Mr. Blue Tiger wants to create his own version of fibonacci sequence. Since 3 is his favorite number, he decides that any element should be the sum of its previous three elements. Can you help him figure out the time complexity of his recursive function? Select All the answers that are correct, and state your reason. int TigerNacci (unsigned int n) { 2 if (n < 3) return 1; 3 return TigerNacci (n-1) + Tiger Nacci (n - 2) + TigerNacci(n − 3); i) (n³ log n) ii) (3" log n) iii) O(3" log n) iv) (3¹) v) (n² log n) vi) (2" log n) vii) O(2" log n) viii) (2¹¹) (a) Derive the recurrence relation of the TigerNacci function complexity. (Hint: Can you use master theorem here?) Solution: then find out its time
Answers
Answer:
The time complexity of the TigerNacci function can be derived using the recurrence relation. Since the function is calculating the sum of the previous three elements, its recurrence relation is:
T(n) = T(n-1) + T(n-2) + T(n-3)
where T(n) is the time taken to calculate the nth element of the TigerNacci sequence.
Unfortunately, we cannot use the Master theorem directly to solve this recurrence relation because it is not in the form T(n) = aT(n/b) + f(n). However, we can try to guess the solution and then prove it using induction.
One possible guess is that T(n) = O(3^n). To prove this, we assume that T(k) <= c*3^k for all k < n (inductive hypothesis), where c is a constant. Then,
T(n) = T(n-1) + T(n-2) + T(n-3) <= c3^(n-1) + c3^(n-2) + c3^(n-3) (by inductive hypothesis) = c3^(n-3) * (3 + 1 + 1/3) = c3^(n-3) * 10/3 < c3^n (for c >= 10/3)
Therefore, we have shown that T(n) = O(3^n). This means that options (i), (ii), (iii), and (v) are incorrect because they have an asymptotic upper bound of less than 3^n. Option (iv) is also incorrect because it has a constant upper bound. Option (vi) is correct because it has an asymptotic upper bound of 2^n and 2 < 3. Option (vii) is also correct because it is equivalent to O(2^n). Option (viii) is incorrect because it has a constant upper bound. Therefore, the correct answers are (vi) and (vii).
Explanation:
Related Questions
eggzOG43199
:) it has to be more than 20 characters so I'm just saying this
Answers
Answer:
giberishgiberishgiberishgiberishgiberishgiberishgiberishgiberishgiberish
Explanation:
i have no idea what the question is but do u 4 real need help?
Given a positive integer (call it ), a position in that integer (call it P), and a transition integer (call it D). Transform N as follows: • If the ph digit of N from the right is from 0 to 4, add D to it. Replace the P digit by the units digit of the sum. Then, replace all digits to the right of the pa digit by 0. If the ph digit of N from the right is from 5 to 9, subtract D from it. Replace the pa digit by the leftmost digit of the absolute value of the difference. Then, replace all digits to the right of the pa digit by 0. Example 1: N-7145032, P = 2, D = 8. The 2nd digit from the right is 3; add 8 to it (3+8=11), and replace the 3 with 1 to get 7145012. Replace the digits to the right by Os to get 7145010. Example 2: N = 1540670, P = 3, D = 54. The 3 digit from the right is 6; the absolute value of 6-54 is 48; replace with the 4 to get 1540470. Replace the digits to the right with Os to get 1540400 INPUT: There will be 5 sets of data. Each set contains 3 positive integers: N. P. and D. N will be less than 10"; P and D will be valid inputs. No input will cause an output to have a leading digit of o. OUTPUT: Print the transformed number. The printed number may not have any spaces between the digits. SAMPLE INPUT: (http://www.datafiles.acsl.org/2020/contestl/jr-sample-input.txt) 124987 2 3 540670 39 7145042 2 8 124987 2 523 4386709 1 2 SAMPLE OUTPUT: 1. 