: In a certain men's track and field event, the shotput has a mass of 7.50 kg and is released with a speed of 13.0 m/s at 30.0° above the horizontal over a man's straight left leg Part A What is the initial horizontal component of the momentum of this shotput? Express your answer in kilogram meters per second. ΑΣΦ ? Ph= kg-m/s Submit Request Answer Part B What is the initial vertical component of the momentum of this shotput? Express your answer in kilogram meters per second. | ΑΣΦ ]] ? Pv= kg-m/s Submit Request Answer

The diameter of the aorta can be determined by using the given velocity and flow rate. The velocity in branch arteries can be calculated using the given flow rate and the total area of the arteries. The first branch off the aorta can be identified based on its location. The valve area can be determined by utilizing the given velocities and the area of the LVOT.

To calculate the diameter of the aorta, we need to relate the velocity and the flow rate. Velocity is given as 33 cm/sec, and the flow rate is 4.4 L/min. We can convert the flow rate to cm^3/sec (1 L = 1000 cm^3), which gives us a flow rate of 73.33 cm^3/sec. The flow rate is proportional to the cross-sectional area of the vessel multiplied by its velocity. Using the formula Q = A * V, where Q is the flow rate, A is the cross-sectional area, and V is the velocity, we can rearrange the formula to solve for the diameter of the aorta.

To determine the velocity in each branch artery, we can use the given flow rate of 5.1 L/min and the total area of the branch arteries, which is 50 cm^2. By dividing the flow rate by the total area, we can find the velocity in the branch arteries.

Identifying the first branch off the aorta requires knowledge of the anatomy. Typically, the first branch off the aorta is the brachiocephalic trunk, which divides into the right subclavian artery and the right common carotid artery.

To calculate the valve area, we can utilize the velocities and the area of the left ventricular outflow tract (LVOT). The velocity in the aortic valve is given as 4.4 m/sec, and the velocity in the LVOT is 88 cm/sec. The valve area can be determined using the continuity equation, which states that the product of the cross-sectional area and velocity at one point is equal to the product of the cross-sectional area and velocity at another point along the flow path.

In summary, the diameter of the aorta can be determined using the given velocity and flow rate. The velocity in branch arteries can be calculated using the flow rate and the total area of the arteries. The first branch off the aorta is typically the brachiocephalic trunk. The valve area can be calculated using the velocities and the area of the LVOT, utilizing the continuity equation.

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\(\huge\text{Hey there!}\)

\(\text{The formula for mechanical advantage is: }\rm{MA = \dfrac{F_o}{F_i}}\\\\\rm{Whereas, MA\ is: Mechanical\ average, F_o \ is \ the\ out put \ force, \ \& \ F_i\ is\ the\ in put}}\\\rm{force.}\)

\(\rm{MA = \dfrac{0.72}{1.85}\ or\ MA = \dfrac{1.85}{0.72}}\\\\\\\text{SIMPLIFYING }\rm{MA = \dfrac{0.72}{1.85}}\\\\\rm{MA \approx 0.72\div 1.85}\\\rm{MA \approx 0.3892}\\\rm{MA\approx 0.4}\\\\\\\text{SIMPLIFYING }\rm{MA = \dfrac{1.85}{0.72}}\\\\\rm{MA \approx 1.85\div 0.72}\\\rm{MA \approx 2.5694}\\\rm{MA \approx 2.6}\\\\\\\\\huge\text{Your answer probably is: \boxed{\mathsf{Option \ B. \bf 2.6}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

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Answer:

2.78m/s²

Explanation:

Complete question:

A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?

According to Newton's second law of motion:

\(\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\\)

Where:

\(\mu\) is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

\(\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2\)

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

\(gsin\theta - \mu g cos\theta = a_x\\\)

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

Hence the acceleration of the box as it slides down the incline is 2.78m/s²

Answer:

Pressure of .2 m^3 of bricks:

Pb = ρ g H = 1.8 ρw * 9.80 m/s^2 * .20 m = 1800  * 9.8 * .2 = 3530 Pascals

ρb = 1.8 ρw = 1.8    since the density of bricks is 1.8 that of water

Pw = 1 * 9.8 * 1000 * .2 = 1960 Pascals

W = P * A   pressure * Area = Force

Pnet = 1570 Pascals - pressure due to bricks under water

F = 1570 N/m^2 * .2m^2 = 63 N     force on pile of bricks

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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Answer:

43,919.66 Kilotones de Co2 en 2016.

Explicación:

Ecuador produce 43,919.66 Kilotones de Co2 en 2016. Las tierras húmedas son muy importantes para la biodiversidad porque proporcionan hábitat a millones de animales. Alrededor del 35 por ciento de todas las especies amenazadas y en peligro vive en estas tierras húmedas. Estas tierras húmedas son altamente productivas y tienen la capacidad de mejorar la calidad del agua, prevenir la degradación del suelo y proporcionar alimentos a los animales que viven en estas tierras húmedas.

The current through each resistor is 13 A.

To calculate the current in each resistor, we can use Ohm's law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.

In this case, we are given the current and the resistance of each resistor, so we can use Ohm's law to calculate the voltage across each resistor, and then use the current to find the current through each resistor.

Let's start with the first resistor, which has a resistance of 2 ohms:

V = IR

V = (13 A) x (2 ohms)

V = 26 V

Now, we can use the voltage and resistance to find the current through the first resistor:

I = V/R

I = (26 V) / (2 ohms)

I = 13 A

So, the current through the first resistor is also 13 A.

Next, we can repeat the same process for the other two resistors:

For the second resistor with a resistance of 3 ohms:

V = IR

V = (13 A) x (3 ohms)

V = 39 V

I = V/R

I = (39 V) / (3 ohms)

I = 13 A

So, the current through the second resistor is also 13 A.

For the third resistor with a resistance of 4 ohms:

V = IR

V = (13 A) x (4 ohms)

V = 52 V

I = V/R

I = (52 V) / (4 ohms)

I = 13 A

So, the current through the third resistor is also 13 A.

Therefore, the current through each resistor is 13 A.

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The magnitude of the resultant vector is 81.5 m and the direction is 41.3 degrees with respect to the x-axis.

To find the magnitude of the resultant vector, we use the law of cosines: c^2 = a^2 + b^2 - 2ab * cos(C),

where a = 66.0 m, b = 40.0 m, and C = 180 - (28 + 56) = 96 degrees.

Plugging in these values, we get c^2 = 66.0^2 + 40.0^2 - 2 * 66.0 * 40.0 * cos(96).

Solving for c, we find c ≈ 81.5 m.

To find the direction of the resultant vector, we use the law of sines: sin(A)/a = sin(B)/b = sin(C)/c, where A is the angle opposite to side a, B is the angle opposite to side b, and C is the angle opposite to side c.

In this case, we want to find angle A.

Plugging in the values, we get sin(A)/66.0 = sin(96)/81.5.

Solving for sin(A), we find sin(A) ≈ (66.0 * sin(96))/81.5.

Taking the inverse sine of this value, we find A ≈ 41.3 degrees.

Therefore, the direction of the resultant vector is 41.3 degrees with respect to the x-axis.

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Answer:

30mph

Explanation:

7.5 miles / .25 hours = 30 mph

Larry's average speed, in km/h, can be calculated by dividing the total distance he ran by the time taken.

Average speed is a measure of the overall rate at which an object covers a certain distance. It is calculated by dividing the total distance traveled by the total time taken. The average speed is a scalar quantity, meaning it only has magnitude and no direction. It represents the overall "average" rate at which an object moves without considering the specific details of its motion. Larry ran 4 kilometers in 30 minutes. To calculate the average speed, we convert the time from minutes to hours by dividing it by 60. So, 30 minutes is equal to 0.5 hours.

Average speed = Total distance / Time taken

Average speed = 4 km / 0.5 hours

Dividing 4 km by 0.5 hours, we get:

Average speed = 8 km/h

Therefore, Larry's average speed is 8 km/h.

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Answer:

friction doesn't let the desk move.

Explanation:

the law of motion states any object in motion should stay in motion.

Answer: The greater an object's mass, the more gravitational force it exerts.

Explanation: So, to begin answering your question, Earth has a greater gravitational pull than the moon simply because the Earth is more massive. Sorry if I get this wrong. I am in 5th grade! ♥

The gravitational attraction between the Sun and Earth is stronger than the attraction between the Sun and the Moon, principally because of the Sun's greater mass and greater distance from Earth.

An object's mass affects how much gravitational pull it exerts. Both the Earth and the Moon are much less massive than the Sun. Approximately  330,000 times more massive than the Earth, and roughly 27 million times more massive than the Moon, is the Sun. Because of the Sun's greater mass, its gravitational pull is thus much stronger.

The strength of the gravitational force between two objects is greatly influenced by their distance from one another. The Sun and Earth are separated from one another by a far smaller distance than the Sun and Moon. The Sun is located roughly 150 million kilometers from Earth, while the Moon is located roughly 384,400 kilometers from the Sun on average. The inverse square law asserts that the gravitational force decreases with increasing distance, and that it is only one-fourth as strong when two objects are twice as far apart.

Hence, the gravitational force between the sun and earth is larger than the sun and the moon due the mass of the sun and earth is greater than the moon and sun. The distance between the sun and the earth is comparatively smaller than the distance between the sun and the moon.

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Explanation:

Your body uses chemical energy every day to perform daily tasks. Food contains calories and when you digest food, the energy is released. The molecules in food are broken down into smaller pieces. As the bonds between the atoms break or loosen, oxidation occurs.The chemical reaction involved in digestion supplies you with warmth, helps to maintain and repair your body and gives you the energy you need to move around.

Answer:

is the last one, a magnetic wave and electrical current moving in opposite directions

Explanation:

opposite directions always attract in magnetic waves and fields

Answer:

The acceleration that the jet liner that must have is 2.241 meters per square second.

Explanation:

Let suppose that the jet liner accelerates uniformly. From statement we know the initial (\(v_{o}\)) and final speeds (\(v_{f}\)), measured in meters per second, of the aircraft and likewise the runway length (\(d\)), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (\(a\)), measured in meters per square second:

\(a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}\)

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 82\,\frac{m}{s}\) and \(d = 1500\,m\), then the acceleration that the jet must have is:

\(a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}\)

\(a = 2.241\,\frac{m}{s^{2}}\)

The acceleration that the jet liner that must have is 2.241 meters per square second.

Answer:

Explanation:

Designing investigations to predict the effect of hurricanes (D) best describes a scientific endeavor.

A scientific endeavor builds scientific knowledge by postulating theories that explains any phenomenon. It might differ from what was already known as the truth. In a scientific endeavor, a problem is first identified, observations are made, hypothesis are created based on the observations and experiments are conducted to prove the hypothesis.

The other options manly focusses on developing devices and technologies to prevent or withstand hurricanes which are examples of engineering endeavors.

Therefore, Designing investigations to predict the effect of hurricanes (D) best describes a scientific endeavor.

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Answer:

Zero

Explanation:

Zero....  Inertia states a body in motion will remain in motion unless acted on by external forces.... no friction forces means it needs no force to keep going

Porter's Five Forces is a framework used to analyze the competitive intensity and attractiveness of an industry. The five forces are: Threat of New Entrants, Bargaining Power of Suppliers, Bargaining Power of Buyers, Threat of Substitute Products or Services and Intensity of Competitive Rivalry.

Threat of New Entrants: This force considers the ease or difficulty for new competitors to enter an industry. It includes barriers to entry such as high capital requirements, economies of scale, brand loyalty, and government regulations.

Example: The airline industry is known for its high barriers to entry due to the significant capital required to purchase aircraft, establish routes, and secure necessary licenses and permits. Additionally, established airlines often have loyal customer bases and strong brand recognition, making it challenging for new entrants to compete effectively.

Bargaining Power of Suppliers: This force assesses the power suppliers have over the industry in terms of pricing, quality, and availability of inputs. It considers factors such as the concentration of suppliers, uniqueness of their products, and their ability to forward integrate.

Example: In the smartphone industry, major suppliers of components like microchips and display screens hold significant bargaining power. These suppliers provide essential inputs, and their products may have limited alternatives or require specialized manufacturing processes. As a result, smartphone manufacturers must negotiate favorable terms with these suppliers to ensure a reliable supply chain and competitive pricing.

Bargaining Power of Buyers: This force examines the power customers have in influencing prices, demanding better quality or service, and potentially switching to alternative products or suppliers. It considers factors such as buyer concentration, product differentiation, and switching costs.

Example: The retail industry experiences strong buyer power, particularly in highly competitive markets. Customers have access to various options, and their ability to compare prices and products easily through online platforms empowers them to demand competitive pricing, promotions, and high-quality products and services.

Threat of Substitute Products or Services: This force looks at the availability of alternative products or services that can satisfy customer needs. It considers factors such as price-performance trade-offs, switching costs, and customer loyalty.

Example: The rise of streaming services such as Netflix, Amazon Prime Video, and Hulu posed a significant threat to traditional cable and satellite TV providers. These streaming platforms offer a wide range of content at competitive prices, allowing customers to switch from traditional TV services to streaming options, resulting in a decline in subscriber numbers for traditional providers.

Intensity of Competitive Rivalry: This force evaluates the level of competition among existing firms in the industry. It considers factors such as the number and size of competitors, industry growth rate, product differentiation, and exit barriers.

Example: The soft drink industry, dominated by major players like Coca-Cola and PepsiCo, experiences intense competitive rivalry. These companies fiercely compete for market share through advertising campaigns, new product launches, pricing strategies, and distribution channels. The rivalry is further intensified by the high market saturation and the limited scope for differentiation among similar products.

The interconnection of these forces lies in their collective influence on the competitive dynamics and profitability of an industry. Changes in one force can trigger a chain reaction that impacts the others. For instance, a high threat of new entrants may lead to increased competitive rivalry as existing firms strive to defend their market share. Similarly, a strong bargaining power of buyers can limit the pricing power of suppliers and impact their profitability. Understanding these interconnections helps businesses assess the overall attractiveness and competitive landscape of an industry and develop appropriate strategies to thrive within it.

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Blowing across the top of an empty soda bottle that is 21 cm deep, assuming it is a closed tube, would result in a resonant frequency of approximately 408.33 Hz.

The resonant frequency of a closed tube can be determined using the formula:

f = (n * v) / (4L),

where f is the resonant frequency, n is the harmonic number (which represents the number of half-wavelengths that fit inside the tube), v is the speed of sound in air (which is approximately 343 m/s at room temperature), and L is the length of the tube.

In this case, the soda bottle is 21 cm deep, which is equivalent to 0.21 meters. Since it is a closed tube, we can assume that n = 1, as the fundamental frequency is the first harmonic. Plugging in the values into the formula, we get:

f = (1 * 343) / (4 * 0.21),

f ≈ 408.33 Hz.

Therefore, the expected resonant frequency would be approximately 408.33 Hz.

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Answer:

Explanation:

Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.

