limif f(x)=cosx−1sin2x, then limx→0f(x) is equivalent to which of the following?

Answer:

a) There are 9 outcomes.

b) **i have attached the tree diagram**

c) 1/9

d) 1/9

Step-by-step explanation:

Both events (choosing a shirt and choosing pants) are not mutually exclusive (disjoint). Meaning that both events can occur at the same time.

a) For a sequence of two events in which the first event can occur m ways and the second event can occur n ways, the events together can occur a total of m • n ways. So for this problem, you would do 3 • 3 which equals 9.

b) **tree diagram is attached**

c) Because there are two different events occurring (choosing a shirt and choosing pants) you need to multiply using the Multiplication Rule for Independent Events : P(A and B) = P(A) * P(B)

The probability of event A occurring (choosing a red shirt) is 1/3 and the probability of event B occurring (choosing brown pants) is also 1/3.

1/3 * 1/3 = 1/9

d) You would do the same thing here as part c.

The probability of event A occurring (choosing a blue shirt) is 1/3 and the probability of event B occurring (choosing blue pants) is again 1/3.

1/3 * 1/3 = 1/9

I hope this was helpful!! :)

b =(17,6x 8,9):19,7=7,95

The statement that accurately describes the form of the sampling distribution is:The inspecting dissemination is regularly circulated with a mean of 37 and standard deviation 1.41.

According to the central limit theorem, regardless of how the population distribution is shaped, the sampling distribution of the sample mean will be approximately normally distributed for a sufficiently large sample size.

For this situation, irregular examples of 32 are drawn from Meredith's patient populace, which fulfills the state of a sufficiently huge example size. The central limit theorem can be used to determine the sampling distribution's mean and standard error.

In this instance, the population mean, which is 37, is equal to the mean of the sampling distribution.

The population standard deviation divided by the square root of the sample size is the sampling distribution's standard error. For this situation, the standard mistake is 8 partitioned by the square foundation of 32, which is around 1.41.

Therefore, the statement that accurately describes the form of the sampling distribution is:

The inspecting dissemination is regularly circulated with a mean of 37 and standard deviation 1.41.

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Answer:

The correct range is thus;

(-6,-12,-9)

Step-by-step explanation:

Here, we want to get the range given the domain

we simply make a substitution of the domain in the equation so as to get the range

So let us substitute the value of the domain one after the other

f(3) is 3-9 = -6

f(-3) = -3-9 = -12

f(0) = 0-9 = -9

The quadratic equation does not have solutions where both x and y are integers.

Here we have the following quadratic equation:

2x^2 + 5y^2 = 14

We want to check that we can't solve this equation with x and y integers, to see that, we can start by isolating one of the variables:

2x^2 + 5y^2 = 14

5y^2 = 14 - 2x^2

y^2 = (14 - 2x^2)/5

y = ±√((14 - 2x^2)/5)

Now, trivially:

(14 - 2x^2)/5

Is not an integer for any integer value of x, and this happens because 5 is not a factor of 14, thus, for any integer value of x the value of y that we get is non integer, then there aren't two integers that solve the quadratic equation.

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Answer:

  2. 26.2 m

  3. 117.2 cm

Step-by-step explanation:

You want the perimeters of two figures involving that are a composite of parts of circles and parts of rectangles.

The circumference of a circle is given by ...

  C = πd . . . . . where d is the diameter

The length of the semicircle of diameter 12.6 m will be ...

  1/2C = 1/2(π)(12.6 m) = 6.3π m ≈ 19.8 m

The two lighted sides of the rectangle have a total length of ...

  3.2 m + 3.2 m = 6.4 m

The length of the light string is the sum of these values:

  19.8 m + 6.4 m = 26.2 m

The length of the string of lights is about 26.2 meters.

The perimeter of the figure is the sum of four quarter-circles of radius 11.4 cm, and 4 straight edges of length 11.4 cm.

Four quarter-circles total one full circle in length, so we can use the formula for the circumference of a circle:

  C = 2πr

  C = 2π·(11.4 cm) = 22.8π cm ≈ 71.6 cm

The four straight sides total ...

  4 × 11.4 cm = 45.6 cm

The perimeter of the figure is the sum of the lengths of the curved sides and the straight sides:

  71.6 cm + 45.6 cm = 117.2 cm

The design has a perimeter of about 117.2 cm.

__

Additional comment

The bottom 12.6 m edge in the figure of problem 2 is part of the perimeter of the shape, but is not included in the length of the light string.

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The constant term (1) is not affected by the modulo operation, we can conclude that for any odd integer n, the expression n^4 mod 16 is equal to 1.

So we have successfully proved the statement that if n is an odd integer, then n^4 mod 16 is equal to 1.

What is an integer?

A whole number (from the Latin integer means "whole") is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 512, and √2 are not. The integers form the smallest group and the smallest circle containing the natural numbers.

To prove the statement "If n is an odd integer, then n^4 mod 16 = 1," we need to show that for any odd integer value of n, the expression n^4 mod 16 always evaluates to 1.

Let us continue the proof by considering properties of odd integers and modular arithmetic.

