Lines are drawn on the gym floor for different sports for basketball playing area is marked so that there is an out of bounds. 2 m wide around the gym the gym is measure 20 m x 15 m what are the dimensions of the basketball court?

Answer:

729

Step-by-step explanation:

I have not done this in some time so the terms may be a bit unconventional, but they work. The key to this is multiplying by -3.

1*(-3) = -3

-3*(-3) = 9

And so on.

1, -3, 9, -27, 81, -243, 729

Answer:

34

Step-by-step explanation:

90-56=34

Answer:

Step-by-step explanation:

K=34

Hope it helps

And I’m only in 6th grade

And i smart ÙwÚ

With a 95% probability, 62 students should be sampled to be within 0.25 drinks of the population mean.

\(\alpha\) is the level obtained by subtracting 1 from the confidence interval and dividing by 2.

So,

\(\alpha\) = (1 - 0.95) ÷ 2 = 0.25

Now, find z in the Z-table, as z has a p-value of 1 - \(\alpha\).

As a result, z has a p-value of (1 - 0.025) = 0.975

so, z  = 1.96

Now, infer M as follows:

M = z × (σ ÷ √n) where n is the sample size and is σ the population standard deviation.

When M = 1, this is n.

According to the question, the standard deviation is roughly 1.

σ = 1

M = z × (σ ÷ √n)

0. 25 = 1.96 × (1 ÷ √n)

√n = 1.96 × (1 ÷ √n)

Square both sides,

(√n)² = ((1.96 × 1) ÷ 0.25)²

n = (7.84)²

n = 61.4656

n ≈ 62

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Chi-square test is a statistical test for categorical data. It is used to determine whether your data are significantly different from what you expected. There are two types of Pearson’s chi-square tests:

1. The chi-square goodness of fit test is used to test whether the frequency distribution of a categorical variable is different from your expectations.

2. The chi-square test of independence is used to test whether two categorical variables are related to each other.

Both of Pearson’s chi-square tests use the same formula to calculate the test statistic, chi-square (Χ2):

X^2=E{(O-E)^2}{E}} where,

Χ2 is the chi-square test statistic

Σ is the summation operator (it means “take the sum of”)

O is the observed frequency

E is the expected frequency

The larger the difference between the observations and the expectations (O − E in the equation), the bigger the chi-square will be. To decide whether the difference is big enough to be statistically significant, you compare the chi-square value to a critical value.

Chi square test is often useful in following situations -

1. if we want to check a hypothesis between two or more categorical variables.

2. The sample was randomly selected from the population.

3. There are a minimum of five observations expected in each group or combination of groups.

So, the Chi square test is used for checking the value of categorical data.

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Answer:

-0.48

Step-by-step explanation:

Trust me I took the test.

Answer:

multiply (-1.2)*(0.4) = -0.48

Step-by-step explanation:

k12

The standardized value of X = 16, given that X is a normal random variable with mean = 20 and standard deviation = 2, is -2.

To find the standardized value of X = 16, we need to convert it into a standard normal random variable by using the formula for standardization.

The standardization process involves subtracting the mean of the random variable and dividing by its standard deviation.

Given that X has a mean of 20 and a standard deviation of 2, the formula for standardization is:

Z = (X - μ) / σ

Where Z represents the standardized value, X is the original random variable, μ is the mean, and σ is the standard deviation.

Plugging in the values, we have:

Z = (16 - 20) / 2

Z = -4 / 2

Z = -2

Therefore, the standardized value of X = 16 is -2.

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Answer:

bruh

Step-by-step explanation:

Answer:

31.34 (to 2d.p.)

Step-by-step explanation:

Just use a calculator and type 42/134

Answer:

The width of Dana's living room is 16 feet.

Explanation:

Because Dana's living room is rectangular and we are given the length of one side and the length of the diagonal we can use the Pythagorean Theorem to solve this problem.

For a right triangle which the length, width and diagonal make up the Pythagorean Theorem states:

a

2

+

b

2

=

c

2

Let the length of 12 be

a

and because the diagonal is the hypotenuse of the triangle (the side opposite the right angle) we let

c

be 20. Substituting and solving gives:

12

2

+

b

2

=

20

2

144

+

b

2

=

400

144

−

144

+

b

2

=

400

−

144

0

+

b

2

=

256

b

2

=

256

√

b

2

=

√

256

b

=

16

Answer:

Step-by-step explanation:

The first two steps solved and the last step to be performed

Solve the quadratic equation

The solution is:

Correct choice is C

Solving from step 3

Option C

Answer:

I believe that It would be L.

Answers in bold

Each answer is in interval notation.

=================================================

Explanation:

The graph is increasing when the curve goes uphill when moving to the right.

This occurs on the interval -2.5 < x < 0 which condenses to the interval notation (-2.5, 0); be sure not to mix this up with ordered pair notation which unfortunately looks identical.

----------

The graph is decreasing when the curve goes downhill when moving to the right.

This happens on two separate intervals of -∞ < x < -2.5 and 0 < x < ∞ which condense to the interval notation (-∞, -2.5) and (0, ∞) respectively.

Joining those two intervals up with the union symbol gets us

(-∞, -2.5) U (0, ∞)

The degrees of freedom for the error source of variation is:  df = 30 - 3 = 27 To calculate the degrees of freedom for the treatment source of variation in an ANOVA table, we need to use the formula:

df (degrees of freedom) = number of groups - 1

In this case, the number of groups is equal to the number of processes, which is 3. Therefore, the degrees of freedom for the treatment source of variation is:

df = 3 - 1 = 2

This means that we have 2 degrees of freedom for the variation among the three processes. These degrees of freedom will be used to calculate the F-statistic, which is a measure of the variability between the means of the different groups (in this case, the processes).

It's worth noting that the other source of variation in an ANOVA table is the error or residual variation, which represents the variation within the groups or samples. The degrees of freedom for this source of variation are calculated using the formula:

df = total sample size - number of groups

In this case, the total sample size is 30 (the sum of the sample sizes for each process), and the number of groups is 3. Therefore, the degrees of freedom for the error source of variation is:

df = 30 - 3 = 27

This means that we have 27 degrees of freedom for the variation within the samples.

Overall, the ANOVA table provides information about how much of the variation in the data can be explained by the treatment (process) and how much is due to random error. By comparing the F-statistic to a critical value based on the degrees of freedom and a chosen significance level, we can determine whether there is a significant difference between the means of the different processes.

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Answer:

did not get the point of the sum

Answer:

Step-by-step explanation:

1. 1/3*60:

Multiply 1/3 by 60/1= 60/3= 20

1/3 of a minute = 20 seconds

2. 4/5*60:

multiply 4/5 by 60/1

=240/5= 48

4/5 of a minute= 48 seconds

3.  7/10*1000 = 7000/10 = 700/1 = 700

7/10 of a kilogram is 700 grams

4. 3/5*100 = 300/5 = 60

3/5 of a meter is 60 centimeters

Answer: -1, 1.5, 3 1/12

Step-by-step explanation: I was tested on these type of questions

Answer:

The answer is 17-36 (15) (32) *300 divided by 2

Step-by-step explanation:

do the work

Answer:

A. The twelve-pack is better because each soda cost $0.25

Step-by-step explanation:

12 x 0.25 = $3.00 which is only like a buck and 25 cents more for 6 more orange juices.

In the market, you would buy the 12 pack because $1.25 is less than 6 more orange crushes. Also, it's a solid deal and the rate is not pricey! :)

Answer:

$16.125 but i don't know if you have to round

Step-by-step explanation:

a) The light flashes as the circuit leaves the field at a speed of 16 ms.

b) The current flow as the loop exits the field in the clockwise direction.

c) The power dissipated in the bulb during the flash is 0.04 W. 

To reply to these questions, we will utilize Faraday's Law, which states that a changing attractive field actuates an electromotive drive (EMF) in a circuit, and the initiated EMF is rise to the rate of alter of attractive flux through the circuit.

a) The attractive flux through the circle is given by the item of the attractive field, region of the circle, and cosine of the point between the attractive field and the ordinary to the plane of the circle.

As the circle is pulled out of the attractive field, the magnetic flux through the circle diminishes, and thus, an EMF is actuated within the circle. This initiated EMF drives a current through the light bulb, causing it to light up.

The time term of the streak of light can be decided from the time taken by the circle to move out of the attractive field.

The removal voyage by the circle is 40 cm, and the speed is 25 m/s, so the time taken is:

t = d/v = 0.4 m / 25 m/s = 0.016 s = 16 ms

Subsequently, the streak of light endures for 16 ms.

b) Concurring to Lenz's Law, the course of the initiated current is such that it contradicts the alter within the attractive flux that produces it. As the circle is pulled out of the attractive field, the attractive flux through the circle diminishes.

Hence, the actuated current flows in a course that makes a magnetic field that restricts the initial attractive field. This could be accomplished by the induced current streaming clockwise as seen from above. Hence, the reply is clockwise.

c) The control scattered within the light bulb can be calculated utilizing the equation P = V²/R, where V is the voltage over the bulb and R is its resistance.

The voltage over the bulb is break even with to the initiated EMF, which can be calculated from Faraday's Law. The attractive flux through the circle changes at a rate of (40 cm) x (25 m/s) = 1 T.m²/s.

The region of the circle is (40 cm) x (10 cm) = 0.04 m². The cosine of the point between the attractive field and the ordinary plane of the circle is 1 (since the circle is opposite to the field). Subsequently, the induced EMF is:

EMF = -d(phi)/dt = -NA(dB/dt)

= -(1)(0.04 m²)(1 T.m²/s)/0.016 s

= -1 V

The negative sign indicates that the actuated EMF is within the inverse course of the current stream. Subsequently, the voltage over the light bulb is:

V = -EMF = 1 V

The power dissipated within the bulb is:

P = V²/R = (1 V)²/25 ohm = 0.04 W

Subsequently, the control scattered within the bulb during the streak is 0.04 W. 

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Answer: 0.10175

Step-by-step explanation:

First, bring the decimal points to the right for both numbers, to be a total of 5 decimal points to the right. Then, with the numbers 25 and 407, multiply them, and we get 10175. Then, we must bring the 5 decimal points back, and we end up with 0.10175.

Answer: 0.10

Step-by-step explanation:

on time4llearning

Answer:

Step-by-step explanation:

180-68=112

1= 68

2=112

Answer:

4

Step-by-step explanation:

LJK is a special right triangle with angle measures of 90° 60° 30°

If the side length of hypotenuse is 8√2 the side length that sees 30° would be half of it so it's 4√2

LMJ is a special right triangle with angles 90° 45° 45° and if the side length of hypotenuse is 4√2 the the value of equal sides would be 4

The curvature of r(t) = 3t, t2, t3 at the point (3, 1, 1) is 0.178

In this question we need to find the curvature of r(t) = <3t, t^2, t^3> at the point (3, 1, 1).

The derivative of r(t) with respect to t is:

r'(t) = <3, 2t, 3t^2>

The point (3, 1, 1) corresponds to t = 1,

and r′(1) = <3, 2(1), 3(1)^2>

r'(1) = <3, 2, 3>

|r'(1)| = √(3^2 + 2^2 + 3^2)

|r'(1)| = √(9 + 4 + 9)

|r'(1)| = √(22)

|r'(1)| = 4.69

Now, r''(t) = <0, 2, 6t>

and r′'(1) = <0, 2, 6(1)>

r''(1) = <0, 2, 6>

r′(1) × r′′(1) = <0, 4, 18>

|r′(1) × r′′(1) |

= √(0^2 + 4^2 + 18^2)

= √(16 + 324)

= √340

= 18.44

So, the curvature of r(t) would be,

κ(1) = |r′(1) × r′′(1)| ÷ |r′(1)|^3

k(1) = 18.44 / 4.69³

k(1) = 0.178

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A Verilog testbench can be created to generate the waveform for outputs a and b as 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, and 50. The testbench will simulate the behavior of the circuit or module responsible for producing these outputs and verify that the expected waveform is generated.

In Verilog, a testbench is used to simulate the behavior of a circuit or module and test its functionality. It consists of a stimulus generation process and an assertion process to verify the expected behavior. To create a testbench that generates the specified waveform for outputs a and b, we can follow these steps:

Instantiate the module under test: Declare the module and its input/output ports in the testbench.

Define the inputs: Create the required signals or variables to drive the inputs of the module.

Stimulus generation: Write a process or set of procedural blocks to provide the inputs to the module. In this case, we want to generate the waveform for outputs a and b. So, we can assign the values 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, and 50 to the outputs at specific time intervals using delay statements or a clock signal.

Assertion: After providing the inputs, we can add assertions to verify that the outputs match the expected waveform. This ensures that the module is behaving correctly.

Simulation setup: Set up the simulation parameters, such as the time resolution and duration, and run the simulation. By following these steps, the Verilog testbench will produce the desired waveform for outputs a and b. It will verify that the module or circuit correctly generates the expected values at the specified time intervals.

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The peak is at y = 24 feet, the vertex point (h, k) is (16, 24). Plugging these values into the equation, we get:

y = |x - 16| + 24

This equation models the roof line of Terry's house.

To model the roof line of Terry's house, we can use the concept of absolute value. The equation for an absolute value function can be written as:

y = |x - h| + k

where (h, k) represents the vertex of the absolute value graph.

In this case, the peak of the roof line is at 24 feet. Since the width of the house is 32 feet, the vertex of the absolute value graph will be at the midpoint of the width, which is 16 feet. Therefore, h = 16.

Since the peak is at y = 24 feet, the vertex point (h, k) is (16, 24). Plugging these values into the equation, we get:

y = |x - 16| + 24

This equation models the roof line of Terry's house.

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The probability that both randomly selected people own a dog is approximately 0.0361, or 3.61%.

To find the probability that both randomly selected people own a dog, we need to multiply the probabilities of each event occurring.

Given that 19% of people own dogs, the probability that a randomly selected person owns a dog is 0.19.

Since we're selecting two people independently, the probability that both of them own a dog can be calculated by multiplying the probabilities:

P(both own a dog) = P(owning a dog for person 1) * P(owning a dog for person 2)

P(both own a dog) = 0.19 * 0.19 = 0.0361

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Answer:

x+2

=1x+2

=3x.

it's soo easy.

The expression of the mathematical statement is 3x + 4 = 12x - 14 and the solution is x = 2

From the question, we have the following mathematical statement that can be used in our computation:

The product of a number and three increased by four is the same as......

When represented as an expression

We have

3x + 4 = 12x - 14

Where the number is represented by x

Collect the like terms

So, we have

12x - 3x = 14 4

Evaluate

9x = 18

Divide by 9

x = 2

Hence, the mathematical statement when expressed as an expression is 3x + 4 = 12x - 14

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