In a certain region the average horizontal component of Earth's magnetic field is 17 μT, and the average inclination or "dip" is 79°. What is the corresponding magnitude of Earth's magnetic field in microteslas?

It takes 0.1311 seconds to hear the echo of the stone.

First we need to determine the time it takes for the sound wave to travel from the stone to the bottom of the mine shaft and back up to our ears.

Let's start by finding the time it takes for the sound wave to reach the bottom of the mine shaft. We can use the formula:

time = distance / speed

The distance is the depth of the mine shaft, which is 15 meters. The speed of sound is 343 m/s, as given in the problem. Therefore, the time it takes for the sound wave to reach the bottom of the mine shaft is:

time = 15 m / 343 m/s

time = 0.0437 s

Now, we need to find the time it takes for the sound wave to travel back up to our ears. Since the sound wave travels at the same speed, 343 m/s, the distance it needs to cover is twice the depth of the mine shaft, or 30 meters. Therefore, the time it takes for the sound wave to travel back up to our ears is:

time = 30 m / 343 m/s

time = 0.0874 s

Finally, to find the total time it takes to hear the echo, we add the time it takes for the sound wave to reach the bottom of the mine shaft to the time it takes to travel back up to our ears:

total time = 0.0437 s + 0.0874 s

total time = 0.1311 s

Therefore, it takes 0.1311 seconds to hear the echo of the stone.

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Answer:

  2

Explanation:

If the energy is doubled, the mass must be doubled (increased by a factor of 2) in order for the temperature effect to remain the same.

Heat capacity is measured in units of J/(kg·°C), so the ratio will remain constant if mass varies directly with amount of heat.

The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.

To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.

The force between two point charges can be calculated using Coulomb's law, which states that

F = k × q₁× q₂ / r²

where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.

The force between q₁ and q₂ is

F₁ = k × q₁ × q₂ / r₁²

where r₁ = 0.10 m.

Substituting the values, we get

F₁ = 9.0 x 10⁹ N m² / C²  × 8.0 C  × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N

The force between q₂ and q₃ is

F₂ = k  × q₂  × q₃ / r₂²

where r₂ = 0.15 m.

Substituting the values, we get

F₂ = 9.0 x 10⁹ N m² / C²  × 3.5 C  × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N

Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.

The net force on q₂ is the vector sum of F₁ and F₂

\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N

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Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Given that,

Three resistors of resistances 2 Ω, 3 Ω and 4 Ω are connected in series with a 15 V supply.

Solution,

The equivalent resistance in series combination is given by :

\(R=R_1+R_2+R_3\\\\R=2+3+4\\\\=9\ \Omega\)

(i) Total resistance of the circuit is equal to 9 ohms.

(ii) Let I be the total current. Using Ohm's law as follows :

\(V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{15}{9}\\\\=1.67\ A\)

(iii) Voltage drop across 2 ohm resistor is :

\(V=1.67\times 2=3.34\ V\)

Voltage drop across 3 ohm resistor is :

\(V=1.67\times 3=5.01\ V\)

Voltage drop across 4 ohm resistor is :

\(V=1.67\times 4=6.68\ V\)

Hence, this is the required solution.

Answer:

i think the 2nd one

the first=0 b/c it's initial velocity and final ones are equal the third one is constant

The angle of the red line (λ = 656 nm) in the ∅₁ 1st order is 0.0321 radians.

An optical lattice is a periodic structure formed by interfering laser beams, which creates a spatially varying pattern of light and dark regions. The lattice serves as a diffraction grating that can split light into its constituent wavelengths, enabling scientists to study the properties of light and matter. Optical lattices are widely used in experiments involving cold atoms, quantum optics, and condensed matter physics.

The angle of the red line (λ = 656 nm) in the ∅₁ 1st order can be calculated using the formula:

sin(θ) = mλ/d

where θ is the angle between the incident light and the diffracted light, m is the order of the diffraction (m = 1 for the ∅₁ 1st order), λ is the wavelength of the light, and d is the spacing between the diffracting elements of the grating (d = 1/560 mm in this case).

