In an aneurysm, the cross-sectional area of a vessel expands. With the approximation that blood is non-viscous and incompressible, and that you have a laminar flow, which one of the following is true in the expanded segment, compared to the normal vessel?a) The velocity is higher.b) The flow is higher.c) The density of the blood increases.d) The velocity is the same.e) The density of the blood decreases.f) None of the above.

Answer:

The principal hair fiber used to produce textile fabrics is sheep's wool. In wild sheep, the wool is a short, soft underlayer protected by longer, coarser hair. ... Fur fibers from animals such as mink and beavers are sometimes blended with other hairs to spin luxury yarns but are most often found as fur pelts.

Answer:

Below

Explanation:

The vaulter's entire KE will be converted to PE to clear the bar (5-.9) = 4.1 m above the COM.

PE required = mgh = 70 ( 9.81)(4.1) = 2815.5 J

KE required will then be   2815.5  J

(As an aside:  = 1/2 mv^2 = 2815.5 = 1/2 ( 70)(v^2)   shows v = 9  m/s)

Answer:

The "solid force"? ... The direction of the force always seems to be coming out of the solid surface. A direction which is perpendicular to the plane of a surface is said to be normal. The force that a solid surface exerts on anything in the normal direction is called the normal force.

Explanation:

i think i hope this helps

The puppy was not moving relative to Daylon, the wagon, or his collar.

He was moving relative to a point on the sidewalk.

Note that the puppy did NOT get his walk.

Answer:

15 V

Explanation:

From the question,

For series connection: (i) Both resistor have a common current flowing through the (ii) The combined resistance = R1+R2

Rt = R1+R2.................. Equation 1

Given: R1 = 5 ohms, R2 = 7.5 ohms.

Rt = 5+7.5 = 12.5 ohms.

Applying Ohm's law,

V = IRt................... Equation 2

Where V = Voltage, I = current.

make I The subject of the equation

I = V/Rt.............. Equation 3

Given: V = 25 V, Rt = 12.5 ohms.

Substitute into equation 3

I = 25/12.5

I = 2 A.

Now,

Voltage drop across the 7.5 ohms resistor = R2×I

Voltage drop across the 7.5 ohms resistor = 7.5×2

Voltage drop across the 7.5 ohms resistor = 15 V

The ray diagram that shows the emergent ray from the glass prism is shown.

A light ray that has crossed a boundary between two different transparent substances, such as air and water or air and glass, is referred to as a "emergent ray". Light can change direction when it comes into contact with an interface between two media having distinct optical characteristics, such as differing refractive indices. The light ray that continues on its route in the second medium after crossing the interface is known as an emergent ray.

Refraction, a phenomenon, is the cause of the emerging ray's shift in direction. Refraction happens because light moves through different materials at varying speeds, and when it comes into contact with a boundary at an angle, it bends or changes course.

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Answer: gravity

normal force

friction

Explanation:

A force is refered to as the interaction which when unopposed, will lead to a change in an objects motion. The velocity of an object will be changed when force is applied.

Since Alisa s riding down a hill and she and the skateboard are considered to be a single object, then the forces that are acting on her include gravity, normal force and friction.

The addition of vectors allows to find the vector that the equilibrium is

                F = (40.02 i ^ - 49.95 j ^) N

Parameters given

To find

The force is a vector magnitude so the sum of the force must be done using the methods to add vectors.

One of the easiest methods to perform the addition of vectors is the analytical method where each vector is decomposed in a Cartesian system and the components added using algebraic summation and then the resulting vector is constructed.

We decompose the vector

                 cos θ = \(\frac{A_x}{A}\)Ax / A

                 sin θ = \(\frac{A_y}{A}\)

                 Aₓ = A cos θ

                 \(A_y\)= A sin θ

                 Aₓ = 64 cos 128.7

                 \(A_y\) = 64 sin 128.7

                 Aₓ = -40.02 N

                 \(A_y\) = 49.95 N

To find the vector that allows equilibrium, we work each axis independently

X axis

                 Aₓ + Fₓ = 0

                 Fₓ = - Aₓ

                 Fₓ = 40.02 N

Y axis

                  \(A_y + F_y =0 \\F_y = - A_y\\F_y = - 49.95 N\)

We can write the resulting vector in two ways

1) F = (40.02 i ^ - 49.95 j ^) N

2) in the form of module and angle

Let's find the module with the Pythagoras' Theorem

              F =\(\sqrt{F_x} ^2 + F_y^2)\\F = \sqrt{40.02^2 + 49.95^2 }\)  

              F = 64 N

Angles

              tan θ = \(\frac{F_y}{F_x}\)

              θ = tan⁻¹  \(\frac{F_y}{F_x}\)

              θ = tan⁻¹ \(\frac{-49.95}{40.02}\)

              θ = -51.3º

This angle is measured clockwise from the positive side of the x-axis

In conclusion using the sum of vectors we can find the vector that allows the equilibrium is

                F = (40.02 i^  - 49.95 j^ ) N

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The weight of a 1 in x 1 in steel bar if it were 27 in long would be 7.64 lbs.

Density of steel is approximately = 0.283 lbs/in³

Dimensions of steel bar is= 1 in x 1 in

Steel bar is 27 inches long

We have to calculate weight of steel bar

Formula used for calculation

Density = mass/volume

Weight = density x volume

We can get the volume of steel bar as

Volume of steel bar = length x breadth x height

Volume of steel bar = 1 x 1 x 27Volume of steel bar = 27 in³

Now, we will calculate the weight of the steel bar

Weight = density x volume

Weight = 0.283 x 27Weight = 7.641 lbs

So, the weight of a 1 in x 1 in steel bar if it were 27 in long would be 7.64 lbs.

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Answer:

See below

Explanation:

Energy is lost in the form of friction/heat/sound

  you cannot get more work out of a machine than you put into it.  

False

The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.

However, the winds will not be the same in both features.  

In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.  

Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.

Answer:

Parallel Circuits

Explanation:

Loads can be operated on their own. If you had a series circuit, adding another light would dim the rest!

Answer:

Change in velocity = 4 m/s and acceleration = 0.5 m/s²

Explanation:

Given that,

Initial velocity, u = 3 m/s

Final velocity, v = 7 m/s

Time, t = 8 seconds

(a) The change in velocity of a cyclist.

\(\Delta v=v-u\\\\=7\ m/s-3\ m/s\\\\=4\ m/s\)

(b) Acceleration,

\(a=\dfrac{\Delta v}{t}\\\\a=\dfrac{4\ m/s}{8\ s}\\\\a=0.5\ m/s^2\)

So, the change in velocity is 4 m/s and acceleration is 0.5 m/s².

I will go through each statement and provide a true or false answer for an electron.
(a) True

(b) False

(c) True

(d) True

(e) True

(a) True. An electron is a quantum particle that exhibits both particle-like and wave-like behaviour, depending on the experiment being conducted.
(b) False. An electron's rest energy is not zero. It has a rest mass, which means it has a non-zero rest energy according to the equation E=\(mc^2\).
(c) True. An electron carries energy in its motion, both kinetic energy due to its movement and potential energy due to its position in an electric field.
(d) True. An electron carries momentum in its motion, which can be described as the product of its mass and velocity (p=mv) in classical mechanics, or as the product of its wavelength and Planck's constant divided by 2π in quantum mechanics (p=h/(2πλ)).
(e) True. The motion of an electron is described by a wave function, which has a wavelength and satisfies the Schrödinger wave equation. This wave function provides information about the electron's position and momentum in a probabilistic manner.

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Plate tectonics, the rock cycle, and surface processes interact to create, concentrate, and distribute mineral resources. Understanding these processes is crucial for identifying and extracting valuable minerals for human use.

Plate tectonics, the rock cycle, and surface processes such as weathering and erosion play important roles in the availability of mineral resources for human extraction and use. Here's how these processes contribute:

Plate Tectonics: Plate tectonics is the theory that explains the movement of Earth's lithospheric plates. It influences the distribution of mineral resources through several mechanisms:

a. Subduction Zones: When one tectonic plate is subducted beneath another, it creates intense heat and pressure, causing rocks to melt and form magma chambers. This process can generate large deposits of minerals, including precious metals, such as gold and silver, as well as base metals like copper and lead.

b. Divergent Boundaries: At divergent plate boundaries, such as mid-oceanic ridges, magma rises to the surface, cools, and solidifies, forming new crust. These areas often contain valuable mineral resources, including iron, manganese, and hydrothermal vents that can host valuable metal deposits.

c. Transform Boundaries: Transform plate boundaries, where plates slide past each other, can create fault zones. These fault zones can act as conduits for hydrothermal fluids, which can deposit minerals like copper, zinc, and lead.

