Answer:
True
Explanation:
Answer:
True is the correct answer
Explanation:
i took the test
I have the mass but I can't find (b) or (c)
In 1986, a gargantuan iceberg broke away from the Ross Ice Shelf in Antarctica. It was approximately a rectangle 160 km long, 40.0 km wide, and 250 m thick.
(a) What is the mass of this iceberg, given that the density of ice is 917 kg/m3?
(b) How much heat transfer (in joules) is needed to melt it?
(c) How many years would it take sunlight alone to melt ice this thick, if the ice absorbs an average of 100 W/m2, 12.00 h per day?
Answer:
i only wrote this for points
Explanation:
what is observed when a charged perspex rod is placed close to a suspended polystyrene sphere
When a charged body is placed near the conductor, the opposite charge is appeared on the one side of the uncharged conductor body near the charged body under the effect of induction.
The opposite charge on the another body is also known as the induced charge.
The perpex rod in the given question is charged.
let the charge on the perpex is positive as shown in the figure.
Then, the polystrene sphers (insulator uncharged sphere) will not have any charge induced as the charges are not free to move inside the insulator.
Thus, when a charged perspex rod is placed close to a suspended polystyrene sphere then the induced charge on the sphere is not observed under the phenomenon of induction process and sphere remain uncharged.
Dr. Gonzalez wants to measure how how room temperature affects a students ability to focus in class. In this experiment, room temperature would be the:
In this experiment, room temperature would be the independent variable.
The independent variable is the factor that is being manipulated or changed by the researcher in an experiment.
In this case, the researcher, Dr. Gonzalez, is interested in measuring how changes in room temperature affect a student's ability to focus in class.
To conduct the experiment, Dr. Gonzalez would need to manipulate the room temperature, for example by adjusting the thermostat, while keeping all other variables constant.
The dependent variable, on the other hand, is the variable that is being measured or observed and is expected to change as a result of the independent variable.
In this case, the dependent variable would be the students' ability to focus in class.
Dr. Gonzalez could measure this by using a standardized test or by observing the students during class and noting any changes in their behavior or performance.
As with any scientific experiment, it's important to control for any extraneous variables that could affect the results.
In this case, Dr. Gonzalez would need to ensure that all other factors that could affect a student's ability to focus (such as noise level, lighting, or time of day) are kept constant throughout the experiment.
By manipulating the independent variable (room temperature) while keeping all other variables constant, Dr. Gonzalez would be able to determine whether changes in room temperature have a significant impact on students' ability to focus in class.
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At what voltage can a 10 μF capacitor be energized to 0.45 J?
Given :
Capacity of capacitor is, \(C = 10\ \mu F\).
To Find :
At what voltage can a 10 μF capacitor be energized to 0.45 J.
Solution :
We know, energy in capacitor is given by :
\(E = \dfrac{CV^2}{2}\)
So,
\(V = \sqrt{\dfrac{2E}{C}}\\\\V = \sqrt{\dfrac{2\times 0.45}{10}}\ \mu V\\\\V = 0.3 \ \mu V\)
Therefore, voltage required is \(0.3 \ \mu V\) .
the pages of a book are numbered 1 to 300. Each leaf is 0.1 mm thick . If each cover is 0.25 mm thick. what is the thickness of the book
Answer:
30.5mm
Explanation:
There are 300 pages, so to find the number of pages we do 0.1mm*300 to get 30mm. There are two covers in the book (the front and the back). 0.25mm*2 = 0.5mm. To determine the total thickness of the book we do 30mm+0.5mm to get a total of 30.5mm
Your answer is 30.5mm.
Answer:
15.5mm
Explanation:
there are 150 pages(one page has 2 sides so 300/2 = 150) and 2 covers
page's thickness is 0.1mm, cover's thickness is 0.25
so books thickness = 150*0.1+0.25*2 = 15.5mm
...
Assist please
A steel tape 20 m long standardized at 55° F with a pull of 10 kg was used for measuring a base line. Find the correction per tape length, if the temperature at the time of measurement was 80°F and
The correction per tape length, due to the change in temperature from 55°F to 80°F, is approximately 0.003333 m.
To calculate the correction per tape length for a steel tape used for measuring a baseline, we need to consider the effects of temperature on the length of the tape.
