man runs for an hour and a half at 8 miles an hour due south. he then continues south on a bus traveling at 55 miles an hour for 24 minutes. how far d

Answer:

1.6056648e+12

Step-by-step explanation:

Answer:

21071715921

Step-by-step explanation:

This is what I got when i entered it into a calculator. Hopefully i'm correct and this helps :) Have a good day/night

490

472 <490<500

it fits the criteria

Answer:5

Step-by-step explanation:

the lenglength of 2x2x is 10 so 2x2x. Means that x is 5

a) Positive b)   Degree per minute    c) Interpretation of f'(20)=2

So as we have we are given in the question: T = f(t)

where T is the temperature in degrees Fahrenheit of a cold yam placed in a hot oven and t is the time in minutes since the yam was put in the oven .f'(t) will represent the rate of change in temperature.

f'(t) will represent the change in temperature of yam when 1 minute has passed since it was kept in oven.

Since the temperature will always increase in oven, f'(t) will have a positive sign. units of f'(20)Since, f'(t) represent the rate of change in temperature. the unit will be degrees Fahrenheit per minute .f'(20)=2f'(20) will tell the change in temperature when 20 minutes have passed after the yam has been kept in oven .Thus, the given statement means that 20 minutes after the yam was kept for  in the oven, the temperature of yam was increasing by 2 degree Fahrenheit per minute.

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If the cost of advertising was $100,000 and the reach or circulation was 10,000,000 people, then the CPM is $10.

Cost per thousand (CPM), which is also called cost per mille, is a marketing word used to denote the price of 1,000 advertisement prints on one web page. If a publisher of a website charges $2.00 CPM, that means an advertiser must pay $2.00 for every 1,000 prints of its ad.

The CPM is calculated by dividing the cost of the advertisement by the number of people reached and then multiplying by 1000.

Given that the cost of advertising was $100,000 and the reach was 10,000,000 people, the CPM can be calculated as follows:

CPM = ($100,000 / 10,000,000) × 1000 = $10.

So, the CPM is $10.

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The linearization of f(x) at x = 8 is L(x) = 3x.

The critical point for the function y = 3x^2 - 96 is x = 0.

To find the linearization of f(x) at x = a, we can use the formula:

L(x) = f(a) + f'(a)(x - a).

For the given function f(x) = 3x and a = 8:

f(x) = 3x, a = 8.

a) L(x) = 3(8) + 3(x - 8)

= 24 + 3x - 24

= 3x.

To determine the critical points of the function y = 3x^2 - 96, we need to find the points where the derivative of the function is equal to zero.

y = 3x^2 - 96.

a) Taking the derivative of y with respect to x:

dy/dx = 6x.

b) Setting dy/dx equal to zero and solving for x:

6x = 0.

x = 0.

c) Therefore, the critical point of the function is x = 0.

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After excluding 4, the intersection of sets C and D contains 10 numbers.

the correct answer is (E) 10.

To find the intersection of sets C and D, we need to determine the numbers that are common to both sets.

Set C contains all the integers from -13 through 4, excluding -13 and 4. So, it contains the numbers -12, -11, -10, ..., 2, 3.

Set D contains the absolute values of the numbers in Set C. This means that each number in Set C is transformed into its positive counterpart. Thus, Set D contains the numbers 12, 11, 10, ..., 2, 3.

To find the intersection, we need to identify the numbers that are common to both sets C and D. In this case, we can observe that all the numbers from 2 to 12 (inclusive) are present in both sets.

Therefore, the intersection of sets C and D consists of the numbers 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

Counting the numbers in the intersection, we find that there are 11 numbers.

However, it's important to note that the problem statement excludes the number 4 from Set C. Therefore, we should exclude it from the intersection as well. After excluding 4, the intersection of sets C and D contains 10 numbers.

Hence, the correct answer is (E) 10.

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Writing linear equations given two points can be a useful skill when graphing linear equations.

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A sector is a part of a circle bounded by two radii and an arc. So then, constructing a line that would represent all points equidistant from MN and MP implies the angle bisector of angle NMP.

The line which represents all points equidistant from MN and MP is an angle bisector of NMP. An angle bisector is a straight line that divides a given angle into two equal parts.

The steps required to construct the line are:

ii. Reflection is the process of turning a given shape or figure about a point or line. The reflection of the figure across the line (angle bisector) would not map the figure onto itself. This is because of the change in the orientation of the points N and P.

The construction to this question is attached to this answer for more clarifications.

