In static equilibrium, given that the mass (m1) is 7.40 kg and the coefficient of static friction between mass (m1) and the surface on which it rests is 0.30, what is the maximum mass that (m2) can have for which the system will still remain in equilibrium?

effort distance/resistance distance or length of ramp/height of ramp or dE/dr  is correct for calculating the ideal mechanical advantage

Theideal mechanical advantage would not have any friction. this is due to the fact that some of the effort put into the machine is lost trying to overcome friction.

ideal mechanical advantage is denoted by the sign IMA, that ignores the drawbacks of friction.

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Answer:

I think its C and D

Explanation:Force is like a energy that moves stuff. :)

Answer:

If I'm not wrong; I think the answer is A

Explanation:

A. Increasing kinetic energy

Answer:

moving them closer together and making the charges more unbalanced

Explanation:

moving them closer together will increase the voltage potential

making the charges more unbalanced. an electrical circuit works by having more charges on one side of a power source.

Answer:

The answer should be: 1.20 A

Explanation:

It would take approximately 716,943 years for the New Horizons space satellite to travel to Proxima Centauri at its current speed.

To calculate the number of years it would take for the New Horizons space satellite to travel to Proxima Centauri, we need to convert the speed of the satellite to the appropriate units and then use the formula for time:

Distance = Speed × Time

Given:

Distance to Proxima Centauri = 4.3 light years

Speed of New Horizons = 53,000 kilometers per hour

First, we need to convert the speed of New Horizons from kilometers per hour to light years per year. To do this, we'll use the conversion factor:

1 light year ≈ 9.461 × \(10^{12\) kilometers

Speed of New Horizons in light years per year:

Speed in light years per year = (53,000 kilometers per hour) × (1 year / 8766 hours) × (1 light year / 9.461 × \(10^{12\) kilometers)

Speed in light years per year ≈ 0.000006003

Now, we can calculate the time it takes to travel to Proxima Centauri:

Time = Distance / Speed

Time = 4.3 light years / 0.000006003 light years per year

Time ≈ 716,943 years

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If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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Answer:

The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor, that's why rainwater is also distilled, it doesent have any particles or minerals in it.

The steam is completely condensed, i.e., it becomes a saturated liquid. Therefore, final pressure, P2 = pressure of saturated liquid at 175°C.

Isothermal and mechanically reversible process.Q is the heat absorbed by the system.W is the work done by the system.(a) Q and W using steam tables: Using steam tables from Appendix F:

At P1 = 400 kPa,

T1 = 448.15 K (from the table for superheated steam),

h1 = 3228.1 kJ/kg (from the table for superheated steam)

At P2 = pressure of saturated liquid at T2 = 175°C from the table for saturated water,

v2 = vf = 0.0010588 m³/kghf = 688.72 kJ/kg

Saturated water at 175°C is a compressed liquid.

Therefore, the process 1-2 is a compressed liquid process.

Δu = u2 - u1 = 0 (isothermal process)

Δh = h2 - h1 = hf - h1 = 688.72 - 3228.1 = -2539.38 kJ/kg (heat removed by the system)

Q = mΔh = 4 × (-2539.38) = -10157.52 kJ (heat absorbed by the system)

The process 1-2 is a compressed liquid process.

Therefore, the work done is given byW = m(v2 - v1)

= 4 (0.0010588 - 0.029354)

= -0.11458 kJW = -114.58 kJ (work done by the system)

Therefore, the heat absorbed by the system is -8898.7 kJ and work done by the system is 1,435.7 kJ.

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Answer:

d. ice

Explanation:

Answer:

The correct answer is C. Ice, you know, since it's so slippery. lol

pls give brainliest

Answer: ethanol which will dissolve in both water (a polar solvent) and gasoline (a non-polar solvent)

Explanation:

According to the concept of solubility, ethanol is a molecule which is soluble in both polar and non-polar solvents.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.

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A) Circuit A represents a circuit where the ammeter correctly measures the current in the headlight.

B) For Circuit A, the current flowing through the ammeter would be 6 A, as the ammeter has no resistance and is connected in series with the headlight.

C) For Circuit B, the current flowing through the ammeter would be 6 A - 0.1 A = 5.9 A.

An ammeter is an electrical instrument used to measure electrical current. It is connected in series with the circuit and measures the current directly. The ammeter is a type of galvanometer, which is a device used to detect and indicate small electric currents. The ammeter works by generating a magnetic field around the current-carrying conductor and measuring the strength of the field with an electromagnet. The strength of the field is directly proportional to the current flowing through the conductor. The ammeter can measure both direct and alternating currents. It has a low resistance and is usually connected in series with the circuit to ensure that all the current flows through it. The ammeter can also measure very small currents, making it an important instrument in the study of electricity.

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Answer:

1498962290

Explanation:

The refractive index of the glass material is approximately 1.4226.

To calculate the refractive index of the glass material for the fiber optic cable, you can use Snell's Law and the definition of the critical angle. The critical angle (θc) is the angle of incidence at which the angle of refraction is 90°. In this case, the critical angle is 25°.

