Modify the program to print the average as well as the sum. Hint: You don't actually have to change the loop, but rather change what you print.
import java.util.Scanner;
public class ArraySum {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_ELEMENTS = 8; // Number of elements
int[] userVals = new int[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
// Prompt user to populate array
System.out.println("Enter " + NUM_ELEMENTS + " integer values...");
for (i = 0; i < NUM_ELEMENTS; ++i) {
System.out.println("Value: ");
userVals[i] = scnr.nextInt();
}
// Determine sum
sumVal = 0;
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
System.out.println("Sum: " + sumVal);
return;
}
}
Answers
To modify the program to print the average as well as the sum, you can add a new variable called "averageVal" and compute the average by dividing the sumVal by the number of elements (NUM_ELEMENTS). Then, you can print the average value along with the sum value. Here is the modified code:
```java
import java.util.Scanner;
public class ArraySum {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_ELEMENTS = 8; // Number of elements
int[] userVals = new int[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
int averageVal = 0; // For computing average
// Prompt user to populate array
System.out.println("Enter " + NUM_ELEMENTS + " integer values...");
for (i = 0; i < NUM_ELEMENTS; ++i) {
System.out.println("Value: ");
userVals[i] = scnr.nextInt();
}
// Determine sum
sumVal = 0;
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
// Compute average
averageVal = sumVal / NUM_ELEMENTS;
// Print sum and average
System.out.println("Sum: " + sumVal);
System.out.println("Average: " + averageVal);
return;
}
}
```
Note that the averageVal variable should be declared as a double if you want to get a more accurate result. In that case, you should also cast the sumVal and NUM_ELEMENTS to double before dividing them. Here is the modified code with double averageVal:
```java
import java.util.Scanner;
public class ArraySum {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_ELEMENTS = 8; // Number of elements
int[] userVals = new int[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
double averageVal = 0.0; // For computing average
// Prompt user to populate array
System.out.println("Enter " + NUM_ELEMENTS + " integer values...");
for (i = 0; i < NUM_ELEMENTS; ++i) {
System.out.println("Value: ");
userVals[i] = scnr.nextInt();
}
// Determine sum
sumVal = 0;
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
// Compute average
averageVal = (double)sumVal / (double)NUM_ELEMENTS;
// Print sum and average
System.out.println("Sum: " + sumVal);
System.out.println("Average: " + averageVal);
return;
}
}
```
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To modify the program to print the average as well as the sum, you can add a new variable called "averageVal" and compute the average by dividing the sumVal by the number of elements (NUM_ELEMENTS). Then, you can print the average value along with the sum value. Here is the modified code:
```java
import java.util.Scanner;
public class ArraySum {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_ELEMENTS = 8; // Number of elements
int[] userVals = new int[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
int averageVal = 0; // For computing average
// Prompt user to populate array
System.out.println("Enter " + NUM_ELEMENTS + " integer values...");
for (i = 0; i < NUM_ELEMENTS; ++i) {
System.out.println("Value: ");
userVals[i] = scnr.nextInt();
}
// Determine sum
sumVal = 0;
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
// Compute average
averageVal = sumVal / NUM_ELEMENTS;
// Print sum and average
System.out.println("Sum: " + sumVal);
System.out.println("Average: " + averageVal);
return;
}
}
```
Note that the averageVal variable should be declared as a double if you want to get a more accurate result. In that case, you should also cast the sumVal and NUM_ELEMENTS to double before dividing them. Here is the modified code with double averageVal:
```java
import java.util.Scanner;
public class ArraySum {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_ELEMENTS = 8; // Number of elements
int[] userVals = new int[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
double averageVal = 0.0; // For computing average
// Prompt user to populate array
System.out.println("Enter " + NUM_ELEMENTS + " integer values...");
for (i = 0; i < NUM_ELEMENTS; ++i) {
System.out.println("Value: ");
userVals[i] = scnr.nextInt();
}
// Determine sum
sumVal = 0;
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
// Compute average
averageVal = (double)sumVal / (double)NUM_ELEMENTS;
// Print sum and average
System.out.println("Sum: " + sumVal);
System.out.println("Average: " + averageVal);
return;
}
}
```
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Related Questions
A body, with a volume of 2 m3, weighs 40 kN.
Determine its weight when submerged in a liquid
with S 1.59.
