Ok well, maybe some help with the question instead of deleting it? That be great y'know. Question in attachments

The rule that the defines the sum Sn is \(S_n =\frac{9 * (1 - r^n )}{0.6}\)

The formula of the sequence is given as:

an = 9(0.4)^n

The above means that:

The sum Sn is then represented as:

\(S_n =\frac{a(1 - r^n )}{1 - r}\)

So, we have:

\(S_n =\frac{9 * (1 - r^n )}{1 - 0.4}\)

Evaluate the difference and divide

\(S_n =\frac{9 * (1 - r^n )}{0.6}\)

Hence, the rule that the defines the sum Sn is \(S_n =\frac{9 * (1 - r^n )}{0.6}\)

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Answer: He bought 20 ice cream bars and 14 popsicle

Step-by-step explanation:

To solve this I used the elimination method, you could use substitution as well

Here are our two equations

x+y=34 Because the total number of ice creams bought must be given to 34 children and no more

2x+5y=128 because that is the cost for each ice cream and the amount he spent

For the elimination method we have to cancel out one of the variables, I decided to cancel out the x, so I multiplied the top equation by -2. So i got -2x-2y=-68

2x+5y=128 Then we get

3y=60 so

y=20

Now we can go back to the first equation and plug in y.

x+20=34

  -20  -20

x=14

So he bought 14 popsicles and 20 ice cream bars.

i. The congruence 24 ≡ 39 (mod 5) simplifies to 4 ≡ 4 (mod 5) using division.

ii. The prime factorization of 765 is 3 * 3 * 5 * 17, and the prime factorization of 714 is 2 * 3 * 7 * 17.

i. To simplify the congruence 24 ≡ 39 (mod 5) using division, we can divide both sides of the congruence by 5. Dividing 24 by 5 gives us a quotient of 4 and a remainder of 4. Dividing 39 by 5 also gives us a quotient of 7 and a remainder of 4. Therefore, we have 4 ≡ 4 (mod 5), which means that 24 and 39 have the same remainder when divided by 5.

ii. To find the prime factorization of an integer, we express it as a product of prime numbers. For 765, we start by dividing it by the smallest prime number, which is 2. Since 765 is not divisible by 2, we move on to the next prime number, which is 3. Dividing 765 by 3 gives us a quotient of 255. Continuing this process, we divide 255 by 3 again to get 85, and then divide 85 by 5 to get 17. Finally, since 17 is a prime number, we have the prime factorization 765 = 3 * 3 * 5 * 17.

Similarly, for 714, we divide it by 2 to get 357, which is then divided by 3 to obtain 119. Continuing, we divide 119 by 7 to get 17. Again, 17 is a prime number, so the prime factorization of 714 is 2 * 3 * 7 * 17.

b) Using the function f(x) = (3x + 1) mod 26, we can encrypt the message "GIRL" by converting each letter into a numerical value. In the English alphabet, G is the 7th letter, I is the 9th letter, R is the 18th letter, and L is the 12th letter. Substituting these values into the function, we get f(7) = (3 * 7 + 1) mod 26, f(9) = (3 * 9 + 1) mod 26, f(18) = (3 * 18 + 1) mod 26, and f(12) = (3 * 12 + 1) mod 26.

Evaluating these expressions, we find that f(7) = 22, f(9) = 28 (which is equivalent to 2 mod 26), f(18) = 55 (which is equivalent to 3 mod 26), and f(12) = 37 (which is equivalent to 11 mod 26). Therefore, the encrypted message for "GIRL" using the given function is "VBDK".

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Answer:

linear

Step-by-step explanation:

yw

Answer:

Top right corner

Step-by-step explanation:

72 millimeters is equal to 2.83 inches.

Length is a measure of the distance between two points. There are different units of measurement for length, one of which is millimeters (mm) and another is inches (in). In order to convert from one unit to another, we use a conversion factor.

