It takes 50 seconds for a wave with a wavelength of 0.2 m to travel past you. What is the frequency of the wave?A.10 HzB.250 HzC.0.02 HzD.0.5 Hz

Answers

Answer 1

Answer:

C. 0.02 Hz

Explanation:

The wavelength is 0.2 m and the period is 50 seconds because the period is the time that the wave takes to travel past you. Then, the frequency can be calculated as

f = 1/T

Where T is the period. Replacing T = 50 s, we get

f = 1/50

f = 0.02 Hz

Therefore, the frequency of the wave is

C. 0.02 Hz


Related Questions

A sheet of metals brass is 40cm long and 8cm broad at 0c if a surface area at 100c is 320. 1cm^2 find a coefficient of linear expansion of the brass

Answers

The Coefficient of linear expansion of the brass =  1.56 * 10 ⁻⁶  

Thermal expansion is the tendency to be counted to trade its form, vicinity, volume, and density in reaction to an exchange in temperature, typically not including phase transitions. Temperature is a monotonic function of the average molecular kinetic electricity of a substance.

Length of metal sheet = 40 cm

broad = 8 cm

Initial Surface area = 40 × 8 = 320 cm²

Final surface area = 320.1  cm²

Change in area ΔA = 320.1  cm² - 320 cm² = 0.1 cm².

change in temperature ΔT = T final -T initial  

                                       ΔT = 100 - 0 = 100

α =  coefficient of linear expansion

β =  coefficient of Surfacial expansion

         ΔA = A initial β  ΔT

          β =   ΔA/A initial  ΔT

          β =  0.1 / 320 *100

          β = 3.125 * 10 ⁻⁶

Relation between α and β :

         α =  β/2

        α = 3.125 * 10 ⁻⁶/2

        α = 1.56 * 10 ⁻⁶   answer.

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What is the power of a motor that transfers 550 J of energy in 11s?

Answers

Answer:

The answer is 50 watts

Explanation:

The formula of power is work done over elapsed time

P= W/t
P= 550 J / 11 sec

P= 50 watts

A curve on a highway has a radius of curvature of 200.0 m. What is the magnitude of a car’s centripetal acceleration as it travels along this curve at a constant speed of 26.8 m/s in 4.00 s?

Answers

Answer:

173.2

Explanation:

The centripetal acceleration of the car moving in a radius of curvature of 200 m with a velocity of 26.8 m/s is 3.591 \(m/s^2\).

What is centripetal acceleration?

The centripetal acceleration is the rate at which a body moves through a circle. Considering that velocity is a vector quantity (that is, it has both a magnitude, speed, and direction). When a body moves in a circle, its direction is constantly changing, which causes a change in velocity and acceleration.

The circle's center is where the acceleration is pointed radially. The square of the body's speed along the curve divided by the distance r from the circle's center to the moving body determines the centripetal acceleration, which has a magnitude equal to ac.

Given information:

The velocity of the car, \(v=26.8 \ m/s\),

The radius of the curvature, \(r=200\ m\).

Calculate the acceleration by the formula given below,

\(\alpha =v^2/r\)

\(\alpha\) is the acceleration,

Substitute the values,

\(\alpha =(26.8)^2/200\)

\(\alpha = 3.591\ m/s^2\)

Therefore, the centripetal acceleration of the car moving in curvature is 3.591 \(m/s^2\)

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Your friend has decided to make some money during the next State Fair by inventing a game of skill. In the game as she has developed it so far, the customer shoots a rifle at a 5.0 cm diameter target falling straight down. Anyone who hits the target in the center wins a stuffed animal. Each shot would cost 50 cents. The rifle would be mounted on a pivot 1.0 meter above the ground so that it can point in any direction at any angle. When shooting, the customer stands 100 meters from where the target would hit the ground if the bullet misses. At the instant that the bullet is fired (with velocity of 1200 ft/sec according to the manual), the target is released from its holder 7.0 meters above the ground. (You see, the trigger is electronically connected to the release mechanism.) Your friend asks you to try out the game which she has set up on a farm outside of town. Before you fire the gun you calculate where you should aim. You may, as usual, neglect any effects of air resistance. Your conclusion? At what angle from the vertical should you aim?

