In many cases, lenders allow homeowners to include their homeowners insurance premium with their monthly mortgage payment. tim’s home is worth $279,500. if his homeowners insurance premium is $0.33 per $100, how much is added to his monthly mortgage payment for insurance? a. $7.69 b. $76.86 c. $92.35 d. $922.35 please select the best answer from the choices provided a b c d

The Central-Limit-Theorem in statistics states that  "for a large sample size, the distribution of sample mean will approach to Normal-Distribution, even if the population distribution is not normal."

The Central Limit Theorem (CLT) is considered a fundamental concept in statistics , which states that the sampling distribution of mean of any independent, identically distributed random variables will tend towards a normal distribution as the sample size increases, regardless of the  distribution of the population from which the samples are drawn.

This means that if we take repeated samples of the same size from any population, the means of those samples will be normally distributed, with a mean = population mean and a standard deviation = population standard deviation divided by the square root of sample size.

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The project is performing well at the end of WEEK 7.

1. The planned value (PV) at the end of WEEK 7 is $30,000.
2. The earned value (EV) at the end of WEEK 7 is $30,000.
3. The actual cost (AC) at the end of WEEK 7 is $30,000.
4. The cost variance (CV) at the end of WEEK 7 is $0.
5. The schedule variance (SV) at the end of WEEK 7 is $0.
6. The cost performance index (CPI) at the end of WEEK 7 is 1.0 (CV/AC).
7. The schedule performance index (SPI) at the end of WEEK 7 is 1.0 (EV/PV).
8. At the end of WEEK 7, this project is performing according to the plan. The CPI and SPI are both equal to 1.0, indicating that the project is on track in terms of cost and schedule. The cost variance (CV) and schedule variance (SV) being zero further support this conclusion, as it means that the project is meeting its planned budget and schedule.

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Three angles of the triangle:

\(3x \\ 5x \\ x\)

___________________________________________

3x + 5x + x = 180

9x = 180

x = 180/9

x = 20

Answer:

GCF = 10

Step-by-step explanation:

The headstart that runner 1 must give runner 2 is approximately 0.8 meters, rounded to the nearest meter.

To determine the headstart that runner 1 must give runner 2 in order for them to run the same distance, we need to consider the relative positions of the runners and the width of the lanes.

Let's assume that the circular track has a circumference of C meters. Runner 1 runs along the inner lane, while runner 2 runs along the outer lane, which is 80 cm (0.8 meters) wider than the inner lane.

When runner 1 completes one lap around the track, they will have covered a distance equal to the circumference of the inner lane (C_inner). On the other hand, runner 2 will need to run an additional distance equal to the width of the outer lane (0.8 meters) to complete one lap around the track.

Since both runners need to cover the same distance for their runs to be equivalent, we can set up the following equation:

C_inner = C_outer + 0.8

Now, let's solve for the headstart that runner 1 must give runner 2:

C_inner = C_outer + 0.8

C_inner - C_outer = 0.8

Since the difference in distances between the inner and outer lanes is 0.8 meters, runner 1 needs to start 0.8 meters ahead of runner 2 for them to cover the same distance.

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Hence the given statement if p is an invertible m x m matrix, then rank PA = rank A is proved.

what is invertible matrix?

An invertible matrix is a matrix for which matrix inversion operation exists, given that it satisfies the requisite conditions.

proof:

Let A be an m × m matrix and P be an invertible m × m matrix.

We know that Rank(A) is the number of non-zero rows in A based on the definition of matrix rank.

Therefore,

Rank(PA) = Number of non-zero rows in PA

Therefore,

Rank(PA) = Number of non-zero rows in PA

               = Number of non-zero rows in A

               = Rank(A)

Hence, we can conclude that if P is an invertible m × m matrix, then Rank(PA) = Rank(A).

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Answer:

3: အားနည်းချက်ကို YC တလျှောက်တွင် XYZ Translate ။ ထောင့် X'YA ဖြင့် C ပတ်လည် X'YZ ကိုလှည့်ပါ။ CB ရှိ“ X” Y“ Z” ကိုရောင်ပြန်ဟပ်ပါ။

Answer:

Translate XYZ using directed line segment YC. Rotate X'Y'Z' using C as the center so that X' coincides with B. Reflect X"Y"Z" across line CB.

Step-by-step explanation:

Its correct because I just got the answer right on the assignment

Hope this helps! :)

Trigonometric relations can be used to transform p to q.

To transform x into 1/x, you can press the following sequence of buttons:
1. Press the sin button.
2. Press the cos^-1 button.
3. Press the tan button.

To transform \(\sqrt[2]{x}\) to \(\sqrt[2]{x+1}\), you can press the following sequence of buttons:
1. Press the sin^-1 button.
2. Press the cos button.
3. Press the tan button.

To show that you can get any positive rational number, you can use the fact that any positive rational number can be expressed as a ratio of two positive integers, say p and q. Then, you can press the following sequence of buttons:
1. Press the sin button q times.
2. Press the cos button p times.
3. Press the tan button.

By pressing this sequence of buttons, the calculator will display the desired positive rational number q.

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Statistics on women in politics highlight that woman - who make up over 50 percent of the U.S. population - are substantially lag in high government positions.

In U.S. the population of Women are 50.8 percent. Approximately, 60 percent of women have their undergraduate degree, and 60 percent of women have their master's degree. They are very well educated. They earn almost 60 percent of law degrees.

But, when it comes to representation in high government positions, they substantially lag behind men. There are only 14.6 percent of executive officers, they hold only 24.2 percent of state legislative seats. They hold only 18.5 percent of congressional seats, and they are just 20 percent of U.S. senators.

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If a lead puck has a diameter of 7.5 cm and height of 2.3 cm and is floating in the mercury then the bottom of the lead puck is 1.9 cm below the mercury surface.

In order to solve this problem, we will make use of Archimedes’ principle. Archimedes’ principle states that the buoyant force on an object equals the weight of the fluid displaced by the object.

Let the bottom of the lead puck is d meter below the mercury surface.

So, the volume of the mercury displaced by the lead puck is equal to the volume of the puck under the mercury:

V(mercury displaced) = V(puck) = πr²d,

where r = 0.075 m (diameter = 7.5 cm)

V(mercury displaced) = π(0.075 m)²d,

We also know that the density of mercury is 13,600 kg/m³ and the density of lead is 11,300 kg/m³.

Mass of mercury displaces = Volume × density = π(0.075 m)²d × 13600

Mass of the lead puck = π(0.075 m)²×0.023 × 11,300

At equilibrium weight of the mercury displaces will be equal to the weight of the lead puck.

π(0.075 m)²d × 13600 × g = π(0.075 m)²×0.023 × 11,300 × g

d = (0.023 × 11,300)/13600

d = 0.019 m

d = 1.9 cm

Therefore, the bottom of the lead puck is 1.9 cm below the surface of the mercury.

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The result obtained when a decision alternative is chosen and a chance event occurs is known as consequence. The answer is: b.

When a decision alternative is chosen and a chance event occurs, the result is referred to as a consequence. A consequence represents the outcome or outcome state that arises from the combination of a decision and a chance event.

It is the result or effect that occurs based on the chosen alternative and the unpredictable element introduced by the chance event.

Consequences are an essential concept in decision theory and decision analysis, as they help evaluate the potential outcomes and impacts of different choices and events. By considering the consequences associated with each decision alternative, decision-makers can assess the desirability or utility of different outcomes and make informed choices.

Hence, the correct option is: b. consequence.

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For T to be a normal operator on a finite-dimensional complex inner product space V,

(a) If Tⁿ is the zero map, then T is the zero map.

(b) U commutes with T if and only if U commutes with each eigenprojection of T.

(c) There exists a normal U such that U² = T.

(d) T is invertible if and only if lambda_j is nonzero for all eigenvalues λ_j of T.

(e) T is a projection if and only if lambda_j is either 0 or 1 for all eigenvalues λ_j of T.

(f) T = -T* if and only if each eigenvalue of T is imaginary.

(a) If Tⁿ = 0 for some n ∈ ℕ, then the characteristic polynomial of T is p_T(x) = xⁿ. But by the spectral decomposition, the characteristic polynomial of T is given by p_T(x) = (x - λ₁)(d₁) × ... × (x - λ_k)(d_k), where λ₁, ..., λ_k are the distinct eigenvalues of T and d₁, ..., d_k are the dimensions of the corresponding eigenspaces. Since T is normal, the eigenspaces are orthogonal and hence the dimensions add up to the dimension of V. Thus we must have n = dim(V), which implies that T is the zero map.

(b) Let U be a linear operator on V that commutes with T. By the spectral decomposition, we can write T = λ₁P₁ + ... + λ_kP_k, where P₁, ..., P_k are orthogonal projections onto the eigenspaces of T. Since U commutes with T, we have U(P_i(v)) = P_i(U(v)) for any eigenvector v of T. It follows that U commutes with each P_i. Conversely, suppose U commutes with each P_i. Then we have U(T(v)) = U(λ_i P_i(v)) = λ_i U(P_i(v)) = λ_i P_i(U(v)) = T(U(v)) for any eigenvector v of T. Since the eigenvectors span V, this implies that U commutes with T.