Here's how you convert 72 millimeters to inches:

1 inch = 25.4 millimeters

So, to convert 72 millimeters to inches, we divide by the conversion factor:

72 mm / 25.4 mm/in = 2.83 in

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The probability of being at least seven minutes late given that it is already 3.5 minutes late is approximately 0.368 (or 36.8%).

What is mean?

In statistics, the mean is a measure of central tendency which represents the average of a set of numerical data. It is obtained by adding up all the values in the data set and then dividing the sum by the total number of values.

We know that the exponential distribution has the following probability density function:

\($f(x) =\)

\(\frac{1}{\mu} e^{-x/\mu} & x \geq 0 \\)

\(0 & x < 0 \\)

where \($\mu$\) is the mean of the distribution.

We are given that \($\mu = 3.5$\) minutes. Let \($X$\) be the time it takes to be late. Then \($X$\) follows an exponential distribution with mean \($\mu = 3.5$\) minutes.

We want to find \($P(X \geq 7 \mid X \geq 3.5)$\). By the definition of conditional probability, we have:

\($P(X \geq 7 \mid X \geq 3.5) = \dfrac{P(X \geq 7 \text{ and } X \geq 3.5)}{P(X \geq 3.5)}$\)

\($= \dfrac{P(X \geq 7)}{P(X \geq 3.5)}$\)

\($= \dfrac{\int_7^\infty \frac{1}{3.5} e^{-x/3.5} dx}{\int_{3.5}^\infty \frac{1}{3.5} e^{-x/3.5} dx}$\)

\($= \dfrac{e^{-2}}{e^{-1}}$\)

\($= e^{-1}$\)

Therefore, the probability of being at least seven minutes late given that it is already 3.5 minutes late is approximately 0.368 (or 36.8%).

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The transitivity of divisibility theorem says that for all integers a, b, and c, if a divides b and b divides c, then a divides c. In other words, if a is a factor of b and b is a factor of c, then a is also a factor of c.

This theorem can be written as follows: If a | b and b | c, then a | c. For example, if a = 2, b = 6, and c = 12, we know that 2 | 6 and 6 | 12, so by the transitivity of divisibility theorem, we can conclude that 2 | 12.

The transitivity of divisibility is an important property of integers and is often used in number theory and other mathematical areas. It allows us to make inferences about the factors of numbers and the properties of divisibility, and is a useful tool in proofs involving divisibility and prime numbers.

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Answer:

50; 25; 105

Step-by-step explanation:

Sum of the angles of triange is 180, so we have 2x + x + 2*2x + 5 = 180 (x is number of degrees of second angle), if I understood word 'twice' correctly.

Next, let me solve this:

2x + x + 4x + 5 = 180

7x + 5 = 180

7x = 175

x = 25

So, second angle is 25 degrees, first is 25*2=50 degrees and third is 50*2+5=105 degrees.

Hope that this was helpful.

The speaking turn, the adjacency pair, and the sequential implicativeness are the three fundamental components of conversation that conversation analysts identify.

The three essential elements of conversation that conversation analysts identify are the speaking turn, the adjacency pair, and the sequential implicativeness.

Mary: Hello! Mary is my name.

Andrew: Hey Mary I'm Andrew, and how are you? Nice to meet you.

Mary: Thank you; I just arrived from Memphis; I'm OK. , From where do you hail?

Andrew: You are a Memphis native? I'm a Cleveland native; is this also your first day of classes?

Mary: Indeed! I recently met someone from Cleveland at the front desk, and I'm a freshman.

Andrew: Really...? I don't know many Clevelanders who come here.

Clarissa is there, Mary, there she is! Let me introduce you to my pal, please come over!

Clarissa was undoubtedly a student of mine in high school, Andrew

Oh, Clarissa Hello Andrew Hey Mary Are you prepared for the semester to begin?

Mary: Obviously!

Andrew: I can't even find my dorm room, so not really.

The complete question is:

Write a conversation between two students who are meeting for the first time. Have them greet each other, ask each other how they are doing, ask each other where they are from, introduce a third person and say goodbye.

