Mars orbits the sun at less then 60% of the speed of earth. True or false?

Answer:

The angle of launch of the rubber band affects the initial velocity. The more the rubber band is stretched the more force it applies to return to equilibrium and the more kinetic energy that results in.

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

the ball lose kentic energy and gains potential energy rolling upward

Answer:

c

Explanation:

when a ball is rolling down it loses potential and gains kinetic, but in this case since the ball is going upwards it is losing kinetic energy and gaining potentail like a roller coaser

In a ocean full of storms

A new wave was born

Deep into that darkness flooding

Suddenly, I heard some pummeling

By the grave I saw the winds

And the sun just shined

Answer:

a friendly face that comes with waves,

the waves of all the memorial days,

and with these days we smile with pride,

as for the waves we used to ride,

given up the day has passed,

how it went away like an hour glass,

as if we knew the world was right,

just like the waves, oh so bright,

the time has come the days have passed,

the waves ashore the waves alast,

as if the friendly face was right,

the waves that rode, oh goodnight.

Answer:

Explanation:

2) Draw a horizontal line below the squiggle and call it your reference origin.

Highest potential energy is farthest above the origin.

I would suggest for highest to lowest

GACE(D = F)B

3) I have no way of knowing how to compare kinetic and potential energies because we are given no reference levels for either.

IF we ASSUME it is a typo and they want highest to lowest KINETIC energies, then the values will be the reverse of #2 because, in the lack of friction, Kinetic and Potential energies will always be swapping keeping the total mechanical energy constant.

B(D = F)ECAG

(a)  the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.

(b)  the man is in the air for approximately 0.843 seconds.

To determine the horizontal distance between the saddle and limb when the man makes his move, we need to consider the horizontal velocity of the man when he drops from the tree limb.

Given:

Speed of the horse (constant velocity), v = 13.5 m/s

Vertical distance between the limb and saddle, h = 3.55 m

a) To find the horizontal distance, we can use the formula:

horizontal distance = horizontal velocity × time

Since the man drops vertically, his initial horizontal velocity is zero. The only horizontal velocity he will have is due to the motion of the horse.

The time taken by the man to fall can be determined using the equation for free fall:

h = (1/2) × g × t²

Where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time.

Rearranging the equation, we get:

t = √(2h / g)

Substituting the given values:

t = √(2 × 3.55 / 9.8) ≈ 0.843 s

Now, we can find the horizontal distance:

horizontal distance = v × t

horizontal distance = 13.5 × 0.843 ≈ 11.386 m

Therefore, the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.

b) The time the man is in the air can be calculated using the same equation for free fall:

t = √(2h / g)

Substituting the given value of h:

t = √(2 × 3.55 / 9.8) ≈ 0.843 s

Thus, the man is in the air for approximately 0.843 seconds.

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Answer:

Tension

Explanation:

Answer:

If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.

Explanation:

Hope this helps!

To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

v = √(k / m) ×A

v = velocity of the mass

k= spring constant

m =mass of the object

A= amplitude of the oscillation.

substituting all the given values in the above equation, we get

2.3 m/s = √(200 N/m / 3.00 kg)×A

A = 2.3 m/s / √(200 N/m / 3.00 kg)

    = 0.23 m

v =√(200 N/m / 3.00 kg) ×0.23 m

 = 2.75 m/s

Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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The power used by the dryer to spin the drum and produce heat is 11000 Watts.

Power is simply the quantity of energy transferred per unit time.

This is expressed as;

P = v × I

Where v is voltage and I is current.

Given that;

Plug the given values into the above formula and solve for P.

P = v × I

P = 220V × 50A

P = 11000 Watts

Therefore, the power used by the dry is 11000 Watts.

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Answer:

11.186 * 10^3 m/s

Explanation:

For a Veracious to escape the gravitational pull of the earth it has to a attain

Vesc = \(\sqrt{\frac{2GM}{R} }\)  -------- ( 1 )

where: G = ( gravitational constant ) = 6.674 * 10^-11 m^3 kg^-1 s^-2 )

            M = ( mass of earth) =  5.972 * 10^24 kg

            R =  ( Radius of earth ) =  6.371 * 10^6  m  

next we will Input  values into equation ( 1 )

The required Vesc that the Veracious can attain to escape the gravitational pull of the earth = 11.186 * 10^3 m/s

Answer:

Answer:

Yes

Explanation:

Yes, we can control the motion.

Motion can be controlled by applying friction which is a force that opposes the motion. For example, if a car is in motion, brakes are applied to stop the motion of the car, this is due to the use of force of friction to convert that kinetic energy into heat.

Hence, the correct answer is "yes".

-- If A and B are pointing in exactly opposite directions, then their sum A+B is the minimum possible value.  A+B = 2 N in the same direction as B.

-- If A and B are pointing in exactly the same direction, then their sum A+B is the maximum possible value.  A+B = 6 N in that same direction.  

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Answer:

The rescue workers can get energy to the batteries in their equipment during rescue missions by using a generator to convert the kinetic energy to potential energy. Potential energy is then stored in the battery.

