Answer:
any luck bro with this question
Step-by-step explanation:
a diver was collecting water samples from a lake. he collected a sample at every 3m, starting at 5m below water surface. the final sample was collected at a depth of 35m.how many sample did he collected
The diver collected water samples at every 3 meters, starting from 5 meters below the water surface, up to a final depth of 35 meters.
We can find the number of samples collected by dividing the total depth range by the distance between each sample and then adding 1 to include the first sample.
The total depth range is:
35 m - 5 m = 30 m
The distance between each sample is 3 m, so the number of samples is:
(30 m) / (3 m/sample) + 1 = 10 + 1 = 11
Therefore, the diver collected a total of 11 water samples.
how to tell if a graph is a function?
Answer:
If you take a vertical line and place it on the graph, then no matter where on the graph you place the vertical line, the graph should only cross the vertical line once. If so, then it is a vertical line.
If not, then it isn't one.
Step-by-step explanation:
Write : linear equation to represent the line shown on the graph.
The equation of the line that passes through the points (0,-2) and (3,2) is 4x-3y-6 = 0.
What is equation of line?A line's equation is an algebraic way of expressing the collection of points that make up a line in a coordinate system.
The many points that collectively make up a line on the coordinate axis are represented as a group of variables (x, y) to create an algebraic equation, also known as an equation of a line.
In the given graph,
The points are (0,-2) and (3,2)
To find the equation of the line,
Find slope by using formula m = (y₂-y₁)/(x₂-x₁)
m = (2-(-2))/(3-0)
m = 4/3
The equation of line is,
y-y₁ = m (x-x₁)
y-(-2) = 4/3(x-0)
y+2 = 4/3x
3y+6 = 4x
4x-3y-6 = 0
The required equation of line is 4x-3y-6 = 0.
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When coding the phrase "supravesical fissure of urinary bladder," the main term to reference in the index is ________ .a. urinaryb. bladderc. fissured. supravesical
The correct option of the given question is option (c) fissure.
When coding the phrase "supravesical fissure of urinary bladder," the main term to reference in the index is c. fissure.
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The main term to reference in the index when coding the phrase "supravesical fissure of urinary bladder" is c. fissure.
In medical coding, the index is typically organized alphabetically based on the main terms or significant words within medical terminology. In this case, "fissure" is the main term that represents the specific condition or anatomical feature being coded.
The other terms, such as "urinary," "bladder," and "supravesical," provide additional context but are not the primary focus when searching for the appropriate code in the index.
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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point.
x=t^2+1, y=6√t, z=eᵗ²−ᵗ, (2,6,1)
(x(t),y(t),z(t))=( )
The parametric equations for the tangent line to the curve at the point (2, 6, 1) are: x_tan(t) = 2 + 4t , y_tan(t) = 6 + (3√2/2)t , z_tan(t) = 1 + 4e^2t
To find the parametric equations for the tangent line to the curve at the specified point (2, 6, 1), we need to find the derivatives of x(t), y(t), and z(t) with respect to t and evaluate them at the given point. Let's calculate:
Given parametric equations:
x(t) = t^2 + 1
y(t) = 6√t
z(t) = e^(t^2 - t)
Taking derivatives with respect to t:
x'(t) = 2t
y'(t) = 3/t^(1/2)
z'(t) = 2t*e^(t^2 - t)
Now, we can substitute t = 2 into the derivatives to find the slope of the tangent line at the point (2, 6, 1):
x'(2) = 2(2) = 4
y'(2) = 3/(2^(1/2)) = 3√2/2
z'(2) = 2(2)*e^(2^2 - 2) = 4e^2
So, the slope of the tangent line at the point (2, 6, 1) is:
m = (x'(2), y'(2), z'(2)) = (4, 3√2/2, 4e^2)
To obtain the parametric equations for the tangent line, we use the point-slope form of a line. Let's denote the parametric equations of the tangent line as x_tan(t), y_tan(t), and z_tan(t). Since the point (2, 6, 1) lies on the tangent line, we have:
x_tan(t) = 2 + 4t
y_tan(t) = 6 + (3√2/2)t
z_tan(t) = 1 + 4e^2t
Therefore, the parametric equations for the tangent line to the curve at the point (2, 6, 1) are:
x_tan(t) = 2 + 4t
y_tan(t) = 6 + (3√2/2)t
z_tan(t) = 1 + 4e^2t
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Sean has 1/3 of his action figures left over after he donates some of them. He wants to share his remaining action figures with 6 of his friends. What fraction of the original action figures will Sean and his 6 friends each receive?