(c) Let T = λ₁P₁ + ... + λ_kP_k be the spectral decomposition of T. Define U = λ₁(1/2)P₁ + ... + λ_k(1/2)P_k. Since T is normal, the eigenspaces are orthogonal and hence the projections P₁, ..., P_k are also orthogonal. It follows that U is also an orthogonal operator, and hence a normal operator. Moreover, we have U² = λ₁P₁ + ... + λ_kP_k = T.

(d) By the spectral theorem for normal operators, we can write T = λ₁P₁ + ... + λ_kP_k, where λ₁, ..., λ_k are the distinct eigenvalues of T and P₁, ..., P_k are orthogonal projections onto the corresponding eigenspaces. Moreover, we have T⁻¹ = λ₁⁻¹P₁ + ... + λ_k⁻¹P_k if all the eigenvalues are nonzero. Indeed, if all the eigenvalues are nonzero, then T is invertible and hence bijective. It follows that each eigenspace has a dimension at most 1, and hence T has a unique decomposition into a sum of orthogonal projections onto its eigenspaces. It is then easy to check that T⁻¹ has the desired decomposition. Conversely, suppose that T⁻¹ has the desired decomposition. Then we have T(T⁻¹(v)) = v for any v ∈ V. It follows that each eigenspace has dimension at most 1, and hence T is bijective, and hence invertible.

(e) By the spectral theorem for normal operators, we can write T = λ₁P₁ + ... + λ_kP_k, where λ₁, ..., λ_k are the distinct eigenvalues of T and P₁, ..., P_k are orthogonal projections onto the corresponding eigenspaces. It follows that T is a projection if and only if T² = T, which is equivalent to the condition that λ_i ∈ {0, 1} for all i.

(f) By the spectral theorem for normal operators, we can write T = λ_1 P_1 + ... + λ_k P_k, where λ_1, ..., lambda_k are the distinct eigenvalues of T and P_1, ..., P_k are the orthogonal projections onto the corresponding eigenspaces. Note that T is self-adjoint if and only if T = T*, or equivalently, λ_j is real for all j. On the other hand, T = -T* if and only if λ_j = -λ_j × for all j, or equivalently, lambda_j is imaginary for all j. Thus, T = -T* if and only if each λ_j is imaginary, as desired.

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Answer:

so the answer must be 8

Step-by-step explanation:

4×-2(×+3)=8

The function T(n) in terms of the number of operations is:

T(n) = 2n^3 + 3n^2 + 2n + 1 and the asymptotic complexity of the matrix multiplication algorithm is O(n^3).

To analyze the provided pseudo code for matrix multiplication and determine the function T(n) in terms of the number of operations, we need to examine the code and count the number of operations performed.

The pseudo code for matrix multiplication may look something like this:

```

MatrixMultiplication(A, B):

   n = size of matrix A

   C = empty matrix of size n x n

   for i = 1 to n do:

       for j = 1 to n do:

           sum = 0

           for k = 1 to n do:

               sum = sum + A[i][k] * B[k][j]

           C[i][j] = sum

   return C

```

Let's break down the number of operations step by step:

1. Assigning the size of matrix A to variable n: 1 operation

2. Initializing an empty matrix C of size n x n: n^2 operations (for creating n x n elements)

3. Outer loop: for i = 1 to n

- Incrementing i: n operations  

- Inner loop: for j = 1 to n

- Incrementing j: n^2 operations (since it is nested inside the outer loop)

- Initializing sum to 0: n^2 operations

- Innermost loop: for k = 1 to n

- Incrementing k: n^3 operations (since it is nested inside both the outer and inner loops)

- Performing the multiplication and addition: n^3 operations

- Assigning the result to C[i][j]: n^2 operations

- Assigning the value of sum to C[i][j]: n^2 operations

Total operations:

1 + n^2 + n + n^2 + n^3 + n^3 + n^2 + n^2 = 2n^3 + 3n^2 + 2n + 1

Therefore, the function T(n) in terms of the number of operations is:

T(n) = 2n^3 + 3n^2 + 2n + 1

To determine the asymptotic (big O) complexity of the algorithm, we focus on the dominant term as n approaches infinity.

In this case, the dominant term is 2n^3. Hence, the asymptotic complexity of the matrix multiplication algorithm is O(n^3).

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Answer:

\(y=[1]cos([\frac{2\pi }{3}]x)\)

Step-by-step explanation:

Looking at the graph, we can see the domain to be from (0 , 2π).

Now we have to find one period that corresponds to cos(x).