Rock Cycle: The rock cycle is a continuous process that describes how rocks are formed, weathered, and transformed over time. It contributes to the availability of mineral resources in the following ways:

a. Igneous Processes: Igneous rocks, formed from the solidification of magma or lava, can host valuable mineral deposits. For example, granite and pegmatite rocks can contain minerals such as quartz, feldspar, and mica, while basaltic rocks can contain minerals like iron and magnesium.

b. Metamorphic Processes: Heat and pressure during the metamorphic process can cause minerals to recrystallize and concentrate, leading to the formation of economically significant mineral deposits. Examples include metamorphic deposits of asbestos, talc, and graphite.

c. Sedimentary Processes: Sedimentary rocks are formed from the accumulation of sediments, which may contain mineral grains eroded from existing rocks. Sedimentary deposits are important for resources like coal, oil, natural gas, and mineral sands (e.g., titanium, zircon).

Surface Processes (Weathering and Erosion): Surface processes, including weathering and erosion, can influence the availability and concentration of mineral resources:

a. Weathering: Weathering breaks down rocks into smaller particles, releasing minerals from their original host rocks. Through chemical weathering, certain minerals can be concentrated or leached, leading to the formation of economically viable deposits. For instance, weathering of sulfide minerals can generate ore bodies containing valuable metals like copper, zinc, and nickel.

b. Erosion and Sedimentation: Erosion transports weathered materials and deposits them in new locations, potentially concentrating mineral resources. Sedimentation in riverbeds, deltas, and ocean basins can create deposits of heavy minerals like gold, diamonds, and rare earth elements.

Overall, plate tectonics, the rock cycle, and surface processes interact to create, concentrate, and distribute mineral resources. Understanding these processes is crucial for identifying and extracting valuable minerals for human use.

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When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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Answer:

Explanation:  Please see my attached calculations.

The change in the kinetic energy is (22000 + 416500sinθ) J

The net force on the car F' = F - f - N where

So, F' = F - f - N

F' = F - f - mgsinθ

Since the car moves at constant velocity, the net force F' = 0

So, F' = F - f - mgsinθ

F - f - mgsinθ = 0

F = f + mgsinθ

From the work-kinetic energy theorem,

The kinetic energy change of the car ΔK equals the work done by force on car, W

ΔK = W = Fd where

ΔK = Fd

= (f + mgsinθ)d

=  fd + mgdsinθ

Substituting the values of the variables into the equation, we have

ΔK = fd + mgdsinθ

= 440 N × 25 m + 1700 kg × 9.8 m/s² × 25 m × sinθ

= 22000 Nm + 416500sinθ Nm

= (22000 + 416500sinθ) J

So, the change in the kinetic energy is (22000 + 416500sinθ) J

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Answer:

the heating method in here is conventional heating due to the warn air goes to the top bunk whereas the cold air sinks down

Answer:

???????????????? Tell me also

Answer:

Area is inversely proportional to pressure.

Explanation:

✍ Lesser the area, higher the pressure.

✍ More the area, lower the pressure.

Thank You

The work done in case a) is positive, in case b) is negative and in case c) is positive.

Work is said to be done when the displacement is occur in the direction of the applied force.  

W = F×d×cosθ

Where F is the force, d is the displacement and θ is the angle between the displacement and the direction of the force.

In case a) as the work is done against the direction of the gravity so the work is positive. In case b) the weight of the buckets acts in downwards direction, that is the direction of the acceleration due to gravity. So the work is negative. In case c) the bucket were lowered, it means the displacement is in the direction of the applied force. Hence the work done is positive.

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Answer:

k and...

Explanation:

Answer:

no thank you.

explanation: Do not want to

The tension in the wire just after the collision is 98.1 N.

To solve this problem, we need to use the principle of conservation of momentum and energy.

Before the collision, the momentum of the system is:

p = m1v1 + m2v2

where m1 = 8.00 kg is the mass of the hanging ball, v1 = 0 (since it is at rest), m2 = 2.00 kg is the mass of the moving ball, and v2 = 5.00 m/s is its velocity. Therefore, the initial momentum of the system is:

p_initial = m1v1 + m2v2 = 2.005.00 = 10.00 kgm/s

After the collision, the 2.00 kg ball will stick to the 8.00 kg ball, and they will move together as one body. Since the collision is elastic, the total mechanical energy of the system is conserved. The mechanical energy of the system before the collision is:

E_initial = (1/2)m1v1² + (1/2)m2v2²= 0.52.005.00^2 = 25.00 J

The mechanical energy of the system after the collision is:

E_final = (1/2)MV²

where M = m1 + m2 = 10.00 kg is the mass of the combined system, and V is the velocity of the combined system just after the collision.

Using the principle of conservation of momentum, we know that:

p_initial = p_final

or

m1v1 + m2v2 = (m1 + m2)*V

Substituting the values we know, we get:

8.000 + 2.005.00 = (8.00 + 2.00)*V

V = 1.00 m/s

So, the velocity of the combined system just after the collision is 1.00 m/s.