Explanation:

Complete Question

The diagram illustrating this question is shown on the first uploaded image

Answer:

The value is \(\theta = 27^o\)

Explanation:

Generally the distance covered by the ball thrown at angle 45° that did not bounce is mathematically represented as

\(D = v cos (45) * t\)

Here t is the total time duration which is mathematically represented as

\(t = \frac{v sin (45)}{g}\)

This distance distance is also mathematically represented as

\(D = vcos(\theta)* t_1 + \frac{v}{2} cos(\theta )*t_2\)

Here \(\theta\) the angles made as shown in the diagram

Here \(t_1\) is the time before the first bounce which is mathematically represented as

\(t_1 = \frac{v sin (\theta )}{g}\)

\(t_1\) is the time duration before the final point which is mathematically represented as

\(t_2 = \frac{\frac{v}{2} * sin (\theta )}{g}\)

So

\(v cos (45) * \frac{v sin (45)}{g} = vcos(\theta)* \frac{v sin (\theta )}{g} + \frac{v}{2} cos(\theta ) * \frac{\frac{v}{2} * sin (\theta )}{g}\)

=> \(cos (45) sin(45) = cos(\theta)sin(\theta ) + cos(\theta )sin(\frac{\theta}{4})\)

=> \(0.5 = \frac{5}{8} * sin(2\theta )\)

=> \(\theta = 27^o\)

The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

Answer:

a)   F_total = 6.15 10-5 N

b)    r₁ = 0.3045 m,    r₂ = 0.0051 m

Explanation:

In this exercise we must use that the total force is the sum of the forces on the body, remember that the gravitational force is attractive

      ∑un F = F₁₂ - F₃₂

where F₁₂2 is the force between the body of M1 = 155 kg, placed to the right and the body of m = 69 kg; the force F₃₂ is the force between the body of M3 = 455 kg, located on the left and the body of 69 kg

    these forces are gravitational forces, which is described by the expression

       F = G M m / r²

let's write each force

       F₁₂= G M₁ m / r²

leather m is at the midpoint of large bodies

 F₁₂= 6.67 10⁻¹¹ 155 69 / 0.15²

 F₁₂ = 3.17 10⁻⁵ N

 F₃₂ = 6.67 10⁻¹¹ 455 69 / 0.15 2

  F₃₂= 9.31 10⁻⁵ N

the net force is

      F_total = (3,17 - 9,31) 10-5

      F_total = 6.15 10-5 N

This force is directed to the left

b) in this case it asks us to know where we place the body so that the force is zero

            F12 = F32

the object is at a distance r from the mass1 and at a distance (0.3 - r), we avoid the equation

              F12 = G M1 m / r²

              F32 = G M3 m / (0,3-R) 2

             G M1 m / r2 = G M3 m / (0,3-r) 2

              M1 / r2 = M2 / (0,3-r) 2

              (0,3 -r) 2 M1 / ​​M2 = r2

               0.32 - 2 r 0.3 + r2) = M2 / M1r2

                (0.09 - 0.6 r + r2) = 455/155 r2 = 2,935 r2

                -0.09 + 0.6r + 1.935 r2 = 0

we simplify the expression

               r2 +0.31 r - 0.0465 = 0

let's solve the quadratic equation

               r = [0.31 + - RA (0.31 2 -4 0.0465)] / 2

               r = [0.31 + - RA (0.0899] / 2

               r = [0.31 + - 0.2998] / 2

               r₁ = 0.3045 m

               r₂ = 0.0051 m

Table tennis can be defined as an indoor sport and recreational activity in which two (2) or four (4) players hit a ping-pong ball back and forth on a table that is divided into halves by a low net, especially through the use of a small-solid bat (racket).

Generally, there are two (2) main types of grip in table tennis and these include:

Basically, there are four (4) fundamental skills used in table tennis and these are:

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The silver would be coolest since it has the lowest heat capacity.

Heat capacity, also known as thermal capacity, is the amount of heat energy required to raise the temperature of a substance by a certain amount. It is expressed as the amount of heat energy per unit temperature change, and is usually measured in joules per kelvin (J/K) or calories per degree Celsius (cal/°C).

Heat capacity is a key property of materials that provides important information about their thermal behavior and is critical for many areas of science and technology.

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The total distance moved or the total path covered by the dog is 34 m.

The given parameters;

initial distance of the dog, = 14 m east

final distance of the dog, = 20 m west

Distance is defined as the total path covered by an object. It is a scalar quantity because it can only be represented in magnitude only.

The total distance moved by the dog is calculated as follows;

distance = 14 m + 20 m

distance = 34 m

Thus, the distance moved or the total path covered by the dog is 34 m.

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Answer:

amplitude

frequency

wave

transition

transverse waves

Nearby jet airplane

Fast train

Siren

Lawn move

Answer:a vertical expanse of water stretching between the surface and the floor of a body of water

Explanation:

Answer:Electric Current!

Explanation: Electric current ;)

Answer:

The correct answer is - B. Increase the time it takes to stop the egg once it hits his hand.

Explanation:

In order to catch the egg the force and time makes an impulse to the egg to change its momentum and bring it to rest. In order to change the momentum, one needs to decrease the force exerted onto the egg and increase the time it takes to make it rest.

Less force can be given to the egg by increasing the time to bring it to rest stop the egg once it hits his hand. Other than this it should be caught to the sides.