Answers

Answer: from the vertical, one should aim  86.6°

Explanation:

height of the center of object = 7.0 m - 0.05 m = 6.95 m

now let the bullet hits centre at point A height x meters from the ground

also let t be the time taken for the bullet to hit the object

so distance travelled by the target will be

d = h - x = 6.95 - x

now using the equation of motion

d = 1/2gt²

so 1/2gt² = 6.95 - x

x = 6.95 - 1/2gt² .........let this be equ 1

let angle of fire be ∅

so v(cos∅) × t = 100

our velocity v is 1200 ft/sec = 365.76 m/s

365.76(cos∅) × t = 100 ........equ 2

also vertical position of the bullet after t is

y = y₀ + c(sin∅)t - 1/2gt²

y = 1 + 365.76(sin∅)t - 1/2gt² ----- equ 3

After time t. the vertical position x and y are same, else the bullet wouldn't have strike target at centre, so;

x = y

we substitute

equ 1 = equ 3

6.95 - 1/2gt² = 1 + 365.76(sin∅)t - 1/2gt²

6.95 - 1 = 365.76(sin∅)t - 1/2gt² +  1/2gt²

5.95 = 365.76(sin∅)t

t = 5.96 / 365.76(sin∅)

now input the above equ  into equ 2

365.76(cos∅) ×  5.96/365.76(sin∅) = 100

5.95(cos∅)/sin∅ = 100

tan∅ = 5.95/100 = 0.0595

∅ =  3.40°

therefore from the vertical, one should aim (90° - 3.40°) = 86.6°

Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?

Answers

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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You are a sound engineer working on a music festival and need to calculate the speed of sound in the air. You measure the distance between the sound source and a microphone to be 10 meters and the time it takes for the sound to reach the microphone to be 0.05 seconds. What is the speed of sound in the air? (Units: speed - meters per second (m/s), distance - meters (m), time - seconds (s))
2 You are an electrician w orking on a circuit. You need to calculate the electric current flowing through a wire with a resistance of 10 ohms and a voltage of 50 volts. What is the electric current flowing through the wire? If the wire has a length of 10 meters and a cross - sectiona l area of 0.5 square meters, what is the electric conductivity of the wire? (Units: current - amperes (A), resistance - ohms (Ω), voltage - volts (V), length - meters (m), cross - sectional area - square meters (m^2), electric conductivity - siemens per mete r (S/m))

Answers

The electric conductivity of the wire is 0.05 siemens per meter (S/m).

To calculate the speed of sound in the air, you can use the formula:

Speed of sound = Distance / Time

In this case, the distance is 10 meters and the time is 0.05 seconds:

Speed of sound = 10 m / 0.05 s = 200 m/s

Therefore, the speed of sound in the air is 200 meters per second (m/s).

To calculate the electric current flowing through a wire, you can use Ohm's Law:

Current = Voltage / Resistance

In this case, the voltage is 50 volts and the resistance is 10 ohms:

Current = 50 V / 10 Ω = 5 A

Therefore, the electric current flowing through the wire is 5 amperes (A).

To calculate the electric conductivity of the wire, you can use the formula:

Electric conductivity = 1 / Resistance * (Cross-sectional area / Length)

In this case, the resistance is 10 ohms, the length is 10 meters, and the cross-sectional area is 0.5 square meters:

Electric conductivity = 1 / 10 Ω * (0.5 m^2 / 10 m) = 0.05 S/m

Therefore, the electric conductivity of the wire is 0.05 siemens per meter (S/m).

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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Suppose you have a barometer with mercury and a barometer with water. How does the height hwater compare with the height hmercury?.

Answers

The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.

Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.

Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.

This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.

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A 60-kg woman runs up a staircase 15 m high (vertically) in 20 s.

Required:
a. How much power does she expend?
b. What is her horsepowerrating.