Sean and his six companions will each receive 1/7 of the original action figures.
Let's assume Sean originally had x action figures. After donating some, he has 1/3 of them left, which is (1/3)x.
To find out how many action figures Sean has left, we can use the equation:
(1/3)x = x - y
where y is the number of action figures Sean donated.
Simplifying this equation, we get:
y = (2/3)x
Now, Sean wants to share his remaining action figures with 6 friends, so they will split the total number of action figures into 7 equal parts (Sean + 6 friends).
Therefore, each person will get 1/7th of the total number of action figures.
To find out what fraction of the original action figures each person will get, we need to divide the number of action figures each person will get by the original number of action figures (x):
1/7 = \(\frac{[(\frac{1}{3} )x - y]}{x}\)
Substituting y = (2/3)x, we get:
1/7 = \(\frac{[(\frac{1}{3} )x - (\frac{2}{3} )x]}{x}\)
1/7 = (1/3)
Therefore, each person will get 1/7th of the original number of action figures.
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1/3(y+7)=3(y−1)
Solve for y
Answer:
2
Step-by-step explanation:
multiplying each number by 1/3 gives
1/3y+7/3= 3y-3
3y-1/3y=7/3+3
8/3y=16/3
y=16/3÷8/3
y=16/3×3/8
y=2
The solution of the equation 1/3(y+7)=3(y−1) will be ; y = 2
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Given that the equation is 1/3(y+7)=3(y−1)
First, multiplying each number by 1/3 gives;
1/3y+7/3= 3y-3
3y-1/3y=7/3+3
8/3y=16/3
Cross multiplication;
y=16/3÷8/3
y=16/3×3/8
y=2
Therefore, the solution of the equation 1/3(y+7)=3(y−1) will be ; y = 2
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What is the area of an equilateral triangle with sides 10 cm and altitude 5 cm
Answer:
25 cm^2
Step-by-step explanation:
The formula for the area of a triangle is \(1/2*base*height\).
We're given the base and height (altitude) in this question. The base is 10 cm and the height is 5 cm. All we have to do is plug them in to the formula now.
\(1/2*10*5\)
\(1/2*50\)
\(25\)
- 28x + 18 = simplest form
Answer:
The answer is -2(14x - 9)
Step-by-step explanation:
Hoped this helped!
Sorry if this is wrong.
What do these (>, ≥, <, ≤) mean
Answer:
Less Than,Less Than or Equal to,Greater Than,Greater Than or Equal to
Step-by-step explanation:
The line under plays the role of an equal sign and the others are pretty self explanatory
Answer: The first one is a greater sign, the second one is greater than or equal to, the third one is less than, and the last one is less than or equal to.
Step-by-step explanation: hope this helps
PLZ HELP EMERGENCY!!Find the total area of the figure below. Round your answer to the nearest tenth.
Answer:
area = 63.25 m²
Step-by-step explanation:
area of triangle = 1/2 x 6 x 8 = 24 m²
area of semi circle = 1/2 x 3.14 x 5² = 39.25 m²
total area = 24 + 39.25 = 63.25 m²
don conducted a survey of two groups (n subscript 1 equals 50 comma space n subscript 2 space end subscript equals 50 )of students that recently graduated from private and public colleges. he found that the mean debt for the students who attended private college was $26,600, while those who attended public colleges had a mean debt of $24,400. don wants to see if the difference in mean debt is statistically significant. what should don state for the null hypothesis?
Don's null hypothesis is that there is no statistically significant difference between the mean debt of students who attended private college and the mean debt of students who attended public colleges, represented as H₀: μ₁ - μ₂ = 0
The null hypothesis (H0) is a statement of "no difference" or "no effect" and is typically represented as "there is no statistically significant difference between the mean debt of students who attended private college and the mean debt of students who attended public colleges." Therefore, in this case, Don's null hypothesis can be stated as
H₀: μ₁ - μ₂ = 0
where μ₁ represents the population mean debt for students who attended private college, and μ₂ represents the population mean debt for students who attended public colleges.
