Mercury is a liquid with a density of 13.6 g/ml. How many pounds
of mercury will 16.45 fluid ounces weigh? (Round your answer to
2 places after the decimal)

Explanation:

Divide the distance between the nuclei of the atoms by two if the bond is covalent

The pH of a 0.25 M solution of NaNO2= 6.65.

Given the concentration of NaNO2, we can find the concentration of NaOH and HNO2 as follows:

NaNO2 = 0.25 MNaOH = HNO2 = x

(since they have equal concentrations due to the stoichiometry of the reaction)

Thus, we can write the equilibrium constant expression as:

Ka = x^2/0.25

Now, let's solve for x:

x^2 = 0.25 x 4.5 x 10^-4x = √(0.25 x 4.5 x 10^-4) = 0.015

This value represents the concentration of both HNO2 and NaOH. Since we are interested in pH, we need to find the concentration of H+ ions using the following equation:

Kw = [H+][OH-]

Since we have found the concentration of OH- (which is the same as the concentration of NaOH),

we can solve for H+:

Kw = 1.0 x 10^-14[H+][0.015] = 1.0 x 10^-14[H+] = 6.7 x 10^-13

Finally, we can find pH:

pH = -log[H+]pH = -log(6.7 x 10^-13)pH = 6.65

Therefore, the correct option is d) pH = 6.65.

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A basic amino acid has an R group that contains ( D) a carboxyl group.

Acid is a substance that has a pH level of lower than 7.0 and is capable of corroding or dissolving other substances. It is usually found in aqueous solutions and is a highly reactive substance. Examples of acid include sulfuric acid, hydrochloric acid, nitric acid and acetic acid. These are used in a variety of industries such as food production, industrial cleaning and chemical engineering. Acid is also used in the laboratory for titrations, pH testing and other experiments. Acids can be dangerous if mishandled and can cause skin, eye and respiratory irritation and even chemical burns.

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(diagram below)

1. has two electron shells, so draw two rings around the nucleus

2. has 4 electrons, and since the first shell always has two the second shell would have 2 as well (to add up to four). this makes sense, because the description says that Be has 2 valence electrons

3. Draw 4 protons inside the grey circle (the nucleus)

4. Draw 5 neutrons inside the grey circle too (the nucleus)

they don't have to be in any particular order, hope this helps!

Beryllium (Be) atom has 5 neutrons, 4 electrons and 4 protons. It has two electron shells as it is in the second period of the periodic table.

Only two electrons can fit in the first shell, which is the innermost shell. Beryllium has two electrons in its initial shell. There are additionally 2 electrons in the second shell, which is the outermost shell for beryllium. Valence electrons are the moniker for these outermost electrons.

The electron configuration of beryllium is 1s² 2s², where the superscript refers to the number of electrons in each orbital and shell. The two electrons in the 1s orbital of the first shell are denoted by the symbol 1s², while the two electrons in the 2s orbital are denoted by the symbol 2s².

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The highest home radon concentration levels are most likely to be found in: c. Basements

Radon is a radioactive gas that comes from the natural decay of uranium in soil, rock, and water. It typically moves up through the ground and into homes through cracks and other holes in the foundation. Basements are closest to the ground and have more direct contact with the soil, which leads to higher radon concentration levels compared to other areas of the home.Radon gas enters homes through the foundation and accumulates in damp, low-lying areas such as basements, crawl spaces, and other areas with poor ventilation. Upstairs halls, dining areas, and near windows are not typically areas where radon gas concentrations are high.

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Stack effect? I'm not totally sure about this...

Explanation:

Large amount of tiny particles of water droplets, dust and smoke are present on a misty day. These tiny particles in the air scatter blue colour of white light passing through it. When this scattered light reaches our eyes, the smoke appears blue.

Answer:

Evaporation

Explanation:

Students are to mix the solvent to dilute completely,and get and evaporation dish,candle(heat),tripod stand...pour the solution in the evaporation dish and place it on tripod stand above the candle wait for some time the water will change into gas and to get the water they have to cover the evaporating and direct it to a different container to get the water and salt

The oxidation product of treating the given alkene with a peroxyacid reagent is the epoxide.

The addition of oxygen to a molecule or the removal of hydrogen from a molecule are both examples of oxidation. Primary alcohols can be oxidized to aldehydes, which can then be oxidized further to carboxylic acids. Originally, the term oxidation was used to describe reactions in which an element combines with oxygen.