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Answer:

the answer is -5 because of the addition of the numbers

Answer:

Hope this settles it for ya! XD

Step-by-step explanation:

g'day all!

The feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

To determine whether the feasible set for each system of constraints is convex, we need to analyze the constraints individually and examine their intersection.

a) (x1)² + (x2)² > 9

This constraint represents points outside the circle with a radius of √9 = 3. The feasible set includes all points outside this circle.

b) x1 + x2 ≤ 10

This constraint represents points that lie on or below the line x1 + x2 = 10. The feasible set includes all points on or below this line.

c) x1, x2 > 0

This constraint represents points in the positive quadrant, where both x1 and x2 are greater than zero.

Now, let's analyze the intersection of these constraints:

Considering the first two constraints (a and b), we can see that the feasible set consists of all points outside the circle (constraint a) and below or on the line x1 + x2 = 10 (constraint b).

To determine whether the feasible set is convex, we need to check if any two points within the set create a line segment that lies entirely within the set.

If we consider the points (5, 5) and (3, 7), both points satisfy the individual constraints (a) and (b). However, the line segment connecting these two points, which is the line segment between (5, 5) and (3, 7), exits the feasible set since it passes through the circle (constraint a) and above the line x1 + x2 = 10 (constraint b).

Therefore, the feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

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Answer:

9. y=-2x+1

10. y=3/2x-2

Step-by-step explanation:

could u vote me brainliest plz? thx :)

Answer:

FREE POINTS!!!

Step-by-step explanation:

The given costs are : Cost of pen = $1.85Cost of marker = $0.47 less than a pen

Cost of marker = $1.85 - $0.47 = $1.38Cost of 2 pens and a marker= 2($1.85) + $1.38 = $3.72 + $1.38 = $5.10

If Jon gives a ten-dollar bill, then he gets a change of $10 - $5.10 = $4.90

Thus, Jon will get $4.90 change from a ten-dollar bill.

Pens are more harmful to the environment than pencils. Pens are always ready to write, whereas pencils need to be sharpened. A pencil becomes harder to use and shorter the more you sharpen it. Pencils cannot be used to write on skin. Ballpoint pens are one of the most common and well-known kinds of pens.

Ballpoint pens use an oil-based ink that dries more quickly than other types of ink. When you write, you'll notice less smudging as a result. Since the ink is thick, ballpoint pens utilize less ink as you compose, enduring longer than other pen types.

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Answer:

the answer is 10000+5000+9

Answer:

10,000+5,000+9

Step-by-step explanation:

that is the answer

Answer:

6y²(2y - 1)(y - 5)

Step-by-step explanation:

12\(y^{4}\) - 66y³ + 30y² ← factor out 6y² from each term

= 6y²(2y² - 11y + 5) ← factor the quadratic

consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term, that is

product = 2 × 5 = 10 and sum = - 11

the factors are - 1 and - 10

use these factors to split the y- term

2y² - y - 10y + 5 ( factor the first/second and third/fourth terms )

y(2y - 1) - 5(2y - 1) ← factor out (2y - 1) from each term

(2y - 1)(y - 5)

then

12\(y^{4}\) - 66y³ + 30y² = 6y²(2y - 1)(y - 5)

\(12y {}^{4} - 66y {}^{3} + 30y {}^{2} \\ 6y {}^{2} (2y {}^{2} - 11y + 5) \\ 6y {}^{2} (2y {}^{2} - y - 10y + 5) \\ 6y {}^{2} (y(2y - 1) - 5(2y - 1)) \\ 6y {}^{2} (2y - 1)(y - 5)\)

Answer:

(x,y) --> (x+5, y)

Step-by-step explanation:

You are moving the image 5 units to the right so you would add 5 to each x coordinate.

The area between the two functions, g(x) = 5x - 9 and\(f(x) = x^2 - 16x + 9\), over the interval [-9, -2], is __ square units (exact answer, not rounded).

To find the area between two curves, we need to calculate the definite integral of the difference between the upper and lower functions over the given interval. In this case, the upper function is g(x) = 5x - 9 and the lower function is \(f(x) = x^2 - 16x + 9\).

The first step is to find the points where the two functions intersect. We can set them equal to each other:

\(5x - 9 = x^2 - 16x + 9\)

Rearranging the equation gives us:

\(x^2 - 21x + 18 = 0\)

Solving this quadratic equation, we find that x = 3 or x = 6. Since the interval is [-9, -2], we only need to consider the value x = 6 as it lies within the interval.