Snell's Law: n1 * sin(θ1) = n2 * sin(θ2)

For the critical angle, θ1 = 25°, and θ2 = 90°. The refractive index of air (n1) is approximately 1.

Applying Snell's Law: 1 * sin(25°) = n2 * sin(90°)

Solving for the refractive index (n2) of the glass material:
n2 = sin(25°) / sin(90°)

n2 ≈ 0.4226 / 1

n2 ≈ 1.4226

The refractive index of the glass material is approximately 1.4226.

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Answer:

\(F = kmg \\ k = \frac{F}{mg} \)

Explanation:

F = k . m . g

=> F = k . mg

\( = > k = \frac{F}{mg} (ans)\)

In words, the R2 of 0.27 means that 27% of the variability in y (24-hour urinary Na) can be explained by x (estimated 24-hour urinary Na) obtained from casual urine specimens at one point in time.

The INTERSALT Study was designed to investigate the relationship between dietary sodium and blood pressure (hypertension) in populations worldwide.

The study included 10,079 men and women from 52 population samples in 32 countries. One of the goals of the study was to quantify the relationship between 24-hour urinary Na (y) and estimated 24-hour urinary Na (x) obtained from casual urine specimens at one point in time.

The investigators presented a simple linear regression of y on x, separately for men and women. The regression equation for men was: Y = 1.03x + 7.19, with R2 = 0.27, n = 1369.

The coefficient of determination, R2, is a statistical measure that represents the proportion of the variance for a dependent variable (y) that's explained by an independent variable (x) or variables in a regression model.

In this case, the R2 of 0.27 means that 27% of the variability in y (24-hour urinary Na) can be explained by x (estimated 24-hour urinary Na) obtained from casual urine specimens at one point in time. The remaining 73% of the variability in y is due to other factors that are not included in the regression model.

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The force exerted between two charges is given by Coulomb's law:

F = k * (q1 * q2) / r^2

where:

F = force (N)

k = Coulomb's constant (8.99 x 10^9 N m^2/C^2)

q1, q2 = charges (C)

r = distance between charges (m)

Given that the magnitude of the force exerted is 8 mN and the distance between the charges is 4.2 m, we can substitute these values and the value of k into the equation and solve for q1 and q2:

8 x 10^-3 N = k * (q1 * q2) / (4.2 m)^2

q1 * q2 = (8 x 10^-3 N * (4.2 m)^2) / k

Given that q1 + q2 = 10C and q1 < q2, and q1,q2 are positive, so they repel each other.

By solving this equation, we can find q1 and q2:

q1 = x and q2 = 10 - x

substituting the above values into q1 * q2 = (8 x 10^-3 N * (4.2 m)^2) / k we can find the value of x

x(10-x) = (8 x 10^-3 N * (4.2 m)^2) / k

x^2 - 10x + (8 x 10^-3 N * (4.2 m)^2) / k = 0

By solving the above equation we can find the value of x which is q1.

q1 = (10 + sqrt(100 - (32 * 8 * 10^-3 * (4.2)^2) / 8.99 * 10^9))/2

q2 = 10 - q1

q1 = 3.32 C

q2 = 6.68 C

So, q1 is 3.32 C and q2 is 6.68 C

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The time period of oscillation is 2.09 units.

The equation of motion for a simple harmonic oscillator is given by:

\(\frac{d^2x}{dt^2} + (\omega^2)x = 0,\)

The time period of a periodic motion is the time required for one complete cycle of the motion. In other words, it is the time interval between two successive identical points in the motion.

where x is displacement, t is time, and ω is the angular frequency of the oscillator.

Comparing this equation to the given equation, we can see that \(\omega^2\) = 9, so ω = 3. The period T of the oscillation is given by:

T = 2π/ω

Substituting the value of ω, we get:

T = 2π/3

T = 2 (3.14)/3

T = 2.09

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To solve this problem, we need to use the concepts of velocity, overhead, and reference.
First, we know that the UFO is moving at a constant velocity, which means its speed and direction are not changing.
Second, the term "overhead" refers to the fact that the UFO is passing directly above the astronaut on the moon. This gives us a reference point for the UFO's location.
Finally, we need to consider the reference frame of the UFO. This means that we need to think about how time and distance are perceived from the perspective of the UFO.
Using the given information, we can calculate the time it takes for the UFO to travel from the earth to the moon in the UFO's reference frame.
From the astronaut's perspective on the moon, the UFO takes 2.6 seconds to pass overhead. This means that the distance the UFO traveled in that time is:
distance = velocity x time

We don't know the velocity of the UFO from the astronaut's perspective, but we can calculate it using the distance between the earth and the moon.
distance = 3.8 x 10^8 m
The time it takes for the UFO to travel from the earth to the moon in the UFO's reference frame is:
time = distance / velocity

To find the velocity of the UFO in the UFO's reference frame, we need to use the principle of time dilation. This means that time appears to slow down for objects that are moving relative to each other. The formula for time dilation is:
t' = t / √(1 - v^2/c^2)
where t is the time in the astronaut's reference frame, t' is the time in the UFO's reference frame, v is the velocity of the UFO, and c is the speed of light.
We know that t = 2.6 seconds and c = 3 x 10^8 m/s. Plugging in these values and solving for v, we get:
v = 0.866 c
Now we can use this velocity to calculate the time it takes for the UFO to travel from the earth to the moon in the UFO's reference frame:
time = distance / velocity
time = 3.8 x 10^8 m / (0.866 c)
time = 13.8 seconds
Therefore, from the UFO's reference frame, it takes 13.8 seconds to travel from the earth to the moon.

 In order to answer your question, we'll need to use the given terms: "velocity", "overhead", and "reference". Since the UFO is moving at a constant velocity and is observed passing overhead on the moon 2.6 seconds later, we can assume that the astronaut and the UFO are in the same inertial reference frame.
To find the time it takes for the UFO to travel from Earth to the moon in the UFO's reference frame, we can use the formula: time = distance/velocity. We're given the distance as 3.8 x 10^8 meters, but we don't have the velocity. Unfortunately, without the velocity, we cannot determine the exact time it took for the UFO to travel from the Earth to the moon in its reference frame.

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Answer:

The mass of the apple is 0.49kg

Explanation:

Potential energy=mgh

P=mgh

6=m×1.22×10

6=12.2m

divide both sides by 12.2

m=6/12.2

m=0.49kg

Therefore, the mass of ball 2 is approximately 24.7 kg.

A collision is an event that occurs when two or more objects come into contact with each other in a way that alters their motion. In physics, collisions are studied in terms of the conservation of momentum and the conservation of kinetic energy. In an elastic collision, the total kinetic energy of the system is conserved, and the objects bounce off each other without any loss of energy. In an inelastic collision, some of the kinetic energy is converted into other forms of energy, such as heat or sound, and the objects may stick together after the collision. Collisions can be categorized into two types: head-on collisions and oblique collisions. In a head-on collision, the objects approach each other directly from opposite directions, while in an oblique collision, the objects approach each other at an angle. Collisions are an important concept in physics and have applications in fields such as engineering, transportation, and sports. Understanding the principles of collisions can help us design safer cars, improve the performance of athletic equipment, and develop new technologies for space exploration.

Here,

We can use the conservation of momentum and the conservation of kinetic energy to solve for the mass of ball 2 in the completely elastic collision. Using the conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

Substituting the known values:

(6.7 kg)(2.0 m/s) + m2(-5.0 m/s) = (6.7 kg)(-6.18 m/s) + m2(0.83 m/s)

Simplifying and solving for m2:

(13.4 - 33.9) kg·m/s = -44.006 kg·m/s + 0.83 m2

-20.5 kg·m/s = 0.83 m2

m2 = (-20.5 kg·m/s) / (0.83 m/s)

m2 ≈ 24.7 kg

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A region has uniform electric field pointing to the right, most likely true is D.) There are positive charges to the right of, and/or negative charges to the left of this region.

Electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in field either attracting or repelling them.

A uniform electric field is caused by a distribution of electric charges. If the electric field points to the right, there must be a net positive charge to the right of the region and/or a net negative charge to the left of the region. It is not possible for the electric field to be caused by only positive or only negative charges.

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The two pith balls will repel each other. When the plastic rod is rubbed by cat fur, it gains an excess of negative charge (electrons) and becomes negatively charged.

By contact, the charged rod transfers some of its electrons to the pith balls, causing them to become negatively charged as well. Since both pith balls have the same charge (negative), they will experience mutual electrostatic repulsion. Like charges repel each other, leading to the repulsion between the two pith balls. This phenomenon follows the principle of electrostatics, where objects with the same charge repel while objects with opposite charges attract.

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Answer:

please refer to the attachment.

Answer:

bigger instruments make lower pitches

Explanation:

bass drums and other large instruments have low sounds because they're so big. the smaller the instrument is, the higher pitch it's going to have

Answer:

It is mostly the Bass instruments because they use mouthpieces while the wind instrument use reeds and make a higher pitched sounds

Explanation:

Band

To respond, one can say:

Venus and Mars are two planets in our solar system. Venus is the second planet from the Sun and is similar in size and composition to Earth. It is often referred to as Earth's "sister planet."

Mars, on the other hand, is the fourth planet from the Sun and is smaller than Earth. It is often referred to as the "Red Planet" due to its reddish appearance in the sky.

Both Venus and Mars have been the focus of much scientific study, particularly regarding their potential for supporting life.

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Answer:

\(K.E = \frac{1}{2} mv {}^{2} \)

m = 10m/s

mass = 0.5kg

\(K.E = \frac{ {1} }{2} \times 0.5 \times 10 ^{2} \\ = K.E = \frac{1}{2} \times50 \\ \)

K.E = 25 J

Answer:

Explanation:

This is a simple gravitational force problem using the equation:

\(F_g=\frac{Gm_1m_2}{r^2}\) where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

\(F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2}\) I'm going to do the math on the top and then on the bottom and divide at the end.

\(F_g=\frac{2.4012*10^{40}}{3.721*10^{23}}\) and now when I divide I will express my answer to the correct number of sig dig's:

\(Fg=\) 6.45 × 10¹⁶ N