A molecule loses electrons or increases its oxidation state as a result of oxidation. Electrons lost by a molecule during oxidation are gained by another molecule that is reduced during the process.

Alkenes on oxidation with peroxyacids give peroxides. The oxidation product is the epoxide. Because, oxidation of alkene to epoxide has occured. Peracid is reduced to acid. Thus, the acid formed is the reduction product.

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The statement "the Bohr model was based on the helium atom and rings around the nucleus are called orbits" is partially true and partially false.

The Bohr model was actually based on the hydrogen atom, not the helium atom. However, it is true that the rings around the nucleus are called orbits. So, the correct answer would be that the statement is both true and false due to the inaccuracy regarding the atom the model was based on.

The statement mentioned in the question is not entirely accurate. The Bohr model was based on the hydrogen atom, not the helium atom. The Bohr model was developed to explain the hydrogen atom's atomic structure, which is simpler than the helium atom's atomic structure. The hydrogen atom has one electron and one proton, whereas the helium atom has two electrons and two protons.

On the other hand, the second part of the statement is accurate. The rings around the nucleus in the Bohr model are called orbits. These orbits are specific, quantized energy levels that electrons can occupy in an atom. When an electron transitions between these energy levels, it emits or absorbs a photon of specific energy, which gives rise to the spectral lines observed in atomic spectra.

Therefore, the statement "the Bohr model was based on the helium atom and rings around the nucleus are called orbits" is partially true and partially false. The first part of the statement is incorrect because the Bohr model was based on the hydrogen atom, not the helium atom. The second part of the statement is accurate because the rings around the nucleus in the Bohr model are called orbits.

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Hi there!

\(\large\boxed{2 m/s}\)

Use the equation:

d / t = s where:

d = distance (m)

t = time (s)

s = speed (m/s)

Plug in the given values into the equation:

10 / 5 = s

s = 2 m /s

Zinc will react with lead nitrate but not calcium chloride because zinc is higher than lead on the reactivity series.

The reactivity series of metals can be seen in the attached image.

From the image, Zn is seen as being less reactive than Ca but more reactive than Pb. The higher the location of a metal on the series, the more its reactivity.

Thus, Zn cannot displace Ca in CaCl2 and thus will not react. However, Zn can displace Pb from PbNO3 and thus will react.

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Among various electrochemistry technologies, lithium-ion batteries are considered the most cost-efficient due to their widespread use, decreasing prices, and high energy density.

Lithium-ion batteries have emerged as the dominant technology for energy storage in portable electronics, electric vehicles, and renewable energy systems. They offer a combination of high energy density, long cycle life, and relatively low self-discharge rates compared to other electrochemical technologies. These factors make them highly cost-efficient in a variety of applications.

One example of the cost efficiency of lithium-ion batteries can be seen in the electric vehicle (EV) market. Over the years, advancements in lithium-ion battery technology and increased production scale have led to significant cost reductions. This has resulted in a decline in the prices of EVs, making them more accessible to consumers. The cost efficiency of lithium-ion batteries has also been demonstrated in the renewable energy sector. Energy storage systems based on lithium-ion batteries allow for efficient integration of intermittent renewable energy sources, such as solar and wind power, into the grid. This helps stabilize the grid and reduce reliance on fossil fuels.

Furthermore, the high energy density of lithium-ion batteries enables compact and lightweight designs, making them suitable for portable electronics like smartphones and laptops. This not only enhances user convenience but also contributes to cost efficiency by reducing material and transportation costs. Additionally, the long cycle life of lithium-ion batteries ensures durability and longevity, further enhancing their cost efficiency as they require fewer replacements over their lifespan.

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The given chemical equation represents a double displacement reaction, also known as a precipitation reaction. In this type of reaction, the cations and anions of two ionic compounds switch places, forming two new ionic compounds.

One of the products formed in this reaction is a solid precipitate, which separates from the solution.
In the given equation, aluminum hydroxide (Al(OH)3) reacts with sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3) and water (H2O). The aluminum ions (Al3+) from the reactant compound combine with sulfate ions (SO4 2-) from the acid to form the product compound. Meanwhile, the hydroxide ions (OH-) from the aluminum hydroxide react with the hydrogen ions (H+) from the sulfuric acid to form water.
Overall, this is a balanced chemical equation that represents a double displacement or precipitation reaction, where a solid precipitate is formed from the reaction between two aqueous solutions.