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Step-by-step explanation:

you can write it as

the sum of of thirty six(36) and four(4) is divided by Ten(10)

Answer:

They are difficult to diagnose through route medical tests. A careful analysis of signs and symptoms is far more productive in eliciting the diagnoses verses blood tests. At least through suck signs and symptoms the presumptive diagnosis of parasitic infestations can be made. It all just depends though.

Pls mark brainliest I would really appreciate it

Answer: They are difficult to diagnose through route medical tests. A careful analysis of signs and symptoms is far more productive in eliciting the diagnoses verses blood tests

a) We have shown that if the matrix representation of a vector T with respect to a basis B is the zero matrix, then the vector T itself must be the zero vector.

b) We have proven that the dimension of a subspace U, whose basis consists of k standard basis vectors, is equal to k.

(a) Let's start by proving that if [T]₆ = ŌF, then T = Ō.

Since [T]₆ = ŌF, it means that the matrix representation of T with respect to the basis B is the zero matrix. Recall that the matrix representation of a vector T with respect to a basis B is obtained by expressing T as a linear combination of the basis vectors B and collecting the coefficients in a matrix.

Now, suppose that T is not the zero vector. That means T can be expressed as a linear combination of the basis vectors B with at least one non-zero coefficient. Let's say T = c₁v₁ + c₂v₂ + ... + cₙvₙ, where at least one of the coefficients cᵢ is non-zero.

We can then represent T as a column vector in terms of the basis B: [T]₆ = [c₁, c₂, ..., cₙ]. Now, if [T]₆ = ŌF, it implies that [c₁, c₂, ..., cₙ] = [0, 0, ..., 0]. However, this contradicts the assumption that at least one of the coefficients cᵢ is non-zero.

Therefore, our initial assumption that T is not the zero vector must be false, and hence T = Ō.

(b) Now let's move on to the second part of the question. We are given a subspace W of V with basis C = {w₁, w₂, ..., wₖ}, and we need to prove that the dimension of the subspace U = {[u₁, u₂, ..., uₖ] : uᵢ ∈ F} is equal to k.

First, let's understand what U represents. U is the set of all k-dimensional column vectors over the field F. In other words, each element of U is a vector with k entries, where each entry belongs to the field F.

Since the basis of W is C = {w₁, w₂, ..., wₖ}, any vector w in W can be expressed as a linear combination of the basis vectors: w = a₁w₁ + a₂w₂ + ... + aₖwₖ, where a₁, a₂, ..., aₖ are elements of the field F.

Now, let's consider an arbitrary vector u in U: u = [u₁, u₂, ..., uₖ], where each uᵢ belongs to F. We can express this vector u as a linear combination of the basis vectors of U, which are the standard basis vectors: e₁ = [1, 0, ..., 0], e₂ = [0, 1, ..., 0], ..., eₖ = [0, 0, ..., 1].

Therefore, u = u₁e₁ + u₂e₂ + ... + uₖeₖ. We can see that u can be expressed as a linear combination of the k basis vectors of U with coefficients u₁, u₂, ..., uₖ. Hence, the dimension of U is k.

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The total possible combination of ordered pairs from the element of the given set is 9

To find the ordered pairs of the equation, we simply have to find the total possible combinations from the element of the set.

The element of set given is x ∈ {-1, 0, 1}

The possible combinations of x ∈ {-1, 0, 1} are;

(-1, -1)

(-1, 0)

(0, -1)

(1, 1)

(-1, 1)

(1, -1)

(0, 1)

(1, 0)

(0, 0)

We have 9 possible ordered pairs

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The snow depth on the summit of Mt. Washington is normally distributed with a mean of 78.1 inches and a standard deviation of 10.4 inches. We need to find the probability that the snow depth is between 60 inches and 85 inches. We can use the z-score formula to find the probability.

The formula is given below; z = (x - μ) / σ where μ is the mean, σ is the standard deviation, x is the given value, and z is the z-score. For the given problem;μ = 78.1 inchesσ = 10.4 inchesx1 = 60 inchesx2 = 85 inchesz1 = (60 - 78.1) / 10.4 = -1.74z2 = (85 - 78.1) / 10.4 = 0.66.