Answers
Answer:
The weight of the body when submerged in the liquid will be (40 kN) * (1.59) = 63.6 kN.
Explanation:
The values of four out of a sample of five deviations are: -5, +2, +4, -2. What is The value of the fifth deviation?
Answers
Answer:
The fifth deviation is +1
Explanation:
Given
\(Deviations = -5, +2, +4,-2\)
Required
Determine the fifth deviation
Represent the fifth deviation with x.
As a theorem, the sum of deviations from mean is always 0.
So, we have:
\(-5 +2 +4-2+x = 0\)
\(-1+x = 0\)
Add 1 to both sides
\(1 -1+x = 0 +1\)
\(x = 0 +1\)
\(x= +\ 1\)
Hence, the fifth deviation is +1
g When constructing a railroad, two connecting rails need to be given a small separation, to allow for expansion during the summer months. If the beams are made of steel in a factory at 23oC at a length of 3 m, and they can be expected to heat up to temperatures of 50oC, what should the spacing between steel beams be
Answers
When constructing a railroad, two connecting rails need to be given a small separation, to allow for expansion during the summer months.
If the beams are made of steel in a factory at 23oC at a length of 3 m, and they can be expected to heat up to temperatures of 50oC, what should the spacing between steel beams beThe length of the rail is 3 m or 300 cm. Let's assume that the rail expands equally from both sides. So the expansion of each rail would be half of the total expansion, i.e. (50-23) / (2 x 100) = 0.135 cm/cm.∆L = L0 α ∆TSubstituting values:∆L = 300 x 0.135 x 27 = 1094.5 micronsNow, this is the total expansion in both the rails together, so the expansion in one rail would be 1094.5 / 2 = 547.25 microns.
∆L = αL0 ∆T and α = coefficient of linear expansionThe distance between the rails is the difference in length after expansion. This would be 547.25 / 100 = 5.4725 cm. So, the distance between rails should be increased by 5.4725 cm. Hence the spacing between steel beams should be 5.4725 cm more than the original distance.
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When responding to a railroad incident, most railroad companies advise that all vehicles be kept at least _____ from the tracks.
Answers
Answer:
Twenty feet from the tracks
Explanation:
can someone please help me with this
I've an exams tomorrow
Answers
Answer:
I am in Eight Grade
Explanation:
What should you do before you start welding?
Answers
Explanation:
1. Weld only in authorized areas. Make sure the area is dry, chemical free, and well ventilated.
2. Inspect the equipment before starting to use it.
3. Keep other people away, unless they are authorized to be there and are wearing the appropriate personal protective equipment.
A mass of 10 g of oxygen fill a weighted piston-cylinder device at 20 kPa and 106°C. The device is now cooled until the temperature is O°C. Determine the change of the volume of the device during this cooling. The gas constant of oxygen is R= 0.2598 kPa.m3/kg.K. The change of volume is ______ m3
Answers
The change of volume of the device during the cooling process is 0.0448 m³.
How much does the volume of the device decrease when it is cooled from 106°C to 0°C, given that it initially contains 10 g of oxygen at 20 kPa?
During the cooling process, the volume of the device decreases by 0.0448 m³.
This can be calculated using the ideal gas law, which states that PV = mRT, where P is the pressure, V is the volume, m is the mass, R is the gas constant, and T is the temperature. By rearranging the formula to solve for V, we have V = (mRT) / P.
Plugging in the given values and solving the equation, we find that the change in volume is 0.0448 m³.
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Question 2
Salt in crude oil must be removed before the oil undergoes processi
fed to a washing unit where fresh water fed to the unit mixes with t
the sal contained in the oil. The oil (containing salt but no water), be
can be removed at the top of the washer. If the "spent" wash water
oil contains 5% salt, determine the concentration of the salt in the w
crude oil (with salt) to water used is 4:1.
Answers
The concentration of the salt in the w crude oil (with salt) to water used is 4:1 is 0.0061.
What is crude oil?
Crude oil is a hydrocarbon mixture that exists in liquid form in natural subterranean reservoirs and stays liquid at atmospheric pressure after passing through surface separation facilities.
The salt content of "spent" wash water is 15%.
5% of crude oil is salt.
The crude oil (with salt) to water ratio utilised is 4: 1.
Crude oil fraction:
95% of crude oil = 0.95
0.95F1 = x1E1
0.95(100) = x1E1
95= x1E1
E1 = 95/X1
wash water fraction:
15% of wash water = 100% -15% = 85%
= F2 = 0.85E2
salts fraction:
0.05F1 = (1-X1)E1 + 0.15E2
0.05F1 = (1-X)95/X1 + 0.15(F2/0.85)
0.05F1 = 95/X1 - 95 + 0.15(F2/0.85) (SINCE = 95.588 = 95/X1 = 99.38)
0.05(100) = 95/X1 - 95 + 17.61(1/4F1)
5 = 95/X1 - 95 + 4.41
Fraction of salts = 1- X1 = 0.0061
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a venturi meter with a 7 in diameter throat is installed in a 14 in diameter water line. the venturi is perfectly smooth, so that the discharge coefficient is 1.00. an attached mercury manometer registers a 3 in differential. what is the volumetric flow rate?
Answers
Micrometer for brake rotors. For air disc brakes, the steering axle brake lining/pad thickness must be at least 3.2 mm (1/8 inch), and for hydraulic disc, drum, and electric brakes, it must be at least 1.6 mm (1/16 inch).
Every 45° (1/8 of a rotation), take a measurement of the brake rotor thickness of 0.40 inches (10mm) inside the outside circumference of the brake rotor. 6. Compare the lowest result obtained to the brake rotor's minimum thickness requirements. Depending on the vehicle, replacement brake pads can range in thickness from roughly 3/8" to 1/2". When the pads are down to around 1/4 inch, some shops advise changing them; others advise doing so at 1/8 or when only 20 to 25 percent of the original thickness remains.
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Determine the initial void ratio, the relative density and the unit weight (in pounds per cubic foot) of the specimens for each sand.
Answers
The initial void ratio is the parameter which is used to show the structural foundations for each specimen of sand so that the method and speed of compression would be measured.
Relative density is the mass per unit volume of each specimen of sand which is measured and it has to do with the relative ratio of the density of the sand.
Unit weight is the the exact weight per cubic foot of the sand which is measured.
Please note that your question is incomplete so I gave you a general overview to help you better understand the concept
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Hãy tính phản lực liên kết tại ngàm A, bản lề C và gói di động D biết p=400N/m
P1=100N
P2=200
P3=300
M1=100N/m
N2=200N/m
Answers
Answer:
say in English plz I don't understand
Exam
3. Your employer has asked you to remove old metal plating from the worksite. The metal plating is
heavy and has sharp edges. What PPE should you use?
Select the best answer(s). There may be more than one
(4 Points)
A respirator
Steel-toed boots
Gloves
Safety glasses
AVAL
Answers
Answer:
Gloves
Explanation:
Gloves are personal protective equipment that a user wears on hands to protect against scrapes and scratches. Some gloves are improved in a manner that they protect against cuts, chemicals and contaminants. Gloves should always be worn when performing a task that requires hands-handling.
Answer:
steel toed shoes and gloves
Explanation:
Segment A in the urban four-lane divided arterial reference population will be screened by the "Excess Predicted Average Crash Frequency Using SPFs" performance measure. Segment A is 0.60 mi long. If the sliding window method is used to study this segment with a window of 0.30-mi and 0.10-mi increment, how many times will the performance measure be applied on Segment A?
Answers
The sliding window technique is utilized to identify the crash frequency of a certain region. A performance measure called "Excess Predicted Average Crash Frequency Using SPFs" will be used to screen Segment A in the urban four-lane divided arterial reference population.
The segment is 0.60 mi long. Let's determine the number of times the performance measure will be applied to Segment A using the sliding window method.In 0.30-mi windows, the section is analyzed. The increment is 0.10 miles long. As a result,0.30 mi long window = 0.60 / 0.30 = 2 windows.0.10 miles long increment = 0.60 / 0.10 = 6 increments.So, the total number of applications = number of windows × number of increments in each window= 2 × 6= 12.The performance measure will be used 12 times on Segment A. Answer: In 200 words. The sliding window technique is utilized to identify the crash frequency of a certain region. A performance measure called "Excess Predicted Average Crash Frequency Using SPFs" will be used to screen Segment A in the urban four-lane divided arterial reference population. The segment is 0.60 mi long. Let's determine the number of times the performance measure will be applied to Segment A using the sliding window method.In 0.30-mi windows, the section is analyzed. The increment is 0.10 miles long. As a result,0.30 mi long window = 0.60 / 0.30 = 2 windows.0.10 miles long increment = 0.60 / 0.10 = 6 increments.So, the total number of applications = number of windows × number of increments in each window= 2 × 6= 12.The performance measure will be used 12 times on Segment A.
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Does anyone understand philosophy and can explain pragmatism in the philosophy of religion ?
Answers
Religion: Philosophy of religion is the philosophical study of the meaning and nature of religion. It includes the analyses of religious concepts, beliefs, terms, arguments, and practices of religious adherents. The scope of much of the work done in philosophy of religion has been limited to the various theistic religions.
A plant might be emitting some dangerous pollutants that are environmentally harmful, but completely eliminating them would be so expensive that the plant would have to close, throwing many local inhabitants out of work. Assuming there is an obligation both to preserve jobs and to protect the environment. What is the best technique that should be used to resolve this problem?
Select one:
a. The convergence and divergence techniques
b. The Utilitarian approach
c. The creative middle way
d. The line drawing technique
Answers
Answer: c. The creative middle way
Explanation:
As there is both an obligation to preserve jobs and to protect the environment, a creative middle way which involves compromise would be most effective.
The company involved should process and remove the worst pollutants alone while leaving others so that the process will not be so expensive that they have to close down.
They will do this till a better and more environmentally beneficial solution can be found at which point they can then clean up the previous pollutants with the hope that they have not irrecoverably damaged the environment.
A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated the field conditions, the total stress parameters were measured to be C total = 250 lb/ft2 and φ total = 29°. Estimate the shear strength on a horizontal plane at a depth of 12 ft below the ground surface at this site in lbs/ sq ft
Answers
Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Explanation:
Given that;
Weight of soil r = 118 lb/ft³
stress parameter C = 250 lb/ft²
φ total = 29°
depth Z = 12 ft
The shear strength on a horizontal plane at a depth of 12ft
ζ = C + δtanφ
where δ = normal stress
normal stress δ = r × z = 118 × 12 = 1416
so
ζ = C + δtanφ
ζ = 250 + 1416(tan29°)
ζ = 250 + 1416(tan29°)
ζ = 250 + 784.9016
ζ = 1034.9015 lb/ft²
Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
The predator uav has the following characteristics: has the following characteristics: wingspan = 14.85 m, wing area = 11.45 m2, maximum weight = 1020 kgf, and fuel weight = 295 kgf. the power plant is a rotax four-cylinder, four-stroke engine of 85 horsepower driving a two-blade, variable-pitch pusher propeller. assume that the oswald efficiency factor is 0.7, the zero-lift drag coefficient is 0.03, the propeller efficiency is 0.9, and the specific fuel consumption is 0.2 kgf of fuel per horsepower per hour. calculate the following:
1: maximum velocity at sea level.
2: the maximum range
3: the maximum endurance
Answers
The maximum velocity at sea level can be found using the following equation:
V_max = sqrt((2 * W) / (rho * S * CL_max))
where:
W = maximum weight = 1020 kgf
rho = air density at sea level = 1.225 kg/m^3
S = wing area = 11.45 m^2
CL_max = maximum lift coefficient = (2 * W) / (rho * V^2 * S)
To find CL_max, we need to assume a value for the velocity V and iterate until convergence. Let's start by assuming V = 70 m/s:
CL_max = (2 * 1020 kgf) / (1.225 kg/m^3 * (70 m/s)^2 * 11.45 m^2) = 1.87
Now we can use this value to find the maximum velocity:
V_max = sqrt((2 * 1020 kgf) / (1.225 kg/m^3 * 11.45 m^2 * 1.87)) = 35.5 m/s
Therefore, the maximum velocity of the Predator UAV at sea level is approximately 35.5 m/s.
Maximum Range:
The maximum range can be found using the following equation:
R = (L/D) * (1/OE) * ln(Wi/Wf)
where:
L/D = lift-to-drag ratio = CL / CD
CL = lift coefficient = W / (0.5 * rho * V^2 * S)
CD = drag coefficient = CD_0 + (CL^2 / (pi * e * AR))
CD_0 = zero-lift drag coefficient = 0.03
e = Oswald efficiency factor = 0.7
AR = aspect ratio = (wingspan)^2 / S
OE = overall efficiency = propeller efficiency * engine efficiency
propeller efficiency = 0.9
engine efficiency = 0.85 (assuming 85 horsepower for the engine)
Wi = initial weight = maximum weight + fuel weight = 1020 kgf + 295 kgf = 1315 kgf
Wf = final weight = maximum weight
We can start by assuming a value for the velocity V and iterating until convergence. Let's start with V = 25 m/s:
CL = 1315 kgf / (0.5 * 1.225 kg/m^3 * (25 m/s)^2 * 11.45 m^2) = 1.67
AR = (14.85 m)^2 / 11.45 m^2 = 19.3
CD = 0.03 + (1.67^2 / (pi * 0.7 * 19.3)) = 0.071
L/D = 1.67 / 0.071 = 23.5
OE = 0.9 * 0.85 = 0.765
R = 23.5 * (1/0.765) * ln(1315 kgf/1020 kgf) = 393 km
Now we can try a different value for V, let's say V = 30 m/s:
CL = 1315 kgf / (0.5 * 1.225 kg/m^3 * (30 m/s)^2 * 11.45 m^2) = 1.24
AR = (14.85 m)^2 / 11.45
describe a process that would satisfy the conservation of energy principle but does not actually occur in nature
Answers
The only process I can think of that would satisfy the conservation of energy principle but does not occur in nature is a perpetual motion machine.
Working principle of perpetual motion machinePerpetual Motion Machine would produce work indefinitely without any external input of energy, thus violating the first law of thermodynamics which states that energy cannot be created or destroyed, only converted from one form to another.
While it is theoretically possible to design a machine that appears to produce more energy than it consumes, such a machine cannot exist in reality due to the various energy losses that occur in any real-world system.
These losses can occur due to factors such as friction, heat transfer, and resistance in electrical circuits, among others.
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Technician A says that hoods are designed with reinforcements to prevent folding during a collision. Technician B says that some hoods are made from reinforced plastic. Who is right?
Answers
Technician A is wrong.
Usually, hoods have what is called "Crush Zones" underneath the panels. The function of the Crush Zone is to prevent the hoods, during a collision, from entering into the passenger space. The crush zones allow the hoods to fold instead.
Technician B is right.
Automobile producers now make use of a hybrid form of hood that consists of fiberglass reinforced with plastic.They are mostly used for trucks that have a low volume of production. The hood is built using a process called Resin Transfer Model (RTM).
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Can anyone tell me what rock this is?
Answers
Answer: answer is B
Explanation:
Answer: metamorphic rock
Explanation:
1. types of ecosystem ?
2. explain each ecosystem
Answers
a c-section specimen is designed to tolerate a stress-concentration factor for 1.75. calculate the allowable normal strength in the c-section if the material used to make the section has a yield strength of 84 kpsi.
Answers
The allowable normal strength in the c-section is 48000 pounds per square inch.
The allowable stress depends on both the factor of safety imposed on the object and the yield strength or stress at which an object will be permanently damaged. To calculate the allowable normal strength we can divide the yield strength by the factor of safety.
To determine the allowable normal strength output we can use this equation below:
The allowable normal strength = The number yield strength : A stress-concentration factor
The number yield strength is 84 kpsi.
Then convert kpsi to psi : 84 kpsi = 84000 psi
A stress-concentration factor is 1.75
The formula to find allowable normal strength output is:
84000 psi : 1.75 = 48000
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If an athlete can row at a rate of 50 m/min, how many days would it take to cross the Atlantic (≈3000 mi)?
Answers
The kinematics we can find the time to cross the Atlantic is 67 days.
The kinematics studies the movement of the body making relationships between the position, the speed and the acceleration of the same.
The average velocity is defined as the relation between the displacement between the time of the interval
v = \(\frac{\Delta x}{t}\)
Δt = \(\frac{\Delta x}{v}\)
Where v is the velocity, x the displacement t time
In this case they indicate the displacement is Δx = 3000 mi and the speed is v = 50 m / min
The system of units allow data to be exchanged with precision and safety, for this there is currently the international system of measurements (SI), where the unit of length is the meter and the unit of time is the second, let's reduce the magnitudes given to these units.