We begin by assuming that n is an odd integer. By definition, an odd integer can be represented as 2k + 1, where k is an integer.

Now we substitute the value of n in the expression n^4 mod 16:

(2k + 1)^4 mod 16

Expression expansion:

(2k + 1)^4 = 16k^4 + 32k^3 + 24k^2 + 8k + 1

If we take this expression modulo 16, all terms except the constant term (1) will have factors of 16, making them divisible by 16.

The expressions 16k^4, 32k^3, 24k^2, and 8k will all have at least one factor of 16.

Therefore, we can simplify the expression as follows:

(2k + 1)^4 mod 16 ≡ 1 (mod 16)

Since the constant term (1) is not affected by the modulo operation, we can conclude that for any odd integer n, the expression n^4 mod 16 is equal to 1.

So we have successfully proved the statement that if n is an odd integer, then n^4 mod 16 is equal to 1.

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Answer:

24.44%

Step-by-step explanation:

1) Find the difference between 45 and 56 as a number.

2) Divide the result from Step 1 by the starting number 45.

3) Multiply the result from Step 2 by 100 to get it in terms of percent.

The three steps above can be made into a formula. Thus, to find the percent change from 45 to 56, we use this formula:

((Y-X)/X)*100 = Percent Change

X is the starting number 45, and Y is the ending number 56 that it changed to. When we enter these numbers into the formula, we get:

((56-45)/45)*100 = 24.44%

Thus, the answer to the question "What is the Percent Change from 45 to 56?" is:

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

\(M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\)

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(6, 7) and (6,-5)

The midpoint is

\(M = ( \frac{6 + 6}{2} \: , \: \frac{7 - 5}{2} ) \\ = ( \frac{12}{2} \: , \: \frac{2}{2} )\)

We have the final answer as

Hope this helps you

You are absolutely correct

Perhaps in other parts of the country, ticket prices are much cheaper. So, the average of all of the ticket prices turns out to be less.

What do you mean by rates?

A rate in mathematics is the comparison of two related values expressed in different units. The numerator of the ratio indicates the rate of change in the other (dependent) variable if the denominator of the ratio is written as a single unit of one of these quantities, and if it is assumed that this quantity may be modified systematically (i.e., is an independent variable).

1. Perhaps in other parts of the country, ticket prices are much cheaper. So, the average of all of the ticket prices turns out to be less.

2. From 1988 to 1989 the cost of a ticket decreased. Also from 1991 to 1992 the cost decreased a little. The graph slants a little downward.\

3. From 1990 to 1994 the cost stayed pretty much the same. Those years on the graph look almost level... not sloping upward or downward.

4.  1980-1988 price increased from about $2.75 to about $4.25 $1.50 over 8 years = $0.19 per year 1989-1993 price increased from about $4.00 to about $4.20 = $0.20 over 4 years = $0.05 per year 1994-2011 price increased from about $4.20 to about $8.00 $3.80 over 7 years = $0.54 per year

5. Maybe 2012 will be $8.20, 2013 will be $8.30, 2014 will be $8.50, 2015 will be $8.60 ish
Maybe I should make the price go up about $0.17 cents per year ... on average.

6.  1979 maybe $2.52
     1978 maybe $2.36
     1977 maybe $2.19
     1976 maybe $2.02
      975 maybe $1.85
I figured that the price was going down, on average, at about $0.17 per year.

7. one possibility might be y=$5.30/31 x + $2.70 or y = 0.17x+2.7.

8.Using the equation that we fit to this data y = 0.17x + 2.7 we get 0.17(40) + 2.7= $9.50 for the year 2020 and for the year 2030 we get 0.17(50)+2.7 $11.20

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Answer:

Step-by-step explanation:

its b like this the aetter  number g

1.746 is the critical t value that corresponds to 90% confidence.

To find the critical t-value that corresponds to 90% confidence with 16 degrees of freedom, follow these steps:
1. Determine the desired confidence level: 90%
2. Calculate the corresponding significance level (alpha) by subtracting the confidence level from 100%: 100% - 90% = 10%
3. Divide the significance level by 2 to get the value for a two-tailed test: 10% / 2 = 5%
4. Look up the critical t-value in a t-distribution table using the degrees of freedom (16) and the 5% value.

From the t-distribution table, the critical t-value for 16 degrees of freedom and 90% confidence is approximately 1.746.

So, the CRITICAL T VALUE that corresponds to a 90% CONFIDENCE level with 16 DEGREES FREEDOM is 1.746, rounded to three decimal places.

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profit margin does the stadium anticipate for this year 575050

Given,

This year, a stadium manager has booked five performances with a projected aggregate revenue of $1,050,050.

Profit: 1000 - 425 (85 x 5) = 575

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Answer:

A.

continuous data

Step-by-step explanation:

Function A(n) = 2n is continuous data.

" Discrete data is the data which represents finite number and not related to any other variable. It is isolated."

" Continuous data represents the infinite data and it is obtained by measuring. It is related."

According to the question,

A supermarket sell string beans for $2 a pound.

Function A(n) = 2n

It represents the relation between selling of string beans to the price.

Therefore, it is continuous data.

Hence, function A(n) = 2n is continuous data.

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Answer:

1) AD = 9 in

2) DE = 9.25 in

3) ∠EDC = 36°

4) ∠AEB = 108°

5) 11.5 in

Step-by-step explanation:

1) AD = BC = 9in

2) AC = BD (diagonals are equal)

⇒ BD = 14.25

⇒ BE + DE = 14.25

⇒ 5 + DE = 14.25

DE = 9.25

3) Since AB ║CD,

∠ABE = ∠EDC = 36°

4) ∠ABE = ∠BAE = 36°

Also ∠ABE + ∠BAE + ∠AEB = 180 (traingle ABE)

⇒ 36 + 36 + ∠AEB = 180

∠AEB = 108

5) midsegment = (AB + CD)/2

= (8 + 15)/2

11.5

Step-by-step explanation:

you can clear decimals from the equation

use multiplication property of equality to multiply both sides of the equation.

Answer: 14/45

Step-by-step explanation:

Answer:

Here's the solution.

Step-by-step explanation:

Okay so,

12 with an exponent of 5 equals 248832 because you multiply 12*12*12*12*12.

12 with an exponent of 4 equals 20736 because you multiply 12*12*12*12.

Since it's division you use the inverse which is multiplication.

Therefore 248832×20736=5159780352

So 12 with an exponent of what number equals 5159780352?

12 with an exponent of 9.

To check your answer do 5159780352 divided by 248832 which equals 20736.

Therefore your answer would be C.

I hope this helps you understand and your cursor is cool, it's the yin yang symbol, correct? How did you do that?

Answer:
x = −3/2

Step-by-step explanation:

There are 87 fewer fish in small school compared to big school.

We solve addition and subtraction problems by focusing on either the action (joining or separating) or the relationship in the problem. Many problems involve monetary relationships.

This week, we looked at COMPARISON problems, which involve determining the similarities and differences between sets.

Difference Unknown: One type of compare problem entails determining how many more items are in one set than another. James, for example, has six mice. Joy has eleven mice. Joy has how many more mice than James?

Given,

Number of fish in small school = 25

Number of fish in big school =  112

then,

Number of fewer fish does small school have 112 -25 = 87

Thus, there are 87 fewer fish in school than big school.

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The unsigned base 9 equivalent of the unsigned decimal integer value is 2233322

Decimal is a base 10 number system that we use in our daily lives to represent numbers.

In this case, the decimal number 6239124 is being converted to an unsigned base 9 equivalent.

To do this, we first divide the decimal number by 9 to get the first digit of the base 9 equivalent.

In this case, 6239124 divided by 9 is 693234 with a remainder of 2. So, the first digit of the base 9 equivalent is 2.

Next, we take the result of the division

=> (693234) / 9 = 76803 with a remainder of 3.

So, the second digit of the base 9 equivalent is 3.

We repeat this process until the result of the division is 0.

The final result is the base 9 equivalent of the decimal number 6239124. In this case, the base 9 equivalent is 2233322.

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Answer:

False

Step-by-step explanation:linear functions will create a straight line on a graph, exponentials will not.

They may require more advanced techniques from dynamical systems theory to fully understand the behavior of the system.

If both eigenvalues of a critical point of a linear system of differential equations in two dimensions are real and equal, the critical point is a degenerate node.

The behavior of the solutions near a degenerate node depends on the higher-order terms in the Taylor series expansion of the vector field around the critical point. Specifically, the critical point is asymptotically stable if the higher-order terms in the Taylor series expansion satisfy certain conditions, and unstable otherwise.

If the higher-order terms in the Taylor series expansion satisfy the so-called "center manifold" conditions, then the critical point is a center, and the solutions near the critical point exhibit periodic behavior.

In general, the classification of a critical point with real and equal eigenvalues can be more complicated than the case where the eigenvalues have different signs, and may require more advanced techniques from dynamical systems theory to fully understand the behavior of the system.

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The variance for the sum of the squared deviation scores is SS = 20 for a sample of n = 5 scores is 5.

The formula for the variance of a sample is:

\(s^2\) = SS / (n - 1)

where SS is the sum of squared deviation scores, n is the sample size, and \(s^2\) is the variance.

In this case, SS = 20 and n = 5, so we can substitute these values into the formula:

\(s^2\) = 20 / (5 - 1)

\(s^2\) = 5

Therefore, the variance for this sample is 5.

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Answer:

The X axis

Step-by-step explanation:

Answer:

x = 4°

Step-by-step explanation:

According to exterior angle sum property , sum of two opposite interior angles of the triangle is equal to the exterior angle.

So, using exterior angle sum property :-

mBDC + mBCD = mWBC

=> 8x - 1 + 46° = 18x + 5

=> 18x - 8x = 46 - 1 - 5

=> 10x = 40

=> x = 4°

Answer:

it's says that it is ×=1

Step-by-step explanation:

3×-5=2(x-2)

3x-5=2x-4

3x-5+5=2x-4+5

3x=2x+1

3x=2x + 1

3x-2x=2x+1-2x

Answer x=1