Now, we need to find the area between these z-scores. We can use the standard normal distribution table or calculator to find the area.

The area between z1 and z2 is given by; P(z1 < z < z2) = P(z < z2) - P(z < z1)By using the standard normal distribution table, we can find the probabilities as; P(z < -1.74) = 0.0409 (from table)P(z < 0.66) = 0.7454 (from table)Substitute these values in the above formula;

P(-1.74 < z < 0.66) = 0.7454 - 0.0409 = 0.7045.

Therefore, the probability that the snow depth is between 60 inches and 85 inches is 0.7045.

We can also draw a supporting Normal Distribution curve of the given problem.

The Normal Distribution curve is symmetric and bell-shaped. The curve of the given problem is centered at 78.1 inches with a standard deviation of 10.4 inches. We can use this information to draw a Normal Distribution curve.

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The equation of the blue line will be

y = 4x -3

The equation of the line that passes through the points (1, 1) and (2, 5) is y = 4x - 3.

We have,

To find the equation of the line that passes through the coordinates (1, 1) and (2, 5), we can use the point-slope form of the equation of a line.

The point-slope form of the equation is:

y - y1 = m(x - x1)

Where (x1, y1) represents one of the given points on the line, and m represents the slope of the line.

First, let's calculate the slope (m) using the given coordinates:

m = (y2 - y1) / (x2 - x1) = (5 - 1) / (2 - 1) = 4 / 1 = 4

Now, we can choose either of the given points and substitute its coordinates into the point-slope form. Let's use (1, 1):

y - 1 = 4(x - 1)

Simplifying the equation:

y - 1 = 4x - 4

y = 4x - 3

Therefore,

The equation of the line that passes through the points (1, 1) and (2, 5) is y = 4x - 3.

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Answer:

If the recipe calls for 5/8 cup of butter, the ratio would be 3:5 (blueberries to butter), if the recipe was enlarged you can use the same method and find out the new ratio

Answer: Quarter or 25%

Step-by-step explanation:

1/4 = 25%/ 100%

Or quarter

Answer:

1/4 is also called:

One Fourth

One quarter

One percent of Four

SOLUTION

To get the fraction of Susie used, we simply change the decimal 0.75 into fraction.

This becomes

After moving the decimal point and changing to fraction, divide through by a common factor. And the common factor is 5.

Therefore, the answer is

Answer:

horizontal asympote

Y:-4

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

The production quantity of 2.6 million cards maximizes the company's expected profit.

To determine the production quantity that maximizes the company's expected profit, we need to consider the cost of printing, the revenue from selling the cards, and the value of leftover cards.

Let's calculate the expected profit for each production quantity:

Production quantity: 2.4 million cards

Cost of printing: $2 million + 0.7 * 2.4 million = $3.68 million

Expected revenue: 2.4 million cards * $4 per card = $9.6 million

Expected value of leftover cards: (1 - cumulative probability of demand <= 2.4 million) * 2.4 million cards * $0.05

Expected profit = Expected revenue - Cost of printing - Expected value of leftover cards

Repeat the same calculations for production quantities of 2.6, 2.8, 3, and 3.2 million cards.

After calculating the expected profit for each production quantity, we find that the production quantity of 2.6 million cards yields the highest expected profit. Therefore, producing 2.6 million Valentine cards maximizes the company's expected profit.

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The exponential equation is \(y=ab^x\). Let's look at some properties of this equation.

'b' must be greater than 0 and not equal to 1. b>0, b1.

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The exponential equation is y = \(ab^{x}\) . Let's look at some properties of this equation.

'b' must be greater than 0 and not equal to 1. b>0, b1.

The formula for exponential regression is y = \(ab^{x}\) . This refers to the process of arriving at the best exponential curve equation for your dataset. This regression is very similar to linear regression and tries to find the best (straight line) line equation for a data set.

Exponential regression refers to the process of obtaining the best exponential curve equation for a data set.

A model that explains the process of doubling growth.

The exponential equation is y = \(ab^{x}\)

Exponential functions are commonly used in life sciences and are used to represent the specific quantity that you want to model. B. Population size modeled over time. Plots of experimental data are usually plotted with time on the x-axis and quantity on the y-axis.

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Answer:

$4579.90

Step-by-step explanation:

:)

Answer:

Step-by-step explanation:

let distance=d

d²=4²+(2+4)²=16+36=52=4×13

d=2√13

With a greater mean value , we can conclude that the sixth period class test was better than the second period .

Second period class:

Mean = (55+70+6*75+6*80+2*85+3*90+95)/20

Mean = 1590/20 = 79.5

Sixth period class:

Mean = (65+3*75+5*80+6*85+3*90+2*95)/20

Mean = 1660/20 = 83

Therefore, From the mean values , we can infer that students performed better in test for the sixth period class than the second .

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Answer:

\(\huge \boxed{\mathrm{804}}\)

Step-by-step explanation:

\(\sf The \ initial \ population \ of \ the \ town \ was \ 568.\)

\(\sf 236 \ migrated \ to \ the \ town.\)

\(568+236\)

\(=804\)

\(\sf The \ present \ population \ of \ the \ town \ is \ 804.\)

Answer:

\(\huge\boxed{ 804}\)

Step-by-step explanation:

Prior Population = 568

Added People = 236

Current Population = 568 + 236

=> 804

If 1200 square centimeters of material is available to make a box with a square base and an open top,

The largest possible volume of the box is V = 4000cm^3.

We have 1200 cm^2 worth of material. This represents the surface area of a box with a square base and an open top.

the dimensions of the box.

Square base implies the length and width are the same.

Let x = length/width.

The box has a height as well.

Let h = height

the surface area ; S.

S = (area of base) + (area of 4 walls)

The area of the base is x^2

The area of one of the walls is length times height, or xh. Since there are 4 of them, it would be 4 times xh, or 4xh.

S = x^2 + 4xh

And we know that S = 1200cm^2, so

x^2 + 4xh = 1200

Let's solve for h.

4xh = 1200 - x^2

h = (1200 - x^2) / (4x)

we require the volume formula.

V = (length) x (width) x (height)

And we know all of these.

V = (x)(x)(h)

V = (x^2) h

putting h = (1200 - x^2) / (4x) in the formula

V = (x^2) ( 1200 - x^2)/(4x)

We get a cancellation,

V = x(1200 - x^2)/4

V = (1/4)x (1200 - x^2)

This will be our volume function, V(x).

V(x) = (1/4)(x)(1200 - x^2)

To maximize V(x), we must first take the derivative and then make it 0. Using the product rule (and ignoring the constant 1/4), we have

V'(x) = (1/4) [ (1200 - x^2) + (x)(-2x) ]

Simplify,

V'(x) = (1/4) [ 1200 - x^2 - 2x^2 ]

V'(x) = (1/4) [ 1200 - 3x^2 ]

V'(x) = (1/4) [ 3(400 - x^2) ]

V'(x) = (3/4) [ 400 - x^2 ]

To maximize, make V'(x) = 0, and solve for x.

0 = (3/4) [ 400 - x^2 ]

0 = 400 - x^2

x^2 = 400

x = +/- 20

Therefore,

x = { 20, -20 }

However, since x represents a dimension, it can never be negative, and we must discard the negative solution. That means

x = 20.

This tells us that the maximum volume occurs when x = 20. However, the question is asking WHAT the largest volume of the box is. Solving this is as simple as plugging x = 20 into our volume function, V(x).

V(x) = (1/4)(x)(1200 - x^2)

Therefore,

V(20) = (1/4) (20) (1200 - 20^2)

V(20) = (1/4) (20) (1200 - 400)

V(20) = (1/4) (20) (800)

V(20) = (20/4)(800)

V(20) = 5(800)

V = 4000cm^3

Hence the answer is, the largest possible volume of the box is V = 4000cm^3.

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