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two fair dice are rolled. the score is the difference between the two dice. some of the possible scores are shown in the table.
c) which score has a probability of occurring 1/18
Answer:
Step-by-step explanation:
a). From the table attached,
Number in 1st column and 1st row = 1 - 1 = 0
Number in 1st column and 6th row = 6 - 1 = 5
Number in 2nd column and 4th row = 4 - 2 = 2
Number in 5th column and 2nd row = 5 - 2 = 3
Number in 6th column and 5th row = 6 - 5 = 1
b). Probability of scoring 1 = \(\frac{\text{Preferred outcome}}{\text{Total outcomes}}\)
Preferred outcomes of getting = 10
Total outcomes = 36
Probability of scoring 1 = \(\frac{10}{36}\)
= \(\frac{5}{18}\)
c). Probability of occurring a score = \(\frac{1}{18}\)
= \(\frac{1\times 2}{18\times 2}\)
= \(\frac{2}{36}\)
= \(\frac{\text{Preferred outcome}}{\text{Total outcomes}}\)
Since, 5 is a number which has occurred twice
Score that has a probability of occurring of \(\frac{1}{18}\) is 5.
In 2014, Congress cut $8.7 billion from the Supplemental Nutrition Assistance Program (SNAP), more commonly referred to as food stamps. The rationale for the decrease is that providing assistance to people will result in the next generation of citizens being more dependent on the government for support. Hoynes (2012) describes a study to evaluate this claim. The study examines 60,782 families over the time period of 1968 to 2009 which is subsequent to the introduction of the Food Stamp Program in 1961. This study examines the impact of a positive and policy-driven change in economic resources available in utero and during childhood on the economic health of individuals in adulthood. The study assembled data linking family background in early childhood to adult health and economic outcomes. The study concluded that the Food Stamp Program has effects decades after initial exposure. Specifically, access to food stamps in childhood leads to a significant reduction in the incidence of metabolic syndrome (obesity, high blood pressure, and diabetes) and, for women, an increase in economic self-sufficiency. Overall, the results suggest substantial internal and external benefits of SNAP. a. Identify the population that is of interest to the researchers. b. Describe the sample. c. What characteristics of the population are of interest to the researchers
Main AnswerIn the study by Hoynes (2012), the population that is of interest to the researchers are families who receive Supplemental Nutrition Assistance Program (SNAP) or more commonly known as food stamps. The study examines the impact of the policy-driven change in economic resources available in utero and during childhood on the economic health of individuals in adulthood.
The sample that the study examines are 60,782 families over the time period of 1968 to 2009, which is subsequent to the introduction of the Food Stamp Program in 1961. The data links family background in early childhood to adult health and economic outcomes.The characteristics of the population that are of interest to the researchers are the impact of a positive and policy-driven change in economic resources available in utero and during childhood on the economic health of individuals in adulthood. Specifically, the researchers looked at the long-term effect of access to food stamps in childhood on the incidence of metabolic syndrome (obesity, high blood pressure, and diabetes) and an increase in economic self-sufficiency for women.
Based on the study, the researchers concluded that access to food stamps in childhood leads to a significant reduction in the incidence of metabolic syndrome and, for women, an increase in economic self-sufficiency. Hence, the results suggest substantial internal and external benefits of SNAP.
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1. Which of the equations below will answer the following question? Check (!) all that apply.
“I think of a number, add 7 and then multiply by 4.
My answer is 80. What was my number?”
1. ¿Cuál de las siguientes ecuaciones responderá a la siguiente pregunta? Marque todo lo que corresponda.
“Pienso en un número, le sumo 7 y luego lo multiplico por 4.
Mi respuesta es 80. ¿Cuál era mi número?”
The correct option is B. 4(x+7) = 80.
Adding 7 to the number then multiplying it with 4 given the result 80 is shown by the equation; 4(x+7) = 80.
What is defined as the mathematical operations?Calculating a value with operands as well as a math operator is referred to as a mathematical "operation." The math operator symbol has predefined rules that must be applied to a given operands and numbers.
Operands are the numbers that are used in an operation. The operands are given different names depending on the type of operation.An operator is a symbol that represents a mathematical operation, such as:+ for addition− for subtraction× for multiplication÷ for division = equal to denotes equivalence, indicating that left hand side value is equal to a right hand side value.Now as per the given question;
Let us assume that the given number is 'x'.
Adding 7 to this number will form; x + 7.