Now, we can calculate the mechanical energy of the system after the collision:

E_final = (1/2)MV^2 = 0.510.001.00²= 5.00 J

Since the total mechanical energy of the system is conserved, we have:

E_final = E_initial

Therefore, the kinetic energy lost during the collision is:

ΔK = E_initial - E_final = 25.00 - 5.00 = 20.00 J

This kinetic energy is dissipated in the form of internal energy, such as heat, sound, and deformation of the balls.

Finally, we can find the tension in the wire just after the collision by considering the forces acting on the combined system. Since the system is in equilibrium, the tension in the wire must be equal to the weight of the system:

Tension = Weight = M*g

where g = 9.81 m/s² is the acceleration due to gravity.

Substituting the values we know, we get:

Tension = 10.00*9.81 = 98.1 N

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Answer:

x=48.12 m

Vf=23.544 m/s

Explanation:

a=g

t=2.4

Vf=?

Vø=0

Vf=Vø+at

Vf=0+(9.81)(2.4)=23.544

x=Xø+Vøt+1/2at^2

x=1/2at^2

x=(1/2)(9.81)^2=48.11805

When a star collapses to one-fifth its size, the gravitational force at its surface increases.

Gravitational force is directly proportional to the mass of an object and inversely proportional to the square of its distance. When the star collapses to one-fifth its size, its mass remains the same, but the distance from the center of the star to its surface decreases.

Let's denote the original radius of the star as R and the collapsed radius as R/5. The distance from the center of the star to its surface decreases by a factor of 1/5, which means the new distance is (1/5)R.

The gravitational force at the surface of the star can be calculated using Newton's law of universal gravitation:

F = (G * M * m) / r^2

where F is the gravitational force, G is the gravitational constant, M is the mass of the star, m is the mass of an object at the surface of the star, and r is the distance between the center of the star and the surface.

Since the mass of the star remains the same during the collapse, we can consider M as a constant. The gravitational force is inversely proportional to the square of the distance, so as the distance decreases, the gravitational force increases.

Therefore, when the star collapses to one-fifth its size, the gravitational force at its surface increases.

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The speed of the block will increase as the angle of elevation decreases.

As the angle of elevation of the inclined plane decreases, the gravitational force component acting parallel to the surface of the incline decreases. This component contributes to the acceleration of the block down the incline. Therefore, with a smaller angle of elevation, there is less opposition to the motion of the block, resulting in an increased acceleration and ultimately a higher speed. This can be understood by considering the forces involved: the force of gravity acting down the incline and the normal force perpendicular to the incline. As the angle decreases, the gravitational force component parallel to the incline becomes larger relative to the normal force, leading to a greater acceleration and faster sliding speed.

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A block is sliding down the surface of an inclined plane while the angle of elevation is gradually decreased. Which of the following is true about the results of this process?

a) The speed of the block will increase.

b) The speed of the block will decrease.

c) The speed of the block will remain unaffected.

d) Block will stop moving.

First find Acceleration

\(\boxed{\sf Acceleration=\dfrac{v-u}{t}}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{42-0}{2}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{42}{2}\)

\(\\ \sf\longmapsto Acceleration=21m/s^2\)

Using second equation of kinematics

\(\boxed{\sf s=ut+\dfrac{1}{2}at^2}\)

\(\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}(21)(2)^2\)

\(\\ \sf\longmapsto s=21(2)\)

\(\\ \sf\longmapsto s=42m\)

Answer:

B) Decreases

Explanation:

Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.

Hope this helps!

Answer:

The answer would be B

Explanation:

Answer:

  a = -7.29 m / s²

Explanation:

For this exercise we must use Newton's second law,

          F -W = m a

Force is electrical force

         F = k q₁ q₂ / r²

         k q₁ q₂ / r² -mg = m a

indicate that the charge of the two spheres is equal

         q₁ = q₂ = q

         a = (k q² / r² - m g) / m

         a = k q² / m r² - g

Let's reduce the magnitudes to the SI system

        m = 0.19 g (1kg / 1000 g) = 1.9 10⁻⁴ kg

        q1 = q2 = q = -23.0 nC (1C / 10⁹ nC) = -23.0 10⁻⁹ C

        r = 10.0 cm (1m / 100cm) = 0.1000 m

let's calculate

        a = 9 10⁹ (23.0 10⁻⁹)² / (0.1000² 1.9 10⁻⁴) - 9.8

        a = -7.29 m / s²

The negative sign indicates that the direction of this acceleration is downward