124950 2. 540300 3. 7145020 4. 124950 5. 4386707 TEST DATA TEST INPUT: 4318762 4 3 72431685 1 7 123456789 78 9876543210 10 25 314159265358 8 428 TEST OUTPUT: 1. 4315000 2. 72431682 3. 121000000 4. 1000000000 5. 314140000000
Answers
When the program prompt , you can copy paste the following lines as input 124987 2, 3 540670 3 9, 7145042 2 8, 124987 2 52,3 and 4386709 1 2
importing the Java utility scanner;
public class TransformNumbers {
public static void main(String[] args) {
int numSets = 5; //no of input sets
int P, D;
String N;
int digit;
int sum, diff, unitDigit;
char leftMost;
System.out.println("Please enter 5 sets of N P D values on separate lines");
Scanner input = new Scanner(System.in);
for(int i = 1; i <= numSets; i++)
{
N = input.next();
P = input.nextInt();
D = input.nextInt();
digit = N.charAt(N.length() - P ) - '0'; //convert from char to int
if(digit >= 0 && digit<= 4)
{
sum = digit + D;
unitDigit = sum % 10;
N = N.substring(0, N.length() - P) + unitDigit;
}
else if(digit >= 5 && digit <= 9)
{
diff = digit - D;
if(diff < 0)
diff = -diff;
leftMost = (""+diff).charAt(0);
N = N.substring(0, N.length() - P) + leftMost;
}
//set remaining on right to 0
for(int j = 1; j < P; j++)
N = N + "0";
System.out.printf("%d. %s\n",i, N);
}
}
}
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Tech A says that a parasitic draw is measured in volts. Tech B says that pulling fuses one at a time can help locate a parasitic draw. Who is correct
Answers
Answer:
Tech B
Explanation:
A___________combines the function of a video camera and a sound recorder.
Answers
Answer:
A video camera with onboard storage(whether is a tape or digital memory) will record sound
The alternator is considered to be a part of your car's _______ system:_____.
a. fuel
b. suspension
c. electrical
d. ignition
Answers
Answer:
C
Explanation:
The alternator generates electricity to power headlights/radio/windows etc and charge the battery.
What are the top 4 solar inventions, how they are used, and how they are better than the original way of powering them
Answers
12. Some engine blocks are made of _______, but its high cost prohibits use in average-priced vehicles. A. cast iron B. aluminum C. magnesium alloy D. hydrocarbon
Answers
To determine the viscosity of a liquid of specific gravity 0.95, you fill to a depth of 12 cm a large container that drains through a 30 cm long vertical tube attached to the bottom. The tube diameter is 2 mm, and the rate of draining is found to be 1.9 cm3 /s. What is the fluid viscosity (assume laminar flow)
Answers
Answer:
Fluid viscosity, \(\mu = 2.57 * 10^{-3} kgm^{-1}s^{-1}\)
Explanation:
Container depth, D = 12 cm = 0.12 m
Tube length, l = 30 cm = 0.3 m
Specific Gravity, \(\rho\) = 0.95
Tube diameter, d = 2 mm = 0.002 m
Rate of flow, Q = 1.9 cm³/s = 1.9 * 10⁻⁶ m³/s
Calculate the velocity at point 2 ( check the diagram attached)
Rate of flow at section 2, \(Q = A_2 v_2\)
\(Area, A_2 = \pi d^{2} /4\\A_2 = \pi/4 * 0.002^2\\A_2 = 3.14159 * 10^{-6} m^2\)
\(v_{2} = Q/A_{2} \\v_{2} =\frac{1.9 * 10^{-6}}{3.14 * 10^{-6}} \\v_{2} = 0.605 m/s\)
Applying the Bernoulli (energy flow) equation between Point 1 and point 2 to calculate the head loss:
\(\frac{p_{1} }{\rho g} + \frac{v_{1}^2 }{2 g} + z_1 = \frac{p_{2} }{\rho g} + \frac{v_{2}^2 }{2 g} + z_2 + h_f\\ z_1 = L + l = 0.12 + 0.3\\z_1 = 0.42\\p_1 = p_{atm}\\v_1 = 0\\z_2 = 0\\\frac{p_{atm} }{\rho g} + \frac{0^2 }{2 g} + 0.42= \frac{p_{atm} }{\rho g} + \frac{0.605^2 }{2 *9.8} +0 + h_f\\h_f = 0.401 m\)
For laminar flow, the head loss is given by the formula:
\(h_f = \frac{128 Q \mu l}{\pi \rho g d^4} \\\\0.401 = \frac{128 * 1.9 * 10^{-6} * 0.3 \mu}{\pi *0.95* 9.8* 0.002^4}\\\\\\\mu = \frac{0.401 * \pi *0.95* 9.8* 0.002^4}{128 * 1.9 * 10^{-6} * 0.3} \\\\\mu = 2.57 * 10^{-3} kgm^{-1}s^{-1}\)
Answer:
0.00257 kg / m.s
Explanation:
Given:-
- The specific gravity of a liquid, S.G = 0.95
- The depth of fluid in free container, h = 12 cm
- The length of the vertical tube , L = 30 cm
- The diameter of the tube, D = 2 mm
- The flow-rate of the fluid out of the tube into atmosphere, Q = 1.9 cm^3 / s
Find:-
To determine the viscosity of a liquid
Solution:-
- We will consider the exit point of the fluid through the vertical tube of length ( L ), where the flow rate is measured to be Q = 1.9 cm^3 / s
- The exit velocity ( V2 ) is determined from the relation between flow rate ( Q ) and the velocity at that point.
\(Q = A*V_2\)
Where,
A: The cross sectional area of the tube
- The cross sectional area of the tube ( A ) is expressed as:
\(A = \pi \frac{D^2}{4} \\\\A = \pi \frac{0.002^2}{4} \\\\A = 3.14159 * 10^-^6 m^2\)
- The velocity at the exit can be determined from the flow rate equation:
\(V_2 = \frac{Q}{A} \\\\V_2 = \frac{1.9*10^-^6}{3.14159*10^-^6} \\\\V_2 = 0.605 \frac{m}{s}\)
- We will apply the energy balance ( head ) between the points of top-surface ( free surface ) and the exit of the vertical tube.
\(\frac{P_1}{p*g} + \frac{V^2_1}{2*g} + z_t_o_p = \frac{P_2}{p*g} + \frac{V^2_2}{2*g} + z_d_a_t_u_m + h_L\)
- The free surface conditions apply at atmospheric pressure and still ( V1 = 0 ). Similarly, the exit of the fluid is also to atmospheric pressure. Where, z_top is the total change in elevation from free surface to exit of vertical tube.
- The major head losses in a circular pipe are accounted using Poiessel Law:
\(h_L = \frac{32*u*L*V}{S.G*p*g*D^2}\)
Where,
μ: The dynamic viscosity of fluid
L: the length of tube
V: the average velocity of fluid in tube
ρ: The density of water
- The average velocity of the fluid in the tube remains the same as the exit velocity ( V2 ) because the cross sectional area ( A ) of the tube remains constant throughout the tube. Hence, the velocity also remains constant.
- The energy balance becomes:
\(h + L = \frac{V_2^2}{2*g} + \frac{32*u*L*V_2}{S.G*p*g*D^2} \\\\0.42 = \frac{0.605^2}{2*9.81} + \frac{32*u*(0.3)*(0.605)}{0.95*998*9.81*0.002^2} \\\\u = 0.00257 \frac{kg}{m.s}\)
- Lets check the validity of the Laminar Flow assumption to calculate the major losses:
\(Re = \frac{S.G*p*V_2*D}{u} \\\\Re = \frac{0.95*998*0.605*0.002}{0.00257} \\\\Re = 446 < 2100\)( Laminar Flow )
FILL IN THE BLANK. Human skin resistance in ohms _________, when the bare body part is _________, compared to when ________.