Answers

Answer:

(a) 441 W (b) 0.59 hP

Explanation:

Given that,

Mass of a woman, m = 60 kg

Height of a staircase, h = 15 m

Time, t = 20 s

(a) We need to find the power she expend. Work done per unit time is called power. It is given by :

\(P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\P=441\ W\)

( b) Since, 1 hP = 745.7 W

P = 0.59 hP

An object with a mass of 7 kg accelerates 8 m/s2 when an unknown force is applied to it. What is the amount of the force?

Answers

The amount of force applied to the 7kg object that caused it to accelerate at 8m/s² is 56 newtons.

What is the force applied to the object?

A force is simply a push or a pull of an object resulting from the object's interaction with another object.

From newton's second law;

Force = mass × acceleration

Given the data in the question;

Mass of the object = 7kgAcceleration = 8m/s²Applied force = ?

Plug the given values into the formula to determine the applied force.

Force = mass × acceleration

Force = 7kg × 8m/s²

Force = 56kgm/s²

Force = 56 N

Therefore, the applied force is 56 newtons.

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A force of 150 N is used to push a motorcycle 10 m along a road in 20 s.

Calculate WORK done in joules.

(Work = Force x Distance)

Calculate POWER in Watts

(Power = Work / Time) Work = 75 Watts

Power = 1500 Joules


Work = 1500 Joules

Power = 75 Watts


Work = 1500 Joules

Power = 1500 Watts


Work = 3000 Watts

Power = 75 Joules

Answers

Answer:

beuhhhhhhhghhhhhhhhhhh

what is output light frequency of material used before doubling

Answers

The output light frequency of material used before doubling will be 0.056 Hz.

What is frequency?

The term frequency refers to the number of repetitions that there will be for a certain unit of time. Frequency is usually measured in hertz (Hz). The hertz is going to tell us the number of frequencies per second, which would then be a cycle per second.

The frequency can be calculated by counting the number of occurrences within a time interval and dividing by the time that elapsed in that period. So the calculation will be:

                                                  1 Hz=\(\frac{1}{s}\)

A term that is related to the frequency and that is reciprocal to it is the period, which refers to the duration of time of a cycle in an event that is going to be repeated.

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The tires of a car make 77 revolutions as the car reduces its speed uniformly from 95.0 km/h to 65.0 km/h. The tires have a diameter of 0.90 m.
If the car continues to decelerate at this rate, how far does it go? Find the total distance.

Answers

Answer:

Explanation:

95.0 km/hr = 26.39 m/s

65 km/hr = 18.06 m/s

Circumference of a tire is 0.9π m

77 revolutions is a distance of

77(0.9π) = 69.3π m

v² = u² + 2as

a = (v² - u²) / 2s

a = (18.06² - 26.39²) / (2(69.3π))

a = -0.85 m/s²

s = (v² - u²) / 2a

s = (0² - 26.39²) / 2(-0.85)

s = 409 m

If 10 waves pass one dock every 16.0 seconds, determine the frequency of the wave.

Answers

The frequency of the wave is 0.625 waves per second, calculated by dividing the number of waves (10) by the time (16.0 seconds).

To determine the frequency of a wave, you need to divide the number of waves (in this case, 10) by the time it takes for those waves to pass a certain point (in this case, a dock) within 16.0 seconds.

Frequency is usually measured in Hertz (Hz), which represents the number of cycles or events per second. So, to find the frequency, we calculate 10 waves / 16.0 seconds = 0.625 waves per second or 0.625 Hz.

This means that every second, 0.625 waves pass by the dock, giving you the frequency of the wave.

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Which planet is terrestrial? Jupiter Mars Saturn Uranus

Answers

Answer: The planet Mars is terrestrial.

Terrestrial planets are made of rock, earth, or a solid substance. Your other options, Jupiter, Saturn, and Uranus, are all made up of a mixture of gases.

Hope this helps!

The answer is Mars.

What is a terrestrial planet's simple definition?

Terrestrial planets are Earth-like planets made up of rocks or metals with a hard surface. Terrestrial planets also have a molten heavy-metal core, few moons, and topological features such as valleys, volcanoes, and craters.

What is the difference between terrestrial and jovian planets?

