Answer:
the weight of the rider is 493.53 N
Explanation:
Given the data in the question and as illustrated in the image below,
Tension T = 1900 N
the rider is moving at a constant speed so the net force in the horizontal direction will be 0
In the horizontal direction
F\(_{sail\)cos( 30° ) = Tcos ( 17° )
F\(_{sail\) = Tcos( 17° ) / cos( 30° )
F\(_{sail\) = 1900cos( 17° ) / cos( 30° )
F\(_{sail\) = 2098.07 N
Now, In the vertical direction,
F\(_{sail\) sin( 30° ) = W + T sin( 17° )
W = F\(_{sail\) sin( 30° ) - T sin( 17° )
W = 2098.07sin( 30° ) - 1900sin( 17° )
W = 1049.035 - 555.506
W = 493.53 N
Therefore, the weight of the rider is 493.53 N
What distance will be traveled if you are going at an average speed of 420 km/hr for 45 minutes?
Answer: 12
Explanation: 34
What is the Mr of HCO3
Answer:
61.0168 g/mol Explanation:
How is thermal energy transferred during conduction? Check all that apply.
Thermal energy is transferred between particles that are not touching each other.
Thermal energy is transferred between particles that are in direct contact with each other.
Thermal energy is transferred between objects of different temperatures.
Thermal energy is transferred between objects of the same temperature.
Thermal energy is transferred from slow-moving particles to fast-moving particles.
Thermal energy is transferred from fast-moving particles to slow-moving particles.
The correct options for how thermal energy is transferred during conduction are " Thermal energy is transferred between particles that are in direct contact with each other.", "Thermal energy is transferred between objects of different temperatures.", and "Thermal energy is transferred from fast-moving particles to slow-moving particles." The correct options are B, C, and F.
During conduction, thermal energy is transferred through a material or between objects in direct contact with each other. The transfer of thermal energy occurs because of temperature differences between the two objects or regions. When two objects at different temperatures are in direct contact with each other, the hot object transfers thermal energy to the cold object through collisions between the particles of the two objects. The fast-moving particles in the hot object collide with the slow-moving particles in the cold object, transferring thermal energy from the hot object to the cold object. This process continues until the two objects reach thermal equilibrium, meaning they have the same temperature and there is no more net transfer of thermal energy between them.
Option A is not true because thermal energy is actually transferred between particles that are in direct contact with each other, not particles that are not touching each other.
Option D is not true because thermal energy does not transfer between objects that are already at the same temperature. Heat transfer only occurs when there is a temperature difference.
Option E is not true because thermal energy actually flows from hot objects to cold objects. Therefore, thermal energy is transferred from fast-moving particles to slow-moving particles, not the other way around.
Therefore, The correct answers are B, C, and F.
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describe measurement in our daily life
360 s to ms? Need help! Converting units, with work pls
1 s = 1,000 ms
2 s = 2,000 ms
3 s = 3,000 ms
.
.
10 s = 10,000 ms
20 s = 20,000 ms
30 s = 30,000 ms
.
.
.
100 s = 100,000 ms
200 s = 200,000 ms
300 s = 300,000 ms
310 s = 310,000 ms
320 s = 320,000 ms
.
.
.
350 s = 350,000 ms
360 s = 360,000 ms
370 s = 370,000 ms
.
.
.
How much work is done on a 85 Newton box of books that you carry horizontally 4 meters across a room?
a 60 J
b 360 J
c 0 J
d 10 J
e 6 J
The work done on 85 N boxes of books while carried horizontally 4m across a room is equal to zero. Therefore, option (C) is correct.
What is the work?Work can be demonstrated as the energy used when a force is exerted to move an object through a definite displacement. The work done defines both the exerted force on the object and the distance moved by the object.
The applied force moves an object in a straight line in the direction of the exerted force over a displacement 'd'.
W= F × d
Where 'F' is the exerted force and 'd' is the displacement and W is work done.
Given, the weight of the box = 80 N
The displacement , d = 4 m
In order for to work to be done the box should move in the direction of exerted force as the books are moving forward direction and the applied force in an upward direction to carry the box.
Therefore, the distance moved in the direction of force is zero so the work done is also equal to zero.
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If the toy car weighs 250g and has a kinetic energy of 2.0 J, what is its velocity
Explanation:
Kinetic energy (J) = 2j
mass= 250g
velocity=?