Substituting the values given, we get:

sin(θ) = (1)(656 nm)/(1/560 mm)

sin(θ) = 0.0005596

Taking the inverse sine of both sides, we get:

θ = sin⁻¹(0.0005596)

θ = 0.0321 radians

Therefore, the angle of the red line (λ = 656 nm) in the ∅₁ 1st order is 0.0321 radians.

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Answer:

72mph/sec

Explanation:

The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:

216mph / 3sec = 72mph/sec, our final answer

Hope it made sense. I would appreciate Brainliest, but no worries.

Answer:

Bill bill bill bill

Explanation:

Omigosh you brought me back to my childhood.

(still watching it rn and will take notes)

The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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Answer:

A producer needs the sun to make its own food, because producers use photosynthesis. In photosynthesis you use the sun to turn the air people breathe out and water into glucose and oxygen.

Explanation:

Hope this helps ^-^

The energy released per kilogram of fuel used is 3.39 * 1014 J/Kg

Energy is released in a reaction because of  the breaking of bonds are well as formation of bonds.

The quantity of energy released in reactions differs according to the reaction type involved.

The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.

The energy, E released in nuclear reactions is given by the formula below:

Energy per kilogram of reactants (in joules) = Energy per mole of reactants (in joules) / Total molar mass of reactants (in kg)

Energy per kilogram of reactants (in joules)  = \(1.60218 x 10^-^1^3 joules\) /  5 grams

Energy per kilogram of reactants (in joules)   =  3.39 * 1014 J/Kg

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The energy released per kilogram of fuel used is 5.632 × 10^-14 J/kg.

5 grammes, 0.005 kilogrammes, of reactants are provided.

Since 1 mile of tritium and 1 mile of deuterium are equal to 1 mole of "reactions," the sum of the "reactions" in 0.005 kilogrammes of reactants may be computed as follows:

Total moles of "reactions" in 0.005 kg of reactants = (0.005 kg / 5 g/mol)                            

                                                                                     = 0.001 mole.

The MeV per reaction must now be multiplied by the total number of "reactions" in order to get the total energy released by the "reactions."

Next, the energy must be converted from MeV to Joules.

MeV to Joules conversion factor is 1.6 10-13 J/MeV.

Total energy released = (MeV per reaction) x (number of reactions) x (conversion factor)

Total energy released = (17.6 MeV/reaction) x (0.001 mole) x (1.6 × 10^-13 J/MeV)

Total energy released = 2.816 × 10^-16 J

The total energy released by the "reactions" is 2.816 × 10^-16 J.

To determine the energy released per kilogram of fuel used, we need to divide the total energy by the mass of fuel used.

Total energy released per kilogram of fuel used = (total energy released) / (mass of fuel used)

Total energy released per kilogram of fuel used = (2.816 × 10^-16 J) / (0.005 kg)

Total energy released per kilogram of fuel used = 5.632 × 10^-14 J/kg

Therefore, the energy released per kilogram of fuel used is 5.632 × 10^-14 J/kg.

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Answer:

The answer of this question is windmill

The water tank waves are transverse waves while the sound waves are longitudinal waves.

A wave is a disturbance along a medium which transfers energy. We know that the water tank waves are transverse waves while the sound waves are longitudinal waves.

The difference between the two is that in the water waves, the direction of the wave motion is perpendicular to the disturbance while in the sound waves, the the direction of the wave motion is parallel to the disturbance.

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Answer:

Freddy is participating in a pumpkin lifting contest. The 68 kg pumpkin starts at rest on the ground. If Freddy exerts a 720N force on the pumpkin, what is the acceleration of the pumpkin as he lifts it off the ground?

Explanation:

Answer:

W = 3.15 · 10⁶ J  

Explanation:

We know that power is calculated using the formula:

We can derive a formula for work using this formula by multiplying t to both sides of the equation.

Let's convert 15 kW to W.