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Answer:

A pure substance consists only of one element or one compound and a mixture consists of two or more different substances, not chemically joined together.

So, a mixture is like mixing - let's say - sugar and rice together (dry BTW), but you can clearly see both substance are not chemically mixed together, if that makes sense. Thus, you can easily separate them out.

True. An alloy is a solid solution consisting of two or more metallic elements, or a metallic element and a non-metallic element.

The properties of an alloy are usually different from those of its constituent elements. The reason for this is that the atoms of different elements in an alloy interact with each other differently than they would if they were in their pure elemental form. This interaction can lead to changes in the electronic and crystal structure of the alloy, which in turn can affect its physical and chemical properties. Some common examples of alloys include brass (copper and zinc), stainless steel (iron, chromium, and nickel), and bronze (copper and tin).

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Complete question:

An alloy is a mixture of elements that has metallic properties. True or False

Answer:

Determine the volume of the sample of CO2(g) if the temperature and pressure are changed to 336K and 152.0 kPa. Answer-->151 mL (PV/T=PV/T ) 60.

The combined gas law gives the value of the volume. The final volume at 336 K is 151.3 mL.

Charle's, Boyle's, and Gay-Lussac's laws together give the combined gas law. It is given as:

PV / T = k

Given,

Initial volume = 200 mL

Initial pressure = 101.3 kPa

Initial temperature = 296 K

Final pressure = 152 kPa

Final temperature = 336 K

The final volume is calculated as:

(P₁V₁) ÷ T₁ = (P₂V₂) ÷T₂

(101.3 × 200) ÷ 296 = (336 × V) ÷ 152

V = 151.3 mL

Therefore, 151.3 mL is the final volume at 300 K.

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The approximate hardness of the resulting steel in GPa is 7.7 GPa.

6150 steel (0.5%C) cooled from 1000°C and isothermally treated at 650°C for 10 s then quenched to room temperature. Prior to heating, it was normalized and had a hardness of 1.8 GPa. We need to find the approximate hardness of the resulting steel in GPa.

After normalizing, the steel is cooled from 1000°C to 650°C, which means it is cooled to the austenitic temperature range, which changes its microstructure. At this temperature, the steel has pearlite microstructure.

Pearlite is an alloy of ferrite and cementite phases. As the steel is isothermally treated at 650°C, it means that the pearlite phase of the steel has completely transformed into the austenite phase. Therefore, after the quenching process, the steel will have martensite microstructure.

The hardness of the martensite is related to the carbon content of the steel.

After cooling from 1000°C to 650°C, the steel microstructure changes, which means its carbon content also changes. We can see from the Fe-C phase diagram that at 650°C, the steel's carbon content is approximately 0.2% to 0.3%. We are given that the steel has 0.5% carbon content before the process, which means its carbon content has reduced.

We can assume that the carbon content in the steel after quenching will be about 0.3%. From the given diagram, the approximate hardness of the steel will be 7.7 GPa.

Therefore, the approximate hardness of the resulting steel in GPa is 7.7 GPa.

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Answer:

C. people rely on ecosystem services provided by intact ecosystems

Explanation:

:) Comment was correct! <3

Protecting and managing biodiversity resources is a crucial part of maintaining ecological harmony and ensuring the survival of species' future generations so that they can live long healthy lives. The correct option is C.

In order to stop the extinction of species, biodiversity should be protected. To keep nature in balance, it is conserved. Other organisms will suffer if one species in the food chain becomes extinct.

The systems that sustain all life on Earth, including humans, depend on biodiversity. We cannot have the healthy ecosystems that we depend on to give us the air we breathe and the food we consume without a diverse variety of animals, plants, and microorganisms.

Thus the correct option is C.

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Answer:

0.008303 mol and 0.0997 g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.

This implies that 1 mole of carbon also contains 6.022×10²³ atoms.

Next, we shall determine the mole of carbon that contains 5.0×10²¹ atoms. This can be obtained as follow:

1 mole of carbon contains 6.022×10²³ atoms.