Answers
Human skin resistance in ohms varies depending on different factors such as moisture, pressure, and surface area.
On average, the skin resistance can range from around 1,000 to 100,000 ohms. When the bare body part is dry, the skin resistance tends to be higher, typically in the range of several thousand ohms. However, when the skin is moist or comes into contact with a conductive surface, the skin resistance decreases significantly, often dropping to several hundred ohms. Therefore, the skin resistance is generally higher when the bare body part is dry compared to when it is moist or in contact with a conductive material.
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Energy is important to life forms because
A) it is required to do work
B) all life forms require a continuous supply of it
C) it is required to make specific alterations in the cell
D) both a and b
E) a, b and c
Answers
The correct option is B). Energy is important to life forms because all life forms require a continuous supply of it.
Explanation: Energy is an essential requirement for all living organisms to maintain their vital processes such as growth, repair, and reproduction. Energy is an important requirement for every single cellular process in a living organism. All the metabolic processes that occur in the body require energy to be conducted efficiently.
Without energy, the metabolic processes within the body would not be able to continue and would lead to cell death. Animals and humans derive energy from the food they consume. The food is broken down into glucose, which is used to produce ATP, the molecule that provides energy to every process in the body.
Plants, on the other hand, get their energy from the sun through the process of photosynthesis, in which the energy from the sun is converted into usable energy stored in the form of glucose. In conclusion, all living organisms require energy for their survival and maintenance.
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1.4 A body with a mass of 2.5 tons moves on a horizontal surface. To maintain constant velocity, a force of 10 kN is used to drive the body. What is the coefficient of friction between the body and the horizontal surface?
Answers
Answer:
μ ≈ 0.408
Explanation:
The coefficient of friction is the ratio of friction force to normal force. The normal force is ...
F = mg = (2500 kg)(9.8 m/s²) = 24.5 kN
Then the coefficient of friction (μ) is ...
μ = (10 kN)/(24.5 kN) ≈ 0.408
Determine the Force in lbf required to lower the screw given the R is 7 in long, 1.0 in diameter screw with a pitch p = 0.130 in, where Q is 14 lbf of force and the coefficient of friction is 0.40. -R- -R-
Answers
Force in lbf required to lower the screw = 45.9
Force in lbf required to lower the screw given the R is 7 in long, 1.0 in diameter screw with a pitch p = 0.130 in, where Q is 14 lbf of force and the coefficient of friction is 0.40 can be determined as follows:The pitch is defined as the distance between the same two points on successive threads.
We will make use of the formula given below to find out the force required to lower the screw by using the concept of worm drive.
tan Φ=frictional force/perpendicular force (p/πd)
Φ= inverse tan (frictional force/perpendicular force (p/πd))
Where, Φ is the helix angle of the worm, and d is the diameter of the screw
Substitute the values in the above formula.
tan Φ=0.4 / (0.130/π×1)
Φ = inverse tan (0.4 / (0.130/π×1))
= 19.08 degrees
Tangential force, F = Q/sin Φ
F = 14 / sin 19.08
F = 45.9, lbf
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Explain any five applications of computer modeling in beams.
Answers
Answer:
Explain any five applications of computer modeling in beams.
Explanation:
why people act like that
Answers
Answer:
i dob't know
Explanation:
So, I act like I believe them.
the sum of the numbers (1ae)16 and (bbd)16 is
Answers
The sum and product of each hexadecimal number are for a D6A, 1A3F88 for b 216BB, 1438D5A for c ACD8F, B051FA2E for d E0BAA8, 92A26ABAE4
Here is how you find the sum and product of each of these pairs of hexadecimal numbers.
a) (1AE)16, (BBC)16
Sum: 1AE + BBC = D6A (in hexadecimal)
Product: 1AE * BBC = 1A3F88 (in hexadecimal)
b) (20CBA)16, (A01)16
Sum: 20CBA + A01 = 216BB (in hexadecimal)
Product: 20CBA * A01 = 1438D5A (in hexadecimal)
c) (ABCDE)16, (1111)16
Sum: ABCDE + 1111 = ACD8F (in hexadecimal)
Product: ABCDE * 1111 = B051FA2E (in hexadecimal)
d) (E0000E)16, (BAAA)16
Sum: E0000E + BAAA = E0BAA8 (in hexadecimal)
Product: E0000E * BAAA = 92A26ABAE4 (in hexadecimal)
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You are one of the quality inspectors at Dart motors and looking after the quality of engine cylinders. Assume that the cylinders capacities are normally distributed with a mean of 1200 and standard deviation of 80 . What will be the probability of a selected engine having capacity a. greater than 1260[1] b. greater than 950 [1] c. 1240 or less d. less than 1130 [1] e. between 1100 to 1150 [2]
Answers
The probability calculations for the given scenarios can be performed using the normal distribution with a mean of 1200 and a standard deviation of 80.
What are the probabilities of a selected engine having capacities greater than 1260, greater than 950, 1240 or less, less than 1130, and between 1100 and 1150?To calculate the probabilities, we can use the standard normal distribution table or statistical software such as R or Python.
a. To find the probability of a selected engine having a capacity greater than 1260, we calculate the z-score as (1260 - 1200) / 80 = 0.75. Using the z-score table or software, we find the probability associated with a z-score of 0.75.
b. For the probability of a selected engine having a capacity greater than 950, we calculate the z-score as (950 - 1200) / 80 = -3.125. Again, using the z-score table or software, we find the probability associated with a z-score of -3.125.
c. To determine the probability of a capacity of 1240 or less, we calculate the z-score for 1240 as (1240 - 1200) / 80 = 0.5. We find the probability associated with a z-score of 0.5.
d. The probability of a selected engine having a capacity less than 1130 can be calculated by finding the z-score for 1130 as (1130 - 1200) / 80 = -0.875. We find the probability associated with a z-score of -0.875.
e. For the probability of a capacity between 1100 and 1150, we calculate the z-scores for both values as (1100 - 1200) / 80 = -1.25 and (1150 - 1200) / 80 = -0.625. Then, we find the probabilities associated with these z-scores and calculate the difference between them to obtain the desired probability.
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A coil having resistance of 7 ohms and inductance of 31.8 mh is connected to 230v,50hz supply.calculate 1. The circuit current 2.the phase angle, 3.power factor, 4 the power consumed
Answers
(1) The current in the circuit is 18.87 A,
(2) The phase angle is 54.97°
(3) The power factor is 0.574
(4) The power consumed is 2491.2 W
(1) To calculate the current in the circuit, first, we need to find the overall impedance of the circuit.
We can calculate the overall impendence of the circuit using the formula below.
Z = √[R²+(2πfL)²]........................ Equation 1Where:
R = resistance of the coilf = FrequencyL = Inductance of the coilZ = Overall impedance of the circuitFrom the question,
Given:
R = 7 ohmsL = 31.8 mH = 0.0318 Hf = 50 Hzπ = 3.14
Substitute these values into equation 1
Z = √[7²+(2×3.14×50×0.0318)²]Z = √(49+99.7)Z = √(148.7)Z = 12.19 ohms.Therefore we use the formula below to calculate the current in the circuit.
I = V/Z.................. Equation 2Where:
V = VoltageI = current in the circuit.Given:
V = 230 V.Substitute into equation 2
I = 230/12.19I = 18.87 A(2) To calculate the phase angle, we use the formula below.
∅ = tan⁻¹(2πfL/R)............... Equation 3Where:
∅ = Phase angle.
Substitute into equation 3
(3) To calculate the power factor, we use the formula below.
pf = cos∅............ Equation 4Where:
pf = power factor.Substitute the value of ∅ into equation 4
pf = cos(54.97°)pf = 0.574.
(4) And Finally to calculate the power consumed we use the formula below.
