Oil dropping down the inner side of a tube confirms amine. This is what analysis ?

The thermal efficiency of the cycle is approximately 62.2%.

(a) The Brayton cycle with the given parameters can be drawn in a T-S diagram as follows:

The cycle consists of two adiabatic processes and two isobaric processes. The gas enters the compressor at state 1 and is compressed to state 2. Then, it enters the combustion chamber and is heated at constant pressure to state 3. In the turbine, it expands adiabatically to state 4 and finally, it is cooled at constant pressure to state 1.

(b) To find the exit temperatures at the exits of the compressors and turbines, we can use the isentropic efficiencies of the compressor and turbine. The isentropic efficiency is the ratio of the actual work done to the work done in an isentropic process between the same inlet and outlet pressures.

The exit temperature of the compressor, T2s can be found using the following equation:

T2s = T1*(P2/P1)^[(k-1)/k*eta_c]

where T1=300K, P2/P1=8, k=1.4 (for air), eta_c=0.85 (compressor efficiency)

T2s = 300*(8)^[(1.4-1)/(1.4*0.85)] = 522.3 K

The actual exit temperature of the compressor, T2 can be found using the following equation:

T2 = T1 + (T2s - T1)/eta_c

T2 = 300 + (522.3 - 300)/0.85 = 579.8 K

Similarly, the exit temperature of the turbine, T4s can be found using the following equation:

T4s = T3*(P4/P3)^[(k-1)/k*eta_t]

where T3=1300K, P4/P3=1/8 (since the pressure ratio across the turbine is the inverse of the pressure ratio across the compressor), k=1.4, eta_t=0.9 (turbine efficiency)

T4s = 1300*(1/8)^[(1.4-1)/(1.4*0.9)] = 634.5 K

The actual exit temperature of the turbine, T4 can be found using the following equation:

T4 = T3 - eta_t*(T3 - T4s)

T4 = 1300 - 0.9*(1300 - 634.5) = 1096.6 K

(c) The thermal efficiency of the cycle can be found using the following equation:

eta_th = (h3 - h2)/(h4 - h1)

where h is the specific enthalpy of the gas at the corresponding state.

The specific enthalpy at state 1 can be taken as zero. Using the constant specific heat assumption, we can calculate the specific enthalpy at states 2, 3 and 4 as:

h2 = cpT2 = 1.005579.8 = 582.6 kJ/kg

h3 = cpT3 = 1.0051300 = 1306.5 kJ/kg

h4 = cpT4 = 1.0051096.6 = 1101.4 kJ/kg

Substituting these values in the above equation, we get:

eta_th = (1306.5 - 582.6)/(1101.4 - 0) = 0.622

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The wind (W) is blowing at 35.0km/h, south. The northern component of the airplane’s velocity relative to the ground is

  (v AP,G ) y =(v AP,W ) y +(v W,G ) y =630km/h−35.0km/h    =595km/h

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Velocity is the rate of change of displacement. Acceleration is the rate of change of velocity. Velocity is a vector quantity because it consists of both magnitude and direction. Acceleration is also a vector quantity as it is just the rate of change of velocity.

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Answer:

Air resistance is pushing up on the parachute and force of gravity is pulling down so she slows down. This increases friction which slows free fall down. So when the skydiver reaches terminal velocity, the force of gravity is balance by air resistance. But when the forces are balance, there is no acceleration.

Lamarck's theory of evolution, also known as Lamarckism, proposed two main ideas. Firstly, the theory of use and disuse suggests that organs or traits that are used more frequently become stronger and more developed, while those that are not used gradually deteriorate over generations. Secondly, the theory of inheritance of acquired characteristics states that an organism can pass on traits acquired during its lifetime to its offspring.

Under Lamarck's theory, an organism might evolve by developing or strengthening certain traits through use and passing them on to the next generation. For example, if a giraffe stretches its neck to reach leaves high in the trees, its offspring would inherit a longer neck. This gradual elongation of the neck would continue over generations.