1kg=1000g
mass= 250/1000
mass=0.25kg
Kinetic energy (J) = ½ x mass (kg) x [velocity]² (m/s)
2=1/2 × 0.25× [velocity]²
2=0.125× [velocity]²
[velocity]² = 2/0.125
[velocity]²=16
velocity= (16)^1/2
velocity= 4 m/s
One day, the distance between the crests of the waves at sea is 2.5m. The shortest time between the lowest and highest positions of the floating boat was 0.625 seconds.
a) Calculate the wave period.
b) Calculate the speed of the wave.
Answer:
1.25 sec, 2 m/s
Explanation:
Period = 2 * 0.625 sec = 1.25 sec
speed = 2.5/1.25 = 2 m/s
A 5 kg block is released from rest at the top of a quarter- circle type curved frictionless surface. The radius of the curvature is 3.8 m. When the block reaches the bottom o the curvature it then slides on a rough horizontal surface until it comes to rest. The coefficient of kinetic friction on the horizontal surface is 0.02.
a. What is the kinetic energy of the block at the bottom of the curved surface?
b. What is the speed of the block at the bottom of the curved surface?
c. Find the stopping distance of the block?
d. Find the elapsed time of the block while it is moving on the horizontal part of the track.
e. How much work is done by the friction force on the block on the horizontal part of the track?
Answer:
a. 186.2 J b. 8.63 m/s c. 190 m d. 43.2 s e. 186.2 J
Explanation:
a. From conservation of energy, the potential energy loss of block = kinetic energy gain of the block.
So, U + K = U' + K' where U = initial potential energy of block = mgh, K = initial kinetic energy of block = 0, U' = final potential energy of block at bottom of curve = 0 and K' = final kinetic energy of block at bottom of curve.
So, mgh + 0 = 0 + K'
K' = mgh where m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height above the ground of block = radius of curve = 3.8 m
So, K' = 5 kg × 9.8 m/s² × 3.8 m = 186.2 J
b. Since the kinetic energy of the block K = 1/2mv² where m = mass of block = 5 kg, v = velocity of block at bottom of curve
So, v = √(2K/m)
= √(2 × 186.2 J/5 kg)
= √(372.4 J/5 kg)
= √(74.48 J/kg)
= 8.63 m/s
c. To find the stopping distance, from work-kinetic energy principles,
work done by friction = kinetic energy change of block.
So ΔK = -fd where ΔK = K" - K' where K" = final kinetic energy = 0 J (since the block stops)and K' = initial kinetic energy = 186.2 J, f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance
ΔK = -fd
K" - K' = - μmgd
d = -(K" - K')/μmg
Substituting the values of the variables, we have
d = -(0 J - 186.2 J)/(0.02 × 5 kg × 9.8 m/s²)
d = -(- 186.2 J)/(0.98 kg m/s²)
d = 190 m
d. Using v² = u² + 2ad where u =initial speed of block = 8.63 m/s, v = final speed of block = 0 m/s (since it stops), a = acceleration of block and d = stopping distance = 190 m
So, a = (v² - u²)/2d
substituting the values of the variables, we have
a = (0² - (8.63 m/s)²)/(2 × 190 m)
a = -74.4769 m²/s²/380 m
a = -0.2 m/s²
Using v = u + at, we find the time t that elapsed while the block is moving on the horizontal track.
t = (v - u)/a
t =(0 m/s - 8.63 m/s)/-0.2 m/s²
t = - 8.63 m/s/-0.2 m/s²
t = 43.2 s
e. The work done by friction W = fd where
= μmgd where f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance = 190 m
W = 0.02 × 5 kg × 9.8 m/s² × 190 m
W = 186.2 J
The potential energy of the loss of the block will be equal to the kinetic energy gain. The kinetic energy of the block is 186.2 J at the bottom of the curved surface.
The potential energy of the loss of the block will be equal to the kinetic energy gain.
So,
\(U = mgh\)
Where,
\(U\) - potential energy
\(m\) - mass of block = 5 kg
\(g\) - gravitational acceleration = 9.8 m/s²
\(h\) = height = radius of curve = 3.8 m
Put the values in the formula,
\(U = 5 \times 9.8 \times 3.8 \\\\ U = 186.2 \rm \ J\)
Therefore, the kinetic energy of the block is 186.2 J at the bottom of the curved surface.
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Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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238 U
92 ———————>
The alpha decay of ___ produces an atom with a mass number of...
OA. 234
B. 236
C. 238
D. 240
Answer:
A. 234
Explanation:
An alpha particle is a Helium atom which has a mass number of 4 and atomic number of 2. So, an alpha particle decay cause the mass number to decrease by 4 units.
So 238 - 4 = 234
The answer is A
At the end of the _____ era matter and antimatter annihilate each other. Because of a small imbalance in the ratio, the universe is left with only ______.
