In animals, energy is produced by the:

A. chloroplast
B. endoplasmic reticulum
C. mitochondria
D. nucleus

At higher temperatures, reactant molecules possess greater kinetic energy, resulting in more frequent and energetic collisions, which increases the rate of reaction at 120.

When the temperature is increased, the average kinetic energy of the molecules rises. According to the kinetic theory of gases, this leads to an increase in the speed and frequency of molecular collisions. As a result, reactant molecules collide with each other more frequently, providing a higher chance of successful collisions. Additionally, the increased kinetic energy of the molecules enhances the likelihood of the necessary activation energy being surpassed, allowing the reaction to occur. Therefore, at higher temperatures, the collisions between reactant molecules become more frequent and energetic, enabling the reaction to proceed at an observable rate at 120 degrees Celsius.

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Answer: Physical - Color, density, boiling/melting point, magnetism, texture, and odor

Chemical - reactivity, combustibility, color change, and temperature change

Explanation:

Physical properties are changes to a substance that can be reversed and refer to its state at the time. Chemical properties are properties that are observable during or after a chemical reaction and cannot be reversed since the reaction has changed the state of the substance.

China's scientific prowess is the result of a combination of historical legacy, government support, a strong education system, global competitiveness, and a commitment to international collaboration.

China's emphasis on science and scientific advancements can be attributed to several factors:

1. Historical Legacy: China has a rich history of scientific discoveries and innovations dating back centuries. Ancient Chinese contributions include inventions such as papermaking, gunpowder, compass, and the development of traditional Chinese medicine. This legacy has instilled a cultural appreciation for scientific knowledge and inquiry.

2. Government Support: The Chinese government recognizes the importance of science and technology for economic development and national progress. It has implemented policies and initiatives to promote scientific research, innovation, and education. Significant investments have been made in research and development, infrastructure, and the establishment of scientific institutions and universities.

3. Education System: China has a rigorous education system that places a strong emphasis on science, technology, engineering, and mathematics (STEM) education. There is a focus on producing a skilled scientific workforce to drive innovation and economic growth. The country has numerous prestigious universities and research institutions that attract talented students and researchers from both within China and internationally.

4. Global Competitiveness: China's rise as a global economic power has led to a desire to enhance its scientific capabilities and compete with other advanced nations. It recognizes that scientific advancements are key to technological innovation, industrial competitiveness, and addressing societal challenges.

5. International Collaboration: China actively engages in international scientific collaborations and partnerships. It recognizes the value of exchanging knowledge, sharing resources, and collaborating with researchers worldwide. This approach facilitates access to cutting-edge research, global networks, and diverse perspectives.

Overall, China's scientific prowess is the result of a combination of historical legacy, government support, a strong education system, global competitiveness, and a commitment to international collaboration. These factors have contributed to China's significant scientific advancements and its position as a scientific powerhouse.

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The hybridization schemes corresponding to each electron geometry:

a. Linear: The hybridization scheme for linear electron geometry is sp hybridization.
b. Trigonal planar: The hybridization scheme for trigonal planar electron geometry is sp2 hybridization.
c. Tetrahedral: The hybridization scheme for tetrahedral electron geometry is sp3 hybridization.
d. Trigonal bipyramidal: The hybridization scheme for trigonal bipyramidal electron geometry is sp3d hybridization.
e. Octahedral: The hybridization scheme for octahedral electron geometry is sp3d2 hybridization.

In each case, the hybridization scheme is determined by the combination of s, p, and d orbitals required to accommodate the electron geometry.

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a. Linear: sp, b. Trigonal planar: sp², c. Tetrahedral: sp³, d. Trigonal bipyramidal: sp³d, e. Octahedral: sp³d². These hybridization schemes describe the arrangement of orbitals around the central atom in each respective electron geometry.

a. The hybridization scheme for a linear electron geometry is sp.

b. The hybridization scheme for a trigonal planar electron geometry is sp².

c. The hybridization scheme for a tetrahedral electron geometry is sp³.

d. The hybridization scheme for a trigonal bipyramidal electron geometry is sp³d.

e. The hybridization scheme for an octahedral electron geometry is sp³d².

In the case of linear electron geometry (a), the central atom is surrounded by two electron groups, resulting in a linear arrangement. The atom undergoes sp hybridization, where one s orbital and one p orbital hybridize to form two sp hybrid orbitals.