The change in length of a material due to temperature can be determined using the coefficient of linear expansion (\(\alpha\)). The equation to calculate the change in length (\(\Delta L\)) is given by:
\(\Delta L = L_0 \cdot \alpha \cdot \Delta T\)
where:
- \(\Delta L\) is the change in length,
- \(L_0\) is the initial length of the tape,
- \(\alpha\) is the coefficient of linear expansion for steel (which is approximately 12 x 10^(-6) per degree Celsius),
- \(\Delta T\) is the change in temperature.
In this case, we need to calculate the correction per tape length for a change in temperature from 55°F to 80°F.
First, let's convert the temperatures to degrees Celsius:
- Initial temperature \(T_0 = 55°F\) is approximately 12.78°C
- Final temperature \(T_f = 80°F\) is approximately 26.67°C
Now calculate the change in temperature:
\(\Delta T = T_f - T_0 = 26.67°C - 12.78°C = 13.89°C\)
Given that the initial length of the tape is 20 m, substitute the values into the equation:
\(\Delta L = 20 \, \text{m} \cdot (12 \times 10^{-6} \, \text{per degree Celsius}) \cdot 13.89°C\)
Calculating the expression:
\(\Delta L \approx 0.003333 \, \text{m}\)
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Which standing wave has exactly 2 anti-nodes
A standing wave is formed by the superposition of two waves traveling in opposite directions, resulting in points of constructive and destructive interference. Anti-nodes are points of maximum displacement, where the amplitude of the wave is at its highest.
To have exactly 2 anti-nodes, we need a standing wave pattern with two peaks of displacement. One possible configuration is the second harmonic, also known as the first overtone.
In the second harmonic, the wave has two complete wavelengths between the two ends of the system. The wave undergoes one complete cycle (from peak to trough and back) within each wavelength. The nodes (points of zero displacement) occur at the ends of the system, while the two anti-nodes (points of maximum displacement) are located in the middle, equidistant from the nodes.
The second harmonic is commonly observed in systems such as strings fixed at both ends or open tubes with one closed end. For example, plucking a guitar string at the halfway point creates a second harmonic standing wave pattern with two anti-nodes.
In summary, a standing wave with exactly 2 anti-nodes corresponds to the second harmonic or the first overtone, where there are two peaks of displacement separated by one complete wavelength.
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what is the least restrictive isolation level that will prevent dirty reads?
READ COMMITTED is the least restrictive isolation level that can prevent dirty reads.
The least restrictive isolation level that will prevent dirty reads is the READ COMMITTED isolation level. This level allows only committed data to be read by transactions. If a transaction is updating a row, it locks that row to ensure that other transactions can't read or modify the data until the transaction is completed and the lock is released. This means that dirty reads cannot occur since uncommitted data is not accessible.READ COMMITTED level allows for better concurrency and performance since it doesn't block other transactions from accessing other rows that are not being modified.
In conclusion, READ COMMITTED is the least restrictive isolation level that can prevent dirty reads.
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with what force in the rightward direction, fx , should marcel push? if your expression would give a negative result (using actual values) that just means the force should be toward the left.
The force in the rightward direction, fx , should Marcel push is this force leads to counterclockwise torque. Fx = - (w L2 + w L3 - W Lend) / h.
A force in physics is an effect that changes the velocity, or acceleration, of a mass-moving object. It is a vector quantity since it can be a push or a pull and always has magnitude and direction.
Viewing equilibrium of torque:
W Lend + Fx × h = w L2 + wL3
Fx = (w L2 + w L3 - WLend) / h
In the rightward direction, Fx,
Fx = - (w L2 + w L3 - W Lend) / h
Thus, this force leads to counterclockwise torque.
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The given question is incomplete, so the most probable complete question is,
With what force in the rightward direction, fx , should Marcel push? if your expression would give a negative result (using actual values) that just means the force should be toward the left.
The image of the question is attached below.
Consider you are X units in distance from a light source. You receive Y unit of light per unit time. You have to be _____ X units in distance from the light source in order to receive 4Y unit of light per unit time.
when it takes 4x units of distance from the light for you to receive 4Y units of light in a given amount of time.