At the end of the Electroweak era, matter and antimatter annihilate each other. Because of a small imbalance in the ratio, the universe is left with only matter.
What is baryogenesis process?The baryogenesis process refers to the hypothetical mechanism or mechanisms that generated the observed baryon asymmetry in the universe which refers to the fact that there is much more matter than antimatter
If the universe were perfectly symmetric between matter and antimatter the particles and antiparticles would have annihilated each other completely leaving behind only radiation.
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Describe and explain motion due to uniform velocity in one direction and uniform acceleration in a perpendicular direction
Answer: you have to divide and multiple fam
Explanation:
Total internal reflection at the air liquid surface is observed for an unknown liquid when the angle of incidence is 43 degrees. What is the index of refraction of this unknown liquid?
a. 0.68
b. 1.0
c. 1.47
d. 1.59
Answer:
c. 1.47
Explanation:
Snell's law states that there exists always a fixed relationship between the index of refraction of two transparent media, and the sines of the incident and refraction angles, as follows:\(\frac{n_{i} }{n_{r} } = \frac{sin_{\theta r} }{sin_{\theta i} } (1)\)
When there is a total internal reflection, this means that light can't go across the border between two media, i.e., the refraction angle is 90º, which means that sin θr = 1Since the refraction index for air is 1, i.e. nr =1, this means that (1) , for total internal reflection becomes:\(n_{i} = \frac{1}{sin_{\theta i} } = \frac{1}{sin 43} = 1.47 (2)\)
Some amount of ideal gas with internal energy U was heated from 100^0C to 200^0C. We can predict that internal energy after heating in terms of U is:
The internal energy after heating in terms of U is 100U.
The given parameters;
initial temperature of the gas, T₁ = 100 ⁰Cfinal temperature of the gas, T₂ = 200 ⁰CAssuming a constant pressure, the internal energy of the ideal gas is equal to the change in the enthalpy of the ideal gas.
\(\Delta H = U \times \Delta T\\\\\Delta H = U (200 - 100)\\\\\Delta H = 100 U\)
Thus, we can conclude that the internal energy after heating in terms of U is 100U.
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1 point
Nuclear equations like the one below show "parent" and "daughter” nuclei.
What is the mathematical relationship between the superscripts on the
left-hand side and the superscripts on the right-hand side of the nuclear
equation?
27
27
0
12 Mg
13 AL +
je
Answer:
Mg- 27 means isotope with 12 protons and 15 neutrons.
Also 27 is mass number which express sum of protons and neutrons.
In nucleus one neutrn decays to electron and proton. Mass number remain same but Al-27 nucleus contain 13 protons and 14 neutrons. Electron is ejected out from nucleus.
A 10-cm long solenoid has 100 turns and a radius of 5 cm. If it carries a current of 2 A, What is the magnetic field B inside the solenoid
Hi there!
We can use Ampère's Law:
\(\oint B \cdot dl = \mu_0 i_{encl}\)
B = Magnetic field strength (B)
dl = differential length element (m)
μ₀ = Permeability of free space (T/Am)
Since this is a closed-loop integral, we must integrate over a closed loop. We can integrate over a rectangular-enclosed area of the rim of the solenoid - ABCD - where AD and BC are perpendicular to the solenoid.
Thus, the magnetic field is equivalent to:
\(\oint B \cdot dl = \int\limits^A_B {B} \, dl + \int\limits^B_C {B} \, dl + \int\limits^C_D {B} \, dl + \int\limits^D_A {B} \, dl\)
Since AD and BC are perpendicular, and since:
\(\oint B \cdot dl = B \cdot L = BLcos\phi\)
\(BLcos(90) = 0\)
If perpendicular to the field, the equation equals 0.
Additionally, since AB is outside of the solenoid, there is no magnetic field present, so B = 0. The only integral we integrate now is:
\(\oint B \cdot dl = \int\limits^C_D {B} \, dl\)
Which is horizontal and inside the solenoid. Let the distance between C and D be 'L', and the enclosed current is equivalent to the number of loops multiplied by the current:
\(B L = \mu_0 Ni\)
N = # of loops per length multiplied by the length, so:
\(BL = \mu_0 nL i \\\\B = \mu_0ni\)
Plug in the given values and solve. Remember to convert # of loops to # of loops per unit length.
\(B = \mu_0 (100/0.1)(2) = (4\pi *10^{-7})(1000)(2) = \boxed{0.00251 T}\)
Please help me! I need help on this.
Answer:
light is captured through ozone layer.
