need help pleeeeeeeeeeeeeeease

To solve the inequality, we need to get the variable on one side and the constant on the other side. We can start by multiplying both sides of the inequality by 3:

\(4a ≥ 6\)

Now, we can divide both sides by 4:

\(a ≥ \frac{3}{2}\)

The solution to this inequality is all values of a that are greater than or equal to 3/2. We can represent this on a number line as:

(-infinity, -1.5) U [1.5, infinity)

Where ( -infinity, -1.5) represents all values less than -1.5 and [1.5, infinity) represents all values greater than or equal to 1.5.

Note that the solution can also be represented as a >= 1.5.

Answer:

4a/3≥ 2

4a/3*3≥ 2*3

4a≥6

4a/4≥6/4

a≥3/2

On a number line, you would plot 3/2 with a filled in hole. The arrow you would draw to is the one that goes to the positive side, to the right. That's how to plot it.

Step-by-step explanation:

The closest answer is 80 cupcakes per minute, so the correct option is .8. The closest answer is 165 minutes, so the correct option is 165.

The throughput capacity of the icing stage can be calculated by dividing the number of cupcakes in a batch (100) by the time required to process each cupcake (1.25 minutes).

Throughput capacity = Number of cupcakes in a batch / Time to process each cupcake

Throughput capacity = 100 cupcakes / 1.25 minutes

Throughput capacity = 80 cupcakes per minute

The closest answer is 80 cupcakes per minute, so the correct option is .8.

The throughput time for a batch of cupcakes is the time required to process the entire batch, including the setup time.

Throughput time = Time for setup + (Number of cupcakes in a batch * Time to process each cupcake)

Throughput time = 40 minutes + (100 cupcakes * 1.25 minutes per cupcake)

Throughput time = 40 minutes + 125 minutes

Throughput time = 165 minutes

The closest answer is 165 minutes, so the correct option is 165.

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The transfer function U(s)/Y(s) for the given system modeled by the differential equation y'' + 3y' + 2y = 21 + u is 1/(s^2 + 3s + 2).

To find the transfer function U(S)/Y(S) for the given system modeled by the differential equation y'' + 3y' + 2y = 21 + u, we need to take the Laplace transform of both sides of the equation.

Taking the Laplace transform, and assuming zero initial conditions:

s^2Y(s) + 3sY(s) + 2Y(s) = 21 + U(s)

Now, let's rearrange the equation to solve for Y(s):

Y(s)(s^2 + 3s + 2) = 21 + U(s)

Dividing both sides by (s^2 + 3s + 2):

Y(s) = (21 + U(s))/(s^2 + 3s + 2)

Therefore, the transfer function U(s)/Y(s) is:

U(s)/Y(s) = 1/(s^2 + 3s + 2)

The transfer function U(s)/Y(s) for the given system modeled by the differential equation y'' + 3y' + 2y = 21 + u is 1/(s^2 + 3s + 2).

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Answer:

you  need to draw a triangle on the grid

Step-by-step explanation:

find point -3 then 7

then find points -2 and 1

then -5 and 2

then join the points together

hope that helps

pls mark brainliest

Answer: 8.49 inches

Step-by-step explanation:

16.4-7.91=8.49 inches

Answer:

C Subtraction property of equality

Step-by-step explanation:

You are subtracting 21 from both sides in step 3

Answer:

I would guess C

Step-by-step explanation:

I hope I'm correct, good luck.

Answer:

B isa the answer for me it might be wrong for you or switch them

Step-by-step explanation:

Answer:

98

Step-by-step explanation:

Solution 1, (quick)

When enlarging by a scale factor, the shape's area is multiplied by the scale factor squared.

3.5*7*2^2=98

This works because for a rectangle width x and length y, width 2x and length is 2y, area is 4xy compared to area xy originally.

Solution 2, (technical)

Scale factor of 2 means multiplying by 2

3.5^2=7

7*2=14

7*14=98

Answer:

341.25

Step-by-step explanation:

You first split the figure into 2 pieces the triangular prism and the rectangular prism now that we know the dimensions of each figure we can create an expression, we will start with the triangular prism. the expression will be 3/2 x 5/2 x 10.5. Then we solve the rectangular prism. 5 x 5 x 10.5.

Now that we have acquired all the math that we need we can continue to simplify. 3 x 2 x 5/2 was derived from (3 x 5)/2 and we physically drew it out with properties of algebra (a later topic to study) anyways we get 15/2=7.5 and we multiply that by 10.5 giving us 78.75. the triangular prism is easier we just do 25 x 10.5 giving us 262.5. Now that we have succumbed both figures we can combine the to get the volume which is 341.25 (78.75 + 262.5).

HOL blocking issue in HTTP 1.1 HOL stands for "Head of Line" and is the term for what happens when a network pipeline receives requests from multiple connections and the first request needs to be processed before the next request can be processed.

As a result, if a single request takes longer to process, all other requests in the queue will be held up.

The problem that arises from this is known as the Head of Line (HOL) blocking issue.

HTTP/1.1 aims to solve the HOL blocking issue by reusing the same connection for multiple requests to avoid the connection setup overhead.

However, requests that are delayed for any reason, including server processing, network congestion, or latency, can create a bottleneck in the connection and cause subsequent requests to be blocked.

HTTP/2 approach to solve the HOL blocking issue

HTTP/2 attempts to solve the HOL blocking problem by introducing multiplexing, which is the ability to send multiple requests and responses simultaneously over a single connection.

With HTTP/2, the server can send several responses to the client for a single request in a non-blocking manner, avoiding the blocking problem that occurred with HTTP/1.1.

Another feature of HTTP/2 is that it enables server push, where the server can push data to the client before the client requests it, which can improve the performance of a web page.

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Answer: -8

Step-by-step explanation: 1/4 + 1/4 = 1/2, -8 1/2 + 1/2 = -8

The isosceles triangle of the maximum area is also an equilateral triangle.

Given, an isosceles triangle ABC is inscribed in a circle with center D and radius r.

We can obtain the side a in function of r and α by applying Law of Sines to triangle BCD,

a/sin(2α) = r/sin β

Since, 2α + β + β = 180°

2α + 2β = 180°

α + β = 90°

β = 90° - α

a = r(sin 2α/sin(90°-α))

a = r(2 sinα cosα)/cosα

a = 2r sinα

a = 4r sin(α/2) cos(α/2)

We can obtain the height h in function of r and α,

tan(α/2) = (a/2)/h

h = a/2tan(α/2)

Replacing with the value of a,

h = [4r sin(α/2) cos(α/2)/2][cos(α/2)/sin(α/2)]

h = 2r cos2(α/2)

Now, find the area of the triangle in function of a and r,

Area, A = (base)(height)/2

A = [4r sin(α/2) cos(α/2)][2r cos2(α/2)]/2

A = 4r2sin(α/2) cos3(α/2)

Now, take the derivative to find the maximum or minimum of the area of the triangle.

dA/dα = [4r2cos(α/2)(1/2)cos3(α/2)] + [4r2sin(α/2) 3cos2(α/2)(-sin(α/2))(1/2)]

On simplification,

= [2r2cos4(α/2)] - 6r2sin2(α/2) cos2(α/2)

Taking out common terms,

= 2r2cos2(α/2)[cos2(α/2) - 3sin2(α/2)]

Equating the derivative to zero, we get

2r2cos2(α/2)[cos2(α/2) - 3sin2(α/2)] = 0

2r2cos2(α/2) = 0

cos2(α/2) = 0

Thus, α/2 = 90°

α = 180°

Also, cos2(α/2) - 3sin2(α/2) = 0

cos2(α/2) = 3sin2(α/2)

[sin2(α/2)/cos2(α/2)] = 1/3

tan2(α/2) = 1/3

tan(α/2) = 1/√3

So, α/2 = 30°

α = 60°

This implies that ∠B = ∠C = 60°

Thus, the isosceles triangle of the maximum area that can be inscribed in a circle of radius r. is also an equilateral triangle.

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Answer:

yes

Step-by-step explanation:

Yes, every number have their fixed values around the world.

A number is an arithmetic value used for representing the quantity and used in making calculations.

Given that, do numbers have a fixed value even though their values are represented differently in varying parts of the world.

Yes,  each and every number have exactly one value of theirs and that value is not different but same for every part of world.

Hence, every number have their fixed values around the world.

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The domain of the function f(x, y) = p⁴ - x² - y²is the entire xy-plane, represented by { (x, y) | x ∈ R, y ∈ R }.

How to find domain?

To find and sketch the domain of f(x, y) = p⁴ - x² - y², we need to determine the values of x and y for which the function is defined.

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Answer:

g(x) = g = 3(x)

g(-10) = -30

Step-by-step explanation:

as we can see in the pattern, x times 3 is equal to g(x) -->

so we can conclude that g=3(x) which means g is 3 then multiply by x

finding g(-10) = 3(-10) => -30 and thus, we have our answers

Hope this helps ad sorry if it's a little not clear!

La ecuación de la recta es y = 1.2x + 0, o simplemente y = 1.2x. Y el precio en euros de 10 dólares es de 12 €.

La ecuación de la recta que nos da el precio en euros, y, de x dólares se puede hallar utilizando la fórmula de la pendiente de una recta, que es m = (y2 - y1) / (x2 - x1). En este caso, los puntos dados son (3, 3.6) y (7, 8.4).

Primero, calculamos la pendiente de la recta:
m = (8.4 - 3.6) / (7 - 3)

m = 4.8 / 4

m = 1.2

Luego, utilizamos la fórmula de la ecuación de la recta, y = mx + b, para encontrar el valor de b. Podemos utilizar cualquiera de los puntos dados para esto. Usaremos el punto (3, 3.6).

3.6 = 1.2(3) + b
3.6 = 3.6 + b
b = 0

Por lo tanto, la ecuación de la recta es y = 1.2x + 0, o simplemente y = 1.2x.

Esta ecuación nos da el precio en euros, y, de x dólares. Si queremos encontrar el precio en euros de una cierta cantidad de dólares, simplemente sustituimos el valor de x en la ecuación y resolvemos para y. Por ejemplo, si queremos encontrar el precio en euros de 10 dólares, sustituimos x = 10 en la ecuación:

y = 1.2(10) = 12

Por lo tanto, el precio en euros de 10 dólares es de 12 €.

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Volume of 1st box:

\(3 \times 5 \times 8 = 120ft ^{3} \)

Volume of 2nd box:

\(3 \times 5 \times 4 = 60ft ^{3} \)

Combined volume:

\(120 + 60 = 180ft ^{3} \)

The probability that on any one day, Heila will not be late for school is 0.69 or 69%.

We can use conditional probability to find the probability that Heila will not be late for school on any one day.

Let W be the event that Heila walks to school, and L be the event that Heila is late for school.

We know that:

P(W) = 0.65 (the probability that Heila walks to school)

P(L | W) = 0.4 (the probability that Heila is late for school given that he walks to school)

P(L | W') = 0.1 (the probability that Heila is late for school given that he cycles to school)

The probability that Heila is not late for school is the complement of the event that he is late for school. So:

P(L') = 1 - P(L)

We can use the formula for conditional probability to find the probability that Heila is not late for school:

P(L' | W) = 1 - P(L | W) = 1 - 0.4 = 0.6

P(L' | W') = 1 - P(L | W') = 1 - 0.1 = 0.9

We also know that the total probability of the outcomes must be equal to 1. Therefore, we can find the probability that Heila walks to school, P(W) by using the following equation:

P(W) + P(W') = 1

We know that P(W) = 0.65, so we can find P(W') by subtracting P(W) from 1:

P(W') = 1 - P(W) = 1 - 0.65 = 0.35

Now, we can use the formula of Total Probability to find the probability that Heila will not be late for school:

P(L') = P(L' | W) * P(W) + P(L' | W') * P(W')

P(L') = 0.6 * 0.65 + 0.9 * 0.35 = 0.69

Therefore, the probability that on any one day, Heila will not be late for school is 0.69 or 69%.

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The solution to the given initial value problem, obtained using Laplace transforms, is y(x) = 0. This means that the function y(x) is identically zero for all values of x.

To find the solution of the initial value problem using Laplace transforms for the equation d²y/dx² + 9y = 9sin(t)u(t - 3), where y(0) = y'(0) = 0, we can follow these steps:

Take the Laplace transform of the given differential equation.

Applying the Laplace transform to the equation d²y/dx² + 9y = 9sin(t)u(t - 3), we get:

s²Y(s) - sy(0) - y'(0) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))

Since y(0) = 0 and y'(0) = 0, the Laplace transform simplifies to:

s²Y(s) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))

Solve for Y(s).

Combining like terms, we have:

Y(s) * (s² + 9) = 9 * (1/s² + 1/(s² + 1))

Multiply through by (s² + 1)(s² + 9) to get rid of the denominators:

Y(s) * (s⁴ + 10s² + 9) = 9 * (s² + 1)

Simplifying further, we have:

Y(s) * (s⁴ + 10s² + 9) = 9s² + 9

Divide both sides by (s⁴ + 10s² + 9) to solve for Y(s):

Y(s) = (9s² + 9)/(s⁴ + 10s² + 9)

Partial fraction decomposition.

To proceed, we need to decompose the right side of the equation using partial fraction decomposition:

Y(s) = (9s² + 9)/(s⁴ + 10s² + 9) = A/(s² + 1) + B/(s² + 9)

Multiplying through by (s⁴ + 10s² + 9), we have:

9s² + 9 = A(s² + 9) + B(s² + 1)

Equating the coefficients of like powers of s, we get:

9 = 9A + B

0 = A + B

Solving these equations, we find:

A = 0

B = 0

Therefore, the decomposition becomes:

Y(s) = 0/(s² + 1) + 0/(s² + 9)

Inverse Laplace transform.

Taking the inverse Laplace transform of the decomposed terms, we find:

L^(-1){Y(s)} = L^(-1){0/(s² + 1)} + L^(-1){0/(s² + 9)}

The inverse Laplace transform of 0/(s² + 1) is 0.

The inverse Laplace transform of 0/(s² + 9) is 0.

Combining these terms, we have:

Y(x) = 0 + 0

Therefore, the solution to the initial value problem is:

y(x) = 0

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Answer:

Tyler. Because the temperature dropped at a faster °/hr rate then Mai's did

Step-by-step explanation:

                \(\frac{temp.drop}{hours}\)

Tyler

from 4-6 it dropped 8° in a course of 2 hours. averaging a 4°/Hr drop

\(\frac{8}{2hrs}\)= 4°/hr

Mai

from 6-10 it dropped 9° in a course of 4 hours. averaging a 2.25°/hr drop

\(\frac{9}{4hrs}\)= 2.25°/hr

Therefore Tyler is correct

The statement "A matrix that is both symmetric and upper triangular must be a diagonal matrix" is true. The other three statements are not true.

If A and B are n×n matrices such that A+B is symmetric, it does not imply that A and B are symmetric. Counterexamples can be constructed by considering matrices A and B that are not symmetric individually but whose sum is symmetric. For example, consider A = [1 2; 3 4] and B = [0 1; 1 0]. Their sum A+B = [1 3; 4 4] is symmetric, but A and B are not symmetric.

If A and B are n×n matrices such that A+B is upper triangular, it does not imply that A and B are upper triangular. Counterexamples can be constructed by considering matrices A and B that are not upper triangular individually but whose sum is upper triangular. For example, consider A = [1 1; 0 2] and B = [0 1; 1 0]. Their sum A+B = [1 2; 1 2] is upper triangular, but A and B are not upper triangular.

If A² is a symmetric matrix, it does not imply that A is a symmetric matrix. Counterexamples can be constructed by considering matrices A that are not symmetric but satisfy A² being symmetric. For example, consider A = [0 1; 0 0]. A² = [0 0; 0 0] is symmetric, but A is not symmetric.

The statement "A matrix that is both symmetric and upper triangular must be a diagonal matrix" is true. If a matrix is symmetric and upper triangular, it means that all its entries above the main diagonal and below the main diagonal are zero. In other words, the only nonzero entries are on the main diagonal. Hence, the matrix is diagonal.

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False. An update rule which is not a non-expansion can still converge, but it may not converge to the unique fixed point of interest.

A non expansion update rule ensures convergence by guaranteeing that the distance between iterates decreases with each iteration. However, there are update rules that do not satisfy this condition but can still converge to a fixed point, such as contraction mappings.

A contraction mapping is a function that maps a metric space into itself and contracts the distance between points by a fixed factor. A well-known example is the function f(x) = x/2, which is a contraction mapping on the real line with a fixed point at x = 0.

Therefore, an update rule that is not a non-expansion may still converge to a fixed point, but the convergence may be slower or may converge to a different fixed point.

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Answer: If you have a segment AB, place the unit length segment on the line where AB lies, starting with A and in the direction opposite to B; let C be the other point of the segment. Now draw a semicircle with diameter CB; and a line perpendicular to A; this line crosses the semicircle in a point D. AD is then the square root of AB.

△BCD is a right triangle, like △ACD and △ABD; all of these are similar, so you find out that AC/AD=AD/AB. But AC=1, so AD=√AB.

Step-by-step explanation: See the drawing below:

Answer:

obtuse angle triangle

Step-by-step explanation:

please make me Brilliant for this correct answer

Answer:

2

Step-by-step explanation:

The U.S. president may serve 2 terms according to the 22nd Amendment to the U.S. Constitution.

Answer:

2

Step-by-step explanation:

it is not mathmatic!!!

Answer:

The answer is 7794, rounded is 7790.

Since the 4 in the ones place is not greater than 5, you round down and get 0.

Step-by-step explanation:

Answer:The Y axis of a velocity time graph represents the instateneous velocity of a particle or body

Step-by-step explanation:

Answer:

good question

Step-by-step explanation:

this is your answer

A rectangle measures 3 1/3 inches by 2 1/2 inches what is its area ? Find the area of the last part .

we know that the area of a rectangle is the product of it's dimensions

so, the area of the given rectangle would be

so ,the measure of the last part would be

\(\frac{1}{3} \times \frac{1}{2} \\ = \frac{1}{6} \)