What is a distance?Distance is a measurement of the separation between two things or locations, either quantitatively or qualitatively. A physical distance or perhaps an estimate relying on other physics- or usage-related characteristics can both be referred to as distance. The phrase is also employed metaphorically to denote a measurement of the degree of distance between two common pieces since spatial intelligence is a rich source of implicatures in human understanding. The majority of these concepts of distance, both literal and figurative, are codified using the idea of a metric space.
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A proton of kinetic energy 2. 80 MeV travels head-on toward a lead nucleus which is fixed in space. Assuming that the proton does not penetrate the nucleus and that the only force between proton and nucleus is the Coulomb force, calculate the smallest center-to-center separation dp between proton and nucleus when the proton momentarily stops. If the proton were replaced with an alpha particle (which contains two protons) of the same initial kinetic energy, the alpha particle would stop at center-to-center separation da. What is da/dp?
The smallest center-to-center separation dp between proton and nucleus when the proton momentarily stops is 4.17 x 10^-14m and the ratio da/dp is 2:1.
Given the kinetic energy of proton (KE) = 2.80MeV
The charge if proton (q1) = 1.6 x 10^-19C
The proton hits a lead nucleus. So, the atomic number of lead = 82
The charge on lead nucleus (q2) = 82e = 82 x 1.6 x 10^-19
The Coulomb force is the sole force that exists between the proton and the nucleus because the proton cannot enter the nucleus.
We know that KE = q1V where V is the potential difference
We know that from coulombs law V = kq2/r where r is separation distance
Then r = dp such that dp = kq1/V = kqxq2/KE = kq1q2/KE
dp = (8.9 x 10^9)(1e)(82e)/2.8 MeV
dp = 1167.68 x 10^-10/2.8 x 10^6 = 4.17 x 10^-14m
The the smallest center-to-center separation dp between proton and nucleus is 4.17 x 10^-14m
If the proton was replaced by two alpha particle charge (q1) = 2e
The separation between alpha particle and nucleus = da
da = (8.9 x 10^9)(2e)(82e)/2.8x10^6eV = 2335.36x10^-16/2.8 = 8.34x10^-14m
Hence the required ratio of da/dp = 8.34x10^-14m/4.17 x 10^-14m = 2:1
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if we shake the branches of tree the fruits fall why
Answer:
Explanation:
when a tree is shaken it's fruits and leaves fall down due to the gravitational force exerted by earth.
All fruits and leaves do not fall when tree is shaken, mostly only those fruits and leaves are fallen that are ripped.
It's because their tissues has become weak
The large, roughly circular, dark, and somewhat younger regions on the moon are called?
The large, roughly circular, dark, and somewhat younger regions on the moon are called Maria.
What is Maria?Lunar Maria are large, dark, basaltic plains on Earth's Moon. It was created by an ancient asteroid impacting the Moon on the far side and triggering some volcanic activity on the opposite side.
These are vast basins containing lava flows that are marked by craters, ridges, faults and straight and immersed valleys called rills. They are waterless. There are about 20 major areas of this type. Most of which include the largest located on the side of the Moon that always faces Earth.
These maria were the result of the melting and eruption of basaltic lava on the lunar surface 3.8 to 2.8 billion years ago. This type of lava was highly fluid under the Moon's weak gravitational field and spread over vast distances.
Thus, the large, roughly circular, dark, and somewhat younger regions on the moon are called Maria.
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What is Light ?
What are 7 spectrums of Light ?
Answer:
Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that is perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nanometres, between the infrared and the ultraviolet.
Here are the 7 from shortest to longest wavelength.
Violet - shortest wavelength, around 400-420 nanometers with highest frequency.
Indigo - 420 - 440 nm.
Blue - 440 - 490 nm.
Green - 490 - 570 nm.
Yellow - 570 - 585 nm.
Orange - 585 - 620 nm.
Red - longest wavelength, at around 620 - 780 nanometers with lowest frequency.
