Let fR-R;f(x)=x2. Evaluate the two sets f((-1,1)) and f(0,1)). O f((-1,0)=[0,1); f(0,1)=(-1,1) O f(-1,1))=0,1); f'((0,1])=(-1,0) U (0,1) O f((-1,1))=[0,1), f(0,1)=(0,1) O f((-1,1))=[0.1); F'((0,1])=(-1,0) U (0,1) O f((-1,1))=[0,1); f'((0,1)=(-1,0) U (0,1] O f((-1,1))=(0,1); f(0,1])=(0,1) Of((-1,1))=[0,1]: f-'((0,1)=(-1,1)

Answer:

Step-by-step explanation:

Answer: A (2,5)

Step-by-step explanation: Remove Parenthesis

                                             y = 3 (2) - 1

                                             Simplify 3 (2) - 1

                                             Multiply 3 by 2

                                             y = 6 - 1

                                             Subtract 1 from 6

                                             y = 5

Use the x and y values to from the ordered pair.

(2,5)

Answer:

(2.5)

Step-by-step explanation:

The length of June's scarf change using patterns and structure is 4.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Given that;

The length of friend june scarf= 4 feet

The representation of length of june after a month= 0.5x4

Now,

Sue knitted a scarf for her friend June that was also 4 feet long and, after a month, the length of June's scarf is given by the expression 3/3 x 4, to know how did the length of June's scarf change you must perform the following calculation;

Month; 1 = 4

Month; 2 = 3/3 x 4 = 1 x 4 = 4

Therefore, by algebra the the answer will be 4.

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Answer:

D. Vertex: (3, -1); zeros: (2,0), (4,0), y-intercept: (0,8)

Step-by-step explanation:

I used the desmos graphing calculator. Just plug in your equation and it should be pretty easy to find these points

Answer:

Vertex is (3,-1)  zeros ( 4,0) (2,0) and y intercept (0,8)

Step-by-step explanation:

y = x^2 - 6x+8

Factor

y = (x-4) (x-2)

Set = 0 to find the zeros

0 = (x-4) (x-2)

Using the zero product property

x-4 = 0    x-2 =0

x=4   x=2

The vertex is 1/2 way between the zeros

(4+2)/2 = 6/2 = 3

y = (3-4) (3-2)

  -1 (1)

y = -1

Vertex is (3,-1)

The y intercept is at x=0

y = 0-0+8

y =8

Answer:

$750,000

Step-by-step explanation:

$750,000 $680,000 $600,000 $880,000 $1,200,000 $760,000 $480,000

Write the prices in increasing order and choose the middle one.

$480,000 $600,000 $680,000 $750,000 $760,000 $880,000 $1,200,000

Answer: $750,000

Answer:

5

Step-by-step explanation:

slopes of the parallel lines are always same this line has slope five

because equation in y intercept form is y=mx+b

where m is the slope.

so the slope of the new line will be five

Answer:

The percent increase = 100%

Step-by-step explanation:

We need to determine the percentage increase.

Using the formula

% increase = 100% × (final - initial)/ initial

                   =  100% × (4 - 2)/2

                   =  100% × 2/2

                   = 100% × 1

                   = 100%

Thus, the percent increase = 100%

Answer: 3x - 4v

Steep by step explanation: All you do is keep it the same because you just simplify

The curve with parametric equations x = sin(t), y = 3sin(2t), z = sin(3t) can be graphed in three-dimensional space. To find the total length of this curve, we need to calculate the arc length along the curve.

To find the arc length of a curve defined by parametric equations, we use the formula:

L = ∫ sqrt((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2) dt

In this case, we need to find the derivatives dx/dt, dy/dt, and dz/dt, and then substitute them into the formula.

Taking the derivatives:

dx/dt = cos(t)

dy/dt = 6cos(2t)

dz/dt = 3cos(3t)

Substituting the derivatives into the formula:

L = ∫ sqrt((cos(t))^2 + (6cos(2t))^2 + (3cos(3t))^2) dt

To calculate the total length of the curve, we integrate the above expression with respect to t over the appropriate interval.

After performing the integration, the resulting value will give us the total length of the curve. Rounding this value to four decimal places will provide the final answer.

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Answer:

Between the edges of the first two triangles there is a ratio. To find this ratio, you need to ratio one edge of a small triangle to one edge of a large triangle. So 5/30=6/36=8/48=1/5. The ratio we want to find is 1/5 or 5.

Answer:

4 vans, 6 cars

Step-by-step explanation:

Answer:

$300 because $36,450 X 0.10 is equals to $3,645 divided by 12months is equals to $303.75

round off by the nearest hundred is $300.

Respuesta:

9 años

Explicación paso a paso:

Dado :

Capital = Principal, P = 8500 €

Rendimiento, tasa, r = 3,75%

Intereses, i = 2868,75 €

Para obtener el plazo, número de años que se necesitarán para devengar un interés de 2868,75 € sobre un capital de 8500 € al tipo del 3,75%;

Interés = principal * tasa * tiempo

2868,75 € = 8500 € * 0,0375 * t

2868,75 € = 318,75 billones €

t = 2868,75 € / 318,75 €

t = 9

Por lo tanto, tomará un período de 9 años.

The variance of the sample mean x = 7 is 18(option c).

Given table:

X          7  5  11   1   11

(x₁ - x)² 0  4  16 36 16​

n = number of observations = 5

Variance σ² = 1/n-1 Σ\(\ \ n} \atop {i=1} \right.\) (\(X_{1}\) - X)²

= 1/5-1 (0 +4 + 16 + 36 + 16)

= 1/4(72)

= 18

Therefore variance σ² = 18

Hence the variance of the sample mean x = 7 is 18.

so option c is correct.

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​

After 10 years, the car will be worth 0.54 of the price when Rob purchases it. The result is obtained using the exponential depreciation equation.

The depreciation can be calculated by the exponential depreciation equation.

y = P (1 - r)ˣ

Where

If given

How much will the car be worth after 10 years?

The depreciation rate would be

r = 6%

r = 6/100

r = 0.06

So, after 10 years, the car would be worth

y = P (1 - r)ˣ

y = P (1 - 0.06)¹⁰

y = P (0.94)¹⁰

y = P (0.54)

y = 0.54P

Hence, after 10 years, the car will be worth 0.54 of its original price.

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Answer:

El costo es:

Primero tenemos un cargo fijo de $140.

Luego tenemos un $25 por cada m^3 consumido.

Entonces, si tenemos x m^3 consumidos en un mes, el cargo de ese mes va a ser:

C(x) = $140 + $25*x.

Esto es una relación linear.

A) En este caso tendríamos x = 140

C(140) = $140 + $25*140 = $3640

B) La formula es, como ya escribimos arriba, C(x) = $140 + $25*x.

C) El grafico estará al final.  En el podemos ver que la linea corta el eje vertical en y = $140, que seria lo minimo que se puede pagar al mes, en el caso de que el consumo sea x = 0.

D) La ordenada al origen es $140, representa el cargo fijo que no depende de la variable x.

Answer:

240000

Step-by-step explanation:

Answer:

240,000

Step-by-step explanation:

Pretend it is only 4 ten thousands. It would be 40,000. Since it is 24, there are 2.4 times more digits, so it would be 240,000 since it is at least 10 times more than a thousand which would be the 40,000 .

In case anyone needs 24 ten thousandths in the future:

0.0024

0.00024 is equal to 24 hundred-thousandths and there are tenths (0.1), hundredths (0.01), and thousandths (0.001). Then ten thousandths would just be a step lower (0.0001) but since there are 24, it would go into the thousandths place but have the four in the ten thousandths. So it would be 0.0024.

Based on the straight line being parallel to the line, L1, and the gradient, the equation of the straight line L2 is y = 2x - 5

The equation of a straight line takes the form:

y = mx + b

Where:

m = slope

b = y - intercept

The slope is the same as the gradient and parallel lines have the same gradient. The gradient of L2 is therefore 2 as well.

Use this gradient and the point (0, -5) to find the y - intercept:

-5 = 2(0) + y - intercept

y - intercept = -5

The equation of the line is:

y = 2x - 5

Full question is:

A straight line, L2, is parallel to the straight line L1 and passes through the point (0,-5). L1 has a gradient, 2.

Find an equation of the straight line L2.

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Answer:

1/10

0.1

Step-by-step explanation:

To find the percentage of all students who like science but not humanities, we need to subtract the percentage of students who chose both science and humanities from the percentage of students who chose science only. 30% of all students like Science but not Humanities.

So, the percentage of students who like science but not humanities is:

41% (students who chose science) - 11% (students who chose both science and humanities) = 30%

Therefore, 30% of all students like science but not humanities.

To find the percentage of students who like Science but not Humanities, we need to subtract the percentage of students who chose both from the percentage who chose Science. Here's the step-by-step explanation:

1. The percentage of students who chose Science: 41%
2. The percentage of students who chose both Science and Humanities: 11%
3. Subtract the percentage of students who chose both from the percentage who chose Science: 41% - 11% = 30%

So, 30% of all students like Science but not Humanities.

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For k = - 3 and n = - 2, the expression evaluates to - 6.

We have the following expression -

- \(k^{2}\) - (9k - 7n) + 5n

We have to evaluate the above expression for k = - 3 and n = - 2.

The expression ax + b for x = - 2 can be evaluated as follows -

Substituting the value of x = - 2, we get :  - 2a + b

We can similarly solve the expression given to us -

- \(k^{2}\) - (9k - 7n) + 5n

Substitute k = - 3 and n = - 2 in the equation, we get -

\(-(-3)^{2} - (9\times -3 \;\;-\;\;7\times -2) + 5\times -2\)

- 9 - (- 27 + 14) - 10

- 9 + 27 - 14 - 10

18 - 14 - 10

18 - 24

- 6

Hence, for k = - 3 and n = - 2, the expression evaluates to  - 6.

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To show that the matrix A = [XX - X'Z(ZZ)^(-1)Z'X] is positive definite, we need to demonstrate two properties: (1) A is symmetric, and (2) all eigenvalues of A are positive.

Symmetry: To show that A is symmetric, we need to prove that A' = A, where A' represents the transpose of A. Taking the transpose of A: A' = [XX - X'Z(ZZ)^(-1)Z'X]'. Using the properties of matrix transpose, we have:

A' = (XX)' - [X'Z(ZZ)^(-1)Z'X]'. The transpose of a sum of matrices is equal to the sum of their transposes, and the transpose of a product of matrices is equal to the product of their transposes in reverse order. Applying these properties, we get: A' = X'X - (X'Z(ZZ)^(-1)Z'X)'.  The transpose of a transpose is equal to the original matrix, so: A' = X'X - X'Z(ZZ)^(-1)Z'X. Comparing this with the original matrix A, we can see that A' = A, which confirms that A is symmetric.  Positive eigenvalues: To show that all eigenvalues of A are positive, we need to demonstrate that for any non-zero vector v, v'Av > 0, where v' represents the transpose of v. Considering the expression v'Av: v'Av = v'[XX - X'Z(ZZ)^(-1)Z'X]v

Expanding the expression using matrix multiplication : v'Av = v'X'Xv - v'X'Z(ZZ)^(-1)Z'Xv. Since X and Z have full column rank, X'X and ZZ' are positive definite matrices. Additionally, (ZZ)^(-1) is also positive definite. Thus, we can conclude that the second term in the expression, v'X'Z(ZZ)^(-1)Z'Xv, is positive definite.Therefore, v'Av = v'X'Xv - v'X'Z(ZZ)^(-1)Z'Xv > 0 for any non-zero vector v. Implications in econometrics: In econometrics, positive definiteness of a matrix has important implications. In particular, the positive definiteness of the matrix [XX - X'Z(ZZ)^(-1)Z'X] guarantees that it is invertible and plays a crucial role in statistical inference.

When conducting econometric analysis, this positive definiteness implies that the estimator associated with X and Z is consistent, efficient, and unbiased. It ensures that the estimated coefficients and their standard errors are well-defined and meaningful in econometric models. Furthermore, positive definiteness of the matrix helps in verifying the assumptions of econometric models, such as the assumption of non-multicollinearity among the regressors. It also ensures that the estimators are stable and robust to perturbations in the data. Overall, the positive definiteness of the matrix [XX - X'Z(ZZ)^(-1)Z'X] provides theoretical and practical foundations for reliable and valid statistical inference in econometrics.

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Given:

Width of the canvas = 49 inches

The height of the canvas is 3 inches less than the width.

To find:

The area of the canvas.

Solution:

It is given that,

Width of the canvas = 49 inches

The height of the canvas is 3 inches less than the width

So, the height of the canvas is:

\(h=49-3\)

\(h=46\)

We know that the shape of the canvas is a rectangle and the area of the rectangle is:

\(A=length\times width\)

The two dimensions of the canvas are  46 inches and 49 inches. So, the area of the canvas is:

\(A=46\times 49\)

\(A=2254\)

Therefore, the area of the canvas is 2254 square inches.

Based on the text, the primary source of primate endangerment today is habitat destruction.

Habitat destruction is considered the primary source of primate endangerment based on various factors mentioned in the text. Primates, like many other species, heavily rely on their natural habitats for survival, including food, shelter, and breeding. However, human activities such as deforestation, urbanization, and land conversion for agriculture or infrastructure development have significantly reduced and fragmented primate habitats.

Habitat destruction leads to the loss of critical resources and disrupts the ecological balance necessary for primate populations to thrive. As their habitats shrink, primates face increased competition for limited resources, reduced access to food and water sources, and decreased opportunities for successful reproduction and rearing of offspring. This loss of habitat also exposes primates to increased vulnerability to predation, disease transmission, and human-wildlife conflicts.

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Answer:

C

Step-by-step explanation:

Hopefully

C

I did it on edge hopefully this helps you and don't think i copied the other person

y =\((x/2)^2 + 1 or y = (x/2)^2 + 1\)

The curve represents a parabola opening upwards. It is symmetric about the y-axis.

Let's eliminate the parameter t and sketch the curves for each exercise:

1. x = t^2 + 2t, y = t + 1

To eliminate the parameter t, we can solve the first equation for t and substitute it into the second equation:

t^2 + 2t = x

t = -1 ± √(x + 1)

Substituting the expression for t into the equation y = t + 1, we get:

y = (-1 ± √(x + 1)) + 1

y = -√(x + 1) or y = √(x + 1)

The curve represents two branches of a parabola opening upwards. It is symmetric about the y-axis.

2. x = cos(t), y = sin(t), (0, 2π]

Eliminating the parameter t, we obtain:

\(x^2 + y^2 = cos^2(t) + sin^2(t) \\= 1\)

The curve represents a circle centered at the origin with a radius of 1. It covers a full revolution (360 degrees or 2π) in the counterclockwise direction.

3. x = 2t + 4, y = t - 1

By eliminating the parameter t, we have:

t = (x - 4) / 2

Substituting this expression into the equation for y, we get:

y = ((x - 4) / 2) - 1

y = (x - 6) / 2

The curve represents a line with a slope of 1/2 and a y-intercept of -3. It is inclined upwards from left to right.

4. x = 3 - t, y = 2t - 3, 1.5 ≤ t ≤ 3

Eliminating the parameter t, we have:

t = 3 - x

Substituting this expression into the equation for y, we get:

y = 2(3 - x) - 3

y = 6 - 2x - 3

y = -2x + 3

The curve represents a line with a slope of -2 and a y-intercept of 3. It is inclined downwards from left to right.

\(5. x = 2t^2, y = t^4 + 1\)

To eliminate the parameter t, we can solve the first equation for t and substitute it into the second equation:

t^2 = x/2

t = ±√(x/2)

Substituting the expressions for t into the equation y = t^4 + 1, we get:

y = (√(\(x/2))^4\) + 1 or y = (-√\((x/2))^4\) + 1

\(y = (x/2)^2 + 1 or y = (x/2)^2 + 1\)

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The function θ : p(z) → p(z) defined as θ(x) = x is injective and surjective, therefore bijective.

The function θ(x) = x takes an element x from the set p(z) and returns the same element x. This means that for any input x in p(z), the function simply returns x as the output.

To determine whether θ is injective, we need to check if distinct inputs produce distinct outputs. In this case, since the function θ simply returns the input element x, it is evident that if two different elements are provided as input, they will always produce different outputs. Thus, θ is injective.

To assess the surjectivity of θ, we need to determine if every element in the codomain p(z) has a corresponding preimage in the domain p(z). In this scenario, since the function θ returns the same element x that is provided as input, it covers all elements in p(z). Therefore, for any given element in the codomain, there exists a preimage in the domain. Hence, θ is surjective.

Since the function θ is both injective and surjective, it is bijective. This means that for every input element x, there is a unique output element x, and every element in the codomain p(z) has a corresponding preimage in the domain p(z).

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Answer:

I'm pretty sure 44cm2

Step-by-step explanation:

If  im  wrong sorry if Im right give me 5 stars pls