Therefore, Xmol of carbon will contain 5.0×10²¹ atoms i.e

Xmol of carbon = 5.0×10²¹ / 6.022×10²³

Xmol of carbon = 0.008303 mole

Therefore, 0.008303 mole of carbon contains 5.0×10²¹ atoms.

Finally, we shall determine the mass of carbon. This can be obtained as follow:

Mole of carbon = 0.008303 mole

Molar mass of carbon = 12.01 g/mol

Mass of Carbon =.?

Mole = mass /Molar mass

0.008303 = mass of carbon/12.01

Cross multiply

Mass of Carbon = 0.008303 x 12.01

Mass of Carbon = 0.0997 g.

Answer

Explanation:

he most recent Ebola virus outbreak in West Africa, which was unprecedented in the number of cases and fatalities, geographic distribution, and number of nations affected, highlights the need for safe, effective, and readily available antiviral agents for treatment and prevention of acute Ebola virus (EBOV) disease (EVD) or sequelae1. No antiviral therapeutics have yet received regulatory approval or demonstrated clinical efficacy. Here we report the discovery of a novel small molecule GS-5734, a monophosphoramidate prodrug of an adenosine analogue, with antiviral activity against EBOV. GS-5734 exhibits antiviral activity against multiple variants of EBOV and other filoviruses in cell-based assays. The pharmacologically active nucleoside triphosphate (NTP) is efficiently formed in multiple human cell types incubated with GS-5734 in vitro, and the NTP acts as an alternative substrate and RNA-chain terminator in primer-extension assays using a surrogate respiratory syncytial virus RNA polymerase. Intravenous administration of GS-5734 to nonhuman primates resulted in persistent NTP levels in peripheral blood mononuclear cells (half-life, 14 h) and distribution to sanctuary sites for viral replication including testes, eyes, and brain. In a rhesus monkey model of EVD, once-daily intravenous administration of 10 mg kg−1 GS-5734 for 12 days resulted in profound suppression of EBOV replication and protected 100% of EBOV-infected animals against lethal disease, ameliorating clinical disease signs and pathophysiological markers, even when treatments were initiated three days after virus exposure when systemic viral RNA was detected in two out of six treated animals. These results show the first substantive post-exposure protection by a small-molecule antiviral compound against EBOV in nonhuman primates. The broad-spectrum antiviral activity of GS-5734 in vitro against other pathogenic RNA viruses, including filoviruses, arenaviruses, and coronaviruses, suggests the potential for wider medical use. GS-5734 is amenable to large-scale manufacturing, and clinical studies investigating the drug safety and pharmacokinetics are ongoing.

Main

The 2013–2016 outbreak of EVD in West Africa was the largest and most complex EBOV outbreak in the recorded history of the disease, with >28,000 EVD cases and >11,000 reported deaths1. Medical infrastructures in Guinea, Sierra Leone, and Liberia were seriously impacted by a loss of >500 healthcare workers1. Additionally, EVD-related sequelae (joint and muscle pain, as well as neurological, ophthalmic, and other symptoms) together with viral persistence and recrudescence in individuals who survived the acute disease have been documented2,3,4,5.

EBOV is a single-stranded negative-sense non-segmented RNA virus from the Filoviridae family. In addition to EBOV, other related viruses, namely Marburg, Sudan, and Bundibugyo viruses, have caused outbreaks with high fatality rates6. Although the efficacy of various experimental small molecules and biologics have been assessed in EVD animal models and in multiple clinical trials during the West African outbreak7,8,9,10,11,12,13,14,15,16,17,18, there are no therapeutics for which clinical efficacy and safety have been established for treatment of acute EVD or its sequelae. The availability of broadly effective antiviral(s) with a favourable benefit/risk profile would address a serious unmet medical need for the treatment of EBOV infection.