Explanation:
An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
Let Va is the velocity of the airplane
Va is the velocity of the wind
When flying against the wind then
(Va+Vw)*(3.2 hours) = 640
3.2Va + 3.2Vw = 640
3.2Vw = 640 - 3.2Va
Vw = 200 - Va----------------(1)
When flying with the wind:
(Va-V)*(2 hours) = 640km
2Va - 2Vw = 640
Va - Vw = 320 ----------------(2)
Putting the value of VW in equation (2) we get
Va - (200-Va) = 320
2Va = 320 +200
2Va = 520
Va = 260
Putting this value in equation (2)
Vw =Va - 360
Vw = 100
Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
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28. A car with an initial velocity of 24.5 m/s east has an
acceleration of 4.2 m/s2 west. What is its displacement
at the moment that its velocity is 18.3 m/s east?
The displacement of the car after the given final velocity is 31.59 m.
The given parameters;
Initial velocity of the car, u = 24.5 m/s eastFinal velocity of the car, v = 18.3 m/s eastAcceleration of the car, a = 4.2 m/s²The displacement of the car after the given final velocity is obtained by applying the third kinematic equation as shown below;
v² = u² + 2as
\(s = \frac{v^2 - u^2}{2a} \\\\s = \frac{(18.3)^2 - (24.5)^2}{2(-4.2)} \\\\s = 31.59 \ m\)
Thus, the displacement of the car after the given final velocity is 31.59 m.
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. Explain What makes the rock cycle a cycle?
SC.7.E.6.2 hi how do you do this
The Rock cycle is a model that describes the formation degradation, and regeneration of rocks as a result of sedimentation magma, and metamorphism. All rocks are made of minerals.
Rock circulation is the process by which rocks change continuously between three types igneous sedimentary and metamorphic. The three processes that transform one rock into another are crystallization, metamorphism erosion, and sedimentation. Any rock can be transformed into another rock by undergoing one or more of these processes. This creates a lock cycle.
Rock circulation is a fundamental concept that describes the transition between three rock types metamorphic igneous, and sedimentary rocks. Simply put it is a set of processes that create and transform rock types within the Earth's crust. Rock cycling by definition is the natural process by which sedimentary igneous, and metamorphic rocks are formed, transformed from one type to another, and destroyed.
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If a bowling ball weighing 3,630 g is accelerating down the alley at a rate of 4 m/s2, then what is the net force applied to the bowling ball?
Answer:
\(\huge\boxed{\sf F = 14.52\ N}\)
Explanation:
Given data:Mass = m = 3,630 g = 3.63 kg
Acceleration = a = 4 m/s²
Required:Force = F = ?
Formula:F = ma
Solution:Put the given data in the above formula.
F = (3.63)(4)
F = 14.52 N\(\rule[225]{225}{2}\)
How far does a freely falling apple drop in 7.4 s after being released from rest?
The freely falling apple will travel 268.32 meters along y-axis
We need to know about free fall motion to solve this problem. The free fall motion should follow this rule
vt = gt
vt² = 2gh
h = 1/2 . g . t²
where vt is final velocity, g is the gravitational acceleration (9.8 m/s²), h os height and t is time.
From the question above, we know that
t = 7.4 s
Use the third equation to get the distance (height)
h = 1/2 . g . t²
h = 1/2 . 9.8 . 7.4²
h = 268.32 m
The freely falling apple will travel 268.32 meters along y-axis.
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A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult. Assuming the acceleration is constant, how far did it travel during those 2.0 s?
First find Acceleration
Initial velocity=u=0m/sFinal velocity=v=42m/sTime=t=2sDistance=sAcceleration=a\(\boxed{\sf Acceleration=\dfrac{v-u}{t}}\)
\(\\ \sf\longmapsto Acceleration=\dfrac{42-0}{2}\)
\(\\ \sf\longmapsto Acceleration=\dfrac{42}{2}\)
\(\\ \sf\longmapsto Acceleration=21m/s^2\)
Using second equation of kinematics
\(\boxed{\sf s=ut+\dfrac{1}{2}at^2}\)
\(\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}(21)(2)^2\)
\(\\ \sf\longmapsto s=21(2)\)
\(\\ \sf\longmapsto s=42m\)
A cable of 10 mm outside is to be laid in an atmosphere of 25 degree Celsius (h = 12.5 W/m2 degree) and its surface temperature is likely to be 75 degree Celsius due to heat generated within it. How would the heat flow from the cable be affected if it is insulated with rubber having thermal conductivity k = 0.15 W/m degree?
a) 43.80 W per meter length
b) 53.80 W per meter length
c) 63.80 W per meter length
d) 73.80 W per meter length
Insulating the cable with rubber having a thermal conductivity of 0.15 W/m degree increases the heat flow from the cable to 63.80 W per meter length compared to a non-insulated cable in an atmosphere with a temperature difference of 50 degrees Celsius. The correct option is C.
To determine how the heat flow from the cable is affected by insulation, we need to calculate the heat transfer rate for both the insulated and non-insulated cases. The heat transfer rate can be determined using the formula:
Q = (T2 - T1) / (R_total)
Where:
Q is the heat transfer rate per unit length (W/m),
T2 is the surface temperature of the cable (75 degrees Celsius),
T1 is the ambient temperature (25 degrees Celsius),
R_total is the total thermal resistance.
For the non-insulated case:
R_total = R_convection
For the insulated case:
R_total = R_convection + R_insulation
Let's calculate the heat transfer rate for both cases:
Non-insulated case:
R_convection = 1 / (h * A)
A = 2 * π * r * L (surface area of the cable)
Q_non-insulated = (T₂ - T₁) / (R_convection)
Insulated case:
R_insulation = d / (k * A)
Q_insulated = (T₂ - T₁) / (R_convection + R_insulation)
Given the information:
h = 12.5 W/m² degree
k = 0.15 W/m degree
d = 10 mm = 0.01 m
T₂ = 75 degrees Celsius
T₁ = 25 degrees Celsius
By comparing the heat transfer rates for the non-insulated and insulated cases, we can determine the effect of insulation on the heat flow from the cable.
Therefore, by Calculating the values and comparing the heat transfer rates, we find that the correct option is c) 63.80 W per meter length.
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On a pool of water (n = 1.5) there is a thin layer of oil (n =
1.2). Where does a phase difference occur?
a) only at the first transition
b) only at the second transition
c) at both transitions
d) no
The phase difference occurs at both transitions.
When light passes from one medium to another with a different refractive index, it undergoes a change in speed and direction, resulting in the phenomenon known as refraction. In this case, light travels from water (n = 1.5) to oil (n = 1.2), and then from oil to air (or vice versa).
At the first transition, when light passes from water to oil, there will be a phase difference. This is because the speed of light changes as it enters the oil, causing the wavefronts to bend and the phase of the wave to shift.
At the second transition, when light passes from oil to air, there will also be a phase difference. Again, the change in speed and direction of light as it enters the air causes the wavefronts to bend and the phase of the wave to shift.
Therefore, the correct answer is c) at both transitions
A phase difference occur: A phase difference occurs at both transitions. The correct option is c.
When light travels from one medium to another with a different refractive index, a phase difference occurs. In this case, the light travels from the pool of water (n = 1.5) to the layer of oil (n = 1.2), and then from the oil back to the water. At each transition, there is a change in the refractive index, causing the light waves to undergo a phase shift.
The phase shift is determined by the difference in the optical path length traveled by the light in the two media. Since the refractive index of oil is lower than that of water, the light waves experience a shorter optical path length in the oil compared to the water. This leads to a phase difference when the light waves pass through the interface between the water and oil, as well as when they pass back from the oil to the water.
Therefore, at both transitions, there will be a phase difference between the light waves due to the difference in refractive indices. The correct option is c.
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Complete question:
On a pool of water (n = 1.5) there is a thin layer of oil (n = 1.2). Where does a phase difference occur?
a) only at the first transition
b) only at the second transition
c) at both transitions
d) no phase difference
After overcome that from of friction you must push against.... friction
Answer:
In static friction, the frictional force resists force that is applied to an object, and the object remains at rest until the force of static friction is overcome. In kinetic friction, the frictional force resists the motion of an object. For the case of a brick…
consider a planet whose rotation axis is not tilted with respect to its orbital plane. what are the seasons like on this planet?
As the planet orbits the sun, the angle at which the sunlight hits the planet's surface may change slightly, but this does not result in significant changes in the amount of sunlight that the planet receives.
On a planet whose rotation axis is not tilted with respect to its orbital plane, the seasons are not pronounced. This is because the amount of sunlight that the planet receives does not change significantly throughout the year.
