In ABC find a if b = 2, C = 6, and A=35°

Show work plzz!!!!

Answer:

x = 5

Step-by-step explanation:

We know that BD = 2x - 1 and BC + CD = BD.  Thus, we can set the sum of (x- 3) and 7 equal to 2x - 1 to find x:

BC + CD = BD

x - 3 + 7 = 2x - 1

x + 4 = 2x - 1

x + 5 = 2x

5 = x

Thus, x = 5

Checking the validity of our answer:

We can check that our answer is correct by plugging in 5 for x in x - 3 and 2x - 1 and checking that we get the same answer on both sides of the equation:

5 - 3 + 7 = 2(5) - 1

2 + 7 = 10 - 1

9 = 9

Thus, our answer is correct.

Answer:

To determine the amount of engine oil needed, we need to find 5% of 3.8 gallons:

0.05 x 3.8 = 0.19

So, 0.19 gallons of engine oil should be added to the jerry can.

Part A :

Yes, the statement is true that  P( A and B ) = 0 .

Given,

Event A and Event B are mutually exclusive.

Thus P ( A and B ) = 0

Part B:

A and B are mutually exclusive events if they do not occur at the same time.

This means that A and B do not share any common outcomes and

P(A and B) = 0.

Part C:

Let,

The sample space W = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}.

Let A = {1, 2, 3, 4, 5}, Y = {4, 5, 6, 7, 8}, and B = {7, 9}.

A and B do not have any numbers in common so P(A and B) = 0.

Hence, A and B are mutually exclusive.

Learn more about Probability,

https://brainly.com/question/29492440

#SPJ1

Answer: 0.625 lbs

Step-by-step explanation:

3.5 x 3 = 10.5

10.5 / 4 = 2.625

3.5 - 2.625 = 0.875

0.875 - 0.25 = 0.625

Round accordingly!

Answer:

y = 3x +4

Step-by-step explanation:

The only parallel line equations are the first two, but the second satisfies the given point

Hope this helps

Answer:

3.6

Step-by-step explanation:

set-up percentage like this!

\(\frac{part}{whole} =\frac{part}{whole}\)

Then use what you know from the question to fill in the blanks

Answer: \(\frac{6}{100} =\frac{?}{60}\)

Then: \(60\) × 6 ÷ 100 = 3.6

Final Answer: 3.6

Answer:

3.999 millimeters.

Step-by-step explanation:

To find the height of the cylinder, we can use the formula for the volume of a cylinder:

V = πr²h

Given that the radius (r) of the cylinder is 4 millimeters and the volume (V) is 200.96 cubic millimeters, we can substitute these values into the formula and solve for the height (h).

200.96 = π(4²)h

200.96 = 16πh

To solve for h, we can divide both sides of the equation by 16π:

200.96 / (16π) = h

Using a calculator, we can calculate the approximate value of h:

h ≈ 200.96 / (16 × 3.14159)

h ≈ 3.999

Therefore, the height of the cylinder is approximately 3.999 millimeters.

Answer:

47%

Step-by-step explanation:

First we need to find the ratio of masks on Jack's wall to the total number of masks, which is 235/500. Now we need to make the denominator 100 in order to find the percentage by dividing the numerator and denominator by 5 to get 47/100. Therefore the percentage of Jack's mask collection that is on his wall is 47%.

Answer:

\(a_n=6+(-1)^{n+1}6\)

Step-by-step explanation:

The given sequence is

\(12,0,12,0,12,0,...\)

Assume that the pattern continues as indicated, the we need to find an explicit formula for the above sequence.

From the given sequence it is clear that all odd terms are 12 and all odd terms are 0.

Half of 12 is 6.

We know that,

\(6+6=12\)

\(6-6=0\)

So, the required formula is

\(a_n=6+(-1)^{n+1}6\)

Therefore, \(a_n=6+(-1)^{n+1}6\) .

The equation that could be used to represent this situation, where x is the course fee and R(x) is the total revenue, is: R(x) = 250000 + 375x - 2.5x²

Equations are mathematical statements with two algebraic expressionsοn either sideοf an equals (=) sign. It illustrates the equality between the expressions writtenοn the left and right sides. To determine the valueοf a variable representing an unknown quantity, equations can be solved. A statement is not an equation if there is no "equal to" symbol in it. It will be regarded as an expression.