A 1′-cyano-substituted adenine C-nucleoside ribose analogue (Nuc) exhibits antiviral activity against a number of RNA viruses19. The mechanism of action of Nuc requires intracellular anabolism to the active triphosphate metabolite (NTP), which is expected to interfere with the activity of viral RNA-dependent RNA-polymerases (RdRp). Structurally, the 1′-cyano group provides potency and selectivity towards viral RNA polymerases, but because of slow first phosphorylation kinetics, modification of parent nucleosides with monophosphate promoieties has the potential to greatly enhance intracellular NTP concentrations20. GS-5734, the single Sp isomer of the 2-ethylbutyl L-alaninate phosphoramidate prodrug (Supplementary Information), effectively bypasses the rate-limiting first phosphorylation step of the Nuc (Fig. 1a). In human monocyte-derived macrophages, incubation with GS-5734 caused rapid loading of cells with high levels of NTP that persist with a half-life (t1/2) of 24 h following removal of GS-5734 (Extended Data Fig. 1a), resulting in up to 30-fold higher levels compared to incubation with Nuc (Fig. 1b). In cell-based assays, GS-5734 is active against a broad range of filoviruses including Marburg virus and several variants of EBOV (Fig. 1c). GS-5734 inhibits EBOV replication in multiple relevant human cell types including primary macrophages and human endothelial cells with half-maxi

The salt that produces a basic solution in water is NaF.

When a salt dissolves in water, it can either produce an acidic, basic, or neutral solution, depending on the nature of the salt. Salts that are derived from strong bases and weak acids are basic solution, while salts that are derived from weak bases and strong acids are acidic in nature. Salts that are derived from either strong bases and strong acids or weak bases and weak acids are neutral in nature.

In this case, NaF is derived from the strong base NaOH and the weak acid HF, so it is a basic solution. KCl is derived from the strong base KOH and the strong acid HCl, so it is neutral in nature. NH4Cl is derived from the weak base NH3 and the strong acid HCl, so it is acidic in nature. Therefore, the salt that produces a basic solution in water is NaF.

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The mass of the mixture is 95.8 g and the percentage by mass of cyclohexane in the mixture is 81.33%.

To calculate the percentage by mass of cyclohexane in the mixture, you need to use the formula:

Percentage by mass = (mass of component / total mass of mixture) × 100

Given that you have a mixture of cyclohexane and water and the density of the mixture is 0.958 g/mL,

1. To determine the mass of the mixture, you need to know the volume of the mixture and the density of the mixture. Since the density of the mixture is given, you can use the following formula to determine the mass of the mixture:

mass of mixture = density of mixture × volume of mixture

The mass of the mixture is: mass of mixture = 0.958 g/mL × 100 mL = 95.8 g

2. Since the density of cyclohexane is given as 0.779 g/mL, you can use the following formula to determine the mass of cyclohexane:

mass of cyclohexane = density of cyclohexane × volume of cyclohexane = 0.779 g/mL × 100 mL = 77.9 g

3. Using the formula given above, you can calculate the percentage by mass of cyclohexane in the mixture:

percentage by mass of cyclohexane = (mass of cyclohexane / mass of mixture) × 100

percentage by mass of cyclohexane = (77.9 g / 95.8 g) × 100 = 81.33%

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Answer:

OH

Explanation:

Since one mol is 17g/mol, the formula is simply OH.

O is 16 g per atom and H is 1 g per atom, so when you have one atom of each you get 17 g/mol

The empirical formula represents the molecular formula. Therefore, the molecular formula is also .

The molecular formula of a compound is a representation of the number and types of atoms that make up one molecule of that compound. It shows the actual number of each type of atom in a molecule and is a multiple of the empirical formula.

The empirical formula of the liquid is H, which means it contains one hydrogen and one oxygen atom per molecule.

1(1.008) + 1(15.999) = 17.007 g/mol

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For the following reaction, 4.27 grams of hydrogen gas are allowed to react with 11.0 grams of ethylene (C2H4). The maximum amount of ethane (C2H6) that can be formed is 11.79 g. The formula for the limiting reagent is C2H4. The amount of the excess reagent remains after the reaction is complete is is 3.48 g.

The balanced chemical reaction for the given scenario is given below: C2H4 + H2 → C2H6Ethylene (C2H4) and hydrogen (H2) react to give ethane (C2H6).

The balanced chemical equation provides the stoichiometry of the reaction. The stoichiometric ratio can be used to determine the moles of reactants and products involved in the reaction. Since the stoichiometric ratio is in terms of moles, we need to convert the mass of the given reactants to moles.

Let's start by calculating the number of moles of hydrogen and ethylene.