For trigonal planar electron geometry (b), the central atom is surrounded by three electron groups, forming a planar arrangement. The atom undergoes sp² hybridization, where one s orbital and two p orbitals hybridize to form three sp² hybrid orbitals.

In tetrahedral electron geometry (c), the central atom is surrounded by four electron groups, resulting in a three-dimensional arrangement. The atom undergoes sp³ hybridization, where one s orbital and three p orbitals hybridize to form four sp³ hybrid orbitals.

For trigonal bipyramidal electron geometry (d), the central atom is surrounded by five electron groups, forming a complex arrangement. The atom undergoes sp³d hybridization, where one s orbital, three p orbitals, and one d orbital hybridize to form five sp³d hybrid orbitals.

In octahedral electron geometry (e), the central atom is surrounded by six electron groups, resulting in a symmetrical arrangement. The atom undergoes sp³d² hybridization, where one s orbital, three p orbitals, and two d orbitals hybridize to form six sp³d² hybrid orbitals.

Therefore, a. Linear: sp, b. Trigonal planar: sp², c. Tetrahedral: sp³, d. Trigonal bipyramidal: sp³d, e. Octahedral: sp³d². These hybridizations correspond to the electron geometries and describe the arrangement of orbitals around the central atom.

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This diagrammatic representation is called an organizational chart or an organogram.

Organizational charts use boxes or rectangles to represent positions or departments within a firm, and lines or arrows to connect them, indicating the reporting relationships and hierarchy within the organization.   Organizational charts can vary in complexity depending on the size and structure of the firm. They provide a visual representation of the reporting relationships and help individuals understand the hierarchy and structure of the organization.

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They tell us that the pressure of the gas is constant and the temperature and volume vary. If we assume that the gas behaves like an ideal gas, we can apply Charles's law, which tells us:

where,

V1 is the initial volume, 3.62L

T1 is the initial temperature, 21.6°C=294.75K

V2 is the final volume, 3.45L

T2 is the final temperature, in Kelvin

Now, we clear T2 and replace the known data:

The temperature at which the volume of the gas is 3.45 L will be 281K

Answer. b) 281K

The Bohr radius is a fundamental constant in atomic physics that represents the average distance between the nucleus and the electron in a hydrogen atom. The value of the Bohr radius is approximately 0.529 Å (angstroms) or 52.9 pm (picometers).

The Bohr radius (a₀) is a physical constant derived from the Bohr model of the hydrogen atom. It represents the average distance between the nucleus (a single proton) and the orbiting electron in a hydrogen atom. The Bohr model assumes that the electron moves in circular orbits around the nucleus, and the radius of the orbit depends on the energy level of the electron.

The value of the Bohr radius is approximately 0.529 Å (angstroms) or 52.9 pm (picometers). This value is commonly used as a unit to measure atomic sizes and distances. The picometer (pm) is a convenient unit for expressing atomic scales, as it is equivalent to 10^(-12) meters.

The Bohr radius provides a scale for understanding the size of atoms and their electronic structure. It is particularly relevant in hydrogen-like systems, where the electronic structure is similar to that of a hydrogen atom with a single electron orbiting a central nucleus.

The Bohr radius allows scientists to estimate the average size of atomic orbitals and the distances between atoms in molecules.

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5N force was applied to an object if 35 j of work was done and the object moved 7 m

A force is an effect that can alter an object motion according to physics and an object with mass can change its velocity or accelerate as a result force and also force is as push or pull and work done by the force on an object means assuming that direction of the force is parallel to the displacement of the object

Then the formula is

W = f × d

Where f is the magnitude of force and d is the displacement of the object

Then W = 35 J is the work done and

d = 7m is the displacement of the object

So rearrange the equation then

F = 35/7 = 5N

5N force was applied to an object if 35 j of work was done and the object moved 7 m

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The fact that water has a high melting and boiling point (0°C/32°F for melting and 100°C/212°F for boiling) makes it unique.

When a substance's solid and liquid phases are in equilibrium, that point is known as its melting point. When a substance's vapour pressure matches the outside pressure, that's when it reaches its boiling point.

Saturation temperature is another name for boiling point. The pressure at when the measurement was made can occasionally be used to define boiling point. The standard boiling point is the temperature at which water begins to boil at one bar of pressure, according to the International Union on Pure an Applied Chemistry (IUPAC) definition from 1982.