In contrast, on a planet with a tilted rotation axis, the seasons are much more pronounced. As the planet orbits the sun, the angle at which the sunlight hits the planet's surface changes significantly, resulting in longer periods of sunlight in certain parts of the planet and shorter periods of sunlight in other parts. This leads to significant differences in temperature and weather patterns, resulting in the four distinct seasons that we experience on Earth.
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A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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what properties define a mineral? (select all that apply) naturally occurring solid element or compound definite crystalline structure definite chemical composition
The properties that define a mineral include being a naturally occurring solid with a definite crystalline structure and a definite chemical composition.
Therefore, the correct options are:
Naturally occurringSolidDefinite crystalline structureDefinite chemical compositionNaturally occurring means that the mineral is formed by natural processes, rather than being artificially created. Being a solid means that the mineral has a fixed shape and volume, and is not a liquid or gas. The crystalline structure of a mineral refers to the specific arrangement of atoms or molecules that make up its crystal lattice. Finally, the definite chemical composition of a mineral means that it has a specific set of chemical elements in a fixed proportion, which gives it distinct physical and chemical properties.
Overall, these properties help to distinguish minerals from other types of materials and allow them to be identified and studied based on their unique characteristics.
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How long does it take a bicycle to travel 100 m if it goes a speed of 15 m/s?
The time taken for the bicycle to travel the given distance at the given velocity is 6.667 seconds.
Given the data in the question:
Distance travelled by the bicycle; \(S = 100m\)
Speed or velocity of the bicycle; \(v = 15m/s\)
Time taken for the bicycle to travel the given distance; \(t = ?\)
We know that speed is the rate of change of position of an object with respect to time.
That is to say, Speed = Distance / Time
Hence, Time = Distance / Speed
\(t = \frac{S}{v}\)
So, to get our time "t", we simply substitute in our given values
\(t = \frac{100m}{15m/s}\)
\(t = 6.667 s\)
Therefore, the time taken for the bicycle to travel the given distance at the given velocity is 6.667 seconds.
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Students build four electromagnets and test them by picking up metal tacks. Here are their partial results.
12 coils 4 tacks
24 coils 9 tacks 36 coils
13 tacks 48 coils ? tacks
Which is the best prediction for the number of nails the electromagnet with 48 coils will pick up?
a. 16
b. 12
c. 13
d. 20
Option (a) "16" is the best prediction for the number of nails the electromagnet with 48 coils will pick up.
What should be the approach to prediction for the number of nails in the electromagnet?To determine the best prediction for the number of tacks the electromagnet with 48 coils will pick up, we need to examine the relationship between the number of coils and the number of tacks picked up by the electromagnets. From the results given, it appears that as the number of coils increases, the number of tacks picked up also increases.
Based on this relationship, it's reasonable to predict that the electromagnet with 48 coils will pick up more tacks than the one with 36 coils. Given that the electromagnet with 36 coils picked up 13 tacks, a reasonable prediction for the number of tacks the electromagnet with 48 coils will pick up would be between 13 and 20.
In conclusion, a prediction of 16 or 17 tacks for the electromagnet with 48 coils is likely to be a good estimate, given the data provided.
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Answer: The answer is (16)
A bat is flitting about in a cave, navigating via ultrasonic bleeps. Assume that the sound emission frequency of the bat is 38.9 kHz. During one fast swoop directly toward a flat wall surface, the bat is moving at 0.015 times the speed of sound in air. What frequency does the bat hear reflected off the wall?
Answer:
40085 Hz
Explanation:
We are given; Sound frequency emmision of bat;f = 38.9 kHz = 38900 Hz
Bat is moving at 0.015 times the speed of sound in air.
Speed of sound in air = 343 m/s
The formula for waves reflected off the wall is calculated from Doppler equation as:
f' = f(v + v_d)/(v - v_s)
Where;
f is the frequency = 38900 Hz
f' is the detected frequency,
v_d is the velocity of the detector = 0.015 × 343 = 5.145
v_s is the velocity of the source = 0.015 × 343 = 5.145 m/s
v is the velocity of the sound = 343 m/s
Thus;
f' = 38900(343 + 5.145)/(343 - 5.145)
f' ≈ 40085 Hz
What term best describes the regular path of a spacecraft or other object around a planetary body?
a. Cycle
b. Orbit
c. Rotation
d. Spin
Answer:
Explanation:
b. orbit