Next, we integrate the difference between the two functions from x = -9 to x = 6:

Area = ∫[-9, 6] (g(x) - f(x)) dx

Using the definite integral, we evaluate the expression:

Area = ∫\([-9, 6] (5x - 9 - (x^2 - 16x + 9))\)dx

Simplifying further:

Area = ∫\([-9, 6] (-x^2 + 21x - 18)\) dx

Integrating the polynomial, we find:

\(Area = [-x^3/3 + (21x^2)/2 - 18x] | [-9, 6]\)

Evaluating the definite integral from -9 to 6, we get the exact area between the two functions over the given interval.

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Answer:

Slope = 27/11

AB = 29.15 u

Step-by-step explanation:

Given :-

To Find :-

We can find the slope of the line passing through the points \(( x_1,y_1)\) and \(( x_2,y_2)\)as ,

\(\implies m = \dfrac{ y_2-y_1}{x_2-x_{1}}\)

\(\implies m = \dfrac{ 42-15}{18-7} \\\\\implies \boxed{ m = \dfrac{ 27}{11 }}\)

Hence the slope of the line is 27/11 .

\(\rule{200}2\)

Finding the length of AB :-

\(\implies Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2} \\\\\implies Distance =\sqrt{ (18-7)^2+(42-15)^2 } \\\\\implies Distance =\sqrt{ 11^2 + 27^2 } \\\\\implies Distance =\sqrt{ 121 + 729 } \\\\\implies Distance = \sqrt{ 850} \\\\\implies \boxed{ Distance = 29.15 \ units }\)

Hence the length of AB is 29.15 units .

Answer:2 I thinkkk

Step-by-step explanation:

The width of the original piece of sheet metal is (w^2 - l^2)/(3w + 3l), and the length is (l^2 - w^2)/(3w + 3l).

To solve this problem, we can use the formula for the volume of a rectangular box, which is V = lwh, where l is the length, w is the width, and h is the height.

First, let's find the height of the box. Since we cut squares from each corner, the height of the box is the length of the square that was cut out. Let's call this length x.

The width of the box is the original width minus the lengths of the two squares that were cut out, which is w - 2x.

Similarly, the length of the box is the original length minus the lengths of the two squares that were cut out, which is l - 2x.

Now we can write the volume of the box in terms of x, w, and l:

V = (w - 2x)(l - 2x)(x)

Expanding this expression, we get:

V = x(4wl - 4wx - 4lx + 8x^2)

Simplifying further:

V = 4x^3 - 4wx^2 - 4lx^2 + 4wlx

To find the dimensions of the original piece of sheet metal, we need to maximize this volume. We can do this by taking the derivative of the volume with respect to x and setting it equal to zero:

dV/dx = 12x^2 - 8wx - 8lx + 4wl = 0

Solving for x, we get:

x = (2wl)/(3w + 3l)

Now we can use this value of x to find the width and length of the original piece of sheet metal:

w - 2x = w - 2(2wl)/(3w + 3l) = (w^2 - l^2)/(3w + 3l)

l - 2x = l - 2(2wl)/(3w + 3l) = (l^2 - w^2)/(3w + 3l)

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Answer:

13.2 g

Step-by-step explanation:

let x = grams sugar in a 200 ml glass

16.5 g sugar / 250 ml = x g sugar / 200 ml

x(250) = (16.5)(200)

x =  (16.5)(200) / (250) = 3300 / 250 = 13.2

Answer:  there are 13.2 g sugar in a 200 ml glass of juice

The customer have to choose 2002 ways to taste 5 different white wine.

The number of possible ways to choose items from a collection when the order of choice is irrelevant is determined using the combination formula. Combination, to put it simply, is the process of choosing items or things from a bigger group where order is irrelevant.

The combination formula is: n! / (n-r)! r! , where n is the total number of items (14 in this case) and r is the number of items being selected at once (5 in this case),

Plugging our numbers into the formula we get:

= 14! / (14-5)! 5!

= 2002

After simplifying, we get 2002.

So, there are 2002 ways of picking 5 different white wines to taste from a group of 14 local winery bottles.