The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.

b = 2pi/3

a is the same range as cos(x). Range: (0,0)

y = [a] * cos ([b]*x)

y = [1] * cos([2pi/3]x)

Answer: 3750

Step-by-step explanation:

To find the area of the surface generated by revolving the curve y = 4 - x^2, -1 ≤ x ≤ 1, about the y-axis, we can use the formula for the surface area of revolution:

\(A = 2π ∫[a,b] f(x) √(1 + (f'(x))^2) dx\)

In this case, we have \(f(x) = 4 - x^2 and f'(x) = -2x.\)

Plugging these into the formula, we get:

\(A = 2π ∫[-1,1] (4 - x^2) √(1 + (-2x)^2) dx\)

Simplifying the expression inside the square root:

\(A = 2π ∫[-1,1] (4 - x^2) √(1 + 4x^2) dx\)

Now, we can integrate to find the area:

\(A = 2π ∫[-1,1] (4 - x^2) √(1 + 4x^2) dx\)

Note: The integral for this expression can be quite involved and may not have a simple closed-form solution. It may require numerical methods or specialized techniques to evaluate the integral and find the exact area.

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Answer:

Step-by-step explanation:

Answer:

(B)

Step-by-step explanation:

4 cans - $0.98

1. $0.98/4 = $0.245 will cost 1 can

2. $0.245 × 5 = $1.225 will cost 5 cans

so $1.225 = $1.23

so the answer is B

Answer:

22

Step-by-step explanation:

66 ÷3=22

3= one third

Answer:

\(13y\)

Step-by-step explanation:

Add similar elements: 2.6y-11.7y-3.9y=13y

\(13y\)

The number of calories that Darrell will burn in 1 minute while kayaking is given as follows:

4 calories.

The number of calories that Darrell will burn in 1 minute while kayaking is obtained applying the proportions in the context of the problem.

For each input-output pair in the table, the constant of proportionality is of 4, hence the number of calories that Darrell will burn in 1 minute while kayaking is given as follows:

4 calories.

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Answer:

The answer is #4

Answer:

The correct answer is number 4.

Step-by-step explanation:

If this helped give it a like :)

The work would be finished 3 times faster if they had been doing the work at the same time. The correct option is B.

Assumption;

Provided each one of the workers works for an hour which is equivalent to the time it takes to finish the hole.

In essence, the total time required to finish the ditch by 2 workers is; 2 hours.

Hence, for 3 workers working simultaneously, the time required is

1hour  = 60 minutes

However, since they took 1 hour turns on the job, it follows that; The total time used is;

Total time = 3 × 1hr = 3 hours = 180 hours

Hence they could have finished the work in;

R = 180/60 times faster =3 times faster.

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Find H

\(\\ \rm\rightarrowtail H^2=36^2+15^2\)

\(\\ \rm\rightarrowtail H^2=39^2\)

\(\\ \rm\rightarrowtail H=39\)

Now

\(\\ \rm\rightarrowtail sinR=\dfrac{P}{H}=\dfrac{15}{39}=\dfrac{5}{13}\)

\(\\ \rm\rightarrowtail cosR=\dfrac{B}{H}=\dfrac{36}{39}=\dfrac{12}{13}\)

\(\\ \rm\rightarrowtail tanR=\dfrac{P}{B}=\dfrac{5}{12}\)

\(\\ \rm\rightarrowtail sinT=\dfrac{36}{39}=\dfrac{12}{13}\)

\(\\ \rm\rightarrowtail cosT=\dfrac{5}{13}\)

\(\\ \rm\rightarrowtail tanT=\dfrac{12}{5}\)

Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \sf{(7.5 \: , \: 5.5)}}}}}\)

Step-by-step explanation:

Let the points be A and B

Let A ( 10 , 7 ) be ( x₁ , y₁ ) and B ( 5 , 4 ) be ( x₂ , y₂ )

Finding the midpoint

\( \boxed{ \sf{midpoint = (\frac{x1 + x2}{2} , \: \frac{y1 + y2}{2})}} \)

\( \dashrightarrow{ \sf{( \frac{10 + 5}{2} \: , \: \frac{7 + 4}{2} )}}\)

\( \dashrightarrow{ \sf{( \frac{15}{2} \: , \frac{11}{2}}} )\)

\( \dashrightarrow{ \sf{(7.5 \: , \: 5.5)}}\)

Hope I helped!

Best regards! :D

Answer:

the answers is 160

you take 180-120=60

m<6= 60

Step-by-step explanation:

Answer:

The previous year's population was 12000.

Step-by-step explanation:

Let the previous year's population be P.  Then:

P + 0.04P = 1.04P = 12480.

Solving 1.04P = 12480 results in P = 12000

The previous year's population was 12000.

Step-by-step explanation:

12480*4/100

= 1248* 0.4

=499.2 is 4% of 1280

:. 1280 - 499.2

780.8 is previous year's population

Answer:

40

Step-by-step explanation:

Answer:

None

Step-by-step explanation:

It would be easier to ask your teacher instead of getting wrong answers from random people. Ever think of that :0