Terrestrial planets are smaller, closer to the Sun, and formed from the rock around a molten metal core. They have secondary atmospheres, fewer moons, and a slower spin. Jovian planets are larger, further from the Sun, and formed from gases around a solid metal and hydrogen core.

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Normal temperature of human body is 98.6F while its atmosphere temperature is 84.6F what will be temperature of dead body in such atmosphere
A. 84.6F
B. 98.6F
C. 92.5F
D. 185F

Answers

Answer:

B. 98.6F is the temperature of dead body in 84.6F atmosphere.

Answer:

See below

Explanation:

After a while, the body will assume the temperature of its surroundings

  and will be  84.6 degrees F

 IMMEDIATLY after death the body will still be at 98.6 F ...but beginning to cool......

PLEASE HELP PLS ITS DUE IN 10 MINUTES!!
Suppose you’re standing at the top of a 100m high building. How much potential energy would you lose if you walked down the stairs by 20m?
You are now standing at a height of 80m. How much potential energy would you lose if you went down by 20m?
Suppose now you decide to go down by 20m more (you’re standing at 60m high). How much potential energy would you need to get to 40? Can you draw any conclusions about potential energy from this observation?

Answers

Answer:

I AM SO SORRY

but here is the answer

Explanation:

20 j

Mass
7. If the mass of the diver is 75 kg. What is the height he jumped
from?

Answers

Answer:

The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.

Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:

PE = mgh

Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.

When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:

KE = (1/2)mv^2

Where v is the velocity of the diver just before hitting the water.

According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:

mgh = (1/2)mv^2

h = (1/2)v^2/g

We need to find the value of v to calculate h. We can use the kinematic equation:

v^2 = u^2 + 2as

Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).

Substituting the values, we get:

v^2 = 2gh

v^2 = 2 * 9.8 * h

v^2 = 19.6h

Therefore:

h = v^2/(19.6)

Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:

h = (10^2)/(2*9.8) = 51 meters

Therefore, the height from which the diver jumped is approximately 51 meters.

You walk 5.0 km to the east and then turn and travel 8.0 km to the north. Determine your resultant displacement. (Resultant includes hypotenuse, theta,
and direction)

Answers

We can obtain the resultant displacement by geometry as 9.4 m North East

What is displacement?

Displacement is the distance covered in a specific direction. It is a vector quantity hence its resultant must be obtained geometrically.

Given that, we can obtain the resultant displacement by the use of the Pythagoras theorem;

R= √(5)^2 + (8)^2

R = 9.4 m North East

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What is the speed of each ball when they are each 4.10 m above the ground?

What is the speed of each ball when they are each 4.10 m above the ground?

Answers

ANSWER:

12.3 m/s

STEP-BY-STEP EXPLANATION:

The vertical speed can be calculated by means of the following equation:

\(v^2_{^{}y}=u^2_y+2\cdot a\cdot s\)

The speed in both cases is the same, since the angle remains the same.

We can calculate the initial speed in y since we know the angle, the value s would be the height, therefore, we substitute and calculate the final speed in y:

\(\begin{gathered} v^2_y=(11\cdot\sin 50)^2+2\cdot(-9.8)\cdot(-4.1) \\ v^2_y=151.36 \\ v_y=\sqrt[]{151.36} \\ v_y=12.3\text{ m/s} \end{gathered}\)

The speed would be 12.3 m/s in both cases

12.3 m/s is the correct answer

ge(s): What factors affect the speed of
sound waves?

Answers

Answer:

The speed varies depending on atmospheric conditions; the most important factor is the temperature. Humidity has little effect on the speed of sound, nor does air pressure by itself. Air pressure has no effect at all in an ideal gas approximation.

Calculate the speed of a 5 kg object that possesses 20 J of kinetic energy KE=1/2
mv2
2.83 m/s/s
2.83 m/s
2 m/s
4 m/s

Answers

Answer:

2.83 m/s

Explanation:

m = 5 kg,

KE = 20 J

KE = mv^2/2

20 = 5*v^2/2

5*v^2 = 40

v^2 = 8

v = \(\sqrt{8}\) = 2.83 m/s

In a race, Usain Bolt accelerates at
1.99 m/s2 for the first 60.0 m, then
decelerates at -0.266 m/s2 for the final
40.0 m. What was his final velocity? (Unit = m/s)

Answers

100 is his final velocity to his speed

A 6.35 kg bowling ball moving 8.49 m/s strikes
a 1.59 kg bowling pin at rest. After, the pin moves 20.1 m/s at a -77.0° angle. What is
the x and y component of the ball's final velocity?