To make a 200 ml solution of 5 mm sucrose from a 100 mm sucrose solution we have to take a volume of: 10ml of the concentrated solution

To solve this problem, the formula and the procedure that we have to use is:

c1 * v1 = c2 * v2

Where:

Information about the problem:

Applying the dissolution of concentrations formula and clearing the volume of the concentrated solution (c1) we get:

c1 * v1 = c2 * v2

v1 = (c2 * v2)/ c1

v1 = (5 mm * 200 ml)/ 100 mm

v1= 10 ml

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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Explanation:

En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua

q1= charge 1 = -0.0004C

q2= charge 2 = 0.0003c

r = distance = 3 m

F = k (q1*q2) / r^2

Where:

F= force

k= constant = 9 x 10^9 kgm^3/s^2m^2

Replacing:

F = 9x10^9 ( -0.0004 * 0.0003 ) / 3^2

F= 120 N

The comet is expected to make approximately 26 more visits to the inner solar system, assuming its orbital period remains constant.

If a short-period comet has an orbital period of 50 years, it means that it takes 50 years for the comet to complete one orbit around the Sun.

Therefore, the comet would have completed 24/50 of its current orbit at the time of observation.

To determine how many more years this comet would be expected to continue its visits to the inner solar system, we need to subtract the current time from the time it takes for the comet to complete one orbit around the Sun.

The time left for the comet to complete one orbit around the Sun can be calculated as follows:

50 years - (24/50) x 50 years

= 50 years - 24 years

= 26 years

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The near-point distance of the eye is 11 cm.

The near-point distance of the eye is the closest possible distance an object can be from the eye in order for its image to be formed on the retina. It can also be termed the closest distance of accommodation.

The near-point distance of the eye in the given scenario can be calculated using the lens formula given below:

1/f = 1/v + 1/u

where;

f = focal length

v = image distance

u = object distance

From the data provided;

f = 2.20 cm

v = 2.75 cm

u = ?

Solving for u:

1/u = 1/f - 1/v

1/u = 1/2.20 - 1/2.75

1/u = 0.91

u = 11 cm

In conclusion, the lens formula is used to determine the eye's near-point distance.

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Answer:

The most reactive element is fluorine, the first element in the halogen group. The most reactive metal is francium, the last alkali metal (and most expensive element)

Explanation:

Answer: runner B

Explanation:

i did the test

Runner which has the weakest force is A.

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

The image attached shows the times for runners in a 100 m dash.

Force = mass x Acceleration

Force = mass x Velocity /Time

If each runner has the same mass, runner with the maximum time has the weakest or lowest force.

Among all the four runners, Runner A has the highest time for completing 100 m dash.

Thus, Runner A has the weakest force.

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a) The null and alternative hypotheses can be stated as follows:

H0: The mean body temperature of a healthy adult is 98.6 °F.

H1: The mean body temperature of a healthy adult is not 98.6 °F.

b) The appropriate significance level is given as 0.10, which corresponds to a 10% significance level.

c) To perform the hypothesis test, we can use the t-test since the population standard deviation is unknown. The test statistic can be calculated using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / √n)

where the sample mean is 98.24 °F, the hypothesized mean is 98.6 °F, the sample standard deviation is 0.92 °F, and n is the sample size, which is 35 in this case.

Substituting these values into the formula, we get:

t = (98.24 - 98.6) / (0.92 / √35)

t = -0.36 / (0.92 / √35)

t = -0.36 / (0.92 / 5.92)

t ≈ -0.36 / 0.155

t ≈ -2.32 (rounded to two decimal places)

d) The test statistic is approximately -2.32.

e) To calculate the p-value, we need to determine the probability of obtaining a test statistic as extreme as -2.32 (in either tail) assuming the null hypothesis is true. Since we have a two-tailed test, we need to calculate the area under the t-distribution curve beyond -2.32 in the left tail and beyond 2.32 in the right tail.

Looking up the p-value corresponding to -2.32 (or the closest value) in the t-distribution table or using statistical software, we find that the p-value is approximately 0.0257.

Therefore, the p-value is approximately 0.0257 (rounded to four decimal places).

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