Now, multiplying the number resultant number with 4 gives; 4(x + 7)
Now the number formed is equal to the result 80.
Thus, 4(x + 7) = 80.
Therefore, the equation which correctly represents the given formation is 4(x + 7) = 80.
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The correct question is -
Which of the equations below will answer the following question? Select all that apply. Explain your answers.
I think of a number, add 7 and then multiply by 4. My answer is 80. What was my number?
A. x + 28 = 80
B. 4(x+7) = 80
C. 4x + 7 = 80
D. 4x + 28 = 80
At top speed, a rabbit can cover 6 miles in 12 minutes. If a rabbit could
continue at this rate indefinitely, how long would it take the rabbit to
cross the 220-mile expanse of the Mojave Desert?
Answer:
440 minutes
Step-by-step explanation:
i just multiplied by 2
Exercise 2.1.1 functions: for the given function and domain, specify the associated range: Function: y= 5(1/x) Domain: (1,2,3,4,5,6)
Function: s= Ix+4I Domain: -6≤ x ≤ 6
Case 1 - Range: (5, 5 / 2, 5 / 3, 5 / 4, 1, 5 / 6)
Case 2 - The range of the function is 0 ≤ s ≤ 10.
What are the range of a function?
Functions are characterized by three elements:
An input set known as domain.An output set known as range.Relationships between elements from the domain to the range such that each element of the domain is related to only one element of the range.These relations may be represented, but not exclusively, by equations.The elements of the range are determined by evaluating each function:
Case 1 - y = 5 · (1 / x)
x = 1
y = 5 · (1 / 1) = 5
x = 2
y = 5 · (1 / 2) = 5 / 2
x = 3
y = 5 · (1 / 3) = 5 / 3
x = 4
y = 5 · (1 / 4) = 5 / 4
x = 5
y = 5 · (1 / 5) = 1
x = 6
y = 5 · (1 / 6) = 5 / 6
Range: (5, 5 / 2, 5 / 3, 5 / 4, 1, 5 / 6)
Case 2 - s = |x + 4|
x = - 6
s = |- 6 + 4| = |- 2| = 2
x = - 4
s = |- 4 + 4| = |0| = 0
x = 6
s = |6 + 4| = |10| = 10
The range of the function is 0 ≤ s ≤ 10.
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what is the inequality shown
Answer:
-4 ≤ x ≤ 3
Step-by-step explanation:
A closed circle (●) means 'greater than or equal to' or 'less than or equal to'.
An open circle (○) means 'greater than' or 'less than'
Answer:
3\(\geq\)-4
Step-by-step explanation:
\(\leq, \geq\)° <,>
Evaluate 1∫0 dx/1+x^2. Using Romberg's method. Hence obtain an approximate value of π
Answer:
Step-by-step explanation:
\begin{align*}
T_{1,1} &= \frac{1}{2} (f(0) + f(1)) \\
&= \frac{1}{2} (1 + \frac{1}{2}) \\
&= \frac{3}{4}
\end{align*}
Now, for two subintervals:
\begin{align*}
T_{2,1} &= \frac{1}{4} (f(0) + 2f(1/2) + f(1)) \\
&= \frac{1}{4} \left(1 + 2 \left(\frac{1}{1 + \left(\frac{1}{2}\right)^2}\right) + \frac{1}{1^2}\right) \\
&= \frac{1}{4} \left(1 + 2 \left(\frac{1}{1 + \frac{1}{4}}\right) + 1\right) \\
&= \frac{1}{4} \left(1 + 2 \left(\frac{1}{\frac{5}{4}}\right) + 1\right) \\
&= \frac{1}{4} \left(1 + 2 \cdot \frac{4}{5} + 1\right) \\
&= \frac{1}{4} \left(1 + \frac{8}{5} + 1\right) \\
&= \frac{1}{4} \left(\frac{5}{5} + \frac{8}{5} + \frac{5}{5}\right)
\end{align*}
Thus, the approximate value of the integral using Romberg's method is T_2,1, and this can also be used to obtain an approximate value of π.
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Problem(8) Prove the following two famous Identity/Principle in Discrete Mathematics (a) (Pascal's Identity) Let n and k be positive integers with n≥k, show that ( n+1
k
)=( n
k−1
)+( n
k
). (b) (The Generalized Pigeonhole Principle) Show that if N objects are placed into k boxes, then there is at least one box containing at least ⌈ k
N
⌉ objects. (b') Among 45 students in our Discrete Math at least how many were born in the same month?
In the given Discrete Mathematics class, at least four students were born in the same month.
a) Pascal's Identity:Let us consider a set with n + 1 elements. We need to choose k elements from these. We can choose a subset of k elements in two ways:
(i) Choose one of the n elements as the first element of the subset, then choose k − 1 elements from the remaining n − 1 elements. This can be done in nC1 * (n − 1)C(k − 1) ways.
(ii) The subset does not include the first element. This can be done in nCk ways. Now, we count the number of ways of choosing a subset with k elements from the set with n + 1 elements. This can be done in (n + 1)Ck ways. By the addition principle of counting, we add these two cases and get the identity (n + 1)Ck = nC(k−1) + nCk.b)
The Generalized Pigeonhole Principle:
Let N be the number of objects and k be the number of boxes. Let q be the quotient when N is divided by k. If N is divisible by k, then each box will contain exactly q objects. Otherwise, there will be (N mod k) boxes containing q + 1 objects and the remaining k − (N mod k) boxes containing q objects. At least one of the former boxes will contain at least ⌈N/k⌉ objects.
b') Among 45 students in our Discrete Math at least how many were born in the same month?Let us consider 12 boxes, one for each month. Since there are 45 students, by the Generalized Pigeonhole Principle, at least one box must have ⌈45/12⌉ = 4 students. Therefore, at least four students in our Discrete Math course were born in the same month.
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Someone explain please
Answer:
SA = 94 ft²
Step-by-step explanation:
To find the surface area of a rectangular prism, you can use the equation:
SA = 2 ( wl + hl + hw )
SA = surface area of rectangular prism
l = length
w = width
h = height
In the image, we are given the following information:
l = 4
w = 5
h = 3
Now, let's plug in the information given to us to solve for surface area:
SA = 2 ( wl + hl + hw)
SA = 2 ( 5(4) + 3(4) + 3(5) )
SA = 2 ( 20 + 12 + 15 )
SA = 2 ( 47 )
SA = 94 ft²
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PLEASE HELP ME :(
(X+4)^2-3(x+4)-3=0
Select the solutions of the og equation
Answer:
\(\boxed{\textsf{ The value of x is }\bf{ \dfrac{-5\pm\sqrt{21}}{2}}.}\)
Step-by-step explanation:
A quadratic equation is given to us and we need to find the Solutions of the quadratic equation . So the given equⁿ is ,
\(\sf\implies (x+4)^2 -3(x+4) -3 = 0 \)
Firstly let's simpify the quadratic equation and then use the quadratic formula also known as " Shreedhacharya's Formula" .
Taking the given equation :-
\(\sf\implies (x+4)^2 -3(x+4) -3 = 0\\\\\sf\implies x^2 + 16 + 8x -3x -12 -3 = 0 \\\\\sf\implies x^2+5x +1 = 0 \)
Now let's use the Quadratic formula ,
Quadratic Formula :-
\(\qquad\boxed{\boxed{ \sf x =\dfrac{ -b \pm \sqrt{ b^2-4ac}}{2a} }} \)
With respect to Standard form ax² + bx + c form. Here a = 1 , b = 5 and c = 1 .
\(\sf\implies x = \dfrac{ -5\pm \sqrt{ (5)^2-4(1)(1)}}{2(1)} \\\\\sf\implies x = \dfrac{ -5 \pm \sqrt{ 25 -4 } }{2} \\\\\sf\implies \boxed{\pink{\sf x = \dfrac{-5+\sqrt{21}}{2}, \dfrac{-5-\sqrt{21}}{2} }}\)
Tim and Jane both work for a company that sells boxes of breakfast cereal. the boxes of cereal cost £3.00 and the amount of cereal in each box weighs 160g. the company wants to have a special offer. here is Tim's idea for the special offer: put 25% more cereal in each box and do not change the price here is Jane's idea: reduce the price and do not change the amount of cereal in each box Jane wants her idea to give the same value for money as Tim's idea by what percentage does she need to reduce the price?