P = V×I×pf................ Equation 5Where:
P = The power consumedSubstitute the values into equation 5
P = 230(18.87)(0.574)P = 2491.22 W
Hence, (1) The current in the circuit is 18.87 A, (2) The phase angle is 54.97° (3) The power factor is 0.574 (4) The power consumed is 2491.2 W
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1. A transfer girder is to support one symmetrically located column having a factored load of P (5000+200N) KN and is supported on 600mmx600mm square columns. The clear span of the transfer girder is 6m. The overall depth of the beam is (h = 4000mm) and the width of the beam is (b=400mm). Using C25 concrete and S360 reinforcing steel, Design the beam by STM method. (Neglect self-weight of the beam). Note: N=3.
Answers
Answer:
15000 KN.m
Explanation:
To design the transfer girder using the STM (Simplified Theory of Moments) method, we need to follow the steps outlined below:
Step 1: Calculate the factored load (P):
Given: P = 5000 + 200N KN
Let's substitute N = 3 into the equation:
P = 5000 + 200(3) = 5000 + 600 = 5600 KN
Step 2: Calculate the factored moment (Mu):
Mu = P x L^2 / 8
= 5600 KN x (6m)^2 / 8
= 15000 KN.m
Step 3: Calculate the design moment (Md):
Md = Mu / γm
(where γm is the partial safety factor for moment)
The value of γm depends on the design code or standard being used. For example, in Eurocode 2, the value of γm for reinforced concrete beams is typically taken as 1.35. However, since the specific code or standard is not provided in the question, we cannot calculate the design moment without this information.
To proceed with the design, we need to know the value of γm as specified in the relevant design code. Once that value is known, we can calculate the design moment and continue with the design process.
It is advisable to consult a structural engineer or refer to the appropriate design code or standard to obtain the required values and ensure accurate calculations for the design of the transfer girder.
What relates a landscape architect's knowledge of design to the landscape architect's knowledge of law and government?
Answers
Answer:
The landscape architect uses knowledge of legal requirements to inform design choices.
Explanation:
The landscape architect doesn’t only draw on knowledge of law and government to design grounds for public buildings, but will draw on that knowledge quite often on many projects. The landscape architect’s knowledge of design is not purely intuitive but is a product of study and might involve research. The landscape architect’s knowledge of law and government, however, does come into play in making design choices that are consistent with the law and government regulations.
The beam is subjected to the two concentrated loads. Assuming that the foundation exerts a linearly varying load distribution on its bottom, determine the load intensities
�
1
w
1
and
�
2
w
2
for equilibrium if P=500 lb and L=12 ft.
Answers
To determine the load intensities, we need to first find the reactions at the supports of the beam. the load intensities are w1 = 125 lb/ft and w2 = 375 lb/ft for equilibrium if P = 500 lb and L = 12 ft.
Assuming the loads are applied at distances of x1 and x2 from the left support, the reactions at the supports are:
Sum of moments about the left support:
(R2)(12 ft) - (500 lb)(x2) - (1000 lb)(6 ft - x1) = 0
Sum of forces in the vertical direction:
R1 + R2 - 500 lb - 1000 lb = 0
Solving for R1 and R2 gives:
R1 = 750 lb
R2 = 750 lb
Now, to determine the load intensities, we can use the fact that the load distribution on the foundation is linearly varying. We can assume that the load intensity at any point along the beam is proportional to the distance from that point to the left support.
Let w1 and w2 be the load intensities at x1 and x2, respectively. Then:
w1 = (R1 - 500 lb)x1/6 ft
w2 = (R1 - 500 lb)(12 ft - x2)/6 ft
Substituting the values for R1 and solving for w1 and w2, we get:
w1 = 125 lb/ft
w2 = 375 lb/ft
Therefore, the load intensities are w1 = 125 lb/ft and w2 = 375 lb/ft for equilibrium if P = 500 lb and L = 12 ft.
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The following incomplete method is intended to sort its array parameter arr in increasing order.
// postcondition: arr is sorted in increasing order
public static void sortArray(int[] arr)
{
int j, k;
for (j = arr.length - 1; j > 0; j--)
{
int pos = j;
for ( /* missing code */ )
{
if (arr[k] > arr[pos])
{
pos = k;
}
}
swap(arr, j, pos);
}
}
Assume that swap(arr, j, pos) exchanges the values of arr[j] and arr[pos]. Which of the following could be used to replace /* missing code */ so that executing the code segment sorts the values in array arr?
A
k = j - 1; k > 0; k--
B
k = j - 1; k >= 0; k--
C
k = 1; k < arr.length; k++
D
k = 1; k > arr.length; k++
E
k = 0; k <= arr.length; k++
Answers
As it meets the criteria for looping through the unsorted portion of the array and iterating from the first unsorted element up to the current value of j, k = 1; k arr. length; k++.
How can I determine how many elements there are in an unsorted array?We must do a linear search to locate the largest value in an unsorted array by examining each element and keeping note of the location the maximum has been discovered thus far.
Which approach requires the least amount of time to search an entry in an unsorted array?The most popular method of searching an element in an unsorted array is by performing a linear search, which checks each element one by one from start to finish and has an O(n) complexity.
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In unguided medium (free space), the electromagnetic (EM) signal wave spreads as it leaves the transmit antenna. Since the power of the EM signal resides at the surface area of the wave front, signal power is described as signal power density (i.e., watts per area).
a. True
b. False
Answers
Answer:
a. True
Explanation:
A basic 3-input logic circuit has a LOW on one input and a HIGH on the other two inputs, and the output is LOW. What type of logic circuit is it
Answers
Answer:
any of AND, NOR, XOR
Explanation:
An AND gate will give a Low output for any input Low. The logic circuit could be an AND gate.
A NOR gate will give a Low output for any input High. The logic circuit could be a NOR gate.
An XOR gate will give a Low output for an even number of High inputs. The logic circuit could be an XOR gate.
The logic circuit could be any of ...
AND or NOR or XOR
__
Additional comment
What you consider a "basic" gate is not defined here. All of these are catalog items. If you consider only AND, OR, and NOT to be the basic gates, then your answer is AND.
identifies potential new customers and preserves favorable business relationships with past customers
Answers
❎❎❎❎❎❎❎ sorry but that didn't help me that much
During one month, 45 preflight inspections were performed on an airplane at Southstar Airlines. 15 nonconformances were noted. Each inspection checks 50 items. Assuming 2 sigma off-centering, what sigma level does Southstar maintain if this incidence of nonconformance is typical of their entire fleet of airplanes
Answers
The incidence of nonconformance in Southstar Airlines that is typical of their entire fleet of airplanes is needed. We have been given that in one month, 45 preflight inspections were performed on an airplane at Southstar Airlines, 15 nonconformances were noted and each inspection checks 50 items.
Assuming 2 sigma off-centering, what sigma level does Southstar maintain?
From the given, the nonconformance rate is calculated by taking the ratio of the number of nonconformances to the number of items inspected.
Nonconformance rate = 15/ (45 * 50) = 0.0066667 (approx)
Now, we can calculate the Z-score by using the standard normal distribution table
Z-score = 2sigma off-centering = 2
looking up a Z-score table we obtain that 0.0066667 corresponds to 2.11 standard deviations or 2.11 sigma level approx.
Southstar Airlines maintains a sigma level of about 2.11 if this incidence of nonconformance is typical of their entire fleet of airplanes.
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(d) Why might a blue orange be more difficult to represent by the developed brain than an orange-coloured orange. Explain your answer. How might this example inform the localist versus distributed debate? [3 marks] (e) Assuming a two-by-two input array, depict a set of four similar and four dissimilar input patterns. [2 marks]
Answers
A blue orange may be more difficult to represent by the developed brain compared to an orange-colored orange due to the mismatch between the expected color association and the perceived color.
This example highlights the challenges of representing an object with an unconventional or unexpected color, which can inform the localist versus distributed debate in terms of how the brain processes and represents sensory information.
The human brain has developed associations between certain objects and their typical colors based on prior experiences and learned associations. For example, oranges are commonly associated with the color orange. When encountering an orange-colored orange, the brain can easily match the perceived color with the expected color association.
However, when presented with a blue orange, there is a mismatch between the expected color association (orange) and the perceived color (blue). This discrepancy can lead to cognitive processing difficulties as the brain tries to reconcile the unexpected color with the known object. The representation of the blue-orange may be more challenging because it requires overriding the preexisting color association and establishing a new color-object association.
This example informs the localist versus distributed debate, which pertains to how sensory information is processed and represented in the brain. The localist perspective suggests that specific representations are localized to distinct brain regions, while the distributed perspective proposes that representations are distributed across multiple brain regions. The difficulty in representing a blue orange demonstrates the complexities involved in integrating and reconciling conflicting sensory information, supporting the argument for a distributed processing approach where multiple brain regions work together to form representations.
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a technician is bench testing a reciprocating compressor. during testing the maximum achievable discharge pressure was 120 psig, even though the low side intake of the compressor was open to the atmosphere. the pressure held when the compressor was off. what is a possible cause of this condition
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Based on the given information, we can conclude that Valve malfunction should be a possible cause of this condition.
There are several possible causes for a reciprocating compressor to achieve a maximum discharge pressure of 120 psig, even though the low side intake of the compressor was open to the atmosphere and the pressure held when the compressor was off. Some possible causes could include:
Valve malfunction: The compressor's discharge valve may be stuck in a closed position or partially blocked, causing the pressure to build up in the discharge line even though the low side intake is open to the atmosphere. This could be due to debris or dirt accumulation, valve wear or damage, or improper installation.Cylinder leak: There may be a leak in one or more of the compressor's cylinders, allowing the pressure to build up in the discharge line even when the compressor is not running. This could be due to worn piston rings, damaged valves, or other cylinder-related issues.Pressure regulator failure: If the compressor has a pressure regulator or relief valve that is not functioning properly, it may not be relieving excess pressure from the discharge line, resulting in the high pressure reading even when the compressor is not running.Gauge or sensor error: It's also possible that there could be an issue with the pressure gauge or sensor used to measure the discharge pressure, such as calibration error or malfunction, resulting in inaccurate readings.learn more about discharge pressure here:
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1. explain the concepts of sampling and sampling rate. then, listen to this 2 khz file, this 8khz file, and this 44.1 khz file and compare their sound
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Sampling refers to the process of capturing and representing continuous signals as a discrete set of values at specific time intervals.
How is this so?The sampling rate is the number of samples taken per second,typically measured in kilohertz (kHz).
The 2 kHz file has a lower sampling rate,resulting in a lower frequency range andpotential loss of high-frequency details.
The 8 kHz file has a slightly better quality, capturingmore frequency information.
The 44.1 kHz file offers the highest quality, preserving a wider range of frequencies and providing a more accurate representation of the original sound.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
If the voltage increases in a circuit, what happens to the current (amperes) if the resistance stays
the same?
A) Decreases
C) Increases
B) Remains the same
D) Cannot be determined
Answers
Answer:
b remains the same
Explanation:
voltage and amps have no connection
the electricity used to rin your clothes dryer is normally 220V 18-24A
the voltage in your car's battery is usually 12V 20-30A
see they are approximately the same amperage but very different voltage
System grounding on a power system means electrically connecting the __?__ of every wye-connected transformer or generator to earth.
Answers
Answer: Neutrals
Explanation: System grounding on a power system is a term used to describe the entire processes involved when a neutral is used as the conductor to connect to the solid earth. This ensures that power is generated. This is usually done using either an inductor, an impendance or a resistor. It is very important and necessary to carry out a proper grounding of a power system in order to ensure the safety of the equipment and the personnel etc