if you repeated this experiment with a different concentration of crystal violet, would you expect to find the same order with respect to crystal violet or a different one?

The more massive particle will move at the same speed as the less-massive particle. The correct answer is Option D.

In physics, mass is a measure of an object's resistance to acceleration when a net force is applied to it. The larger the mass, the more force is required to accelerate it. This property is usually referred to as inertia in everyday speech.

In physics, the mass of an object is frequently denoted by m. The standard unit of mass is the kilogram (kg).

Mass has a considerable influence on the velocity of an object. The greater the mass of an object, the slower it travels at a given speed. According to Newton's second law of motion, a force acting on an object equals the mass of the object times its acceleration.

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Answer:

zero

Explanation:

The correct option is 4) Zero

Answer:

atoms bonding

Explanation:

When the pressure of a gas is tripled while keeping the temperature constant, the volume of the gas will decrease to one-third of its initial volume.

This is an example of Boyle's law, which states that the volume of a gas is inversely proportional to its pressure when the temperature is constant. This means that as pressure increases, volume decreases, and vice versa.Rubber rafts are often used in water activities as a means of transportation. They can easily be deflated, folded up, and stored in a compact space. Rubber rafts, on the other hand, are vulnerable to the sun's heat. If a rubber raft is left in the sun on a hot summer day, it can cause it to burst.

What happens is that the rubber expands when it is heated. As the temperature rises, the air molecules in the rubber become agitated and collide with each other, causing the rubber to expand. When this happens, the raft stretches and becomes weaker. If the temperature continues to rise, the pressure inside the raft increases as well. The pressure will eventually become too great, and the raft will burst.

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The mass (in grams) of oxygen, O₂ required to produce 61.3 grams of carbon dioxide, CO₂ is 44.6 grams

First, we shall write the balanced equation. This is shown below:

C + O₂ -> CO₂

From the balanced equation above,

44 g of CO₂ were obtained from 32 g of O₂

Finally, we shall obtain the mass of oxygen, O₂ needed to produced 61.3 g of carbon dioxide, CO₂. Details below:

From the balanced equation above,

44 g of CO₂ were obtained from 32 g of O₂

Therefore,

61.3 g of CO₂ will be obtain from = (61.3 × 32) / 44 = 44.6 g of O₂

Thus, we can conclude that the mass of oxygen needed to produced 61.3 g of carbon dioxide is 44.6 g

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Answer:

72.440064 in

Explanation:

Convert meters to yards.

(1.84 m) × (1.0936 yd/m) = 2.012224 yd

Convert yards to feet.

(2.012224 yd) × (3 ft/yd) = 6.036672 ft

Convert feet to inches.

(6.036672 ft) × (12 in/ft) = 72.440064 in

Thick liquid layer that interacts with an inert carrier gas or mobile phase and is chemically linked to the inside of a capillary column

What is a chromatographic example?

Chromatography Methods

Some forms of liquid chromatography include high-performance liquid chromatography (HPLC), size exclusion chromatography, and supercritical fluid chromatography. Ion-exchange, resin, and paper chromatography are a few other varieties of chromatography.

What is the chromatography's fundamental tenet?

Chromatography is one more method for separating and analyzing chemical mixtures. The method is based on the interaction of polarity between the sample and two additional components, the solid (or stationary) phase, and the mobile phase, which can be either a liquid or a gas.

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The work function of the metal is obtained as 5.1 eV

The cutoff frequency is the frequency below which photo electric effect can not occur as electrons are not removed from the metal surface.

Now;

fo = 1.22 x 10^15 Hz

Wo = hfo

Wo = 6.6 * 10^-34 * 1.22 x 10^15

Wo = 8.1 * 10^-19 J

If 1 eV = 1.60 x 10-19 J

x eV = 8.1 * 10^-19 J

x = 8.1 * 10^-19/ 1.60 x 10-19

x = 5.1 eV

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An ionic equation is balanced when the number of atoms of each element and the total charge is the same on both sides of the equation.

The question is incomplete but I will show you how to balance ionic equation.

Write the unbalanced ionic equation, including the charges of the ions.

Identify the species that are present on both sides of the equation and cancel out any ions that appear on both sides of the equation.

Balance the atoms of each element in the equation, using coefficients as needed to make sure that the same number of atoms appears on both sides of the equation.

Check that the overall charge is balanced by adding or removing electrons as needed. If electrons are added, they should be added to the side of the equation where the total charge is more positive, and if electrons are removed, they should be removed from the side of the equation where the total charge is more negative.

Check that the equation is fully balanced by making sure that the number of atoms of each element and the total charge is the same on both sides of the equation.

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In the given reaction BF3 + F → BF4, F is acting as a Lewis base.

According to the Lewis acid-base theory, a Lewis acid is a species that accepts an electron pair, while a Lewis base is a species that donates an electron pair. In this reaction, F donates its lone pair of electrons to form a bond with BF3, making it a Lewis base. BF3, on the other hand, acts as a Lewis acid by accepting the electron pair from F to complete its octet.

F does not act as a Brønsted-Lowry acid or base in this reaction because it does not donate or accept a proton (H+). Therefore, the correct answer is b. Lewis base.

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The value of the activation barrier for the reaction in kJ/mol is 0.4426 kJ/mol.

Given that the temperature increase from 25.0 °C to 50.0 °C triples the rate constant for a reaction, we can use the Arrhenius equation to find the value of the activation barrier for the reaction in kJ/mol.Arrhenius equation is given as;

k = Ae^{-Ea/RT}

where k = rate constant

A = frequency factor

Ea = activation energy

R = gas constant

T = temperature

In order to determine the activation energy of a reaction, the Arrhenius equation can be expressed as follows;

ln k1/k2 = (Ea/R)(1/T2 - 1/T1)

Where k1 and k2 are the rate constants at temperatures T1 and T2, respectively.

Now, since the temperature has tripled the rate constant, we can say that the ratio of the rate constants is 3:

k1/k2 = 3/1ln

k1/k2 = ln 3

Substituting the values in the above equation;ln 3 = (Ea/R)(1/T2 - 1/T1)

Now, we need to express the temperature in Kelvin;

T1 = 25.0°C + 273.15 = 298.15 K, and T2 = 50.0°C + 273.15 = 323.15 K

Substituting in the equation;

ln 3 = (Ea/R)(1/323.15 - 1/298.15) = (Ea/R)(0.000850)ln 3/(0.000850) = Ea/R = 53.19

Therefore, Ea = R × 53.19 = 8.314 J/K × 53.19 = 442.6 J/mol

Converting to kJ/mol;

442.6 J/mol ÷ 1000 J/kJ = 0.4426 kJ/mol

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Answer:

Answer is: mass.

Explanation:

hope this helps!

Answer:

The pH indicates how acidic or basic a solution is.

Explanation:

i just took the test and got it right.

pH of a solution is the measure of how acidic or basic the solution is. It is determined based on the H+ ion concentration in the solution. Hence, option C is correct.

pH of a solution is the measure of the H+ ion concentration in a solution. It determines the acidity or basicity of the solution. Mathematically it is the negative logarithm of H+ ions concentration.

pH = - log [H+]

A pH scale can be used to determine the acidity or basicity of a solution. If the basicity is 7, then the solution is neutral. If the pH is less than 7 then the solution is acidic and a pH above 7 is basic solution.

Red- green color in pH scale represent the acidic solution where green is neutral and cyan to dark blue color is given by bases. Using a litmus paper the acidity can be checked based on these color change.

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Answer:

H - Cl2 +NaBr -> Br2+2NaCl

Sand and water can be separated by any of the following methods:

1. Sedimentation and decantation: This method involves the mixture being kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container. Now, water is poured into another container to separate it from sand.

2. Filtration: This method involves the mixture being passed through a filter paper (a filter with very fine pores). Sand particles being larger in size are retained by the filter paper and get separated from water.

I hope this helps! :D

Given data:

Mole% of benzene (B) = 30%

Mole% of toluene (T) = 25%

Balance = xylene (X)

Bottom product contains mole% of X = 98%

The overhead product from the second column contains mole% of B in the feed to this column = 97%Composition of overhead product = 94% B

Mole% of X recovered in the bottoms product = 96%

Let's solve the problem:Since the sum of mole% of benzene, toluene, and xylene is 100%, the mole% of X = 100 - 30 - 25 = 45%

In the feed, mole% of B = 30%, mole% of T = 25%, and mole% of X = 45%.

Calculation of benzene emerging in the overhead product from the second column:

Let's consider the flow rate of feed as 100 units, so the flow rate of B in the feed = 100 × 0.3 = 30 units.The flow rate of B in the overhead product of the first column = 30 × 0.03 = 0.9 units (since 97% of benzene in the feed is recovered in the overhead product).

Thus, the flow rate of benzene in the feed to the second column is 0.9 units.The composition of the overhead product from the second column is 94% benzene. Thus, the flow rate of benzene in the overhead product from the second column = 0.9 × 0.94 = 0.846 units.

The percentage of benzene emerging in the overhead product from the second column = (0.846/30) × 100 = 2.82%.

Hence, the percentage of benzene in the process feed that emerges in the overhead product from the second column is 2.82%.Calculation of toluene emerging in the bottom product from the second column:

Let's consider the flow rate of feed as 100 units, so the flow rate of T in the feed = 100 × 0.25 = 25 units.The flow rate of T in the overhead product from the first column = 25 × 0.04 = 1 unit (since 96% of the X in the feed is recovered in the bottoms product).

Thus, the flow rate of T in the feed to the second column is 25 - 1 = 24 units.The composition of the bottom product from the second column is 98% X. Thus, the flow rate of X in the bottom product from the second column = 24 × 0.98 = 23.52 units.

The flow rate of T in the bottom product from the second column = 100 - 30 - 23.52 = 46.48 units.The percentage of toluene in the process feed that emerges in the bottom product from the second column = (46.48/25) × 100 = 185.92%.

Hence, the percentage of toluene in the process feed that emerges in the bottom product from the second column is 185.92%.

Thus, the required answers are:

(i) The percentage of benzene in the process feed that emerges in the overhead product from the second column = 2.82%

(ii) The percentage of toluene in the process feed that emerges in the bottom product from the second column = 185.92%.

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Carbon-14 (C-14) dating is the method of choice to radiometrically date a fossil of a plant that is believed to be about 30,000 years old.

C-14 dating is commonly used to determine the age of organic materials, such as plant fossils or animal remains, that are up to about 50,000 years old.

During photosynthesis, plants absorb carbon dioxide (CO2) from the atmosphere, which contains a small amount of radioactive C-14. When the plant dies, the C-14 begins to decay into nitrogen-14 (N-14) at a known rate, with a half-life of approximately 5,700 years. By measuring the remaining amount of C-14 in a fossil, scientists can calculate how long ago the plant died and therefore determine its age. This method is widely used in the field of archaeology to date ancient artifacts and fossils.

Therefore, Carbon-14 (C-14) isotope is used to radiometrically date a fossil of a plant you believe lived about 30,000 years ago.

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Answer: in a straight path!

Explanation: hope this helps

Seven squares represent seven f-subshell orbitals with magnetic quantum number values of -3, -2, -1, 0, +1, +2, +3.

The paramagnetic nature is represented by a single electron in the seventh orbital.

This quantum number describes the spatial orientations of electrons.

It defines the orientation of an orbital in space of a given energy(n) and shape using magnetic quantum numbers (l). It divides the subshell into orbitals made up of electrons.

It is represented by the symbol ml. Each subshell contains 2l+1 orbitals. The value of lies between -l and +l, where l is the azimuthal quantum number.

Orbitals with l=0, s-subshell, and ml = 0 = 1

P-subshell ml = -1, 0, +1 = 3 orbitals for l=1.

When l=2, the d-subshell ml = -2, -1, 0, +1, +2 = 5 orbitals.

For l=3, the f-subshell ml are -3, -2, -1, 0, +1, +2, +3 = 7 orbitals.

These orbitals are represented as squares in orbital notations of an atom, with electrons represented by upward and downward arrows.

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Answer:

it have more more mass, gravitational potential energy

Explanation:

In a plant, the cell wall is primarily composed of a polymer of carbohydrate subunits. This structural component provides support and protection to plant cells.

The main carbohydrate found in the cell wall is cellulose, which is a complex polysaccharide made up of glucose units linked together.

Cellulose forms a rigid and fibrous network that gives strength to the cell wall. Additionally, other carbohydrates such as hemicellulose and pectin contribute to the overall structure and flexibility of the cell wall.

Lipids, nucleic acids, and amino acids are present in trace amounts and play other roles within the cell.

Thus, the cell wall of a plant cell is primarily made up of cellulose, a polymer of carbohydrate subunits.

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The 4s orbitals are filled first because, according to our theory, they have a lower energy than the 3d orbitals. We are aware that the 4s electrons are lost first when an atom ionizes.

The highest energy level electrons that are lost first are those that are most far from the nucleus' influence. A higher energy must therefore exist in the 4s orbital than in the 3d orbitals.

The electron is a subatomic particle with the symbol e or with an electric charge of one elementaryly negative charge. Due to their lack of known components or substructure, electrons, which are part of the first generation of the lepton particle family, are typically considered to be elementary particles.

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The molarity of the sodium ion is 0.31 M while the molarity of the sulfate ion is 0.62 M.

First of all, we would have to establish that the molarity would be the same as the concentration of the substance. We know that we can be able to obtain the concentration from the number of moles and the volume of the solution thus we would need to use the mass the substance that we have to be able to obtain the number of moles of the solution that we have.

Mass of the sodium sulfate = mass/molar mass

18 g/142 g/mol

= 0.13 moles

Now we know that;

Molarity of the substance = 0.13 moles/0.21 L

= 0.62 M

Number of moles of the sodium ions = 0.62 M/2 = 0.31 M

Number of moles of the sulfate ions =  0.62 M

These are the ions in the solution.

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It took 32.47 ml of .1224 m NaOH to reach the endpoint when titrating a sample containing .4073 g of an unknown acid.

The formula for number of moles(n) is:

n = Molarity × Volume( in liters )

n = 0.1224 x32.47 ÷ 1000 moles

n = 0.00397 Moles.

\(3.9 * 10 ^-3 Mol NaOH\)

Sodium hydroxide is sometimes known as caustic soda or lye. It is a common ingredient in cleansers and soaps.

At room temperature, sodium hydroxide is a solid that is white and odorless. Sodium hydroxide is a liquid that has no color or smell. It can have violent interactions with water and strong acids. The corroding acid is sodium hydroxide. NaOH may heat up as it dissolves if airborne moisture reacts with it. This heat may be sufficient to start a fire if it is close to combustible materials.

Sodium hydroxide is useful because it can alter lipids. It is a crucial component of household products like liquid soap and drain cleaners. White pellets or a solution in water are the two most widely available forms of sodium hydroxide for sale.

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Answer: Density (ρ) = 0.225 kilogram/cubic meter

Explanation:

Conduction is the energy transfer mode in solids. To minimize the heat loss by conduction, we can apply a thermal insulation which can be wrapped onto the material.

Conduction is a mode of energy transfer in substances in solid state. The other two energy transfer modes are convection and radiation. Convection is taking place in liquids and radiation for gases.

In solids, molecules are closely packed and to form a perfect shape and they can easily transfer heat or electric current to other molecules in chain. Thus as one molecule become hot it transfers the heat to the next and so on.

Based on the conductivity there are are three types of materials namely conductors, semiconductors and insulators. Conductors are highly conducting at room temperature and semiconductor will conduct only at some high temperature but not as much as conductors.

Insulators are non-conducting materials which prevent the heat transfer through the material. Therefore, to minimize the conduction in a material, we can use an insulator for coating. There are thermal insulators and electrical insulator coatings available.

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We can start by using the equilibrium concentrations of A, B, and C to calculate the equilibrium constant (Kc) for the reaction:

Kc = [C]^2 / ([A] x [B])

Substituting the given concentrations, we get:

Kc = (0.500 M)^2 / (0.200 M x 3.00 M) = 0.4167

Next, we can use the equilibrium concentrations to write an ICE table (Initial, Change, Equilibrium) to determine how the concentrations will change when we add more A to the system:

       A(g)   +   B(g)   =   2C(g)

I 0.200 M 3.00 M 0 M

C -x -x 2x

E 0.200 M - x 3.00 M - x 0.500 M + 2x

We know that we want the concentration of C to be 0.700 M, so we can set up an equation to solve for x:

0.700 M = 0.500 M + 2x

0.200 M = 2x

x = 0.100 M

This tells us that we need to add 0.100 moles of A to the system to increase the concentration of C from 0.500 M to 0.700 M at 200°C. To calculate the number of moles of A required, we can use the initial volume of the system, which is 1.00 L, and the concentration of A:

moles of A = volume x concentration = 1.00 L x 0.200 M = 0.200 moles

Therefore, we need to add 0.100 moles of A to the system, which is half the amount of A present initially.