N(x) = 625 + 2.5x

The revenue R(x) will be the productοf the numberοf students enrolled and the fee charged per student. The fee charged per student will be (400 - x) dollars. So, the revenue function can be represented as:

R(x) = (625 + 2.5x)(400 - x)

Simplifying the expression, we get:

R(x) = 250000 + 375x - 2.5x²

Therefore, the equation that could be used to represent this situation, where x is the course fee and R(x) is the total revenue, is:

R(x) = 250000 + 375x - 2.5x²

Learn more about equations, by the following link

brainly.com/question/2972832

#SPJ1

The value of the composite function (f o g)(3) is 1603

The functions are given as

f(x) = 3x² - 7x - 3

g(x) = -4x - 10

Next, calculate (f o g)(x) using

(f o g)(x) = f(g(x))

So, we have

(f o g)(x) = 3(-4x - 10)² - 7(-4x - 10) - 3

Substitute 3 for x.

So, we have

(f o g)(3) = 3(-4 x 3 - 10)² - 7(-4 x 3 - 10) - 3

Evaluate

(f o g)(3) = 1603

Hence, the value of the composite function (f o g)(3) is 1603

Read more about composite function at

https://brainly.com/question/10687170

#SPJ1

Answer:

may i have brainiest please

Step-by-step explanation:

Answer:

the person above me or below me is correct

Step-by-step explanation:

The required solutions of the functions are given as follows,

1. f(−7) = 35

2. f(−1) =  -1

3. f(0) =  1

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
1 .
for x = -7
f(x) = x² + 2x
f(-7) = (-7)² + 2(-7) = 35

2.
for x = -1
f(x) = x² + 2x
f(−1) = (-1)² + 2(-1) = -1

3.
For x = 0
f(x) = x + 1

f(0) = 0 + 1 =  1

Thus, the required solutions are given as follows,

1. f(−7) = 35

2. f(−1) =  -1

3. f(0) =  1

Learn more about simplification here:

https://brainly.com/question/12501526

#SPJ1

We can conclude that with 95 percent confidence, the sample means will fall within the interval of approximately (0.9534, 0.9566).

To determine the interval within which 95 percent of the sample means will fall, we need to calculate the margin of error using the standard deviation and the desired level of confidence.

The formula to calculate the margin of error is given by:

Margin of Error = Z * (Standard Deviation / √n)

Where:

Z is the critical value corresponding to the desired level of confidence

Standard Deviation is the standard deviation of the population

n is the sample size

Since the sample size is 41 and we want to find the interval at a 95 percent confidence level, we need to find the critical value corresponding to a 95 percent confidence level.

The critical value can be found using a standard normal distribution table or a calculator. For a 95 percent confidence level, the critical value is approximately 1.96.

Now we can calculate the margin of error:

Margin of Error = 1.96 * (0.0050 / √41)

Calculating this, we find:

Margin of Error ≈ 0.001624

To find the interval within which 95 percent of the sample means will fall, we need to subtract and add the margin of error to the true mean:

Interval = True Mean ± Margin of Error

Interval = 0.9550 ± 0.001624

Calculating this, we find:

Interval ≈ (0.9534, 0.9566)

Therefore, we can conclude that with 95 percent confidence, the sample means will fall within the interval of approximately (0.9534, 0.9566).

for more such question on interval visit

https://brainly.com/question/30460486

#SPJ8

Given:

To Determine: At what rate did they build the road in a week

Solution

To determine the rate per week, we would divide the total road built in 5 weeks by the number of weeks. Therefore, the rate is

Hence, the rate is 1.25km per week

Algebra transformation

for  Graph1 f(x)=f(x)+4

for  Graph2 f(x)=-f(x-4)

for  Graph3 f(x)=f(x-7)

for  Graph4 f(x)=f(x-2)-5

In mathematics, the reflection of a graph is a transformation that produces a mirror image of the original graph across a specific line or point. The line or point across which the reflection occurs is called the axis of reflection.

