Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of
strength-training
is Laasya performing?

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

For more such questions on equilibrium, click on:

https://brainly.com/question/517289

#SPJ8

Answer: To answer this question, we will need the following equation: SPEED = DISTANCE/TIME (A multiplication and division triangle will be shown)i) The speed of the car is calculated by doing 100 metres/ 20 seconds which gives us 5 metres per second. ii) Rearranging the equation earlier, we can make the distance the subject of the equation so that we get SPEED x TIME = DISTANCE. We worked out the speed and the time was given as 1 minute 40 seconds but we cannot plug in the numbers yet as the time has to be converted to units of seconds (because our speed is in meters per second). 1 minute 40 seconds = 60 seconds + 40 seconds = 100 secondsWe then plug in the numbers to get the distance travelled = 5 metres per second x 100 seconds = 500 metres.

Explanation:

Answer:

See below

Explanation:

Downward force = weight = mg   where g = accel of gravity  9.81 m/s ^2

the tension force acting UPWARD to cause the elevator to accelerate upward is  F = T=m(a+g)   where ' a ' is the UPWARD acceleration ...the tension must be equal to

   the weight of the object + mass of object* acceleration

Because one mole of H X 2 is typically lighter than N e, it stands to reason that it would have a higher entropy than N e. Ne, on the other hand, is thought to have a higher entropy due to its lower molar mass.

A chemical equation can be examined for changes in physical states and the number of moles of product and reactant particles to predict relative changes in entropy using the same factors on a macroscopic level.

The species with the greater molar mass between two monoatomic ones will have a greater standard entropy. The more mobile of two allotropic forms of an element will have a higher standard entropy value. The entropies of these substances are not zero, despite the fact that their conventional internal energies and enthalpies would be. The "energies of formation" of elements in their normal states are typically set to zero because there is no absolute scale of energy.

Entropy, on the other hand, gauges the distribution of energy among the numerous quantum states that can accept it; they exist even in pure substances.

Evidently, entropies often rise with molecule weight. This is, of course, a direct reflection of the fact that translational quantum states are more densely packed in heavier molecules, making them more occupiable, for the noble gases.

The additional impacts of rotational quantum levels are visible in the entropies of the diatomic and polyatomic molecules.

To know more about entropy

https://brainly.com/question/13146879

#SPJ4

Answer:

See below

Explanation:

See diagram below

8 seconds to 60 m/s     then    60 m/s for 22 seconds then   to 0 m/s in 5 seconds

Answer:

8.167

Explanation:

Answer:

Approximately \(2.11\; \rm m\cdot s^{-2}\) (assuming that \(g = 9.81\; \rm m\cdot s^{-2}\), the floor is horizontal, and that the external force is applied horizontally.)

Explanation:

The mass of this couch is \(m = 100\; \rm kg\). Calculate the weight of the couch:

\(W = m \cdot g = 100\; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 981\; \rm N\).

Assume that the floor is horizontal. The magnitude of the normal force between the floor and the couch would be equal to the size of the weight of this couch.

Therefore, the normal force between the floor and the couch would be \(N = 981\; \rm N\).

The first step is to find out whether the couch would move at all.

The question has provided two constants of friction: \(\mu_\text{s}\) (coefficient of static friction) and \(\mu_\text{k}\) (coefficient of kinetic friction.)

The coefficient of static friction applies when the couch is stationary relative to the floor: \(f_\text{s} = \mu_\text{s} \cdot N = 0.40\times 981\; \rm N \approx 313.92\; \rm N\). In other words, while the couch isn't moving, the maximum (horizontal) external force that friction could resist would be \(f_\text{s} = 313.92\; \rm N\).

Assume that the external force in this question is horizontal. The size of the external force (\(525\; \rm N\)) exceeds that of \(f_\text{s}\). Hence, the couch would start to move after the \(525\; \rm N\!\) external force is applied.

Once the couch starts to move, the coefficient of static friction would no longer be relevant. Instead, the coefficient of kinetic friction (\(\mu_\text{k}\)) would give size of the friction between the floor and the couch. The size of that friction would be \(f_\text{k} = \mu_\text{k} \cdot N = 0.32\times 981\; \rm N \approx 313.92\; \rm N\).

This friction would counteract the horizontal external force on the couch. Hence, the net force on the couch in the horizontal direction would be:

\(\begin{aligned}& F(\text{external}) - f_\text{k} \\ &\approx 525\; \rm N - 313.92\; \rm N \\ &\approx 211.08\; \rm N \end{aligned}\).

Apply Newton's Second Law of motion to find the acceleration of the couch:

\(\begin{aligned}a &= \frac{(\text{Net Force})}{m} \\ & \approx \frac{211.08\; \rm N}{100\; \rm kg} \approx 2.11\; \rm m \cdot s^{-2}\end{aligned}\).

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

Answer:

Explanation:

3.  answer is d.

Displacement increases b/c slopes of both lines are positive. Spring 1 displaces more than Spring 2 per unit force applied.  Graphs are straight lines, so the increase is proportional.

4.  Fnet = 5 - 30 - 5 = -30 N       Positive direction is to the right, negative direction is to the left.

answer is d. 30 N to the LEFT

Answer:

A = 2.1 × 10^(-4) m²

Explanation:

We are given;

Temperature; T = 2450 K

Emissivity; ε = 0.35

Bulb rating; H = 150 W

To calculate the surface area, we will use the formula;

H = AεσT⁴

Where σ is stephan boltzman constant with a value of 5.66 × 10^(−8) W/m²⋅K⁴

Making A the subject of the formula, we have;

A = H/εσT⁴

Plugging in the relevant values gives;

A = 150/(0.35 × 5.66 × 10^(−8) × 2450⁴)

A = 2.1 × 10^(-4) m²

The weight of a 190 lb person is 844.5 N.

Newton is the SI (International System) unit of force, named after Sir Isaac Newton, a famous physicist, and mathematician. It is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg m/s²).

To convert pounds (lb) to Newtons (N), we need to use the conversion factor:

1 lb = 4.45 N

Therefore, a 190 lb person weighs:

190 lb × 4.45 N/lb = 844.5 N

So the weight of a 190 lb person is 844.5 N.

Learn more about Newton here:

https://brainly.com/question/20389058

#SPJ1

Answer:

3.4 rad/sec^2

Explanation:

rotational inertia = 2.5 kg-m^2   radius = 1.1 m   force = 7.7 N

t = rotational inertia * angular acceleration    equation 1

also t = force * radius

therefore to calculate angular acceleration equation 1 becomes

f * r = inertia * angular acceleration   hence

angular acceleration = f * r / inertia = \(\frac{7.7 * 1.1 }{2.5}\)   8.47 / 2.5 = 3.388 ≈ 3.4 rad/sec^2

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

The electric field is zero at x = -16.45cm

Data;

As the 3μC is larger than -2.0μC  and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

\(k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\\)

Let's solve for x using mathematical methods.

\(\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0\)

Solving the above quadratic equation;

\(x = -16.45cm\)

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

https://brainly.com/question/1592046

https://brainly.com/question/14372859

The static friction formula is

As you can observe, the normal force is equal to the weight force.

Therefore, the value of the coefficient of static friction is 0.25.

The equation of motion for the rodent is x(t) = -1.12cos(3.20t), and the damping force is Fd = -0.62*vx(t). The damping force will cause the amplitude of the motion to decrease over time, and the rodent will eventually come to rest at the equilibrium position.

We can use the following equations to solve this problem:

F = -kx (Hooke's Law)

F = ma (Newton's Second Law)

a = d^2x/dt^2 (Definition of Acceleration)

Fd = -bv (Definition of Damping Force)

x(t) = A*cos(ωt + φ) (Equation of Motion for Simple Harmonic Motion)

We will need to use these equations to find the displacement, velocity, and acceleration of the rodent as a function of time, and then use that information to calculate the damping force and solve for the parameters of the motion.

First, let's find the natural frequency of the system:

ω = sqrt(k/m) = sqrt(3.50 N/m / 0.400 kg) = 3.20 rad/s

Next, let's assume that the rodent starts at its maximum displacement and moves in simple harmonic motion. We can use the equation of motion for simple harmonic motion to write:

x(t) = A*cos(ωt + φ)

where A is the amplitude of the motion and φ is the phase angle.

To find A and φ, we need to use the initial conditions. We know that at t=0, the rodent is at its maximum displacement, so x(0) = A. We also know that at t=0, the velocity of the rodent is zero, so vx(0) = -Aωsin(φ) = 0. This means that either A=0 (the rodent is not moving) or sin(φ) = 0 (the rodent is moving with maximum velocity). We will assume that the latter is true, so sin(φ) = 0 and cos(φ) = 1.

Now we can write:

x(t) = A*cos(ωt)

To find A, we use the fact that the rodent has a mass of 0.400 kg and is moving on a spring with force constant 3.50 N/m. The force on the rodent is given by:

F = -kx = -3.50 N/m * A*cos(ωt)

At maximum displacement, the force is equal to the weight of the rodent:

mg = 0.400 kg * 9.81 m/s^2 = 3.92 N

So we can write:

3.92 N = -3.50 N/m * A

A = -1.12 m

Therefore, the equation of motion for the rodent is:

x(t) = -1.12cos(3.20t)

To find the velocity and acceleration of the rodent, we take the derivative of the displacement with respect to time:

vx(t) = dx/dt = 3.58sin(3.20t)

ax(t) = d^2x/dt^2 = -11.46cos(3.20t)

To find the damping force, we use the equation:

Fd = -bv = -bdx/dt = -b3.58sin(3.20t)

We don't know the value of b, so we can't solve for it directly. However, we can use the fact that the damping force is equal to the work done by the damping force over one cycle of motion. This work is equal to the energy lost by the system due to damping. Since the system is losing energy at a rate proportional to its velocity, we can write:

Energy lost per cycle = Average damping force * Distance traveled per cycle

The distance traveled per cycle is equal to 2piA = 7.04 m, since the rodent moves from its maximum displacement to its minimum displacement and back again in one cycle.

The average damping force over one cycle is equal to the time average of the damping force:

<Fd> = (1/T)∫[0,T] -bdx/dt dt

where T = 2*pi/ω is the period of the motion. Evaluating the integral gives:

<Fd> = (1/T)∫[0,T] -b(-1.12)3.20sin(3.20*t) dt

<Fd> = 3.58*b

Since the energy lost per cycle is also equal to (1/2)kA^2, we can write:

(1/2)kA^2 = <Fd>2pi*A

Solving for b, we get:

b = (kA)/(2pi)

Substituting the given values, we get:

b = (3.50 N/m * 1.12 m)/(2*pi) = 0.62 Ns/m

Therefore, the equation of motion for the rodent is:

x(t) = -1.12cos(3.20t)

vx(t) = 3.58sin(3.20t)

ax(t) = -11.46cos(3.20t)

and the damping force is given by:

Fd = -0.62*vx(t)

Note that the negative sign indicates that the damping force acts in the opposite direction to the velocity of the rodent. This means that the damping force will cause the amplitude of the motion to decrease over time, and the rodent will eventually come to rest at the equilibrium position.

Therefore,The equation of motion for the rodent is x(t) = -1.12cos(3.20t), and the damping force is Fd = -0.62*vx(t).

To learn more about Newton's law of motion click:

brainly.com/question/29775827

#SPJ1

Answer:

356°C.

Explanation:

(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.

That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.

(2). The next thing to do is to determine the fourier number.

fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.

(3). The next thing is to determine the temperature at the center plane after 15 s of heating.

The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).

The temperature at the center plane after 15 s of heating = 356°C.

Answer:

Bob will be able to stop in time.

I think the final answer should be reported to two significant figures.

Explanation:

First, it is necessary to calculate the time (in s) it takes ol' Bob to stop his vehicle.  Use kinematic equation #1 and the given data to determine the time.  For this problem, let

\(V_i=25.5\frac{m}{s}\\V_f=0.0\frac{m}{s}\\a=-7.2\frac{m}{s^2}\)

Acceleration is a negative value because it opposes the current motion of the vehicle.

So,

\(V_f=V_i+at\\0.0\frac{m}{s}=25.5\frac{m}{s}+(-7.2\frac{m}{s^2})t\\-25.5\frac{m}{s}=(-7.2\frac{m}{s^2})t\\3.5s=t\)

Next, use kinematic equation #2 and the calculated time to solve for Δx:

\(\Delta x=(\frac{V_i+V_f}{2})t\\\Delta x=(\frac{25.5\frac{m}{s}+0.0\frac{m}{s}}{2})(3.5s)\\\Delta x=(12.75\frac{m}{s})(3.5s)\\\Delta x=45.2m\)

45.2m < 52m, so Bob and our crepuscular ungulate will not bump into each other.

I would say that the final answer should have two significant figures because the value for acceleration is given to two significant figures.  The rules for significant figures state that when multiplying or dividing, the number of significant figures in the answer is determined by the value with the lowest number of significant figures.  So, the value for time can only be recorded as having two significant figures.  Since time is used as a multiplier to determine the distance traveled, the final answer should also be reported to two significant figures.  I think.

, the answer is 2020 kV

Electric potential of a point charge is

so

Step 1

Diagram:

Step 2

distances:fromthe center to each charge:

:

Step 3

electric potential due to each charge.

a) Q1

b)Q2

c)Q3

d)Q4

so, the resultant electric potential are:

:

So

therefore, the answer is 2020 kV

I hope this helps you

Answer:

Part A: \(1.97ms^{-1}\) (2 s.f.)
Part B: 0.33m (2 s.f.)

Explanation:

Part A:

Frequency = \(\frac{1}{period} = \frac{1}{3}\) Hz

Wavespeed = frequency x wavelength
Wavelength = distance between two crests = 5.90

Freq = 1/3 Hz

Therefore: Wavespeed = 1/3 x 5.90

                  Wavespeed = 1.967 ms^-1

Part B:
Amplitude = \(\frac{peak-to-peak- amplitude }{2}\)

Peak to peak amplitude = 0.65m

Amplitude = 0.65/2 = 0.325m = 0.33m 2sf

Answer:

The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.

Answer:

The time period of the empty car will be "1.00 s".

Explanation:

The given values in the question will be:

Mass,

m = 250 kg

Loaded car's time period will be:

T = 1.08 s

Shock absorbers compression,

x = 4 cm

or,

  = 0.04 m

Now,

Weight of passengers will be:

⇒  \(F=mg\)

         \(=250\times 9.8\)

         \(=2450 \ N\)

The spring constant of shock absorbers will be:

⇒  \(k=\frac{F}{x}\)

        \(=\frac{2450}{0.04}\)

        \(=61.250 \ N/m\)

As we know,

Time period, \(T = 2 \pi\sqrt{\frac{M}{k} }\)

On substituting the values, we get

                   \(1.08=2\pi \sqrt{\frac{M}{61250} }\)

                  \(\frac{M}{61250}=0.02955\)

                      \(M=0.02955\times 61250\)

                           \(=1809.6 \ kg\) (Total mass of car as well as its passengers)

Now,

The mass of the empty car will be:

⇒  \(m'=M-m\)

          \(=1809.6-250\)

          \(=1559.6 \ kg\)

hence,

The time period of empty car will be:

⇒  \(T'=2\pi\sqrt{\frac{m'}{k} }\)

         \(=2\pi\sqrt{\frac{1559.6}{61250} }\)

         \(=2\pi \sqrt{0.0254}\)

         \(=1.003 \ s\)

or,

         \(=1.00 \ s\)

43.8 m

Explanation:

The only force acting on the car is the frictional force f and since friction is a force that is always directed opposite to the direction of motion, it will have a negative sign. Therefore, we can write Newton's 2nd law as

\(x:\;\;\;\;F_{net} = -f = -\mu N = ma\) (1)

\(y:\;\;\;\;F_{net} = N - mg = 0\) (2)

Substituting Eqn(2) into Eqn(1), we get

\(\Rightarrow a = -\mu g\) (3)

To find the stopping distance x, we are going to use the equation

\(v^2 = v_0^2 + 2ax\)

Initially, the car was moving at \(v_0 = 27\:\text{m/s}.\) When it stopped, its final velocity \(v\) is zero. Using these, as well as Eqn(3) on the equation for v^2, we find that

\(0 = v_0^2 + 2(-\mu g)x \Rightarrow 0 = v_0^2 - 2\mu gx\)

or solving for x,

\(x = \dfrac{v_0^2}{2\mu g} = \dfrac{(27\:\text{m/s})^2}{2(0.85)(9.8\:\text{m/s}^2)}\)

\(\:\:\:\:= 43.8\:\text{m}\)

Answer:

Anyway, space exploration absolutely does give us a direct benefit. When space technology has advanced far enough, we will be able to leave this planet in large numbers and live among the stars. This will solve our population/environment/resource/energy problems for a long, long time. Even a fraction of the money spent annually on space exploration could save millions of people in poverty-stricken countries, and improve living conditions for future generations. The foundations of the world we live in are largely based on science and it is indeed vital to extend our knowledge of the universe.

                                            Thank You

                                        Please mark me brainliest

The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:

Potential energy (PE) = mass (m) × gravity (g) × height (h)

Where:

m = 2.5 kg (mass of the object)

g = 9.8 m/s² (acceleration due to gravity on Earth)

h = ? (height)

First, let's find the height (h) by rearranging the formula:

h = PE / (m × g)

Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):

Energy (E) = power (P) × time (t)

E = 0.20 kW × 1 min × 3,600 J/kW

Now, we can substitute the values into the equation to find the height:

h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)

Calculating the expression on the right side:

h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)

Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

For more such questions on Energy & Power

https://brainly.com/question/1634438

#SPJ11