Explanation:
as its the ozone layer that protects earth from the harmful radiation of the earth and store only the light and energy needed.
Fun Fact - ozone layer can provide light for about 7 minutes so if sun disappears, we won't even realise it for 7 minute straight.
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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A basketball has a circumference of .203 m.what is the radius of a baseball?
Given that the circumference of the basketball is C = 0.203 m.
We have to find the radius of basketball, r.
The radius can be calculated as
\(\begin{gathered} C=2\pi r \\ r=\frac{C}{2\pi} \\ =\frac{0.203}{2\times3.14} \\ =0.032\text{ m} \end{gathered}\)Thus, the radius of the basketball is 0.032 m
why doping method is used to design a diode circuit
Answer:
To increase the conductivity of the material.
Explanation:
Generally , the group 4 elements are non conductor but in certain conditions, such as doping or the increase in temperature, they becomes conductor.
The doping is the process of mixing of pentavalent or the trivalent material into tetra valent material in the very small amount, so that the material becomes conductor.
In making a diode we need two types of the materials, n type semiconductor and p type semi conductor.
When the trivalent impurity is added in the tetra valent element, the semiconductor becomes n type because an electron is left for the conduction.
When the pentavalent impurity is added in the tetra valent element, the semiconductor becomes p type because a hole is left for the conduction.
How do you know that light travels faster than
sound? (Hint: Give an example of something that
produces sound and light at the same time.)
Answer:
Explanation:
Answer
How about a thunder storm. I don't know if you live in a city or out in the sticks as I do. Lighting is very obvious and it is not a good idea to be out when experiencing a thunderstorm, especially in an open field. You might be the only thing around that will cause the lightning to be connected to the ground.# Seconds later, you will hear the thunder which is quite harmless. If you live in the city, observing this is not quite so easy. There are all kinds of buildings around and some of them may block your view.
#The great golfer, Lee Travino, was "hit" by lightening storm twice while playing in tournaments.
While driving down Business 40 West, you notice that your engine light comes on in the dashboard of your car. Once you get the car to a mechanic, she explains that your 41 lb lead car battery began to melt during the process of the car overheating. If the temperature reached 625 degrees Fahrenheit from 250 degrees Fahrenheit, what was the total amount of heat in this process? PLEASE SHOW ALL WORK AND UNITS
Answer:
the answer is 375°F
Explanation:
you simply subtract 250°F from 625°F
How much force
would be required for a ten strand pulley system
to lift 1000 newtons?
Answer: 250
Explanation:
The force acting on a rotating object with mass 3.0 kg is 8.0 N. If the speed of rotation is 5.0 m/s, find the radius of rotation. Use F=mv2/r
Radius of rotation, r = \(mv^2\)/F = (3.0 kg)(5.0 \(m/s)^2\)/(8.0 N) = 9.375 m.
To find the radius of rotation for a rotating object with a mass of 3.0 kg and a force of 8.0 N acting upon it,
we can use the centripetal force formula:
F = \(mv^{2/r\). In this formula, F represents the force, m is the mass, v is the velocity, and r is the radius.
Given a mass of 3.0 kg, a force of 8.0 N, and a rotational speed of 5.0 m/s,
we can rearrange the formula to solve for the radius: r = \(mv^{2/F\).
Plugging in the given values,
we get r = (3.0 kg)(5.0 \(m/s)^2\)/(8.0 N) = 9.375 m.
Thus, the radius of rotation is 9.375 meters.
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4. True or false. When measuring a liquid ingredient, the measuring cup should be held up so the mark on
the cup for the desired amount is at eye level.
Foods class
It takes a cheetah just 3 s to reach its top speed of 30 m/s. What is its acceleration?
Answer:
The acceleration would be 10m/s.
Explanation:
To find this out, use the formula:
A = speed/time:
30 divided by 3 = 10m/s.
May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I only need 12 more brainliest to become a genius! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!
Explain what it means when we say a substance is magnetic.
Discuss the relationship between electric and magnetic fields.
Which types of wires (cooper, aluminum, or string) are ferromagnetic metals?
Answer: See the explanation.
Explanation:
When we say a substance is magnetic it means the atoms are lined in a way that created a magnetic field that goes from one side to the other
These are essentially two aspects of the same thing, because a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. This is the relationship.
Answer: Copper isn't ferromagnetic,
Aluminum isn't ferromagnetic,
String does have a ferromagnetic property
PLEASE HELP WORTH 30 POINTS!!!
Answer:because the circuit will be fully complete
Explanation:
please help me out with these !! 50 points would greatly appreciate it.
Answer:
Its nymber 2
Explanation: