know what x is, so there is no way to write \(48x\) as \(8x+40\). This is not equivalent.

Option 4: Expanding with the distributive property gives

\(8(5x+1) = 8\cdot 5x+8\cdot1\\~~~~~~~~~~~~~=40x+8,\)

which is not equivalent.

(b) First, we combine like terms in the given expression:

\(12+14y-2-y=12-2+14y-y\\~~~~~~~~~~~~~~~~~~~~~~~=10+(14-1)y\\~~~~~~~~~~~~~~~~~~~~~~~=10+13y.\)

Looking at the given answer choices, only the fourth option is equivalent.

Answer:

7

Step-by-step explanation:

42/6=7

In  quadratic equation  (-11)2 = 121, the solution is actually both x = 11 and x = -11.

What in mathematics is a quadratic equation?

x² = 121. To find x, we need to get rid of the exponent, and to do this, we can take the square root of both sides:

√x² = √121

x = √121

You might believe that x = 11, but keep in mind that x might also be negative because negative numbers can be squared.

In essence, each real number has both a positive and a negative square root.

Because (-11)2 = 121, the solution is actually both x = 11 and x = -11.

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We cannot claim that the newsletter publisher's statement is incorrect. Hence, the conclusion is uncertain.

The newsletter publisher's claim is uncertain after performing a test at the 0.02 level of significance as the testing firm fails to reject the null hypothesis.

In this case, we cannot claim that the publisher's statement is incorrect without additional tests and proof. Here is an explanation of the above statement.

A hypothesis test is conducted to find out whether or not there is sufficient evidence to contradict a hypothesis. In this case, the hypothesis test's null hypothesis claims that the newsletter publisher's statement is correct.

The alternate hypothesis claims that the newsletter publisher's claim is incorrect. As a result, the null hypothesis is represented by \(H_0\):

p = 0.71 (71%) and

the alternate hypothesis is represented by \(H_a\):

p ≠ 0.71 (71%).

Where 'p' denotes the percentage of newsletter readers who own a Rolls Royce.

The test statistic for a sample proportion can be calculated by

z = (p - P) / √(P(1 - P) / n)

Where 'p' denotes the sample proportion,

P denotes the population proportion, and

n denotes the sample size.

A two-tailed test is used because the alternate hypothesis is written as \(H_a\):

p ≠ 0.71 (71%).

At a 0.02 significance level, the test statistic's critical value is ±2.58 (round off) Because the test statistic does not fall in the rejection region, we fail to reject the null hypothesis.

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The area of the rhombus is approximately 112.5 square centimeters.

In a rhombus, all internal angles are equal, so we know that the opposite angles are congruent.

Additionally, the diagonals of a rhombus bisect each other at right angles, forming four congruent right triangles.

Let's denote the length of one diagonal as 15 cm, and the lengths of the sides of the rhombus as a.

Using the Pythagorean theorem, we can find the length of the other diagonal.

Let's label it as d.

In each right triangle, the hypotenuse is the length of a side, which is a, and one leg is half the length of the diagonal, which is 15/2 = 7.5 cm.

Applying the Pythagorean theorem, we have:

a² = (7.5)² + (7.5)²

a² = 56.25 + 56.25

a² = 112.5

a = √112.5

a ≈ 10.61 cm

Thus, the length of each side of the rhombus is approximately 10.61 cm.

Since the diagonals of a rhombus are perpendicular bisectors of each other, the other diagonal (d) is equal to the square root of the sum of the squares of the two sides.

Hence:

d² = a² + a²

d² = 2a²

d = √(2a²)

d = √(2 \(\times\) 10.61²)

d ≈ √(2 \(\times\) 112.5)

d ≈ √225

d ≈ 15 cm

So, the length of the other diagonal is approximately 15 cm.

To find the area of the rhombus, we can use the formula:

Area = (diagonal₁ \(\times\) diagonal₂) / 2

Substituting the values, we get:

Area = (15 \(\times\) 15) / 2

Area = 225 / 2

Area = 112.5 cm²

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Answer:

  (B) one

Step-by-step explanation:

You want to know how many points on the interval [0, 5] the function f(x) = e^(2x) have a slope equal to the average slope.

The instantaneous rate of change of function f(x) is its derivative:

  f'(x) = 2e^(2x)

This is a continuously increasing function (as is f(x)), so in any given interval there will be only one point that has any given slope.

The Mean Value Theorem says there is at least one point in the interval with the same slope as the average slope. The nature of the derivative tells you there is exactly one point with the same slope as the average slope.

The average rate of change on [0, 5] is ...

  AROC = (e^(2·5) -e^(2·0))/(5 -0) = (e^10 -1)/5

The instantaneous rate of change will have that value where ...

  f'(x) = 2e^(2x) = (e^10 -1)/5

  2x = ln((e^10 -1)/10)

  x = ln((e^10 -1)/10)/2 ≈ 3.84868475302

For this value of x, f'(x) = AROC

Answer:

x = 8 or x = -8

Step-by-step explanation:

Answer:

absolute value will always be positive

the answer is x=8

Answer:

3

Step-by-step explanation:

Answer:

AC with endpoints at A(1; -1) and C(5; 3)

While a smaller Mars would have been an interesting geological object to study, it would likely have been a less attractive candidate for extraterrestrial life.

If Mars had turned out to be significantly smaller than its current size, the number of geological features would have been less than the present. This is because geological processes are highly dependent on the size of the planet and the amount of heat energy produced. A smaller Mars would have had less heat energy, meaning less activity in the mantle and crust, and therefore fewer geological features.

The four major geological processes - erosion, tectonics, volcanism, and impact cratering - would have also been affected by a smaller size of Mars. Erosion would have been less extensive due to a smaller atmosphere and less weathering. The tectonic activity would have been reduced as well due to a weaker gravitational pull and less heat energy. The volcanic activity would have also been less intense due to a smaller magma chamber. Impact cratering would have been less frequent as the planet would have been smaller and less likely to be hit by large asteroids or comets.

As for the potential for extraterrestrial life, a smaller Mars would likely be a worse candidate. A smaller Mars would have had less heat energy, meaning it would have had a less stable environment and less opportunity for life to emerge and evolve. Additionally, a smaller Mars would have had less atmosphere, making it more difficult for liquid water to exist, which is a key ingredient for life as we know it.

Thus Overall, while a smaller Mars would have been an interesting geological object to study, it would likely have been a less attractive candidate for extraterrestrial life.

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Answer:

1.625 miles

Step-by-step explanation:

40 miles in 65 minutes means that every 65 minutes, 40 miles is travelled. To find the distance travelled per minute, divide 65 and 40:

65 minutes / 40 miles = 1.625 miles per minute. So every minute, the train travels 1.625 miles.

Hope this helps :)

There are 201376 ways can a group of 5 lucky students be selected to sit in the front of the classroom.

What are combinations?

Combinations are mathematical operations that count the variety of configurations that can be made from a set of objects, where the order of the selection is irrelevant. You can choose any combination of the things in any order.

Permutations and combinations are often mistaken. The chosen components' order is crucial in permutations, though. For instance, whereas permutations treat the arrangements differently, combinations treat the arrangements ab and ba equally (as one arrangement).

Use the combinations formula:

n = 32, r=5

\(^{n}C_{r}=\frac{n!}{(n-r)! r!}\)

\(^{32}C_{5}=\frac{32!}{(32-5)! 5!}\)

       = (32*31*30*29*28*27!)/(5!*27!)

       = (32*31*30*29*28)/ (5*4*3*2*1)

       = 201376

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Answer:

24 kilograms of catfish

Step-by-step explanation:

Take the percentage of catfish as a decimal or fraction and multiply it by the total amount of fish caught. The percent of catfish is 40% which is the same thing as 0.4. Multiply that by the total 60 kg of fish to get 24 kg of catfish.

XY is less than 14,  MR is less than 10.5, if DE || AB, AC = 15, DC = 10, and EC = 8 then BE is equal to 18.75, the sides are not proportional and DE is not parallel to AB.

To find XY, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

Using this theorem, we have:

WZ + ZX > WY

6 + 8 > 9

14 > 9

XY must be less than the sum of WZ and ZX. Therefore, XY is less than 14.

To find MR,

RS + ST > RT

6 + 4 1/2 > 3

10.5 > 3

Since the inequality holds true, we can conclude that MR must be less than the sum of RS and ST. Therefore, MR is less than 10.5.

By the similar triangles property:

EC/DC = AC/BC

Substituting the given values:

8/10 = 15/BC

Cross-multiplying:

8 × BC = 10 × 15

BC = 150/8

BC = 18.75

BC=BE

BE is equal to 18.75.

If DE is parallel to AB, then the ratio of the lengths of the corresponding sides AD and BE should be equal.

Using the given lengths:

AD/BE = 4/3

Ratio does not equal 1, which means the sides are not proportional and DE is not parallel to AB.

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The approximate real solutions is; A. x≈0.20, x≈±2.05.

Using the Rational Root Theorem, we can find the possible rational roots of the equation, that are the factors of the constant term, 1, divided by the factors of the leading coefficient, 1.

Possible rational roots are: ±1, ±1/5

Now these values, we find that x=1/5 is a root of the equation.

Using synthetic division, we have to factor the equation:

\((x-1/5)(x^2+1/5x-5)=0\)

Solving for the remaining quadratic equation:

\(x^2+1/5x-5=0\)

To solve the equation \(x^2+1/5x-5=0\), we can use the quadratic formula:

x = [-b ± √(b² - 4ac)] / 2a

where a = 1, b = 1/5, and c = -5. Substituting these values into the formula, we get:

x = [-(1/5) ± √((1/5)²  - 4(1)(-5))] / 2(1)

Simplifying the expression under the square root:

x = [-(1/5) ± √(1/25 + 20)] / 2

x = [-(1/5) ± √(521/25)] / 2

x = (-1 ± √521) / 10

x = (-1 + √521) / 10 and x = (-1 - √521) / 10

Using the quadratic formula,

x≈2.049, x≈-2.449

Therefore, the approximate real solutions are:

A. x≈0.20, x≈2.05, x≈-2.45

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