Answer:
25%
Step-by-step explanation:
As the given situation the parameters are below:-
Cost of each box = 3 pounds
Amount of cereal in each box = 160 g
now,
160 g of cereal = 100%
and
25% of 1 box of cereal = 25% of 160 g which is
\(= \frac{25}{100} \times 160 g= 40 g\)
As per the question, it is mention that Jane need her idea to give the equal value of amount as Tim's idea, provided
160 g of cereal costs 3 pounds
and
1 g of cereal will cost
= \(\frac{3}{60}\ pounds\)
40 g of cereal will cost \(40\times \frac{3}{160} = \frac{3}{4}\ pounds\)
So, the percentage of \(\frac{3}{4}\) the pound is of 3 pounds is 3 ÷ 4 ÷ 3 × 100
= 25%
Therefore as the situation, Jane need to decline the amount by 25% for the same amount as Tim's idea.
A 10-ft ladder rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1 ft/sec, how fast, in ft/sec, is the top of the ladder sliding down the wall, at the instant when the bottom of the ladder is 6 ft from the wall
At the instant when the bottom of the ladder is 6 ft from the wall and sliding away at a rate of 1 ft/sec, the top of the ladder is sliding down the wall at a rate of -3/4 ft/sec.
Let's denote the distance between the top of the ladder and the ground as y and the distance between the bottom of the ladder and the wall as x. We are given that dx/dt = 1 ft/sec and want to find dy/dt when x = 6 ft.
According to the Pythagorean theorem, we have the equation
\(x^2\) + \(y^2\) = \(10^2\).
Differentiating both sides with respect to time (t), we get:
2x(dx/dt) + 2y(dy/dt) = 0.
Substituting the given values, we have:
2(6)(1) + 2y(dy/dt) = 0.
Simplifying the equation, we get:
12 + 2y(dy/dt) = 0.
Now, we can solve for dy/dt:
2y(dy/dt) = -12,
dy/dt = -6/y.
To find dy/dt when x = 6 ft, we substitute x = 6 into the equation:
dy/dt = -6/y = -6/8 = -3/4 ft/sec.
Therefore, the top of the ladder is sliding down the wall at a rate of -3/4 ft/sec when the bottom of the ladder is 6 ft from the wall.
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I have to turn this in soon. Can you help me please
I need help with this can someone help me please!!! I will give brainlist, no links!!
Leo is visiting New York City to see the Empire State building. He knows that the Empire State building is 1,484 feet tall. When he spots it, he stops and has to look up at an angle of 84.7 degrees to see the top. How far away from the base of the Empire State building is he?
Answer:
Leo stop at 1339. 3 feet tall and Leo almost reach the top of the building
What are the values of m and e in the diagram below?
Answer:
Answer is the second bullet
Step-by-step explanation:
HELPP!!!!!!!!!!!!!!!!
Answer:
D.4 3/4
Step-by-step explanation:
hope it helps you
Express the confidence interval
left parenthesis 0.008 comma 0.096 right parenthesis(0.008,0.096)
in the form of
ModifyingAbove p with caret minus Upper E less than p less than ModifyingAbove p with caret plus Upper Ep−E
Modifying Above p with caret minus Upper E less than p less than ModifyingAbove p with caret plus Upper E
where p is the point estimate, and Upper E is the margin of error.
To express the confidence interval (0.008, 0.096) in the form of ModifyingAbove p with caret minus Upper E less than p less than ModifyingAbove p with caret plus Upper E, we first need to find the point estimate (p) and the margin of error (Upper E).
The point estimate is the midpoint of the interval, which is:
p = (0.008 + 0.096) / 2 = 0.052
The margin of error is half the width of the interval, which is:
Upper E = (0.096 - 0.008) / 2 = 0.044
Therefore, the confidence interval can be expressed as:
ModifyingAbove 0.052 with caret minus 0.044 less than p less than ModifyingAbove 0.052 with caret plus 0.044
This means that we are 95% confident that the true population proportion (p) falls within the range of 0.008 to 0.096.
the confidence interval (0.008, 0.096) can be expressed in the form of Modifying Above p with caret minus Upper E less than p less than Modifying Above p with caret plus Upper E as Modifying Above 0.052 with caret minus 0.044 less than p less than Modifying Above 0.052 with caret plus 0.044. This means that we are 95% confident that the true population proportion falls within this range.
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Evaluate: -6 × (-4)
= Enter your next step here
() TO
Answer:
24
Step-by-step explanation:
-6*(-4)
The negative signs cancel:
6*4
24