In contrast, under Darwin's theory of natural selection, an organism might evolve through the process of adaptation to its environment. For instance, consider a bird population with varying beak sizes. If the available food source consists of small seeds, individuals with smaller beaks are more likely to survive and reproduce, passing on their genes for smaller beaks. Over time, the average beak size in the population would decrease due to the selective advantage of smaller beaks in obtaining food.

In summary, Lamarck's theory proposed that acquired traits can be inherited, leading to gradual changes in an organism's characteristics. Darwin's theory, on the other hand, emphasized the role of natural selection in the adaptation of organisms to their environment, resulting in the accumulation of advantageous traits over generations.

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The angle of incidence of the light on the screen is 17.0°. the smallest positive angle, relative to the original direction of the laser beam, at which the intensity of the light is 1/10 the maximum intensity on the screen is approximately 3.37°.  

The smallest positive angle, relative to the original direction of the laser beam, at which the intensity of the light is 1/10 the maximum intensity on the screen can be found using the formula:

I = I_max * (1 - (d/λ)\(^2)^2\)

where I is the intensity of the light on the screen, I_max is the maximum intensity of the light on the screen, d is the distance between the slits, and λ is the wavelength of the light.

Given that the first completely dark fringes occur at ±17.0∘, we can use the tangent function to find the angle of incidence of the light on the screen. The angle of incidence is related to the angle of the slits by the equation:

θ = sin\(^-1\)(1/cosθ)

where θ is the angle of incidence, θ_slits is the angle of the slits, and cosθ is the cosine of the angle of incidence.

Using the given value of d and the wavelength of the light, we can find the angle of incidence using the equation:

θ = sin\(^-1\)(1/cos(17.0° + θ_slits))

Substituting the given value of θ_slits, we get:

θ = sin\(^-1\)(1/cos(17.0°))

Solving for θ, we get:

θ = 17.0°

Substituting this value of θ in the equation for the angle of incidence, we get:

θ = sin\(^-1\)(1/cos(17.0° + θ_slits))

= sin^-1\(^-1\)(1/cos(17.0°))

= 17.0°

Therefore, the angle of incidence of the light on the screen is 17.0°.

To find the distance between the slits, we need to know the distance between the screen and the slits. From the problem statement, we know that the first completely dark fringes occur at ±17.0∘, so the distance between the screen and the slits can be found using the equation:

d = λ * tan(17.0°)

Substituting the given value of λ, we get:

d = 1.81 * tan(17.0°)

= 1.81 * 0.50955

= 0.93965 ft

Therefore, the distance between the slits is 0.93965 ft.

Using the formula for the intensity of the light on the screen, we can now find the smallest positive angle at which the intensity of the light is 1/10 the maximum intensity:

I_max = (1 - (0.1702\()^2)^2\) = 0.000395

I = I_max * (1 - (0.93965/1.81\()^2)^2\) = 0.0000035

The smallest positive angle at which the intensity of the light is 1/10 the maximum intensity is:

θ = tan\(^-1\)(1/0.0000035) ≈ 3.37°

Therefore, the smallest positive angle, relative to the original direction of the laser beam, at which the intensity of the light is 1/10 the maximum intensity on the screen is approximately 3.37°.  

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Answer:

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).

Explanation:

I hope this helps.

Answer: gravity is one major force that creates tides

Explanation:

in 1687, sir Isaac newton explained that ocean tides result from the gravitational attraction of the sun and the moon on the oceans of the earth

Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

The joining of tail of the first vector with the head of the second vector represents the resultant vector whereas the direction of the resultant vector is from the tail of the first vector towards the head of the second.

So we can conclude that Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

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Answer:

\(\huge\boxed{\sf V_i=60 \ m/s}\)

Explanation:

Final speed = \(V_f\) = 40 m/s

Time = t = 5 s

Acceleration = a = -4 m/s²

Initial velocity = \(V_i\) = ?