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Answer:

0.909 mole

Explanation:

Given N = 14, O = 16

=> so N20 = 14(2) + 16 = 44 g/mole

so number of mole of 40.0g = (40.0g)/(44 g/mole) = 0.909 mole

Activation energy is best defined as the minimum energy required by the reactant to overcome the barrier potential in a chemical reaction.

Every reaction is taking place within some preferred condition and and without achieving this, the reaction does not proceed. According to kinetic theory of particles. The particles of different elements collide each other and form products.

For the effective collision, the reactant particles have to overcome a barrier potential, for which they have to attain some energy beyond their actual energy.

This energy that the reactants have to attain to overcome the barrier potential of a reaction is called its activation energy. The less the activation energy, more will be the reaction rate.

Increase in temperature and addition of catalysts helps to reduce the activation energy.

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The lipids that have two long hydrocarbon chains linked by an ester group are called phospholipids. Phospholipids are essential components of cell membranes as they form a bilayer structure, with the hydrophobic tails facing inward and the hydrophilic heads facing outward.

This arrangement provides a barrier that regulates the passage of substances into and out of the cell. In contrast, waxes have long hydrocarbon chains linked by a different type of bond, and they are primarily used for waterproofing and protection.

Steroids have a distinct structure with four rings of carbon atoms and are involved in a variety of physiological processes, including hormone regulation.

Triglycerides, on the other hand, have three long hydrocarbon chains linked to a glycerol molecule and are used for energy storage.

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The absolute amount of the discrepancy or simply error between the measured value and the actual value is multiplied by 100 and divided by the actual value to determine the percent error.

Follow these easy procedures to determine the error rate-

1. Don't take into consideration any minus (-) signs when calculating the inaccuracy (by deducting the predicted value from the actual value). take the error's absolute value, etc.

Approximate Value - Exact Value = Absolute Error

2. Subtract the mistake from the accurate figure (sometimes, we may get a decimal number).

3. Relative error is the difference between the precise and approximative values.

4. Add a "%" following the conversion to a percentage (by multiplying by 100).

|Approximate Value - Exact Value|/Exact Value 100% Percent Error

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A lunar eclipse can be photographed sometimes when Earth is in between the sun and the Moon.

A lunar eclipse occurs when the Sun, Earth, and Moon align in the same line in which the Moon passes into Earth's shadow. In a total lunar eclipse, the entire Moon falls within the darkest part of Earth's shadow, called the umbra so we can conclude that claim 2  is the right answer about lunar eclipse.

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Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 4500 g

density = 20.5 g/cm³

We have

\(volume = \frac{4500 }{20.5} \\ = 219.51219...\)

We have the final answer as

Hope this helps you

Answer:

complementary mRNA would be UGCUAG, TRNA anticodon would be UAC. Transcription for eukaryotes happens in nucleus and translation happens in cytoplasm. For prokaryotes both happen in cytoplasm.

Explanation:

Hope that helps!

Answer:

The procedure is Filtration

Explanation:

Filtration is a process that is use to separate insoluble solid from liquid for example Salt and water.

This process uses filter paper which is placed inside a funnel and then placed inside a beaker.

The mixture of sand and water is poured into the the filter paper and water then drains out down to the funnel and the beaker.

The solid part remain at the filter paper and it is called the residue and the water is the filtrate.

Answer:

the answer is the third figure from left

The molar mass of the unknown gas is 43.87 g/mol.

To determine the molar mass of the unknown gas, consider Graham's law of effusion, wherein we can equate the ratio between the times of effusion of the two gases, to the ratio of the roots of the molar masses of the unknown gas and He gas, such that:

t_He / t_unknown gas = √MW_He / √MW_unknown gas

If He gas is observed to effuse through a porous barrier in 8.76 minutes and under the same conditions, the same number of moles of an unknown gas requires 29.0 minutes to effuse through the same barrier, then the molar mass of the unknown gas can be solved as follows.

8.76 minutes / 29.0 minutes = (√4.002602 g/mol) / √MW_unknown gas

√MW_unknown gas = (√4.002602)(29.0 minutes) / (8.76 minutes)

MW_unknown gas = 43.87 g/mol

Hence, the molar mass of the unknown gas is 43.87 g/mol.

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The given statement "Running water is the single most important erosional agent sculpting Earth's land surface" is false because it fails to acknowledge the significant role played by other erosional agents such as glaciers, wind, waves, and gravity.

Running water is indeed a significant erosional agent, but it is not the sole or primary agent responsible for shaping Earth's land surface. Erosion refers to the process of wearing away or removal of materials from the Earth's surface. While running water, particularly in the form of rivers and streams, plays a crucial role in erosion, other agents such as glaciers, wind, waves, and gravity also contribute significantly.

Glaciers, for example, have immense erosive power as they move across the land, carving out valleys and shaping mountains. The movement of ice and the grinding action of rocks embedded in the glacier can profoundly reshape the landscape.

Wind erosion occurs when wind transports and deposits sediment, resulting in the formation of sand dunes and the gradual weathering of rocks. Waves erode coastlines through processes like abrasion, hydraulic action, and corrosion. Gravity also plays a vital role in erosion, causing landslides, mass wasting, and the downward movement of materials on slopes.

While running water is important in shaping the Earth's surface, it is essential to acknowledge the significant role played by other erosional agents as well. The combined action of these forces contributes to the diverse and dynamic landforms we observe on our planet.

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Answer:

1.24×10^6/6.2×10^-3

200

acc to scientific notation: 0.2×10^3 is the answer

Explanation:

pls mark me as brainlest

Answer:

You become negatively charged

Answer:

because it does not cost much and can be found easily.  due to their low resistance and excellent conductivity.

Explanation:

The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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Answer:

214.77 g/mol

Explanation:

Tin(II) sulfate

From Wikipedia, the free encyclopedia

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Tin(II) sulfate

Tin(II) sulfate crystallizes in an heavily distorted barium sulfrate structure.

Unit cell of tin(II) sulfate.

Names

Other names

Stannous sulfate

Identifiers

CAS Number  

7488-55-3 ☑

3D model (JSmol)  

Interactive image

ChemSpider  

21106484 ☑

ECHA InfoCard 100.028.457 Edit this at Wikidata

EC Number  

231-302-2

PubChem CID  

62643

UNII  

0MFE10J96E ☑

CompTox Dashboard (EPA)  

DTXSID20884389 Edit this at Wikidata

InChI[show]

SMILES[show]

Properties

Chemical formula SnSO4

Molar mass 214.773 g/mol

Appearance white-yellowish crystalline solid

deliquescent

Density 5.15 g/cm3

Melting point 378 °C (712 °F; 651 K)

Boiling point decomposes to SnO2 and SO2

Solubility in water 33 g/100 mL (25 °C)

Structure[1]

Crystal structure Primitive orthorhombic

Space group Pnma, No. 62

Lattice constant  

a = 8.80 Å, b = 5.32 Å, c = 7.12 Å[2]

Hazards

NFPA 704 (fire diamond)  

NFPA 704 four-colored diamond

010

Flash point Non-flammable

Lethal dose or concentration (LD, LC):

LD50 (median dose) 2207 mg/kg (oral, rat)

2152 mg/kg (oral, mouse)[3]

Related compounds

Other anions Tin(II) chloride, tin(II) bromide, tin(II) iodide

Other cations Lead(II) sulfate

Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Tin(II) sulfate (SnSO4) is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence. It can be prepared by a displacement reaction between metallic tin and copper(II) sulfate:[4]

Sn (s) + CuSO4 (aq) → Cu (s) + SnSO4 (aq)

Tin(II) sulfate is a convenient source of tin(II) ions uncontaminated by tin(IV) species.

Answer:

I beileve it is NORTH KOREA!! XD actually D.

Explanation:

Since they are the main producers of the organic compounds needed for the development and survival of other organisms, phototrophs are essential for the flow of energy in the biosphere.

The flow of energy in the biosphere begins primarily with phototrophs. Phototrophs are organisms that use energy from the sun to convert carbon dioxide and water into organic compounds, such as sugars and carbohydrates, through the process of photosynthesis. These organic compounds provide a source of energy and nutrients for other organisms in the biosphere, which ultimately fuels the flow of energy through the food chain. Other organisms, such as chemotrophs, can also obtain energy from oxidized chemicals or inorganic compounds, but the primary source of energy in most ecosystems is derived from photosynthesis.

Therefore, phototrophs play a crucial role in the flow of energy in the biosphere, as they are the primary producers of organic compounds that support the growth and survival of other organisms.

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