Na2CO3 + CaCl2•2H2O -> CaCO3 + 2NaCl + 2H2O
Calculate how many moles of CaCl2•2H2O are present in 1.50 g of CaCl2•2H2O and then calculate how many moles of pure CaCl2 are present in 1.50 g of CaCl2•2H2O. Then determine how many grams of Na2CO3 are necessary to reach stoichiometric quantities.
For CaCl2 I got 0.0135 mol but I have seen some put 0.0102 mol. Which is it?
For the initial mol of Na2CO3 I got 0.0102 mol but again I’m not sure if I’m right.
For the grams of Na2CO3 I got 1.08 g
Can someone help me figure out if I have this correct?

Answer:

Take a look at the attachment below

Explanation:

Hope that helps!

There are approximately 1.765 x 10²³ molecules of KCl in 21.89 grams of KCl.

Potassium chloride (KCl) is a compound made up of potassium and chloride ions. It is a colorless, odorless salt that is commonly used in a variety of applications.

Molar mass of KCl is 74.55 g/mol; number of moles = Mass/ Molar mass

So, the number of moles = 21.89 g ÷ 74.55 g/mol = 0.2936 mol

and the number of molecules = Number of moles * Avogadro's number

Number of molecules = 0.2936 mol x 6.02 x 10²³ molecules/mol

Number of molecules = 1.765 x 10²³ molecules

Therefore, there are approximately 1.765 x 10²³ molecules of KCl in 21.89 grams of KCl.

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The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

the answer is D all of the above

Answer: Temperature

Explanation:

Answer: Temperature

Explanation: can i get brainliest plss

Answer: The concentration(molarity) of the solution will be 1.35 X10-4 M

Explanation: Molarity is defined as number of moles of solute present in one litre of any solution.

Mathematically,

Molarity= no of moles of solute/volume of solution(in liters)

M=N/V(liters)

Also upon dilution the number of moles of the solution remain unchanged

Therefore initial no of moles(before dilution)= final no of moles(after dilution)

M1V1=M2V2

According to the question,

Molarity of Na2S04 before dilution(M1)=1.5 M

Volume of NA2SO4(V1)=45 mL

Molarity of Na2S04 after dilution(M2)=x M

Volume of Na2S04(V2)=500 mL

x=M1V1/V2

=1.5X45/500

=0.135 M =1.35 X10-4 M

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By the concept of calculating moles ,it can br concluded that the no. of atoms of phosphorus in 8.80mol of copper(II) phosphate is=1.06\(x10^{25}\)

A mole is defined as amount of substance containing as many as elementary entities that are there in atoms of exactly 12 g of carbon-12.Therefore we can say,1 mole of copper(II) phosphate, Cu3(PO4)2, contains three moles of copper(II) cations and two moles of phosphate anions.

Again 1mole of phosphate anions contains one mole of phosphorus and four moles of oxygen.Considering all these informations we can conclude that:1 mole of copper(II) phosphate contains 2 moles of Phosphorus

Accordingle the sample contains=(8.80\(x\)2) moles of Phosphorus

                                    =(17.6\(x\)Avogadro's constant) atoms of  Phosphorus

                                    =(17.6\(x\)6.022\(x\)\(10^{23}\)) atoms of  Phosphorus

                                    =1.06\(x10^{25}\) [approx] no. of Phosphorus atoms

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In 8.80 moles of copper(II) phosphate, there are approximately 1.06 x 10²⁵ atoms of phosphorus.

The number of atoms of phosphorus in a given amount of a compound can be calculated using the concept of mole in chemistry. Copper(II) phosphate is Cu3(PO4)2, containing 2 moles of phosphorus (P) for every 1 mole of the compound. Avogadro's number (6.022 x 10²³) gives the number of atoms in one mole.

So, if there are 8.80 moles of copper(II) phosphate, there would be 2 × 8.80 moles of phosphorus. Multiplying this by Avogadro's number gives the total number of phosphorus atoms.

Therefore, the number of phosphorus atoms is 2 × 8.80 × 6.022 x 10²³ = 1.06 x 10²⁵ atoms of phosphorus.

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Answer:

21.51g/cm³

Explanation:

To answer this question we need to know that, in 1 unit FCC cell:

Edge length = √8 * R  

Volume = 8√8 * R³

And there are 4 atoms per unit cell

The mass of the 4 atoms of the cell, in grams, is:

4 atom * (1mol / 6.022x10²³atom) * (195.09g / mol) = 1.2958x10⁻²¹g

Volume in cm³:

0.1386nm * (1x10⁻⁷cm / 1nm) = 1.386x10⁻⁸cm

Volume = 8√8 * (1.386x10⁻⁸cm)³

Volume = 6.02455x10⁻²³cm³

And density, the ratio of mass and volume, is:

1.2958x10⁻²¹g  / 6.02455x10⁻²³cm³  =

Answer:

4-Methyl-1-pentene

Explanation:

According to  the International Union of Pure and Applied Chemistry (IUPAC), IUPAC nomenclature of organic chemistry is defined as the system of naming organic chemical compounds.

There are certain rules for naming organic chemical compounds as per IUPAC. The name of given (CH3)2CHCH2CH=CH2 will be based on the same rules.

4-Methyl-1-pentene is the name of this chemical, as methyl is in 4th carbon position, Pent for 5 carbon chain and -ene (suffix) for one double bond).

Hence, the correct answer is "4-Methyl-1-pentene".

Answer:

H2SO4(aq)

Explanation:

The balanced equation for the reaction is given below:

H2SO4(aq) + Mg(s) —> MgSO4(aq) + H2 (g)

An acid is a substance which dissolves in water to produce hydrogen ion, H+ as the only positive ion.

To know which of the substance is acid, let us dissolve them in water to see which will produce hydrogen ion, H+ as the only positive ion.

This is illustrated below:

H2SO4(aq) —> 2H+(aq) + SO4^2-(aq)

Mg(s) + 2H2O(l) —> Mg(OH)2(aq) + H2(g)

MgSO4(aq) —> Mg^2+(aq) + SO4^2-(aq)

H2 is insoluble in water.

From the above, only H2SO4 produces hydrogen ion H+ on dissolution in water. Therefore, H2SO4 is an acid

Answer:

D on edg 2021

Explanation:

Answer:

The amount of air (in grams) is required for an answer. The process is outlined below.

Explanation:

An example for 1 kg of air:

Energy = (specific heat)*(mass)*(temperature change)

Joules = (1.03J/g°C)*(1,000g)*(27°C - 9°C)

Joules = 18540J

Coversion: 1 Joule = 2.78E-07 kwh

Kwh to heat 1 kg of air from 9 to 27°C is 5.15E-03 kwh

Use the same process with the actual mass of air in the house. If you are given house dimensions, calculate the volume and multiply by the density of air to get grams air. (Remember to subtract the volume taken up by household items (e.g., beer cans).

The kilowatt-hours of energy that are necessary to heat the air in the house from 9 ∘C to 27 ∘C is 5.15 x 10³.

When the temperature of a material rises 1 K (or 1 °C), the amount of heat (J) absorbed per unit mass (kg).

Given that, the heat capacity of air is 1.03 J/g∘C.

The changing temperature of the house is  9∘C to 27 ∘C

Here, the energy has to be calculated and the heat capacity is given. Then we have to change or convert the unit into kilowatt-hours.

Energy = (specific heat)*(mass)*(temperature change)

Joules = (1.03J/g°C) x (1,000g) x (27°C - 9°C)

Joules = 18540J

The conversion of the unit is 1 Joule = 2.78 x 10⁷

KWH to heat 1 kg of air from 9 to 27°C is 5.15 x 10³.

Thus, the energy that is necessary to heat the air in the house is 5.15 x 10³.

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Answer:

40.04g

Explanation:

the water has one molecule of hydrogen and two molecules of oxygen(H20)

(4.02)(2)(32)

Scaling a life-size crime scene onto a sketch paper involves reducing the dimensions of the scene while maintaining accurate proportions.

Here's an example of how to do it:

Measure the dimensions of the crime scene (e.g., length and width) using a tape measure.

Determine the desired scale for the sketch (e.g., 1 inch represents 1 foot).

Calculate the reduction factor by dividing the length of the crime scene by the length on the sketch paper. For example, if the crime scene length is 30 feet and the sketch length is 10 inches (120 inches), the reduction factor would be 30/120 = 0.25.

Multiply all measurements of the crime scene (length, width, objects, distances) by the reduction factor to obtain the corresponding measurements for the sketch.

Transfer the scaled measurements onto the sketch paper using a ruler and appropriate drawing tools.

Citation: The procedure described above is a commonly used method for scaling objects or scenes in forensic science investigations. It is based on principles of measurement and proportion commonly employed in the field. No specific citation is provided since this is a widely used technique in forensic science practice.

Therefore, scaling a life-size crime scene onto a sketch paper involves reducing the dimensions of the scene while maintaining accurate proportions.

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The value of the rate constant at 9.30×102 K is 2.03×102 s–1.

To solve this problem, we can use the Arrhenius equation:

k = A * exp(-Ea/RT)

where:

k = rate constant

A = pre-exponential factor or frequency factor

Ea = activation energy

R = gas constant (8.314 J/mol·K)

T = temperature in Kelvin

We can rearrange this equation to solve for the rate constant at the new temperature:

k2 = A * exp(-Ea/RT2)

where k2 is the rate constant at the new temperature T2.

We are given k1 = 3.241×10-5 s–1 at T1 = 800 K, and Ea = 255 kJ/mol. We need to find k2 at T2 = 9.30×102 K.

To find A, we can rearrange the Arrhenius equation to solve for A:

A = k / exp(-Ea/RT)

Using k1 and T1, we get:

A = 3.241×10-5 s–1 / exp(-255000 J/mol / (8.314 J/mol·K * 800 K))

A = 7.07×1013 s–1

Now we can use A, Ea, k1, and T2 to find k2:

k2 = A * exp(-Ea/RT2)

k2 = 7.07×1013 s–1 * exp(-255000 J/mol / (8.314 J/mol·K * 930 K))

k2 = 2.03×102 s–1

Therefore, the value of the rate constant at 9.30×102 K is 2.03×102 s–1. using Arrhenius equation.

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The fingerprint region is the right term for this area. The IR spectrum of a molecule is a graphical depiction of the vibrational frequencies of the molecule's bonds.

The fingerprint area is the portion of the IR spectra between 1,000 and 400 cm-1 that is frequently used to distinguish between identical molecules with the same functional groups. This is due to the fact that each molecule has a unique bond configuration, which results in a unique set of vibrational frequencies.The fingerprint region is the right term for this area. The IR spectrum of a molecule is a graphical depiction of the vibrational frequencies of the molecule's bonds.  It is possible to identify individual molecules and distinguish between similar ones by studying the peaks in the fingerprint area.The remaining areas indicated, the downfield, functional group, and Ri regions, are not typically used to define the IR spectrum.

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thefunctionalgroupregion These are often connected to functional group stretching vibrationsA functional group's stretching vibrations are restricted to a small range

Functional connection is defined as the geographically dispersed neurophysiological events' temporal coherence (Friston, 1994). In other words, if there is a statistical link between the activity measurements that have been recorded for two areas, then those two regions are said to exhibit functional connectivity. This connection strategy is based on the idea that if two regions' functional activity is regularly associated, then those two areas are assumed to be connected or to be parts of the same network Functional connectivity is a considerably more direct method of analysing functional networks than effective connectivity studies, which rely on a number of assumptions about the underlying neurobiology and the model used to predict it. Particularly it is in agreement with the intuitive

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A snow globe is a suspension combination because it shakes up with snow all over it, which eventually settles.

Glycerin, a transparent liquid that is often manufactured from vegetable oils, is one of the secrets to making a snow globe. It is used frequently to reduce the impact of glitter and agitated water on the appearance of snowfall. Your snow globes risk drying out, cracking, and color fading if the right precautions aren't taken to protect them. In general, you should store your snow globes away from hot surroundings, bright sunlight, and other risky places where they could break.

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Answer:

I'll do it if you give brainlyest and some points

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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Coenzyme q carries electrons from complex I to complex III  and complex II to complex III  in the electron-transport chain.

Coenzyme q  (CoQ), also known as ubiquinone, is the electron carrier in the electron transport system (ETS) present on the inner membrane of mitochondria.

Ubiquinone is a ubiquitous quinone, which accepts electrons from complex II ( succinate dehydrogenase) and  reduces to ubiquinol ( reduced form)

The purpose of the ETS is to generate an H+ ion concentration, by carrying electrons obtained from NADH AND \(FADH_{2}\)   produced by the Krebs cycle and glycolysis in the mitochondrial matrix. This  H+ ion potential will be used by ATP synthase to generate ATP.

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The inner mitochondrial membrane contains CoQ, a key part of the mitochondrial electron transport chain (ETC), which moves electrons from complexes I and II to complex III to provide energy for proton translocation to the intermembrane gap.

An organelle called a mitochondrion can be found in the cells of the majority of Eukaryotes, including mammals, plants, and fungi. Adenosine triphosphate, which is produced by aerobic respiration in mitochondria with their double membrane structure, is used as a source of chemical energy throughout the entire cell.

Coenzyme Q10 takes electrons from reducing equivalents produced during the metabolism of fatty acids and glucose and then transports them to electron acceptors as part of the mitochondrial electron transport chain.

Ubiquinone, also known as coenzyme Q, is a lipophilic molecule that is found in all tissues and cells and is mostly found in the inner mitochondrial membrane. It is generally known that Coenzyme Q is an essential part of the oxidative phosphorylation process in mitochondria.

Thus, The inner mitochondrial membrane contains CoQ, a key part of the mitochondrial electron transport chain (ETC).

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Hi there! Answer is below :)

Explanation:

For this question, we apply Boyle's Law and Charles' Law.

When you double the amount of pressure and temperature of a compound or mixture, the volume will decrease by a half. So, if the pressure and temperature are 2, and the volume is 1, and you double, your volume will be 0.5 and your pressure and temperature will be 4.

Best of Luck!

Answer:

This apparent change in the pitch (or frequency) of sound is called Doppler shift. ... You see these stretched-out light waves as having a lower frequency. Since red is at the low-frequency end of the visible spectrum, we say that light from a receding star is shifted toward red, or red shifted.

Explanation:

The number of atoms present in 591 g of gold is 1.81×10²⁴ atoms

From Avogadro's hypothesis,

1 mole of Gold = 6.02×10²³ atoms

But

1 mole of gold = 197 g

Thus,

197 g of gold = 6.02×10²³ atoms

197 g of gold = 6.02×10²³ atoms

Therefore,

591 g of gold = (591 × 6.02×10²³) / 197

591 g of gold = 1.81×10²⁴ atoms

Thus, 1.81×10²⁴ atoms is present in 591 g of gold.

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Answer:

X₅Y₂Z₃

Explanation:

The formula of a compound is determined as the whole number ratio between moles of each element present in the molecule.

The molecule is made from X, Y and Z. To fin the ratio we will divide the given moles in the moles of Y (0.197 moles), because is the element with the low number of moles.

X = 0.492 moles / 0.197 moles = 2.5

Y = 0.197 moles / 0.197 moles = 1

Z = 0.295 moles / 0.197 moles = 1.5

But, as the formula is given just with whole numbers, if we multiply each number twice:

X = 2.5*2 = 5

Y = 1*2 = 2

Z = 1.5*2 = 3

The formula is:

Answer:

yes it is a chemical reaction

Explanation:

because the substances combined and made something new

Answer:

Soil acidity can be corrected easily by liming the soil, or adding basic materials to neutralize the acid present. ... As lime dissolves in the soil, calcium (Ca) moves to the surface of soil particles, replacing the acidity. The acidity reacts with the carbonate (CO3) to form carbon dioxide (CO2) and water (H2O).

Explanation:

Answer:

How do amoeba respire.

How do plants respire.

Answer:

Explanation:

If a zero is found between significant digits, it is significant

Answer:

B, B and C

Explanation:

The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.

This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.

(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.

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