Let's convert 3.5 min to s.

Substitute these values into the formula for work and solve for W.

This is the amount of work done by a 15 kW engine in 3.5 minutes.

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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The current flowing through the 1Ω resistor in the circuit is 0.66 A.

The emf of the cells, V = 1.1 V

Internal resistance of the cells, r = Ω

Resistance across the circuit, R = 1 Ω

According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.

According to Kirchoff's current law,

(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1

3/2(1.1 - V') = V'

3.3 - 3V' = 2V'

5V' = 3.3

Therefore, the terminal velocity of the battery is,

V' = 3.3/5

V' = 0.66 V

Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,

I = V'/R

I = 0.66/1

I = 0.66 A

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Answer:

d = 0.05 [m] = 50 [mm]

Explanation:

We must remember the principle of conservation of energy which tells us that energy is transformed from one way to another. For this case, the initial kinetic energy is transformed into useful work that is equal to the product of force by distance.

\(E_{k}=F*d\\400 = 8000*d\\d = 0.05 [m] = 50 [mm]\)

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.

A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.

The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.

Hence option B is correct.

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Hi there!

Recall the equation for work given a potential difference and charge:
\(\large\boxed{W = qV}\)

W = Work (J)
q = charge (C)
V = Potential difference (V)

The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.

Thus:

\(W' = (2Q)(V) = 2W\)

This is equivalent to:

\(\large\boxed{2W = \text{ d) } 2K}}\)

Answer:

\(M=7.05*10^{-4}\)

Explanation:

From the question we are told that:

Coil one turns N_1=1550 Turns/m

Radius \(r=0.0240m\)

Turns 2 \(N_2=200N\)

Generally the equation for area is mathematically given by

\(A=\pi*r^2\)

\(A=\pi*0.024^2\)

\(A=\1.81*10^{-3} m^2\)

Therefore

The mutual inductance of this system is

\(M=\mu*N_1*N_2*A\)

\(M=(4 \pi*10^{-7})*1550*200*1.81*10^{-3}\)

\(M=7.05*10^{-4}\)

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Answer: 4.97 years

Explanation: I got the answers right

By the use of the Kepler's laws, the period of the orbit is 5.22 years. Option D

We know that when we are dealing with the orbits that our mind would have to be turned to the Kepler's law. In the Keplers law, we see the relationship that cold be used in the attempt to connect the period of the orbit to the radius of the semi major axis of an orbiting body.

By the application of the Keplers third law;

T^2 = r^3

The statement of the law is that the square of the period of the objects orbit is equal to the cube of the length of the semi major axis.

We then know that;

T = period

r = distance

Hence;

T = r^3/2

T = (3.01 )^3/2

T = 5.22 years

The period of the object is seen to be 5.22 years from the calculation above.

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In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

a. Check image below.

b. Check image below.

c. 4m/s.

d. 3m/s.

Check attached image 1 below.

Let's first find the average velocity.

Average velocity's formula: \(A_v=\frac{Td}{Tt}\); where Td is the total distance covered by the robot and Tt is the total time used to cover that distance. Substitute the values in the formula and calculate:

\(A_v=\frac{30m}{10s}=3m/s\)

Hence, the average velocity on the graph will consist on a line whose slope is 3. Another easier method to mark the average velocity of the robot is to just make a line that starts on the first point of the graph and finishes on the last point. Check attached image 2 to see the result.

To calculate the answer for this question, use the same formula presented on "Part b" and substitute by the correct values.

\(A_v=\frac{25m-17m}{8s-6s}=4m/s\).

We already solved this in "Part b". Write it again with more detail for this part.

\(A_v=\frac{P_2-P_1}{t_2-t_1}\); where \(P_2\) and \(P_1\) are the final position, and initial position, respectively. Also, \(t_2\) and \(t_1\) are the final time, and initial time, respectively.

\(A_v=\frac{P_2-P_1}{t_2-t_1}=\frac{30m-0m}{10s-0s}=3m/s\)