Δx = 3000 mi ( ) = 4.828 10⁶ m
v = 50 m / min ( ) = 0.833 m / s
Now we can calculate the time to cross the Atlantic
Δt = 4.828 10⁶ / 0.833
Δt = 5.796 10⁶ s
Let's reduce to days
Δt = 5.796 10⁶ s ( ) ( )
Δt = 67 days
In conclusion using kinematics we can find the result of the time to cross the Atlantic is 67 days.
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Of the following, which are the most important parts on any vehicle?
a) wheel bearings
b)Tires
c) windshield wipers
d) Spurving bearings
Answers
Answer:
tires
Explanation:
without tyres you can not drive.
Answer:
d spurving bearings
Explanation:
because IN a car you can't move without them.in the old days they were using wood as tires
Cellular network towers are configured in such a way so that they avoid what type of problem?
Answers
Answer:
They are configured this way to avoid overlap issues.
Explanation:
Identify the right components for gsm architecture that consists of the hardware or physical equipment such as digital signal processors, radio transceiver, display, battery, case and sim card
Answers
The right components for gsm architecture that consists of the hardware or physical equipment such as digital signal processors, radio transceiver, display, battery, case and sim card is the Mobile station.
What are the 4 main components?In GSM, a cell station includes 4 fundamental additives: Mobile termination (MT) - gives not unusualplace features consisting of: radio transmission and handover, speech encoding and decoding, blunders detection and correction, signaling and get right of entry to to the SIM. The IMEI code is connected to the MT.
Under the GSM framework, a cell tele cell smartphone is called a Mobile Station and is partitioned into wonderful additives: the Subscriber Identity Module (SIM) and the Mobile Equipment (ME).
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A resistor and a capacitor are connected in series across a 150 Vac supply. When
the frequency is 40 Hz the current is 5 A, and when the frequency is 50 Hz the
current is 6 A. Find the resistance and capacitance for the of the resistor and
capacitor respectively.
Answers
Explanation:
for 40hz
since they are in series they will have the same amper
so R=30ohm
C=30F
for 50Hz
R=25
C=25
Tech A says that during troubleshooting, you should never disconnect an electronic control unit or module that is powered up. Tech B says that when flashing an electronic control unit or module, make sure no power loss or disconnect occurs, as the electronic control unit or module may be damaged. Who is correct?
Answers
Answer:
TECH B
Explanation:
in a ________, the wheel flange is part of the axle, which is supported by a single bearing assembly (usually a ball or cylindrical roller bearing style) near the flange end of the axle.
Answers
In a bearing cage, the wheel flange is part of the axle, which is supported by a single bearing assembly (usually a ball or cylindrical roller bearing style) near the flange end of the axle.
What is the process of wheel bearing?A wheel hub bearing, hub assembly, wheel hub unit, or hub and bearing assembly, the wheel hub assembly is a crucial part of your steering system contributing to the safe steering and handling of your vehicle.
Most wheel bearing assemblies include the following components: an outer race, an inner race, roller bearings or ball bearings, and a bearing cage in order to hold the rollers or balls in place.
Ball bearings are rolling-element bearings that use balls to maintain the separation and distance between the bearing races. They are designed to reduce rotational friction while supporting both radial and axial loads.
Therefore, in a bearing cage, the wheel flange is part of the axle, which is supported by a single bearing assembly (usually a ball or cylindrical roller bearing style) near the flange end of the axle.
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Which of the following are among the fastest growing occupations?
a. Computer specialists
b. Engineers
c. Systems analysts
d. All of the above
Answers
Employment growth is often used as a measure of economic expansion and a test for domestic economic health.
Installing and repairing computer hardware and software is typically a responsibility of a Computer specialist. They meet the needs of customers, review and troubleshoot equipment, carry out upgrades, as well as start debating the extent of client reparations or restitution.Engineers are professionals who invent, design, analyze, construct and test machinery, complex structures, frameworks, gadgets. These materials satisfy functional goals and demands while taking into account the limits placed by practicalities, regulatory oversight, safety, and costs.Analysts create diagrams that assist computer network designers and architects.In this, the system's architects, indicate the level systems and processes of an organization as well as design solutions to improve the organizational framework.In this question all the choices were interlinked with each other therefore, the final answer is "Option d".
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