Answers

The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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The block falls for a time t0, but the string does not completely unwind. What is the change in angular momentum of the pulley-block system from the instant that the block is released from rest until time t0?

Answers

The change in angular momentum of the pulley-block system is given as \(\omega = Rm_ogt_o\)

Data;

time = t0mass = Mo

Torque

This is the force that makes object rotate about an axis. The formula is given as the product between the radius about the axis and the force acting upon it.

The torque about point o is given as

\(\tau = R * m_og\)

The change in angular momentum about point 'o' is the product between the torque and time.

\(\omega = \tau * t_o\\\omega = Rm_ogt_o\)

The change in angular momentum of the pulley-block system is given as

\(\omega = Rm_ogt_o\)

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A ball is thrown straight up. At the top of its path is instantaneous speed is

Answers

Answer:

If a ball is thrown straight up, its instantaneous velocity at the top of its path is 0 m/s, but its acceleration is 10 m/s2. ... Its acceleration can't be zero - that would mean that its velocity would not change

Explanation:

When a ball is hurled straight up, it has an instantaneous top speed of 0 m/s but an acceleration of 10 m/s². Since its velocity wouldn't change if its acceleration were zero, it can't be.

What is instantaneous speed?

The instantaneous speed, as its name suggests, has to do with how fast an item is moving at a particular moment in time. The brief distance that an object has gone divided by the equivalent amount of time can also be used to determine its instantaneous speed. With each instant that passes, the instantaneous speed can fluctuate.

An automobile's speedometer, for instance, displays the vehicle's current speed. The instantaneous speed of the car might be 50 kmph at one point, and with a light press of the pedal, it might increase to 54 kmph at the next.

When the ball is thrown straight up, with the increase in height the speed of the ball starts to reduce, at the top the speed will become zero.

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If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?

Answers

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

Time of motion of the girl

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

v is initial vertical velocity = 0t is time of motiong is acceleration due to gravity

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

Final vertical velocity of the skydiver

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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pathogens grow best at which temperature

Answers

Pathogens grow best at temperatures between 5°C and 60°C.

The ideal temperature range for food-poisoning bacteria to develop is between 5°C and 60°C. The temperature danger zone is the name given to this temperature zone.

The bacteria can't thrive if potentially dangerous items are kept heated (above 60°C) or cold (below 5°C). Bacteria can double in number in as little as 20 minutes at temperatures between 40 °F and 140 °F, where they proliferate the fastest.

FATTOM, an acronym for food, acidity, time, temperature, oxygen, and moisture, stands for the elements necessary for bacterial growth.

Due to their availability of nutrition, energy, and other elements that the bacteria require for growth, foods offer the ideal conditions for bacterial growth.

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find a vector(s) of length √15m in the x-z plane that is perpendicular to the vector A= (2i+3j+k) m

Answers

The vector that is perpendicular to the original vector is vector B = (√3 i  - 2√3 k )

What is the vector that is perpendicular to the original vector?

The vector that is perpendicular to the original vector is calculated as follows;

Let the vector = B = (xi + 0j + zk)

The dot product of A and B must be equal to zero.

A . B = (2i + 3j + k) . (xi + 0j + zk)

A.B = 2x  + z = 0

2x = - z

The product of the vector must be √15 and it is calculated as;

√ (x² + z²) = √15

x² + z² = 15

Substitute the value of x for z;

x²  +  (-2x)² = 15

x² + 4x² = 15

5x² = 15

x² = 15/5

x² = 3

x = √3

z = - 2x

z = -2√3

The vector B = (√3 i  - 2√3 k )

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The law of ellipse simple explanation

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Kepler's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. ... The resulting shape will be an ellipse. An ellipse is a special curve in which the sum of the distances from every point on the curve to two other points is a constan

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