Number of moles of hydrogen (H2) = mass / molar mass = 4.27 g / 2.016 g/mol = 2.12 mol

Number of moles of ethylene (C2H4) = mass / molar mass = 11.0 g / 28.054 g/mol = 0.392 mol

According to the stoichiometry of the reaction, 1 mole of ethylene (C2H4) reacts with 1 mole of hydrogen (H2) to form 1 mole of ethane (C2H6).

Since ethylene (C2H4) is present in less quantity as compared to hydrogen (H2), ethylene (C2H4) will be the limiting reagent in this reaction. Therefore, the maximum amount of ethane (C2H6) that can be formed is obtained by using the number of moles of limiting reagent i.e. ethylene.

Number of moles of ethane (C2H6) = number of moles of limiting reagent = 0.392 mol

Mass of ethane (C2H6) = number of moles × molar mass = 0.392 mol × 30.070 g/mol = 11.79 g

Thus, the maximum amount of ethane (C2H6) that can be formed is 11.79 g.

The limiting reagent is the reactant that is consumed completely during the reaction. Since ethylene (C2H4) is the limiting reagent in this reaction, its formula is C2H4.

Excess reagent is the reactant that remains unconsumed after the reaction is complete. We have already determined that ethylene (C2H4) is the limiting reagent in this reaction, which means that hydrogen (H2) is the excess reagent.

Hence, the amount of the excess reagent i.e. hydrogen (H2) remaining after the reaction is complete is obtained by subtracting the amount of hydrogen used in the reaction from the amount of hydrogen available.

Number of moles of hydrogen used = number of moles of limiting reagent = 0.392 mol

Number of moles of hydrogen available = 2.12 mol

Number of moles of hydrogen remaining = 2.12 mol - 0.392 mol = 1.73 mol

Mass of hydrogen remaining = number of moles × molar mass = 1.73 mol × 2.016 g/mol = 3.48 g

Therefore, the amount of the excess reagent (hydrogen) that remains after the reaction is complete is 3.48 g (approx).

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Answer:

Seasonal Winds: Blow in opposite direction of normal winds  and cause droughts in winter.

Prevailing Winds: Blow mainly in one direction and move huge air masses.

Mountain Ranges: force coastal air masses to rise, cool, and  form rain clouds.

Explanation:

Hope this helps you, sorry for responding so late... have an amazing night, day, or evening

The term precipitation implies the falling of rain due to condensation of water vapor in the cloud.

The term precipitation implies the falling of rain due to condensation of water vapor in the cloud.  We must note that several factors affect precipitation in a given area.

The following phrases below are matched with how it affects precipitation;

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Radiant energy is emitted from all objects with temperatures greater than ABSOLUTE ZERO. This means ALL objects emit radiant energy.

Radiant heat is a type of energy that largely depends on the temperature of an object.

This type of energy (radiant energy) is emitted from all objects and can be observed when heat is absorbed on the surface of another material.

Radiant energy can be defined as a type of electromagnetic energy.

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Answer:

Corona

Explanation:

Is the answer so yeah...

The system that reacts within hours to days through the production, absorption, and excretion of acids, bases, and ions is the renal system. The renal system, also known as the urinary system, consists of the kidneys, ureters, bladder, and urethra. It regulates the body's fluid and electrolyte balance by producing, absorbing, and excreting acids, bases, and ions.

Acids are chemicals that release hydrogen ions when they dissolve in water. They have a sour taste and can cause chemical burns. Bases, on the other hand, are chemicals that release hydroxide ions when they dissolve in water. They have a bitter taste and can cause chemical burns as well.

Ions are charged particles that can be either positively charged (cations) or negatively charged (anions). They are present in most biological fluids, including blood and urine. They are important for maintaining the body's pH balance and electrical conductivity.

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Answer:

7.224 × 10^28 atoms

Explanation:

The number of moles contained in a substance (n) can be calculated from this expression:

nA = n × 6.02 × 10^23 atoms

Where;

nA = number of atoms of substance

n = number of moles of substance

Avagadro's number or constant = 6.02 × 10^23 atoms

Using nA = n × 6.02 × 10^23 atoms

In this question, there are 1.2 x 10^5 moles of neon (N). The number of atoms (nA) is as follows:

nA of neon = 1.2 x 10^5 × 6.02 × 10^23

nA = 7.224 × 10^ (5 + 23)

nA = 7.224 × 10^28 atoms

The number of neon atoms in 1.2 x 10^5 is 7.224 × 10^28 atoms.