Graph1

Transform the graph by +4 units in y direction.

f(x)=f(x)+4

Graph2

Transform the graph by +4 units in x direction.

f(x)=f(x-4)

Now take the reflection of graph about x axis

f(x)=-f(x-4)

Graph3

Transform the graph by +7 units in x direction.

f(x)=f(x-7)

Graph5

Transform the graph by -5 units in y direction.

f(x)=f(x)-5

Now Transform the graph by -2 units in x direction.

f(x)=f(x-2)-5

To know more about line, visit:

https://brainly.com/question/30003330

#SPJ1

Answer:

t ≥ 75

Step-by-step explanation:

"at least 75" means 75 or higher.

The temperature is equal to 75 or greater than 75.

t ≥ 75

Answer:

9.98- 2.53 = 7.45

7.68 + 13.07 = 20.75

100.03 - 16.28 = 83.75

Step-by-step explanation:

 9.98

- 2.53

_____

7.45

  1   1        - Process of carrying 10's

   7.68

+ 13.07

_______

 20.75

0000 13 ⇔ What the number becomes after carrying

↑↑↑↑↑

100.03

- 16.28

______

83.75

Happy New Year!

Answer:

∠ BDC = 29°

Step-by-step explanation:

the sides of a rhombus are congruent, so CD = ED and Δ EDC is therefore isosceles with base angles congruent , then

∠ BCD = ∠ BED = 61°

• the diagonals are perpendicular bisectors of each other , then

∠ CBD = 90°

the sum of the 3 angles in Δ BCD = 180°

∠ BDC + ∠ CBD + ∠ BCD = 180°

∠ BDC + 90° + 61° = 180°

∠ BDC + 151° = 180° ( subtract 151° from both sides )

∠ BDC = 29°

The correct statement regarding the minimum value of the quadratic functions is given as follows:

D) The graphed function has a lower minimum value.

From the graph, the minimum value of the quadratic function is given as follows:

y = -8.

The algebraic function is defined as follows:

f(x) = 0.25x² - 2x.

Hence the coefficients are given as follows:

a = 0.25 and b = -2.

The x-coordinate of the vertex is given as follows:

x = -b/2a

x = 2/0.5

x = 4.

Then the y-coordinate of the vertex, representing the minimum value, is given as follows:

f(4) = 0.25(4)² - 2(4)

f(4) = -4 -> meaning that the graphed function has a lower minimum value.

The graph is given by the image presented at the end of the answer.

More can be learned about quadratic functions at brainly.com/question/31895757

#SPJ1

Answer:

so the picture attached is not a function, but it looks it exactly like a function, or y=x^2. Functions are relations are similar that they both relate something, but functions are sets of relations put together, as long as their are is only one output per one input

Answer:

-6x+3>9

Step-by-step explanation:

Shift the equation to suitable form

Suppose you begin with a number . Multiply it with 3 then subtract 6 from it ,describe a suitable no so that the resulting number will be less than -9.

If Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

To show that x is also an eigenvector of QT, we need to demonstrate that QT * x is a scalar multiple of x.

Given that Q is an orthogonal matrix, we know that QT * Q = I, where I is the identity matrix. This implies that Q * QT = I as well.

Let's denote x as the eigenvector corresponding to the eigenvalue λ1 This means that Q * x = λ1 * x.

Now, let's consider QT * x. We can multiply both sides of the equation Q * x = λ1 * x by QT:

QT * (Q * x) = QT * (λ1 * x)

Applying the associative property of matrix multiplication, we have:

(QT * Q) * x = λ1 * (QT * x)

Using the fact that Q * QT = I, we can simplify further:

I * x = λ1 * (QT * x)

Since I * x equals x, we have:

x = λ1 * (QT * x)

Now, notice that λ1 * (QT * x) is a scalar multiple of x, where the scalar is λ1. Therefore, we can rewrite the equation as:

x = λ2 * x

where λ2 = λ1 * (QT * x).

This shows that x is indeed an eigenvector of QT, with the eigenvalue λ2 = λ1 * (QT * x).

In conclusion, if Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

for more such question on matrix visit

https://brainly.com/question/2456804

#SPJ8

The correct Option is D. 45÷3= 15 . The equation that best shows that 45 is a multiple of 15 is 45 ÷ 3 = 15.

A multiple is a product that results from multiplying two or more numbers.

A common multiple is a multiple that is common to two or more numbers.

A multiple of a number can be expressed as an integer multiple of the number.

If the result is a whole number, the first number is a multiple of the second.

An equation that shows 45 is a multiple of 15 is as follows: 45 ÷ 3 = 15.

A multiple is a number that can be divided by another number without leaving a remainder.

As a result, we divide 45 by 3 to find out whether 45 is a multiple of 15.

If the result is a whole number, 45 is a multiple of 15.

Here is the equation that shows this: 45 ÷ 3 = 15

Thus, we can conclude that the equation that best shows that 45 is a multiple of 15 is  45 ÷ 3 = 15.

For more questions on equation

https://brainly.com/question/17145398

#SPJ8

Answer:

3.00

Step-by-step explanation:

One bow and and 1 roll of wrapping paper  cost 6.00$

so the roll by itself would cost 6.00$

Answer:

General form \(x^{2}\) + \(y^{2}\) -2x -2t -14 = 0

Step-by-step explanation:

\(\sqrt{(x-1)^{2} +(y-1)^{2} }\) = 4  Square both sides

\((x-1)^{2}\) + \((y-1)^{2}\) = \(4^{2}\)

\(x^{2}\) - 2x + 1 + \(y^{2}\) -2y + 1 = 16  Combine like terms

\(x^{2}\) + \(y^{2}\) -2x - 2y +2 = 16  Subtract 16 from both sides

\(x^{2}\) + \(y^{2}\) -2x -2y -14 = 0

Answer:

Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.

Step-by-step explanation:

Given

See attachment for histogram

Required

Select the true statement

Option A: Class 46-50 = 12 students

From the histogram, we have:'

\(Class\ 46 - 48 = 8; Class\ 48 - 50 = 3\)

So:

\(Class\ 46 - 48 = Class\ 46 - 48 + Class\ 48 - 50\)

\(Class\ 46 - 48 = 8+ 3\)

\(Class\ 46 - 48 = 11\)

(a) is false

Option B: %Class 52-54 = 18%

From the histogram, we have:'

\(Class\ 52-54 = 18\)

and

\(Total = 53\)

So, the percentage is:

\(\% Class\ 52-54 = \frac{Class\ 52-54}{Total}\)

\(\% Class\ 52-54 = \frac{18}{53}\)

\(\% Class\ 52-54 = 0.3396\)

Express as percentage:

\(\% Class\ 52-54 = 33.96\%\)

(b) is false

Option C: Class 54-60 > Class 46 - 50 students

From the histogram, we have:'

\(Class\ 54-60 =Class\ 54-56 + Class\ 56-58 + Class\ 58-60\)

\(Class\ 54-60 = 4 + 4+3\)

\(Class\ 54-60 = 11\)

In (a), we have:

\(Class\ 46 - 48 = 11\)

By comparison:

\(Class\ 54-60 =Class\ 46 - 48 = 11\)

(c) is false

Option D: Class 44-52 < Class 52 - 60 students

From the histogram, we have:'

\(Class\ 44-52 =Class\ 44-56 + Class\ 46-48 + Class\ 48-50 +Class\ 50-52\)

\(Class\ 44-52 = 4+8+3+9\)

\(Class\ 44-52 = 24\)

\(Class\ 52-60 =Class\ 52 - 54 + Class\ 54-56 + Class\ 56-58 + Class\ 58-60\)

\(Class\ 52-60 = 18+ 4 + 4+3\)

\(Class\ 52-60 = 29\)

By comparison:

\(24 < 29\)

i.e.

\(Class\ 44 - 55 < Class\ 52 - 60\)

(d) is true

Let's use the following inequation as an example:

First let's simplify it dividing the inequation by 2:

Now, let's draw a number line, and include the point 3 in it:

We want the values of y that are greater than 3, that is, the numbers to the right of the number 3 in the number line. So we mark the area that corresponds to the values of y that satisfies the inequation:

The number 3 is not part of the answer, because 3 is not greater than 3, so we draw a small empty circle on the number 3. If the number 3 was part of the answer, the circle would be filled.