\(\displaystyle a = \frac{V_f-V_i}{t}\)

Put the givens in the above formula

\(\displaystyle -4=\frac{40 - V_i}{5} \\\\Multiply \ -5 \ to \ both \ sides\\\\-4 \times 5 = 40 - V_i\\\\-20 =40-V_i\\\\Subtract \ 40 \ to \ both \ sides\\\\-20-40=-V_i\\\\-60\ m/s=-V_i\\\\60 \ m/s = V_i\\\\V_i=60 \ m/s\\\\\rule[225]{225}{2}\)

A lightbulb need 300 J to stay on for 5 Seconds. How much power was needed to keep the lightbulb on for this amount of time?

We know that,

\( \: { \boxed{ \sf{Power = \dfrac{Work}{time}}}}\)

Where,

\( \longrightarrow \sf \dfrac{300}{5} \\ \\ \longrightarrow \sf60 \: watts \\ \\ \)

Therefore, 60 watts power is needed to keep the lightbulb on.

To ensure maximum reflectance of normally incident 530 nm wavelength light in a soap bubble with an index of refraction of 1.33, the minimum thickness of the bubble can be calculated using the formula for the thickness of a thin film that exhibits maximum reflectance:

t = (m + 0.5)λ / (2 * n)

Where:
t = thickness of the film
m = an integer (0, 1, 2, ...)
λ = wavelength of the incident light (530 nm)
n = refractive index of the film (1.33)

Plugging in the values, we get:

t = (m + 0.5) * 530 nm / (2 * 1.33)

To find the minimum thickness that ensures maximum reflectance, we can use the smallest value of m, which is 0. Thus, the minimum thickness is:

t = (0.5) * 530 nm / (2 * 1.33) = 99.62 nm

Therefore, a soap bubble with a minimum thickness of 99.62 nm will ensure maximum reflectance of normally incident 530 nm wavelength light.


1. Recall that maximum reflectance occurs when the optical path difference between the reflected rays is equal to an odd multiple of half the wavelength. This can be represented as:
  (2 * thickness * index of refraction) = (2n + 1) * (wavelength / 2)

2. For minimum thickness, we will use n = 0:
  (2 * thickness * 1.33) = (2(0) + 1) * (530 nm / 2)

3. Solve for thickness:
  thickness = (1 * 530 nm) / (2 * 1.33)

4. Calculate the value:
  thickness ≈ 199.25 nm

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Answer:

The last option, 20 N and 2.04 kg

Explanation:

work = (force)(distance)

work = 120 joules

distance: 6 m

rearrange to find force:

120=(6)F

F= 120/6 = 20 Newtons.

Assuming its lifted from Earth's surface, the force of gravity will be 9.81 m/s^2. Let's find mass:

F=mg

m=F/g

m=(20)/(9.81)= 2.038 kg

The recoil velocity of the soda bottle is -10 m/s

To find the recoil velocity of the soda bottle, we'll need to use the conservation of momentum principle. The initial momentum of the system is zero since both the soda bottle and rubber stopper are initially at rest. The equation for conservation of momentum is:

m1v1 + m2v2 = 0

Where m1 and v1 are the mass and velocity of the soda bottle, and m2 and v2 are the mass and velocity of the rubber stopper. We know the masses and the velocity of the rubber stopper, so we can plug in those values:

(0.1 kg) * v1 + (0.01 kg) * (100 m/s) = 0

Now, solve for v1 (the recoil velocity of the soda bottle):

0.1 kg * v1 = -1 kg*m/s
v1 = -1 kg*m/s / 0.1 kg
v1 = -10 m/s

The recoil velocity of the soda bottle is -10 m/s, with the negative sign indicating that it moves in the opposite direction to the rubber stopper.

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Answer:

yes

Explanation:

Answer and Explanation: Comets are frozen extras from the development of the nearby planetary group made out of residue, rock and frosts. They range from a couple of miles to many miles wide, however as they circle nearer to the sun, they heat up and regurgitate gases and residue into a shining head that can be bigger than a planet. This material structures a tail that extends a huge number of miles.

Answer:

D. all of the above

Explanation:

took the quiz

hope this helps :)

Answer:

The trees would remove more carbon from the atmosphere.

Explanation:

I just completed the test, and got a 100%.

The electric potential at 70 cm to the right of the left charge is 7.125 x \(10^3 V.\)

To calculate the electric potential at a point due to two point charges, we need to use the following formula:

V = kq1 / r1 + kq2 / r2

where V is the electric potential, k is Coulomb's constant (\(9 x 10^9 N m^2 / C^2\)), q1 and q2 are the magnitudes of the charges, r1 and r2 are the distances between the point and the charges.

In this case, the left charge has a magnitude of 3 micro-c and the right charge has a magnitude of 7 micro-c. The distance between the left charge and the point of interest (70 cm to the right of the left charge) is 120 cm, and the distance between the right charge and the point of interest is 50 cm.

So, plugging in the values, we get:

V = (9 x \(10^9\)N \(m^2\) / \(C^2\)) x (3 x \(10^-6\) C) / 1.2 + (9 x \(10^9\) N \(m^2\) / \(C^2\)) x (7 x \(10^-6\) C) / 0.5

Simplifying this expression gives:

V = 7.125 x\(10^3\) V

Therefore, the electric potential at 70 cm to the right of the left charge is 7.125 x \(10^3 V.\)

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Answer: a fuse wire is a wire of high resistance and low melting point.

e = W/Q(h)

e = 400/1,200 = 0.3333

Answer: 33%

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Answer:

The height balls rise above the collision point, is approximately 7.37 meters

Explanation:

The given parameters just before the collision are;

The mass, m₁ and velocity, v₁ of the ball moving upward are;

m₁ = 3.0 kg, v₁ = 22 m/s

The mass, m₂ and velocity, v₂ of the ball moving downward are;

m₂ = 1.3 kg, v₂ = -11 m/s (downward motion)

The type of collision = Inelastic collision

We note that the momentum is conserved for inelastic collision

Let, \(v_f\), represent the final velocity of the balls after collision, we have;

∴ Total initial momentum = Total final momentum

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·\(v_f\)

Therefore, we get;

m₁·v₁ + m₂·v₂ = 3.0 kg × 22 m/s + 1.3 kg × (-11) m/s = 51.7 kg·m/s

(m₁ + m₂)·\(v_f\) = (3.0 kg + 1.3 kg) ×

∴ 51.7 kg·m/s = 4.3 kg × \(v_f\)

\(v_f\) = (51.7 kg·m/s)/4.3 kg ≈ 12.023 m/s

The final velocity, \(v_f\) ≈ 12.023 m/s

The maximum height, h, the combined balls will rise from the point of collision, moving upward at a velocity of \(v_f\) ≈ 12.023 m/s, is given from the kinetic equation of motion, v² = u² - 2·g·h, as found follows

At maximum height, we have;

\(h_{max} = \dfrac{v_f^2}{2 \cdot g }\)

Therefore;

\(h_{max} \approx \dfrac{12.023^2}{2 \times 9.81 } \approx 7.37\)

The height the combined two balls of putty rise above the collision point, \(h_{max}\) ≈ 7.37 m.

Features of a chemistry Lab goggles-

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The final speeds of the spheres are 3.47 m/s and 3.08 m/s.

We can use conservation of momentum to solve this problem since there are no external forces acting on the system.

The initial momentum of the system is:

p_initial = m₁ * v₁ + m₂ * v₂

where m₁ and m₂ are the masses of the spheres, and v₁ and v₂ are their initial velocities (4.00 m/s and 0 m/s, respectively).

After the collision, the momentum of the system is:

p_final = m₁ * v1' + m₂ * v₂'

where v₁' and v₂' are the final velocities of the spheres. We also know that the angle between the first sphere's final path and its initial path is 60 degrees, which means that the angle between the two spheres after the collision is 150 degrees (90 + 60).

Using conservation of momentum, we can set the initial and final momenta equal to each other:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' + m₂ * v₂'

We can also break down the final velocities into their x and y components using trigonometry. Let's define the angle between the first sphere's final path and the x-axis as theta. Now we can use conservation of momentum to solve for the final velocities:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' * cos(theta) + m₂ * v₂' * cos(150 degrees)

0 = m₁ * v₁' * sin(theta) + m₂ * v₂' * sin(150 degrees)

Solving the first equation for v₂', we get:

v₂' = (m₁ * v₁ + m₂ * v₂ - m₁ * v₁' * cos(theta)) / (m₂ * cos(150 degrees))

Substituting this expression into the second equation and solving for v₁', we get:

v₁' = (m₂ * sin(150 degrees) * v₁ + m₂ * sin(150 degrees) * v₂ + m₁ * sin(theta) * v₁' - m₁ * sin(theta) * m₂ * v₁ * cos(theta) / cos(150 degrees)) / (m₁ * sin(theta))

Plugging in the given values and solving, we get:

v₁' = 3.47 m/s

v₂' = 3.08 m/s

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660 newtons

830 newtons

no

additional force would be 350 newtons

In materials such as metals the outer most electrons are loosely bound and therefore their movement is chaotic, this allows for the transportation of energy in form of electricity therefore, this materials are good conductors. The statement is true.

Answer:

In this experiment, students use their own exhaled breath to explore the reaction between carbon dioxide and water. They observe the formation of a weak acid via the colour change of an acid–base indicator

Answer:

sequence

Explanation:

sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)

To determine the strength of the dipole created by the redistributed charge on the conducting spherical shell, we can consider the concept of electric dipole moment.

The electric dipole moment (p) is defined as the product of the magnitude of either charge (q) in the dipole and the separation distance (d) between them:

p = q * d

In this case, the dipole moment arises from the redistribution of charge on the conducting spherical shell. The magnitude of the charge on the shell will depend on the electric field (E) it experiences.

Now, let's analyze the scenario step by step:

1. The electric field (E) is uniform and acts on the conducting spherical shell of radius (r).

2. Due to the presence of the electric field, charges on the shell will redistribute themselves until equilibrium is reached.

3. The redistribution of charges will result in a dipole-like configuration, where positive charge accumulates on one side and negative charge on the other side.

4. To calculate the strength of the dipole moment (p), we need to determine the magnitude of the charge (q) and the separation distance (d) between them.

5. In the case of a conducting shell, the electric field inside the shell is zero, and the charges redistribute themselves to the outer surface of the shell. This means that the separation distance (d) between the positive and negative charges is equal to the diameter of the shell (2r).

6. The magnitude of the charge (q) on each side of the dipole can be determined by considering the net charge on the shell, which is zero. Therefore, the charges on each side of the dipole are equal in magnitude.

Now, we can express the dipole moment (p) as:

p = q * d = q * 2r

To find the value of q, we need to consider the electric field (E) acting on the shell. The electric field due to an idealized dipole at the center of the shell is given by:

E = (kp * cosθ) / r^2

where kp is the electric dipole moment of the idealized dipole and θ is the angle between the direction of the electric field and the axis of the dipole.

Since the electric field (E) acting on the shell is the same as the field due to the idealized dipole, we can equate these two expressions:

E = (kp * cosθ) / r^2 = (kq * 2r * cosθ) / r^2

From this equation, we can deduce that kp = 2krq.

Therefore, the strength of the dipole moment (p) is given by:

p = q * 2r = (kp * r) / (2k)

Substituting kp = 2krq, we get:

p = (2krq * r) / (2k) = rq

Hence, the strength of the dipole moment is given by p = rq, where r is the radius of the conducting spherical shell and q is the magnitude of the charge on each side of the dipole.

Note: The negative sign indicating the direction of the dipole is not considered here since we are only interested in the magnitude of the dipole moment.

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