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Answer:

Mean = 125.136

Median = 110

Mode = 180

Step-by-step explanation:

Given the data:

75 95 180 136 89 75 110 180 100 136 180 95 180 136 75 100 110 180 180 136 75 90

Frequency distribution:

Value(X) ___freq (F) ____cumm frequency

85 _________ 4 _______ 4

89 _________ 1 _______5

90 __________1 _______6

95 __________2 ______ 8

100 _________ 2 ______10

110 __________2______ 12

136 __________4 _____ 16

180 __________6______22

2) Using the frequency distribution :

Mean = Σfx / Σf

[(85*4) + (89*1) + (90*1) + (95*2) + (100*2) + (110*2) + (136*4) + (180*6)]/ 10

= 2753 / 22

= $125.136

Median of grouped data :

Frequency + 1 / 2 = 23/2 = 11.5 th term

The median value = $110

Mode of the data:

Most frequently occurring = 180 (frequency of 6)

The mean of the frequency distribution is $125.136, the median of the frequency distribution is $110, and the mode of the frequency distribution is $180.

Given :

a) The frequency distribution is given below:

Prices              Frequency       Cumulative Frequency

85                           4                                 4

89                            1                                 5

90                            1                                  6

95                            2                                  8

100                           2                                 10

110                            2                                  12

136                            4                                 16

180                            6                                 22

b) The mean is calculated as:

\(\rm Mean = \dfrac{85\times4 + 89\times1 +90\times1 +95\times 2+100\times2 +110\times2 +136\times4 +180\times6 }{10}\)

Simplify the above expression.

Mean = $125.136

c) The median of the frequency distribution is calculated as:

\(\rm Term= Frequency + \dfrac{1}{2}=11.5\)

So, the median is $110.

The mode of the frequency distribution is $180.

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Of the two products the newsvendor order more quantity for X is more than the quantity ordered for Y.

Cr = 0.8 which is the critical ratio for both the products

The value of Z corresponding to the critical ratio of 0.8 from the standard normal distribution tables is 0.8416

Unless the quantity ordered by the newsvendor is Q, then

Q =  mean value of demand + Z x standard deviation of demand

Below are the specifications of the two products:

The mean requirement for both X and Y is 900O units.

Z value for both X and Y = 0.8416

Let,

Sd₁ Demand Standard Deviation for Product X

Sd₂ = Demand Standard Deviation for Product Y

Assuming that  (Product X does have a higher standard deviation than Product Y),

quantities for X =  mean value of demand + Z x standard deviation of demand

9000 + 0.8416Sd₁

Order amount for Y =  mean value of demand + Z x standard deviation of demand

9000 + 0.8416Sd₂

because

X₁ > X₂

As a result,

9000 + 0.8416Sd₁ > 9000 + 0.8416Sd₂

The quantity ordered for X is > the quantity ordered for Y.

Therefore, The quantity ordered for X is more than the quantity ordered for Y. As a result, Newsvendor orders Product X more frequently because it has a higher level of uncertainty.

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The critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:  θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.

To find the critical numbers of g(θ) = 4θ - tan(θ) on the interval 0 ≤ θ < 2π, we need to find the values of θ where the derivative of g(θ) is equal to 0 or undefined.

First, we find the derivative of g(θ) using the chain rule and quotient rule:

g'(θ) = 4 - sec²(θ)

To find where g'(θ) is equal to 0, we set the derivative equal to 0 and solve for θ:

4 - sec²(θ) = 0

sec²(θ) = 4

Taking the square root of both sides, we get:

sec(θ) = ±2

Since sec(θ) = 1/cos(θ), we can rewrite this as:

cos(θ) = ±1/2

We know that on the interval 0 ≤ θ < 2π, the cosine function is positive in the first and fourth quadrants and negative in the second and third quadrants.

Therefore, we need to find the values of θ in the first and fourth quadrants where cos(θ) = 1/2, and the values of θ in the second and third quadrants where cos(θ) = -1/2.

For cos(θ) = 1/2, we have:

θ = π/3 or 5π/3 in the first quadrant
θ = 7π/3 or 11π/3 in the fourth quadrant

For cos(θ) = -1/2, we have:

θ = 2π/3 or 4π/3 in the second quadrant
θ = 8π/3 or 10π/3 in the third quadrant

Therefore, the critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:

θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.

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Answer:

D

Step-by-step explanation:

Answer:

Yes, Chen should by the TV on sale. This is because in the end, he will have saved $150. Hope this helps you.

Answer:

3.2M!!!!!!!!!!!!!!!!

Answer:

Solution : Let Tn=0. Then,21+(n-1)×(-3)=0⇒n=8. So, 8th term is zero.

Step-by-step explanation: